a 3 kg object traveling at 4 m/s is pushed by a net force of 5 n. the speed increases to 6 m/s. find the distance the object travels.

Answer:

um d. but I am guessing this ans

The kinetic theory of matter states that matter is made up of tiny particles that are in constant motion. When a substance is heated, kinetic energy of its particles increases, causing them to move faster and further apart.

The substance may eventually reach its boiling point, at which vapor pressure of the liquid equals pressure of the surrounding atmosphere. Boiling occurs when the kinetic energy of the particles in a liquid overcomes the attractive forces between them, causing the liquid to change into a gas. At the boiling point, causing bubbles to form and rise to the surface. Saturated vapor pressure is pressure exerted by vapor of a substance in equilibrium with its liquid phase at a given temperature.

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Given,

The mass of an object is m = 3 kg

Initial temperature, T1 = 400 K

The specific heat of this object is c = 478 J/kg.K

The heat is Q = 13 kJ

Let T2 be the final temperature.

The formula is used to calculate the final temperature.

Thus, the value of the final temperature is

Therefore, the given answer (a) is correct.

When a passenger is walking toward the back of a train as the train is leaving the station, the person's description of their motion would differ from that of an observer standing on the station platform because the passenger would feel as if they are stationary while.

the station platform is moving backward. This is known as a long answer. The following paragraph it in more detail From the passenger's viewpoint, their motion seems normal, and it appears that they are stationary and the of station is moving in the opposite direction. Because the passenger is moving at the same speed as the train, they are would feel no different from when they are walking on a stationary platform. This is due to the fact that there is no are contact between the passenger and the station; hence, the passenger cannot feel any force acting on them.

The observer, on the other hand, would see the passenger's motion differently. They would see the passenger moving backwards as they move away from the platform. The observer would also see that the train is moving away from the platform and would soon disappear. This is because the observer is stationary and the train and the passenger are the they both in motion. When observed from a stationary position, any moving object appears to move in a straight line of When viewed from this perspective, the observer would see the passenger moving in a straight line away from the are station, although the passenger would feel as if they were stationary. The passenger and the observer are both seeing the same event from two different perspectives, and as a result, their description of the motion would differ.

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Answer and Explanation:

For computing the displacement at point B and D we need to determine the following calculations

\(P_Net = P_C + P_E + P_B\)

= 250 + 350 - 50

= 550 N

Now the deflection for bar AB is

\(\delta_{AB} = \frac{PL_{AB}}{AE} \\\\ = \frac{550 \times 500}{6,000 \times 200 \times 10^{3}}\)

Now for bar BC it is

\(\delta_{BC} = \frac{PL_{BC}}{AE} \\\\ = \frac{(550 + 50) \times 250}{5,000 \times 200 \times 10^{3}} \\\\ = 1.5 \times 10^{-04} mm\)

And for bar CD it is

\(\delta_{CD} = \frac{PL_{CD}}{AE} \\\\ = \frac{(550 -250 + 50) \times 250}{5,000 \times 200 \times 10^{3}} \\\\ = 0.875 \times 10^{-4} mm\)

Now the displacement is as follows

For B

2.292 × 10^{-4} mm

For D, it is

\(= 2.292 \times 10^{-4} + 1.5 \times 10^{-4} + 0.875 \times 10^{-4} mm \\\\ = 4.667 \times 10^{-4} mm\)

We simply applied the above formulas for determining the  displacements at points B, D and the same is to be considered  

It take more force for something to slide across a surface then it does to change direction on the same surface

What does the word force mean?

The definition of force in physics is: The push or draw on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a trajectory and a magnitude.

Friction is the energy that opposes motion, slowing or stopping it entirely. When two things rub against one another, friction is created. Sliding friction is the resistance that any two things produce when they slide against one another. This friction, also referred to as kinetic friction, is the force required to maintain one surface moving along another.

