The basketball player must throw the basketball at an initial speed of 8.19 m/s so that it goes through the hoop without striking the backboard.
Initial speed refers to the magnitude of the velocity of an object before it starts accelerating.
We can use the following kinematic equations to solve for the initial speed of the basketball:
\(V_y = V_{oy} + a_y\times t\)
\(V_y = V_{oy} \times t + 1/2(a_y \times t^2)\)
where \(V_y\) is the vertical component of the velocity, \(V_{oy}\) is the initial vertical component of the velocity, ay is the acceleration due to gravity (-9.81 m/s²), y is the vertical displacement, t is the time of flight,
Since the basketball player wants to throw the ball through the hoop without striking the backboard, the ball needs to travel a horizontal distance of 10.0 m and a vertical distance of (3.05 - 2) m. The initial angle of 40.0 degrees can be broken down into its horizontal and vertical components:
\(V_{oy} = V_o sin(40.0)\)
\(V_{ox} = V_o cos(40.0)\)
where \(V_o\) is the initial velocity.
Using the second kinematic equation, we can solve for the time of flight:
\(10 = V_{ox}t + 1/2a_xt^2\)
\(10 = V_o cos(40.0) t\) (since ax = 0)
\(t = 10/(V_o cos(40.0))\)
Now using the time of flight in the vertical direction:
\(1.05 = V_o sin(40.0) \times 10/V_o cos(40.0) - 1/2\times 9.81 * (10/(V_o cos(40.0)))^2\)
\(1.05 = 8.39 - 835/V_o^2\)
\(V_o = 10.1 \ m/s\)
Therefore, the basketball player must throw the basketball at an initial speed of approximately 10.1 m/s (to three significant figures) in order to make the shot without striking the backboard.
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Explain the quantization of energy.
Answer:
The quantization of energy refers to the fact that at subatomic levels, energy is best thought of as occurring in discreet "packets" called photons. Like paper money, photons come in different denominations. ... Each photon contains a unique amount of discreet energy
PLEASE HELP WILL GIVE BRAINLIEST (I NEED TWO PICKED) PLZzZZZZ AND THxS
Answer:
A and B
Explanation:
They contain Chlorophyll
They are relatively tall
What is it called when two or more bodies orbit at multiples of the same orbital period?
Orbital resonance,called when two or more bodies orbit at multiples of the same orbital period.
In celestial mechanics, an orbital resonance is when two orbiting bodies exert a regular, periodic gravitational impact on one another. This frequently occurs as a result of the two bodies' orbital periods being related by a ratio of two tiny integers.The gravitational influence of the bodies is significantly strengthened by orbital resonances. The majority of the time, this causes an unstable interaction in which the bodies trade momentum and modify their orbits until the resonance vanishes. A resonant system may occasionally be robust and self-correcting, allowing the bodies to stay in resonance. Examples include the 2:3 resonance between Pluto and Neptune and the 1:2:4 resonance of the Jupiter's moons Ganymede, Europa, and Io. Gaps in Saturn's rings are caused by unstable resonances with its inner moons.
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HURRY PLEASE HELP ME
Which of the following is an incorrect statement?
A pencil on a table contains potential energy.
Potential energy does work.
All objects contain potential energy.
Potential energy is stored energy.
Answer:
I think it is Potential energy is stored energy
Explanation:
Answer:
potential energy is stored energy, to my knowledge
A 6.00 kg bowling ball with speed 9.00 m/s strikes a 0.750 kg pin. This slows the ball to
7.00 m/s. Find the force exerted on the pin due to the impact if the collision last for 0.030 s.
(a) Find the change in momentum of the bowling ball
(b) Find the impulse imparted on the pin
(c) Find the resulting speed of the pin after the collision
(d) Find the force exerted on the pin during the collision
For a 6.00 kg bowling ball:
(a) change in momentum of the bowling ball is −12.0 kg m/s
(b) impulse imparted on the pin is −12.0 kg m/s.
(c) resulting speed of the pin after the collision is 8.00 m/s
(d) force exerted on the pin during the collision −400 N
How to solve for collision?(a) The change in momentum of the bowling ball is given by
Δp = m(vf − vi) = (6.00 kg)(7.00 m/s−9.00 m/s) =−12.0 kg m/s
(b) The impulse imparted on the pin is equal to the change in momentum of the bowling ball, so the impulse is −12.0 kg m/s.
