Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
What type of tv uses a VfL for backlighting
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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an electric train moving at 5m/s accelerates to a speed of 8m/s in 20 seconds. Fine the distance travelled in meters during the period of acceleration
===================================================
Explanation:
vi = 5 and vf = 8 are the initial and final velocities respectively. The change in time is t = 20 seconds.
So,
x = 0.5*(vi + vf)*t
x = 0.5*(5+8)*20
x = 130 meters
represents the distance traveled. The first equation shown above is one of the four kinematics equations.
Potassium-40 has a half-life of approximately 1.25 billion years. Approximately how many years will pass before a sample of potassium-40 contains one-eighth the original amount of parent isotope?
Answer:
3.75 billion years
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 1.25 billion years
Number of half-lives (n) = 3
Time (t) =?
The time taken for the sample of potassium-40 to contains one-eighth the original amount of parent isotope can be obtained as:
n = t / t½
3 = t / 1.25
Cross multiply
t = 3 × 1.25
t = 3.75 billion years.
Therefore, it will take 3.75 billion years for the sample of potassium-40 to contains one-eighth the original amount of parent isotope
1) You and some friends are enjoying a trip to the water park on a hot summer day! Upon arrival, you decide you want to try the fastest (and scariest) water slide they have. To ride this water slide, a rider stands on a retractable floor and leans up against an almost vertical portion of water slide, that makes an angle of approximately 84° with the horizontal. The operatorpresses a button, the floor is retracted, and riders slide straight at that angle for approximately 6.3 meters until they are dropped into the twisting turning water slide. You (m= 62 kg) start at the top from rest. If the coefficient of kinetic friction between you and the slide is 0.12, how fast are you moving at the end of the straight portion of the slide? (Hint: set the y=0 level tothe bottom of the straight portion of the slide!)
ANSWER
11.02 m/s
EXPLANATION
Given:
• Your mass, m = 62 kg
,• Your initial velocity, u = 0 (you start from rest at the top)
,• The coefficient of kinetic friction between you and the slide, μk = 0.12
,• The angle between the slide and the horizontal, θ = 84°
,• The length of the slide, d = 6.3 m
Let's make a diagram of the description of the slide given,
First, we can find what is your gravitational potential energy just before the floor is retracted,
\(PE=mgh\)We can find the vertical height of the slide using the right triangle formed,
\(\sin\theta=\frac{h}{d}\Rightarrow h=d\sin\theta=6.3m\cdot\sin84\degree\approx6.27m\)So your gravitational potential energy is,
\(PE=62kg\cdot\cdot9.8m/s^2\cdot6.27m=3809.65J\)If there was no friction between you and the slide, this energy would be conserved and it would be equal to your kinetic energy when you reach the bottom of the straight portion of the slide. However, there is indeed friction, so some of this energy will be lost to the work done by the kinetic frictional force.
To find the mentioned work, we have to draw a force diagram of you sliding down the slide and find the kinetic frictional force,
By Newton's second law,
\(F_N-F_{gy}=0\)Using trigonometry, we have that the weight in the y-direction is,
\(F_N=F_{gy}=F_g\cos\theta=mg\cos\theta\)So, the frictional force is,
\(F_f=\mu_k\cdot F_N=\mu_k\cdot m\cdot g\cdot\cos\theta=0.12\cdot62kg\cdot9.8m/s^2\cdot\cos84\degree\approx7.62N\)And this force acts for a distance of 6.3 meters, so the work it does on the person sliding down the slide is,
\(W=F_f\cdot d=7.62N\cdot6.3m=48.01J\)This is the energy lost to friction, so the kinetic energy you will have at the end of the straight portion of the slide is,
\(KE=PE-W=3809.65J-48.01J=3761.64J\)This kinetic energy is equal to,
\(KE=\frac{1}{2}mv^2\)Solving for v,
\(v=\sqrt{\frac{2KE}{m}}=\sqrt{\frac{2\cdot3761.64J}{62kg}}\approx11.02m/s\)Hence, your speed at the end of the straight portion of the slide is 11.02 m/s, rounded to two decimal places.
a ball is thrown straight up into the air with an initial speed of 3.1 m/s. a. After 0.24 seconds what is the ball's velocity and b. what is it's acceleration?
a. The ball's velocity after 0.24 s is 0.75 m/s
b. The acceleration of the ball is given by the acceleration due to gravity
a. The ball's velocity can be calculated with the following equation:
\( v_{f} = v_{0} - gt \)
Where:
\( v_{f} \): is the final speed =?
