5
Five chemical reactions are listed in the table below.
Reaction 1 C.CO, COCO,
Reaction 2 Ca(OH)2 + 2HC- Ch2410
Reaction 3 NHSHA NICI
Reaction 4
PO - P +0,
Reactions 2Mg +0,- 2MgO
Identify any decomposition reaction(s) shown in the table.
A Reaction 1
B Reaction 2
C Reaction 3
D Reaction 4
E Reaction 5

Answer:

saturated solution

Explanation:

hope this helps!

Answer:

it would be saturated

Explanation:

because there is to much of the solute

Answer:

1.6cm3

Explanation:

density = mass/volume

15.6g/cm3= 9.75 g/volume

15.6/9.75 = volume

1.6cm3 = volume

Answer:

carbon dioxide, water, and sunlight.

Explanation:

The final temperature will be approximately -55.6 degrees Celsius when the volume is reduced to 5.25 mL.

According to Charles' Law, when pressure is constant, the volume of a gas is directly proportional to its temperature (in Kelvin). The formula for Charles' Law is V1/T1 = V2/T2.

First, convert the initial temperature from Celsius to Kelvin (68 + 273.15 = 341.15 K). Then, plug in the values: (12.75 mL / 341.15 K) = (5.25 mL / T2).

To solve for T2, multiply both sides by T2 and divide by 5.25 mL: T2 = (341.15 K * 5.25 mL) / 12.75 mL ≈ 139.6 K. Finally, convert back to Celsius: 139.6 K - 273.15 ≈ -55.6 degrees Celsius.

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The resistance of the copper wire is 0.1039 Ω.

In calculating the resistance of a wire, the formula below can be used.

Resistance = (Resistivity*Length of wire)/(Cross-section Area)

The resistivity of copper wire is 1.72 x 10-8 Ωm. The length of the wire is 20.0 m and the area of the wire is 3.3103x10-6 square meters. The area of the wire is calculated by using the formula below.

Cross-section area= (π/4)(diameter)^2

Cross-section area=(π/4)(2.053 mm or 2.053x10-3 m)^2

Cross-section area= 3.3103x10-6 square meters

Calculating for the resistance of the wire:

Resistance= (1.72x10-8 Ωm * 20.0 m)/( 3.3103x10-6 m2)

Resistance=0.1039 Ω

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The true statement about exothermic reactions is: the energy in the system is less once the reaction makes products.

option B.

Exothermic reactions are those reactions in which energy is released into the surroundings.

This energy release results in a decrease in the internal energy of the system, which means that the energy in the system is less after the reaction than before.

Also, the decrease in energy corresponds to an increase in stability of the system. Therefore, in an exothermic reaction, the energy of the products is less than the energy of the reactants.

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Therefore, the value of k is 0.64/T², peak time is 1.25T, maximum overshoot is 23.6% and settling time is 6.67 seconds.

Given data:

Damping ratio, ζ = 0.6

We know that the settling time, Ts = 4 / ζωn

The formula for the natural frequency is given as follows;ωn = √(1 - ζ²) / Tk = 2π / T

Therefore, substituting the values of k and ζ in the equations, we have:

ωn = √(1 - ζ²) / Tωn = √(1 - (0.6)²) / Tωn = √(0.64) / Tωn = 0.8 / T

T = 2π / ωnk = ωn²Then; k = (0.8 / T)²

k = 0.64 / T²

We have also, Ts = 4 / ζωnTs = 4 / (0.6 * 0.8 / T)Ts = 6.667 seconds

Maximum overshoot (Mp) is given by;

Mp = e^(-πζ / √(1 - ζ²))

Mp = e^(-π * 0.6 / √(1 - 0.6²))Mp = 0.236

Settling time (Ts) is given by;

Ts = 4 / ζωnTs = 4 / (0.6 * 0.8 / T)Ts = 6.667 seconds

Therefore, the value of k is 0.64/T², peak time is 1.25T, maximum overshoot is 23.6% and settling time is 6.67 seconds.

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Answer:

a. The limiting reagent is NO2.

b. 126g of nitric acid can be produced.

Explanation:

1st) It is necessary to write the balanced equation:

From the balanced equation we know that 3 moles of NO2 (3x46g= 138g) react with 1 mol of water (18g/mol) to produce 2 moles of nitric acid (2x63g= 126g) and 1 mol of NO (30g/mol).

2nd) To calculate the limiting reagent it is necessary to use the given values and the stoichiometry of the balanced equation:

The 10.0g of NO2 will need 1.30g of H2O to react.

The 30.0g of H2O will need 230g of NO2 to react.

So, as we only have 10.0g of NO2 and 30.0g of H2O, the limiting reagent will be NO2.

