A box-and-whisker plot titled Move length in minutes is shown. The number line goes from 80 to 400 in increments of 10. The whiskers range from 81 to 138, and the box ranges from 95 to 128. A line divides the box at 108. Describe the shape of the graph. Although the mean cannot be determined from the graph, can an approximation of the mean be determined? Explain.

Step-by-step explanation:

so it starts with

182 = 182 × 3 / p

as the price is inversely related to D.

(a)

so, in general

D = 182 × 3/p = 546/p

(b)

D = 546/3.25 = 168 bags

if the price increases to $3.25, then they will sell only 168 bags.

I am sure, the function will not stay linear for every value of p. for example, if they increase the price to $546 per bag, they would still sell 1 bag. but I am certain, they would fall to 0 sold bags much, much earlier than that ...

Answer:

Area of circle = pie r²

= 3.14 × 2.25

=7.065

Answer: 7.07cm²

Step-by-step explanation: diameter=3

radius=d/2

          =3/2

          =1.5cm

area=πr²

       =22/7 x 1.5 x 1.5

       =22/7 x 2.25

       =99/2 ÷ 7

       =99/2 x 1/7

       =99/14

Answer:

120 Miles

Step-by-step explanation:

60 miles x 2 hours = 120 miles

Answer:

\(120\)

Step-by-step explanation:

If you've driven 60 mile per hour, you'll have to find how many miles you can drive in two hours. To find this, you will have to multiply the miles by 2 hours. You can also add 60 miles with another 60 miles to find your answer.

\(60*2=120\)

\(60+60=120\)

So you've driven 120 miles per hour.

Answer:

540 Mies per hour

Step-by-step explanation:

add 600 and 480 then divide by 2

Alyssa's average speed on the round trip is 540 Mies per hour.

We have given,

The speed of the jet Alyssa flew on from Boston to London was 480

mph.

On her return flight, the speed of the jet was 600 mph with a tail

wind.

\(average speed=\frac{a+b}{2}\)

a=inital speed

b=final speed

add 600 and 480 then divide by 2

That can be given by

\(=\frac{600+480}{2}\\\\=\frac{1080}{2}\\\\=540\)

Alyssa's average speed on the round trip is 540mph.

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B. 70

I took the test on Edge 2022

Answer:

20\(c^{6}\)

Step-by-step explanation:

using the rule of exponents

\(a^{m}\) × \(a^{n}\) = \(a^{(m+n)}\)

given

(- 4c³)(- 5c³) ← remove parenthesis

= - 4 × c³ × - 5 × c³

= - 4 × - 5 × c³ × c³

= 20 × \(c^{(3+3)}\)

= 20\(c^{6}\)

Answer:

x=-11

Step-by-step explanation:

YOU WILL MAINTAIN THE X AT WHERE IS IT AND WILL BRING EQUAL SIGN AFTER THE EQUAL SIGN BRING -3 -8 AND IT WILL GIVE YOU -11 BECAUSE HAVING TWO NEGATIVE SIGNS CAN BE ADD TOGETHER.

FOR A EXAMPLE YOU OWN SOMEONE 3 APPLES AND YOU HAVE GO AND COLLECT ADDITIONAL 8 SO IT WILL BE ADDED AND YOU WILL OWN -11

Answer:

lesser x = - 1 , greater x = 1

Step-by-step explanation:

- 4x² - 7 = - 11 ( add 7 to both sides )

- 4x² = - 4 ( divide both sides by - 4 )

x² = 1 ( take square root of both sides )

x = ± \(\sqrt{1}\) = ± 1

then

lesser x = - 1

greater x = 1

Answer:

63 1/4°f - 2 1/5°f = 61 1/20°f

Step-by-step explanation:

The expression that describes all of the values for which the graph is positive and decreasing is all real values of x where x < -1

The equation of the function is given as:

f(x) = (x - 3)(x + 1)

When the value of the graph is positive, we have:

f(x) > 0

So, the function becomes

(x - 3)(x + 1) > 0

Split the above inequality

x - 3 > 0 and x + 1 > 0

Solve for x in the inequalities

x > 3 and x > -1

Hence, the expression that describes all of the values for which the graph is positive and decreasing is all real values of x where x < -1

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Answer:

455 to 464

Step-by-step explanation:

Answer: 1560

Step-by-step explanation: The average rate of change of a function over an interval is the total change in the value of the function divided by the length of the interval. In this case, the function is f(x) = 10(2)^x and the interval is [3, 5].

