A 0.62 m copper rod with a mass of 0.14 kg carries a current of 12 A in the positive x direction. Let upward be the positive y f5 6/1/22, 10:37 AI What is the magnitude of the minimum magnetic field needed to levitate the rod?
Answers
The magnitude of the minimum magnetic field needed to levitate the rod is approximately 0.185 T.
To calculate the magnitude of the minimum magnetic field needed to levitate the copper rod, we can use the equation for the magnetic force on a current-carrying wire: F = BILsin(θ)
Where:
F is the magnetic force
B is the magnetic field
I is the current
L is the length of the wire
θ is the angle between the magnetic field and the current direction
In this case, the copper rod carries a current of 12 A in the positive x direction, and we need to find the minimum magnetic field required to levitate it.
Given:
Length of the rod (L) = 0.62 m
Mass of the rod (m) = 0.14 kg
Current (I) = 12 A
First, let's calculate the magnetic force required to counteract the weight of the rod (assuming the rod is in a uniform magnetic field and the angle θ is 90 degrees, perpendicular to the field):
F = mg
Where:
m is the mass of the rod
g is the acceleration due to gravity (approximately 9.8 m/s^2)
F = (0.14 kg) * (9.8 m/s^2) = 1.372 N
Now, we can rearrange the formula for the magnetic force to solve for the magnetic field (B):
B = F / (ILsin(θ))
Since sin(90 degrees) = 1, we can simplify the equation:
B = F / (IL)
B = 1.372 N / (12 A * 0.62 m)
Using a calculator, the magnitude of the minimum magnetic field needed to levitate the rod is approximately:
B ≈ 0.185 T (tesla)
Therefore, the magnitude of the minimum magnetic field needed to levitate the rod is approximately 0.185 T.
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Related Questions
Which terrestrial world has the most atmospheric gas?.
Answers
Answer:
Venus
Explanation:
It has the most atmospheric gas, and it’s made up of 96% of Carbon Dioxide and around 3.5% of molecular nitrogen.
I hope it helps! Have a great day!
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predict the date of the next full moon.
please help me quickly i will give you branliest! ๑>ᴗ<๑
Answers
Answer:
The 19th
Explanation:
going based off of the calandar, you just start from the 4 at the bottom and then just count up as you go through it agains starting back at the top.
Answer: the 19th
Explanation:
count the number of days it takes you to get from full moon (20th) to no moon (4th)
it takes 15 days to get to the no moon phase
so theoretically if we add 15 days to the 4th when there was no moon, we should find the day when there is a full moon
4 + 15 = 19
so the full moon should happen on the 19th :))
A point charge produces an electric flux of +305 N⋅m2/C through a gaussian sphere of radius 15.0 cm centered on the charge. a What is the flux through a gaussian sphere with a radius 29.0 cm ?b What is the magnitude of the charge?
Answers
Given
The electric flux is
\(\phi=+305\text{ Nm}^2\text{ /C}\)Radius of the sphere,
\(r=15.0\text{ cm}\)To find
a. The flux through a gaussian sphere with radius of 29.0 cm.
b. The magnitude of the charge
Explanation
a. Since the gaussian sphere covers the same charge so the electric flux through both the sphere will be same.
Thus the required flux is
\(\phi=305\text{ Nm}^2\text{ /C}\)b.
The magnitude of the charge is
\(\begin{gathered} Q=\phi\epsilon_o \\ \Rightarrow Q=305\times8.85\times10^{-12} \\ \Rightarrow Q=30.97\times10^{-12}\text{ C} \end{gathered}\)Conclusion
a. The flux is
\(305\text{ Nm}^2\text{ /C}\)b. The charge is
\(30.97\times10^{-12\text{ }}C\)What would happen to the magnitude of the force if the distance between the 2 masses is decreased by 6?
Answers
F = G * (m1 * m2) / r^2
Where:
F = Magnitude of the force G = Gravitational constant m1 and m2 = Masses of the two objects r = Distance between the centers of the two objects
If the distance between the two masses is decreased by 6, then the new distance would be r - 6.
So, the new magnitude of the force would be:
F' = G * (m1 * m2) / (r - 6)^2
Since the denominator of the equation is squared, any decrease in the distance r would cause a significant increase in the magnitude of the force F'. Therefore, decreasing the distance between the two masses by 6 would result in a significant increase in the magnitude of the force between them.
