A ball that is out of play is called a __________________. 2. Volleyballs are made out of __________________ material. 3. A __________________ occurs when the server steps on or over the end line. 4. Contact of the ball by a player is called __________________. 5. The __________________ decides who will serve and the choice of playing area.

Answers

Answer 1

Answer:

1) Deadball

2) Leather

3) Foot Fault

4) Pass

5) Captain

Explanation:

1) In most sports when a ball is out of play or termed temporarily unplayable, it is said to be a Deadball.

2) Volleyballs are generally made of leather materials be it synthetic or genuine leather.

3) In volleyball, when a server steps on or over the end line, it is called foot fault.

4) The first contact of a ball by a player after a serve from a passer is usually called a pass.

5) In volleyball, the referee issues a coin toss in presence of both captains and the captain with the winning toss is the one that makes the choice of play area and the first server.


Related Questions

Question 1(Multiple Choice Worth 3 points)
(01.04 LC)
Which of the following is not an intensive physical property?
Electrical conductivity
Mass
Density
Freezing point

Answers

Answer:

Electrical conductivity

Explanation:

This is because it is not a bulk property where as the others are.

how many joules of energy are used if the burner is on for 125 seconds?

Answers

If the burner is on for 125 seconds with a power rating of 1000 watts, then 125000 joules of energy are used.

We need to know the power rating of the burner to calculate the energy used. Let's assume the power rating of the burner is 1000 watts.

Power = 1000 watts

Time = 125 seconds

Energy = Power x Time

Energy = 1000 watts x 125 seconds

Energy = 125000 joules.

Energy is a fundamental concept in physics and is typically measured in joules (J). The joule (J) is the SI unit of energy and is defined as the amount of energy transferred or work done when a force of one newton acts on an object to move it one meter in the direction of the force.

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The world's longest continuous mountain ridge is under the ocean.
True
False

Please hurry!!!

Answers

Answer:

True

Explanation:

LL Bean shifted from collecting structure data to unstructured
because:
A). the data warehouse is on site.
B). they a single marketing channel
C). the volume of data collected over time stayed
consist

Answers

LL Bean shifted from collecting structured data to unstructured data because the volume of data collected over time remained consistent.

Collecting structured data typically involves organizing and storing data in a predefined format, such as a data warehouse. However, LL Bean's decision to shift to unstructured data suggests that their existing data warehouse, which is likely designed for structured data, may not have been capable of efficiently handling the increasing volume of data collected over time.

Unstructured data, on the other hand, does not adhere to a specific format and can accommodate a larger and more diverse range of data types, allowing LL Bean to effectively manage the growing volume of data they were collecting.

Please note that the provided options A and B are not directly relevant to the reason stated for LL Bean's shift to unstructured data.

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Which is an example of potential energy being transformed into kinetic energy?
A. A rock sitting at the top of a hill rolling down the hill.
B. A rock sitting at the top of a hill without moving.
C. A rock at the bottom of a hill being pushed up the hill.
D. A rock sitting at the bottom of the hill without moving.

Answers

Answer:

B is the right answer

can you please rate &like

A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. What minimum coefficient of static friction is required

Answers

A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. Minimum coefficient of static friction is required 13.56.

To find the minimum coefficient of static friction required, we need to calculate the centrifugal force acting on the child and compare it to the force of friction.

The centrifugal force acting on the child is given by:

= Fc

= m * r * w^2

where

= m

= 50.0 kg (mass of child)

= r

= 2.70 m (radius of the merry-go-round)

= w

= 3.95 rad/s (angular velocity)

So, Fc = 50.0 kg * 2.70 m * (3.95 rad/s)^2

= 6629.775 N

The force of friction acting on the child is given by:

= Ff

= friction coefficient * normal force

where

friction coefficient = minimum coefficient of static friction required (unknown)

= normal force

= m * g

The normal force is equal to the weight of the child, which is

= m * g

= 50.0 kg * 9.8 m/s^2

= 490 N

So, Ff = friction coefficient * 490 N

To find the minimum coefficient of static friction, we need to set Ff equal to Fc and solve for the friction coefficient:

friction coefficient = Ff / N

friction coefficient = 6629.775 N / 490 N

= 13.56

So the minimum coefficient of static friction required is 13.56.