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Answer:

i guess u could pick "B" :)

Explanation:

We have that the velocity of the ball when it hits the glass.Using the appropriate significant figures is

V=4.43ft/s

From the question we are told that

Generally the equation for the Velocity  is mathematically given as

\(V^2=2as\\\\Therefore\\\\V=\sqrt{2*9.8*1}\\\\V=4.43ft/s\)

Therefore

the velocity of the ball when it hits the glass.Using the appropriate significant figures is

V=4.43ft/s

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To find the horizontal and vertical forces exerted by the ground on the base of the ladder, we can use the concepts of equilibrium.

1. Horizontal forces:
- The horizontal component of the weight of the ladder, which acts towards the wall. This force can be calculated as: F_hor = m₁ * g * sin(θ), where m₁ is the mass of the ladder, g is the acceleration due to gravity, and θ is the angle the ladder makes with the horizontal.

- The horizontal component of the force exerted by the firefighter on the ladder, which acts in the opposite direction. This force can be calculated as: F_hor_firefighter = m₂ * g * sin(θ), where m₂ is the mass of the firefighter.

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The forces acting on the ladder include the normal force and static friction force from the floor, the weight of the ladder, and the normal force from the wall. The sum of the normal reaction and the static friction forces at the contact point between the ladder and the floor are the forces that the ground exerts on the ladder. A firefighter climbing further up the ladder introduces an additional weight force.

The physics of the situation involves calculating the forces acting on the ladder. There are four forces to consider: the normal force (N) from the floor acting upwards, the static friction force (f = µs N) preventing slippage along the floor, the weight (w) of the ladder acting downwards from its center of mass, and the normal force (F) from the wall preventing the ladder from moving horizontally.

When finding the forces the ground exerts on the base of the ladder, we should consider the sum of the normal reaction from the floor and the static friction forces at the contact point with the ladder and the floor. Because the wall is frictionless, there are no other forces acting at the contact point with the wall.

The firefighter of mass m₂ climbing the ladder further introduces an additional weight force acting downwards, which will affect the balance of forces and torques acting on the ladder. Gravity's effect increases the further up the ladder the firefighter goes, increasing the ladder's tendency to topple or slip.

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Answer:Bohr placed the electrons in distinct energy levels.  Rutherford described the atom as consisting of a tiny positive mass surrounded by a cloud of negative electrons. Bohr thought that electrons orbited the nucleus in quantised orbits.

Explanation: also rutherfords was just a hypothesis while Bhor took the time to make his an experiment

Answer:

I'm not sure but I think it is electric currents in the outer core

The head loss over 20 km of pipe is approximately 2059 meters.

Head loss over 20 km of pipe, we can use the Darcy-Weisbach equation:

Δh = f * (L/D) * (\(v^2\)/2g)

here:

Δh = head loss

f = Darcy friction factor (dimensionless)

L = length of pipe (m)

D = diameter of pipe (m)

v = mean velocity of flow (m/s)

g = acceleration due to gravity (9.81 m/s)

First, we need to calculate the Reynolds number to determine the friction factor:

Re = (v * D) / ν

here ν is the kinematic viscosity of the fluid, which we'll assume to be 1.5 x 10^-6 m^2/s for water at 20°C.

Re = (0.5 m/s * 0.3 m) / (1.5 x 10^-6 m/s)

Re ≈ 10

Since the Reynolds number is above 4000, we can assume the flow is turbulent and use the Colebrook equation to find the friction factor:

1 / √f = -2.0 * log10((ε/D) / 3.7 + 2.51 / (Re * √f))

where ε is the pipe roughness, which we'll assume to be 0.26 mm for cast iron.

We can solve for f using an iterative method. Starting with a guess value of f = 0.02:

1 / √0.02 = -2.0 * log10((0.00026 m / 0.3 m) / 3.7 + 2.51 / (10 * √0.02))

√f ≈ 0.0086

f ≈ 0.000074

The head loss:

Δh = 0.000074 * (20000 m / 0.3 m) * (0.5 m/s) / (2 * 9.81 m/s)

Δh ≈ 2059 m

Therefore, the head loss over 20 km of pipe is approximately 2059 meters.

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We determine the  head loss over 20 km of pipe as 2059 meters.

