a cyclist rides their bike 4.5 km due west for 10 min, then 2.0 km 25° west of south for 6 min. from this point they ride 7.2 km due south for 20 min. using the positive x direction as due east and the positive y direction as due north
Answers
The cyclist ends up at point P with coordinates (-2.70, -8.05).
To find the coordinates of point P, let's analyze the movements of the cyclist step by step.
First movement: The cyclist moves 4.5 km due west. This results in a change of the x-coordinate by -4.5 km (negative because it is towards the west). Therefore, the new coordinates are (-4.5, 0).
Second movement: The cyclist moves 2.0 km 25° west of south.
We can calculate the change in x-coordinate and y-coordinate as follows:
Change in x-coordinate = 2.0 km × cos 25° ≈ 1.80 km
Change in y-coordinate = -2.0 km × sin 25° ≈ -0.85 km
Therefore, the new coordinates become (-4.5 + 1.80, -0.85) ≈ (-2.70, -0.85).
Third movement: The cyclist moves 7.2 km due south. This means the y-coordinate changes by -7.2 km (negative because it is towards the south).
Therefore, the new coordinates are (-2.70, -0.85 - 7.2) = (-2.70, -8.05).
Hence, the final position of the cyclist is at point P, which has coordinates (-2.70, -8.05).
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The cyclist's total displacement is approximately 8.6 km.
The cyclist's motion can be divided into three segments:
1. In the first segment, the cyclist rides 4.5 km due west for 10 minutes. Since the motion is due west, it can be represented as (-4.5, 0) km in the coordinate system. To convert the time to hours, divide 10 minutes by 60, giving 0.167 hours. Therefore, the velocity in the x-direction is (-4.5 km / 0.167 h) = -27 km/h. The velocity in the y-direction is 0 km/h since there is no north or south component.
2. In the second segment, the cyclist rides 2.0 km 25° west of south for 6 minutes. To find the components of this motion, we can use trigonometry. The x-component is given by (2.0 km) * cos(25°), which is approximately 1.8 km.
The y-component is given by (2.0 km) * sin(25°), which is approximately -0.86 km. Converting the time to hours (6 minutes / 60) gives 0.1 hours. Therefore, the x-velocity is (1.8 km / 0.1 h) = 18 km/h and the y-velocity is (-0.86 km / 0.1 h) = -8.6 km/h.
3. In the third segment, the cyclist rides 7.2 km due south for 20 minutes. This can be represented as (0, -7.2) km in the coordinate system. Converting the time to hours (20 minutes / 60) gives 0.333 hours. Therefore, the velocity in the y-direction is (-7.2 km / 0.333 h) = -21.62 km/h. The velocity in the x-direction is 0 km/h since there is no east or west component.
To find the total displacement, add the displacements from each segment:
- Displacement in the x-direction = -4.5 km + 1.8 km + 0 km = -2.7 km
- Displacement in the y-direction = 0 km - 0.86 km - 7.2 km = -8.06 km
Therefore, the total displacement is approximately (-2.7 km, -8.06 km).
In terms of distance, you can use the Pythagorean theorem to find the magnitude of the displacement:
Magnitude of the displacement = sqrt((-2.7 km)^2 + (-8.06 km)^2) ≈ 8.6 km
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A Cyclist Rides Their Bike 4.5 Km Due West For 10 Min, Then 2.0 Km 25° West Of South For 6 Min. From This Point They Ride 7.2 Km Due South For 20 Min. Using The Positive X Direction As Due East And The Positive Y Direction As Due North A. (1 Pt.) Write Each Of The Three Displacements Vectors In Terms Of Their Magnitude And The Angle Measured
Related Questions
You stand 3.5 m in front of a large mirror, and your little sister stands 2.0 m directly in front of you. At what distance should you focus your camera if you want to take a picture of your sister in the mirror?
