A cheetah can maintain a constant speed of 30 m/s. At this rate, how far will it travel in 3 seconds? (Express you answer in m.)

A sound wave has a speed of 339 m/s and frequency of 640 hz, 0.42 meters is the wavelength of this wave.

The formula for calculating wavelength is wavelength = speed of sound / frequency. In this case, the speed of sound is given as 339 m/s and the frequency is 640 Hz. Using the formula, we get:
wavelength = 339 m/s / 640 Hz
wavelength = 0.529 m or 52.9 cm
Therefore, the correct answer is not listed as one of the options given in the question. The closest option is B. 0.42 meters, which is incorrect. The actual wavelength is 0.529 meters or 52.9 cm.

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Two advantages of alkaline accumulators over lead-acid accumulators are:

1. Higher energy density: Alkaline accumulators have a higher energy density than lead-acid accumulators, which means they can store more energy in the same volume or weight of battery. This makes them ideal for portable devices where size and weight are important factors.

2. Longer cycle life: Alkaline accumulators have a longer cycle life than lead-acid accumulators, which means they can be charged and discharged many more times before they need to be replaced.

This makes them a more cost-effective and reliable option for applications where the battery will be used frequently, such as in electric vehicles or renewable energy systems.

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Answer:

A. 45 degrees

Explanation:

Answer:

A. 45 degrees

Explanation:

A projectile travels the farthest when it is launched at an angle of 45 degrees.

The maximum range is 45 degrees, ignoring air resistance.

sin(2θ) = 1

∴ 2θ = π/2.

(2θ)/2 = (π/2)/2

θ = π/4

π/4 or 45°

Answer:

Astronomers led by Eduardo Bañados of the Max Planck Institute for Astronomy have discovered a gas cloud that contains information about an early phase of the galaxy and star formation, merely 850 million years after the Big Bang.

Explanation:

The total distance covered is 21 km while their displacement is 14.87 km SouthWest.

The distance covered by a moving body is the product of the speed of movement and the total time taken.

Displacement, on the other hand, is the property of a body or an object to be moved from one place to another.

While distance is a scalar quantity, displacement is a vector quantity.

In this case, the total distance covered by Justing can be calculated as:

15 km + 5 km + 1 km = 21 km

The displacement can be calculated from the attached image:

\(hyp^2 = opp^2 + adj^2\)

         = \(14^2 + 5^2\)

               = 221

                 = 14.87 km

Thus, they have been displaced by 14.87 km from the starting point in the SouthWestern direction.

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The answer is definitely Potassium

Answer:

1. and 2. If the buoyant force is greater than the object's weight, the object rises to the surface and floats. If the buoyant force is less than the object's weight, the object sinks. If the buoyant force equals the object's weight, the object can remain suspended at its present depth.

3. When the buoyant force equals one ton, it will sink no further. When any boat displaces a weight of water equal to its own weight, it floats. This is often called the “principle of flotation” where a floating object displaces a weight of fluid equal to its own weight.

Explanation:

Can anyone help me with my history question.

Answer:

Paralympic swimming is an adaptation of the sport of swimming for athletes with disabilities. Paralympic swimmers compete at the Summer Paralympic Games and at other sports competitions throughout the world. The sport is governed by the International Paralympic Committee.

The final angular velocity of the merry-go-round after the children climb onto it is 2.79 radians/second.

The first thing we need to do is calculate the angular velocity of the merry-go-round in radians per second. We can do this by using the formula:
angular velocity = (2π x RPM) / 60
Plugging in the values given in the problem, we get:
angular velocity = (2π x 19) / 60 = 3.98 radians/second
Next, we can calculate the moment of inertia of the merry-go-round using the formula:
moment of inertia = (1/2) x mass x radius^2
Plugging in the values given in the problem, we get:
moment of inertia = (1/2) x 110 kg x (1.9 m)^2 = 197.33 kg m^2
Now, we can use the conservation of angular momentum to find the final angular velocity of the merry-go-round after the children climb onto it. The initial angular momentum is zero, since the merry-go-round is not rotating when the children get on. The final angular momentum is:
final angular momentum = (moment of inertia x initial angular velocity) + (mass of first child x radius x final angular velocity) + (mass of second child x radius x final angular velocity) + (mass of third child x radius x final angular velocity)
We can solve for the final angular velocity by rearranging this equation and plugging in the values given in the problem:
final angular velocity = [mass of first child x radius + mass of second child x radius + mass of third child x radius] / [moment of inertia + (mass of first child x radius^2) + (mass of second child x radius^2) + (mass of third child x radius^2)] x initial angular velocity
final angular velocity = [(22 kg x 1.9 m) + (28.4 kg x 1.9 m) + (31.8 kg x 1.9 m)] / [197.33 kg m^2 + (22 kg x (1.9 m)^2) + (28.4 kg x (1.9 m)^2) + (31.8 kg x (1.9 m)^2)] x 3.98 radians/second
final angular velocity = 2.79 radians/second
Therefore, the final angular velocity of the merry-go-round after the children climb onto it is 2.79 radians/second.
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Therefore, the velocity of the water leaving the nozzle is approximately 6.57 m/s.

