a block measuring 20cm by 10cm by 5cm rests on a flat surface. The block has a weight of 3N. Determine the maximum pressure it exerts on the surface​

Given what we know, we can confirm that option D,  Electromagnetic waves with high frequency are more energetic than electromagnetic waves with low frequency is true.

High-frequency waves are synonymous with short wavelengths. This means that the waves are oscillating much quicker and therefore carry more kinetic energy within them. This is transformed and released as electromagnetic radiation, which is the reason why high-frequency waves are more energetic than low-frequency electromagnetic waves.

Therefore, we can confirm that the statement "Electromagnetic waves with high frequency are more energetic than electromagnetic waves with low frequency" is true.

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Answer:

Explanation:

All

The mass of a pure platinum disc can be gotten by multiplying the density with the volume.

Therefore the mass is 2418.2 grams or 2.4182 kilograms.

A body's mass is an inherent quality. Prior to the discovery of the atom and particle physics, it was widely considered to be tied to the amount of matter in a physical body.

The kilogram is the primary mass unit in the SI.

The resistance of the body to acceleration in the presence of a net force can be measured as mass.

Due to the lower gravity on the Moon, an object would weigh less than it does on Earth while maintaining the same mass. This is due to the fact that mass, coupled with gravity, determines the strength of weight, which is a force.

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What is the mass of a pure platinum disk with a volume of 113 cm3? The density of platinum is 21.4 g/cm3.

Give your answer in grams and kilograms.

The section of the diagram that includes the coolest, brightest stars is A, Section 1.

On the Hertzsprung-Russell diagram, the vertical axis represents luminosity, which is the total amount of energy emitted by a star per unit time. The luminosity is measured in units of solar luminosity, which is the amount of energy emitted by the Sun per unit time.

The section that includes the coolest, brightest stars is Section 1. This is because in this section, the stars have a low temperature (around 3,000-4,000 K) and a high luminosity (around 1,000-10,000 times that of the Sun). These stars are called red giants, and they are nearing the end of their lives. As they run out of fuel, their outer layers expand and cool, making them appear red and bright.

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Answer:

d. conduction ​

Explanation:

Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.

In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.

Any material or object that allow the conduction (transfer) of electric charge or thermal energy is generally referred to as a conductor. Conductors include metal, steel, aluminum, copper, frying pan, pot, spoon etc.

In conclusion, conduction typically involves the transfer of heat energy by direct contact between two or more conductors such as a pot and electric cooker.

Answer:

d. conduction ​

Explanation:

Conduction is the transfer of energy from one molecule to another by direct contact.

Answer:

C 40 m/s the velocity of WAve

Answer:

hsjdsdddwqdqwdd

Explanation:

Answer:

where u put it last time or retrace ur steps to where u last put it

Answer:

Explanation:

Assuming that not only is the size of the two blocks the same but the MASS is also the same, then the higher block will have more potential energy.

Potential energy is equal to the amount of work required against gravity to position a mass

Work is a force times a distance. PE = W = Fd

As each block has the same mass, they each create the same force which would be their weight mg

PE = W = Fd = mgd

so potential energy is directly proportional to the height of each block

the lower block has potential energy PE = Fd = mg(5)

while the upper block has potential energy PE = mg(6)

above a reference frame origin, possibly the floor.

It is possible that the higher block has less potential energy then the lower block if only the size is considered. If the higher block is a one foot cube of ice at 57.2 lbs and the lower block is a one foot cube of copper at 559 lbs then the lower mass would have much more potential energy because of its much greater mass.

559(5) = 2795 ft•lb of potential energy

57.2(6) = 343.2 ft•lb of potential energy

Bonjour,

AU is the astronomical unit referring to the distance between the Earth and the Sun 1 AU is equal to 1,50 × 10¹¹ m.

It therefore comes,

\(\Delta t = \frac{d}{v} = \frac{9,5 \times 1,5 \times 10^{11}}{3,0 \times 10^8} = 4 750 \Longleftrightarrow \Delta t \approx 80 \text{ m}\)

Time = t = 6.62 s

Explanation:

Given data:

Height = h = 215 m

Initial velocity =  = 0 m/s

gravitational acceleration = g = 9.8 m/s²

Time = t = ?