What factors can cause an induced current in a wire loop through which a magnetic field passes?.
Answers
The factors that can cause an induced current in a wire loop are number of turns of the wire, area of the wire and magnetic field strength.
Induced emf
According to Faraday's law of electromagnetic induction, the rate of change of flux in a magnetic field is proportional to the flux through the magnetic field.
emf = dФ/dt
where;
Ф is magnetic flux = BA (magnetic field and area of the coil)emf = N(BA)/dt
where;
N is number of turnsThus, the factors that can cause an induced current in a wire loop are number of turns of the wire, area of the wire and magnetic field strength.
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stanford institutes of medicine summer research program
Answers
The Stanford Institutes of Medicine Summer Research Program is a program offered by Stanford University that provides opportunities for undergraduate students to engage in biomedical research.
The program typically lasts for 8 to 10 weeks during the summer. Students have the opportunity to work with faculty mentors on cutting-edge research projects and gain hands-on experience in various aspects of medicine and biomedical sciences. The program aims to expose students to the research process and help them develop their scientific skills.
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The Carnot cycle consists of a combination of ____ and ____ processes.
Answers
The Carnot cycle is an ideal reversible closed thermodynamic cycle. Carnot's cycle consists of a combination of the adiabatic and isothermal processes.
Carnot's engine is the theoretical idea proposed by Leonard Carnot, that determines the efficiency of a heat engine between the heat and cold reservoir. The Carnot engine works by the Carnot cycle.
The Carnot cycle is a reversible closed thermodynamic cycle that has four successive operations. This involves isothermal compression, adiabatic compression, isothermal expansion, and adiabatic expansion.
Hence, the Carnot cycle involves isothermal and adiabatic processes.
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While playing a video game on your laptop, the laptop gets very hot. Which Thermodynamics Law does this exemplify?
Answers
Answer
The dedicated graphics card is used when performing hardware-intensive tasks so as to ensure efficiency and balanced performance. However, it uses more power and thus produces more heat. When the cooling system is not sufficient or the room is not well ventilated, your PC begins to overheat while playing games. Explanation: How does the second law of thermodynamics relate to the direction of heat flow? Heat of itself never flows from a cold object to a hot object. ... The second law expresses the maximum efficiency of a heat engine in terms of hot and cold temperatures. one of these answers i am not sure
5.How far must a 5 N force pull a 50 g toy car if 30 J of energy are transferred?
Answers
Answer:
5 meters
Explanation:
Step one:
given data
mass of the toy car= 50g
Work done= 30J
Force applied F= 5N
Required
The distance moved
Step two:
The expression for the work done is given as
WD= force * distance
substitute
30= 5*d
divide both sides by 5
d=30/5
d= 5m
The distance moved is 5 meters
I NEED ANSWERS ASAP
Speed equals distance divided by ___________________.
time
displacement
velocity
acceleration
Answers
Answer:
Time
Explanation:
s=d/t
a student pushes a book with a force of 5 N to the east.which statement
describes the reaction force?
Answers
Answer:
5N westward, acting on the student
Explanation:
Answer: 5N westward, acting on the student
Explanation:
Find as many sets of three perfect squares where the largest of the three perfect squares is the sum of the two smaller perfect squares. for example, one set is 9, 16, 25 because 9 + 16 = 25.
Answers
Here are a few sets of three perfect squares where the largest is the sum of the two smaller ones:
1. 3, 4, 5 (since 3^2 + 4^2 = 5^2)
2. 5, 12, 13 (since 5^2 + 12^2 = 13^2)
3. 7, 24, 25 (since 7^2 + 24^2 = 25^2)
4. 8, 15, 17 (since 8^2 + 15^2 = 17^2)
5. 9, 40, 41 (since 9^2 + 40^2 = 41^2)
6. 11, 60, 61 (since 11^2 + 60^2 = 61^2)
7. 12, 35, 37 (since 12^2 + 35^2 = 37^2)
8. 13, 84, 85 (since 13^2 + 84^2 = 85^2)
These are just a few examples, and there are infinitely many more sets of three perfect squares satisfying the given condition.
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the horse's center of gravity is not exactly in its middle; it is closer to its front hooves. what does this tell us about the force exerted by the front and back hooves at equilibrium?
Answers
At equilibrium, the forces exerted by the front and back hooves must be equal, but the force exerted by the front hooves will be slightly greater than that of the back hooves.