3rd) Now, to calculate the theorical yield, we need to use the stoichiometry of the balanced equation using the limiting reagent:

1 mol of H2O produces 2 moles of nitric acid. With the molar mass of nitric acid (63g/mol), we can calculate the grams.

Finally, 126g of nitric acid will be produced if the reaction is 100% efficient (theoretical yield).

The Polar molecules are NH3 (ammonia), CO, and H2O (water).

A polar molecule is formed when there is an uneven distribution of electrons between the atoms, resulting in partial charges.  NH3 has a polar covalent bond between nitrogen and hydrogen, and the molecule has a trigonal pyramidal shape. Nitrogen is more electronegative than hydrogen, which results in the molecule having a partial negative charge on nitrogen and a partial positive charge on the hydrogen atoms. This uneven distribution of electrons makes NH3 a polar molecule.

CO has a polar covalent bond between carbon and oxygen, but the molecule is linear in shape. The electronegativity difference between carbon and oxygen is small, resulting in a small dipole moment. Hence, CO is a polar molecule but has a lower polarity than NH3. H2O has two polar covalent bonds between hydrogen and oxygen, and the molecule has a bent shape. Oxygen is more electronegative than hydrogen, leading to a partial negative charge on oxygen and a partial positive charge on hydrogen atoms. As a result, H2O is a highly polar molecule with a significant dipole moment.

BF3 and CO2 have a symmetrical shape, and the polar bonds present cancel out the partial charges, resulting in a nonpolar molecule. IF2- is a linear molecule, but the electronegativity of iodine and fluorine is not significantly different, leading to a nonpolar molecule. In conclusion, NH3, CO, and H2O are the polar molecules out of the given options.

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Answer:

The answer is D

Answer:liquid b

Explanation:

i took the test

Answer:

459.11 g.

Explanation:

hope this helps

A solution is diluted by adding more solvent, which means the concentration of the solution decreases but the amount (moles) of the solute stays the same.

It is because the total volume of the solution increases but the amount of solute remains constant, resulting in a decrease in concentration. In direct answer to your question, the addition of solvent is what causes a solution to become diluted, and this occurs without any change in the amount of solute present.

A solution is diluted by adding more solvent, which means the volume of the solution increases but the amount (moles) of the solute stays the same.

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Here m means molality.

To arrange these compounds, first, we must know this:

ΔTb = Kb x m x i

ΔTb = boiling point elevation

kb = 0.52 ºC/m for water (solvent) we assume that our solvent is water, the same for the 4 solutions between solutes and water.

m = the same for the 4 of them

i = Van't Hoff factor = number of particles into which the solute is dissociated.

"i" will change for all the cases.

For 0.50 m KCl)

KCl ==> k+ + Cl-, so i = 2 (2 ions)

For 0.5 m C6H6O6)

i = 1 (C6H6O6 doesn't dissociate)

For 0.5 m Fe(NO3)3)

Fe(NO3)3 ===> Fe+3 + 3 NO3-

i = 4 (4 ions)

For 0.5 m Na2SO4)

Na2SO4 ==> 2 Na+ + SO4-2

i = 3

According to ΔTb = Kb x m x i, the only factor that changes is "i", so it will give the order of increasing boiling point elevation of these compounds:

Answer:

0.5 m C6H6O6 < 0.50 m KCl < 0.5 m Na2SO4 < 0.5 m Fe(NO3)3

The melting point is the temperature a substance must reach to go into its liquid phase (or solid) and a boiling point is the temperature a substance must reach to go into its gas phase (or liquid). For example, water must be 0ºC to melt or freeze and 100ºC to boil.

Answer:

-1,300 kJ

Explanation:

P₄  +  3 O₂  ⇒  P₄O₆     ΔH = -1,640.1 kJ    (EQ 1)

P₄O₁₀  ⇒  P₄  +  5 O₂    ΔH = 2,940.1 kJ    (EQ 2)

These are the equations you are given.  You need to make these equations into the equation below.

P₄O₆  +  2 O₂  ⇒  P₄O₁₀  (end equation)

Look at the product side of the end equation.  You need to produce P₄O₁₀.  In the EQ 2, P₄O₁₀ is on the reactant side.  Flip the equation.  Since you flipped the equation, the enthalpy will have the opposite sign.

P₄  +  5 O₂  ⇒  P₄O₁₀    ΔH = -2,940.1 kJ

On the reactant side of the end equation, you need P₄O₆ and 2 O₂.  First, rearrange the equation so that P₄O₆ is on the right side.  In EQ 1, P₄O₆ is on the product side.  Flip the equation.  Like the last one, the sign will change.