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A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that its tires will not leave the track? Round to one decimal place and include units. Image:

A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can

Answers

Answer:

see explanations below

Explanation:

At the point when the car leaves the track, the reaction on the road is zero, meaning that the centrifugal force equals the gravitation force, namely

mv^2/r = mg

Solve for v in SI units

v^2 = gr = 9.81 m/s^2 * 14.2 m = 139.302 m^2/s^2

v = sqrt(139.302) = 11.8 m/s

Answer: at 11.8 m/s (26.4 mph) car will leave the track.

Una bala de cañón se dispara horizontalmente con una velocidad inicial de 120m/s y un ángulo de elevación de 35°.Encuentra:a)su alcance maximo,b)si altura máxima,c)si tiempo maximo de vuelo

Answers

Answer:

a) x = 1353,2 m.

b) \(y_{max}\) = 236,9 m \)

c) \(t_{v} = 13,8 s\)

Explanation:

a) El alcance máximo se puede calcular usando la siguiente ecuación:

\( y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}} \)   (1)

En donde:

y: es la altura final = 0

\(y_{0}\): es la altura inicial = 0

x: es el alcance

θ: es el angulo respecto a la horizontal = 35°  

\(v_{0}\): es la velocidad inicial = 120 m/s

g: es la gravedad = 10 m/s²

Resolviendo la ecuación (1) para x, tenemos:

\( x = \frac{2tan(\theta)*(v_{0}cos(\theta))^{2}}{g} = \frac{2tan(35)*(120 m/s*cos(35))^{2}}{10 m/s^{2}} = 1353,2 m \)          

El alcance máximo es 1353,2 m.

b) La altura máxima es:

\( y_{max} = \frac{v_{0}_{y}^{2}}{2g} = \frac{(v_{0}sen(\theta))^{2}}{2g} = \frac{(120 m/s*sen(35))^{2}}{2*10 m/s^{2}} = 236,9 m \)

Entonces, la altura máxima es 236,9 m.                                       

c) El tiempo de vuelo es el siguiente:

\(t_{v} = \frac{x}{v_{0}cos(\theta)} = \frac{1353,2 m}{120 m/s*cos(35)} = 13,8 s\)

Por lo tanto, el tiempo de vuelo es 13,8 s.

Espero que te sea de utilidad!

4. Un móvil lleva una velocidad de 75 m/s, en dicho momento aplica los frenos durante tiempo de 15 segundos hasta detenerse. ¿cuál será la aceleración del frenado? ¿cuál es la distancia que recorre hasta detenerse?

Answers

Answer:

a = 5 m / s²   and    x = 562.5 m

Explanation:

Let's apply the kinematics relations

          v = v₀ + at

          v² = v₀² + 2a x

In this case, as the car stops, its final speed is zero (v = 0) and the acceleration must be opposite to the speed, that is, negative

           0 = v₀ - a t

           a = v₀ / t

let's calculate

           a = 75/15

           a = 5 m / s²

let's look for the distance

           0 = v₀² - 2a x

           x = v₀² / 2a

let's calculate

           x = \(\frac{75^2}{2 \ 5 }\)

           x = 562.5 m

irst, you must find the wavelength of the laser. you shine the laser into the interferometer and then move one of the mirrors until you have counted 100.0 fringes passing the crosshairs of the telescope. the extremely accurate micrometer shows that you have moved the mirror by 0.03164 millimeters. what is the wavelength λλlambda of the laser?

