1. How many grams of NaHCO, and CH₂COOH would be needed to inflate the same bag of 65.1L of CO₂ gas? CO₂ has a
density 1.57 times that of N₂ gas (d= 0.916 g/L) at the same temperature. (HINT: you need the density of CO₂ first)
NaHCO,+ CH,COOH ) CH,COONa +H,O + CO,

In alpha decay, the core loses two protons. In beta decay, the core either loses a proton or gains a proton.

In gamma decay, no adjustment of proton number happens, so the particle doesn't turn into an alternate component. Chemical reactions take place in radioactive decay.

The three fundamental forces in the nucleus—the "strong" force, the "weak" force, and the "electromagnetic" force—are the causes of alpha, beta, and gamma decay. In every one of the three cases, the outflow of radiation expands the core soundness, by changing its proton/neutron proportion.

The release of a helium nucleus, which consists of two protons and two neutrons, is known as alpha decay. The atomic number and total mass are both reduced by 2 as a result. A neutron decay into a proton, which gives off an electron, is known as beta decay. The atomic number is increased by one while the mass remains unchanged.

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When hydrogen sulfide is bubbled through a solution containing an unknown metal cation, a solid sulfide salt is formed. If 10.00 g of this sulfide is found to contain 2.22 g of sulfur,

Option (b) Cd2+ is the correct answer.

The chemical reaction can be written as  M2+ + H2S → MS (s) + 2H+Where M represents the unknown cation and S represents sulfur.

The ratio of the mass of sulfur in the sulfide to the mass of the entire sulfide can be calculated as follows:2.22 g S / 10.00 g sulfide

= 0.222

Since the sulfide salt has a 1:1 stoichiometric ratio with the cation, this value is equivalent to the fraction of the sulfide's molar mass which is sulfur.

The molar mass of sulfur is 32.06 g/mol, so the molar mass of the sulfide is:32.06 g/mol / 0.222 = 144.3 g/follow that we know the molar mass of the sulfide,

we can calculate the molar mass of the unknown cation. Here are the molar masses of the given metal cations:Pb2+: 207.2 g/molCd2+: 112.4 g/mol

Cu+: 63.5 g/molSn4+: 118.7 g/mol

To calculate the molar mass of the unknown cation, we subtract the molar mass of sulfur from the molar mass of the sulfide:

M unknown = 144.3 g/mol - 32.06 g/mol = 112.2 g/mol

The molar mass of the unknown cation is closest to the molar mass of Cd2+, so Cd2+ is the likeliest identity of the unknown cation. Option (b) Cd2+ is the correct answer.

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Answer:

Atoms

Explanation:

Energy, potential energy, is stored in the covalent bonds holding atoms together in the form of molecules. This is often called chemical energy.

Answer:

a metal is an element that readily forms positive ions (cations) and has metallic bonds

coke is a strong stimulant made from coca leaves

Answer: \(_{38}^{90}\textrm{Sr}\rightarrow _{36}^{86}\textrm{Kr}+_2^4\textrm{He}\)

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

General representation of an element is given as:   \(_Z^A\textrm{X}\)

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

General representation of alpha decay :

\(_Z^A\textrm{Sr}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha\)

The  balanced nuclear equation when the isotope Strontium-90 decays by Q-  decay is :

\(_{38}^{90}\textrm{Sr}\rightarrow _{36}^{86}\textrm{Kr}+_2^4\textrm{He}\)

Rutherford created the cathode-ray tube , is correct answer.

A cathode-ray tube, often known as a CRT, is a vacuum tube that houses one or more electron cannons that produce electron beams that are then bent to produce images on a phosphorescent screen. The visuals could be pictures (from a television or computer monitor), electrical waveforms (from an oscilloscope), radar targets, or other occurrences. The term "picture tube" is often used to refer to a CRT on a television. Additionally, CRTs have been utilised as memory devices, in which case the screen is not meant to be seen by outsiders. When electron beams were initially discovered, before it was realised that what was released from the cathode was an electron beam, they were referred to as "cathode rays."

Johann Wilhelm Hittorf and Julius Plücker made the discovery of cathode rays. Hittorf noticed that the cathode (negative electrode) was emitting some unidentified rays that might throw shadows on the glowing tube wall, indicating that the rays were moving in a straight line. Cathode rays could be redirected by magnetic fields and electric fields, as William Crookes and Arthur Schuster both demonstrated in 1890. The first "subatomic particles," called electrons by Irish scientist George Johnstone Stoney in 1891, were negatively charged particles smaller than atoms. J. J. Thomson was able to measure the charge-mass ratio of cathode rays in 1897 and demonstrate this. The Braun tube, created by the German inventor, was the first iteration of the CRT.