(c) The resulting speed of the pin after the collision can be found using conservation of momentum. The total momentum after the collision is the sum of the momentum of the bowling ball and the momentum of the pin. So,
mbvi = mbvf+ mpvp
where vp = speed of the pin after the collision.
Solving for vp,
vp = mb(vi− vf)/mp = (6.00 kg)(9.00 m/s−7.00 m/s) / 0.750 kg = 8.00 m/s
(d) The force exerted on the pin during the collision is given by
F = Δp/Δt = − 12.0 kg m/s/0.030 s = −400 N
The negative sign indicates that the force is in the opposite direction of the initial velocity of the bowling ball.
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A skateboarder is skating along a level concrete path. Every so often, to keep himself going, he uses his foot to give himself a push. Discuss why the skateboarder needs to regularly push with a foot when skateboarding along a level surface.
In your answer, you should:
- describe the motion of the skateboarder during a push and between pushes
- identify the forces in action and explain whether they are balanced or unbalanced
- link the net force to the motion of the skateboarder.
The skateboarder needs to regularly push with their foot when skateboarding along a level surface because of the presence of frictional forces that oppose motion. When the skateboarder gives themselves a push, they increase their forward velocity.
The skateboarder needs to regularly push with their foot when skateboarding along a level surface because of the presence of frictional forces that oppose motion. When the skateboarder gives themselves a push, they increase their forward velocity. However, over time, the velocity decreases due to the force of friction between the skateboard's wheels and the ground, which acts in the opposite direction to the skateboard's motion. During a push, the skateboarder exerts a force on the skateboard that propels it forward. Between pushes, the skateboard moves at a constant velocity due to the balanced forces acting upon it. However, as frictional forces act on the skateboard, it slows down until the next push is required. The net force acting on the skateboarder is unbalanced, as the force of friction acting against the skateboard's motion is greater than the force of the skateboarder's push. The resulting net force causes the skateboarder to slow down over time. Thus, by pushing themselves, the skateboarder overcomes the force of friction and maintains their forward motion.
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An object weighs 2600 N on Jupiter (g = 26). What is its weight on the Earth (g = 10)?
HELP ASAP!
Answer:
Weight = 1000N
Hope this helps... Have a good day!!
Answer: 1000N
Explanation:
Weight of object = 2600N
Jupiter g = 26
Now converting to mass
2600/26
= 100 kg
Earth g = 10
Converting to Newtons
100×10
1000N
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A truck with 30 -in. -diameter wheels is traveling at 55mi/h. Find the angular speed of the wheels in rad/min? rad/min How many revolutions per minute do the wheels make? rpm.
The angular speed of the wheels is approximately 403.47 rad/min, and the wheels make approximately 387.68 revolutions per minute (rpm).
To find the angular speed of the wheels in rad/min, we need to convert the linear speed of the truck to angular speed. The linear speed of the truck is given as 55 mi/h. We know that the distance traveled on the circumference of a circle is equal to the product of the radius and the angle in radians subtended by the arc. In this case, the distance traveled on the circumference of the wheels is equal to the linear speed multiplied by the time taken.
We can calculate the radius of the wheels by dividing the diameter by 2, which gives us 15 inches. Converting the linear speed from miles per hour to inches per minute, we get (55 mi/h) * (5280 ft/mi) * (12 in/ft) / (60 min/h) ≈ 58080 in/min.
The angular speed is then obtained by dividing the linear speed by the radius of the wheels. So, the angular speed of the wheels in rad/min is approximately 58080 in/min / 15 in ≈ 3872 rad/min.
To find the number of revolutions per minute (rpm), we divide the angular speed by 2π, as one revolution is equal to 2π radians. Therefore, the wheels make approximately 3872 rad/min / (2π) ≈ 616.29 rpm.
