5.05 g
Express your answer as an integer.

The correct answer is B. 8 molecules \(SO_3\). Option B

In the given reaction:

S(s) + \(O_2\)(g) → \(SO_3\)(g)

The stoichiometric coefficient in front of the \(SO_3\)molecule is 8, which indicates that 8 molecules of \(SO_3\)are formed as a product. This coefficient represents the ratio of the number of molecules involved in the reaction.

Option A (8 atoms \(SO_3\)) is incorrect because it only mentions the number of atoms, not molecules. The stoichiometric coefficient does not represent the number of atoms, but rather the number of molecules.

Option C (80.07g \(SO_3\)) is incorrect because it mentions a specific mass. The stoichiometric coefficient does not directly represent the mass of the substance, but rather the relative amount of molecules involved in the reaction.

Option D (32 \(SO_3\)) is incorrect because it mentions a specific volume. The stoichiometric coefficient does not directly represent the volume of the substance, but rather the relative amount of molecules involved in the reaction.

Therefore, the correct way to describe the \(SO_3\)component in the reaction is option B: 8 molecules \(SO_3\). This represents the ratio of the number of molecules of \(SO_3\)that are produced in the reaction.

Option B

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Answer:

Titration of 50.00 mL of 0.0521 M sodium oxalate, Na2C2O4, required 38.71 mL of a potassium permanganate solution: 5 C2O42- + 2MnO4- + 16H+ = 2Mn2+ + 10 CO2 + 8H2O Calculate the molarity of the potassium permanganate solution.

Explanation:

If m and n are integers, which of the following must be an even integer? A. 2mn B. mn C. mn+2 d. mn-2 e. 3mn

The molarity of the chemical of molecular formula is 0.00465 mol/cm³.

Given data,

weight of CONH = 50g

volume = 250cm³

number of moles = ?

Molarity = ?

To find molarity first we should find number of moles,

So,

n = m / M

where,

n is number of moles

m is weight

M is molecular mass

Molecular mass of CONH is 43.0247mol

Putting values,

n = 50g / 43.0247mol

n = 1.162g/mol

So now when we have n we can find molarity,

To calculate molarity using formula,

M = nV

M = 1.162 / 250cm³

M = 0.00465 mol/cm³

A chemical concentration in a solution, specifically the amount of a solute per unit volume of solution, is measured by its molar concentration. The number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units, is the most widely used unit for molarity in chemistry.

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Answer:

2.48 × 10⁴ mol

Explanation:

Step 1: Write the balanced equation

2 CrO₄²⁻ + 3 SO₂ + 4 H⁺ ⇒ Cr₂(SO₄)₃ + 2 H₂O

Step 2: Calculate the reacting moles of CrO₄²⁻

3.00 × 10⁸ L of 5.50 × 10⁻² mM CrO₄²⁻ react. The reacting moles are:

3.00 × 10⁸ L × 5.50 × 10⁻² × 10⁻³ mol/L = 1.65 × 10⁴ mol

Step 3: Calculate the reacting moles of SO₂

The molar ratio of CrO₄²⁻ to SO₂ is 2:3. The reacting moles of SO₂ are 3/2 × 1.65 × 10⁴ mol = 2.48 × 10⁴ mol.

1584 Kg of SO2 is required to treat 3.00 x 10^8 L of 5.50 x 10^-2 mM Cr(VI).

The equation of the reaction is;

2CrO4^2-(aq) + 3SO2(g) + 4H^+(aq) -------> Cr2(SO4)3(s) + 2H2O(l)

Number of moles of Cr(VI) = concentration × volume

concentration =  5.50 x 10^-2 mM or 5.5 x 10^-5 M

volume =  3.00 x 10^8 L

Number of moles of Cr(VI) = 5.5 x 10^-5 M × 3.00 x 10^8 L

= 1.65 x 10^4 moles

From the reaction equation;

2 moles of Cr(VI) reacts with 3 moles of SO2

1.65 x 10^4 moles reacts with  1.65 x 10^4 moles ×  3 moles/2 moles

= 24750 moles

Mass of SO2 = 24750 moles × 64 g/mol

Mass of SO2 = 1584 Kg of SO2

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Answer:

Metals lose electrons when reacting with nonmetals, so the red sphere represents a metal.

The molecular formula of the compound is determined as P₂F₄.

Molecular formula tells us which atoms and how many of each type of atom are present in the molecule.