Now, cancel out all possible values.  P₄ will cancel out since there is one on each side of the equation.  Since there is 5 O₂ on one side and 3 O₂ on the other, subtract the two and put the remainder on the side of the larger value.

P₄  +  5 O₂  ⇒  P₄O₁₀    ΔH = -2,940.1 kJ

P₄O₆  ⇒  P₄  +  3 O₂     ΔH = 1,640.1 kJ    

P₄O₆  +  2 O₂  ⇒  P₄O₁₀

This should be the resulting equation.  Now, add the two enthalpies together to find the overall enthalpy.

-2,940.1 kJ  +  1,640.1 kJ  = -1,300 kJ

The overall enthalpy is -1,300 kJ.

-867.7Answer:

Explanation:

-867.7

Problems with understanding what happens when things burn can be attributed to various factors, such as lack of knowledge about the combustion process, the role of oxygen, and the production of heat and light energy.

When things burn, a chemical reaction called combustion takes place. During this process, a fuel reacts with oxygen, resulting in the release of energy in the form of heat and light. The products of combustion are usually water, carbon dioxide, and sometimes other gases or particles, depending on the fuel and the burning conditions.

One issue in understanding this process is grasping the importance of oxygen. Oxygen is required for combustion to occur, and the presence of more or less oxygen affects the burning process. For example, in a well-ventilated area, the combustion is more efficient, whereas limited oxygen can result in incomplete combustion and the production of harmful byproducts like carbon monoxide.

Another problem in understanding combustion is the role of heat. Heat is both a product of and a catalyst for combustion. As a fuel gets heated, it may reach its ignition temperature, at which point it spontaneously ignites. Heat also contributes to the spread of fire, as it can cause nearby objects to reach their ignition temperature.

The production of light during combustion is another aspect that can cause confusion. The light emitted during burning is a result of excited atoms and molecules in the flame that release energy in the form of light when they return to their original state. This is what makes flames visible and gives them their characteristic colors.

In summary, problems with understanding what happens when things burn stem from a lack of knowledge about the combustion process, the role of oxygen, and the production of heat and light energy. Gaining a deeper understanding of these factors can help individuals better comprehend the complex nature of combustion and fire safety.

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Answer:

Only the oxygen needs to be balanced. There are equal numbers of hydrogen and carbon

Explanation:

 Given expression:

     C₂H₄ + O₂ → 2H₂O + 2CO₂

The law of conservation of mass suggests that chemical equations be balanced since atoms are neither created nor destroyed in the course of a chemical reaction. In retrospect, bonds are broken and chemical species are change to another form.

 From the given equation, only oxygen is not balanced. This flouts the law of conservation.

 On the reactant side, we have 2 oxygen on the product, we have 6.

Answer:

Option C .P=79, N= 118 Atomic number=79 Mass number=197

Answer:

You subtract the given atomic mass by the atomic number

Explanation:

The answer is the explanation

Answer:

5 hours.

Explanation:

Given that,

Initial time, \(T_i=6\ pm\)

Final time, \(T_f=11\ pm\)

We need to find how much time did it take the car to arrive.

Time =  final time-initial time

= 11 pm - 6 pm

= 5

So, it takes 5 hours by car to arrive.

Answer: Magnesium loses two electrons whilst sulfur gains tw

Based on their positions in the periodic table, oxygen (O) has the largest first ionisation energy among Mg, Ba, B, O, and Te.

First ionisation energy is the energy required to remove the most loosely held electron from a neutral atom. In general, ionization energy increases from left to right across a period and decreases from top to bottom within a group in the periodic table. This is due to the increasing nuclear charge and decreasing atomic radius.

Comparing the elements given by considering their positions in periodic table :
1. Mg (Group 2, Period 3) and Ba (Group 2, Period 6) are both alkaline earth metals. Ba is lower in the periodic table, so it has a lower first ionisation energy than Mg.
2. B (Group 13, Period 2) is to the left of O (Group 16, Period 2) in the same period, so O has a higher first ionisation energy than B.
3. Te (Group 16, Period 5) is below O in the periodic table, so it has a lower first ionisation energy than O.

Thus, among Mg, Ba, B, O, and Te, oxygen (O) has the largest first ionisation energy.

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The balanced equation for the ionization of benzoic acid, HC7H5O2, in water can be represented as follows:

HC7H5O2 + H2O ⇌ H3O+ + C7H5O2-

In this equation, the benzoic acid molecule reacts with a water molecule. One of the hydrogen atoms from the water molecule is transferred to the benzoic acid, resulting in the formation of a benzoate ion (C₇H₅O₂⁻) and a hydrogen ion (H⁺). The benzoate ion carries a negative charge due to the transfer of the hydrogen atom, while the hydrogen ion carries a positive charge.