To find the average rate of change of the function over the interval, we can first evaluate the function at the two endpoints of the interval, which are x = 3 and x = 5. At x = 3, the function has a value of f(3) = 10(2)^3 = 80. At x = 5, the function has a value of f(5) = 10(2)^5 = 3200.

The total change in the value of the function over the interval is then the difference between the values at the two endpoints, which is f(5) - f(3) = 3200 - 80 = 3120.

The length of the interval is 5 - 3 = 2, since it goes from x = 3 to x = 5. Therefore, the average rate of change of the function over the interval is the total change in the value of the function divided by the length of the interval, which is (3120) / 2 = 1560.

Therefore, the average rate of change of the function f(x) = 10(2)^x on the interval [3, 5] is 1560.

Hello there. To solve this simultaneous equation, we'll have to remember some properties about logarithms.

Given the equations:

First, we'll transform those ones into logarithms applying the following rule in reverse:

Thus, we get:

For the first equation; Now, apply the power and product rules in reverse:

In order to obtain:

Since both logarithms have the same base, the expressions inside them must be equal as well, therefore:

Now, going for the second equation, we'll apply the same three rules as before:

The thing is that we can plug in 6x as y², found on the first equation, to get a quadratic equation for y:

Subtract 15y-25 on both sides of the equation

Using the quadratic formula, we take the roots of the equation:

So we have two possible roots:

y = (15 - 5)/4 = 10/4 = 5/2 or y = (15 + 5)/4 = 20/4 = 5.

Plugging in this value in the first equation, we solve for x:

Or

The pair of solutions are:

You can plug this into any of the equations and see if they truly satisfy them as an exercise.

Answer:

Step-by-step explanation:

-1/3 + 9/5

-3/15 + 27/15

24/15 = 8/5 = 1 3/5

Answer:

The company charged $500 for its services,and Mia gives the movers a 16% tip. Now, we can add the tip amount to the cost of the service to find the total amount Mia paid: Total amount = Cost of service + Tip amount = $500 + $80 = $580

Step-by-step explanation:

Answer:

wheres the graph?

Step-by-step explanation:

Answer:

The last graph on edge 2021

Step-by-step explanation:

The length of the rectangular garden given the area and width is 8/7 miles

A rectangle is a form of quadrilateral having opposing sides parallel and four right angles. The area of a rectangle can be calculated by multiplying the length by width.

Area of a rectangular garden = length × width

16 = x × 14

16 = 14x

x = 16 / 14

x = 8/7 miles

Therefore, the length of the rectangular garden given the area and width is 8/7 miles.

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Answer: $400

Step-by-step explanation:

Discount = 15%

The original price/value of an item is always 100%

So selling price (%) = original price - discount = 100%-15% = 85%

We got selling price as 85%

This implies that 85% = 340

Let's find 1% first, then 100%

1% = 340÷85 = 4

100% = 4 × 100 = $400

The usual (normal/original) price is $400

Juan sold a bicycle at a discount of 15% if the selling price was $340 then the usual price of the bicycle was $400.

percentage, a relative value indicating hundredth parts of any quantity.

Let's represent the usual price of the bicycle by P.

Since Juan sold the bicycle at a discount of 15%, the selling price (S) would be 85% of the usual price (P).

We can express this relationship as an equation:

S = 0.85P

We also know that the selling price of the bicycle was $340.

Substituting S = $340 into the equation above, we get:

$340 = 0.85P

To find P, we can solve for it:

P = $340 / 0.85

P = $400

Therefore, the usual price of the bicycle was $400.