Answers
Answer:
D = 3.5 m to mirror
d = 1.50 m from mirror to sister
Total distance from camera to sister = d + D = 5.0 m
What is the efficiency of a light bulb if it produces 30j of light energy, with an input of 120j of electrical energy?
Answers
The efficiency of this light bulb is 25% .
How do you calculate the efficiency of a light bulb?Utilizing the following formula, efficiency may be represented as a ratio: output input. The total quantity of beneficial work accomplished, excluding waste and spoilage, is known as output or work output. Efficiency may also be expressed as a percentage by dividing the ratio by 100.To represent the result as a percentage, divide the output by the input and then multiply by 100. Although both work and energy are measured in terms of the Joule, the calculator above has a space for a different unit. Make sure the energy and labour units are equivalent.Efficiency is essentially a measurement of the amount of labour or energy that may be saved throughout a process. In other words, it's similar to comparing the energy intake and output in any particular system.Given data :
output = 30j
Input = 120j
Efficiency = output / input x 100
= 30 / 120 x 100
= 25%
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3. A train is 120 m long. Sydney was standing 200 m from the front of the train when it
began to accelerate from rest. She noticed that the front of the train was moving at 8.00
m/s when it passed her. How fast would the back of the train be going when it passed
her?
Answers
Answer:
Below
Explanation:
Find acceleration first
vf = vo + at (starts from rest so vo = 0)
8 = 0 + at
8 = at
d = vo t + 1/2 a t^2 (substitute 8 in for 'at')
200 = 0 t + 1/2 (8) t
200 / 4 = t = 50 seconds for front of train to pass her at 8 m/s
acceleration = change in velocity / change in time = 8 / 50 = .16 m/s^2
Back of train has to travel 120 meters at initial v = 8 m/s and accelerating at .16 m/s^2 :
d = vo t + 1/2 a t^2
120 = 8 t + 1/2 ( .16 ) t^2
.16t^2 + 8t - 120 = 0 Quadratic Formula shows t = 13.25 s
vf = vo + a t
vf = 8 m/s + .16 m/s^2 ( 13.25 s) = 10.1 m/s
Fossil fuels store energy from the sun as
question 5
Answers
Answer:
Fossil fuels store energy from the sun as
Explanation:
What does the table suggest about the acceleration of the marble and why?
Answers
The table suggests that the acceleration of the marble increases steadily over time due to the increasing force being applied to it. This is because acceleration is directly proportional to the force applied, according to Newton's second law of motion (F = ma).
Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
Newton's second law is often stated as F=ma, which means the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a). This means the more mass an object has, the more force you need to accelerate it. And the greater the force, the greater the object's acceleration.
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What is the answer? I am trying to do some exercise
Answers
Answer:
fourth quadrant.
Explanation:
First, let us see how many 2 pi radians are there in 40 pi /7. The answer is found by dividing 40 pi / 7 by 2 pi
\(\frac{40\pi}{7}\div2\pi=\frac{40\pi}{7}\times\frac{1}{2\pi}\)\(=\frac{40\pi}{7}\times\frac{1}{2\pi}=\frac{20}{7}=2R6\)Meaning ( 40 pi / 7 ) / ( 2pi ) = 2 Remainder 6
Meaning there are 2 complete revolutions in ( 40 pi / 7 ).
How about the revolution that is incomplete?
Now,
\(\frac{40\pi}{7}-2(2\pi)=\frac{40}{7}\pi-4\pi\)\(=\frac{12}{7}\pi\)\(=1.71\pi\)Which if we plot, looks like
Meaning that 40 pi / 7 lies in the fourth quadrant.
After being struck by a bowling ball, a 1.8 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.8 kg bowling pin initially at rest. Find the final velocity of the second pin in the following situations: a) The first pin moves to the right after the collision at 0.8 m/s. Answer in units of m/s. 010 (part 2 of 2) 10.0 points b) The first pin stops moving when it hits the second pin. Answer in units of m/s
Answers
Answer:
a) v₂ = 4.2 m/s
b) v₂ = 5 m/s
Explanation:
a)
We will use the law of conservation of momentum here:
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0.8 m/s
v₂ = speed of second after before collsion = ?