Answers

In conclusion, to find the wavelength of the laser, we measured the displacement of the mirror and calculated the fringe spacing. By multiplying the fringe spacing by 2, we determined the wavelength of the laser to be 0.0003164 mm (or 316.4 nm).

To find the wavelength (λ) of the laser, we can use the given information. When you shine the laser into the interferometer and move one of the mirrors, you observe 100.0 fringes passing the crosshairs of the telescope. By measuring the displacement of the mirror using the accurate micrometer (0.03164 millimeters), we can determine the wavelength of the laser.
Here's how we can calculate it:
1. Recall that the distance between two adjacent fringes is equal to half the wavelength of the laser. So, if we count 100 fringes passing the crosshairs, we've actually observed 200 fringe spacings.
2. Divide the displacement of the mirror (0.03164 mm) by the number of fringe spacings observed (200) to get the fringe spacing (δ).
  δ = 0.03164 mm / 200 = 0.0001582 mm
3. Finally, multiply the fringe spacing (δ) by 2 to get the wavelength of the laser (λ).
  λ = 2 * δ = 2 * 0.0001582 mm
To convert the wavelength from millimeters to meters, you can divide by 1000:
  λ = 2 * 0.0001582 mm / 1000 = 0.0003164 mm
Therefore, the wavelength of the laser is 0.0003164 mm (or 316.4 nm).
In conclusion, to find the wavelength of the laser, we measured the displacement of the mirror and calculated the fringe spacing. By multiplying the fringe spacing by 2, we determined the wavelength of the laser to be 0.0003164 mm (or 316.4 nm).

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Under the current law on nutrition labeling, the Nutrition Facts
panel must include
a. total calories from trans fat
b. grams of monounsaturated fat
c. grams of total fat
d. total calories from satura

Answers

The Nutrition Facts panel must include the grams of monounsaturated fat, grams of total fat, and total calories from saturated fat.

a. The total calories from trans fat are not required to be included in the Nutrition Facts panel. Trans fat is listed separately under "Total Fat" and does not have its own specific calorie value.

b. The grams of monounsaturated fat are required to be included in the Nutrition Facts panel. Monounsaturated fat is a type of fat that is beneficial for health, and its quantity is provided to help consumers make informed choices.

c. The grams of total fat are required to be included in the Nutrition Facts panel. Total fat represents the sum of all types of fats present in the food product.

d. The total calories from saturated fat are required to be included in the Nutrition Facts panel. Saturated fat is a type of fat that is associated with an increased risk of certain health conditions, and providing the calorie value helps consumers monitor their intake.

Therefore, the Nutrition Facts panel must include b. grams of monounsaturated fat, c. grams of total fat, and d. total calories from saturated fat.

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hen approaching a curve, it is best to: A. Search for possible collision traps and escape paths B. Stay close to the centerline if there is oncoming traffic C. Squeeze the clutch lever to slow down D. Shift to a higher gear

Answers

Squeezing the clutch lever to slow down is best to be done when approaching a curve and is denoted as option C.

What is Clutch?

This is a mechanical device which used in the engagement and disengagement of transmission system in a vehicle.

Slowing down will give the driver more time to maneuver the curves so as to prevent accident. This is why it is imperative to squeeze the clutch in such road condition.

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Which is moving faster a car traveling 150 km in 3 hours or one traveling 100 km in 2 hours?

Answers

neither they’re both moving the same . 150/3 = 50km
100/2 = 50km
therefor they’re traveling at the same rate.

