Here's an example of sets that meet the given descriptions:
a. A and B are disjoint sets:
U (Universal Set)
__________________________
| | |
| A | B |
|___________|____________|
In this example, set A and set B are shown as separate circles with no overlapping region, indicating that they are disjoint.
b. A is a proper subset of B:
U (Universal Set)
__________________________
| |
| B |
| _________________|
| | |
| | A |
| |_________________|
In this example, set A is completely contained within set B, indicating that A is a proper subset of B.
c. A∪B∪C = U, but A, B, and C are all mutually disjoint:
U (Universal Set)
__________________________
| |
| A |
|_________________________|
| |
| B |
|_________________________|
| |
| C |
|_________________________|
In this example, the sets A, B, and C are shown as separate circles with no overlapping regions. However, when you combine the three sets A, B, and C, their union covers the entire universal set U.
Please note that these are just visual representations, and the actual elements of the sets are not specified.
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Help pls I will give Brianlist
Answer:
A
Step-by-step explanation:
Hope this helps :)
Answer:
A
Step-by-step explanation:
a factory worker productivity is normally distributed. one worker produces an average of 75 units per day with a standard deviation of 20. another worker produces at an average rate of 65 per day with a standard deviation of 21. what is the probability that in 1 week (5 working days), worker 1 will outproduce worker 2
By using the concept of Probability, 0.771 is the probability by which worker 1 will outproduce worker 2
Let Xi be the random variable representing the number of units the first worker produces in day i.
Define X = X₁+ X₂ + X₃ + X₄ + X₅ as the random variable representing the number of units the first worker produces during the entire week.
We know that Mean =(Sum of all quantities)/(Number of quantities)
Mean=75 and number of quantities =5(given)
Therefore, from the formula
=>Sum of all quantities=75×5
or We can Say that X₁+ X₂ + X₃ + X₄ + X₅=375--------------------------------(eq1)
Now, talking about the standard deviation of first worker
We know that standard deviation = \(\frac{\sqrt{(Each quantity - Mean)^{2} } }{\sqrt{Total Number of quantities} }\)
We are given standard deviation of first worker as 20,
Therefore 20×\(\sqrt{Total Number of quantities}\) = \(\sqrt{(Eachquantity -Mean)^{2} }\)
20√5 = √[(X₁ - Mean)²+(X₂ - Mean)²+(X₃ - Mean)²+(X₄ - Mean)²+(X₅ - Mean)²]-(eq2)
Therefore, from eq1 and eq2,
we get Mean(µx) =375 and standard deviation(σ\(x\)) =20√5
Similarly, define random variables Y₁, Y₂, . . . , Y₅ representing the number of units produces by the second worker during each of the five days and define Y = Y₁ + Y₂ + Y₃ + Y₄ + Y₅.
From the Mean formula,
we get Y₁ + Y₂ + Y₃ + Y₄ + Y₅=(65×5)--------------------------------(eq3)
Standard deviation of second worker = 21(given),
So using the standard deviation formula, we get
Therefore 21×\(\sqrt{Total Number of quantities}\)=\(\sqrt{(Eachquantity -Mean)^{2} }\)
21√5=√[(Y₁ - Mean)²+(Y₂ - Mean)²+(Y₃ - Mean)²+(Y₄ - Mean)²+(Y₅ - Mean)²]-(eq4)
Therefore, from eq3 and eq4,
we get Mean(µy) =325 and standard deviation(σy) =21√5
Of course, we assume that X and Y are independent. The problem asks for P(X > Y ) or in other words for P(X − Y > 0).
It is a quite surprising fact that the random variable U = X −Y , the difference between X and Y ,is also normally distributed with mean µU = µx−µy = 375−325 = 50 and standard deviation σu ,where σ\(u^{2}\) = σ\(x^{2}\)+σ\(y^{2}\) =400·5+441·5 = 841·5 = 4205
It follows that σu=√4205.
Now probability of first worker(P₁)=375/√4205
probability of second worker(P₂) =325/√4205
We can clearly see P₁>P₂
Difference in Probability of both workers(P)=P₁-P₂
=>P=[(375/√4205)-(325/√4205)]
=>P=50/√4205
=>P=50/64.84
=>P=0.771
Hence, probability by which worker 1 will outproduce worker 2 is 0.771.