Therefore,
\((1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s\)
v₂ = 4.2 m/s
b)
We will use the law of conservation of momentum here:
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0 m/s
v₂ = speed of second after before collsion = ?
Therefore,
\((1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)\)
v₂ = 5 m/s
the box with the changing data shows that the acceleration is constant at 4.90 m/s2, but i thought g = 9.80 m/s2. how is this possible?
Answers
The box with the changing data shows that the acceleration is constant at 4.90 m/s2, but i thought g = 9.80 m/s2.
The acceleration due to gravity (g) is different from the acceleration of the object itself. Although g is usually taken to be 9.8 m/s2, it can vary depending on the object's location and height above the Earth's surface. As a result, a falling object can experience acceleration greater than, less than, or equal to g when air resistance is taken into account or not
In the given scenario, the box is not necessarily in free fall; it could be undergoing linear motion along a surface. Furthermore, the box could be in free fall, but with air resistance affecting its motion. In this situation, the box's acceleration would be less than g.The box's acceleration may have been determined using an accelerometer or a ticker tape. Regardless, the acceleration indicates the rate at which the box's velocity is changing, which may or may not be equal to g.
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Petroleum is a non -renewable resource. Therefore, its use needs
to be planned so that present and future use can be adequately met.
Explain how the optimal level of use of petroleum can be
achieved.
Answers
Petroleum is a non-renewable resource, which means that it cannot be replenished. Because of this, its usage needs to be planned properly to make sure that there is sufficient availability for present and future needs
The optimal level of use of petroleum can be achieved by several ways which are listed below:
1. Reduce wastage: The optimal level of petroleum use can be achieved by reducing wastage. We should aim to use petroleum products efficiently to minimize wastage and ensure that the resource is not used up too quickly.
2. Develop alternative energy sources: Another way to achieve the optimal level of petroleum use is to develop alternative energy sources. Renewable energy sources like solar, wind, and hydro can be developed to supplement petroleum.
3. Increase efficiency: The third way to achieve the optimal level of petroleum use is to increase efficiency. We can achieve this by improving the efficiency of vehicles and machinery that consume petroleum products.
4. Conservation: Conservation can also help achieve the optimal level of petroleum use. We can conserve petroleum by using it judiciously and avoiding unnecessary use. We can also reduce our reliance on petroleum products by using alternatives like public transport or bicycles.
5. Develop sustainable transportation: Developing sustainable transportation can also help achieve the optimal level of petroleum use. We can develop transportation systems that are more efficient, rely on alternative energy sources, and reduce the amount of petroleum consumed.
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Which variable is NOT shown on a velocity-time graph?
Answers
Acceleration is the variable that is NOT shown on a velocity-time graph
Velocity - time graph, evidently shows two variables, velocity on one axis and time on other . But as we know , that acceleration can be calculated by the formula which is
acceleration = change in velocity / time
hence , the derivative of velocity is acceleration
which mean that the slope of the Velocity - time graph shows the acceleration , which cannot be seen , but is hidden as the slope of that graph
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if bananas are curved because they grow towards the sun ☀️so say if a was born towards the sun would i have been a curved baby or what
Answers
ಠ_ಠ Hey, hang on.. you might've made a discovery. Nobody has tested it so how do we know? ಠ_ಠ
Answer:
It's because of the sun! Bananas are curved so they can retrieve sunlight. Bananas go through a process called 'negative geotropism'. ... So, bananas do not grow directly towards the sun rays but grow upwards to break through the canopy.
Which of the following is not true about electric potential energy?