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Answer:

\(x = 6\)

Carl is correct

Step-by-step explanation:

Given

\(\frac{6}{3} = \frac{12}{x}\)

See attachment

Required

Is Carl correct?

Using the side spotter theorem, the proportion is:

\(\frac{AB}{BC} = \frac{AE}{ED}\)

This gives:

\(\frac{6}{3} = \frac{12}{x}\)

This proportion is equivalent to Carl's.

Hence, Carl is correct.

Solving further: Cross Multiply

\(6 * x = 12 * 3\)

\(6 * x = 36\)

Make x the subject

\(x = \frac{36}{6}\)

\(x = 6\)

The remaining Kit volume in the syringe is sufficient to correct the dose to 20 mCi.

To solve this problem, we can use the concept of radioactive decay and the decay factor. Here's how we can calculate the required volume to correct the dose:

Determine the initial activity of the kit:

Initial activity = 180 mCi

Calculate the decayed activity at 9:30 (after 1.5 hours):

Decay factor = 0.841

Decay activity = Initial activity * Decay factor

Calculate the remaining activity after withdrawing 20 mCi at 8 am:

Remaining activity = Initial activity - 20 mCi

Calculate the remaining activity at 9:30:

Remaining activity at 9:30 = Remaining activity * Decay factor

Calculate the desired activity at 9:30 (20 mCi):

Desired activity at 9:30 = 20 mCi

Calculate the volume needed to achieve the desired activity:

Volume needed = Desired activity at 9:30 / Remaining activity at 9:30 * Volume at 9:30

Calculate the remaining volume at 9:30:

Remaining volume = Volume at 8 am - Volume withdrawn - Volume accidentally discharged

Calculate the volume that needs to be added:

Volume to be added = Volume needed - Remaining volume

Let's perform the calculations step by step:

Determine the initial activity of the kit:

Initial activity = 180 mCi

Calculate the decayed activity at 9:30 (after 1.5 hours):

Decay factor = 0.841

Decay activity = 180 mCi * 0.841 = 151.38 mCi

Calculate the remaining activity after withdrawing 20 mCi at 8 am:

Remaining activity = 180 mCi - 20 mCi = 160 mCi

Calculate the remaining activity at 9:30:

Remaining activity at 9:30 = 160 mCi * 0.841 = 134.56 mCi

Calculate the desired activity at 9:30 (20 mCi):

Desired activity at 9:30 = 20 mCi

Calculate the volume needed to achieve the desired activity:

Volume needed = (Desired activity at 9:30 / Remaining activity at 9:30) * Volume at 9:30

Volume at 9:30 = Remaining volume = 30 ml - (30 ml / 2) = 15 ml

Volume needed = (20 mCi / 134.56 mCi) * 15 ml = 2.236 ml

Calculate the remaining volume at 9:30:

Remaining volume = 30 ml - (30 ml / 2) = 15 ml

Calculate the volume that needs to be added:

Volume to be added = Volume needed - Remaining volume = 2.236 ml - 15 ml = -12.764 ml

Since the calculated volume to be added is negative, it means that no additional volume is required. The remaining Kit volume in the syringe is sufficient to correct the dose to 20 mCi.

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The solutions to the questions are

The area of a shape is the amount of space on the shape

For most regular quadrilaterals, you multiply the side lengths to determine the area

The area expression is given as

Area = ▢ × 102 + ▢ × 101 + 6

From the question, we can use any number

However, this number must be positive

Assume the number is 5

So, we have

Area = 5 × 102 + 5 × 101 + 6

In (a), we have:

Area = 5 × 102 + 5 × 101 + 6

Evaluate

Area = 1021

The perfect square number closest to this is

Closest = 1024

In (b), we have

Closest = 1024

Rewrite as

Area = 1024

Take the square roots

Length = 32

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The extremas of the function f(x) = x³ - 7x² + 10x are given as follows:

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The image coordinates of K′ if the preimage is reflected across y = −7 is (-4, -8)

Based on the given question, we have certain variables that can be utilized for our calculations.

