A bug slides back and forth in a bowl 12 cm deep, starting from rest at the top, as shown in Fig. 7.20. The bowl is frictionless except for a 1.8-cm-wide sticky patch on its flat bottom, where the coefficient of friction is 0.83. How many times does the bug cross the sticky region?

24 volts is the voltage drop across each of the resistors in the parallel configuration.

When resistors are connected in parallel, they share the same voltage across them. Therefore, the voltage drop across each resistor in this scenario would be the same.

Given:

Power supply voltage (V) = 12 V

Resistance of each resistor (R) = 30 Ω

Since the resistors are in parallel, the total resistance (R_total) can be calculated using the formula:

1/R_total = 1/R1 + 1/R2

Substituting the values:

1/R_total = 1/30 Ω + 1/30 Ω

1/R_total = 2/30 Ω

R_total = 15 Ω

Now, we can find the current flowing through the resistors (I) using Ohm's Law:

I = V / R_total

I = 12 V / 15 Ω

I = 0.8 A

Since the voltage drop across each resistor is the same, we can find it using Ohm's Law:

V_drop = I * R

V_drop = 0.8 A * 30 Ω

V_drop = 24 V

Therefore, the voltage drop across each of the resistors in the parallel configuration is 24 volts.

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Answer:

To solve this problem, you'll need to break the initial velocity of the seed into its horizontal and vertical components, then use the equations of motion to find the time of flight and horizontal distance.

The initial velocity (v) of the seed is 2.65 m/s. The angle it's launched at (θ) is 30.0 degrees below the horizontal. The height (h) it's launched from is 0.460 m.

First, calculate the horizontal (v_x) and vertical (v_y) components of the velocity. Because the seed is launched downward, the vertical component will be negative:

v_x = v * cos(θ) = 2.65 m/s * cos(30.0) = 2.29 m/s

v_y = v * sin(θ) = -2.65 m/s * sin(30.0) = -1.325 m/s

Next, use the equation of motion to find the time it takes for the seed to hit the ground:

h = v_y * t + 0.5 * g * t^2

Where g is the acceleration due to gravity, which is approximately 9.8 m/s². Solving the equation for t gives:

t = (-v_y - sqrt((v_y)^2 - 4 * 0.5 * g * (-h))) / (2 * 0.5 * g)

Plugging in the values:

t = (1.325 + sqrt((-1.325)^2 - 4 * 0.5 * 9.8 * (-0.460))) / (2 * 0.5 * 9.8)

t = 0.182 seconds

Finally, use the horizontal velocity and time of flight to find the horizontal distance the seed covers:

x = v_x * t = 2.29 m/s * 0.182 s = 0.417 m

So, the seed lands after approximately 0.182 seconds and travels approximately 0.417 meters horizontally.

Answer:

Here is your answer,thanks for using brainly!

Explanation:

B:Molecule

Molecules usually consist of 2 atoms linked together,however some molecules  consist of thousands of atoms!

Here is a list of smalles to largest with the answers provided

Molecules

Atoms

Elements

Mixtures

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Given:

The mass of the object, m=3.9 kg

To find:

The work done by gravity.

Explanation:

The work done by gravity does not depend on the path in which the object is brought from point A to point B. The work done depends only on the height difference between point A and point B.

From the figure, the height difference between point A and point B is h=2 m

The work done by the gravity when the object is moved from point A to point B is given by,

Where g is the acceleration due to gravity.

On substituting the known values,

Final answer:

The work done by the gravity on the object is 76 J.

The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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A microscope's objective lens has a focal length of 4 cm, whereas the eye lens's focal length is 8 cm. if 24 cm is the minimum distance at which a person can see clearly,

When an object is magnified, it appears in a microscope image at a scale bigger than its true size. Only when it is able to see more specifics of an item in the photograph than when studying the thing without the use of a magnifying glass does magnification serve a beneficial purpose.

Scanning objective lenses typically have a magnification of 4x, and when paired with a 10x eyepiece lens, they have a total magnification of 40x.

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Answer:

My answer to the question is "when its displacement is zero.