\(v_{0}\): is the initial speed = 3.1 m/s
g: is the acceleration due to gravity = 9.81 m/s²
t: is the time = 0.24 s
The minus sign is because the acceleration is in the opposite direction (downward) of the motion of the ball (upward).
The final speed is:
\( v_{f} = v_{0} - gt = 3.1 m/s - 9.81 m/s^{2}*0.24 s = 0.75 m/s \)
Hence, the ball's velocity after 0.24 s is 0.75 m/s.
b. The acceleration of the ball is given by the acceleration due to gravity because the ball is thrown straight up (the motion of the ball is in the y-direction). The velocity of the ball in the x-direction is zero so the acceleration in the same direction is also zero.
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PLEASE HELP
Which of the following is an example of a chemical reaction?
hydrogen peroxide and yeast are combined, producing lots of bubbles and heat
atoms of silver are bonded together to make a silver nugget
heat is applied to melt chocolate chips
red and blue paints are mixed to make purple paint
Warm air rises because faster moving molecules tend to move to regions of less
A) density.
B) pressure.
C) both of these
D) none of the above
Answer:
76rsfy7zfyuutfzufyztudzutdT7dFy9y8fr6s
Explanation:
rshyyjfshfsgfshfsyhrsyhuydtufhr6ra6yris7toe7r9w7rr6w996ryrowosotusuogsuoufsutot
8. When wind dies down or stops blowing
happens.
Answer:
Deposition
Explanation:
Deposition occurs when water slows or ceases moving, the wind dies or stops blowing, or glaciers melt. The deposited material can also be used to construct new landforms. Waves, for example, can dump sediment in places offshore, where it might accumulate to form sand dunes.When the wind calms down or vegetation stops or slows the breeze, the sediment particles begin to fall. Water is another factor that may erode, move, or deposit sediment. Flowing water is a key erosive agent. Water transports dirt and rock fragments as it moves. Warm, wet air will not travel if wind systems are not present. Water will still evaporate, but it will not move, therefore everywhere else than a major body of water will dry up. Lakes may be fine since evaporating water will flow back into them, and the sea will be fine, but everywhere else will become extremely dry very rapidly. Wind is constantly blowing somewhere on the world at any given time. Winds are usually quiet near the middle of a high pressure system. Wind is the passage of air from a high pressure location to a low pressure area.... So essentially air is always moving. Weathering and erosion are caused by wind. Weathering is caused by wind blowing debris against cliffs and huge rocks. This wears down the rock, reducing it to sand and dust. Sand and dust are also eroded by wind. 2. Rocks are tough and durable, but they don't last forever. Weathering and erosion are processes that occur as a result of forces such as wind and water breaking down rocks. Weathering is the process through which rocks deteriorate. Weathering is caused by a variety of factors, including climate change.
Deposition occurs when wind dies down or stops blowing happens.
What is deposition?Deposition refers to the depositing of sediment carried by wind, flowing water, the sea, or ice. Sediment can be carried in the form of pebbles, sand, and mud, or as salts dissolved in water. Organic activity may later deposit salts.
The fractured rock fragments or soil particles are accumulated in an environment where the energy of the flowing river is reduced. It settles the particles, which compact and form sedimentary rocks over time.
Deposition can occur when a river enters a shallow area of water or when the volume of water decreases, such as after a flood or during a drought. Deposition is common at the mouth of a river near the end of its journey.
Thus, the answer is deposition.
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An object which starts at the origin is traveling in the positive direction with a constant velocity V. After traveling a distance D with this constant velocity, the object begins to slow down at a constant rate until it stops after traveling an addition distance of 2D. In terms of D and V, determine the average velocity of the entire trip.
Answer:
Explanation:
time to travel first leg
D = Vt₁
t₁ = D/V
time to travel second leg.
at constant deceleration, the average velocity will be half of the original.