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If the angle of reflection of a propagated ray is 35°. Calculate the a. Angle of incidence b. Angle of deviation c. Angle of glance
\( \LARGE{ \underline{ \blue{ \tt{Required \: answers}}}}\)
First of all,
Angle of incidence = Angle between normal and incident ray.Angle of reflection = Angle between normal and reflected rayGlance angle of incidence = Angle between incident ray and the surface.Glance angle of reflection = Angle between reflected ray and the surface.We have,
➝ Angle of reflection = 35°
(a) According to law of reflection,
Angle of incidence = Angle of reflection
➝ Angle of incidence = 35°
(b) By using formula,
Angle of Deviation = 180° - 2(Angle of incidence)
From (a),
➝ Angle of Deviation = 180° - 2(35°)
➝ Angle of Deviation = 180° - 70°
➝ Angle of Deviation = 110°
(c) We know,
Angle of Incidence + Glance angle of incidence = 90°
Angle of reflection + Glance angle of reflection = 90°
So,
As angle of incidence = angle of reflection
Then, Angle of glance is also equal.
➝ Angle of glance = 90° - 35° = 55°
━━━━━━━━━━━━━━━━━━━━
The difference between meteoroids and meteor
Answer:
Meteoroids are objects in space that range in size from dust grains to small asteroids. Think of them as “space rocks." When meteoroids enter Earth's atmosphere (or that of another planet, like Mars) at high speed and burn up, the fireballs or “shooting stars” are called meteors.
Explanation:
thx to the internet
the actual frequency of the
A stationary observer is approached by a rapidly moving ambulance with the sirenon. As the ambulance approaches the observer, the apparent frequency of the sound is ______ the actual frequency of the siren
A. The same as
B. Greater than
C. Less than
D. Not related to
Answer:
ITS B need more characters so yessir
What signs of a circuit board failure? sparks escapingelectricity flowingfire and sparks flyingcurrent escaping
Explanation:
The circuit board fails when the positive and negative of the circuit are connected together without any load between them.
Due to the high potential difference, fire and sparks are produced.
Final Answer: sparks and fire flying
Select all the correct answers. Which statements about potential energy are true?
Answer: The statement gaining potential energy is always associated with a force field, is true about potential energy.
Explanation:
The energy acquired by an object due to its position is called potential energy.
Basically, a force field exerts a force that gives rise to potential energy of an object. For example, gravity, spring force etc.
This means that gaining potential energy is always associated with a force field.
A change in position does not always means that an object gains potential energy. For example, a spring will have more potential energy when it is compressed or stretched.
Hence, change in position of an object not necessarily means always gain in potential energy.
There are two types of potential energy that is, gravitational potential energy and elastic potential energy.
Thus, we can conclude that the statement gaining potential energy is always associated with a force field, is true about potential energy.
Answer:
Explanation:
The first one and the last one are the correct answer.
Erector Spinae:
Origin: __ surface of the __, __ __, __ process of the __ __ and last two __ __.
The erector spinae muscles are a group of muscles that extend along the back of the spine. The origin of the erector spinae muscle group is complex, and it varies depending on the specific muscle within the group.
What is Erector Spinae?
The erector spinae muscles are responsible for extending the spine, or bending the spine backwards, as well as for helping to maintain proper posture and balance. They also play a role in lateral flexion and rotation of the spine. These muscles are important for many everyday activities, such as standing, walking, lifting, and bendin
The erector spinae muscles are important for maintaining proper posture, supporting the spine, and allowing movement of the back. They are also involved in activities that require bending, twisting, and lifting.
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in solar heating applications, heat is stored in some medium until it is needed (i.e., to heat a home at night). should this medium have a high or low specific heat? explain.
In solar heating applications, it is desirable for the medium used to store heat to have a high specific heat. This is because the specific heat of a substance is the amount of heat energy required to raise the temperature of a unit mass of the substance by one degree Celsius. Therefore, a substance with a high specific heat can absorb a large amount of heat energy without a significant increase in temperature. This means that a high specific heat medium can store a large amount of heat energy while remaining at a relatively constant temperature, which is ideal for efficient heat storage. In contrast, a medium with a low specific heat would require a large increase in temperature to store the same amount of heat energy, which could result in thermal losses and reduced efficiency.
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jordan has a mass of 65kg and carlos has a mass of 78.0kg. jordan is running at 5.75m/s when he is tackled by carlos who is running in the opposite direction. after the collision of both players are at rest. calculate their velocity before the collision.
