9. Mr. Glover wrote the problem, "Find 16% of 50" on the whiteboard and asked students to
create a proportion or equation to solve the problem. Circle the name of anyone who made a true
statement.
Tur
Tur
DOVAN

Answer:

x² + 34x + 104 = 0

x² + 34x = -104

x² + 34x + ((1/2)(34))² = -104 + ((1/2)(34))²

x² + 34x + 17² = -104 + 17²

x² + 34x + 289 = 185

(x + 17)² = 185

x + 17 = +√185

x = -17 + √185

Answer:

Below

Step-by-step explanation:

The maximum area of land that can be enclosed is a SQUARE

  using the river as one side of the square means there are 3 sides that total 800 ft     800 / 3 = 266 2/3 ft per side

  area would then be L x W =    266 2/3  * 266 2/3 = 71111  1/9 ft^2

Answer:

\(\Large \boxed{ \mathrm{377 \ pounds \ per \ square \ inch} }\)

Step-by-step explanation:

The initial pressure was 435 pounds per square inch.

From 12:00 PM to 1:00 PM, the initial pressure increases by 58 pounds per square inch and then decreases 116 pounds per square inch.

⇒   435 + 58 - 116

⇒   377

Answer:

\(\huge\boxed{377 \ pounds / in.^2}\)

Step-by-step explanation:

The initial pressure was 435 pounds / in.²

After that it increases by 58 pounds / in.²

So, it became

=> 435 + 58

=> 493 pounds / in.²

Then, it decreases by 116 pounds/square inch

=> 493 - 116

=> 377 pound / in.²

This is the final pressure.

In the total amount of $261,000 received from contributors, a majority of $240,000 came from four contributors, with each contributing $60,000. The remaining $21,000 was obtained from smaller individual contributions.

This statement describes the breakdown of contributions received from different sources. Out of the total amount of $261,000, the majority, which is $240,000, came from four specific contributors. Each of these contributors donated $60,000, resulting in a combined contribution of $240,000. The remaining $21,000 represents the sum of smaller individual contributions from various sources.

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The digit that appears the most in the first 6 billion decimal places of pi is  C. 0.

Pi is a mathematical constant that is approximately equal to 3.14159. It is an irrational number, meaning that its decimal representation goes on infinitely without repeating. As a result, it is impossible to determine the exact value of pi, but its value can be approximated using various methods, including the use of computer algorithms. One such algorithm involves calculating pi to billions or trillions of decimal places. The resulting sequence of digits can then be analyzed to determine which digit appears the most frequently. In the case of the first 6 billion decimal places of pi, the digit 0 appears the most frequently.

According to one study, the frequency of each digit in the first 6 billion decimal places of pi is as follows: 0: 599,963,005 1: 600,033,072 2: 599,968,761 3: 600,098,056 4: 599,916,636 5: 599,993,197 6: 600,019,293 7: 600,007,804 8: 599,946,928 9: 599,956,248 As can be seen from these figures, the digit 0 appears more frequently than any other digit in the first 6 billion decimal places of pi. Therefore the correct option is C

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The model's fit to the data is weak, indicated by a correlation coefficient of -0.34. There is a weak negative relationship between the variables, with the model's predictions being imprecise and scattered around the line of fit.

A relationship coefficient of - 0.34 shows a frail negative connection between's the factors in the information. This intends that as one variable expands, the other variable will, in general, diminish, however, the relationship isn't a serious area of strength for exceptionally.

The line of fit for the information recommends that there is a general pattern or example, however, it doesn't fit the information focuses intently. The scatterplot of the information would show focuses spread around the line, for certain focuses straying a considerable amount from it.

The model's capacity to foresee the specific upsides of the reliant variable in light of the free variable(s) is restricted. In outline, the attack of the model to the information isn't an area of strength for extremely, there is a frail negative connection between the factors.

The model's forecasts may not be profoundly precise, and there may be different elements or factors not caught by the model that impact the information.

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The original cost of the tablet is $70.89 in the given algebraic equation.

A mathematical claim containing two equated algebraic expressions is known as an algebraic equation. When P and Q are polynomials, an algebraic equation has the general form P = 0 or P = Q. The term "multivariate equation" refers to an algebraic equation that has more than one variable.

Univariate equations are algebraic equations that only have one variable. Equations in algebra are balanced by definition. Due to this, the right and left sides of the equation will be equal.

Let the original cost be  x

then

15/100 = 24.99.x

x =  166.6

237.49 - 166.6

= $70.89

Thus, the original cost of the tablet is $70.89 in the given algebraic equations.