2D = (V/2)t₂
t₂ = 4D/V
t = t₁ + t₂ = 5D/V
Vavg = d/t = (D + 2D)/(5D/V) = (3D/5D)V = 0.6V
With the concept of kinematics we find the average speed is 0.6V
given parameters
* initial velocity V
* the distances in each part of the movements x₁ = D and x₂ = 2D
to find
The average speed of the entire trajectory
In kinematics we analyze the motion of bodies, the average velocity is defined by
\(V_{avg} = \frac{\Delta x}{\Delta t}\) 1
where \(V_{avg}\) is the average velocity, Δx and Δt are the variation of displacement and time in the interval
For this exercise we have two types of movement in the first part a uniform movement and in the second part an accelerated movement let's solve each onaccelerated movement,e separately
1 Part. uniform motion
we look for the time
V = \(\frac{x_1}{t_1}\)
t₁ = x₁ / V
t₁ = \(\frac{D}{V}\)
2 Part. Accelerated movement, let's start by looking for acceleration, they tell us that the body stops at the end of the interval so its velocity is zero v_f=0, the initial velocity is v₀ = V
\(v_f^2 = v_o^2 - 2 \ a \ x_2\)
0 = v₀² - 2 a x₂
a = \(\frac{v_o^2}{2x_2}\)
we substitute
a = \(\frac{V^2}{D}\)
now we look for the time it takes to stop
v = v₀ - a t₂
0 = v₀ - a t₂
t₂ = \(\frac{v_o}{a}\)
we substitute
t₂ = \(\frac{V}{\frac{V^2}{4D} }\)
t₂ = \(\frac{4D}{V}\)4D / V
for the entire movement, the total displacement is
Δx = x₁ + x₂
Δx = D + 2D
Δx = 3D
the total time is
Δt = t₁ + t₂
Δt = \(\frac{D}{V} + \frac{4D}{V}\)
Δt = \(\frac{5D}{V}\)
we substitute in equation 1 of average velocity
\(V_{avg} = \frac{3D}{\frac{5D}{V} }\)
\(V_{avg} = \frac{3}{5} \ V\)
\(V_{avg } = 0.6 V\)
With the use of the kinematics equations with constant acceleration we can find the average velocity of the body throughout the journey is 0.6V
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A 0.37 kg rock is thrown vertically upward from the top of a 37 m
cliff. When it hits the ground at the base of the cliff, the rock has a
speed of 33 m/s. Consider that air resistance is negligible. Use
conservation of total mechanical energy principle to find
a. The initial speed of the rock.
b. The greatest height of the rock as measured from the base of the
cliff.
c. Comment on the types of mechanical energy of the rock when
i) it is thrown upward, ii) it reached the maximum height, and
iii) it reached the base of the cliff.
(a) The initial speed of the rock is 19.1 m/s.
(b) The greatest height of the rock as measured from the base of the
cliff is 55.6 m.
(c) i. As the ball is thrown up, its kinetic energy is converted to potential energy.
ii. When then ball reaches the maximum height, its kinetic energy becomes zero and it will have maximum potential energy.
iii. When the rock reaches the base of the cliff, its potential energy becomes zero and it will have maximum kinetic energy.
Conservation of mechanical energyThe initial speed of the rock is determined by applying the principle of conservation of mechanical energy as shown below;
Ui + K.Ei = Uf + K.Ef
mghi + ¹/₂mvi² = mghf + ¹/₂mvf²
(0.37 x 9.8 x 37) + ¹/₂(0.37)vi² = (0.37 x 9.8 x 0) + ¹/₂(0.37 x 33)²
134.16 + 0.185vi² = 0 + 201.47
0.185vi² = 201.47 - 134.16
0.185vi² = 67.31
vi² = 67.31/0.185
vi² = 363.84
vi = √363.84
vi = 19.1 m/s
Height reached by the rock from top cliffvf² = vi² - 2gh
0 = vi² - 2gh
2gh = vi²
h = vi²/2g
h = (19.1)²/(2 x 9.8)
h = 18.6 m
Maximum height reached by rock from the base of the cliffThe maximum height from the base = 37 m + 18.6 m = 55.6 m
When the ball is thrown up, its kinetic energy is converted to potential energy.
When then ball reaches the maximum height, its kinetic energy becomes zero and it will have maximum potential energy.
When the rock reaches the base of the cliff, its potential energy becomes zero and it will have maximum kinetic energy.
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A train starts from rest and accelerates uniformly until it has traveled 7.1km and acquired a forward velocity of 36m/s. The train then moves at a constant velocity of 36m/s for 2.1min. The train then slows down uniformly at 0.072m/s^2, until it is brought to a halt. How long does the entire process take (in min )?
The time taken is 369.23 s
Length is measured in distance. For instance, the length of a road is its distance. The most popular units of measurement for distance in the metric system are millimeters, centimeters, meters, and kilometers.