According to the second equation of motion

As the initial velocity is zero, the first term of right-hand side of the above equation is equal to zero.

                                       t² = 2h/g

                                        t = square root 2h/g

                                        t = square root 2x215/9.8

                                        t = 6.62 s

The overcoming force is equal to the friction. The train's mass is 15,560,880.5 Kg

Friction can simply be defined as a force that opposes the movement of an object in a plain surfaces.

Given that the heaviest train ever pulled by a single engine was over 2 km long. Suppose a force of 1.13 X 10^8 N is needed to overcome static friction in the train's wheels. If the coefficient of static friction is 0.741, what's the train's mass?

F = μN

Where

Substitute all the necessary parameters

1.13 X 10^8 = 0.741N

N = 1.13 X 10^8/0.741

N = 152496626.2 N

N = mg

152496626.2 = 9.8m

m = 152496626.2/9.8

m = 15,560,880.5 Kg

Therefore, the mass of the train is 15,560,880.5 Kg.

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Answer:

The difference is between number of turns, Magnetic flux linkage has number of turns while Magnetic flux lacks it

\({}\)

Explanation:

N is number of turns

Answer:

When writing formula, Magnetic flux we don't include numbers of turns which is not the case of magnetic flux linkage.

Explanation:

\({ \tt{magnetic \: flux =BA }}\)

\( { \tt{magnetic \: flux \: linkage = NBA \sin( \theta) }}\)

Answer:

your answer is C

Explanation:

Alveoli is your answer

The torque applied on the rotating rod is 30 N-m.

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction.

Applied force = 60 N

distance = 1.0 m

the force on the lever is exerted at an angle of 30°

sin 30° = 0.5

Hence, the torque applied on the rod = force × distance × sin30°

= 60 N × 1.0 m × 0.50

= 30 N-m.

Hence,  the torque applied on the rotating rod is 30 N-m.

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The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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The energy of the capacitor at this larger plate separation will be= D) U/4

The energy stored in a parallel-plate capacitor with plate area A, plate separation d, and charge Q is given by the formula:

U = (1/2) * (Q^2 / (ε_0 * A * d))

where ε_0 is the permittivity of free space.

If the separation between the plates is increased from d to 2d without changing the charge on the plates, the capacitance of the capacitor will be reduced by a factor of 2. This is because the capacitance of a parallel-plate capacitor is given by the formula:

C = ε_0 * A / d

So, when the separation is doubled, the capacitance is halved.

Since the charge on the plates remains constant, the energy stored in the capacitor is proportional to the square of the charge and inversely proportional to the capacitance. Thus, the new energy of the capacitor when the plates are separated by 2d is given by:

U' = (1/2) * (Q^2 / (ε_0 * A * (2d))) * (1/2)

where the factor of 1/2 is included because the capacitance is halved.

Simplifying this expression, we get:

U' = U / 4

Therefore, the energy of the capacitor at the larger plate separation is (d) U/4.

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A car travels 200 km in the first 2.5 hour then stop for half hour then travels the final speed of 200 km in 2 hours. The average speed of the car is 80 km/hour.

To find the average speed of the car, we need to calculate the total distance traveled and the total time taken.

In the first 2.5 hours, the car travels 200 km.

Then, it stops for half an hour.

After that, the car travels another 200 km in 2 hours.

So the total distance traveled is 200 km + 200 km = 400 km.

The total time taken is 2.5 hours + 0.5 hours + 2 hours = 5 hours.

Therefore, the average speed of the car is:

Average speed = total distance / total time

= 400 km / 5 hours

= 80 km/hour.

So the average speed of the car is 80 km/hour.

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Answer:

Here, m=10 kg

The resultant force acting on the body is

F=(98N)2+(6N)2=10N

Let the resultant force F makes an angle θ w.r.t. 8N force.

