A cruise ship has a large, circular window. It has a diameter of 8 meters. What is the window's area?

Answer:

We will see that the domain of the function is:

D: {x | x ∈ R | x > -6}

How to find the domain of a function?

To find the domain of a function, we start by assuming that it is the set of all real numbers, and then we remove the problematic points.

In this case, we have a logarithm, and as you may remember, we can only evaluate the logarithm in positive values, so we need to remove all the values of x such that:

x + 6 ≤ 0

Solving for x, we get:

x ≤ -6

So the only values of x allowed are the ones that make the next inequality true:

x > -6.

Thus we can write the domain as:

D {x | x ∈ R | x > -6}

Where the second part, x ∈ R, is usually ignored, as we assume that x is a real number unless we specify that it is not, but just for completion, I wrote it.

To find the series solution for the differential equation y'' + 2xy' + 2y = 0, we can assume a power series solution of the form:

Now, substitute y(x), y'(x), and y''(x) into the differential equation:

∑(n=0 to ∞) aₙn(n-1) xⁿ⁻² + 2x ∑(n=0 to ∞) aₙn xⁿ⁻¹ + 2 ∑(n=0 to ∞) aₙxⁿ = 0

We can simplify this equation by combining the terms with the same powers of x. Let's manipulate the equation step by step:

We can combine the three summations into a single summation:

∑(n=0 to ∞) (aₙ₊₂(n+1)n + 2aₙ₊₁ + 2aₙ) xⁿ = 0

Since this equation holds for all values of x, the coefficients of the terms must be zero. Therefore, we have:

This is the recurrence relation that determines the coefficients of the power series solution To find the series solution, we can start with initial conditions. Let's assume that y(0) = y₀ and y'(0) = y'₀. This gives us the following initial terms:

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The value of the inverse function instance; f-¹ (2e) as required in the task content is; f-¹ (2e) = ( 1 + ( ln 2 ) ) / 5.

Since the given function function is; f (x) = e^5x; it follows that; To determine the inverse function; we must first represent f (x) with y;

y = e^5x

Hence, make x the subject of the formula;

ln y = 5x

x = ( ln y ) / 5

Interchange x and y so that we have;

y = ( ln x ) / 5

Finally, replace y with f-¹ (x) so that we have;

f-¹ (x) = ( ln x ) / 5

On this note, the inverse function instance which is to be evaluated; f-¹ (2e) can be evaluated as follows;

f-¹ (2e) = ( ln 2e ) / 5

f-¹ (2e) = ( ln e ) / 5 + ( ln 2 ) / 5

f-¹ (2e) = ( 1 + ( ln 2 ) ) / 5

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Al-Khwarizmi made significant contributions to the world of mathematics, particularly in the field of algebra. His major accomplishment was the development of algebra as an independent mathematical discipline.

Al-Khwarizmi, a Persian mathematician and scholar, wrote the book titled "Kitab al-Jabr wal-Muqabala," which laid the foundation for modern algebra. In this influential work, he introduced systematic methods for solving linear and quadratic equations. Al-Khwarizmi's algebraic techniques, including the use of variables and equations, greatly advanced mathematical understanding and problem-solving. His work also contributed to the development of algorithms and mathematical notation, such as the concept of the "zero" and the decimal system. Overall, al-Khwarizmi's contributions revolutionized mathematics and had a profound impact on subsequent generations of mathematicians and scientists.

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Mia would have to work 26.1 hours (approx. 26) to earn $124.00

4.75x=124

divide 4.75 by 4.75 and divide 124 by 4.75

x=26.1

The coordinate of point R is 11/40, so the correct option is C.

On the number line we can see that:

M = -1/4

T = 5/8

There are 5 segments between T and M, and the difference between T and M is:

5/8 - (-1/4) = 5/8 + 2/8 = 7/8

The measure of each segment will be equal to:

m = (7/8)/5 = 7/(8*5) = 7/40

Now, coordinate R is 2 segments to the left of T, so the coordinate of point R is given by:

R = 5/8 - 2*(7/40)

R = 25/40 - 14/40 = 11/40

The correct option is C.

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The matrix of a transformation for the reflection in the line y = -x is given by A = [ -1 0 0 -1 ] [ 0 1 -1 0 ] [ 0 -1 1 0 ] [ 0 -1 -1 0 ]. This matrix reflects points across the line y = -x and is known as a line reflection.

