Step-by-step explanation:
5x=95
X=95-5
X=90
Therefore ans is 90
What i an equation of the line that i parallel to y= - 5x 6 and pae through the point (-4, -1)?
The equation of the line that is parallel to y=-5x+6 and passes through the point (-4,-1) is y = -5x-21.
How do you find slope through given points?Given the coordinates of two points on the line, use the slope formula to get the slope of the line. The slope formula, or the ratio of the change in the y values to the change in the x values, is m=(y2-y1)/(x2-x1). The initial point's coordinates are x1 and y1, respectively. The second points' coordinates are x2, y2.The slope formula rise/run is all that is required to determine slope between two places. With various forms of accessible information about the line, there are many formulas to determine the slope. When two points on the line are known, the formula for finding the slope from two points is particularly utilized.Given data :
Here, given equation of line is y = -5x+6
Required line is parallel to this given line, so we can say that the slope is same for the lines.
General equation of a line be y = mx+c , where m is the slope
Comparing given equation with this equation we get,
m = -5
The required line also passes through the point (-4, -1)
Now, we know that,
m = (y2-y1)/(x2-x1).
⇒ -5 = (-1 - Y ) / ( -4 - x )
⇒ -5 = y + 1 / x + 1
⇒ y+1 = -5x-20
⇒ y = -5x-21
Hence the equation proved.
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Consider a sequence defined by the explicit rule f(n)=-8+3 (n − 1). Choose True or False for each statement.
Given the general n th term of the sequence,
\(f(n)=-8+3(n-1)\)For n = 1,
\(\begin{gathered} f(1)=-8+3(1-1) \\ =-8 \end{gathered}\)Therefore, the first statement is true.
Now for n = 2,
\(\begin{gathered} f(2)=-8+3(2-1) \\ =-8+3 \\ =-5 \end{gathered}\)Therefore, the first two terms of the sequence is -8 and -5.
So, the common difference is,
\(-5-(-8)=-5+8=3\)Therefore, the common difference is 3.
So, the second statement is true.
Now fifth term is for n = 5.
Therefore,
\(\begin{gathered} f(5)=-8+3(5-1) \\ =-8+(3\times4) \\ =-8+12 \\ =4 \end{gathered}\)Therefore the fifth term is 4 but not 7.
Hence, the third statement is false.
when is written as a decimal, what is the maximum length of the repeating section of the representation?
When a rational number is expressed as a decimal, the maximum length of the repeating section in the decimal representation is equal to the number of distinct prime factors in the denominator.
For example,
If we consider the fraction 1/7, the decimal representation is 0.142857142857..., and the repeating section has a length of 6 digits. This is because the denominator 7 is a prime number, and there is only one distinct prime factor.
Similarly, for the fraction 1/6, the decimal representation is 0.1666..., and the repeating section has a length of 1 digit. The denominator 6 has two distinct prime factors (2 and 3), but since the prime factor 2 is repeated, it contributes to a repeating section of length 1.
In general, if a rational number can be expressed in the form p/q, where p and q are coprime integers (they have no common factors other than 1), and q has prime factors p1^a1 * p2^a2 * p3^a3 * ..., then the maximum length of the repeating section in the decimal representation is equal to the number of distinct prime factors, which is a1 + a2 + a3 + ...
It's important to note that not all rational numbers have repeating decimal representations. For example, the fraction 1/2 can be expressed as the terminating decimal 0.5.
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A taxicab charges a flat rate of $5.00. They then charge $1.50 for every mile. Write an algebraic expression that gives the total cost for any number of miles. Then evaluate the expression for traveling 20 miles Think: What does it mean to
Explanation:
Let 'y' be the total charge for the trip and let 'x' be the number of miles.
When the number of miles x is 0, the taxicab charges $5.00, so y = 5 at first.
Then for each mile x they charge $1.50.
The algebraic expression is:
\(y=1.5x+5\)To evaluate the expression for traveling 20 miles, we have to replace x for 20 in the expression above:
\(y=1.5\cdot20+5=30+5=35\)Answer:
The expression:
\(y=1.5x+5\)The charge for traveling 20 miles is $35
solve this math 1-1=?
Serious question or not the answer is zero
Answer:
0
Step-by-step explanation:
One minus one is zero.
how do you graph y= 6/5x + 1?