It depends on how much charge is moving through the field
It can be measured in joules
It can be measured in calories
It is a measure of how strong the electric field is only
Answers
Answer:
the second one
Explanation:
When a free positive charge q is accelerated by an electric field, such as shown in Figure 1, it is given kinetic energy. The process is analogous to an object being accelerated by a gravitational field. It is as if the charge is going down an electrical hill where its electric potential energy is converted to kinetic energy. Let us explore the work done on a charge q by the electric field in this process, so that we may develop a definition of electric potential energy.
The electrostatic or Coulomb force is conservative, which means that the work done on q is independent of the path taken. This is exactly analogous to the gravitational force in the absence of dissipative forces such as friction. When a force is conservative, it is possible to define a potential energy associated with the force, and it is usually easier to deal with the potential energy (because it depends only on position) than to calculate the work directly.
The original pressure of a gas was 2.5 atmospheres. When the pressure was decreased to 1.7 atmospheres, the volume increased to 850 mL. What was the original volume? Make sure that you show your work and use the proper units.
Answers
Taking into account the Boyle's law, the original pressure of a gas was 2.5 atmospheres and the original volume was 578 mL.
Boyle's lawBoyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. This is because when the volume decreases, the distance that the particles have to travel is less and therefore more shocks occur in each unit of time, that is, the pressure increases.
Mathematically, if the amount of gas and the temperature remain constant, the product of the pressure and the volume always has the same value:
P×V= k
where:
P is the pressure.V is the volume.k is a constant.Being an initial state 1 and a final state 2, it is fulfilled:
P₁×V₁= P₂×V₂
Original volumeIn this case, you know:
P₁= 2.5 atmV₁= ?P₂= 1.7 atmV₂= 850 mLReplacing in Boyle's law:
2.5 atm ×V₁= 1.7 atm ×850 mL
Solving:
V₁= (1.7 atm ×850 mL)÷ 2.5 atm
V₁= 578 mL
The original volume was 578 mL.
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the distance between two successive troughs of wave is 0.4m. If the frequency of the source is 825Hz, calculate the speed of the wave
Answers
Answer:
speed=330m/s
Explanation:
the speed of wave is given as
speed(meter per second) =frequency(hertz) * wavelength(meters)
so using the above formula we substitute the figures given in the question in the formula we get
speed = 0.4*825
speed =330m/s
note m/s is the si unit for speed which is read as meter per second
therefore speed =330m/s
The piton in fig 2. 1. 15 i pulled out of the cylinder from piton x to piton y without changing the temperature of the air encloed if the original preure in the cylinder wa 1. 0 multiply by 10 calculate the air preure when the piton i at poition y
Answers
The pressure at position y to be 10.0, which is the air pressure when the piston is at position y.
If the original pressure in the cylinder was 1.0, and the piston is pulled out from position x to position y without changing the temperature of the enclosed air, the air pressure at position y will be increased. This is due to the change in volume of the cylinder as the piston is pulled out. As the volume increases, the number of air molecules inside the cylinder also increases, which causes an increase in the air pressure.
To calculate the air pressure when the piston is at position y, we can use the gas law known as Boyles' Law, which states that the pressure and volume of a gas are inversely proportional. Therefore, if the volume increases, the pressure will decrease, and if the volume decreases, the pressure will increase.
P₁V₁=P₂V₂Where P₁ is the initial pressure, V₁ is the initial volume, P₂ is the final pressure, and V₂ is the final volume.
By substituting the given values, we have:
1.0V₁ = P₂(V₁+V)Where V is the change in volume due to the movement of the piston.
Solving for P₂:
P₂= 1.0*V₁/(V₁+V)P₂= 1.0*1.0/(1.0+V)As we know, the original pressure is 1.0, and if we multiply it by 10, we will get the final pressure at position y to be 10.0, which is the air pressure when the piston is at position y.
This question is not written in a proper manner. The corrections are:
The piston in fig. 2. 1.15 is pulled out of the cylinder from piston x to piston y without changing the temperature of the air enclosed. If the original pressure in the cylinder was 1.0, multiply by 10 to calculate the air pressure when the piston is at position y.Learn more about piston–cylinder here: brainly.com/question/24884868
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even though the sun is so much bigger than the moon, why does the moon have a stronger effect on tides?