To determine the velocity of the water leaving the nozzle, we can use the principle of conservation of energy, specifically the principle of conservation of mechanical energy.

The change in potential energy of the water is converted into kinetic energy as it flows through the nozzle. Assuming the water flow is ideal (neglecting losses due to friction and other factors), we can equate the initial potential energy to the final kinetic energy.

The potential energy change can be calculated using the formula:

ΔPE = m * g * Δh

where ΔPE is the change in potential energy, m is the mass of the water, g is the acceleration due to gravity, and Δh is the change in height.

Since the water is raised by a height of 2.2 m, Δh = 2.2 m.

The change in potential energy is converted entirely into kinetic energy, which can be expressed as:

ΔKE = 0.5 * m * v^2

where ΔKE is the change in kinetic energy and v is the velocity of the water leaving the nozzle.

Setting the change in potential energy equal to the change in kinetic energy, we have:

m * g * Δh = 0.5 * m * v^2

Canceling out the mass (m) on both sides, we get:

g * Δh = 0.5 * v^2

Plugging in the known values:

g = acceleration due to gravity = 9.8 m/s^2

Δh = change in height = 2.2 m

We can solve for the velocity (v):

9.8 * 2.2 = 0.5 * v^2

v^2 = (9.8 * 2.2) / 0.5

v^2 = 43.12

Taking the square root of both sides, we find:

v = sqrt(43.12)

v ≈ 6.57 m/s

Therefore, the velocity of the water leaving the nozzle is approximately 6.57 m/s.

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Answer:

9.45 m/s

Explanation:

Answer:

D: 9.5

Explanation:

2 seconds divided by 1 is 1 so 19 divided by 1 is 9.5

The ball will continue to advance at a speed of 2.0 m/s once it rolls off the edge of the table until it lands on the ground after 0.45 seconds.

The ball is behaving just like it has been dropped. Nature is unconcerned by the fact that it is also advancing.

D=1/2gt2 and T=√2d/g

By entering the table's height and the gravitational acceleration, we can calculate the time in seconds:

t= √2(1.5m)/9.8m⋅s−2 = 0.553s

So, for a little bit longer than a half-second, the ball will be in the air (and thus able to move ahead). To find the distance travelled, we simply reverse the speed equation, s=dt, and insert in the speed and time:

d= 20m/s(0.553s)= 1.11m

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Answer:

In the interaction between the bus and the bug, we can call the force "bus pushes bug" the action force. Then the force "bug pushes bus" is the reaction force. Since these forces are a Newton's Third Law action/reaction force pair, they are exactly the same size.

Explanation:

Newtons 3rd law

When a rigid item rotates along a fixed axis, the following occurs:

They are all moving at the same angular speed.

They are all moving at the same angular velocity.

When a rigid item rotates along a fixed axis, the following occurs:

They are all moving at the same angular speed.

They are all moving at the same angular velocity.

When a rigid item rotates along a fixed axis, all of its angular speeds are the same.

All of the particles in the rotating object have the same angular speed.

They are all moving at the same angular velocity.

All of the particles in the rotating object have the same angular acceleration.

All of this stems from the following relationships:

v=wR

a = alpha*R

where w is the angular velocity and alpha is the angular acceleration.

tangential velocity and acceleration depend on the distance from the axis, whereas angular velocity and acceleration are the same for all the points on the rotating body.

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The minimum stopping distance for a vehicle, d = v2 / 2 µs g . so, is the minimum stopping distance that can be obtained without the box sliding is , 180 m.

Count the seconds it takes you to get to the same point on the road after the bumper passes a road sign or a wayside object like a telephone pole. You are following too closely if you pass the marking or item in less time than four seconds.

The rule is more of a guide for reaction times than it is for safe stopping distance. Under ideal conditions, the two-second rule indicates the bare minimum distance that must be maintained between vehicles. The two seconds provide a safety buffer to give the driver in front of you time to react.

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The intensity of sound that reaches Jim would be less than the intensity that reaches Jack. This is due to the inverse square law that governs the relationship between intensity and distance from the source of sound. What is the inverse square law? The inverse square law is a principle that describes how the intensity of energy from a source is spread out as it propagates in three dimensions.

According to this law, the energy per unit area decreases as the distance from the source increases.

The inverse square law can be expressed as: I₁/I₂ = (d₂/d₁)²

where: I₁ = intensity at distance

d₁I₂ = intensity at distance

d₂d₁ = distance of the observer from the source of sound (Jack's distance from the lecturer)

d₂ = distance of the observer from the source of sound (Jim's distance from the lecturer)From the given information, Jack is 2 meters away from the lecturer while Jim is 8 meters away from the lecturer.

Therefore, using the inverse square law, we can calculate the intensity ratio of the sound waves that reach Jack and Jim as follows: I₁/I₂ = (d₂/d₁)²

= (8/2)²

= 4²

= 16

This implies that the intensity of sound that reaches Jim is 1/16th (or 0.0625) of the intensity of sound that reaches Jack. Therefore, Jack receives more intense sound than Jim.

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Answer:

Position

Explanation:

A force vector has both magnitude and direction, which can be represented by a line with an arrow head. The length of the line describes magnitude, while the arrows points in the required direction.

generally, the position of a vector is unimportant when describing the vector. Thus, when a force vector is to be described, it is unnecessary to make reference to its original position. Majorly, its magnitude and direction is considered.

The forward azimuth from point A to point B is approximately 151.3421° (clockwise).

The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.

Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.

Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.

Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.

Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.

The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.

Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.

where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.

Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).

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The forward azimuth from point A to point B is approximately 151.3421° (clockwise).

The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.

Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.

Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.

Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.

Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.

The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.

Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.

where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.

Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).

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Answer:

r = 1.999m

Explanation:

E = kq/r²

10 = 9*10^9*q/1²

q = 10/9*10^9

q = 1.11*10^-9

then at what distance

r² = kq/E

r² = 9*10^9*1.11*10^-9/2.5

r² = 9.99/2.5

r² = 3.996

r = √3.996

r = 1.999m

Answer:

Electromagnetic waves consist of both electric and magnetic field waves. These waves oscillate in perpendicular planes with respect to each other, and are in phase. The creation of all electromagnetic waves begins with an oscillating charged particle, which creates oscillating electric and magnetic fields.

Explanation:

Given that all three patterns are formed on the same screen by light of the same wavelength but are formed by pairs of slits with different spacing and the slit spacing used for pattern a is 0.100 mm.

The expression for calculating the spacing between the slits of the diffraction grating is given by;

dsinθ = mλ...Equation 1

Where; d = spacing between the slits

θ = angle of diffraction

m = integer

λ = wavelength

We know that the angle of diffraction is same for all the three patterns formed on the same screen by light of the same wavelength but are formed by pairs of slits with different spacing.

So, we can write

Equation 2d1 sinθ = d2 sinθ = d3 sinθ

Substituting Equation 1 in Equation 2, we get

d1 mλ = d2 mλ = d3 mλ

Equation 3

We know that the slit spacing used for pattern a is 0.100 mm.

So, for m=1 in Equation 3;d1 λ = 0.100 mm

Now, we have to calculate the slit spacing for pattern c. So, for m=2 in Equation 3;

d3 λ = 2d1 λ = 2(0.100 mm)λ = 2.00 × 10^-4 mm or 2.00 × 10^-7 cm

Therefore, the slit spacing used for pattern c is 2.00 × 10^-7 cm

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The position and velocity of the ball change with time as the ball flies through the air. The correct answer is d.

When a ball is thrown, its position and velocity change continuously as it moves through the air. The position of the ball changes as it moves farther away from the point of release, and the velocity of the ball changes as it accelerates due to the force exerted by the thrower's hand and decelerates due to the effect of gravity. However, since the air resistance on the ball is negligible, the acceleration of the ball remains constant throughout its flight. Therefore, only the position and velocity of the ball change with time as it flies through the air, while the acceleration remains constant. Hence option d is correct.

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--The complete question is, you throw a ball. air resistance on the ball is negligible. which of the following functions change with time as the ball flies through the air?

a. only the position of the ball

b. only the velocity of the ball

c. only the acceleration of the ball

d. the position and velocity of the ball

e. the position and the velocity and acceleration of the ball--

Answer:x rays are electromagnetic waves.

x rays are transverse waves

x rays travel at the speed of light

Explanation:

Answer:

adding to or more vectors together . When displacement vectors are added, the result is a resultant displacement. But any two vectors can be added as long as they are the same vector quantity.

Explanation:

When astronomers use the sidereal parallax method to calculate distances to stars, the Earth's orbit around the Sun serves as the baseline for these calculations.

Astronomers have created a new unit of measurement called parsec to make calculating large distances as easy as possible (abbreviated as "pc"). Using Earth's orbit as a baseline, a parsec is the distance to an object with a parallax of one arcsecond.

We does not have two eyes that can accurately determine the distance to other stars. Instead, the starting point for these calculations is the Earth's orbit around the sun.

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