Answer:
Start at postive 1 on the y axis put a dot there. From the dot go down 6 and go left 5.
Step-by-step explanation:
6/5=rise over run
1=y-axis
y=mx+b
m=slope
b=y-intersept
Step-by-step explanation:
Hey, there!!
To graph a equation, we must find the coordinates of x and y.
So, as the equation is,
\(y = \frac{6}{5} x + 1\)
Here, the equation is for finding the coordinates of y and x should be supposed. Remember, always suppose the value in equal interval.
Now,
x = 0 1 2 3
y= 1 2.2 3.4 4.6
Here, if you are confused how do i get 1, 2.2,3.4,4.6 as y value, put the value of x such as,
\(y = \frac{6}{5} \times 0 + 1\)
which is equal to 1.
so,in this we got values.
Now,
List coordinates,
(0,1),(1,2.2),(2,3.4),(3,4.6)
Then plot on graph!!!
Hope it helps.....
write a question of interest for which a two-sided t test for the difference in populations means can be used to answer example
To determine whether the mean weight of two distinct turtle species is equal. It would take too much time and money to weigh each turtle because there are thousands of them in each group.
A two-sample t-test is used to determine whether or not genuine population means are equal.
The accompanying null hypothesis is usually used in a two-sample t-test:
\(H_0\): The two population averages are equivalent when 1 = 2.
The alternative hypothesis might have two tails, a left or right tail, or none at all:
Two-tailed \(H_1\): μ1 ≠ μ2 Neither of the two population means is equal.
(Left-tailed) \(H_1\): Population 1 mean is lower than population 2 mean by a factor of 1.
\(H_1\) (right-tailed): Populations 1 and 2 have mean values that are higher than each other.
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how many atheletes in total were acccused of using performance-enhancing drugs? of these, how many were using and how many were not? what percentage of those accused of using were falsely accused?
There have been numerous cases of athletes being accused of using performance-enhancing drugs, and the numbers may vary depending on the sport, country, and time period in question.
Additionally, determining how many athletes were using or not using performance-enhancing drugs would require specific information on individual cases.
Regarding the percentage of athletes falsely accused of using performance-enhancing drugs, it is difficult to determine an accurate figure without examining each case in detail. False accusations may occur due to various reasons, such as flawed testing procedures or contaminated supplements, and the percentage of false accusations may vary depending on the situation.
If you have a specific case or sport in mind, I can try to provide you with more information on that topic.
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compare numbers.
Performs arithmetic operations (+, –, *, /) as well as comparison or relational operations (<, >, =); the latter are used to compare numbers.
Comparison or relational operations, such as <, >, =, allow for comparing numbers. They determine if a number is less than, greater than, equal to, or not equal to another number, enabling decision-making and comparisons within arithmetic and programming operations.
When comparing numbers, you can use various relational operators to determine the relationship between them. Here are the commonly used comparison operators:
Less than (<): This operator compares two numbers and returns true if the first number is smaller than the second number. For example, 5 < 10 is true.
Greater than (>): This operator compares two numbers and returns true if the first number is larger than the second number. For example, 10 > 5 is true.
Less than or equal to (<=): This operator compares two numbers and returns true if the first number is smaller than or equal to the second number. For example, 5 <= 5 is true.
Greater than or equal to (>=): This operator compares two numbers and returns true if the first number is larger than or equal to the second number. For example, 10 >= 10 is true.
Equal to (==): This operator compares two numbers and returns true if they are equal. For example, 5 == 5 is true.
Not equal to (!=): This operator compares two numbers and returns true if they are not equal. For example, 5 != 10 is true.
These comparison operators allow you to compare numbers and make decisions based on their relationships within arithmetic or programming operations.
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Find m/TRS if m/1 = 2x + 4 and
m/2= 3x - 3.
T
P
S
1
R
If the angles are ∠1 = 2x + 4 and ∠2 = 3x - 3, then m∠TRS = 36°.
What is an angle?
An angle is a figure in plane geometry that is created by two rays or lines that have a shared endpoint. The Latin word "angulus," which meaning "corner," is the source of the English term "angle." The shared terminus of two rays is known as the vertex, and the two rays are referred to as sides of an angle.
The measure of ∠1 = 2x + 4
The measure of ∠2 = 3x - 3
The measure of ∠TRS is -
∠TRS = ∠1 + ∠2
Since, PR is a bisector then ∠1 = ∠2.