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As an atom's size shrinks, its electronegativity rises. This is due to the fact that electronegativity and atomic size are inversely related. Because of this, the atomic size decreases as electronegativity rises.

The contact between the nucleus and the surrounding electrons is reduced as the atomic radius rises, which results in a decline in electronegativity.

When comparing HNO3 and HNO2, HNO3 is a stronger acid because it has more electronegative atoms (in this case, more oxygen atoms).
When comparing HCIO and HCIO2, HCIO2 is a stronger acid because it has more electronegative atoms (in this case, more oxygen atoms).
When comparing HCIO and HBrO, HCIO is a stronger acid because it has fewer electronegative atoms (in this case, fewer oxygen atoms).
When comparing CCI3COOH and CBr2COOH, CCI3COOH is a stronger acid because it has more electronegative atoms (in this case, more chlorine atoms).

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Answer:

i believe it's c

Explanation:

my reason is that if you look at the electrons 2 is the most comm

Answer:

Boyle's law: A) Pressure and volume.

Charles's law: B) Temperature and volume.

Gay-Lussac's law: C) Pressure and temperature.

Explanation:

Hello,

In this case, since Boyle's law study the relationship between pressure and volume at constant temperature as an inversely proportional one, we have:

Boyle's law: A) Pressure and volume.

Next, since the Charles' law study the relationship between the volume and the temperature at constant pressure as a directly proportional one, we have:

Charles's law: B) Temperature and volume.

Then, since the Gay-Lussac's law study the relationship between the pressure and the temperature at constant volume as a directly proportional one as well, we have:

Gay-Lussac's law: C) Pressure and temperature.

Best regards.

Answer:

D, B, E

Explanation:

Answer: I think you have to look in the textbook

Explanation:

it's impossible to answer without the stinking textbook

Answer:

I think D

Explanation:

Kinetic energy has a direct relationship with mass, meaning as mass increases so does the kinetic Energy of an object.

The amount of aluminum that reacted is approximately 0.069 grams.

To determine the mass of aluminum that reacted, we need to use the ideal gas law and consider the partial pressure of hydrogen gas. First, we calculate the pressure of hydrogen gas by subtracting the partial pressure of water vapor from the total pressure. The pressure of hydrogen gas is 751 mmHg - 26.8 mmHg = 724.2 mmHg.

Next, we convert the pressure of hydrogen gas from mmHg to atm by dividing by 760 mmHg/atm, giving us 0.953 atm.

Using the ideal gas law equation PV = nRT, we can calculate the number of moles of hydrogen gas. The volume of hydrogen gas is given as 37.3 mL, which we convert to liters by dividing by 1000 mL/L, giving us 0.0373 L. The temperature is given as 27°C, which we convert to Kelvin by adding 273.15, giving us 300.15 K. The ideal gas constant R is 0.0821 L∙atm/(mol∙K).

Plugging the values into the ideal gas law equation, we can solve for the number of moles of hydrogen gas: (0.953 atm) * (0.0373 L) = n * (0.0821 L∙atm/(mol∙K)) * (300.15 K).

Simplifying the equation, we find that the number of moles of hydrogen gas is approximately 0.00139 moles.

Since the balanced chemical equation between aluminum and hydrochloric acid is 2Al + 6HCl → 2AlCl₃ + 3H₂, we can conclude that 2 moles of aluminum react to produce 3 moles of hydrogen gas.

Using this ratio, we can calculate the number of moles of aluminum that reacted: (0.00139 mol H₂) * (2 mol Al / 3 mol H₂) = 0.000926 moles Al.

Finally, we can convert moles of aluminum to grams using the molar mass of aluminum (26.98 g/mol): (0.000926 mol Al) * (26.98 g/mol) ≈ 0.069 g Al.

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The oxidation of co (carbon monoxide) to less-harmful co₂ (carbon dioxide) and the oxidation of hc (unburned hydrocarbons) to co₂ (carbon dioxide) and h₂o (water).

Oxidation is that the loss of electrons during a reaction by a molecule, atom or ion. Oxidation occurs when the oxidation number of a molecule, atom or ion is increased. the other process is called reduction, which occurs when there's a gain of electrons or the oxidation state of an atom, molecule, or ion decreases.

The term oxidation was first employed by Antoine Lavoisier to signify the reaction of a substance with oxygen. Much later, it had been realized that the substance, upon being oxidized, loses electrons, and therefore the meaning was extended to include other reactions in which electrons are lost, no matter whether oxygen was involved.

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The idea of the atomic nature of matter was first developed by John Dalton.

He introduced the atomic theory, which proposed that matter was made up of tiny, indivisible particles called atoms. This theory was based on his observations and experiments on the behavior of gases

.Dalton's atomic theory had several postulates that helped explain the properties of matter. These postulates were:

All matter is made up of atoms, which are tiny, indivisible particles

.Each element is composed of atoms that are identical in size, shape, and chemical properties.

