−17.1−(−714)+(−22) =?

Answer:

39.54 is greater than 39.4

Step-by-step explanation:

Answer:

39.54 is LESS than 39.4

The correct statements about the capacity of swimming pool are (a) and (d)

The capacity of a swimming pool is given by C = l × w × (d₁ + d₂)/2

where l is the length,

w is the width,

d₁ is the depth of the shallow end,

and d₂ is the depth of the deep end of the pool.

If C = 9,216 ft, l = 48 ft, w = 24 ft, and d₂ = 12 ft, then d₁  would be,

9216 = 48 × 24 × (d₁ + 12)/2

d₁ + 12 = (9216 × 2) / (48 × 24)

d₁ + 12 = 16

d₁ = 4 ft

And formula for the depth of the shallow end would be,

d₁ = (2C/lw) - d₂

Therefore, the correct statements are (a) and (d)

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The complete question is:

The capacity of a swimming pool is given by C = l × w × (d1 + d2)/2, where l is the length, w is the width, d 1 is the depth of the shallow end, and d 2 is the depth of the deep end of the pool.

Select all the correct statements.

a) The depth of the shallow end is given by d1 = 2C/lw - d2.

b) If C = 9,216 ft, l = 48 ft, w = 24 ft, and d2 = 16 ft, then d1 = 4 ft.

c) The depth of the shallow end is given by 2C - d2/lw .

d) If C = 9,216 ft, l = 48 ft, w = 24 ft, and d2 = 12 ft, then d1 = 4 ft.

The remaining Kit volume in the syringe is sufficient to correct the dose to 20 mCi.

To solve this problem, we can use the concept of radioactive decay and the decay factor. Here's how we can calculate the required volume to correct the dose:

Determine the initial activity of the kit:

Initial activity = 180 mCi

Calculate the decayed activity at 9:30 (after 1.5 hours):

Decay factor = 0.841

Decay activity = Initial activity * Decay factor

Calculate the remaining activity after withdrawing 20 mCi at 8 am:

Remaining activity = Initial activity - 20 mCi

Calculate the remaining activity at 9:30:

Remaining activity at 9:30 = Remaining activity * Decay factor

Calculate the desired activity at 9:30 (20 mCi):

Desired activity at 9:30 = 20 mCi

Calculate the volume needed to achieve the desired activity:

Volume needed = Desired activity at 9:30 / Remaining activity at 9:30 * Volume at 9:30

Calculate the remaining volume at 9:30:

Remaining volume = Volume at 8 am - Volume withdrawn - Volume accidentally discharged

Calculate the volume that needs to be added:

Volume to be added = Volume needed - Remaining volume

Let's perform the calculations step by step:

Determine the initial activity of the kit:

Initial activity = 180 mCi

Calculate the decayed activity at 9:30 (after 1.5 hours):

Decay factor = 0.841

Decay activity = 180 mCi * 0.841 = 151.38 mCi

Calculate the remaining activity after withdrawing 20 mCi at 8 am:

Remaining activity = 180 mCi - 20 mCi = 160 mCi

Calculate the remaining activity at 9:30:

Remaining activity at 9:30 = 160 mCi * 0.841 = 134.56 mCi

Calculate the desired activity at 9:30 (20 mCi):

Desired activity at 9:30 = 20 mCi

Calculate the volume needed to achieve the desired activity:

Volume needed = (Desired activity at 9:30 / Remaining activity at 9:30) * Volume at 9:30

Volume at 9:30 = Remaining volume = 30 ml - (30 ml / 2) = 15 ml

Volume needed = (20 mCi / 134.56 mCi) * 15 ml = 2.236 ml

Calculate the remaining volume at 9:30:

Remaining volume = 30 ml - (30 ml / 2) = 15 ml

Calculate the volume that needs to be added:

Volume to be added = Volume needed - Remaining volume = 2.236 ml - 15 ml = -12.764 ml

Since the calculated volume to be added is negative, it means that no additional volume is required. The remaining Kit volume in the syringe is sufficient to correct the dose to 20 mCi.

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The length of the shorter string is 18 inch while that of the longer string is 30 inch.

An equation is an expression used to show the relationship between two or more variables and numbers.

Let s represent the length of the shorter string.