The equation is -
2x + 4 = 3x - 3
2x - 3x = - 3 - 4
-x = -7
x = 7
Substitute the value of x in the angles -
∠1 = 2(7) + 4
∠1 = 14 + 4
∠1 = 18°
∠2 = 3(7) - 3
∠2 = 21 - 3
∠2 = 18°
So, the value of ∠TRS is -
∠1 + ∠2
18° + 18°
36°
Therefore, the measure of ∠TRS is 36°.
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an ant starts from the origin (0, 0) of an xy-grid. each time it moves, it goes either up (50% chance) or right (50% chance) by one unit of distance. after 12 moves, what is the probability that the ant is located at the point (4, 8)?
The given ant can only go up or right here in every turn and as there is a 50% chance for either of
them, therefore each of the paths in 12 moves would be equally likely here.
As for each of the 12 steps here, there are 2 ways that the ant can move, therefore total number of
paths in 12 moves is computed as:
= 2^12 here.
We use the multiplication rule for independent events here to get the total number of outcomes here
by getting the product of the number of outcomes for each of those independent events.
Total number of 12 move paths such that we reach 4, 8 here is computed as the number of
permutation of 12 moves with 4 rights and 8 up points here. This is computed here as:
12!/(8!4!) = 495
Therefore, the probability that the ant is located at (4, 8) here is computed as:
=
495/(2^12)
= 0.1208
Therefore, 0.1208 is the required probability here
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Find the slope of the line.
Answer:
Brainleist!
Step-by-step explanation:
first obvious thing is the line is positive
it goes up 3 over 2
so its 3/2
positive = 3/2
find the inequality represented by the graph
Answer:
First, find the function of the line:
slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{0-3}{0-4} =\frac{-3}{-4}=\frac{3}{4}\)y-intercept = 0Therefore, the function is \(y=\frac{3}{4} x\).
Since it's the area under the graph that's shaded(not ≥ or >) and the graphed line is dotted(not ≤ or ≥), then the inequality would be \(y<\frac{3}{4} x\).
buses arrive at a specified stop at 15-minute intervals starting at 7am. if a passenger arrives at the stop at a time that is uniformly distributed between 7am and 7:30am, find the probability that he waits
If buses arrive at stop at "15-minute" intervals, then the probability that he waits more than 10 minutes for a bus is "1/3".
Let us denote the arrival-time of the passenger by X, where X is uniformly distributed between 7am and 7:30am. hence, the probability-density-function (pdf) of "X" is written as :
f(x) = 1/30, for 7am ≤ x ≤ 7:30am
f(x) = 0, otherwise
We observe that, the passenger will wait for more than 10 minutes for a bus only if he arrives between 7:00 a.m. and 7:05 a.m. , or between 7:15 a.m. and 7:20 a.m.
So, the probability for waiting time can be written as ;
⇒ \(\int\limits^5_0 {\frac{1}{30} } \, dx\) + \(\int\limits^{20}_{15} {\frac{1}{30} } \, dx\),
⇒ (1/30)(5 - 0) + (1/30)(20 - 15);
⇒ 1/3.
Therefore, the required probability is 1/3.
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The given question is incomplete, the complete question is
Buses arrive at a specified stop at 15-minute intervals starting at 7am. If a passenger arrives at the stop at a time that is uniformly distributed between 7am and 7:30am, find the probability that he waits more than 10 minutes.
Solve the following equation by first writing the equation in the form a x squared = c: t squared minus 49 = 0 a. t = 49 b. t = plus-or-minus 49 c. t = 7 d. t = plus-or-minus 7 Please select the best answer from the choices provided A B C D
The best answer is t = 7. Option C
What is a quadratic equation?A quadratic equation is simply defined as an equation that could be rearranged in standard form.
It is also described as an algebraic equation having the highest exponent of as 2.