The man's friend is at a distance 552.5 m away.

Speed of sound in air, v = 340 m/s

Time after which the echo is heard, t = 3.25 s

The expression for the total distance covered by the sound in the given time,

d = v x t

d = 340 x 3.25

d = 1105 m

Therefore, the distance where the friend is staying would be half of the total distance covered by the sound during the given time.

So, the distance of the friend from the man,

d' = d/2

d' = 1105/2

d' = 552.5 m

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Answer:

The height of the  object is 5007.4 miles.

Explanation:

Given that,

Weight of object = 200 lb

We need to calculate the value of \(Gmm_{e}\)

Using formula of gravitational force

\(F=\dfrac{Gmm_{e}}{r^2}\)

Put the value into the formula

\(200=\dfrac{Gmm_{e}}{(3958.756)^2}\)

\(200\times(3958.756)^2=Gmm_{e}\)

\(Gmm_{e}=3.134\times10^{9}\)

We need to calculate the height of the  object

Using formula of gravitational force

\(F=\dfrac{Gmm_{e}}{r^2}\)

Put the value into the formula

\(125=\dfrac{200\times(3958.756)^2}{r^2}\)

\(r^2=\dfrac{200\times(3958.756)^2}{125}\)

\(r^2=25074798.5\)

\(r=\sqrt{25074798.5}\)

\(r=5007.4\ miles\)

Hence. The height of the  object is 5007.4 miles.

Answer:

Potential energy =mass* acceleration due to gravity * height

mass*acceleration due to gravity =weight

hence potential energy of the puppy= weight * height

=18*2

=36 joule

The current theory about the formation of the solar system is that it began as a cloud of dust and gas, known as the solar nebula which is the last response.

The nebula collapsed under its own gravity, forming a spinning disk with a bulging middle that became the sun. The remaining dust and gas in the disk coalesced into small bodies, which collided and stuck together, forming the planets.

This process, known as accretion, resulted in the four inner planets, which are small and rocky, and the four outer planets, which are large and gas-rich.

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Answer:

Potential Energy = x = m g h

Kinetic energy = 1/2 m v^2

Assuming the mass fall from rest

1/2 m v^2 = m g h

v^2 = 2 g h

So the speed attained is independent of the mass

Also, x / v   does not have the units of mass

So the solution is none of the above.

Answer:

Required energy Q = 231 J

Explanation:

Given:

Specific heat of copper C = 0.385 J/g°C

Mass m = 20 g

ΔT = (50 - 20)°C = 30 °C

Find:

Required energy

Computation:

Q = mCΔT

Q = 20(0.385)(30)

Required energy Q = 231 J

Answer:

3.0 x 10 and the exponent on ten is 5.

Explanation:

You are moving the decimal point over to the left 5 times, making the exponent a positive 5 and then you would put a decimal after 3. Making it 3.0 x 10, and the exponent 5.

The speed of x-rays in scientific notation is 3.0 x 10⁶ m/s.

The given parameters;

speed of the x-ray, v = 300,000 m/s

The standard form of the given number represents the scientific notation of the number.

In scientific notation the speed of the x-ray can be expressed as follows;

300,000 m/s = 3.0 x 10⁶ m/s

Thus, the speed of x-rays in scientific notation is 3.0 x 10⁶ m/s.

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Answer:

work done= force × displacement

=800×5

=4000J

Explanation:

The amount of work done is the result of the magnitude of force applied and the displacement of the body due to the force applied. Therefore, work done is defined as the product of the applied force and the displacement of the body.

Answer:

Velocity of the two balls after collision: \(60\; \rm m \cdot s^{-1}\).

\(100\; \rm J\) of kinetic energy would be lost.

Explanation:

Because the question asked about energy, convert all units to standard units to keep the calculation simple:

The two balls stick to each other after the collision. In other words, this collision is a perfectly inelastic collision. Kinetic energy will not be conserved. The velocity of the two balls after the collision can only be found using the conservation of momentum.

Assume that the system of the two balls is isolated. Thus, the sum of the momentum of the two balls will stay the same before and after the collision.