Atoms of different elements have different sizes, shapes, and chemical properties.

Atoms combine in fixed ratios to form compounds, and the ratios of their masses are related by whole numbers.

Atoms are indestructible and cannot be created or destroyed in chemical reactions

.However, Dalton's atomic theory was later modified and expanded upon by other scientists, including J.J. Thomson, Ernest Rutherford, and Niels Bohr, as new discoveries about the structure and behavior of atoms were made.

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(a) The equilibrium constant expression for the dissociation of acetic acid is: Keq = [H3O+][OAc-]/[HOAc].

(b) Using the equilibrium concentrations of [H3O+] = [OAc-] = 4.19x10^-3 M and the initial concentration of [HOAc]o = 1.00 M, we can calculate the equilibrium concentration of undissociated acetic acid (HOAceq) using the equilibrium constant expression: Keq = [H3O+][OAc-]/[HOAc]o = (4.19x10^-3)^2/1.00 = 1.75x10^-5 M. To find the equilibrium concentration of HOAceq, we use the conservation of mass equation: [HOAc]o = [HOAceq] + [OAc-], which gives [HOAceq] = [HOAc]o - [OAc-] = 1.00 - 4.19x10^-3 = 0.996 M.

(c) The equilibrium constant Keq can be calculated using the values from part (b): Keq = [H3O+][OAc-]/[HOAc]o = (4.19x10^-3)^2/1.00 = 1.75x10^-5.

(d) It is not accurate to assume [HOAc]o = [HOAceq] when starting with completely undissociated acetic acid because at equilibrium, some of the acetic acid has dissociated into its component ions. Therefore, [HOAc]o is greater than [HOAceq].

(e) To find the equilibrium concentrations of hydronium and acetate ions in a 15.0 M acetic acid solution, we use the equilibrium constant expression: Keq = [H3O+][OAc-]/[HOAc]. Rearranging this equation and plugging in the values, we get [H3O+] = [OAc-] = sqrt(Keq x [HOAc]) = sqrt(1.75x10^-5 x 15.0) = 0.0416 M.

(f) At 50 °C, the solution will contain more acetate ion (OAc-) than what was calculated in (c) because an increase in temperature favors the dissociation of acetic acid, shifting the equilibrium to the right.

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Answer:

If the atom is neutral, then the number of protons(atomic number) equals the number of electrons. If the atom is an ion and has a charge, then that changes. If the charge is negative(ex. 1-), then you add that number to the number of protons to get the number of electrons. If the charge is positive, then you subtract(ex 1+) that number from the number of protons to get the number of electrons

Explanation:

The volume of oxygen at STP that will be obtained when 24.5 g of potassiumtrioxochlorate(V) crystals are heated is approximately 6.17 L.

Potassiumtrioxochlorate(V) is a chemical compound with the chemical formula KClO3. It is also known as potassium chlorate or chloric acid, potassium salt.

The chemical formula for potassiumtrioxochlorate(V) is KClO3.

We can start by writing a balanced chemical equation for the reaction :

2KClO3(s) → 2KCl(s) + 3O2(g)

From the equation, we can see that 2 moles of KClO3 produce 3 moles of O2. Therefore, we need to first calculate the number of moles of KClO3 in 24.5g of the compound:

Since 2 moles of KClO3 produce 3 moles of O2, we can use this ratio to calculate the number of moles of O2 produced:

moles of O2 = (3/2) x moles of KClO3 = (3/2) x 0.2 mol = 0.3 mol

Finally, we can use the ideal gas law to calculate the volume of O2 at STP:

PV = nRT

Where

Rearranging the equation, we get:

V = nRT/P = (0.3 mol)(0.08206 L atm/mol K)(273 K)/(1 atm) = 6.17 L

Therefore, the volume of oxygen at STP that will be obtained when 24.5 g of potassiumtrioxochlorate(V) crystals are heated is approximately 6.17 L.

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The major organic product generated in the reaction is an alcohol, but without the specific starting material or additional details, the exact region- and stereochemical details cannot be determined.

The reaction you provided is a two-step process:

Step 1: Hg(O Ac)2 + H2O

Step 2: NaBH4

In the first step, Hg(OAc)2 (mercury(II) acetate) and H2O (water) are used. This step is known as the oxymercuration-demur curation reaction. Hg(OAc)2 adds an acetate group (-OAc) and a hydronium ion (H3O+) to the double bond of the starting material.

In the second step, NaBH4 (sodium borohydride) is used as a reducing agent. It reduces the intermediate compound formed in the first step by adding a hydride ion (H-) to the carbon attached to the mercury atom. This results in the removal of the mercury atom and the formation of an alcohol group (-OH) in its place.