From figure, tanθ=8N6N=43

The resultant acceleration of the body is 

a=mF=10kg10N=1ms−2

The resulatnt acceleration is along the direction of the resulatnt force.

Hence, the resultant acceleration of the body is 1 ms−2 at an angle of tan−1(43) w.r.t. 8N force.



Compute the magnitude of the centripetal acceleration a :

a = (22 m/s)² / (50 m) = 9.68 m/s²

Then the magnitude of the centripetal force is

F = (1200 kg) (9.68 m/s²) = 11,616 N ≈ 12,000 N

The truck needs 11,616 N of centripetal force to bend around a radius 50 m.

From the centripetal acceleration,

\(a = \dfrac{v^2}{r}\)

Where,

\(a\)- Centripetal acceleration

\(v\)- velocity = 22 m/s

\(r\)- radius = 50 m

Put the values,

\(a =\dfrac { (22 \rm \ m/s)^2}{(50\rm \ m)}\\\\a = 9.68\rm \ m/s^2\)

So, the centripetal force is

\(F = ma\)

Where, m is the mass = 1200 kg

So,

\(F= 1200\rm \ kg\times 9.68\rm \ m/s^2 \\\\F = 11,616\rm \ N\)

Therefore, the truck needs 11,616 N of  centripetal force to bend around a radius 50 m.

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The mass of the sour cream that should be added is 0.68 kg.

Mass of the water is calculated as follows;

mass = density x volume

mass = (1 kg/L) x 0.5 L = 0.5 kg

Heat gained by the sour cream = Heat lost by the water

\(m_s c_s\Delta \theta _s = m_wc_w\Delta \theta _w\\\\m_s = \frac{m_wc_w\Delta \theta _w}{c_s\Delta \theta _s} \\\\\)

where;

\(m_s = \frac{0.5 \times 4184 \times (80 - 40)}{3510 \times (40 - 5)} \\\\m_s = 0.68 \ kg\)

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Answer:

The temperature of pure melting ice at normal atmospheric pressure is known as the lower fixed point of thermometer

The lower fixed point of a thermometer is the temperature of a pure melting ice at atmospheric pressure of 1 atm

A thermometer is an instrument used in measuring temperature. iThermometers usually have toe fixed ponts the upper fixed pont and the lower fixed point.

The lower fixed point corresponds to the temperature of a pure melting ice at 1 atm

1 atm is normal atmospheric pressure and equal to 101325 Pa

Answer:

hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.

It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.

To find the time it takes for the catcher to stop the ball, you can use the equation:

time = distance / velocity

In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:

time = 0 / 21.80

time = 0 s

So, it takes 0 seconds for the catcher to stop the ball.

To find the distance the ball travels before stopping, you can use the equation:

distance = 1/2 * acceleration * time^2

In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:

distance = 1/2 * (-2000 m/s^2) * (0 s)^2

distance = 0 m

So, the ball travels 0 meters before stopping.

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Answer:

\(g=274\ m/s^2\)

Explanation:

Mass of the Sun, \(M=1.99\times 10^{30}\ kg\)

The radius of the Sun, \(r=6.96\times 10^8\ m\)

We need to find the acceleration due to gravity on the surface of the Sun. It is given by the formula as follows :

\(g=\dfrac{GM}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.99\times 10^{30}}{(6.96\times 10^8)^2}\\\\g=274\ m/s^2\)

So, the value of acceleration due to gravity on the Sun is \(274\ m/s^2\).

The acceleration due to gravity, in meters per second squared, on the surface of the Sun is \(296.88 \;m/s^2\).

Given the following data:

Gravitational constant = \(6.67 \times 10^{-11}\)

To calculate the acceleration due to gravity, in meters per second squared, on the surface of the Sun:

From the law of gravitational force, we have the formula:

\(g = \frac{Gm}{r^2}\)

Where:

Substituting the given parameters into the formula, we have;

\(g = \frac{6.67 \times 10^{-11} \times 1.99 \times 10^{30}}{(6.69 \times 10^8)^2} \\\\g= \frac{1.33 \times 10^{20} }{4.48 \times 10^{17}} \\\\g=296.88 \;m/s^2\)

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Answer:

Explanation:

The fennec may be the world's smallest fox, but it sports outlandishly large ears! In fact, relative to body size, it has the largest ears of any member of the canid family. It uses those big ears to listen for sounds of prey in the sand. The ears also help dispel body heat to keep the fox cool.