The momentum of an object of mass \(m\) and velocity \(v\) is: \(p = m \cdot v\).

Momentum of the two balls before collision:

Based on the assumptions, the sum of the momentum of the two balls after collision should also be \(30\; \rm kg \cdot m \cdot s^{-1}\). The mass of the two balls, combined, is \(0.1\; \rm kg + 0.4\; \rm kg = 0.5\; \rm kg\). Let the velocity of the two balls after the collision \(v\; \rm m \cdot s^{-1}\). (There's only one velocity because the collision had sticked the two balls to each other.)

These two values are supposed to describe the same quantity: the sum of the momentum of the two balls after the collision. They should be equal to each other. That gives the equation about \(v\):

\(0.5\, v = 30\).

\(v = 60\).

In other words, the velocity of the two balls right after the collision should be \(60\; \rm m \cdot s^{-1}\).

The kinetic energy of an object of mass \(m\) and velocity \(v\) is \(\displaystyle \frac{1}{2}\, m \cdot v^{2}\).

Kinetic energy before the collision:

The two balls stick to each other after the collision. Therefore, consider them as a single object when calculating the sum of their kinetic energies.

Sum of the kinetic energies of the two balls right after the collision:

\(\displaystyle \frac{1}{2} \, m \cdot v^{2} = \frac{1}{2}\times 0.5\; \rm kg \times \left(60\; \rm m \cdot s^{-1}\right)^2 = 900\; \rm J\).

Therefore, \(1000\; \rm J - 900\; \rm J = 100\; \rm J\) of kinetic energy would be lost during this collision.

Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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I do not see a pick an awsnser bAr

Answer:

25 m

Explanation:

Let's assume that its acceleration is constant. We can determine the acceleration of the object by its definition

\(a= \frac{\Delta v}{\Delta t} = \frac{10-0(\frac ms)}{5 s} = 2 \frac m{s^2}\)

Now we can write the equation of motion

\(s(t)= s_0 + v_0t + \frac12at^2\)

where, the two terms \(s_0\ v_0\) represent the initial position and velocity respectively. Replacing the values we have ("from rest" means that initial velocity is 0)

\(s(5) = 0+0(5)+\frac12 2 (5)^2 = 25 m\)

Answer:

(A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

Explanation:

Given that,

Mass of marble = 0.0073 kg

Speed = 0.65 m/s

(A). We need to calculate the magnitude of the momentum of the marble

Using formula of momentum

\(p = mv\)

Where, m = mass

v = velocity

Put the value into the formula

\(p=0.0073\times0.65\)

\(p=0.004745\ kg m/s\)

(B). Mass of baseball = 0.136 kg

Momentum of baseball = 3.14 kg m/s

We need to calculate the speed of baseball

Using formula of momentum

\(p=mv\)

\(v=\dfrac{p}{m}\)

Put the value into the formula

\(v=\dfrac{3.14}{0.136}\)

\(v=23.0\ m/s\)

Hence, (A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

This statement is correct. In order to determine the boiling point of a liquid, the thermometer bulb should be positioned in the vapor above the liquid, not in the liquid itself.

When a liquid is heated to its boiling point, the temperature of the liquid will remain constant until all the liquid has turned into vapor. At this temperature, the vapor pressure of the liquid is equal to the atmospheric pressure, causing the liquid to boil. By positioning the thermometer bulb in the vapor above the liquid, it will accurately measure the temperature of the liquid at its boiling point. the boiling point of any liquid is the temperature at which the liquid starts to boiling. If the thermometer bulb were positioned in the liquid, it would measure the temperature of the liquid before it reaches its boiling point, giving an incorrect reading.

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in this experiment, the thermometer bulb should be positioned in the vapor and not in the liquid to determine the boiling point of your liquid. is this statement correct?

At room temperature,300 K, will a miscibility limit emerge. At the temperature less than, the miscibility will fall below 1%.

Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.

Hence, at room temperature,300 K, will a miscibility limit emerge. At the temperature less than, the miscibility will fall below 1%.