First, the train travels 2.1 kilometers.
then travels for 400 seconds at a steady speed of 24 m/s
Distance = V x t = 24 x 400 = 9600m, or 9.6 km.
then it decreases in speed from 24 m/s to 0
hence it requires
Vf- V0=at
0-24=-0.065 xt => t=369.23 s
that indicates that it will endure for
Distance = V0t+1/2 gt2 = 24 x 369.23 - 1/2 (0.065 x 369.23) = 8849.52m, or 8.8km
2.1 + 9.6 + 8.8 = 20.5 kilometers.
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Which of the following are true about a "simple compressible system"? It cannot be a mixture of different substances (e.g. oxygen and nitrogent) It's only relevant reversible work mode is associated with expansion or compression It may not have any heat transfer to or from the system Magnetization is a relevant reversible work mode It can be composed of any phases of a substance: solid, liquid, and/or gas It's state is specified if given two independent, intensive thermodynamic properties
Explanation:
The volume of a simple compressible system is not fixed. At a state of equilibrium, there should be uniformity in the entire system.
From the question we have here, these are the correct options:
1. It cannot be a mixture of different substances (e.g. oxygen and nitrogent)
2. It can be composed of any phases of a substance: solid, liquid, and/or gas
3. It's state is specified if given two independent, intensive thermodynamic properties.
A superelastic collision is one in which...
A. kinetic energy before the collision equals kinetic energy after the collision.
B. kinetic energy after the collision is zero.
C. kinetic energy before the collision is less than kinetic energy after the collision.
D. kinetic energy before the collision is greater than kinetic energy after the collision.
Answer: ~Y/n here~ Your answer I believe would be:
A. kinetic energy before the collision equals kinetic energy after the collision.
(Hope this helps!)
Pest describes the act of using senses or tools to gather information?
ating a hypothesis
king an observation
mmarizing the results
ording the measurements
Answer:
Making an observation
Explanation:
The use of senses as a tool to gather information is described as making an observation.
While making an observation, the senses must be at alert.
Observation making is paramount to the scientific method. It is from observations that questions are asked and then hypothesis which can be tested are formulated. Observation can be carried out using the eyes, nose, feeling e.t.c. Nowadays, observation can also be carried out using some sophisticated equipment in the laboratory. This necessary for phenomenon the eludes our natural senses. A scientist must be a keen observer and their senses must be sharp.Therefore, the act of using senses or tools to gather information is called making an observation.
What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m
The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.
In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.
When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.
For example, if the answer is 12.345, we would round it to 12.3.
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Select the statement(s) that accurately describe why people have to prepare for natural disasters.
1. People have to prepare for natural disasters in order to reduce the risk of injury, death, and property damage caused by the disaster.
What is natural disasters?Natural disasters are adverse events that occur naturally and are a result of the interaction between the physical environment and human activities. They can include floods, hurricanes, tornadoes, earthquakes, tsunamis, wildfires, landslides, volcanic eruptions, and extreme weather events. Natural disasters can have devastating impacts on communities, including loss of life, damage to property, displacement, and destruction of livelihoods. Governments, organizations, and individuals are increasingly working to reduce the impacts of natural disasters through improved risk management, infrastructure planning, and disaster response and recovery efforts.
2. People have to prepare for natural disasters in order to be able to respond quickly and efficiently in the event of an emergency.
3. People have to prepare for natural disasters in order to plan for the financial impacts of the disaster.
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suppose a hiker is on a mountain ridge 1200 meters above sea level. approximately what air pressure will she experience
Assuming standard atmospheric conditions, the air pressure at sea level is approximately 1013.25 hectopascals (hPa) or 1 atmosphere (atm). The air pressure decreases with altitude following the barometric formula, which states that pressure decreases by about 1 hPa for every 8 meters of ascent.
Using this formula, we can estimate the air pressure at 1200 meters above sea level as follows:
1200 m / 8 m per hPa = 150 hPa
Therefore, the hiker on a mountain ridge 1200 meters above sea level would experience an air pressure of approximately 863.25 hPa (1013.25 hPa - 150 hPa) or about 0.85 atm.
Core Light source Cladding The wave shown in the graph above is affected by signal noise. How does this affect the quality of the wave? A It increases the quality. B It decreases the quality. C The quality is not affected by noise. D It only affects the wave if you are far away from the source.
Answer: B. It decreases the quality
Explanation: Signal noise is any unwanted or random variation in a signal that interferes with the transmission or reception of information. Noise can be caused by various factors, such as electrical interference, thermal fluctuations, atmospheric disturbances, or defects in the transmission medium.