This ionization process occurs due to the acidic nature of benzoic acid, which can release a hydrogen ion when it comes into contact with water. The resulting benzoate ion and hydrogen ion can participate in various chemical reactions.

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Svante Arrhenius, as a doctoral candidate, proposed the acid-base theory, which initially faced skepticism from his professors who thought his ideas were unfounded. However, within a decade, the Arrhenius theory was widely accepted and praised in the scientific world. In his theory, Arrhenius defined acids as compounds having ionizable hydrogen, and bases as compounds with ionizable hydroxide ions (OH-).

Arrhenius proposed his theory of acids and bases in 1884 as part of his doctoral thesis. At the time, his ideas were met with skepticism and criticism from his professors and peers, who were more accustomed to the older, classical theories of acids and bases.

However, Arrhenius's theory was eventually accepted and became widely praised within the scientific community. This was in part due to the experimental evidence that supported his theory and the way that it could be used to explain a wide range of chemical phenomena.

In Arrhenius's theory, an acid is a substance that dissociates in water to produce hydrogen ions (H+), while a base is a substance that dissociates in water to produce hydroxide ions (OH-). This theory provided a new and more comprehensive understanding of the behavior of acids and bases and laid the foundation for further research in this area.

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The frequency of the light is 6.06 x 10¹⁴ s⁻¹.  The energy of the photon is 4.02 x 10⁻¹⁹ J or 4.02 x 10⁻²² kJ.

The energy of the photon is 4.02 x 10⁻¹⁹ J or 4.02 x 10⁻²² kJ.

The energy needed to break a mole of Cl-Cl bonds is 243 kJ/mol.

(i) The frequency of light can be calculated using the formula:

frequency (ν) = speed of light (c) / wavelength (λ).

Given that the wavelength (λ) is 495 x 10⁻⁷ m, and the speed of light (c) is approximately 3 x 10⁸ m/s, we can substitute these values into the formula:

frequency (ν) = (3 x 10⁸ m/s) / (495 x 10⁻⁷ m)

                    ν = 6.06 x 10¹⁴ s⁻¹

Therefore, the frequency of the light is 6.06 x 10¹⁴ s⁻¹.

(ii) The energy (E) of a photon can be calculated using the formula:

energy (E) = Planck's constant (h) × frequency (ν)

Planck's constant (h) is approximately 6.626 x 10⁻³⁴ J·s.

Substituting the frequency (ν) calculated in part (i) into the formula:

energy (E) = (6.626 x 10⁻³⁴J·s) × (6.06 x 10¹⁴ s⁻¹)

            E = 4.02 x 10^(-19) J

Converting the energy to kilojoules (kJ):

1 J = 1 x 10⁻³ kJ

energy (E) = 4.02 x 10⁻¹⁹J × 1 x 10⁻³

             E = 4.02 x 10⁻²² kJ

Therefore, the energy of the photon is 4.02 x 10⁻¹⁹ J or 4.02 x 10⁻²² kJ.

(iii) To calculate the energy needed to break a mole of Cl-Cl bonds, we need to know the bond energy of Cl-Cl. Let's assume the bond energy of Cl-Cl is 243 kJ/mol.

The energy needed to break a mole of Cl-Cl bonds is equal to the bond energy:

Energy = 243 kJ/mol

Therefore, the energy needed to break a mole of Cl-Cl bonds is 243 kJ/mol.

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Answer:

Explanation:

The percentage error of a certain measurement can be found by using the formula

\(P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ \)

From the question

actual density = 8.96 g/mL

error = 8.96 - 8.86 = 0.1

We have

\(p(\%) = \frac{0.1}{8.96} \times 100 \\ = 1.1160714...\)

We have the final answer as

Hope this helps you

Answer:

2KNO3 + H2SO4 → K2SO4 + 2HNO3

Explanation:

Hope this helps

Option b-A The isotope ⁷₂H (7He) is more tightly bound than ⁵₂H (5He).

The stability of an isotope depends on its binding energy, which represents the amount of energy required to break apart the nucleus into its constituent particles. Higher binding energy indicates greater stability and tighter binding of nucleons within the nucleus.

To determine which isotope is more tightly bound, we compare their binding energies. The binding energy is related to the mass defect, which is the difference between the sum of the masses of the individual nucleons and the actual mass of the nucleus.

In this case, the atomic mass of ⁷₂H (7He) is 7.027991 u, and the atomic mass of ⁵₂H (5He) is 5.012057 u. The greater the mass defect, the more tightly bound the nucleus. Since the mass defect of ⁷₂H (7He) is greater than that of ⁵₂H (5He), it implies that ⁷₂H (7He) has a higher binding energy and is more tightly bound.

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