The major organic product generated from this reaction is an alcohol. The region chemistry of the reaction depends on the position of the double bond in the starting material.

The stereochemistry is not specified in the given information, so the specific stereochemical details cannot be determined without additional information.

Please provide the starting material or more details about the reaction to provide a more specific explanation and draw the major organic product.

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Answer:

That is true

Explanation:

If the IR spectrum of a crude product shows peaks at 1691 cm⁻¹ and 1702 cm⁻¹, the peak corresponds to the presence of a carbonyl group (C=O).

The carbonyl group is a functional group that is responsible for many of its chemical and physical properties. The C=O bond absorbs infrared radiation in this region, resulting in a characteristic peak. The intensity and shape of the peak provide information about the strength of the bond, its environment, and the presence of any neighboring functional groups. This information is important in determining the identity of the compound and its structure, as well as for studying the chemical reactions and interactions involving the carbonyl group.

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Answer:

94.16g of N2O

50.88g of O2

Explanation:

O2 reacts with N2 as follows:

2N2 + O2 → 2N2O

To find moles of N2O produced we need to convert the mass of each gas to moles to find limiting reactant and the moles of N2O that could be produced:

Moles N2 (Molar mass: 28g/mol):

60g N2 * (1mol / 28g) = 2.14 moles N2

Moles O2 (Molar mass: 32g/mol):

85g O2 * (1mol / 32g) = 2.66 moles O2

For a complete reaction of 2.14 moles of N2 are needed:

2.14 mol N2 * (1mol O2 / 2 mol N2) = 1.07 moles of O2.

As there are 2.66 moles of O2, reactant in excess is O2 and will remain:

2.66 moles - 1.07 moles =

1.59 moles O2. The mass is:

1.59 moles O2 * (32g / mol) =

And there are produced:

2.14 mol N2 * (2 moles N2O / 2 moles N2) = 2.14 moles N2O.

The mass is (44g/mol for N2O):

2.14 moles N2O * (44g/mol) =

The elements listed on the bottom of the reactivity list for all of the following except fireworks and is denoted as option C.

This is referred to the extent in which an element is able to take part in a chemical reaction.

The elements founds at the bottom of the reactivity list include gold which can't be used for making fireworks.

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Answer:

D is the answer. (They turn red litmus paper blue and taste bitter.)

Explanation:

The removal of the alcohol seen in the conversion of the nasal decongestant pseudoephedrine to the illicit drug methamphetamine constitutes the type of reduction process.

Redox is a type of chemical reaction in which the oxidation state of the substrate changes. Oxidation generally can be defined as the loss of electrons or increase in the oxidation state, while reduction is the gain of electrons or decrease in the oxidation state. The removal of alcohol observed in the conversion of pseudoephedrine to the illicit drug methamphetamine constitutes a reduction process. The "red phosphorus method" is a chemical reduction reaction that converts pseudoephedrine to methamphetamine using red phosphorus/hydrogen iodide oxidation chemistry.

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Answer:

downwelling also allows for deep ocean oxygenation to occur because these waters are able to bring dissolved oxygen down from the surface to help facilitate aerobic respiration in organisms throughout the water column

The mass of magnesium chloride produced is 179.15 grams.

The balanced chemical equation for the reaction is:

Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)

From the equation, we can see that 1 mol of Mg reacts with 2 mol of HCl to produce 1 mol of MgCl₂ and 1 mol of H₂.

So, to determine the limiting reactant, we need to calculate the moles of MgCl₂ that can be formed from each reactant:

Moles of MgCl₂ from Mg = 3.79 mol Mg × (1 mol MgCl₂/1 mol Mg) = 3.79 mol MgCl₂

Moles of MgCl₂ from HCl = 3.75 mol HCl × (1 mol MgCl₂/2 mol HCl) = 1.88 mol MgCl₂

Since the amount of MgCl₂ that can be formed is limited by the amount of HCl available, HCl is the limiting reactant.

The stoichiometry of the reaction tells us that 2 moles of HCl react to produce 1 mole of MgCl₂. Therefore, the number of moles of MgCl₂ produced in the reaction is:

1.88 mol MgCl2

Finally, we can use the molar mass of MgCl2 to calculate the mass produced:

Molar mass of MgCl₂ = 95.211 g/mol

Mass of MgCl₂ produced = 1.88 mol × 95.211 g/mol = 179.15 g.

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Answer:

In non-polar covalent bonds, the electrons are equally shared between the two atoms. For atoms with differing electronegativity, the bond will be a polar covalent interaction, where the electrons will not be shared equally.

Explanation:

i did some reasherch so there^^