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A pentagon has 3 congruent sides and 2 other congruent sides. The perimeter of the pentagon is 36 centimeters. The three long congruent sides are 2 centimeters longer than the two shorter congruent sides.
Let x = length of a short side
Let y = length of a long side
The system of equations can be used to represent the situation.
y = x + 2
2x + 3y = 36
What is the length of one of the shorter congruent sides?
Answer:
The shorter side of pentagon is 6cm long
Step-by-step explanation:
Given two equations are:
\(y = x + 2\\2x + 3y = 36\)
We can use any one of the methods to solve the simultaneous linear equations
As it is also given that x is the length of shorter side, we have to find the value of x
Using the substitution method
We will put the value of y i.e. x+2 in the 2nd equation
So,
\(2x+3(x+2) = 36\)
Simplification gives us:
\(2x+3x+6 = 36\\5x+6 = 36\\5x = 36-6\\5x = 30\\x = \frac{30}{5}\\x =6\)
Hence,
The shorter side of pentagon is 6cm long
PLEASE PLEASE HELP REALLY QUICK❤️❤️
Answer:
Sorry
Step-by-step explanation:
Sorry I don't know the answer because I haven't learned this yet. Hope you get your answer!
Find the value of x that will make A parallel to B
Answer:
x = 11
Step-by-step explanation:
The 2 angles are alternate exterior angles and congruent, thus
6x - 2 = 5x + 9 ( subtract 5x from both sides )
x - 2 = 9 ( add 2 to both sides )
x = 11
I need help asap please!!
Answer:
n=130 is the answer because you habe to subtract it from 360
PLEASE HELP!! I WILL MARK THE FIRST CORRECT ANSWER BRAINLIEST!!)) A cylinder has a height of 16 meters and a radius of 14 meters. What is its volume? Use
* 3.14 and round your answer to the nearest hundredth.
cubic meters
Answer:
volume is 9847.04 \(m^{3}\)
Step-by-step explanation:
V = π * \(r^{2}\) * h
V = 3.14 * \(14^{2}\) * 16
=9847.04 \(m^{3}\)
Hope you could understand.
If you have any query, feel free to ask.
Which rational number is between -2 and -3
Answer:
There are infinite numbers between -2 and -3
Step-by-step explanation:
First off these numbers:
-2.1 or this number as any equivilant fraction.
-2.2 or this number as any equivilant fraction
-2.3 or this number as any equivilant fraction
-2.4 or this number as any equivilant fraction
-2.5 or this number as any equivilant fraction
-2.6 or this number as any equivilant fraction
-2.7 or this number as any equivilant fraction
-2.8 or this number as any equivilant fraction
-2.9 or this number as any equivilant fraction
any numbers that are reepeating like : -2.3333333333.....
and any numbers that end and don't go on forever without a single repeating number. -2.485485485485485485485485..... is not rationally repeating. -2.444444444444 is rational.
Justin did push-ups for the past 555 days.The following data points are the number of push-ups he did each day.
21,24,24,27,29
Find the standard deviation of the data set.
Round your answer to the nearest hundredth.
push-ups
Answer: σ: 2.76
Step-by-step explanation:
Count, N: 5
Sum, Σx: 125
Mean, μ: 25
Variance, σ2: 7.6
Steps
look at attached pic for formula
σ^2 = \(\frac{Σ(xi - μ)^{2} }{N}\)
\(\frac{(21 - 25)2 + ... + (29 - 25)2}{5}\)
⇒ \(\frac{38}{5}\)
⇒ 7.6
σ = \(\sqrt{7.6}\)
⇒ 2.756809750418
⇒ or 2.76
Suppose a charity received a donation of 17.7 million. If this represents 49% of the charity's donated funds, what is the total amount of its donated funds? Round your answer to the nearest million dollars
Bottom Text
Answer:
36
Step-by-step explanation:
if 17.7 million = 49%, then 17.7 / 49 = 1% or .361 million. Times 100 = 36.1 million rounded to 36 million.
how many solutions does 3x-1=3 have?
Answer:
one solution
Step-by-step explanation:
3x-1=3
Add 1 to each side
3x-1+1=3+1
3x = 4
Divide by 3
3x/3 = 4/3
x = 4/3
There is one solution
Answer:
One solution
Step-by-step explanation:
3x=4
x=4/3
no other answer
on a number line,AB=3 2/3.The position of point B is 2/5.What is the position of point A
Answer:
-49/15
Step-by-step explanation:
To determine the position of point A on the number line, we need to subtract the length of segment AB from the position of point B.
