1. Calculate the amount of heat required for 25.0 grams of water to
change from 10 degrees Celsius to 30 degrees Celsius. *
2 points
2090
2 points
2.50.0 grams of water at 100 degrees Celsius evaporated to water vapor
at 100 degrees Celsius. Calculate the amount of heat required for this
conversion.
113000
3. A student measured 15.0 grams of ice in a beaker. The beaker was then 2 points
placed on a hot plate where it was heated uniformly for a certain amount
of time. During the melting process of the ice, the student noted that the
temperature was at 0 degree Celsius. When all the ice converted to water,
the final temperature was also at 0 degree Celsius. How much heat was
used to melt the ice? *
Your answer
4. If 5.0 grams of water was cooled from 50 degrees Celsius to 40
degrees Celsius, then calculate the amount of heat released by the water.
2 points
209
5. A certain amount of water used exactly 84.0 Joules of heat energy to
change from 25.0 degrees Celsius to 35 degrees Celsius. How many
grams of water was used?
2 points
No

When the two pith balls are pulled apart, the potential energy of the system rises. This is due to the electrostatic force of repulsion, which is activated when the two pith balls have opposing charges and repel one another.

The two pith balls are pushed apart, and the energy required to do so is stored in the system as potential energy, in accordance with the law of conservation of energy.

This explains why pulling apart the two pith balls increases the system's potential energy. E = qV, where q is the charge on the pith ball and V is the potential difference between the two pith balls, may be used to compute the system's potential energy.

while the two When pith balls are pulled apart, the potential difference between them grows, increasing the system's potential energy. The rise in potential energy is also caused by the electrostatic force of repulsion between the two pith balls. This is due to the fact that when the two pith balls are dragged apart, the electrostatic force of repulsion between them grows, increasing the system's potential energy.

This explains why pulling apart the two pith balls increases the system's potential energy.

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Explanation:

GOLGI BODY - transportation of lipids and steroids.

LYSOSOME - destruction of malfunctioning or worn out cell organelles.

MITOCHONDRIA - oxides glucose to give energy to the cell in a form of cellular respiration.

VACUOLE - FOOD VACUOLE for storage of food while WATER VACUOLE eliminates excess water by a process called OSMOREGULATION.

CELL WALL - provides rigidity for the plant cell.

CHLOROPLAST - pigmented organelle of the plant which functions to manufacture food by a phenomenon known as PHOTOSYNTHESIS.

RIBOSOME - synthesizes protein and enzymes.

ENDOPLASMIC RETICULUM - The ROUGH ENDOPLASMIC RETICULUM has RIBOSOMES attached to it while the SMOOTH ENDOPLASMIC RETICULUM has nothing attached, they transport proteins and enzymes

Students are conducting an experiment to see what colors different salts turn when they are burned. Jack dares Rebecca to taste the other salts to see if they taste like regular table salt. She agrees and her mouth starts burning. Rebecca needs to learn how to behave in the class.

When you add salt to a fire, the flame's color will alter. This isn't because the salt is burning; rather, it happens because the flame's heat affects the energy of the salt's electrons, which causes photons of light to be released. When salt is "burned," a golden flame is frequently visible.

High blood pressure is known to increase the risk of stroke and other health issues, and it is also known to increase the chance of burning in salt. High salt consumption has also been linked in several studies to deteriorating brain function. So, if this occurs, plan for brain surgery and a dedicated teacher to assist the student with wiping and peeling bananas.

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The electronegativity periodic table is a chart that arranges elements according to their electronegativity, which is a measure of an atom's ability to attract electrons to itself. Electronegativity is a chemical property that reflects the relative tendency of an atom to draw electrons towards itself when it forms a chemical bond with another atom.

The electronegativity values are usually determined using the Pauling scale, which was developed by Linus Pauling and is widely used in chemistry. In this scale, the electronegativity of an element ranges from 0.7 for cesium to 4.0 for fluorine, with increasing electronegativity moving from left to right across a period and increasing as one moves down a group.

The electronegativity values can be useful in understanding chemical bonding and the behavior of molecules. For example, elements with high electronegativity values tend to form ionic bonds, while elements with low electronegativity values tend to form covalent bonds. Additionally, the electronegativity difference between two bonded atoms determines the type of bond, with larger differences indicating polar covalent bonds and smaller differences indicating nonpolar covalent bonds.