Answer:

F = 1.6 N

Explanation:

Newton's Second Law of Motion states that whenever an unbalanced force is applied on a body. It produces an acceleration in the body, in its own direction. The magnitude of the force is given by the following formula:

F = ma

where,

F = Force Required to Move the Object Upward = ?

m = mass of object

a = upward acceleration = 2 m/s²

but, we know that weight of object is given as:

Weight = mg

8 N = m(9.8 m/s²)

m = 0.8 kg

using values in the equation:

F = (0.8 kg)(2 m/s²)

F = 1.6 N

Answer:

Sound and power are related through intensity, which is the amount of power per unit area. The intensity of a sound wave is proportional to the square of its amplitude, which is a measure of how far the wave oscillates from its equilibrium position.

To solve this problem, you can use the formula for sound intensity:

I = P/A

where I is the intensity of the sound wave in watts per square meter (W/m^2), P is the power of the sound wave in watts (W), and A is the area of the eardrum in square meters (m^2).

You are given that the softest sound a human ear can hear is 0 dB, which corresponds to an intensity of 10^-12 W/m^2. You are also given that sounds above 130 dB cause pain. To find the maximum power the ear can receive before the listener feels pain, you can rearrange the formula for intensity to solve for power:

P = AI

where A is the area of the eardrum in square meters.

Substituting the given values, you get:

P = (51 x 10^-6 m^2)(10^-12 W/m^2 x 10^(130/10))

Simplifying this expression, you get:

P = 1.8 x 10^-3 W

Therefore, the most power the ear can receive before the listener feels pain is 1.8 x 10^-3 watts.

Answer:

The temperature of this newly discovered planet violates the third law of thermodynamic, there is a mistake in this value.

Explanation:

The third law of the Thermodynamic says:

At zero kelvin all molecular movement stops, which means that the entropy will be zero at this temperature.

So we can say there is no thermodynamic system that has temperature values less than 0 K.

The conclusion of the report will be.

The temperature of this new planet violates the third law of thermodynamic, there is a mistake in this value.

I hope it helps you!

Answer:

(a) To solve for the initial speed of the rock at launch, we can use the kinematic equation:

v = v0 + at

Where:

v = final velocity (15m/s)

v0 = initial velocity (what we're solving for)

a = acceleration due to gravity (-9.8m/s^2)

t = time (2.0s)

Plugging in the values, we get:

15m/s = v0 - 9.8m/s^2 (2.0s)

v0 = 34.6m/s

Therefore, the initial speed of the rock at launch was approximately 34.6m/s.

(b) To solve for the speed of the rock 5.0s after launch, we can use the same kinematic equation:

v = v0 + at

But this time, we need to add the additional time and distance that the rock traveled after the initial 2.0s. To do this, we'll use the equation:

d = v0t + 1/2at^2

Where:

d = distance traveled

v0 = initial velocity (34.6m/s)

a = acceleration due to gravity (-9.8m/s^2)

t = time (5.0s - 2.0s = 3.0s)

Plugging in the values, we get:

d = (34.6m/s)(3.0s) + 1/2(-9.8m/s^2)(3.0s)^2

d = 103.8m - 44.1m

d = 59.7m

So, the rock traveled 59.7m in the additional 3.0s after the initial 2.0s. Now we can find its speed using the kinematic equation:

v = v0 + at

Where:

v0 = final velocity from before (15m/s)

a = acceleration due to gravity (-9.8m/s^2)

t = time (3.0s)

Plugging in the values, we get:

v = 15m/s - 9.8m/s^2 (3.0s)

v = -12.6m/s

Note that the velocity is negative because the rock is now moving downward. Therefore, the speed of the rock 5.0s after launch is approximately 12.6m/s.