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Full question?

Lucas bought a tablet that was on sale at a 15% discount on your supra case for $24.99 which is been a total of $237.49. Write an equation to find the original cost of the tablet?

Answer:

5y-15=180

5y=180+15

5y=195

5y÷5y=195÷5

y=39

The equation is P = 1700x + 22,000 and the population in 2009 is 32,200.

Here we have to find the equation to get to know the population after x years.

Data provided:

Population in 2003 = 22,000

Year = x year

Population increases every year = 1700

Let P be the population after x year.

So the equation is:

P = 1700x + 22,000

Now we have to find the population in 2009.

So 2009 - 2003 = 6

Put x = 6

P = 1700 × 6 + 22,000

  = 10200 + 22,000

  = 32,200

Therefore the equation is P = 1700x + 22,00 and in 2009 population is 32,200.

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Answer: the answer is D

Both sides are equal to 5 radical 2

Step-by-step explanation:

As from question asking the probability of A be the event "the outcome is a divisor of 4".

According to given table there are three divisor of 4 i.e 1 and 2 and 4 so the probability for A is:

Answer: 7/16

Step-by-step explanation:

Vowels: A, E, I, O, and U.

Number of Vowels in the phrase: "Do not run on Ichiro": 7

Now the total numbers of letters in the Phrase "Do not run on Ichiro": 16

For probability it is selected amount/  total amount

So 7/16, and this fraction is in its most simplified (reduced) form.

If this helped please mark me brainliest  

The probability is \(7\div 16\)

Vowels: A, E, I, O, and U.

Number of Vowels in the phrase: "Do not run on Ichiro": 7

Now the total numbers of letters in the Phrase "Do not run on Ichiro": 16

So, the probability is the same.

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Step-by-step explanation:

Answer:

y^13/12 or y^1 1/12

Step-by-step explanation:

Convert the fractions to compatible bases. In this case, you can multiply the 3/4 by 3 making it 9/12, and multiply the 1/3 by 4 making it 4/12. If you add these now compatible fractions, you get 13/12. The base remains the same, I hope this helps!

create your own scale, it could be 2cm=40mm, so 3cm=60mm and 2.5cm=50mm.

then draw your trapezium in the given space using your scale

The collection gadget with the given transfer function and an enter of x(t) = cos(t) has a frequency response given through Y(s) = cos(t) * \([8(s+1)/(s+2)(s^2 + 4)]\). The gadget is solid due to the poor real part of the pole at s = -2. The absence of zeros in addition contributes to system stability.

To set up the frequency reaction of the collection system, we want to calculate the output Y(s) inside the Laplace domain given the input X(s) = cos(t) and the transfer function of the device.

The switch function of the series machine, as proven in Figure 1, is given as H(s) = \(8(s+1)/(s+2)(s^2 + 4).\)

To locate the output Y(s), we multiply the enter X(s) with the aid of the transfer feature H(s) and take the inverse Laplace remodel:

Y(s) = X(s) * H(s)

Y(s) = cos(t) * \([8(s+1)/(s+2)(s^2 + 4)]\)

Next, we want to determine the stability of the overall gadget. The stability is determined with the aid of analyzing the poles of the switch characteristic.

The poles of the transfer feature H(s) are the values of s that make the denominator of H(s) equal to 0. By putting the denominator same to zero and solving for s, we are able to find the poles of the machine.

S+2 = 0

s = -2

\(s^2 + 4\)= 0

\(s^2\) = -4

s = ±2i

The machine has one actual pole at s = -2 and complicated poles at s = 2i and s = -2i. To investigate balance, we observe the actual parts of the poles.

Since the real part of the pole at s = -2 is poor, the system is stable. The complicated poles at s = 2i and s = -2i have 0 real elements, which additionally contribute to stability.

Sketching the poles and zeros at the complex plane, we see that the machine has an unmarried real pole at s = -2 and no 0. The pole at s = -2 indicates balance because it has a bad real component.

In conclusion, the collection gadget with the given transfer function and an enter of x(t) = cos(t) has a frequency response given through Y(s) = cos(t) *\([8(s+1)/(s+2)(s^2 + 4)]\). The gadget is solid due to the poor real part of the pole at s = -2. The absence of zeros in addition contributes to system stability.

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The correct question is:

" Establish the frequency response of the series system with transfer function as specified in Figure 1, with an input of x(t) = cos(t). Determine the stability of the connected overall system shown in Figure 1. Also, sketch values of system poles and zeros and explain your answer in terms of the contribution made by the poles and zeros to overall system stability. x(t) 8 5 s+1 s+2 Figure 1 Block diagram of series system s+2 S² +4"

Step-by-step explanation:

Hey there!!