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Answer:

the last option,matter cannot be created or destroyed

The correct interpretation is  89.6 L of \(NH_{3}\)(g) react with 156.8 L of \(O_{2}\)(g) to produce 89.6 L of \(NO_{2}\)(g) and 134.4 L of \(H_{2} O\)(g).

We know that one mole of a gas does occupy 22.4 L. We can now use this to obtain the number of volumes of the gas based on the stoichiometric coefficient that has been given in the problem.

Molar volume of a gas refers to the volume occupied by one mole of a gas at a specific temperature and pressure. This value is useful in many applications of chemistry, such as in stoichiometric calculations and the determination of gas densities.

Using the stoichiometric coefficients we can see that the volume of the gases are;

Ammonia - 89.6 L

Oxygen -  156.8 L

Nitrogen dioxide - 89.6 L

Water -  134.4 L

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The pH values of the solution after the addition of various amounts of acids are as follows:

(a) When 0.0 mL HCl is added; pH = 11.62

(b) After adding 10.0 mL of 0.100 M HCl; pH = 12.38

(c) After adding 30.0 mL of 0.100 M HCl; pH = 14

(d) After adding 40.0 mL of 0.100 M HCl; pH = 2.70

The equation of the reaction between NH₃ and HCl is:

NH₃ + HCl → NH₄Cl

Before the addition of HCl:

The concentration of NH₃ solution = 0.300 M

The initial concentration of OH- can be calculated from the Kb of NH₃ :

Kb = [NH₄⁺][OH⁻] / [NH₃]

1.8 x 10⁻⁵ = x² / 0.300

x = 0.0024 M

The initial concentration of OH⁻ is 0.0024 M, and the initial pH of the solution ill be:

pH = 14 - pOH

pH = 14 - (-log[OH-])

pH = 11.62

(a) When 0.0 mL HCl is added;

pH = 11.62

(b) After adding 10.0 mL of 0.100 M HCl;

moles of HCl added = (0.100 mol/L) x (0.0100 L)

moles of HCl added = 0.00100 mol

The moles of NH₃ initially present = (0.300 mol/L) x (0.0100 L)

moles of NH₃ initially present = 0.00300 mol

the mole ratio of HCl and NH₃ = 1:1

The remaining moles of NH₃ = 0.00300 mol - 0.00100 mol

remaining moles of NH₃ = 0.00200 mol

The volume of the solution is now 10.0 mL + 10.0 mL = 20.0 mL or 0.0200 L.

The new concentration of NH₃ = 0.00200 mol / 0.0200 L

concentration of NH₃ = 0.100 M

The concentration of OH- can be calculated from the Kb of NH₃ using the new concentration of NH4+:

Kb = [NH4+][OH-] / [NH3]

1.8 x 10⁵ = x² / 0.100

x = 0.0042 M

The new concentration of OH- is 0.0042 M, and the new pH will be:

pH = 14 - (-log[OH-])

pH = 12.38

(c) After adding 30.0 mL of 0.100 M HCl;

the volume of the solution is 40.0 mL or 0.0400 L

The moles of HCl added = (0.100 mol/L) x (0.0300 L)

moles of HCl added = 0.00300 mol

moles NH3 reacted = 0.00300 mol - 0.00300 mol

moles NH3 reacted = 0.00000 mol

[NH₄⁺] remaining [OH⁻] = 0

The concentration of OH- is 0 M, so the pH = 14 - (-log[OH-])

pH = 14

(d) After adding 40.0 mL of 0.100 M HCl;

moles HCl = (0.100 mol/L) x (0.0400 L)

moles HCl = 0.00400 mol

The volume of solution = 0.050 L

All NH₃ has reacted and the remaining moles of HCl = (0.00400 mol - 0.00300 mol) / 0.0500 L

the remaining moles of HCl = 0.00200 M

The concentration of H₃O⁺ can be calculated from the concentration of HCl:

0.00200 M HCl produces 0.00200 M H₃O⁺

pH = -log[H₃O⁺]

pH = -log(0.00200)

pH = 2.70

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To solve this problem, we need to use the equilibrium expression for the base dissociation reaction of pyridine:

C5H5N + H2O ↔ C5H5NH+ + OH-

where Kb is the base dissociation constant for pyridine, defined as:

Kb = [C5H5NH+][OH-]/[C5H5N]

We can use the Kb value to determine the concentration of hydroxide ions produced when pyridine dissolves in water. We can assume that the initial concentration of pyridine is equal to the final concentration of pyridine, since pyridine is a weak base and only partially dissociates in water.