A reheat Rankine cycle operates with water as the working fluid. Steam enters the first turbine at 8 MPa and 450°C and exits at 0.8 MPa. It is then reheated to 400°C before entering the second turbine, where it exits at 10 kPa. If the amount of work into the pump is 8.04 kJ/kg and the net work per cycle produced is 1410.25 kJ/kg, determine the thermal efficiency of the cycle

Answers

Answer:

The thermal efficiency, \(\eta _{reheat}\), of the Rankine cycle with reheat is 36.81%

Explanation:

p₁ = 8 MPa = 80 Bars

T₁ = 450°C = 723.15 K

From steam tables, we have;

v₁ = 0.0381970 m³/kg

h₁ = 3273.23 kJ/kg

s₁ = 6.5577 kJ/(kg·K) = s₂

The p₂ = 0.8 MPa

T₂ = Saturation temperature at 0.8 MPa = 170.414°C = 443.564 K

h₂ = 2768.30 kJ/kg

\(T_{2'}\) = 400°C = 673.15 K

\(h_{2'}\) = at 400°C and 0.8 MPa = 3480.6 kJ/kg

p₃ = 10 kPa = 0.1 Bar

T₃ = Saturation temperature at 10 kPa = 45.805 °C = 318.955 K

h₃ = 2583.89 kJ/kg

h₄ = \(h_{3f}\) = 191.812 kJ/kg

The thermal efficiency, \(\eta _{reheat}\), of a Rankine cycle with reheat is given as follows;

\(\eta _{reheat} = \dfrac{\left (h_{1}-h_{2} \right )+\left (h_{2'}-h_{3} \right )-W_{p}}{h_{1}-\left (h_{4}+W_{p} \right )+\left (h_{2'}-h_{2} \right )}\)

Therefore, we have;

\(\eta _{reheat} = \dfrac{(3273.23 -2768.30 ) + (3480.6 -2583.89 ) - 8.04)}{(3273.23 -(191.812 + 8.04) + (3480.6 -2768.30 ) } = 0.3681\)

Which in percentage is 36.81%.

70kg man runs up a flight of staurs in 4 sec . The vertical height of the stairs is 4.5 m . Calculate his power

Answers

Answer:

771.75 watt

Explanation:

Given,

Mass ( m ) = 70 kg

Distance ( d ) = 4.5 m

Time taken ( t ) = 4 seconds

Power = ?

Now, applying the formula to find power:

\(power = \frac{work \: done}{time \: taken} \)

\( = \: \frac{f \: \times \: d}{t} \)

\( = \frac{m \: \times \: g \: \times \: d}{t} \)

Plugging the values:

\( = \frac{70 \times 9.8 \times 4.5}{4} \)

Calculate the products

\( = \frac{3087}{4} \)

Divide:

\( = 771.75 \: watt\)

Hope this helps...

Best regards!!

PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject

PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have

Answers

Answer:

I believe it is D.

Explanation:

I say this because it is position vs. seconds and it makes the most sense based on the markings. Sorry if I am wrong, hope it is right!  

Answer: D. 40/15 = 2.67m/s

Explanation:

I hope it is correct

robin started at point a. she walked 4m south, then 8m east, then 4m north, then 8m west so that she was back at point a. if her walk took 5 minutes, what was her velocity in meters per minute?

Answers

Robin started at point a. she walked 4m south, then 8m east, then 4m north, then 8m west so that she was back at point a. if her walk took 5 minutes her velocity in meters per minute is 0.96.

Displacement = distance / time = 24m/5 = 4.8

Velocity = displacement / Time = 4.8/5 = 0.96m/min

Its scientific definition and velocity are presumably similar. You are aware that a significant displacement over a short period of time indicates a large velocity, and that velocity has measures of distance / time, like miles/hour or kilometers/hour.

The change in position divided by the distance travelled is the definition of average velocity. However, the average speed of an object tells us nothing about what happens to it between the starting and finishing points. For instance, average velocity does not allow us to determine whether a passenger in an airplane briefly stops or reverses before relocating to the rear of the aircraft. We must consider shorter distances travelled over shorter times in order to obtain more information.

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a person riding in an elevator stands on a metric scale. if the mass of the person is 60.0 kg and the elevator accelerates upward with an acceleration of 4.90 m/s2, what is the reading on the scale?