What is equilibrium?
Chemical equilibrium refers to the situation inside a chemical reaction where both the reactants are present at levels that have no further habit of changing over time, preventing any discernible change in the system's properties. Whenever the forward reaction and the reverse reaction move forward at the same speed, this condition results. The forward as well as backward reactions typically have equal, if not zero, reaction rates. The concentrations of a products and reactants do not change on a net basis as a result. Dynamic equilibrium is the name given to such a situation.
This is due to the fact that the horse's center of gravity is closer to the front hooves, and thus the front hooves must exert a greater force in order to keep the horse balanced.
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What event made it possible for photons to begin to travel freely through the universe when the universe was about 380,000 years old?
A. The universe had expanded and cooled enough for electrons to combine with nuclei to form neutral atoms.
B. Atoms started to combine to make the first molecules.
C. Magnetic fields had weakened to the point that they no longer interfered with light.
D. Atomic nuclei were finally able to escape the plasma of the early universe.
E. Fusion of hydrogen to make helium ceased.
Answers
Explained:
Photons are electromagnetic waves (light) and can move according to the level of magnetism. Also are magnetic fields of the earth are known to protect us from uv rays which are harmful to the body
An outfielder throws a baseball to home plate with a velocity of 27 m/s at 35o. It is caught by the first baseman. How long was it in the air
Answers
Answer:
Explanation:
Initial velocity of the ball = 27 m /s .
Its vertical component = 27 sin 35 = 15.48 m /s
Considering vertical displacement to the top point ,
initial velocity u = 15.48 m /s
acceleration due to gravity g = 9.8 ,
velocity at the top v = 0
v = u - gt
0 = 15.48 - 9.8 t
t = 15.48 / 9.8 = 1.579 s
So time of ascent = 1.579 s
Similarly , time of descent = 1.579
Total time of flight = 2 x 1.579
= 3.16 s
A ball is thrown straight up with a velocity of 16 m/s; what will be its velocity 2.0s after being released?
Answers
Answer:
The ball will be travelling downward with a speed of 9.8 m/s.
Explanation:
The ball will be travelling downward with a speed of 9.8 m/s.
Explanation:
The acceleration of the ball will be a constant
9.8 m s 2
(downward), regardless of whether the ball is travelling upward or downward.
The equation that makes this calculation simplest is
v f = v i − g ( Δ t )
where the negative sign has been used to account for the opposite directions of v i and g . After 3 seconds, v f = 19.6 − ( 9.8 ) ( 3 ) = 19.6 − 29.4 = − 9.8 m s
The negative result tells us that the ball is on its way downward by this time (consistent with our choice of a negative value for the downward acceleration of gravity).
How can diseases impact the circulatory system? How do the levels of organization in the circulatory system work together to prevent disruption from occurring?
Answers
There are numerous connections among illnesses of the circulatory system. For instance, excessive blood pressure harms the blood vessels and may cause additional circulation issues.
Prevention of circulatory diseases
High cholesterol causes the blood arteries to narrow, which raises a person's risk of developing a blood clot.
Obesity and being overweight raise the risk of getting cardiovascular disorders. A healthy diet and exercise, though, can lower the risk.
By lowering the risk of high blood pressure, high cholesterol, and being overweight — all of which are risk factors for circulatory disorders — regular exercise helps to keep the heart healthy.
It is more common for someone to get a circulatory disease if they have family members who have the condition. A healthy lifestyle, however, can lower this risk.
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A force is exerted on a box an an equal and opposite force is exerted by the box. what explains this?
Answers
Answer: What is the force that opposes motion between two surfaces in contact with each ... How is the relationship among mass, force and acceleration explained? ... When a force is exerted on a box, an equal and opposite force is exerted by the box.
Mass is 56.8 g and the volume is 10 mL what is the density
Answers
Explanation; Divide the mass of the unknown substance and the volume of the unknown substance and you will have your answer.
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which feature would you expect to find at the mouth of a submarine canyon?
Answers
At the mouth of a submarine canyon, you would expect to find a fan-shaped accumulation of sediment called a submarine fan. Submarine canyons are deep,
steep-sided valleys that cut into the seafloor and can extend for many kilometers. They are often formed by underwater erosion from currents, landslides, and other geological processes. At the mouth of the submarine canyon, where it opens up onto the continental shelf, sediment carried by the currents can accumulate and form a fan-shaped deposit. This sediment can come from a variety of sources, including the erosion of the canyon walls, rivers that empty into the ocean, and ocean currents that transport sediment from other areas.