It is so arranged such that;
x represents an unknown valueVariables, a, b, and c represent known numbersAlso, a is not equal to 0, a ≠ 0It is important to note that the three methods of solving quadratic equation are;
FactorizationUsing the quadratic formulaUsing completing the square methodFrom the information given, we have that the form is;
x² = c
Given t squared minus 49 = 0
First, represent mathematically
t² - 49 = 0
Now, collect like terms, we have;
t² = 49
Take square root of both sides
t = √49
t = 7
Hence, the equation is t = 7
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The perimeter of a rectangle is 60 meters. The length of a rectangle is 2 m less than the width find the length and the width of the rectangle
Step-by-step explanation:
length = (x-2)
width = x
perimeter = 2 lengths + 2 widths
60 m = (x-2) + (x-2) + x + x
60 m = 4x - 4
64 m = 4x
16 m = x
length = (x-2) = (16-2) = 14 m
width = x = 16 m
The value of a ratio is ______
A. The sum of the two quantities in the ratio.
B. The quotient of the two quantities in the ratio.
C. The difference of the two quantities in the ratio.
D. The product of the two quantities in the ratio.
Answer:
B. The quotient of the two quantities in the ratio.
4. Let X, Y, Z have joint pdf fx.v.z®,M+ z) =k(2+y+z) for 0≤x≤ 1, 0≤ y ≤1, 0≤ z≤1. (a) Find k. (b) Find fx(xly, z) and fz(zlx,y).
The value of integration ∫∫∫fx.v.z(x,y,z)dxdydz = 1∴ k/3 = 1 ⇒ k = 3
Given, the joint pdf of three random variables X, Y, and Z is given by: fx.v.z(x,y,z) = k(2+y+z) 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, 0 ≤ z ≤ 1
(a) To find k, we need to integrate the joint pdf over the entire range of the random variables: ∫
∫∫fx.v.z(x,y,z)dxdydz = 1
∫∫∫k(2+y+z)dxdydz = 1 [0 ≤ x ≤ 1, 0 ≤ y ≤ 1, 0 ≤ z ≤ 1]
∫∫k(2+y+z)dx[0 ≤ x ≤ 1]
∫k[x(2+y+z)]dy[0 ≤ y ≤ 1]
k[x(2+y+z)y]z[0 ≤ z ≤ 1]
∫∫kx(2+y+z)dydz[0 ≤ x ≤ 1]
∫kx[y(2+z)+yz]dz[0 ≤ y ≤ 1]
kx[yz + (2+z)/2]z[0 ≤ z ≤ 1]
kx[yz^2/2 + z^2/2 + z(2+z)/2][0 ≤ x ≤ 1, 0 ≤ y ≤ 1, 0 ≤ z ≤ 1]
Integrating w.r.t z: kx[y(z^3/3+z^2/2+(2/2)z)][0 ≤ x ≤ 1, 0 ≤ y ≤ 1]
Substituting the limits of integration:
k/3 [0 ≤ x ≤ 1, 0 ≤ y ≤ 1]
k/3 ∫∫[0 ≤ x ≤ 1, 0 ≤ y ≤ 1]
Therefore, ∫∫∫fx.v.z(x,y,z)dxdydz = 1∴ k/3 = 1 ⇒ k = 3
(b) We need to find the marginal pdfs fx(x, y, z) and fz(z, x, y).
fx(x, y, z) = ∫f(x, y, z)dydz[0 ≤ y ≤ 1, 0 ≤ z ≤ 1]
fx(x, y, z) = k ∫(2+y+z)dydz[0 ≤ y ≤ 1, 0 ≤ z ≤ 1]
fx(x, y, z) = k [y(2+y+z)/2 + yz + z^2/2][0 ≤ y ≤ 1, 0 ≤ z ≤ 1]
fx(x, y, z) = 3/2 [y(2+y+z)/2 + yz + z^2/2][0 ≤ y ≤ 1, 0 ≤ z ≤ 1]
fz(z, x, y) = ∫f(x, y, z)dxdy[0 ≤ x ≤ 1, 0 ≤ y ≤ 1]
fz(z, x, y) = k ∫(2+y+z)dxdy[0 ≤ x ≤ 1, 0 ≤ y ≤ 1]
fz(z, x, y) = k [(2+y+z)/2 x + (2+y+z)/2 y + xy][0 ≤ x ≤ 1, 0 ≤ y ≤ 1]
fz(z, x, y) = 3/2 [(2+y+z)/2 x + (2+y+z)/2 y + xy][0 ≤ x ≤ 1, 0 ≤ y ≤ 1]
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2. There are 6 children that each want to eat half of a chocolate bar. If they buy a package of 4 chocolate bars, how many chocolate bars will be left over after they've eaten?