We can also assume that the concentration of hydroxide ions produced is much smaller than the initial concentration of pyridine, so we can neglect its contribution to the total concentration of the solution.

First, we can calculate the concentration of hydroxide ions produced by pyridine:

Kb = [C5H5NH+][OH-]/[C5H5N]

1.7 x 10^-9 = [x][x]/[0.10-x]

where x is the concentration of hydroxide ions produced by pyridine.

Simplifying the expression, we get:

x^2 / (0.10 - x) = 1.7 x 10^-9

Since x is much smaller than 0.10, we can assume that (0.10 - x) is approximately equal to 0.10:

x^2 / 0.10 = 1.7 x 10^-9

Solving for x, we get:

x = sqrt(1.7 x 10^-9 x 0.10) = 1.2 x 10^-5 M

Therefore, the concentration of hydroxide

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0.2 M each of nitric acid and carbonic acid will have the same pH.

The pH of substances is mathematically given as:

pH - -log [H+]

Nitric and carbonic acid dissociates according to the following:

HNO3 ---------> H+ + NO3-

H2CO3 -------> H+ + HCO3-

Thus, both acids ionizes to produce the same number of moles of H+, thus, producing the same pH

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Answer:

10.56 moles of NO will be produced

Explanation:

The balanced reaction of ammonia, NH₃ with oxygen, O₂ is:

4NH₃ + 5O₂ → 4NO + 6H₂O

Where 5 moles of oxygen react with an excess of ammonia to produce 4 moles of nitrogen monoxude.

If 13.2 moles of O₂ react:

13.2 mol O₂ * (4 mol NO / 5 mol O₂) =

Answer: D

Explanation: trust

Answer:

Explanation:

D

Answer:

By using a filter.

Explanation:

Answer:

Tyre

In cold weather, you might have regularly kept a check on the pressure of the tyres of your car. Driving increases the temperature of the tyres, and, therefore, the air inside the tyre warms and expands. When you measure the pressure of the tyres at the time when you have just driven the car, it will be high. However, in cold weather, the pressure of the tyres will be low. So, it is recommended that you should always measure the pressure of the tyres.

To answer this, we need to use the equilibrium constant expression for Kp, which is Kp = (PC)^c/(PA)^a(PB)^b, where a, b, and c are the stoichiometric coefficients of A, B, and C, respectively. In this case, a = b = 1 and c = 2, so the expression becomes Kp = (PC)^2/(PA)(PB).

We can use the given partial pressures of A and B to calculate their product: (PA)(PB) = (0.500 atm)(0.500 atm) = 0.250 atm^2. Then, we can rearrange the equilibrium constant expression to solve for PC: PC = sqrt(Kp(PA)(PB)) = sqrt(340*0.250 atm^2) = 4.60 atm.

Therefore, the equilibrium partial pressure of C is 4.60 atm. It's important to note that this assumes the container is sealed and no gases escape or are added during the reaction.

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Answer:

Number of Protons: 45

Number of Neutrons: 58

Number of Electrons: 45

Explanation:

Have a nice day

Answer: The following can indicate that a chemical change has taken place, although this evidence is not conclusive: Change of odor.

Explanation:

Answer:

hey there !!

the mitochondrian is the cell organelle in which cellular respiration takes place and energy is produced during cellular respiration by break down of glucose in presence of oxygen to for energy units known as ATP ( adinosine tri - phosphate) molecule.

since it produces energy it is known as powerhouse of the cell.

i hope this helped.....you

A. Br and Br: The bond between two identical atoms is always pure covalent since both atoms have the same electronegativity. So, the bond between Br and Br is pure covalent.