Answers

The reading on the scale is 882.6 N when the elevator accelerates upwards with an acceleration of 4.90 m/s².

Given that the mass of a person is 60.0 kg and the elevator accelerates upwards with an acceleration of 4.90 m/s², we have to determine the reading on the scale.

Let F be the force exerted by the scale on the person. Then, by Newton's second law of motion, the net force acting on the person is Fnet= m * a

where m = 60.0 kg is the mass of the person and a = 4.90 m/s² is the acceleration of the elevator. Hence, the net force acting on the person is given by;

Fnet = 60.0 kg * 4.90 m/s²

Fnet = 294.0 N

Therefore, the scale reading is equal to the force exerted by the scale on the person. Since the elevator is accelerating upwards, the force exerted by the scale on the person is greater than the weight of the person, which is the force of gravity acting on the person.

The force of gravity acting on the person is given by;

Fg = m * g, where g = 9.81 m/s² is the acceleration due to gravity. Hence, the force of gravity acting on the person is given by;

Fg = 60.0 kg * 9.81 m/s²Fg = 588.6 N

Therefore, the scale reading is given by the sum of the force of gravity acting on the person and the net force acting on the person;

F = Fg + Fnet

F = 588.6 N + 294.0 N

F = 882.6 N

Thus, the reading on the scale is 882.6 N when the elevator accelerates upwards with an acceleration of 4.90 m/s².

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1. If you throw a ball into the air, the Earth's gravity will cause the ball to​

Answers

Explanation:

fall at a faster velocity than what it was thrown! Hope this helps!

Free body diagram is this correct?

Free body diagram is this correct?

Answers

Answer:Yes that is correct

Explanation:

Answer:

yes that is correct.

What travels by vibrating particles? Mechincal Waves or ElecrtoMagnetic Waves.

Answers

Answer:mechanical waves.

Explanation:

Mechanical waves require the particles of the medium to vibrate in order for energy to be transferred. For example, water waves, earthquake/seismic waves, sound waves, and the waves that travel down a rope or spring are also mechanical waves.

a circuit in a home provides power to a light fixture. the homeowners want to use a compact fluorescent bulb instead of an incandescent bulb. compact fluorescent bulbs can produce as much light as incandescent bulbs but with less energy. how is this possible?(1 point) responses fluorescent bulbs have been designed to put out more energy than they receive. fluorescent bulbs have been designed to put out more energy than they receive. fluorescent bulbs produce other forms of energy, too, including heat. fluorescent bulbs produce other forms of energy, too, including heat. energy is destroyed when it passes through an incandescent bulb. energy is destroyed when it passes through an incandescent bulb. incandescent bulbs produce other forms of energy, too, including heat. incandescent bulbs produce other forms of energy, too, including heat.

Answers

A circuit in a home provides power to a light fixture. The homeowners want to use a compact fluorescent bulb instead of an incandescent bulb. compact fluorescent bulbs can produce as much light as incandescent bulbs but with less energy because: it makes them a more cost-effective choice over time.

The homeowners want to use a compact fluorescent bulb instead of an incandescent bulb. Compact fluorescent bulbs can produce as much light as incandescent bulbs but with less energy. Fluorescent bulbs have been designed to put out more energy than they receive. This makes them a more efficient light source than incandescent bulbs.

Unlike incandescent bulbs, fluorescent bulbs produce less heat and use less electricity. Fluorescent bulbs produce light by exciting mercury vapor. The mercury vapor emits ultraviolet light, which is converted into visible light by a phosphor coating on the bulb's interior. This process uses less energy than an incandescent bulb, which produces light by heating a filament until it glows.

Fluorescent bulbs can also last much longer than incandescent bulbs, which makes them a more cost-effective choice over time. Overall, fluorescent bulbs are a more efficient and environmentally friendly choice for lighting compared to incandescent bulbs.