Answer:
1
Step-by-step explanation:
6 children that each want to eat half of a chocolate bar (0.5)
6 * 0.5 = 3 - chocolate bars will be eaten
They bought a package of 4 chocolate bars
4 - 3 = 1 - chocolate bar will be left
Salma runs 6 miles in 55 minutes. At the same rate, how many miles would she run in 44 minutes?
Answer:
The number of miles she would run in 44 minutes is;
\(4.8\text{ miles}\)Explanation:
Given that;
Salma runs 6 miles in 55 minutes;
The rate at which she run is;
\(\text{rate =}\frac{\text{ distance}}{\text{time}}=\frac{6}{55}miles\text{ per minute}\)At the same rate, the distance it will cover in 44 minutes is;
\(\begin{gathered} \text{time}=\frac{\text{distance}}{\text{rate}} \\ \text{distance}=\text{time}\times rate \\ \text{distance}=44\times\frac{6}{55} \\ \text{distance = 4.8 miles} \end{gathered}\)The number of miles she would run in 44 minutes is;
\(4.8\text{ miles}\)A hot air balloon rises 9 meters every 3 seconds. How high does the hot
air balloon rise in 15 seconds?
Answer:
45 meters
Step-by-step explanation:
so if i divided 9 by 3 it's 3 meters per sec then i times 15 by 3 equals 45
Which set of rectangular coordinates describes the same location as the polar coordinates (4,pi)?
A. (0,-4)
B. (-4,0)
C. (0,4)
D. (4,0)
The rectangular coordinate of \(\mathbf{(4,\pi)}\) is (-4,0)
The polar coordinate is given as:
\(\mathbf{(4,\pi)}\)
To represent the polar coordinates properly, we make use of:
\(\mathbf{(r,\theta) = (4,\pi)}\)
Where r represents radius
The rectangular coordinate is represented as: (x,y)
Where:
\(\mathbf{x = rcos(\theta)}\)
\(\mathbf{y = rsin(\theta)}\)
So, we have:
\(\mathbf{x = 4 \times cos(\pi)}\)
Evaluate cos(pi)
\(\mathbf{x = 4 \times -1}\)
Multiply
\(\mathbf{x = -4}\)
Similarly,
\(\mathbf{y = 4 \times sin(\pi)}\)
Evaluate sin(pi)
\(\mathbf{y = 4 \times 0}\)
Multiply
\(\mathbf{y = 0}\)
Recall that the rectangular coordinate is represented as (x,y)
Hence, the rectangular coordinate of \(\mathbf{(4,\pi)}\) is (-4,0)
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An automated car wah can wah 30 car in 5 hour. How long would it take to wah 120 car?
Repone
A 15 h B 20 h
C 25 h D 30 h
pleae help
It would take the automated car wash 20 hours to wash 120 cars.
What is rate ?
In general, a rate is a measure of how much of something happens within a certain period of time. It can be thought of as a ratio that compares two different units of measurement.
In the context of the problem, the rate at which the automated car wash can wash cars is the number of cars that it can wash per unit of time.
The rate at which the automated car wash can wash cars is 30 cars per 5 hours. To find out how long it would take to wash 120 cars, we can use the formula:
Time = (Number of cars / Rate)
Time = (120 cars / 30 cars per 5 hours)
Time = (120/30) * 5 hours
Time = 20 hours
So it would take the automated car wash 20 hours to wash 120 cars.
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The rate at which the automated car wash can wash cars is 30 cars per 5 hours. To find out how long it would take to wash 120 cars, we can use the formula:
Time = (Number of cars / Rate)
Time = (120 cars / 30 cars per 5 hours)
Time = (120/30) * 5 hours
Time = 20 hours
So it would take the automated car wash 20 hours to wash 120 cars.
Given a 32×8ROM chip with an enable input, show the external connections necessary to construct a 128×8ROM with four chips and a decoder.
The combination of the decoder and the 32×8ROM chips forms a 128×8ROM memory system.
To construct a 128×8ROM with four 32×8ROM chips and a decoder, the following external connections are necessary:
Step 1: Connect the enable inputs of all the four 32×8ROM chips to the output of the decoder.
Step 2: Connect the output pins of each chip to the output pins of the next consecutive chip. For instance, connect the output pins of the first chip to the input pins of the second chip, and so on.