To understand how this matrix works, let's consider a point P(x, y). We can represent this point as a vector [x y]. To reflect this point across the line y = -x, we must multiply the vector by the transformation matrix A. This results in the vector [y -x]. Notice that this new vector is a reflection of the original vector in the line y = -x.

For example, let's consider points P(3, 4). We can represent this point as the vector [3 4]. To reflect this point across the line y = -x, we must multiply the vector by the transformation matrix A. This results in the vector [4 -3]. Notice that this new vector is a reflection of the original vector in the line y = -x.

Therefore, the matrix A of T for the given transformation (reflection in the line y = -x) is given by A = [ -1 0 0 -1 ] [ 0 1 -1 0 ] [ 0 -1 1 0 ] [ 0 -1 -1 0 ].

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Answer:

1. D 2. C 3. C

Step-by-step explanation:

On my test

Based on the above, the capacity of a 5-liter tin is about  500 cm³.

To be able to convert the capacity of a 5-liter tin to its volume in cm³, One need to use the conversion factor that is, 1 liter is equivalent to 100 cm³.

So, to be able to calculate the volume of a 5-liter tin in cm³, one have to multiply the capacity (5 liters) by the conversion factor (100 cm³/liter):

Volume in cm³ = 5 liters x 1000 cm³/liter

                           = 500 cm³

Therefore, the capacity of a 5-liter tin is about  500 cm³.

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See full text below

Convert the capacity of a 5 litre tin to its volume in cm³.1litre is equivalent to 100cm³

Answer:

Step-by-step explanation:

Hope this helps u!!

Answer:

5 6/7 or C option

Step-by-step explanation:

5 6/7 is equal to 5.857 and rounded it is 6

While all the others round to 5

Hopes this helps please mark brainliest

Answer:

It is an obtuse triangle I think because

The expression sin(e^37) does not have a well-defined limit as x approaches 0 from the left side since the argument e^37 is not an angle and is a constant.

To find the limit of the function sin(e^37) as x approaches 0 from the left side, we need to evaluate the limit and analyze the behavior of the function near 0.

The expression sin(e^37) represents the sine of a very large number, approximately equal to 5.32048241 × 10^16. The sine function oscillates between -1 and 1 as the input increases, but it does so in a periodic manner.

As x approaches 0 from the left side (x < 0), the function sin(e^37x) will oscillate rapidly between -1 and 1. However, since the argument of the sine function (e^37) is an extremely large constant, the oscillations will occur at a much higher frequency.

To calculate the limit, we can directly evaluate the function at x = 0 from the left side.

sin(e^37 * 0) = sin(0) = 0.

Therefore, the limit of sin(e^37) as x approaches 0 from the left side is equal to 0.

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we can solve the equation using the inverse of A:\(\[x = A^{-1}v = \begin{bmatrix} -1 & 2 & -5 \\ 5 & -9 & 20 \\ -1 & 2 & -4 \end{bmatrix} \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix} = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]Therefore, the four vectors:\[u_1 = \begin{bmatrix} 1 \\ -1 \\ 2 \end{bmatrix} , \; u_2 = \begin{bmatrix} 2 \\ 1 \\ 0 \end{bmatrix} , \; u_3 = \begin{bmatrix} -1 \\ 3 \\ -1 \end{bmatrix} , \; v = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]\)form a basis of .

To do that, we will solve the equation:\[Ax = v\]where x is a column vector of three unknowns. We want v to be linearly independent from the columns of A, so we need the equation to have a unique solution. We can achieve that by taking v to be any vector that is not in the column space of A. For example, we can take:\\([v = \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix}\]\)Then, we can solve the equation using the inverse of A:\(\[x = A^{-1}v = \begin{bmatrix} -1 & 2 & -5 \\ 5 & -9 & 20 \\ -1 & 2 & -4 \end{bmatrix} \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix} = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]Therefore, the four vectors:\[u_1 = \begin{bmatrix} 1 \\ -1 \\ 2 \end{bmatrix} , \; u_2 = \begin{bmatrix} 2 \\ 1 \\ 0 \end{bmatrix} , \; u_3 = \begin{bmatrix} -1 \\ 3 \\ -1 \end{bmatrix} , \; v = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]\)form basis of .

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Answer: 28 inches

Step-by-step explanation:

Since their areas are the same their perimeter would be the same too. So plug 8 in for the length, for the formula of perimeter( 2(L+W) ) which would be 2(8+6) and you get 28

angle has a measure equal to the sum of the the question is ∠DQS.