One piece is 12 inches longer than the other

Length of longer string = s + 12

Since a 48-inch piece of string is cut into two pieces. Hence:

s + (s + 12) = 48

2s + 12 = 48

2s = 36

s = 18

Length of longer string = 18 + 12 = 30

The length of the shorter string is 18 inch while that of the longer string is 30 inch.

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Sally's average annual percentage gain is approximately 5.26%.

To calculate Sally's average annual percentage gain, we can use the formula:

Average Annual Percentage Gain = (Profit / Initial Investment) * (1 / Time) * 100

Profit = $2500

Initial Investment = $19000

Time = 2.5 years

Substituting the values into the formula:

Average Annual Percentage Gain = (2500 / 19000) * (1 / 2.5) * 100

= (0.1316) * (0.4) * 100

= 5.26

Therefore, Sally's average annual percentage gain is approximately 5.26%.

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9514 1404 393

Answer:

  x = 5

Step-by-step explanation:

We can subtract 3x, add 12, and divide by 4.

  7x -12 = 3x +8

  4x -12 = 8 . . . . . . . . subtract 3x

  4x = 20 . . . . . . . . . . add 12

  x = 5 . . . . . . . . . . . . divide by 4

Answer:

W=15cm

L=19cm

The dimensions are 15cm by 19cm

Step-by-step explanation:

P=2W+2L

L=4+W

68=2W + 2(4+W)

68=4W+8

60=4W

W=15cm

L=4+15

L=19cm

Answer:

Please help im on that 2dd

Step-by-step explanation:

dddd

Answer:

Where is the picture?

Step-by-step explanation:

N/A

Answer:

8

Step-by-step explanation:

23 - 7

= 16

16 ÷ 2

= 8

u thought of 8 ;)

Answer:

number maybe 8...

Step-by-step explanation:

because if you will double 8 then you will get 16 and if you will add 16 with 7 you will get 23....

Answer:

A: numerical

B:catergorical

C:catergorical

Step-by-step explanation:

Step-by-step explanation:

Given :-

And we need to find out the volume of the wood. Density , volume and mass are related as ,

Density :-

\(\implies\rm Density =\dfrac{Mass}{Volume}\)

Substitute the respective values :-

\(\implies\rm Density =\dfrac{Mass}{Volume}\\\\\rm\implies 0.065 kg/m^3=\dfrac{3.5kg}{V}\\\\\rm\implies Volume = \dfrac{3.5kg}{0.065 kg/m^3}\\\\\implies\boxed{\red{\rm Volume = 53.84 m^3}}\)

Hence the volume is 53.84 m³ .

Without knowing the total number of coins or the ratio between one dollar and two dollar coins in the jar, we cannot accurately determine the number of two dollar coins.

Amadi has a jar with both one dollar and two dollar coins. The question is asking how many of the coins in the jar are two dollar coins.
To determine the number of two dollar coins, we need more information. The question does not provide any details about the total number of coins or the ratio between one dollar and two dollar coins in the jar. Without this information, it is not possible to give an accurate answer.
If we assume that the jar contains a total of 100 coins, we can use algebra to solve for the number of two dollar coins.

Let's say the number of two dollar coins is x. Then, the number of one dollar coins would be 100 - x.
Since the value of the two dollar coins is double the value of the one dollar coins, we can set up the equation 2x + 1(100 - x) = total value of coins.
Simplifying the equation, we get 2x + 100 - x = total value of coins.
Combining like terms, we have x + 100 = total value of coins.
Since we don't know the total value of coins, we cannot solve for x. Therefore, we cannot determine the number of two dollar coins without additional information.

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Answer:

D)

Step-by-step explanation:

Answer:7/8

Step-by-step explanation:

Answer:

c. The sampling distribution of the sample means can be assumed to be approximately normal because the distribution of the sample data is not skewed

Step-by-step explanation:

From the given data, we have;

The category of the sample = Retired individuals

The number of participants in the sample = 20

The duration of program = six-weeks

The improvement seen by most participants = Little to no improvement

The improvement seen by few participants = Drastic improvement

Therefore, given that the participants are randomly selected and the majority of the participants make the same observation of improvement in the time to walk a mile, we have that, the majority of the outcomes show little difference in walk times after the program, therefore, the distribution of the sample data is not skewed and can be assumed to be approximately normal

The equation of the line that is parallel to the line x + y + 2 = 0 and passing through (2, -2) will be x + y = 0.