Given
mj = 65 kg
mc = 78 kg
voj = 5.75 m/s
after collision
vfj = vfc = 0 m/s
Procedure
The law of momentum conservation can be stated as follows. For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
\(\begin{gathered} p_o=p_f \\ m_jv_{0j}-m_cv_{0c}=0 \\ m_jv_{0j}=m_cv_{0c} \\ v_{0c}=\frac{m_jv_{0j}}{m_c} \\ v_{0c}=\frac{65kg*5.75m/s}{78kg} \\ v_{Oc}=4.8m/s \end{gathered}\)
The velocity before the collision would be 4.8m/s
Find the gravitational force between Earth (5.97 x 1024 kg) and the Sun (1.99 x 1030 kg) knowing they are 1.48 x 1011 m apart.
Using the gravitational force of F= G(m1*m2/r^2)
m1= 5.97 x 10^24 kg (Earth)
m2= 1.99 x 10^30 kg (Sun)
r= 1.48 x 10^11 m
G is a known value, it is 6.672 x 10^-11
All units are proper. Therefore plug in the values and you get 3.16 x 10^22 N.
Let me know if I calculated this wrong and it is something else so I can delete this. Thank you. I don't want to make other students put down the wrong answer.
Answer:
\(\boxed {\boxed {\sf F_g \approx 3.62 *10^{22} \ N}}\)
Explanation:
We are asked to find the gravitational force between Earth and the Sun. Use the following formula:
\(F_g= \frac{Gm_1m_2}{r^2}\)
G is the universal gravitational constant. One mass (m₁) is the Earth and the other (m₂) is the Sun. r is the distance between the planets.
G= 6.67 * 10⁻¹¹ N*m²/kg²m₁ = 5.97 * 10²⁴ kg m₂= 1.99 * 10³⁰ kg r= 1.48 *10¹¹ mSubstitute the values into the formula.
\(F_g = \frac{ (6.67*10^{-11} N*m^2/kg^2)(5.97*10^{24} \ kg)(1.99*10^{30} \ kg) }{ (1.48 *10^{11} \ m)^2}}\)
Multiply the numerator. The units of kilograms cancel.
\(F_g = \frac {7.9241601 *10^{44} \ N*m^2}{ (1.48 *10^{11} \ m)^2 }\)
Solve the exponent in the denominator.
\(F_g= \frac {7.9241601 *10^{44} \ N*m^2}{ 2.1904*10^{22} \ m^2}\)
Divide. The units of meters squared cancel.
\(F_g=3.61767718 *10^{22} \ N\)
The original values all have 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 7 in the thousandth place tells us to round the 1 up to a 2.
\(F_g \approx 3.62 *10^{22} \ N\)
The gravitational force between Earth and the Sun is approximately 3.62 *10²² Newtons.
Although there are rumors of new aircraft that can fly at much higher speeds, the
current official and unclassified record holder is still the Lockheed SR-71 Blackbird, a
high-altitode spy plane. Fully loaded, the Blackbird has a mass of 7.7x104 kg, and at
top speed it has a kinetic energy of 3.7x1010 J. What is the top speed of the SR-71?
Answer: speed X velocity X inertia
Explanation:
you throw a basketball straight up into the air with a speed of 24.5m/s. how long does it take to reach its highest point
Answer:
2.5 seconds.
Explanation:
Time equals speed divided by acceleration. gravitational acceleration is equal to 9.8 \(\frac{m}{s^{2} }\). You know that the speed is equal to 24.5 m/s, so plug those values into the equation.
24.5 / 9.8 = 2.5 seconds.
Hope this helps!
Answer: 2.5 s
Time=speed/acceleration
Gravitational Acceleration=9.8 m/s^2
Speed=24.5 m/s
Time=24.5/9.8=2.5 s
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why is gravitational potential energy greater then kinetic energy?
Answer:
The gravitational acceleration energy of an item increases as it rises in altitude.
Explanation: Hope this helps :D
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Problem 6: The electric field in an electromagnetic wave is in the y-direction and described by E, = Encos(kor - wt). where Eo = 225 N/C. Randomized Variables Eo = 225 N/C 25% Part (a) If the electromagnetic wave is traveling in the x-direction in vacuum, what is the direction of the magnetic field? z direction ✓ Correct! 25% Part (b) Express the amplitude of the magnetic field, Bo, in terms of E, and the speed of light c. Bo=E/C Correct!
the amplitude of the magnetic field is equal to the electric field divided by the speed of light.