Submarine fans can be quite large and can play an important role in the transport of sediment and nutrients in the deep ocean. They can also be important sites of oil and gas deposits, as well as deep-sea habitats for a variety of marine organisms.
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25. When making a 180-degree turn with a radius of 15 meters, a 900 kg car experiences a coefficient of friction of 0.60.
What is the maximum speed with which the car can make the turn?
c. 5.2 m/s
d. 90 m/s
a. 3 m/s
b. 9.49 m/s
Answers
The maximum speed with which the car can make the turn through the 15 meters radius curve is 9.49 m/s (Option B)
How do I determine the maximum speed?We'll begin by obtaining the acceleration of the car. This can be obtained as follow:
Mass of car (m) = 900 KgAcceleration due to gravity (g) = 10 m/s²Normal reaction (N) = mg = 900 × 10 = 9000 NCoefficient of friction (μ) = 0.60Force (F) = μN = 0.6 × 9000 = 5400 NAcceleration (a) =?F = ma
Divide both sides by m
a = F / m
a = 5400 / 900
a = 6 m/s²
Now, we shall obtain the maximum speed. Details below:
Radius (r) = 15 mAcceleration = 6 m/s²Speed of car (v) =?v = √ar
v = √(6 × 15)
v = 9.49 m/s
Thus, the maximum speed is 9.49 m/s (Option B)
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a hiker makes four straight-line walks a 21 km at 143 ◦ b 24 km at 250 ◦ c 16 km at 161 ◦ d 16 km at 84 ◦
Answers
The total distance covered by the hiker is 77 km.
How can we calculate the total distance covered by the hiker?To calculate the total distance covered by the hiker, we need to add up the distances of each individual walk.
For the first walk, the hiker covers a distance of 21 km at an angle of 143 degrees. The distance traveled can be calculated using the formula: distance = magnitude × cos(angle). Thus, the distance for the first walk is 21 km × cos(143°).
For the second walk, the hiker covers a distance of 24 km at an angle of 250 degrees. Using the same formula, the distance for the second walk is 24 km × cos(250°).
For the third walk, the hiker covers a distance of 16 km at an angle of 161 degrees. Again, applying the formula, the distance for the third walk is 16 km × cos(161°).
Finally, for the fourth walk, the hiker covers a distance of 16 km at an angle of 84 degrees. The distance can be calculated as 16 km × cos(84°).
To find the total distance, we add up the distances from each walk: (21 km × cos(143°)) + (24 km × cos(250°)) + (16 km × cos(161°)) + (16 km × cos(84°)) = 77 km.
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Humpback whales are known to produce a collection of elaborate
and repeating sounds with frequencies ranging from 20 Hz to 10 kHz. The sound
waves travel through water at speeds of approximately 1400 m/s. Determine the
wavelengths of the waves at the lower and the upper end of this frequency
range.
Answers
Answer:
70 m.
Explanation:
Given,
Frequency, f = 20 HZ
speed of sound, v = 1400 m/s
wavelength of the waves = ?
we know,
v = f λ
Hence, the wavelength of the wave is equal to 70 m.
37. Which of the following is NOT true about an object over a givenamount of time?bolts displacement can be larger than itsdistanceb Its distance can be equal to its displacementIt can have a non-zero distance and haveCzero displacementdIts distance can be larger than itsdisplacement
Answers
We have the next definitions
Distance It is all the way traveled by a mobile or moving body.
Displacement: It is a straight line distance from an initial position to a final position. This distance has direction therefore it is a vector
Therefore the statement that is not true is
Its displacement can be larger than its distance.
ANSWER
¿Juan quiere calentar una barra de aluminio de 100 g, para realizar un trabajo. La temperatura ambiente es de 27°C pero necesita elevar la temperatura de la barra hasta los 60°C. Si el aluminio tiene un calor especifico de 0,215 cal/g°C que cantidad de calor necesita aplicar ?
Answers
Answer:
709.5 cal
Explanation:
masa m de la barra de aluminio = 100 g
temperatura ambiente = 27 ° C
Asumiremos que la barra de aluminio está en equilibrio térmico con el ambiente.