Molar mass of CaF₂ is 78.07 g/mol(0.2631 g  CaF₂) × (1 mol  CaF₂ / 78.07 g  CaF₂) = 0.00337 mol  CaF₂

2F- + Ca₂+ →  CaF₂

(0.00337 mol  CaF₂) × (2 mol F / 1 mol  CaF₂) = 0.00674 mol F

As, Molar mass of F is 18.9984 g/mol

So, (0.00674 mol F) × (18.9984 g F / 1 mol F) = 0.12805 g F

1 mmHg = 0.00131578947 atm

(97.3 mmHg) × (0.00131578947 atm / 1 atm) = 0.128 atm

(378 cm³) × (1L / 1000 cm³) = 0.378 L

Now, T = 77 + 273 = 350 K

As, PV = nRT

n(PxFy) = PV / RT

n(PxFy) = (0.128 atm × 0.378 L) / (0.0821 L atm mol-1 K-1 × 350 K) = 0.001684 mol

n(PxFy) = 0.001684 mol

n(PxFy) = m(PxFy) / M(PxFy)

M(PxFy) = m(PxFy) / n(PxFy) = (0.2324 g) / (0.001684 mol) = 138 g/mol

m(PxFy) = m(P) + m(F)

0.2324 g = m(P) + 0.12805 g

m(P) = 0.2324 - 0.12805 = 0.10435

m(P) = 0.10435 g

Molar mass of P is 30.9737 g/mol

so, (0.10435 g P) × (1 mol P / 30.9737 g P) = 0.003369 mol P

Now, n(P) : n(F) = 0.003369 mol : 0.00674 mol = 1 : 2

Therefore, empirical formula of PxFy is PF₂

Molar mass of PF₂ 68.9705 g/mol

Molecular formula of PxFy is ( PF₂)n

n = M(PxFy) / M( PF₂) = (138) / (68.9705) = 2

Therefore, the molecular formula of PxFy is P₂F₄.

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Answer:

Hubble's law says that the universe is expanding outward.

Explanation:

Actually Hubble's law was discovered before the Big Bang theory was formulated. The Big Bang Theory is an attempt to explain the observations that led to Hubble's Law.Before the 1900s the theory was that the universe was eternal and self existent. The idea was that the universe was in a steady state having always existed and would always continue to exist. Albert Einstein even changed the equations in his general theory of relativity to reflect the idea of a steady state. Later he called putting in a fudge factor to result in a steady state the worse mistake of his life.

Hubble observed that most of the universe has a red shift indicating that the universe is expanding and moving away from itself. The further out that the universe is observed the faster it is moving apart.

These observations were inconsistent with a steady state universe.

The Big Bang theory extrapolated backwards. If the universe is expanding and spreading out from itself then further back in time the universe was closer together. The Theory explained Hubble's observations by the idea that at the beginning of time ( for our universe) all the matter and energy were together in one place.

This super dense ball of matter and energy then exploded outwards creating space and time as it is presently observed. The question was would the forces of gravity and black holes bring the matter and energy back together again. The answer found in 1998 was no. The rate of the expansion of the universe is increasing not slowing down and the universe will not collapse back into the super dense ball of matter that it began as.

The Big Bang Theory postulated based on the empirical evidence that our universe had a beginning and it will eventually cease to exist. The conclusion based on Hubble's observations is that matter and energy are not eternal and self existent.

Answer:

\(m_{O_2}=120gO_2\)

Explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

\(2KClO_3\rightarrow 2KCl+3O_2\)

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

\(m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2\)

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The heat absorbed by the water is 25.9 KJ

To solve the question given above, we'll begin by calculating the change in the temperature of the water. This can be obtained as follow:

Initial temperature (T₁) = 25 °C  

Final temperature (T₂) = 32.50 °C

ΔT = 32.50 – 25

Finally, we shall determine the heat absorbed by the water. This can be obtained as follow:

Mass of water = 825.4 g

Change in temperature (ΔT) = 7.5 °C

Specific heat capacity of water = 4.184 J/gºC

Q = 825.4 × 4.184 × 7.5

Q = 25901.052 J

Divide by 1000 to express in KJ

Q = 25901.052 / 1000

Therefore, the heat absorbed by the water is 25.9 KJ.

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Scientists hypothesized the existence of another subatomic particle in the nucleus because helium has an atomic mass ratio of 4:1 to hydrogen. Helium and hydrogen have a mass ratio of 2:1 if protons were the only subatomic particles in the nucleus.

Rutherford's well-known gold foil experiment helped him discover protons in 1909. He bombarded a paper-thin piece of gold with alpha particles. Alpha particles, which have a positive charge, struck a piece of gold foil. Alpha particles mostly passed through unharmed. This demonstrated that the gold atoms contained largely void space. All atoms include minuscule, negatively charged subatomic particles or electrons, as demonstrated by J.J. Thomson's cathode ray tube studies. Thomson proposed the plum pudding model of the atom, which had positively-charged "soup" and negatively-charged electrons inside. The gold foil test was the most well-known experiment conducted by Ernest Rutherford. A beam of alpha particles was aiming at the gold foil. Although some alpha particles were scattered backward, the majority of them pierced the foil. This demonstrated that the vast majority of an atom is composed of void space that encircles a tiny nucleus.