For Part (a), since the electric field is in the y-direction and the wave is traveling in the x-direction, the magnetic field must be in the z-direction in order to satisfy Maxwell's equations for electromagnetic waves.
For Part (b), we can use the relationship between the electric and magnetic fields in an electromagnetic wave: B = E/c, where B is the amplitude of the magnetic field and c is the speed of light. So, substituting the given values, we get: B = E/c = (225 N/C)/(3x10^8 m/s) = 7.5x10^-7 T. Therefore, the amplitude of the magnetic field is equal to the electric field divided by the speed of light.
In an electromagnetic wave, the electric field and magnetic field oscillate perpendicular to each other and to the direction of wave propagation. In this case, the electric field (E) is in the y-direction and the wave is traveling in the x-direction. Therefore, the magnetic field (B) is in the z-direction.
The amplitude of the magnetic field (Bo) can be expressed in terms of the electric field (Eo) and the speed of light (c) using the following formula:
Bo = Eo / c
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If a train is going 24 m/s and comes to a stop, what is the distance it covers if the acceleration
is -0.29 m/s??
Explanation:
u=24
v=0
a=-0.29
s=
v^2=u^2+2as
s=(v^2-u^2)/2a
s=(0-576)/0.58
s=-575.42
I need help Will give five stars please show work please
Answer:
These has anwers and also the solution. You can recheck if you want.
5. Principal Rodriguez has asked all students exit the building by 2:45 pm! If you want to exit
efficiently from upstairs you will need to travel 30 m down the stairs, 15 m to the right, and then 20
m to the left. Calculate your total distance.
With the Pythagoras' Theorem we can find that the distance traveled is:
39 m
The distance is the length of the path between two points and it is a scalar magnitude so if the path changes direction the Pythagoras' theorem should be used
d = \(\sqrt{(x-x_o)^2 + (y-y_o)^2 + (z-z_o)^2 }\)
Where d is the distance, (x,y,z) is the interes point, (x₀,y₀,z₀) is de reference point.
In this case, let's set a reference system in the lower part of the school, take the z-axis as vertical and set the point of arrival at as the reference (0, 0, 0).
The distance that the students descend is d₁ = 30 k ^ m, when they arrive from the bottom of the school they travel d₂ = 15 j ^ m and d₃ = 20 i ^ m
let's calculate
d =\(\sqrt{(20-0)^2 + (15-0)^2 + ( 30-0)^2 }\)
d = 39.05 m
Notice that the distance by being a scalar does not have unit vectors
In conclusion using the Pythagoras' Theorem we can find that the distance traveled is 39 m
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the frequency of the fundamental of the guitar string is 320 hz . at what speed v do waves move along that string? express your answer in meters per second.
The Speed of waves is 640L.
Given
The frequency of string is 320 Hz.
To find at what speed v do waves move along that string , we can use following equation-
\(f=\frac{V}{2L}\)
Frequency means reciprocal of time period , i.e. a parameter that decides quality factor of sound / harmonics.
f , V , L represents frequency , speed and length of string.
\(V=2Lf\)
V= 2L(320)
V= 640L
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Two students noted that the acceleration of a car was - 40 km/s^2. The first student said, “That can’t be right. You can’t have a negative acceleration.” The second student said, “That can’t be right. You can’t have s^2.” What would you say to each student to help them better understand how acceleration is described? pls answer
Which of the following is NOT an example of acceleration?
A car is traveling 33 km/h and slows down to 25 km/h.
B.
A car is driving straight at 50 mi/h.
A car is traveling 33 km/h and speeds up to 45 km/h.
A car is traveling 33 km/h north and turns east.
Answer:
B
explanation:
The car is not making a change in speed.
Use all units and work out answers
1.A wavelength of light is 1,600 m. What is the frequency?
2. Light travels through a material at a speed of 9.2 x 108 m/s. What is the index of refraction for the material?
3. What is the speed of light through an unknown glass with an index of refraction of 2.7?
4. A flashlight beam strikes the surface of a pane of glass (n = 1.64) at a 23° angle to the normal. What is the angle of refraction? (Assume air to have an index of refraction of 1.0003)
5. A diver shines a flashlight upward from beneath the water (n=1.33) at an angle of 48.3° to the vertical. At what angle does the light refract through the air above the surface of the water?