According to the problem, we need to find an angle whose measure is equal to the sum of the measures of ∠SQR and ∠QRS. We can use the angle addition postulate which states that the measure of an angle formed by two adjacent angles is equal to the sum of their measures.

Let's consider angle ∠DQS. This angle is formed by adjacent angles ∠SQR and ∠QRS. Therefore, according to the angle addition postulate, the measure of angle ∠DQS is equal to the sum of the measures of ∠SQR and ∠QRS.



Thus, we can conclude that the angle ∠DQS has a measure equal to the sum of the measures of ∠SQR and ∠QRS.

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Answer:

The answer is below

Step-by-step explanation:

Let x represent the number of hours spent on walking and let y represent the number of hours spent on biking.

Tenley wants to exercise at least 15 hours per week, therefore:

x + y ≥ 15        (1)

Tenley cover at least 90 miles total in her weekly workout, therefore:

3x + 10y  ≥ 90     (2)

x ≤ 12, y ≤ 10        (3)

Plotting the above constraints using geogebra online graphing tool. The solution to the problem is:

(5, 10) , (12, 10), (12, 5.4), (8.57, 6.43)

Answer:

  circumcenter

Step-by-step explanation:

You want to know the name of the point equidistant from the vertices of a triangle.

The circle that passes through the vertices of a triangle is called a "circumcircle". It circumscribes the triangle. Its center is equidistant from all points on the circle, so is equidistant from the triangle's vertices.

The point equidistant from the vertices of a triangle is the circumcenter.

__

Additional comment

The circumcenter is at the intersection of the perpendicular bisectors of the sides of the triangle.

They can buy between 3 and 13 pairs of earrings.

The correct answer is: 115 ≤ 9(3) + 6(11) + 6x ≤ 175;

To set up an inequality to model the problem, we can start by calculating the total cost of the bracelets and necklaces.

The cost of 9 bracelets at $3 each is 9 \(\times\) 3 = $27.

The cost of 6 necklaces at $11 each is 6 \(\times\) 11 = $66.

Therefore, the total cost of the bracelets and necklaces is $27 + $66 = $93.

Let's represent the number of pairs of earrings they can buy as "x". The cost of each pair of earrings is $6.

Now, we can set up the inequality to represent the given condition:

$115 ≤ 9 \(\times\) 3 + 6 \(\times\) 11 + 6x ≤ $175

Simplifying the inequality, we have:

$115 ≤ 27 + 66 + 6x ≤ $175

Combining like terms, we get:

$115 ≤ 93 + 6x ≤ $175

To isolate "x", we can subtract 93 from all parts of the inequality:

$115 - 93 ≤ 6x ≤ $175 - 93

This simplifies to:

22 ≤ 6x ≤ 82

Now, divide all parts of the inequality by 6:

22/6 ≤ x ≤ 82/6

This gives us:

3.67 ≤ x ≤ 13.67

Since we cannot have a fraction of pairs of earrings, we round down the lower limit and round up the upper limit:

3 ≤ x ≤ 14

Therefore, they can buy between 3 and 14 pairs of earrings.

So, the correct answer is:

115 ≤ 9(3) + 6(11) + 6x ≤ 175; They can buy between 3 and 14 pairs of earrings.

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Answer:

20 cm

Step-by-step explanation:

If R is the midpoint of HS, and N is the midpoint of RS, then RN is 1/4 of HS. This means that RN 4 times is HS. so 5x4 20.

Answer:

b = 8

Step-by-step explanation:

cos Θ = \(\frac{adjacent}{hypotenuse}\) = \(\frac{PQ}{QR}\) = \(\frac{b}{14}\)

given cos Θ = \(\frac{4}{7}\) , then equate the 2 expressions , that is

\(\frac{b}{14}\) = \(\frac{4}{7}\) ( cross- multiply )

7b = 56 ( divide both sides by 7 )

b = 8

The magnitude of the net electric field at point P due to the particle is 0 . explanation is given as

let us assume that , The charges of the four particles and the distance are given then on understanding the  concept of electric field  at electrostatics concept. on using the concept of the electric field at any given point, then production of  individual electric field by a charge. and we known the concept of superposition law, on applying the law  we  get the value of the electric field in its direction and this shows the determination of   the net electric field at that point.