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P Ar = 1.5

P Xe = 0.5

P tot = 2 atm

Dalton's law of partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases  

Can be formulated:  

P tot = P1 + P2 + P3 ....  

The partial pressure is the pressure of each gas in a mixture  

3 L Argon , P = 1 atm and 1 L Xe, P=1 atm⇒assume T = 273 K

mol Argon :

\(\tt n_{Ar}=\dfrac{PV}{RT}=\dfrac{1\times 3}{0.082\times 273}=0.134\)

mol Xenon :

\(\tt n_{Xe}=\dfrac{1\times 1}{0.082\times 273}=0.045\)

\(\tt P_{Ar}=\dfrac{nRT}{V}=\dfrac{0.134.0.082.273}{2}=1.5\)

\(\tt P_{Xe}=\dfrac{nRT}{V}=\dfrac{0.045.0.082.273}{2}=0.5\)

P tot = 1.5 + 0.5 = 2 atm

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer:

An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height. An object possesses elastic potential energy if it is at a position on an elastic medium other than the equilibrium position.

ANSWER : Metallic bonding is a type of chemical bonding that occurs between metal atoms. It involves the sharing of valence electrons between metal atoms, resulting in a sea of electrons that surrounds a lattice of positively charged metal ions.

Two common properties of metals are malleability and conductivity. Malleability refers to the ability of a metal to be shaped into thin sheets without breaking, while conductivity refers to the ability of a metal to conduct electricity and heat.

Metallic bonding produces these properties because the sea of delocalized electrons is free to move throughout the lattice of metal ions. When a force is applied to a metal, the ions in the lattice can slide past each other, facilitated by the movement of these electrons. This ability to move and slide past each other is what gives metals their malleability.

Similarly, the delocalized electrons are able to carry an electric current through the metal lattice. As electrons move through the metal lattice, they collide with the metal ions, transferring energy and producing heat. This transfer of energy is what gives metals their high thermal conductivity. In addition, the delocalized electrons are also able to transfer electrical charge through the metal lattice, resulting in the high electrical conductivity observed in metals.

In summary, metallic bonding produces the properties of malleability and conductivity in metals by creating a sea of delocalized electrons that can move freely throughout the lattice of metal ions, allowing for the movement of ions and the transfer of energy and electrical charge.

Explanation :

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The identity of element X in the compound X2Fe(CN)6 · 12H2O is sodium (Na).

To find the identity of element X in the compound X2Fe(CN)6 · 12H2O, we can start by determining the molar mass of the compound.

The molar mass of X2Fe(CN)6 is:

2 × molar mass of X + molar mass of Fe + 6 × molar mass of C + 6 × molar mass of N

= 2 × atomic mass of X + atomic mass of Fe + 6 × 12.01 g/mol + 6 × 14.01 g/mol

= 2 × atomic mass of X + 55.85 g/mol + 432.72 g/mol + 84.06 g/mol

= 2 × atomic mass of X + 572.63 g/mol

The molar mass of 12H2O is:

12 × (atomic mass of H + atomic mass of O) = 12 × (1.01 g/mol + 16.00 g/mol) = 216.24 g/mol

The total molar mass of the compound is:

2 × atomic mass of X + 572.63 g/mol + 216.24 g/mol = 2 × atomic mass of X + 788.87 g/mol

Now we can use the given information that the compound is 45.34% water by mass. This means that the mass of water in the compound is 45.34% of the total mass of the compound, and the mass of the rest of the compound (X2Fe(CN)6) is 100% - 45.34% = 54.66% of the total mass of the compound.

Let's assume we have 100 g of the compound. Then the mass of water in the compound is:

45.34 g water = 0.4534 × 100 g compound

The mass of the rest of the compound (X2Fe(CN)6) is:

54.66 g rest of the compound = 0.5466 × 100 g compound

We can now use the mass of the rest of the compound (X2Fe(CN)6) to find the number of moles of the compound:

moles of X2Fe(CN)6 = (54.66 g) / (2 × atomic mass of X + 572.63 g/mol)

We can also use the mass of water to find the number of moles of water:

moles of H2O = (45.34 g) / 18.02 g/mol

Since the compound has 12 moles of water per mole of X2Fe(CN)6, we have:

moles of X2Fe(CN)6 = 1/12 × moles of H2O

We can now set these two expressions for moles of the compound equal to each other and solve for the atomic mass of X:

(54.66 g) / (2 × atomic mass of X + 572.63 g/mol) = 1/12 × (45.34 g) / 18.02 g/mol

Simplifying this equation and solving for the atomic mass of X gives:

atomic mass of X = 22.99 g/mol

The atomic mass of X is very close to the atomic mass of sodium (22.99 g/mol), so it is likely that X is sodium. Therefore, the identity of element X in the compound X2Fe(CN)6 · 12H2O is sodium (Na).