Given that the position of point B is 2/5, we can subtract the length of AB, which is 3 2/3, from 2/5.
To subtract fractions, we need to find a common denominator. The least common denominator for 3/3 and 5 is 15.
Converting 3 2/3 to an improper fraction:
3 2/3 = (3 * 3 + 2)/3 = 11/3
Subtracting the fractions:
2/5 - 11/3 = (2 * 3 - 11 * 5)/(5 * 3) = (6 - 55)/15 = -49/15
The position of point A is -49/15 on the number line.
(If you like this answer i would appreciate if u give brainliest but otherwise, i hope this helped ^^)
A pitcher of lemonade holds 147 ounces if serving 15 ounces then how many servings are in one pitcher?
Answer: 9.2
Step-by-step explanation:
You devide 15 in the number of ounces in the pitcher
There are 10 servings in one pitcher.
What are comparing quantities?Comparing quantities is the qualitative relation between two quantities which reflects the relative size of both the quantities
Now it is given that,
Number pitcher of lemonade in 147 ounces = 1 Pitcher
Now, if 1 serving is 15 ounces
Therefore, Number of servings in 15 ounces = 147/15
⇒ Number of servings in 15 ounces = 9.8
⇒ Number of servings in 15 ounces ≈ 10
So, Number of servings in 1 Pitcher = 10
Thus, there are 10 servings in one pitcher.
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O Rachel was checking the weight of a gold nugget and a piece of fool's gold. Together
they weighed 120.5 grams. If the fool's gold was 23.90 grams, how much did the gold
nugget weigh?
Answer:
96.6
Step-by-step explanation:
120.5 subtracted by 23.90 give you how much the gold nugget weight.
Solve the following:
2x-7\4 = x+3/3
Hope u get this!
Answer:
hello it is so
Step-by-step explanation:
simple simply do the division if don't I can
what is y= (x+2) ^2 vertex, axis of symmetry, direction of opening, max or min and y intercept
Answer:
Vertex: (-2, 0)
Axis of symmetry: x = -2
Direction of opening: Upwards
Min: 0
Y-intercept: 4
Step-by-step explanation:
Let us graph this line, and then pull out the details we need. See attached.
What do all of these different things mean?
Vertex: This is where the graph intercepts the axis of symmetry (x = -2, see below) and is at point (-2, 0) for this graph.
Axis of Symmetry: This is the line that the graph is symmetrical across. The "center" of the graph. Here, it is x = -2.
Direction of Opening: The direction that the graph is going/opening towards. In this case, it is upwards.
Min: The minimum (in this case) value, the lowest y-coordinate. This is 0 here.
Y-intercept: The point at which the line intercepts the y-axis. This is 4 here.
a function is defined on the complex numbers by where and are positive numbers. this function has the property that for each complex number , is equidistant from both and the origin. given that , find
The value of p+q = 403,For the given complex number a+bi and \(b^{2} =\frac{p}{q}\)
where p and q are co-primes
F(z)= (a+ib)z⇒this is equidistant from "0" and "z"
Given modulus of complex number (a+ib) = 10 ; \(b^{2} =\frac{p}{q}\) p and q ∈Z
G.C.D of ( p and q)=1
(a+ib)z equidistant from "0" and "z"
\(&\Rightarrow|(a+i b) z-z|=|(a+i b) \bar{z}-0|\\&|z(a+i b-1)|=|(a+i b) \bar{z}|\\&[\bar{z}||(a-1)+i b|=| z|(a+i b)|\\&|a-1+i b|=|a+i b|\\&\sqrt{(a-1)^2+b^2}=\sqrt{a^2+b^2}\\&|a+i b|=10 \quad a^2+1-2 a+b^2=x^2+b^2\\&\sqrt{a^2+b^2}=10\\&a=1 / 2\\&a^2+b^2=100\\&b^2=100-\frac{1}{4}\\\)
\(b^{2} =\frac{399}{4}\)
p = 399 and q= 4
p+q= 399+4
p+q=403
Hence the value of p+q = 403
Complete question:A function f is defined on the complex number by f (z) = (a + bi)z, where 'a' and 'b' are positive numbers. This function has the property that the image of each point in the complex plane is equidistant from that point and the origin. Given that |a+bi|=8 and that\(b^{2} =\frac{p}{q}\) where p and q are coprime. Find the value of (p+q)
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Determine the approximate value of the vehicle 10 years after purchase
Step 1
Write the expression for the current value of the vehicle in any given year
\(\begin{gathered} P_{}=ab^t \\ P_{}\text{ = value at any year} \\ a=Original\text{ purchase price = \$25000} \\ b=1-\frac{8}{100}=1-0.08=0.92 \\ t=\text{ time= 10years} \end{gathered}\)Step 2
Substitute and get the price of the vehicle after 10 years
\(\begin{gathered} P=25000(0.92)^{10} \\ P=10,859.71136\text{ dollars} \end{gathered}\)To the nearest whole number the cost of the vehicle after 10 years = $10,860
Between what two integers is √95?