In the case of the wave shown in the graph above, which appears to be an optical signal transmitted through a fiber optic cable, noise can affect the quality of the wave by distorting its shape, amplitude, frequency, or phase. This can result in errors or loss of data at the receiver end, as the original signal becomes harder to distinguish from the noise.
The quality of a signal can be measured by its signal-to-noise ratio (SNR), which is the ratio of the power of the signal to the power of the noise. A higher SNR means a better quality signal, while a lower SNR means a worse quality signal. Noise can reduce the SNR of a signal by adding unwanted variations to its power.
Therefore, noise decreases the quality of the wave shown in the graph above.
Hope this helps, and have a great day! =)
What is the frequency of light that has a wavelength of 682 nm? Round to 3 sig figs and put your answer in scientific notation (e.g. 6.11E14). (note: the velocity of light is 3.0E8 m/s) Hz
Answer:
439.6 THz
Explanation:
In a period of 1.00 s, 5.00×1023 nitrogen molecules strike a wall with an area of 8.00cm2. Assume the molecules move with a speed of 300 m/s and strike the wall head-on in elastic collisions. What is the pressure exerted on the wall? Note: The mass of one N2 molecule is 4.65×10−26kg.
A wall with an area of 8 cm² is struck by 5.00 x 10²³ nitrogen molecules over the course of 1 s. Assume that the molecules are moving at a speed of 300 m/s and colliding with the wall in an elastic manner. The pressure acting on the wall is 17.43 kPa.
Mass in motion is a definition of momentum. Mass and velocity are multiplied to determine momentum. That is, p = mv where p,m, and v denotes momentum, mass, and velocity.
Given the change in the time period, Δt is 1 second, the number of nitrogen molecules is 5.00×10²³ molecules, the change in velocity Δv is 300 m/s, and the area is 8×10⁻⁴ m².
The momentum of one molecule is given as 2mΔv. Then, the momentum of N molecules is 2NmΔv.
The force exerted on the wall by nitrogen molecule is written as,
\(\begin{aligned}\text{Force F}&=\frac{\Delta\text {momentum}}{\Delta t}\\&=\frac{2Nm\Delta v}{\Delta t}\end{aligned}\)
Then, the pressure exerted by nitrogen molecule on the wall is,
\(\begin{aligned}P&=\frac{F}{A}\\&=\frac{2Nm\Delta v}{\Delta t\times A}\\&=\frac{2\times 5\times10^{23}\times4.65\times10^{-26}\times300}{8\times 10^{-4}\times 1.00}\\&=\mathrm{17.43\;kPa}\end{aligned}\)
Therefore, the required answer is 17.43 kPa.
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Which two substances are elements?
A. sand and air B. salt and sand
C. iron and helium
D. helium and water
Find the moment of inertia for the following objects: A uniform disc of mass M and radius R rotating about its axis. Replace the sum in 3.31 by the appropriate integral and do the integral in polar coordinates. A uniform solid sphere rotating about a diameter. Replace the sum in 3.31 by the appropriate integral and do the integral in spherical coordinates.
A solid, uniform sphere of mass M and radius R revolving about a diameter has a moment of inertia of (2/5) * M * R2.
What is the uniform disc's moment of inertia?I=21MR2 is the ring's moment of inertia with respect to the Z-axis. Ix=Iy because the disc's uniformity makes all of its distances equal, and Iz=Ix+Iy because of the perpendicular axes theorem, which leads to Ix=2I=4MR.
We compute moment of inertia for what reasons?In linear motion, the moment of inertia plays the same role as mass does. The resistance of a body to a change in its rotaional motiton is measured in this way. For a particular rigid frame and rotational axis, it is fixed.
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Which of the following is a type of physical change?
Humans impact the Earth in good AND bad ways.
A) True
B) False
Answer:
True
Explanation:
yes we can see that we are helping animals but we create pollution which is very bad
A shell is fired from a mortar over level terrain. The firing speed is 59 m/s and the mortar is aimed 70° above the horizontal. Find the range of the shell.
Answer:
228.23m
Explanation:
Vy=59sin70=55.44m/s
x=V0t+1/2at^2
0=55.44t-4.9t^2
t=11.31s
Vx=59cos70=20.18m/s
Range=20.18*11.31=228.23m
An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?
Answer:
Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.
Explanation:
To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.
Given:
m1 = 8 kg
x1 = 3 m
x_cm = unknown (to be found)
m2 = 10 kg
y_cm = 4.5 m
Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.