We apply the Darcy-Weisbach equation:

Δh = f * (L/D) * (/2g)

Δh = head loss

f = Darcy friction factor (dimensionless)

L = length of pipe (m)

D = diameter of pipe (m)

v = mean velocity of flow (m/s)

g = acceleration due to gravity (9.81 m/s)

We find  the Reynolds number to determine the friction factor:

Re = (v * D) / ν

Re = (0.5 m/s * 0.3 m) / (\(1.5 * 10^-^6\) m/s)

Re = 10

we make assumption that the flow is turbulent and use the Colebrook equation to find the friction factor because the Reynolds number is above 4000

1 / √f = -2.0 * log10((ε/D) / 3.7 + 2.51 / (Re * √f))

ε =  the pipe roughness= 0.26 mm for cast iron.

f = 0.02:

1 / √0.02 = -2.0 * log10((0.00026 m / 0.3 m) / 3.7 + 2.51 / (10 * √0.02))

√f = 0.0086

f _= 0.000074

The head loss:

Δh = 0.000074 * (20000 m / 0.3 m) * (0.5 m/s) / (2 * 9.81 m/s)

Δh=  2059 m

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To reduce magnetic flux density, it is necessary to reduce the voltage to a motor when the frequency is reduced. This will resist lowering of inductive reactance and increase of rotor current

When we decrease voltage applied to the motor. The current in stator is winding as well as the magnetic flux density will decrease along with decrease in induced voltage.

The voltage induced over rotor's conductor is defined here

,\(V_{R\) = B.l.u

We can see things in other way also. Changing frequency has effect on  both the motor speed and the strength of the magnetic field. With the lowering of frequency motor speed becomes slow.

With reduction in voltage, magnetic field decreases and magnetic flux becomes constant. This keeps torque production stable, regardless of frequency.

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Answer:

B = 0.157 T

Explanation:

Given that,

Length of the solenoid, l = 8 cm = 0.08 m

Number of turns in the wire, N = 2000

Current, I = 5 A

We need to find the strength of the magnetic field at the center of the solenoid. It is given by the formula as follows :

\(N=\mu_o nI\), N is number of turns per unit length of solenoid.

So,

\(B=4\pi \times 10^{-7}\times \dfrac{2000}{0.08}\times 5\\\\=0.157\ T\)

So, the magnetic field at the center of the solenoid is 0.157 T.

The most important managerial skill Freddy needs to have is business acumen because it will improve his business instincts and allow him to guide him team to where they can have the most impact.

Managerial skills are the knowledge and ability of the individuals in a managerial position to fulfil some specific management activities or tasks.

The most sought-after qualifications in a Convenience Store Manager are;

Thus, the most important managerial skill Freddy needs to have is business acumen because it will improve his business instincts and allow him to guide him team to where they can have the most impact.

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A graph of KE (kinetic energy) vs the mass of an object is a line, as we know that the kinetic energy depends linearly on the mass of the object.

For an object of mass M moving with velocity v, we define its kinetic energy as:

KE = (M/2)*v^2

We can rewrite it as:

KE = (v^2/2)*M

So, it is a "coefficient" (if we assume that the velocity is constant) times the mass. That gives a linear relationship.

Then we conclude that the kinetic energy depends linearly on the mass, which means that the graph of KE vs the mass of an object is a line.

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Friction is the force that acts on the opposite side of direction of force, thus it manages to decelerate an object, so it acts upward along the plane

the minimum speed of the ball at point Z is given by v = √(g(r/g - 1)/(1 - r/g)).

we have T = mv²/r... (1)

where v is the speed of the ball at point P.

We can rewrite this equation as v = √(Tr/m)... (2)

At point Q, the ball has its maximum speed and minimum tension.

Thus, we can write T - mg = mv²/r... (3)

where v is the speed of the ball at point Q.

From equation (3), we can write v² = (T/m)(r + g)... (4)

Substituting the value of v² from equation (4) into equation (3), we get

T - mg = (T/m)(r + g)T - mg = Tr/m + Tg/mT/m = g/(1 - r/g)T = mg/(1 - r/g)... (5)

Substituting the value of T from equation (5) into equation (4), we getv² = g(r/g + 1)/(1 - r/g)v²

= g(2 - r/g)v = √(g(2 - r/g))... (6)

At point Z, the ball has its minimum speed and maximum tension.