Answer:
Between 9 and 10.
Step-by-step explanation:
We know that √81 = 9 and that √100 = 10.
Since √95 is between √81 and √100, we know it will be between 9 and 10.
√95 = 9.74679
In Lily's garden, there are 5 rose bushes the first year. Each year, she adds two new rose bushes. She
has 20 tulip plants the first year and loses 3 each year. When will the number of rose bushes equal
the number of tulip plants? Use graphing to find the solution.
Step-by-step explanation:
Let x = the number of years since the first year and let y = the total number of plants.
Roses: y = 5 + 2x
Tulips: y = 20 – 3x
You can use elimination to solve.
y = 5 + 2x
(-)y = 20 – 3x
0 = -15 + 5x
15 = 5x
3 = x
This means that 3 years after the first year, the number of rose bushes equals the number of tulip plants.
The graphs appear to
intersect at (3, 11) which verifies that x=3
The number of rose bushes will equal the number of tulip plants after 3 years
How to determine the year?The given parameters are:
Rose bushes
Initial = 5Additional = 2Tulip bushes
Initial = 20Additional = -3So, the number of rose bushes and tulip bushes each year is:
y = 5 + 2x
y = 20 - 3x
From the graph of both equations, we have:
(x,y) = (3,11)
Hence, the number of rose bushes will equal the number of tulip plants after 3 years
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A matched design A/B test is likely to be analyzed using
Independent samples t-test
Paired sample t-test
Logistic regression analysis
Analysis of variance (ANOVA)
All of the above
Matched design A/B tests are usually analyzed using the paired sample t-test. Hence, the answer is option B (Paired sample t-test).
The paired sample t-test is used to compare the mean differences between two related groups. The test is used to analyze before and after results of an experiment, the two groups of subjects are matched according to age, sex, or other factors.
It is used to compare the mean difference between the two groups after they have been treated with different interventions.The other options of the independent samples t-test, logistic regression analysis, and analysis of variance (ANOVA) are not appropriate statistical tests for matched design A/B tests.
Therefore, the correct option is Paired sample t-test. Hence, the answer is option B (Paired sample t-test).
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what is 4.768 as a common fraction
Answer:
\( \frac{596}{125} \)
should be it
.2. Determine whether the feasible set for each of the following systems of constraints is convex, and if not, indicate points x^1 and x² that violate definition. a) (x1)² + (x2)² > 9
x1 + x2 ,10
x1, x2 > 0
The feasible set for this system of constraints is not convex, and the points (5, 5) and (3, 7) violate the convexity definition.
To determine whether the feasible set for each system of constraints is convex, we need to analyze the constraints individually and examine their intersection.
a) (x1)² + (x2)² > 9
This constraint represents points outside the circle with a radius of √9 = 3. The feasible set includes all points outside this circle.
b) x1 + x2 ≤ 10
This constraint represents points that lie on or below the line x1 + x2 = 10. The feasible set includes all points on or below this line.
c) x1, x2 > 0
This constraint represents points in the positive quadrant, where both x1 and x2 are greater than zero.
Now, let's analyze the intersection of these constraints:
Considering the first two constraints (a and b), we can see that the feasible set consists of all points outside the circle (constraint a) and below or on the line x1 + x2 = 10 (constraint b).
To determine whether the feasible set is convex, we need to check if any two points within the set create a line segment that lies entirely within the set.
If we consider the points (5, 5) and (3, 7), both points satisfy the individual constraints (a) and (b). However, the line segment connecting these two points, which is the line segment between (5, 5) and (3, 7), exits the feasible set since it passes through the circle (constraint a) and above the line x1 + x2 = 10 (constraint b).