B. O and F: Oxygen and fluorine have different electronegativities, and thus the bond between them is polar covalent. The shared electrons are closer to the more electronegative fluorine atom, creating a partial negative charge on the fluorine and a partial positive charge on the oxygen.

C. N and Cl: Nitrogen and chlorine have different electronegativities, and thus the bond between them is polar covalent. The shared electrons are closer to the more electronegative chlorine atom, creating a partial negative charge on the chlorine and a partial positive charge on the nitrogen.

D. Sr and O: Strontium is a metal, and oxygen is a nonmetal. Thus, the bond between them is ionic. The strontium atom loses two electrons, forming a cation with a 2+ charge, and the oxygen atom gains two electrons, forming an anion with a 2- charge. The electrostatic attraction between the oppositely charged ions forms the ionic bond.

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To prepare a liter of buffer solution with a pH of 10.40, you would weigh out 0.0745 g of sodium bicarbonate and 0.327 g of sodium carbonate and dissolve them in enough water to make a total volume of 1 liter.

Step 1: Calculate the pH of the buffer. The equilibrium constant expression for the reaction between sodium bicarbonate and sodium carbonate is: NaHCO₃ ⇌ Na⁺ + HCO₃¯Ka = [Na+] [HCO₃¯] / [NaHCO₃]We can assume that the concentrations of the two sodium salts are equal, so we can represent them as [Na₂CO₃] and [NaHCO₃]. Therefore, we can write the equilibrium constant expression as follows: Ka = [Na⁺] [HCO₃¯] / [NaHCO₃] = [Na⁺]² / [NaHCO₃]. The pH of the buffer can be calculated from the pKa and the ratio of the concentrations of the conjugate acid-base pair: pH = pKa + log ([A¯] / [HA])where [A¯] is the concentration of the conjugate base (in this case, HCO₃¯), [HA] is the concentration of the acid (in this case, NaHCO₃), and pKa is the negative logarithm of the acid dissociation constant (Ka).

pKa for the bicarbonate ion is 10.33. The ratio of the concentrations of the conjugate acid-base pair (NaHCO₃/Na₂CO₃) must be selected so that the pH of the buffer is 10.40. Using the Henderson-Hasselbalch equation: pH = 10.33 + log ([HCO₃¯] / [NaHCO3])10.40 = 10.33 + log ([HCO₃¯] / [NaHCO₃])[HCO₃¯] / [NaHCO₃] = 4.47. This means that the concentration of HCO3¯ must be 4.47 times greater than the concentration of NaHCO₃.

This ratio is equivalent to a 1:4.47 ratio, or a 1:3.47 ratio for NaHCO₃ :Na₂CO3 (since the total concentration of sodium salts is the sum of the two individual concentrations). Therefore, the ratio of NaHCO₃ to Na2CO₃ in the buffer should be 1:3.47.

Step 2: Calculate the amount of each salt required. To prepare a buffer solution with a pH of 10.40, you will need to weigh out the appropriate amounts of sodium bicarbonate and sodium carbonate.

To calculate these amounts, you need to know the desired volume of the buffer solution, the total concentration of the buffer, and the ratio of NaHCO₃ to Na₂CO₃ in the buffer. Assuming you want to prepare 1 liter of buffer, the total concentration of the buffer (C) can be calculated from the pH:pH = pKa + log ([A¯] / [HA])10.40 = 10.33 + log ([HCO₃¯] / [NaHCO₃])Let x be the concentration of NaHCO₃ (in mol/L). Then the concentration of HCO₃¯ is 4.47x and the concentration of Na₂CO3 is 3.47x. Therefore, C = [NaHCO₃] + [Na₂CO₃]= x + 3.47x= 4.47x= 4.47 (10^-4.40) mol/L= 0.00357 mol/L. Then, x = [NaHCO₃]= 0.00357 mol/L / (1 + 3.47)= 0.0008875 mol/L. Therefore,[NaHCO₃] = 0.0008875 mol/L[Na₂CO₃] = 3.47 x [NaHCO₃]= 0.00308 mol/L. The molecular weights of NaHCO₃ and Na₂CO₃ are 84.01 g/mol and 105.99 g/mol, respectively.