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what is the difference between passive and active solar heating

Answers

Passive solar heating utilizes design and natural processes to capture and distribute solar energy without mechanical devices, while active solar heating uses mechanical systems to collect and distribute solar heat, requiring external energy inputs.

Passive solar heating and active solar heating are two different approaches to utilizing solar energy for heating purposes. Here's a brief explanation of each:

1. Passive Solar Heating:

Passive solar heating refers to the design and use of building materials to capture, store, and distribute solar energy without the use of mechanical or electrical devices. It relies on natural processes and elements to maximize solar gain and heat transfer. Some common passive solar heating techniques include:

Orienting buildings to maximize exposure to the sun's rays.Incorporating large south-facing windows to allow sunlight into the building.Utilizing thermal mass materials, such as concrete or brick, to absorb and store heat during the day and release it gradually at night.Using natural ventilation and shading techniques to control heat gain and loss.

Passive solar heating systems do not require active mechanical components like pumps or fans and are generally considered more energy-efficient and cost-effective.

2. Active Solar Heating:

Active solar heating involves the use of mechanical and electrical devices to collect, store, and distribute solar energy for heating purposes. It typically utilizes solar collectors, such as solar panels or solar thermal systems, to capture sunlight and convert it into heat energy. The collected heat is then transferred to a heat storage system or directly used to provide space heating or water heating. Active solar heating systems may involve pumps, fans, and controls to circulate the heated fluid or air throughout the building.

Active solar heating systems require external energy inputs, such as electricity for powering pumps or fans, and often involve more complex installation and maintenance compared to passive solar heating. However, they can offer greater control and efficiency in heating applications, especially in larger or more demanding spaces.

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Write forty million in scientific notation.

Answers



Answer: 4 x 106

That’s how you write forty million in scientific notation.

Answer:

40,000,000 ⇒ scientific notation

= 4 × \(10^{7}\)

What is the velocity of the girl in Figure b? Please help me!!!!
Is the answer A,B,C,D,E, or F?

What is the velocity of the girl in Figure b? Please help me!!!!Is the answer A,B,C,D,E, or F?

Answers

There is a Blank screen

. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.​

Answers

Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :

Step 1: Calculate the velocity using the equation:

\(v = u + at\)

where:

- \(v\) is the final velocity

- \(u\) is the initial velocity (0 m/s, as the car starts from rest)

- \(a\) is the acceleration (3 m/s²)

- \(t\) is the time (50 seconds)

Substituting the values into the equation:

\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)

Step 2: Calculate the distance traveled using the equation:

\(s = ut + \frac{1}{2}at^2\)

where:

- \(s\) is the distance traveled

- \(u\) is the initial velocity (0 m/s)

- \(a\) is the acceleration (3 m/s²)

- \(t\) is the time (50 seconds)

Substituting the values into the equation:

\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)

Now, let's simplify these equations:

\(v = 3 \times 50\)

\(s = \frac{1}{2} \times 3 \times 50^2\)

Calculating the results:

\(v = 150\) m/s

\(s = 3750\) meters

Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.

A bumper car with a mass of 86 kg is traveling at 3.6
m/s. A bumper car with a mass of 98 kg is traveling at
1.6 m/s in the opposite direction. After the collision, the
86 kg bumper car travels at -0.5 m/s. What is the speed
of the 98 kg bumper car after the collision?

Answers

Answer:

2.0 m/s

Explanation:

i found it on quizlet

in a stack of three polarizing sheets, the first and third are at right angles, while the middle one has its axis at an angle of 0.833 rad with respect to the first one. if an initially unpolarized beam of light with intensity 8000 w/m2 is incident on this stack of polarizers, what is the intensity of the emerging beam?

Answers

Answer:

The correct option is D 18

We know that when an unpolarized light passes through a polarizer its intensity gets halved.