Step 3: Ensure that the decoder has 2 select lines, which are used to select one of the four chips. Connect the two select lines of the decoder to the two highest-order address bits of the four 32×8ROM chips. This connection will enable the decoder to activate one of the four chips at a time.
Step 4: Connect the lowest-order address bits of the four 32×8ROM chips directly to the lowest-order address bits of the system, such that the address lines A0-A4 connect to each of the four chips. The highest-order address bits are connected to the decoder.Selecting a specific chip by the decoder enables the chip to access the required memory locations.
Thus, the combination of the decoder and the 32×8ROM chips forms a 128×8ROM memory system.
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7 Given APHS = ACNF, find the values of x, y, and z.F(3y - 1)H (6x - 290°S36°Р115°fc(4z - 32)N
Here, we have two congruent triangles
Since they are congruent, they have similar and equal angles.
From the diagram, we can see that;
6x - 29 = 115 (They are both topmost angles of both triangles)
Solving this, we have;
6x = 115 + 29
6x = 144
divide both sides by 6
x = 144/6
x = 24°
Furthermore, we can see that;
4z - 32 = 36
4z = 36 + 32
4z = 68
z = 68/4
z = 17°
And lastly;
(3y-1) + 115 + (4z-32) = 180 ( sum of angles in a triangle)
Since z = 17, 4z - 32 will be 4(17)-32 = 68 - 32 = 36
Thus;
3y - 1 + 115 + 36 = 180
3y + 150 = 180
3y = 180 -150
3y = 30
divide both sides by 3
y = 30/3
y = 10°
x = 24° , y = 10° and z = 17°
The ratio of kids to adults in a dollar store is 2:1. Suppose there is a total of 50 kids to adults. How many kids are there?
Find both the vector equation and the parametric equations of the line through (−5,3,5) and (4,−3,0), where t=0 corresponds to the first given point. The vector equation is ⟨x,y,z⟩=1⟩+ Find the parametric equations of the line through (−5,3,5) in the direction from (−5,3,5) toward (4,−3,0) The parametric equations are x=,y=,z= (Use the answer from the previous step to find this answer
The vector equation of the line is ⟨x,y,z⟩ = ⟨−5,3,5⟩ + t⟨9,−6,−5⟩.
The parametric equations of the line are x = -5 + 9t, y = 3 - 6t, and z = 5 - 5t.
To find the vector equation and the parametric equations of the line passing through the points (−5,3,5) and (4,−3,0), we first need to determine the direction vector of the line. We can obtain the direction vector by subtracting the coordinates of the first point from the coordinates of the second point.
Direction vector = (4,−3,0) - (−5,3,5) = (4 + 5, −3 − 3, 0 − 5) = (9,−6,−5).
Now that we have the direction vector, we can write the vector equation of the line using the first point (−5,3,5) and the direction vector:
⟨x,y,z⟩ = ⟨−5,3,5⟩ + t⟨9,−6,−5⟩.
This equation represents the line passing through the given points.
To obtain the parametric equations of the line, we can express each coordinate (x, y, z) in terms of a parameter t. Using the direction vector (9,−6,−5), we can set up the parametric equations as follows:
x = -5 + 9t,
y = 3 - 6t,
z = 5 - 5t.
These equations provide a way to represent any point on the line using the parameter t. By plugging in different values of t, we can obtain various points on the line.
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what does 160=7x+6 equal to?
Answer:
x=22
Step-by-step explanation:
7x+6=160.
Lets start by moving 6 over to the other side. We can do this by subtracting 6 from both sides of the equation.
7x+6-6=160-6
7x=154
Now, let's isolate x by getting rid of the 7. The 7 is being multiplied with x, so to get rid of it we have to divide both sides by 7.
7x/7 = 154/7
x=22
Look Below :
Step-by-step explanation:
160 - 6 = 7x
154 = 7x
Or
7x = 154
x = 22
Can someone help me it’s geometry I will really appreciate it :,)
Answer:
LAS LINEAS PARALELAS TIENEN LA MISMA PENDIENTE. ENTONCES ES
-4
Step-by-step explanation:
What is the common difference or common ratio for the sequence: 27, 9, 3, 1, 1/3, ...
Answer:
It's dividing by 3 everytime, so 1/3
Step-by-step explanation: