A car travels 19 km in 30 minutes. What was its speed in km/hour?
HURRY WILL MARK BRAINLIST

Answer:

The magnitude of the student's displacement is less than the distance she walked.

Walking:  11 Blocks

Displacement:  8.54 Blocks

Explanation:

See the attached diagram.  The unit of length is blocks.  We can add the actual blocks walked as shown.  She walked a total of 11 blocks.

Her displacement is the distance measured directly from where she started (line A).  Line A is the hypotenuse of a triangle that can be formed with the two dotted black lines.  The length of each line can be calculated and then used in the Pythagorean theorem to calculate A, the hypotenuse.

That result is 8.54 Blocks, a shorter distance, once she earns her wings.

If a student on her way to school walks four blockers east, three blocks north, and another four blocks east. Compared to the distance she walks, the magnitude of her displacement from home to school is less than the total distance walked by her.

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.

As given in the problem if a  student on her way to school walks four blockers east, three blocks north, and another four blocks east,

The total distance walked by the student = 11 blocks

Displacement of the student from home = √(8² + 3²)

                                                                   = 8.5 blocks

The total displacement by the student would be less than the

Thus, the magnitude of her displacement from home is less than the distance.

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The surface tension of the soap solution is approximately 0.048 N/m.

W = γΔA

where W is the work done, γ is the surface tension of the soap solution, and ΔA is the change in the area of the soap bubble.

We are given W = 2.4 × \(10^{-4\) J and ΔA = 100 cm² - 50 cm² = 50 cm² = 5 × \(10^{-3\) m².

Substituting the given values in the equation, we get:

2.4 × \(10^{-4\) J = γ × 5 × \(10^{-3\) m²

Solving for γ, we get:

γ = (2.4 × \(10^{-4\) J) / (5 × \(10^{-3\) m²)

γ ≈ 0.048 N/m

Surface tension is a physical phenomenon that occurs at the interface between two different phases of matter, such as between a liquid and a gas. It is the measure of the cohesive forces between the molecules at the surface of a liquid, which tend to minimize the surface area and form a surface layer with higher energy than the bulk of the liquid. This results in the formation of a surface film that is capable of supporting objects that are lighter than the liquid itself.

Surface tension arises due to the strong intermolecular forces between the molecules of the liquid. The surface tension of a liquid is influenced by factors such as temperature, pressure, and the presence of other substances in the liquid. Surface tension plays an important role in many natural phenomena, such as the ability of insects to walk on water, the formation of raindrops, and the capillary action in plants.

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Answer:

1. B

2. C

WELCOME!!

Explanation:

I have had the same thing for school and I got it correct :(

Answer:

Emperor penguins are near the top of the Southern Ocean’s food chain. They have a varied menu that changes with the season. Some prey items are more important than others. One of the most frequently eaten prey species is the Antarctic silverfish Pleuragramma antarcticum. They also eat other fish, Antarctic krill and some species of squid. Most prey items are small. Since they are very cold when ingested, their small size makes it easier to bring food up to body temperature to digest it.

Answer:

9 m/s

Explanation:

speed = distance ÷ time

27÷3

=9

Answer:

Simple machines can actually make more work due to friction. Simple machines make work easier to do by decreasing the force required by increasing the distance over which the work is done. _____increasing___ the distance that force is applied.

Explanation:

v= (f) x ( lambda)

1.7 ms^-1/12.05 m = f =o.14 hz

The centripetal force (Fc) of the ball is 0.64N.

Centripetal force is the force on a rotating or orbiting body in the direction of the centre of rotation.

Centripetal force is a force that makes a body follow a curved path. Its direction is always orthogonal to the motion of the body and towards the fixed point of the instantaneous center of curvature of the path.

Centripetal force formula is given as the product of mass (in kg) and tangential velocity (in meters per second) squared, divided by the radius (in meters) as follows:

Fc = mv²/r

Where;

According to this question, a boy spins a ball on a string over his head with a rotational velocity of 6.3m/s. The length of the string is 0.50 m and the mass of the ball is 0.008 kg. The centripetal force is as follows:

Fc = 0.008 × 6.3²/0.5

Fc = 0.31752 ÷ 0.5

Fc = 0.64N

Therefore, 0.64N is the centripetal force of the ball.

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When you eat pizza, chemical energy is transferred to mechanical energy.

Energy can be defined as the ability to do work. Thus, energy must be possessed or transferred to a physical object (body) before work can be done.

In Science, there are different forms of energy and these include the following;

When a person eats pizza, the chemical energy contained in this snack is transferred to mechanical energy.

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We only have two observations, n = 2, and the formula can be simplified as: E[(θ1 - θ1)^2] = (1/2) * [(t_1 - θ1)^2 + (t_2 - θ1)^2]

Based on the given information, we can calculate the mean squared error (MSE) for the special case of two observations (n=2). The formula for MSE can be expressed as:

E[(θ1 - θ1)^2] = (1/n) * Σ(θ1 - θ1)^2

Since we only have two observations, n = 2, and the formula can be simplified as:

E[(θ1 - θ1)^2] = (1/2) * [(t_1 - θ1)^2 + (t_2 - θ1)^2]

This is the formula for the mean squared error as a function of t1 and t2.

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A coil set-up without an iron core, featuring thirty loops, functioned as the control in the experiments. This configuration served as a baseline to compare the outcomes all other setups contained within the experiment.

It is essential that any testing environment deploys a control to create a standard of reference when assessing alterations made to the conditions of the experiment.

The inclusion of an iron core to the coiling design led to the most significant modifications being brought about for the strength of the electromagnet. These changes were evidence by the rise in paperclips collected when inserting an iron nucleus into both the thirty-loop and sixty-loop configurations.

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Answer:

•Walking briskly

• Running /jogging

•Dancing

•biking

Answer:

500j i got it right on a test

Explanation:

Answer:

Explanation:

Given:

m₁

m₂

R₁

F₁ = 16 units

m₁' = 2·m₁

m₂' = 2·m₂

R₂ = 2·R₁

_________

F₂ - ?

The force of gravity:

F₁ = G·m₁·m₂ / (R₁)²

F₂ = G·m₁'·m₂' / (R₂)² = G·(2·m₁)·(2·m₂) / (2·R₁)² =

= 4·m₁·m₂ / (4·R₁²) = m₁·m₂ / (R₁)² = F₁

F₂ = F₁ = 16 units

The speed of the boat relative to the water is 9.08 m/s, when the boat takes 14 minutes to cross the river.

We can decompose the velocity of the boat into two components: one parallel to the river, and one perpendicular to it. Let's call the parallel component \(v_p_a_r\) and the perpendicular component \(v_p_e_r_p\):-

\(v_p_a_r = v_b_o_a_t cos\theta\)

\(v_p_e_r_p = v_b_o_a_t sin\theta\)

The boat will travel a distance of 102 m across the river, which will take 14 minutes or 840 seconds. Therefore, the distance traveled parallel to the river will be:

\(d_p_a_r = v_p_a_r * t = v_b_o_a_t cos\theta * 840 s\)

The distance traveled perpendicular to the river will be:

\(d_p_e_r_p = v_p_e_r_p * t = v_b_o_a_t sin\theta * 840 s\)

The boat will end up at a point directly north of its departure point on the south bank, which means that \(d_p_e_r_p = 102 m\). Therefore, we can solve for \(v_b_o_a_t\) as follows:

\(v_b_o_a_t sin\theta * 840 s = 102 m\)

\(v_b_o_a_t sin\theta = 102 m / 840 s\)

\(v_b_o_a_t sin\theta = 0.1214 m/s\)

To solve for \(v_b_o_a_t\):-

\(tan\theta = d_p_a_r / d_p_e_r_p\)

\(tan\theta = (v_p_a_r * t) / (v_p_e_r_p * t)\)

\(tan\theta = v_p_a_r / v_p_e_r_p\\tan\theta = v_b_o_a_t cos\theta / (v_b_o_a_t sin(\theta))\\\)

Reserving the value of \(d_p_e_r_p\) and solving for \(\theta\):-

\(\theta = arctan(v_p_a_r / (102 m / 840 s))\\\theta = arctan(v_b_o_a_t cos(\theta) / 0.1214 m/s)\)

\(v_p_a_r^2 + v_p_e_r_p^2 = v_b_o_a_t^2\\(v_b_o_a_t cos(\theta))^2 + (v_b_o_a_t sin(\theta))^2 = v_b_o_a_t^2\)

\(v_b_o_a_t^2 (cos^2(\theta) + sin^2(\theta)) = v_b_o_a_t^2\\v_b_o_a_t^2 = 102^2 / (cos^2(\theta) + sin^2(\theta))\\v_b_o_a_t = \sqrt{[102^2 / {cos^2(\theta) + sin^2(\theta)}]}\)

Reserving the value of \(\theta\):-

\(v_b_o_a_t = \sqrt{[102^2 / {cos^2(\theta) + sin^2(\theta)}]} \\v_b_o_a_t = 9.08 m/s\)

Therefore, the speed of the boat relative to the water is 9.08 m/s.

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The equivalent measurement of 11.5 milliamperes is 11.5 x 10⁻³ amperes.

The rate of flow of charge per unit cross - sectional area is called electric current. Mathematically -

i = dq/dt

From this -

dq = i dt

∫dq = ∫i dt

Q = it

Current is measured in amperes and is a Tensor quantity.

Given is a circuit that measured a current of 11.5 milli amperes.

Now, the current in milli amperes is used to give the measurement of small amount of current. One milliampere of current is equivalent to -

1 mA = (1/1000) A = 10 ⁻³ A

So, in order to calculate the total current in amperes, we will multiply 11.5 milliamperes by 10 ⁻³ as follows -

11.5 milliamperes [mA] = 11.5 x 10⁻³ amperes[A]

Therefore, the equivalent measurement of 11.5 milliamperes is 11.5 x 10⁻³ amperes.

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This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2 Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

Here's the solution to the given problem: Let the origin of our coordinate system be located at the center of the platform. We can assume that there is no friction between the platform and the ground. If v  Rw, the woman will collide with the center of the platform after the platform stops moving because it is not able to move with the required speed to reach the center of the platform before it stops. The net torque about the origin, assuming that the angular momentum is conserved, is Iα = τ, or, assuming that the angular momentum is conserved,T2−T1=IwoR2wR2+mr2αT2 = Mg/2 + Mv/RT1 = (M + m)g/2Let a be the speed of the platform just after the woman reaches the center, which is given by a = v + αr. This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

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The measure of angle 3 is given as 114 degrees

An angle is a geometric figure formed by two rays or lines that share a common endpoint called the vertex. The rays or lines that form the angle are referred to as the arms or sides of the angle. Angles are typically measured in degrees (°) or radians, and the measure of an angle indicates the amount of rotation between the two arms or sides, starting from one arm and rotating around the vertex to reach the other arm.

Line a and line b are parallel.

< 7 = 114°

The value of 3 measured as

= < 7

Having similar angles, = 114°

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Answer:

Yes! Thinking about it graphically a position vs time graph models meters per second in most cases, making every point on the line have the units m/s. If we want the find the slope we are finding the change between each point and those units would change to m/s/s or m/s^2 giving us the same units for acceleration. Simply put, slope of a velocity graph gives us acceleration.

Explanation:

Answer:

Option (b) he is moving with a constant speed (on average)

Explanation:

To know which option is correct, let us calculate the speed at each time.

Case 1:

Distance = 10 yard

Time = 1 s

Speed =?

Speed = distance / time

Speed = 10 / 1

Speed = 10 yard/s

Case 2:

Distance = 20 yard

Time = 2 s

Speed =?

Speed = distance / time

Speed = 20 / 2

Speed = 10 yard/s

Case 3:

Distance = 30 yard

Time = 3 s

Speed =?

Speed = distance / time

Speed = 30 / 3

Speed = 10 yard/s

Case 4:

Distance = 40 yard

Time = 4 s

Speed =?

Speed = distance / time

Speed = 40 / 4

Speed = 10 yard/s

From the calculations made above, we can see clearly that the speed at each case is the same i.e constant. This is true because he is covering the same distance with respect to time.

This also means that the footballer is not accelerating as his speed remains the same i.e constant.

Thus, option B gives the correct answer to the question.

Explanation:

a) Velocity and acceleration of a car are parallel when the car is moving along a straight line in the same direction. For example, when a car is gaining speed as it moves forward in a straight line, both velocity and acceleration are directed in the same direction.

b) Velocity and acceleration of a car are anti-parallel when the car is moving along a straight line in the opposite direction. For example, when a car slows down while moving in a straight line, its acceleration is directed opposite to the direction of its velocity, or the other way around.

Answer:

a)

There is only one case where velocity and acceleration are parallel only when they are moving in the same direction.

b)

There are 3 cases where velocity and acceleration are antiparallel.

(i) When both are moving in different direction

   It means :

(ii) When the object is slowing down, where velocity and acceleration are in the opposite direction.

(iii) In case of motion reversal.

Explanation:

We have that the amount of the charge q is

\(q=1.8*10^{-7}\)

From the Question we are told that

Force \(F=7.89 x*10^{-7}\)

Velocity \(V=2090m/s\)

Angle \(\theta=29.4\)

Magnetic field \(B=4.23 * 10^{-3} T\)

Generally, the equation for Force F is mathematically given by

\(F=qVBsin\theta\\\\q=\frac{F}{VBsin\theta}\)

\(q=\frac{7.89 x*10^{-7}}{4.23 * 10^{-3} T*sin29.4*2090m/s}\)

\(q=1.8*10^{-7}\)

In conclusion

The amount of the charge q is

\(q=1.8*10^{-7}\)

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From the question, the given charge moving within the magnetic field would have a value of 1.82 x \(10^{-7}\) C.

A charge is either a positively or negatively charged particle. When a charge is moving through a magnetic field, it would experience a force which depends on the amount of the charge, its speed, the magnetic field strength and angle. The force on a charge in a magnetic field can be determined by:

F = qvBSin θ

where: q is the charge, v is its velocity/ speed in the field and θ is the angle of deflection of the charge.

Given that: F = 7.89 x \(10^{-7}\) N, v = 2090 m/s, B = 4.23 x \(10^{-3}\) T and θ = 29.4°.

Thus, the amount of the charge can be determined by;

q = \(\frac{F}{vBsin O}\)

  = \(\frac{7.89*10^{-7} }{2090*4.23*10^{-3}* Sin 29.4 }\)

  = \(\frac{7.89*10^{-7} }{4.340}\)

q = 1.818 x \(10^{-7}\)

q = 1.82 x \(10^{-7}\) C

Therefore, the amount of the charge that moved within the magnetic field is 1.82 x \(10^{-7}\) C.

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Answer:

Power required = 3.5E8 * 9.0E4 = 3.2E13     (watts)

Power supplied = 1.5E3 * .15 * 3600 * 6    (watts / m^2) * A

= 1.5E3* .15 * 3600 * 6 = 4.9E6 * A

A = 3.2 / 4.9 * E7 = 3.2 / 4.9 * 10 = 6.5 km*2    (1 km^2 = 10E6 m^2)

Note:  1 W = 1 J / sec    1 kw = 1000 W

The area needed to satisfy US energy needs using solar cells 6.5 km²

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

Power required = 3.5E8 * 9.0E4 = 3.2E13     (watts)

Power supplied = 1.5E3 * .15 * 3600 * 6    (watts / m^2) * A

= 1.5E3* .15 * 3600 * 6 = 4.9E6 * A

A = 3.2 / 4.9 * E7 = 3.2 / 4.9 * 10

= 6.5 km*2  

The area needed to satisfy US energy needs using solar cells 6.5 km².

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The circuits A and B will light up but the circuits C and D would not light up. This is because there is no battery in C and D

Without a battery or other electrical power supply, a circuit won't light up. The circuit needs to be powered and be able to conduct current, and the battery supplies that power.

The circuit will not light up in the absence of a battery or other source of electrical power because it will not have the required potential difference, or voltage, to force current through its components.

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Answer:

6.15 km/h

Explanation:

distance/time

The given position equation of a particle is, s=102−23t+t2Here, t is in seconds.The first derivative of s is its velocity: v = ds/dt - 23 + 2tThe second derivative of s is the particle's acceleration:

The total distance traveled is the sum of all distance travelled in each interval of time: D = ∫|v|dt + ∫|v|dt + ... (From t 0 s to t = 17 s)From the graph of the velocity, the particle is moving to the left and toward the right side. The velocity-time graph is linear, which means that the acceleration is constant and uniform. Hence, the conclusion we can draw is that the particle is moving with uniform acceleration.  a = dv/dt = 2The given equations are: s=102−23t+t2v

=−23+2ta

=2Plot of s-t and v-t graphs:

Net displacement (Δs) during the interval of 17 seconds can be calculated as:Δs = s(17) - s(0)Δs 

= 102 - (2 × 3² / 2) - (23 × 3) + (17² / 2) - 102Δs 

= -4 mmThe particle moves to the left side.

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The chemical secreted by glands that regulates the activities of different body cells is HORMONE.

Answer:

a reactions. that is tha anser