You can simply work with it.

(5x - 17)° + (3x - 11)° = 180° { Being a linear pair}.

or, 8x - 28°= 180°

8x = 180° + 28°

\(x = \frac{208}{8} \)

Therefore, the value of x is 26°.

Now,

3x - 11°= 3×26°-11° = 67°

Again,

67°+90°+(2y+5)° = 180° { being linear pair}.

157°+2y+5° = 180°

or, 2y + 162° = 180°

or, 2y = 180° - 162°

\(y = \frac{18}{2} \)

Therefore, the value of y is 9°.

The value of x is 26° and y is 9°.

Hope it helps....

The solution of the initial value problem y" + 6y' + 10y = 0, y(0) = 2, and y'(0) = -10 is  y(t) = e^(-3t)(2 * cos(t) - 4 * sin(t)).

To find the solution of the initial value problem y" + 6y' + 10y = 0, y(0) = 2, and y'(0) = -10, we will first solve the homogeneous differential equation and then apply the initial conditions.

1. Solve the homogeneous differential equation y" + 6y' + 10y = 0:
Write the characteristic equation: r^2 + 6r + 10 = 0.

2. Solve the characteristic equation:
Using the quadratic formula, we get r = (-6 ± √(6^2 - 4(10))) / 2 = -3 ± i.

3. Write the general solution based on the roots:
The general solution will be in the form y(t) = e^(-3t)(C1 * cos(t) + C2 * sin(t)), where C1 and C2 are constants.

4. Apply the initial conditions:
For y(0) = 2, we have 2 = e^(0)(C1 * cos(0) + C2 * sin(0)) => C1 = 2.

For y'(0) = -10, first find y'(t):
y'(t) = e^(-3t)(-3(C1 * cos(t) + C2 * sin(t)) + (-C1 * sin(t) + C2 * cos(t))).

Now plug in t = 0 and y'(0) = -10:
-10 = e^(0)(-3(2 * cos(0) + C2 * sin(0)) + (-2 * sin(0) + C2 * cos(0))) => C2 = -4.

5. Write the particular solution:
The particular solution is y(t) = e^(-3t)(2 * cos(t) - 4 * sin(t)).

As t → ∞, the exponential term e^(-3t) goes to zero, making the solution approach zero. Therefore, the solution behaves as a decreasing function without bounds as t → ∞. So correct option is "Decreasing without bounds".

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Complete Question

Find the solution of the initial value problem y" + 6y' + 10y = 0, Y y C) 10. 2 TT TT ) - = 0, y' = y(t) = How does the solution behave as t → 00? oo Choose one Choose one Decreasing without bounds Increasing without bounds Exponential decay to a constant Oscillating with increasing amplitude Oscillating with decreasing amplitude

Answer:

Your answer is.......

x^3 + 2x^2 + 4x + 8=0 Note.. if x=-2 then whole equation is 0

So, (x+2) is one factor.

x^3 + 2x^2 + 4x + 8

=x^2(x+2)+4(x+2)

(x+2)(x^2+4)

Mark my answer as brainlist. pls pls pls

Answer:

The angle of elevation of the plane measured from Ahmed is approximately 36.67°

Step-by-step explanation:

The given parameters of the float plane are;

The height of the float plane above the water, y = 350 m

The horizontal distance of the float plane from Ahmed, x = 470 m

Given that Ahmed is sitting on the dock, by the water, by trigonometric ratios, we have;

The height of the float plane, the distance of the plane from Ahmed and the line of sight forming the angle of elevation of the plane measured from Ahmed, form a right triangle

\(tan\angle X = \dfrac{Opposite \ leg \ length}{Adjacent \ Leg\ length}\)

Therefore

\(tan(\theta) = \dfrac{y}{x}\)

Where;

θ = The angle of elevation of the plane measured from Ahmed

y = The leg of the right triangle opposite the reference angle

x = The leg  of the right adjacent to reference angle

Therefore;

θ = arctan(y/x) which gives;

θ = arctan(350/470) ≈ 36.67°

The angle of elevation of the plane measured from Ahmed, θ ≈ 36.67°.