K = (-4, -6)

First, find the equation of the reflection line

The reflection line is y = -7.

This can be expressed as

y = a = -7

The image of the reflection is then calculated as

K' = (x, -(y + 2|a|))

Replace the given or established values in the equation mentioned earlier, resulting in the following expression

K' = (-4, -(-6 + 2 * 7))

Evaluate

K' = (-4, -8)

Hence, the image coordinates of K′ are (-4, -8).

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Answer:

14739

Step-by-step explanation:

1/2mv^2

1/2*105*17*17

=14739

The end behavior of the polynomials are as follows;

(a) y = x³ - 9·x² + 8·x - 14

End behavior; y → ∞ as x → ∞

\({}\)                        y → -∞ as x → -∞

(b) y = -8·x⁴ + 13·x + 800

End behavior; y → -∞ as x → -∞

\({}\)                        y → -∞ as x → ∞

The end behavior of a polynomial is the characteristics of the graph of the polynomial as the input (x-values), tends to plus and minus infinity.

The factors that effect the end behavior of a polynomial are;

The degree of the polynomial, (even or odd)

The sign of the leading coefficient of the polynomial (positive or negative)

The leading coefficient is the coefficient of the term with the highest degree.

(a) The polynomial, function, y = x³ - 9·x² + 8·x  - 14

The specified polynomial is a third degree polynomial, with a positive leading coefficient of 1, the end behavior is therefore;

y tends to positive infinity as x tends to positive infinity

y tends to negative infinity as x tends to negative infinity

End behavior;

y → ∞ as x → ∞

y → -∞ as x → -∞

(b) The polynomial function can be expressed as follows;

y = -8·x⁴ + 13·x + 800

The above polynomial of degree 4 is an even degree polynomial

The leading coefficient of the polynomial is -8, therefore, the leading coefficient is negative

The shape of the graph of the polynomial is therefore ∩ shaped, such that the end behavior is as follows;

y-values approaches negative infinity as x approaches negative infinity

y-values approaches negative infinity as x approaches positive infinity

End behavior;

y → -∞ as x → -∞

y → -∞ as x → ∞

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Answer:

C

Step-by-step explanation:

I think it would be easiest to see these numbers in decimal form to determine which number is the greatest and which is the smallest.

2 as a decimal=2.0

Square root of 7 as a decimal= 2.64575131106

1/3 as a decimal= 0.3333333333333333333333333333333333333333333...

So, 0.3333333...<2.0<2.64575131106

or 1/3, 2, square root of 7

Answer is C

Answer:

The value is \(t_{\frac{\alpha }{2} , 21 } =  2.518\)

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  22

Generally the degree of freedom is mathematically represented as

       \(df = n- 1\)

=>    \(df = 22- 1\)

=>    \(df = 21\)

From the question we are told the confidence level is  98% , hence the level of significance is    

      \(\alpha = (100 - 98 ) \%\)

=>   \(\alpha = 0.02\)

Generally from the t distribution table the critical value  of  \(\frac{\alpha }{2}\)  at a degree of freedom of \(df = 21\)  is  

   \(t_{\frac{\alpha }{2} , 21 } =  2.518\)

The graph could be the graph of exponential function of option b)

\(F(x) = 2 • (0.5)^{x} \)

The general form of an exponential function is

\(f(x) = {ab}^{x} \)

Here, a is the function's starting value and b is its growth factor.

F(x) is an increasing function if b > 1, and if b<1, then f(x) is a decreasing function

The function's initial value is 2 as can be seen from the provided graph. Therefore, a has a value of 2.

Given that the graph indicates that the function is decreasing, b must be less than 1.

It indicates that the necessary function is in the form of

\(f(x) = 2(b)^{x} \)

Where it is b<1

By checking option B, b=0.5<1. Hence, option B is the correct answer

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Note that the full question is:

(check the attached image)

Answer:

6561

Step-by-step explanation:

Answer:

6561 is the answer.

Step-by-step explanation:

-9^4

= -9×-9×-9×-9

= 6561