Therefore, the feasible set for this system of constraints is not convex, and the points (5, 5) and (3, 7) violate the convexity definition.
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3 drinks and 2 pretzels costs $16, but 6 drinks and 5 pretzels ests $21.25. What is the press
of one pretzel?
Answer:
The price of one pretzel is $-10.75
Step-by-step explanation:
I'm not really sure why the pretzel would be negative dollars, but I checked my answer multiple times and it's right. For this problem you need a system of equations. The system will be 3d+2p=16 (since 3 drinks and 2 pretzels is 16 dollars) and 6d+5p=21.25 (since 6 drinks and 5 pretzels is 21.25 dollars). To solve this system, the first thing we're going to do is multiply the first system by -2 so that we can cancel the d variable. This will leave you with
-6d-4p=-32. Now, you can add this to the other equation. Since the -6 and 6 cancel, we only have the p variable now (that's why we multiplied by -2, to cancel out the d variable when we added later). Now we have -4p=-32 and 5p=21.25. Add these two equations together and you'll get 1p=-10.75, or p=-10.75. If you needed to solve for the drinks, you could plug -10.75 back into one of the first two equations, but for this problem we don't so -10.75 is your answer.
Help out with this question please!
Answer:
my answer is A
Step-by-step explanation:
if you work out the equation where you know that at the x intercept y=0 you will find A to be true
Two ride-sharing companies, A and B, provide service for a certain city. A random sample of 52 trips made by Company A and a random sample of 52 trips made by Company B were selected, and the number of miles traveled for each trip was recorded. The difference between the sample means for the two companies
(A−B) was used to construct the 95 percent confidence interval (1.86,2.15).
Which of the following is a correct interpretation of the interval?
A. We are 95 percent confident that the difference in sample means for miles traveled by the two companies is between 1.86 miles and 2.15 miles.
B. We are 95 percent confident that the difference in population means for miles traveled by the two companies is between 1.86 miles and 2.15 miles.
C. The probability is 0.95 that the difference in sample means for miles traveled by the two companies is between 1.86 miles and 2.15 miles.
D. The probability is 0.95 that the difference in population means for miles traveled by the two companies is between 1.86 miles and 2.15 miles.
E. About 95 percent of the differences in miles traveled by the two companies are between 1.86 miles and 2.15 miles.
3. Two community service groups, J and K, each have less than 100 members. Members of both groups volunteer each month to participate in a community-wide recycling day. A study was conducted to investigate whether the mean number of days per year of participation was different for the two groups. A random sample of 45 members of group J and a random sample of 32 members of group K were selected. The number of recycling days each selected member participated in for the past 12 months was recorded, and the means for both groups were calculated. A two-sample t-test for a difference in means will be conducted. Which of the following conditions for inference have been met?
I. The data were collected using a random method.
II. Each sample size is less than 10 percent of the population size.
III. Eachsamplesizeislargeenoughtoassumenormalityofthesampling
distribution of the difference in sample means.
A. I only
B. II only
C. III only
D. I and III only E. I, II, and III
The correct interpretation of the interval is:
B. We are 95 percent confident that the difference in population means for miles traveled by the two companies is between 1.86 miles and 2.15 miles.
The conditions for inference that have been met are: D. I and III only.
For the first question, the correct interpretation of the confidence interval is:
B. We are 95 percent confident that the difference in population means for miles traveled by the two companies is between 1.86 miles and 2.15 miles.
This interpretation reflects the fact that the confidence interval was constructed based on the sample means, but it provides an inference about the population means of the two companies.
For the second question, the conditions for inference that have been met are:
D. I and III only
I. The data were collected using a random method.
This ensures that the samples are representative of the population.
III. Each sample size is large enough to assume normality of the sampling distribution of the difference in sample means.
This condition implies that the sample sizes are sufficiently large to rely on the central limit theorem, which states that the sampling distribution approaches a normal distribution as the sample size increases.
Condition II, which states that each sample size is less than 10 percent of the population size, is not explicitly mentioned in the question. Therefore, we cannot assume that this condition has been met.
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Three numbers add up to 210. The second number is 10 more than the first and the third number is 3 times the first. Find the numbers by modelling the problem using an algebraic equation.