Thus, we can write T + mg = mv²/r... (7)

where v is the minimum speed of the ball at point Z. From equation (7), we can write

v² = (T/m)(r - g)... (8)

Substituting the value of T from equation (5) into equation (8), we get

v² = g(r/g - 1)/(1 - r/g)v

= √(g(r/g - 1)/(1 - r/g))... (9)

Hence, the tension at point P is given by

T = mv²/r or T = mg/(1 - r/g),

the speed of the ball at point Q is given by

v = √(g(2 - r/g)), and the minimum speed of the ball at point Z is given by

v = √(g(r/g - 1)/(1 - r/g)).

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Answer:

t = 11.1 hours

Explanation:

The question says that, "A mobile advances at 20 m / s and travels a distance of 800 km. Determine the time in hours you use".

Given that,

Speed of a mobile, v = 20 m/s = 72 km/h

Distance, d = 800 km

We know that,

Speed = distance/time

So,

\(t=\dfrac{d}{v}\\\\t=\dfrac{800}{72}\\\\t=11.1\ h\)

So, it will take 11.1 hours.

The block is stopped by an opposing stopping force of roughly 50 N over a horizontal surface, and it comes to rest.

The concept of "force" has a specific definition in science. This kind of force may be represented as both a push and a pull. It cannot hold an item or a force, nor can it hold a force.

These sorts of forces are there whenever two things interact and work together. Contact forces can include, but are not limited to, tension, normal, air resistance, applied, and spring forces.

v² - u² = 2as

(0)² - (10)² = 2 × a × 10

-100 = 20a

a = -100/20

a = -5 m/s²

Acceleration (a) = -5m/s²

Now,

Force (F) = Mass(m) × Acceleration (a)

F = m × a

F = 10 × -5

F = -50 N

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Answer:

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Answer: runner B

Explanation:

i did the test

Runner which has the weakest force is A.

The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.

The image attached shows the times for runners in a 100 m dash.

Force = mass x Acceleration

Force = mass x Velocity /Time

If each runner has the same mass, runner with the maximum time has the weakest or lowest force.

Among all the four runners, Runner A has the highest time for completing 100 m dash.

Thus, Runner A has the weakest force.

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Answer:

1-Average speed

2-constant

Explanation:

Question 1 : You have the distance and time , need to find average speed

Question 2 : traveling at the same speed that means it's constant

Answer:

3540.5N

Explanation:

Step one:

given data

mass m= 0.196kg

speed  v= 31m/s

distance r= 5.32cm = 0.0532m

Step two

The expression relating force, mass, velocity and distance is

F= mv^2/r

substitute we have

F=0.196*31^2/0.0532

F=0.196*961/0.0532

F=188.356/0.0532

F=3540.5N

Please find attached photograph for your answer. Answer is c. 16 times. Do comment if you have any query. Don't forget to mark me Brainliest if you like my answer

Answer: By "waves can be refracted" they mean that refraction can occur with waves. To better explain, refraction is the "change in direction of a wave passing from one medium to another or from a gradual change in the medium."  You probably know this best when you put a pencil inside a glass of water where the pencil bends a bit. The same can happen with sound or water waves as well!

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Answer:

Inter Quartile Range

Explanation:

Quartile is a positional statistical average, which divided the data into 4 equal halves.

Q1 (Lower Quartile) has 25% data below it, 75% above it. Q3 (Upper Quartile) has 75% data below it, 25% above it.

Interquartile range is the measure used to calculate how far the lower & upper quartiles are.

Answer:

b

Explanation:

because the metalloids are the thing in the middle

Answer:

t = 1.22 s

Explanation:

Given that,

The initial upward velocity component of a football = 12 m/s

The horizontal velocity component is 20 m/s

We need to find the time required for the football to reach the highest point of the trajectory. Let the time is t.

Using first equation of motion to solve it such that,

\(v=u+at\)

u is initial velocity

v is final velocity

a = -g

so,

\(t=\dfrac{u}{g}\\\\t=\dfrac{12}{9.8}\\\\t=1.22\ s\)

So, the required time taken by the football to reach the highest point is 1.22 seconds.