The magnitude of the electric field,  

E = q * R

where R = The distance of field at  point from the charge, and q = charge of the individual particle

According to the superposition principle, the electric field at a single point due to more than one charges present ,hence on calculation of net electric field  we get the origin of the coordinate system  which is placed at point P and the y-axis is situated and oriented in the direction of the charge,  (passing through the charge, ). The x-axis which  is perpendicular to the y axis, and thus passes through the identical charges, then the  individual magnitudes of an electric field is due to the charges are demonstrated by using the absolute signs of the charges. Now let us assume that the point charge which  being positive i.e  ( q > 0), we can see that the contributions coming from each charge gets cancel to each other. Therefore the net electric field in the direction of the y-axis is given using equation as  E= 0

hence the net electric field is zero .

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Answer:

Step-by-step explanation:

Yes

You almost have an isosceles triangle. The lengths of the longest line segments differ by by 0.3. So the base of the triangle is 2.8 and the long segments are connected to each other and each of them at end of 2.8

∂g/∂u is equal to 21u⁵cos⁴(v)sin⁴(v)(cos(v) + u³cos⁴(v)sin²(v)sin(v)).

To find the indicated derivative, we need to use the chain rule. Let's differentiate step by step:

Given:

g(u, v) = f(x(u, v), y(u, v))

f(x, y) = 7x³y³

x(u, v) = ucos(v)

y(u, v) = usin(v)

To find ∂g/∂u, we differentiate g(u, v) with respect to u while treating v as a constant:

∂g/∂u = (∂f/∂x) * (∂x/∂u) + (∂f/∂y) * (∂y/∂u)

To find ∂f/∂x, we differentiate f(x, y) with respect to x:

∂f/∂x = 21x²y³

To find ∂x/∂u, we differentiate x(u, v) with respect to u:

∂x/∂u = cos(v)

To find ∂f/∂y, we differentiate f(x, y) with respect to y:

∂f/∂y = 21x³y²

To find ∂y/∂u, we differentiate y(u, v) with respect to u:

∂y/∂u = sin(v)

Now, we can substitute these partial derivatives into the equation for ∂g/∂u:

∂g/∂u = (21x²y³) * (cos(v)) + (21x³y²) * (sin(v))

To find the simplified form, we substitute the given values of x(u, v) and y(u, v) into the equation:

x(u, v) = ucos(v) = u * cos(v)

y(u, v) = usin(v) = u * sin(v)

∂g/∂u = (21(u * cos(v))²(u * sin(v))³) * (cos(v)) + (21(u * cos(v))³(u * sin(v))²) * (sin(v))

Simplifying further, we get:

∂g/∂u = 21u⁵cos⁴(v)sin⁴(v)(cos(v) + u³cos⁴(v)sin²(v)sin(v))

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Answer: m= 10 over 9

Step-by-step explanation:

If you want to check your answer

The remainder of the equation is \(\rm 28x+30\).

Given that,

When the equation \(\rm 3x^3-2x^2+4x-3\) is divided by \(\rm x^2+3x+3\).

We have to find,

The remainder of the equation?

According to the question,

The equation \(\rm 3x^3-2x^2+4x-3\) is divided by \(\rm x^2+3x+3\).

On the division of the polynomial, the remainder is,

\(\dfrac{\rm 3x^3-2x^2+4x-3}{\rm x^2+3x+3}\)

Factorize the equation to convert this into the simplest form,

\(\rm 3x^3-2x^2+4x-3\\\\3x^3-11x^2+9x^2+9x+28x-33x-33+30\\\\Taking \ the \ common \ terms \ and \ simplify\ the\ equation\\\\3x^3+9x^2+9x+11x^2+33x-33+28x+30\\\\3x(x^2+3x+3) - 11(x^2+3x+3) + 28x+30\\\\(3x+11) (x^2+3x+3) +28x +30\)

Now, the equation can be written as,

\(\rm = \dfrac{(3x+11) (x^2+3x+3) +28x +30}{ x^2+3x+3}\\\\= \dfrac{(3x+11) (x^2+3x+3) }{ x^2+3x+3} + \dfrac{28x +30}{ x^2+3x+3}\\\\= (3x+11) + \dfrac{28x +30}{ x^2+3x+3}\\\\\)

The relation between the divisor, remainder, and quotient is,

\(\rm = Quotient + \dfrac{Remainder}{Divisor}\)

On comparing with the equation,

The remainder becomes 28x +30.

Hence, The required remainder of the equation is \(\rm 28x+30\).

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Answer:

the answer is around 872