Answer: 0.75 minutes per lap

Explanation:

Answer:

\((x -12)(x + 12)\)

Step-by-step explanation:

Given

See attachment for chart

Required

The factors of \(x^2 - 144\)

First, express \(x^2 - 144\) as \(ax^2 + bx + c\)

So, we have:

\(x^2 - 144 = x^2 + 0x - 144\)

Compare the above expression to: \(ax^2 + bx + c\)

We have:

\(ax^2 + bx + c = x^2 + 0x - 144\)

So:

\(a =1\)

\(b =0\)

\(c = -144\)

and

\(a * c = d * e\)

Calculate ac

\(a* c = 1 * -144\)

\(a* c = -144\)

Rewrite as:

\(a* c = -12 * 12\)

Recall that:

\(a * c = d * e\)

Hence:

\(d = -12; e = 12\)

So, on the x chart, we have:

        ac

d                  e

        b

This gives:

        -144

-12                  12

        0

The factors are

\((x + d)(x + e)\)

\((x -12)(x + 12)\)

Answer:

✔ (x – 12)

 and  

✔ (x + 12)

Step-by-step explanation:

Answer:

3,590.16 Honduran Lempira.

Answer:

4: Matthias

5:8

6: 13 microprocessors

7: No, the poster wouldn't fit

8: 0.2m

9:Yes

10:No

Step-by-step explanation:

for 6:

for 7:

for 8:

for 9:

for 10:

4- Matthias

5-8

6- 13 microprocessors

7- No, the poster wouldn't fit

8- 0.2m

9-Yes

10-No

Step-by-step explanation:

6-   (3 .5)^2  in = 12.25 in^2

      12.25 / 49 / 54= about 13 microprocessors

7-    if you multiply 40*30 you get 1200

      if you multiply 36*36 you get 1296

8-   The edge length of the unit cube is 0.512 which is 0.8m

      the edge length of the new cube is the root of 1 which is 1m

      so you would subtract 1-0.8 and that will give you 0.2 m.

9-    cube root for 729 wouldn't be an integer, so it can't be a perfect               cube or square. 36 would be an exponent expression of 729.

10-     the roots of 1 and -1 are equal, but not the roots of 0, the roots of 0 are 0.

Answer:

The answer is 157

Step-by-step explanation:

Answer:

157

Step-by-step explanation:

just took the test ;)

They are used in navigation, astronomy, and surveying. Rays are also used in computer graphics, physics, and optics. In addition, rays are used in the study of optics to describe the behavior of light as it travels through different mediums.

According to the video above, the geometric object called a ray has the characteristics that it has one endpoint and extends in away from that endpoint without end.A ray is a line that starts at a single point and extends in one direction to infinity. Rays are commonly used in geometry to explain lines and line segments. A ray has one endpoint, called the endpoint of the ray, from which it starts. The other end of the ray continues in the direction in which it is pointed without any limit. A ray is named by using its endpoint and another point on the ray, with the endpoint first. For example, if ray A starts at point P and passes through point Q, we write the name of the ray as ray PAQ or ray QAP. Rays can be part of line segments and other geometric objects. They can also be used to explain angles and the direction of a light source. Rays are commonly used in mathematics, science, and engineering.

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Answer:

B. SAS

\( \frac{sm}{dl} = \frac{27}{9} = 3 \\ \frac{am}{el} = \frac{15}{5} = 3 \\ angle \: m= angle \: l\)

Brainliest please~

By SAS similarity, ΔASM is similar to ΔDLE. Thus, option C is correct.

The SAS theorem is also known as the side-angle-side theorem, also known as a statement in Euclidean geometry that states two triangles are congruent if their corresponding sides are both the same length and their included angles are both of the same measures.

According to the given figure,

SM=27

DL=9

MA=15

LE=5,

∠M=∠L=31°

It is required to determine the similarity postulate that applies. Therefore,

From the ΔASM and ΔDLE, we have

\(\frac{SM}{DL}=\frac{27}{9} \\=3\\\frac{ML}{LE}=\frac{15}{5}\\ =3\\ Hence, \frac{SM}{DL}= \frac{ML}{LE}\)

∠M=∠L=31°

Hence, by SAS similarity, ΔASM is similar to ΔDLE.

Therefore, it can be concluded that option C is correct.

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The probability that the component requires both painting and galvanizing is 0.06.

Considering the values provided in the question,

P(Painted) = 0.20

P(Galvanized) = 0.30

Both the events are independent of each other.

The probability of the part needs both painted and galvanized is

= P(Painted and Galvanized)

= P(Painted) × P(Galvanized)

= 0.20 × 0.30

= 0.06

Therefore, The probability of the part needs both painted and galvanized is 0.06.

The possibility of an event happening is determined by probability. We may need to forecast an event's result in a variety of real-world circumstances. The outcomes of an event may be certain or uncertain to us. In these circumstances, we say if there is a chance the event will happen or not.

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