Therefore, the masses of the salts required are: mass of NaHCO₃ = 0.0008875 mol/L x 84.01 g/mol= 0.0745 g/Lmass of Na₂CO₃ = 0.00308 mol/L x 105.99 g/mol= 0.327 g/L. To prepare a liter of buffer solution with a pH of 10.40, you would weigh out 0.0745 g of sodium bicarbonate and 0.327 g of sodium carbonate and dissolve them in enough water to make a total volume of 1 liter.

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Answer:

150million km

Explanation:

hope it helps

Answer:

1 is not correct ......

All neutral sodium atoms have 11 protons and 11 electrons is about sodium atoms (Na) is not correct. Therefore, option 1 is correct.

When an atom has the same number of electrons and protons, it has the same number of negative (electrons) and positive (protons) electric charges (the protons).

As a result, the total electric charge of the atom is zero, and it is said to be neutral. As a result, all elements in the periodic table have neutral atoms.

The sodium atom contains 11 electrons. As sodium atom loses one electron to form sodium ion, sodium ion has ten electrons. Only sodium atoms have a strong reaction with water, whereas sodium ions do not.

Thus, All neutral sodium atoms have 11 protons and 11 electrons is about sodium atoms (Na) is not correct, option 1 is correct.

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The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

Answer:

A. Corn has changed over time due to selective breeding.

Hope this helps :)

Answer:

The volume of stock solution needed to make the solution is 1875 ml

Explanation:

The parameters given are;

The volume of 75 M solution of H₂SO₄ = 400 ml

The concentration of stock solution = 16.0 M

Number moles per liter of stock solution = 16 moles

Number of moles in required 400 ml solution = 0.4×75 = 30 M

Volume of stock solution that contains 30 M = 30/16×1 = 1.875 l

The volume of stock solution that is required = 1875 ml

In recent years, the output of ammonia has remained mostly steady. Ammonia output was projected to reach 150 million metric tonnes worldwide in 2022. With over 64.6 million metric tonnes produced, East Asia has the largest ammonia output.

Sodium metal is produced via the Castner method, which involves electrolyzing molten sodium hydroxide at a temperature of around 330 °C. At that temperature, the molten sodium would begin to dissolve in the melt; below that temperature, the liquid would harden.

One mole (or one gramme) of sodium chloride (NaCl) has a molecular weight of 58.44, making 58.44g the molecular weight of one gramme. You may create 1M NaCl by dissolving 58.44g of sodium chloride in a final amount of 1 litre.

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If you begin a reaction with radioactive oxygen in the water, the product that would be radioactive is hydrogen peroxide (H2O2).

1. Water (H2O) consists of two hydrogen atoms and one oxygen atom.
2. When a radioactive isotope of oxygen (O) is present in the water, it will combine with the hydrogen atoms to form hydrogen peroxide (H2O2).
3. Hydrogen peroxide is a compound that contains two hydrogen atoms and two oxygen atoms.
4. Since one of the oxygen atoms in hydrogen peroxide is radioactive, the entire compound becomes radioactive.

Therefore, if you start the reaction with radioactive oxygen in the water, the resulting product, hydrogen peroxide, would be radioactive.

It is important to note that the radioactivity in this context refers to the presence of a radioactive isotope, which emits radiation.

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Based on the picture and our knowledge of water molecule polarity, the solute molecule is most likely b. negatively charged or c. polar (with or without charge).

The water molecules are arranged around the solute molecule in a specific way. This arrangement is due to the polarity of water molecules, which have a slight positive charge on one end and a slight negative charge on the other. This arrangement allows water molecules to surround and interact with other charged or polar molecules.
From the picture, we can see that the water molecules are oriented in such a way that the slightly positive ends are facing towards the solute molecule, while the slightly negative ends are facing away from it. This suggests that the solute molecule is either negatively charged or polar, as these types of molecules can interact with the slightly positive ends of the water molecules.
Option a, positively charged, can be ruled out because the water molecules would be oriented differently if the solute molecule was positively charged. Similarly, option d, nonpolar, can also be ruled out because nonpolar molecules do not interact with water molecules in the same way as charged or polar molecules.
Therefore, based on the picture and our knowledge of water molecule polarity, the solute molecule is most likely b. negatively charged or c. polar (with or without charge).

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