Answers
Answer:
the moon is closer to the earth so that its gravitational gradient is stronger than that of the sun.
Explanation:
imma be a positive queen bc i feel like ppl now a days need positive thoughts in they head bc of all that is going on
Answers
Answer:
Calculating the question of whether or not to take it serious
A force is specified by the vector F = [(110)i + (-210)j + (-10)k] N. Calculate the angles made by F with the positive x-, y-, and z-axes.
Answers
The vector F can be written as F = 110i - 210j - 10k.
The angle made by F with the positive x-axis is given by:
θx = arctan(Fy/Fx)
where Fx is the x-component of the vector F and
Fy is the y-component of the vector F.
θx = arctan(-210/110)
θx = -62.25°
The angle made by F with the positive y-axis is given by:
θy = arctan(Fx/Fy)
where Fx is the x-component of the vector F and
Fy is the y-component of the vector F.
θy = arctan(110/-210)
θy = -28.07°
The angle made by F with the positive z-axis is given by:
θz = arctan(Fz/Fr) where Fz is the z-component of the vector F and Fr is the magnitude of the vector F.
Fr can be calculated as:
Fr = √(F²) = √(110² + (-210)² + (-10)²)Fr = 236.31 N
θz = arctan(-10/236.31)
θz = -2.42°
Hence, the angles made by F with the positive x-, y-, and z-axes are -62.25°, -28.07°, and -2.42° respectively.
Note: The angles are measured in the clockwise direction from the positive x-, y-, and z-axes.
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A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s2 . Of the tangential speed of the roller coaster cars is 15-7 m/s
Answers
Answer:
25.152mExplanation:
Compete question;
A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s² . If the tangential speed of the roller coaster cars is 15.7 m/s, find its radius.
centripetal acceleration a = v²/r
v is the tangential speed
r is the radius
Given
v = 15.7m/s
a = 9.8m/s²
9.8 = 15.7²/r
9.8r = 15.7²
r = 15.7²/9.8
r = 246.49/9.8
r = 25.152m
Hence the radius of the coaster is 25.152m
Get some points uwu
What part of the telescope focuses the light
Answers
Answer:
Objective lens is the answer
an airplane having a period of 120 miles an hour in calm air is pointed in a direction 30 deg east of north. a wind having a velocity of 15 miles an hour is blowing from Northwest. FInd the speed of the airplane relative to the ground?
Answers
To find the speed of the airplane relative to the ground, we can use vector addition.First, we need to break down the velocities of the airplane and the wind into their respective components.The airplane's velocity can be decomposed into two components: one in the north direction and one in the east direction.
Since the airplane is pointed 30 degrees east of north, the north component will be given by:V_north = V_airplane * cos(30°)And the east component will be given by:V_east = V_airplane * sin(30°)Given that the airplane's velocity (V_airplane) is 120 miles per hour, we can substitute this value into the equations:V_north = 120 * cos(30°)
V_east = 120 * sin(30°)V_north ≈ 103.92 miles per hour
V_east ≈ 60 miles per hour
Now, let's consider the wind velocity. The wind is blowing from the northwest, which means it has a velocity directed 45 degrees south of west. We can break down the wind velocity into its north and west components:V_wind_north = V_wind * cos(45°)
V_wind_west = -V_wind * sin(45°) (negative sign since it is directed west)
Given that the wind velocity (V_wind) is 15 miles per hour, we can substitute this value into the equations:V_wind_north = 15 * cos(45°)
V_wind_west = -15 * sin(45°)
V_wind_north ≈ 10.61 miles per hour
V_wind_west ≈ -10.61 miles per hour
Now, we can find the total velocity of the airplane relative to the ground by adding the individual components of the airplane's velocity and the wind's velocity:
V_total_north = V_north + V_wind_north
V_total_east = V_east + V_wind_west
V_total_north ≈ 103.92 + 10.61 ≈ 114.53 miles per hour
V_total_east ≈ 60 - 10.61 ≈ 49.39 miles per hour
To find the speed of the airplane relative to the ground, we can use the Pythagorean theorem:
Speed = √(V_total_north² + V_total_east²)
Speed ≈ √(114.53² + 49.39²) ≈ 125.54 miles per hour
Therefore, the speed of the airplane relative to the ground is approximately 125.54 miles per hour.