Let the equation of the line be ax + by + c = 0. Then the equation of the parallel line that is parallel to the line ax + by + c = 0 is given as,

ax + by + d = 0

The equation of the line is given below.

y = - x - 2

x + y + 2 = 0

Then the equation of the line that is parallel to x + y + 2 = 0 is given as,

x + y + d = 0

The line is passing through (2, -2), then we have

2 + (-2) + d = 0

d = 0

The equation of the line that is parallel to the line x + y + 2 = 0 and passing through (2, -2) will be x + y = 0.

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Factoring is an important process that helps us understand more about our equations. Through factoring, we rewrite our polynomials in a simpler form, and when we apply the principles of factoring to equations, we yield a lot of useful information. There are a lot of different factoring techniques.

Step-by-step explanation:

\(\sqrt[3]{t^{2} } + 4\sqrt{t^{3} } \\=t^{\frac{2}{3} } + 4t^{\frac{3}{2} }\\\\then, \\u` = \frac{2}{3}t^{-\frac{1}{3}} + 6t^{\frac{1}{2} }\)

The true expression about the account is D.) It is the sum of the initial amount and the additional amount after d days.

The answer is D because it represents the sum of the initial amount and the additional amount after d days. The initial amount is $10 and Owen adds $0.50 to the account each day for a number of days, represented by d.

By subtracting 1 from d, the expression ensures that on the first day (when d=1), only the initial $10 is counted. On each subsequent day, the additional amount of $0.50 is added to the total. Therefore, the expression 10+0.5(d−1) gives the amount of money in Owen's account after d days.

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Answer:

im study about history it was my favourite subject!

Answer:

2/3's of a football field is 1280

Step-by-step explanation:

were going to take 1920 and were going to divide that by 3.

1920/3 = 640

After that your going to multiply 640 by 2

640(2) = 1280

So your answer is 1280

Answer:

(3) Median

Step-by-step explanation:

I would say median because it most likely wouldn't be any of the others. Mean would be thrown off with the outlier 0.80. Mode wouldn't really work for this. I don't think standard deviation would work because this isn't coninuous data.

Hope it helps and is correct!

Answer:

Answer and steps in picture.

Answer:

(x+11)(x-11)

Step-by-step explanation:

(x+11)(x-11)

Answer:

(x+11)(x-11)

Step-by-step explanation:

If you factor it out, it works.

The minimum sample size required to construct a 95% confidence interval for the population mean is 16.

To determine the minimum sample size required to construct a 95% confidence interval for the population mean circumference of tennis balls within 0.05 inch, we need to use the formula for the margin of error:

Margin of error = Z* (σ/√n)

Where Z* is the z-score corresponding to the desired confidence level, σ is the population standard deviation, and n is the sample size.

Since we want a 95% confidence interval, Z* = 1.96 (from a standard normal distribution table).

We are given that σ = 0.10 inch and we want the margin of error to be 0.05 inch. Plugging in the values, we get:

0.05 = 1.96 * (0.10 / √n)

Solving for n, we get:

n = [(1.96 * 0.10) / 0.05]² = 15.36

We can't have a fractional sample size, so we round up to the nearest whole number. Therefore, the minimum sample size required is 16.

This means that the manufacturer needs to randomly select and measure the circumferences of at least 16 tennis balls to estimate the population mean circumference with 95% confidence and a margin of error of 0.05 inch.

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a. The answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. The answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

a. To represent 20 longs in base seven, we need to find the fewest number of multibase blocks required.

In base seven, we have the following conversions:

1 long = 1 unit

1 flat = 10 units

1 block = 10 flats

To represent 20 longs, we can use 2 flats (each flat representing 10 units) and 0 units since there are no remaining units.

So, the fewest number of multibase blocks required would be 2 flats.

Therefore, the answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. To represent 10 longs in base three, we need to find the fewest number of multibase blocks required.

In base three, we have the following conversions:

1 long = 1 unit

1 flat = 3 units

1 block = 3 flats

To represent 10 longs, we can use 3 flats (each flat representing 3 units) and 1 unit since there is one remaining unit.

So, the fewest number of multibase blocks required would be 3 flats and 1 unit.

Therefore, the answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

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