Answer:
I. First number, a = 40.
II. Second number, b = 50.
III. Third number, c = 120.
Step-by-step explanation:
Let the three numbers be a, b and c respectively.
Given the following data;
Translating the word problem into an algebraic equation, we have;
a + b + c = 210
b = a + 10
c = 3a
Substituting the value of b and c into the equation, we have;
a + a + 10 + 3a = 210
5a + 10 = 210
5a = 210 - 10
5a = 200
a = 200/5
a = 40
To find the value of b;
b = a + 10
b = 40 + 10
b = 50
To find c
c = 3a
c = 3*40
c = 120
sanjeev ate 1/6 of cake he gave to his frend the remainder 1/5 how much did he keep
Step-by-step explanation:
\( = 1 - ( \frac{1}{6} + \frac{1}{5} )\)
\( = 1 - ( \frac{5}{30} + \frac{6}{30} )\)
\( = 1 - \frac{11}{30} \)
\( = \frac{30}{30} - \frac{11}{30} \)
\( = \frac{19}{30} \)
So, he keeps \( \frac{19}{30}\)
Answer:
Sanjeev kept 19/30 of his cake.
Step-by-step explanation:
So, if Sanjeev ate 1/6 of the cake there will be 5/6 of the cake left over.
He gave 1/5 of this 5/6 to his friend.
He did not give 1/5 of the entire cake, he gave 1/5 of the remainder of his cake, which was 5/6.
To solve this, we must first convert both fractions to the same denominator.
1/5 and 5/6 becomes 6/30 and 25/30
He gave away 6/30 of this 25/30
It is now clear that we must take away how much he gave away from the remainder of the cake.
25/30 subtract 6/30 becomes 19/30
We cannot simplify this.
Therefore, Sanjeev kept 19/30 of his cake.
6
1 point
Label the steps in order to solve the following equation:
-11 - 5z = 6 (5z + 4)
&
1
-11 - 5z = 30z + 24
2
-35 = 352
3
-11 = 352 + 24
4
-1=2
Answer:
swap the middle two steps to put them in order
Step-by-step explanation:
The steps in order would be ...
-11 -5z = 30z +24 . . . . . eliminate parentheses-11 = 35z +24 . . . . . . . . add 5z-35 = 35z . . . . . . . . . . . . subtract 24-1 = z . . . . . . . . . . . . . . . . divide by 2A bus is stopped on the side of a road waiting for a few passengers. It is stopped 200 m from the intersection of another road which is perpendicular to it. At this moment the driver of the bus sees a large truck, which is 1200 m from the intersection, and approaches it at 100 km/h.
The distance, d, between the truck and the bus depends on time and is given by the function () = √0.22 + (1.2 − 100)2
a) Determine the speed at which the large truck is approaching the stopped bus.
b) After how long will the truck stop approaching the bus?
a) To determine the speed at which the large truck is approaching the stopped bus, we need to find the derivative of the distance function with respect to time.
1. Taking the derivative of d(t) with respect to t, we have:
d'(t) = d(t) / dt = (1/2) * (0.22 + (1.2 - 100t)^2)^(-1/2) * (-2) * (1.2 - 100t) * (-100)
2. Simplifying this expression, we get: d'(t) = 100 * (1.2 - 100t) / √(0.22 + (1.2 - 100t)^2)
3. Substituting the given values (t = 0), we can calculate the speed at which the truck is approaching the bus:
d'(0) = 100 * (1.2 - 100 * 0) / √(0.22 + (1.2 - 100 * 0)^2)
= 100 * 1.2 / √(0.22 + 1.2^2)
≈ 100 * 1.2 / √(0.22 + 1.44)
≈ 100 * 1.2 / √1.66
≈ 100 * 1.2 / 1.288
≈ 93.17 km/h
Therefore, the speed at which the large truck is approaching the stopped bus is approximately 93.17 km/h.
b) To determine when the truck stops approaching the bus, we need to find the time at which the derivative of the distance function becomes zero.
1. Setting d'(t) = 0, we can solve for t: 100 * (1.2 - 100t) / √(0.22 + (1.2 - 100t)^2) = 0
Simplifying the equation, we have: 1.2 - 100t = 0
2.Since time is measured in hours, we convert this to minutes:
0.012 hours * 60 minutes/hour = 0.72 minutes
Therefore, the truck will stop approaching the bus after approximately 0.72 minutes.
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