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ILL GIVE BRAINLIEST.
Ginny throws the Chaser up the air in a game of Quidditch with a velocity of 55 m/s. Assuming it has lost any magic and is not affected by air resistance, answer the following questions.
c) Assuming she is 10 meters off the ground when she throws it, with what velocity will it hit the ground?
Answers
Does a zero-kinetic energy reference frame always exist, never exist, or sometimes exist?.
Answers
A zero-kinetic energy reference frame can sometimes exist. A zero-kinetic energy reference frame is a frame of reference in which the total kinetic energy of all objects in the frame is zero.
This means that all objects in the frame must be moving at the same velocity. This type of reference frame can sometimes exist in cases where the total momentum of all objects in the frame is zero, such as in a closed system in which the total momentum of all objects is equal to zero and all objects are moving at the same velocity.
However, in most cases, a zero-kinetic energy reference frame does not exist, since in most cases the total momentum of all objects is not zero and therefore the objects are not all moving at the same velocity.
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plz help i will mark brainlyist.
describe how gravitational force is related to mass and distance
compare the magnitude and range of the four basic forces—gravitational, electromagnetic, weak nuclear and strong nuclear
Answers
Answer:
please mark me brainliest
Explanation:
Gravitational force -an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects.
The Four Fundamental Forces of Nature are Gravitational force, Weak Nuclear force, Electromagnetic force and Strong Nuclear force. The weak and strong forces are effective only over a very short range and dominate only at the level of subatomic particles. Gravity and Electromagnetic force have infinite range.
1. What three particles are found in an atom?
Answers
Answer:
Protons, Electrons, and neutrons
Answer:
protons electrons neutrons
Explanation:
A force of 100 N is applied to a crate at an angle of 60° to the horizontal surface. The force causes the crate to move 2 m across the floor. How much work is done on the crate?
a. 50 J
b. 100 J
c. 200 J
Answers
Answer: B 100 J
Explanation: Pic Attached. Hope This Helps.
Net force acting on a 100 kg man standing in an elevator accelerating downward with a = 9. 8m/s^2 comes out to be:(a) 980N(b) 580N(c) 1380N(d) zero
Answers
Answer:
(d) zero
Explanation:
Net acceleration = (a - g)
a is downward so it is positive
F(net) = ma(net)
F = 100 x (9.8 - 9.8)
F = 0
The correct option is (d).
the average energy released by the fission of a single atom of uranium-235 is approximately 205 mev. how much total energy would be released by the complete fission of 4.45 kg of u235 ? express your answer in units of joules. j a typical small town might use about 28.5 mw of power, on average. how long, in days, would it take this town to use the amount of energy produced by the complete fission of 4.45 kg of u235?
Answers
To find the total energy released by the complete fission of 4.45 kg of U-235, we can use the concept of energy per atom and multiply it by the number of atoms in 4.45 kg of U-235.
1. Calculate the number of moles of U-235:
Mass of U-235 = 4.45 kgMolar mass of U-235 = 235 g/molNumber of moles = Mass / Molar mass = 4.45 kg / (235 g/mol) = 0.0189 mol2. Calculate the number of atoms of U-235:
Avogadro's number (NA) = 6.022 × 10^23 mol^-1Number of atoms = Number of moles × NA = 0.0189 mol × (6.022 × 10^23 mol^-1) = 1.137 × 10^22 atoms3. Calculate the total energy released:
Average energy per atom = 205 MeV1 MeV = 1.602 × 10^-13 Joules (conversion factor)Total energy released = Average energy per atom × Number of atoms × Conversion factorTotal energy released = 205 MeV × 1.137 × 10^22 atoms × (1.602 × 10^-13 J/MeV) = 3.50 × 10^9 JoulesTherefore, the total energy released by the complete fission of 4.45 kg of U-235 is approximately 3.50 × 10^9 Joules.