To solve for x2, we can rearrange the formula as follows:
x2 = (x_cm * (m1 + m2) - m1 * x1) / m2
Substituting the given values:
x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg
Simplifying:
x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg
Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:
4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)
Simplifying:
4.5 m = (24 kg + 10 kg * x2) / 18 kg
Multiplying both sides by 18 kg:
81 kg*m = 24 kg + 10 kg * x2
Subtracting 24 kg from both sides:
10 kg * x2 = 81 kg*m - 24 kg
Dividing both sides by 10 kg:
x2 = (81 kg*m - 24 kg) / 10 kg
Simplifying:
x2 = 8.1 m - 2.4 m
x2 = 5.7 m
(brainlest?) ples:(
Answer:
the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.
Explanation:
To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.
The center of mass of a system is given by the equation:
x_cm = (m1x1 + m2x2) / (m1 + m2),
where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.
Given:
m1 = 8 kg,
x1 = 3 m,
m2 = 10 kg,
y_cm = 4.5 m.
To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:
y_cm = (m1y1 + m2y2) / (m1 + m2),
where y1 and y2 are the positions along the y-axis.
Rearranging the equation and substituting the given values:
4.5 = (83 + 10y2) / (8 + 10).
Simplifying the equation:
4.5 = (24 + 10*y2) / 18.
Multiplying both sides by 18:
81 = 24 + 10*y2.
Rearranging the equation:
10*y2 = 81 - 24,
10*y2 = 57.
Dividing both sides by 10:
y2 = 5.7.
Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.
To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:
x_cm = (m1x1 + m2x2) / (m1 + m2).
Substituting the given values:
x_cm = (83 + 10x2) / (8 + 10).
Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:
0 = (83 + 10x2) / (8 + 10).
Rearranging the equation:
83 + 10x2 = 0.
24 + 10*x2 = 0.
10*x2 = -24.
Dividing both sides by 10:
x2 = -2.4.
Ultrasonic images are obtained from the inside organs of our body. This process uses which property of sound wave?
This question involves the concepts of echo, ultrasonic images, ultrasonic sound waves.
The process of ultrasonic images uses the "echo" property of the sound waves.
Echo is the property of the sound wave by the virtue of which the sound wave reflects back to the source of the sound after hitting a surface or an object.
Ultrasonic images are obtained from inside organs of our body. This process involves the use of ultrasonic sound waves that have a frequency greater than 20,000 Hz. These sound waves are out of the range of audible sound by the human ear. When these ultrasonic sound waves are sent in form of pulses into the human body by the use of probes, they reflect back from the tissues of different organs to the probe. The probe then records the reflection properties of these sound waves and displays them in form of an image, known as ultrasonic images.
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The attached picture shows the process of ultrasonic imaging.
An object at rest will stay at rest, and an object in motion will stay in
motion, unless acted upon by an unbalanced force is known as which Law
of Motion?
Answer:
It is Newton's first law of motion also referred to as the law of inertia.
Explanation:
An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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Approximately how many times louder is a 150-dB sound than a 80-dB sound?
a 150-dB sound is approximately 10 million times louder than an 80-dB sound.
What is the range of sound?Provide instances of the differences between the audible, ultrasonic, and infrasonic frequency ranges. Three sorts of sound waves, each covering a distinct frequency range, are used. These are what they are:
Waves that fall inside the ear's sensitivity range are referred to be audible waves.Infrasonic waves are those whose frequencies fall below the range of human hearing. Ultrasonic waves are those with frequencies higher than those of sound.The difference in decibels between two sounds is related to the ratio of their intensities (or power) by the following formula:
dB₂ - dB₁ = 10 log10(I₂ / I₁)
where dB₁ and dB₂ are the decibel levels of the two sounds, and I₁ and I₂ are their intensities (or power).
Using this formula, we can find the ratio of the intensity of a 150-dB sound to that of an 80-dB sound:
150 dB - 80 dB = 10 log10(I₁₅₀ / I₈₀)
70 = 10 log10(I₁₅₀ / I₈₀)
7 = log10(I₁₅₀ / I₈₀)
10^7 = I₁₅₀ / I₈₀
I₁₅₀ = 10^7 * I₈₀
This shows that the intensity of a 150-dB sound is 10 million times greater than that of an 80-dB sound.
Therefore, a 150-dB sound is approximately 10 million times louder than an 80-dB sound.
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