6. What is the index of refraction of a refractive medium if the angle of incidence in air (n=1.0003) is 45 degrees and the angle of refraction is 22 degrees?
7. What is the critical angle for the boundary between an unknown medium (n=1.67) and water (n=1.33)?
8. The critical angle for a certain liquid-air surface is 13°. What is the index of refraction of this liquid?
Light is an electromagnetic wave and light possess dual nature. The speed of light is 3×10⁸m/s and the speed of light may vary when it travels from the rarer to denser medium. The frequency is inversely proportional to the wavelength.
The wavelength of the light is 1,600 m. The frequency is inversely proportional to the wavelength.
Frequency(ν) = speed of light (c) / wavelength (λ)
= 3×10⁸ / 1600
= 187.5 kHz.
The frequency of light is 187.5 kHz.
Light travels through the material is 9.2×10⁸ m/s. The refractive index is the ratio of the velocity of light in air (c) and the velocity of light in the material (v).
n = c /v
= 3×10⁸ / 9.2×10⁸
= 3 / 9.2
= 0.32
Thus, the refractive index is 0.32.
The speed of light through the medium is, n = c /v
n(refractive index) = 2.7
c (speed of light) = 3×10⁸
v =?
v = c /n
= 3×10⁸ / 2.7
= 1.11×10⁸ m/s
Thus, the velocity of the light through the glass is 1.11×10⁸ m/s.
The angle of incidence is equal to the angle of refraction. From, snells law: n₁(sinθ₁) = n₂ (sinθ₂)
n₁ (refractive index of air) = 1.0003
n₂(refractive index of glass) = 1.64
θ₁ = 23°
n₁(sinθ₁) = n₂ (sinθ₂)
1(sin(23)) = 1.64 (sin(θ₂))
θ₂ = sin⁻¹( (sin(23) / 1.64)
= 13.7°
The angle of refraction is 13.7°.
The angle of refraction from Snell's law:
n₁(sinθ₁) = n₂ (sinθ₂)
n₁(refractive index of water) = 1.33
n₂ (refractive index of air) = 1
θ₁ = 48.3°
θ₂=?
n₁(sinθ₁) = n₂ (sinθ₂)
1.33(sin(48.3)) = 1(sinθ₂)
0.9930 = (sinθ₂)
θ₂ = sin⁻¹(0.9930)
= 83.21
The angle of refraction = 83.2°
The refractive index of the medium is:
n₁(sinθ₁) = n₂ (sinθ₂)
n₁ (refractive index of air) = 1
n₂ (refractive index of medium) =?
θ₁(angle of incidence) = 45°
θ₂ (angle of refraction)= 22°
n₁(sinθ₁) = n₂ (sinθ₂)
1(sin(45)) = n₂ (sin (22))
0.707 = n₂ (0.374)
n₂ = 0.707 / 0.374
= 1.89
The refractive index of the medium is 1.89
The critical angle is obtained by, sin θc = n₂ / n₁, n₁ > n₂.
θc = sin⁻¹ ( 1.33/1.67)
= 52.7
The critical angle, θc = 52.7°
The critical angle θc = 13°, the refractive index of liquid =?
the refractive index of air= 1
sin θc = n₂ / n₁
sin(13) = 1 / n₁
n₁ = 1 / 0.2249
= 4.46
The refractive index of the liquid is 4.454
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I am traveling at 100 m/s, I hit the brakes and my speed goes down to 50 m/s. It took 30 seconds to slow down. What was my acceleration?
A.5 m/s2
B.-5 m/s2
C.1.7 m/s2
D.-1.7 m/s2
Answer:
D. -1.7m/s2
Explanation:
the car starts at 100m/s so this is the initial velocity. It ends at 50m/s so this is the final velocity. it took 30 seconds so the time is 30.
\(v_{f}=v_{i}+at\)
\(a=\frac{\left(v_{f}-v_{i}\right)}{t}\)
\(a=\ \frac{\left(50-100\right)}{30}\)
\(a=-1.66666666667\)\(m/s^{2}\)
Therefore, the answer is D