Now, let's calculate how long a small town would take to use this amount of energy.
1. Determine the energy usage of the town:
Power usage = 28.5 MWConvert power to energy: 1 MW = 1 × 10^6 J/sEnergy usage per day = Power usage × 24 hours = 28.5 × 10^6 J/s × 24 hours = 684 × 10^6 J2. Calculate the number of days:
Number of days = Total energy released / Energy usage per dayNumber of days = (3.50 × 10^9 J) / (684 × 10^6 J/day) ≈ 5.11 daysTherefore, it would take approximately 5.11 days for the small town to use the amount of energy produced by the complete fission of 4.45 kg of U-235.
About MolesThe mole is a unit of account for chemistry. The unit of account is used to facilitate the calculation of an object. Count units commonly used in everyday life, for example 1 dozen equals 12 pieces, 1 gross contains 12 dozens, 1 ream equals 500 sheets of paper, 1 score equals 20 sheets of cloth. The mole concept is used to calculate the number of particles contained in a material. The particles of matter can be atoms, molecules and ions. Because the size of the atom is very small, the atomic mass is determined using a standard atom, namely carbon-12 (12C) as a comparison.
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A drag racer starts her car from rest and accelerates at 10.0 m/s2 for the entire distance of 400 m .how long did it take the race car to travel this distance in s? answer key
Answers
To travel a distance of 400 m the car will take a time of: 8.944 s
The formulas and procedures we will use to solve this exercise are:
vf = √ (vi² + 2 * a * x)t = (2 * x)/ (vi + vf)Where:
vf = final velocityx = distancet = timevi = initial velocitya = accelerationInformation about the problem:
vi = 0 m/sa = 10.0 m/s²x = 400 mvf =?t = ?Applying the final velocity formula we have:
vf = √ (vi² + 2 * a * x)
vf = √ ((0 m/s)² + 2 * 10.0 m/s² * 400 m)
vf = √ (0 m²/s² + 8000 m²/s²)
vf = √(8000 m²/s²)
vf = 89.44 m/s
Applying the time formula we have:
t = (2 * x)/ (vi + vf)
t = (2 * 400 m)/ (0 m/s + 89.44 m/s)
t = 800 m / 89.44 m/s
t = 8.944 s
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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(b) Earth rotates on its axis in 1 day. At what velocity is a person standing at the equator in the figure above (Person 1) moving due to our planet's rotation
Answers
Earth rotates on its axis in 1 day. The velocity of a person standing at the equator due to Earth's rotation 463 meters per second.
The velocity of a person standing at the equator due to Earth's rotation can be calculated by considering the circumference of the Earth at the equator and the time it takes for Earth to complete one rotation (which is approximately 24 hours or 86,400 seconds).
The circumference of a circle can be calculated using the formula: C = 2πr, where C is the circumference and r is the radius. For the Earth, the radius at the equator is approximately 6,378 kilometers or 6,378,000 meters.
So, the circumference of the Earth at the equator is:
C = 2π(6,378,000 meters) = 40,075,880 meters (approximately)
Since the Earth completes one rotation in 24 hours or 86,400 seconds, the velocity of a person standing at the equator can be calculated by dividing the distance traveled (circumference) by the time taken:
Velocity = Distance / Time
Velocity = 40,075,880 meters / 86,400 seconds
Calculating this gives us a velocity of approximately 463 meters per second. Therefore, a person standing at the equator is moving with a velocity of approximately 463 meters per second due to Earth's rotation.
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