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Answer:

it can last for 30 minutes

Explanation:

because it is very good at giving off heat, extothermal heat can last for quite a while.

Answer: radio wave frequencies have longer wavelengths and smaller

Energies per photon

Answer:

3 atoms

Explanation:

There is one calcium atom (Ca) and two Bromine atoms (Br2)

1.93g of glucose is required to produce 30KJ of energy

One of the carbohydrates referred to as simple sugars is glucose, commonly known as dextrose (monosaccharides). The chemical formula for glucose is C6H12O6, which means "sweet" in Greek. It is the main free sugar present in higher animals' blood and can be found in fruits and honey. It is the source of energy for cellular activity, hence controlling its metabolism is crucial (see fermentation; gluconeogenesis).

Starch molecules, which make up the majority of plant's energy reserves, are made up of countless linear glucose units. Cellulose is a significant molecule made primarily of glucose and is likewise linear. D-glucose is a chemical found in dextrose. Glycogen, the reserve carbohydrate found in the majority of vertebrate and invertebrate animal cells as well as those of countless fungi and protozoans, is a similar molecule in mammals.

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Answer:

The products have more potential energy than the reactants in an endothermic reaction.

Explanation:

In an endothermic reaction, energy is absorbed, so the products have more potential energy that the reactants, like we can see in this drawing:

The half reaction with a more positive standard reduction potential will proceed spontaneously in a redox reaction

The half reaction with a more positive standard reduction potential will undergo reduction when compared to the half reaction with a more negative standard reduction potential.

Oxidation-reduction reactions, often known as redox reactions, are a set of chemical reactions that involve electron transfer between reactants. In a redox reaction, one reactant is oxidized, losing electrons, while the other reactant is reduced, gaining electrons.

The oxidation half-reaction is the process of losing electrons and increasing the oxidation number, whereas the reduction half-reaction is the process of gaining electrons and decreasing the oxidation number. The total reaction is referred to as the redox reaction.

Half-reaction:Half-reaction refers to the two parts of an oxidation-reduction reaction that happen separately. A half-reaction must always be either an oxidation reaction or a reduction reaction. It also describes the movement of electrons and hydrogen ions in an equation.

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Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptured and all the compressed air was released to a volume of 1370 L at atmospheric pressure.

Hank's Garage has an air compressor with a holding tank that contains a volume of 200L (V₁) of compressed air at a pressure of 5200 torr (P₁).

One day a hose ruptured and all the compressed air was released. The final pressure was the atmospheric pressure (1 atm = 760 torr) (P₂).

We can calculate the new volume (V₂) in these conditions using Boyle's law, which states there is an inverse relationship between the volume and the pressure of an ideal gas.

\(P_1 \times V_1 = P_2 \times V_2\\\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{5200 torr \times 200L}{760torr} = 1370 L\)

Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptured and all the compressed air was released to a volume of 1370 L at atmospheric pressure.

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Answer:

The moon

Explanation:

The moon pulls on the earth, causing the tides to raise as the water is being pulled by the moon.

The two structures are first to combine in translation are 3 and 4. Therefore, option C is correct.

The process in which the information encoded in the mRNA is used to direct the sequencing of amino acids, and therefore  it finally synthesizes a protein is called as translation.

In translation the information passed from DNA  to mRNA and turns it into a series of amino acids bound together with peptide bonds.

Translation is translation from one code of nucleotide sequence to another code of amino acid sequence.The two structures are first to combine in translation are 3 and 4.

Thus, option C is correct.

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Answer: Vanadium(III) Sulfide.

Explanation:

The accumulation of ADP (adenosine diphosphate) affects the rate of metabolic chemical reactions by slowing them down.

What is chemical reaction?
A chemical reaction is a process that leads to the transformation of one set of chemical substances to another. It involves the breaking and forming of chemical bonds, resulting in the formation of new substances with different properties. Chemical reactions are essential for many processes in nature, including respiration, digestion, and photosynthesis.

ADP is a by-product of the energy-producing reactions that take place in cells. This by-product can build up and inhibit the activity of enzymes involved in these metabolic reactions. Therefore, an accumulation of ADP can slow down the rate of metabolic chemical reactions.

However, the rate of metabolic chemical reactions can also be sped up by the presence of ADP. This occurs when the cellular metabolic processes become inhibited by the presence of ADP and require a boost to be activated again. In this case, the presence of ADP can activate enzymes and thus speed up the rate of metabolic chemical reactions.

In sum, the accumulation of ADP can either slow down or speed up the rate of metabolic chemical reactions, depending on the current state of the metabolic process.

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