Now according to Malu's law-

I=I0

So the intensity after passing through 1st polarizer will be

I1=I0 cos2 θ=I0 cos2 45∘=I02

After passing through 2nd polarizer

I2=I1 cos2 θ=I02×12=I04

After passing through 3rd polarizer

I3=I2 cos2 θ=I04×12

I3=I08

The intensity of the emerging beam is 0 W/m².

In other words, no light is transmitted through the stack of polarizers because the third polarizing sheet blocks all of the partially polarized light that passes through the second polarizing sheet.

When unpolarized light passes through a polarizer, half of the light is absorbed and the other half is transmitted in a plane perpendicular to the polarization axis of the polarizer.

In this case, we have three polarizing sheets arranged as follows:

Polarizer 1: |         | (vertical)

                  |____|      

Polarizer 2: /         / (at an angle of 0.833 rad with respect to Polarizer 1)

                 /____/            

Polarizer 3: |         | (horizontal)

                   |____|

The unpolarized beam of light passes through Polarizer 1 and half of its intensity is transmitted. Then, this partially polarized light passes through Polarizer 2, which is at an angle of 0.833 rad with respect to Polarizer 1.

The intensity of the light transmitted through Polarizer 2 is given by:

\(I_2\) = \(I_1\) cos²θ

where \(I_1\) is the intensity of the partially polarized light incident on Polarizer 2 and θ is the angle between the polarization axis of Polarizer 2 and the polarization axis of Polarizer 1.

Substituting the given values, we get:

\(I_2\) = (1/2) cos²(0.833 rad) = 0.2586 \(I_1\)

Therefore, the intensity of the light transmitted through Polarizer 2 is 0.2586 times the intensity of the partially polarized light incident on Polarizer 2.

Finally, the partially polarized light passes through Polarizer 3, which is perpendicular to Polarizer 1. The intensity of the light transmitted through Polarizer 3 is given by:

\(I_3\) = \(I_2\) cos²(90°) = \(I_2\) (0) = 0

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a ray of green light travels through air and is refracted as it enters a glass prism shown in the figure. an unknown liquid is in contact with the right side of the prism. the light then follows the path shown. which one of the following statements concerning this situation is true? a) the frequency of the light changes inside the prism. b) the index of refraction of the glass is smaller than that of air. c) the index of refraction of the unknown liquid is the same as that of the glass. d) the speed of light is larger in the liquid than in the glass. e) the refractive index of the liquid is the same as that of air.

Answers

Option C, Since there is no refraction and light travels in almost the same direction in both the glass as well as the unknown liquid, their indexes of refraction are identical.

Moving from the atmosphere to the glass causes the light to slow down. A prism's angle is 60 degrees, and its green light refractive index is 1.5.

The many media, or matter particles, through which light passes were used to gauge both its speed and how it appears to the human eye. To discern the different light wavelengths, the speed should slow down when the white light is revealed via the prism.

The following formula is used to get the refractive index:

n₁ sinθ₁  = n₂sinθ₂  

where n₁ and n₂ represent the observed difference and represent the diffraction pattern between two liquids.

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A conductor is made in the form of a hollow cylinder with inner and outer radii a and b, respectively. It carries a current I, uniformly distributed over its cross section.

Answers

A conductor is made in the form of a hollow cylinder with inner and outer radii a and b, respectively. It carries a current I, uniformly distributed over its cross section. We are given that

Inner radius,Outer radius,Current=Ia.If r<a

Consider a loop of radius r where r<a

What is conductor?

A conductor is an object or kind of material that permits the movement of charge (electric current) in one or more directions. This term is used in both physics and electrical engineering. Metal-based materials are frequently used as electrical conductors. Negatively charged electrons, positively charged holes, and occasionally positive or negative ions flow to create electric current.

It is not essential for one charged particle to move from the component creating the current (the current source) to those consuming it for current to flow within a closed electrical circuit (the loads). Instead, the charged particle only needs to nuzzle its neighbor a limited number of times, and then the process repeats itself until a particle gets nuzzled into the consumer, generating electricity.

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