Esto significa que la temperatura inicial de la barra es de 27 ° C
temperatura final a la que la barra debe calentarse = 60 ° C
el aumento de temperatura ΔT será
ΔT = 60 ° C - 27 ° C = 33 ° C
capacidad calorífica específica c del aluminio = 0.215 cal/g°C
Calor C requerido = mcΔT
C = 100 x 0.215 x 33 = 709.5 cal
Please help me this is worth allot
Answers
Relate a real life phenomena with each branch of physics..
Answers
Answer:
Absolutely no real-life phenomena/ uses are possible that are related to any branch of physics, except:
1 The device you are reading this answer on. (quantum mechanics, electronics )
2 The air conditioner in your room. ( electromagnetism, electronics )
3 The satellites and space stations in space which will help in the deciphering of the universe will help us look for a suitable planet when we render the earth useless. ( general and special relativity, classical mechanics )
4 Ohh. I forgot, do you wear clothes, well they are made in factories where factories run on the principles of thermodynamics, which is physics.
5 Ever gone somewhere? Well, the transportation uses classical mechanics, thermodynamics, electromagnetism, relativity ( if you know Global Positioning System )
6 GPS itself! It’s used in online maps, navigating, and this sort of stuff. It works on general relativity.
Honestly, this list is endless.
The speed of your automobile has a huge effect on fuel consumption. Traveling at 65 miles per hour (mph) instead of 55mph can consume almost 20% more fuel. As a general rule, for every mile per hour over 55 , you lose 2% in fuel economy. For example, if your automobile gets 30 miles per gallon at 55mph, the fuel consumption is 21 miles per gallon at 70mph. If you take a 400-mile trip and your average speed is 83mph rather than the posted speed limit of 73mph, what is the extra cost of fuel if gasoline costs $3.26 per gallon? Your car gets 30 miles per gallon (mpg) at 63mph.
Answers
The extra cost of fuel for driving 83 mph instead of 73 mph is $3.7671.
The speed of your automobile has a huge effect on fuel consumption. Traveling at 65 miles per hour (mph) instead of 55mph can consume almost 20% more fuel. As a general rule, for every mile per hour over 55 , you lose 2% in fuel economy.
If you take a 400-mile trip and your average speed is 83mph rather than the posted speed limit of 73mph, then the extra cost of the fuel is calculated as:
* **Fuel consumption at 83 mph:** 30 mpg * (1 - 2% * (83 - 55)) = 27.6 mpg
* **Fuel consumption at 73 mph:** 30 mpg * (1 - 2% * (73 - 55)) = 29 mpg
* **Extra fuel used:** 400 miles / 27.6 mpg - 400 miles / 29 mpg = 2.4 gallons
* **Extra cost of fuel:** $3.26/gallon * 2.4 gallons = $3.7671
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If the displacement of a particle is given by the formula S = 3t^3 - 20t^2 + 40t. Find (i) the displacement after 3 seconds (ii) the formula for the velocity at any time t (iii) the value of t when the particle is not moving (iv) the initial velocity of the particle (v) the formula for the acceleration at any time t (vi) the initial acceleration of the particle.
Answers
Answer:
At t = 0 S = 0
S = 3 * 3^3 - 20 * 3^2 + 40 * 3 after 3 sec
S = 3 * 27 - 20 * 9 + 120 = 21 after 3 sec
v = ds/dt = 9 * t^2 - 40 * t + 40 = 9 * 9 - 40 * 3 + 40 = 1
ds/dt = 9 t^2 - 40 t + 40 v at any time
If zero = 9 t^2 - 40 t + 40 then you need to solve the quadratic for t
a = ds^2 / dt^2 = dv /dt = 18 t - 40 for the acceleration at any time
At t = zero (the initial acceleration) a = -40
what is the weight of a 45kg box
____ N
Answers
The weight of a \(45 kg\) box is \(441.45 N\).
Weight refers to the measure of the force exerted on an object due to the gravitational pull of the Earth.
Given the mass of the box is \(m=45 kg\).
The weight of an object (\(W\)) can be found by multiplying the mass of the object (\(m\)) by the acceleration due to gravity (\(g\)).
So, \(W=mg\).
It is known that acceleration due to gravity, \(g=9.81 m/s^2\).
Hence, the weight of the box, \(W=(45kg)\times (9.81 m/s^2)\).
\(\Rightarrow W=441.45 (kg\cdot m/s^2)\\\Rightarrow W=441.45 N\)
Therefore, the weight of the box is \(441.45 N\).
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