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Answer:

from my side the will be b only the mass of the planet thank you

Answer:

D

Explanation:

W=mg

g=GM/r²(G=Gravitational constant, M=mass of earth, r=Radius of earth)

>>W=m(GM/r²)

W is directly proportional to mass of earth and mass of your body

Answer:

a = 1 m/s^2

Explanation:

if we assume that right is the positive x direction and y is the negative x-direction then we get:

Fr = 8N

Fl = -3N

We then find the net force acting upon the object

Ft = Fr + Fl

Ft = 8N - 3N

Ft = 5N

After we find net force acting upon the object we can then use Newton's 2nd Law to find its acceleration.

Ft = m*a

Isolate accerleration

a = Ft / m

a = 5N / 5kg

a = 1 m/s^2

The force that acts on a projectile in the horizontal direction is Gravitational force.

A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.

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Answer:

Freddy is participating in a pumpkin lifting contest. The 68 kg pumpkin starts at rest on the ground. If Freddy exerts a 720N force on the pumpkin, what is the acceleration of the pumpkin as he lifts it off the ground?

Explanation:

Internal energy is the microscopic energy contained in a substance, given by the random, disordered kinetic energy of the molecules. Internal energy is the sum of potential energy of the system and the system's kinetic energy.

This implies that kinetic energy—the energy that results from the system's overall movement—is not included in the internal energy of the system if the system is moving and contains kinetic energy. The system's internal energy is unaffected by this macroscopic potential energy even if we raise the entire structure above the earth. On the one hand, a system can be moving while its internal energy is changing, while on the other hand, a system can be perfectly static and have no apparent energy while its internal energy is changing.

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Going down the first ramp:

• net force parallel to the ramp:

∑ F = W sin(60°) = m a₁

(W for weight)

• net force perpendicular to the ramp:

∑ F = N + W cos(60°) = 0

(N for normal force)

The body has mass 0.1 kg, and with g = 10 m/s², its weight is W = 1 N. So in the first equation, we get

(1 N) sin(60°) = (0.1 kg) a₁   →   a₁ ≈ 8.7 m/s²

Let d₁ be the distance the body moves down the ramp, i.e. the distance along the ramp between the starting point and the point O. Then

sin(60°) = h / d₁   →   d₁ = 2h/√(3) ≈ 1.15h

Given an initial speed v₁ = 3 m/s, we find the speed v₂ at point O to be

v₂² - (3 m/s)² = 2 (8.7 m/s²) d₁

v₂ ≈ √(9 m²/s² + (17.4 m/s²) (1.15h))

v₂ ≈ √(9 m²/s² + (20 m/s²) h)

Going up the second ramp:

• net parallel force:

∑ F = -Fr - W sin(30°) = m a₂

(Fr for friction)

• net perpendicular force:

∑ F = N - W cos(30°) = 0

sin(30°) = cos(60°), and cos(30°) = sin(60°), so the second equation gives N = 0.87 N. Then with µ = 0.1, we have Fr = µ N = 0.087 N. The first equation then gives

-0.087 N - 0.5 N = (0.1 kg) a₂   →   a₂ ≈ -5.9 m/s²

We now have

tan(30°) = h/R   →   h = (2.5 m)/√3 ≈ 1.4 m

(which, by the way, tells us that v₂ ≈ 6.2 m/s)

Then the distance traveled up the ramp is

d₂ = √(h² + R ²) ≈ 2.9 m

Use this to solve for the speed at the top of the ramp:

v₃² - v₂² = 2 (-5.9 m/s²) d₂

v₃ = √((6.2 m/s)² - (11.8 m/s²) (2.9 m)) ≈ 2.0 m/s

At the top of the second ramp:

• net parallel force:

∑ F = -Fsp - W sin(30°) = m a₂

(Fsp for spring)

• net perpendicular force:

∑ F = N - W cos(30°) = 0

By Hooke's law, Fsp = kx, so in the first equation we get

-k (0.10 m) - (1 N) cos(60°) = (0.1 kg) (-5.9 m/s²)

→   k ≈ 0.87 N/m

If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.

Option A is correct.

impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.

If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.

Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.

As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.

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