A dog weighs 250 N. What is his approximate weight in pounds (lb)?
A. 250 lb.
B. 100 lb.
C. 55 lb.
D. 32 lb.
E. 25 lb.

Genes are the basic units of heredity. (Los genes son las unidades básicas de la herencia.)

A short stretch of ADN called a gene. The body's genes instruct it on how to produce particular proteins. About 20,000 genes are found in each human body cell. Together, they make up the genetic makeup of the human body and determine how it functions.

Fundamental unit of the inheritance from parents to children. The genes are constructed from ADN sequences and are arranged one after the other in certain locations within the chromosomal nuclei of cells.

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The hummingbird's total displacement would be approximately 2.52 meters.

To find the hummingbird's total displacement, we need to calculate the straight-line distance between the bird's starting point and its ending point, taking into account both the horizontal and vertical components of its motion.

The horizontal displacement is the distance the hummingbird travels along the straight path before dropping down. From the problem statement, we know this distance is 2.1 m.

The vertical displacement is the distance the hummingbird drops down to reach the flower. From the problem statement, we know this distance is 1.4 m.

To find the total displacement, we can use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle (i.e., the straight-line distance between the two endpoints) is equal to the sum of the squares of the other two sides. In this case, the two sides are the horizontal and vertical displacements, so we have:

total displacement = √(horizontal displacement² + vertical displacement²)

total displacement = √(2.1² + 1.4²)

total displacement = √(4.41 + 1.96)

total displacement = √6.37

total displacement ≈ 2.52 m

Therefore, the hummingbird's total displacement is approximately 2.52 meters.

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Answer:

1 millicoulomb = 1000000 nanocoulombs.

Explanation:

The SI unit for electric charge is Coulomb.

1 coulomb = 1000000000 nC (nanocoulombs)

1 coulomb = 1000 mC (millicoulombs)

Answer:

\( \Huge{\boxed{6.27 m/s²}} \)

Explanation:

The acceleration of the car given it's mass and the force acting on it can be found by using the formula

\( acceleration = \frac{force}{mass}\\ \)

From the question

force = 9079 N

mass = 1447 kg

We have

\( acceleration= \frac{9079}{1447}\\ = 6.27436 \)

We have the final answer as

Answer:

8.6348020882604e-23

Explanation:

Answer:

Nuclear reactors are the heart of a nuclear power plant. They contain and control nuclear chain reactions that produce heat through a physical process called fission. That heat is used to make steam that spins a turbine to create electricity.

Answer:

A nuclear power plant's heart is made up of nuclear reactors. They contain and regulate nuclear chain reactions, which produce heat via a physical process known as fission. This heat is converted to steam, which powers a turbine to generate energy.

The form(s) of energy does the original GPE was transformed is kinetic energy.

If an object is lifted, work is done against gravitational force. The object gains energy.

The equation for calculating gravitational potential energy is

GPE =mgh

where, GPE is the gravitational potential energy, m is the mass, h is the change in height and g is the acceleration due to gravity.

The potential energy is just opposite of the kinetic energy. When potential energy is lower, the kinetic energy is higher.

Thus, the original GPE was transformed into kinetic energy.

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A baseball player see a baseball flying through the air before he hears the crack of the ball on the bat because the sound is made as the ball flies through the air. The eyes react faster than ears. Light moves faster than sound.

The term light wave defined as the motion of light conceptualized as a wave, defined by such properties as reflection, refraction, and dispersion.

The light waves heavily traveled back from the sky, obtaining energy, and the sound waves traveled in a straight line, losing energy, making the sound to be delayed.

Thus, The eyes react faster than ears. Light moves faster than sound.

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Answer:

Balanced Forces

But what exactly is meant by the phrase unbalanced force? What is an unbalanced force? In pursuit of an answer, we will first consider a physics book at rest on a tabletop. There are two forces acting upon the book. One force - the Earth's gravitational pull - exerts a downward force. The other force - the push of the table on the book (sometimes referred to as a normal force) - pushes upward on the book.

Since these two forces are of equal magnitude and in opposite directions, they balance each other. The book is said to be at equilibrium. There is no unbalanced force acting upon the book and thus the book maintains its state of motion. When all the forces acting upon an object balance each other, the object will be at equilibrium; it will not accelerate.

Consider another example involving balanced forces - a person standing on the floor. There are two forces acting upon the person. The force of gravity exerts a downward force. The floor exerts an upward force.

Since these two forces are of equal magnitude and in opposite directions, they balance each other. The person is at equilibrium. There is no unbalanced force acting upon the person and thus the person maintains its state of motion.

Unbalanced Forces

Now consider a book sliding from left to right across a tabletop. Sometime in the prior history of the book, it may have been given a shove and set in motion from a rest position. Or perhaps it acquired its motion by sliding down an incline from an elevated position. Whatever the case, our focus is not upon the history of the book but rather upon the current situation of a book sliding to the right across a tabletop. The book is in motion and at the moment there is no one pushing it to the right. (Remember: a force is not needed to keep a moving object moving to the right.) The forces acting upon the book are shown below.

The force of gravity pulling downward and the force of the table pushing upwards on the book are of equal magnitude and opposite directions. These two forces balance each other. Yet there is no force present to balance the force of friction. As the book moves to the right, friction acts to the left to slow the book down. There is an unbalanced force; and as such, the book changes its state of motion. The book is not at equilibrium and subsequently accelerates. Unbalanced forces cause accelerations. In this case, the unbalanced force is directed opposite the book's motion and will cause it to slow down.

To determine if the forces acting upon an object are balanced or unbalanced, an analysis must first be conducted to determine what forces are acting upon the object and in what direction. If two individual forces are of equal magnitude and opposite direction, then the forces are said to be balanced. An object is said to be acted upon by an unbalanced force only when there is an individual force that is not being balanced by a force of equal magnitude and in the opposite direction.

I would choose the option B.

F = ma

a = 75 / 25 = 3 m/s^2

The acceleration of the given object will be equal to 3 m/s². Therefore, option (B) is correct.

Acceleration of an object can be explained as the change in the velocity of an object with respect to time. The acceleration is a vector quantity as it exhibits magnitude and direction. Acceleration can be calculated from the 2nd derivative of the position of the object w.r.t. time.

The force is the product of the mass and acceleration, according to Newton's second law of motion.

F = ma

And,   a = F/m

From the above formula, we ca say that the acceleration is inversely proportional to mass.

Given, the force acting on the object, F = 75 N

The mass of the object, m = 25.0 Kg

The acceleration of the given object, a = 75/25 =3 m/s²

Therefore, the acceleration of the object is equal to 3 m/s².

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Answer:

the sun energy comes from nuclea fution

Given that the direction sailboat is north and the distance traveled is d = 10 km

The direction of the wind is southeast and the force is

The sailboat travels the distance in time, t = 1 h

We have to find the work done by the wind and wind's power.

The diagram is shown below

The work done by the wind will be

The power of the wind will be

Important Formulas:

\(v=\lambda f\)

velocity(measured in m/s) = wavelength(measured in meters) * frequency(measured in hertz)

\(f=\dfrac{1}{T}\)

frequency(measured in hertz) = 1 / period(measured in seconds)

__________________________________________________________

Given:

\(v=362m/s\)

\(T=4.17s\)

\(\lambda=?\)

__________________________________________________________

Finding frequency:

\(f=\dfrac{1}{T}\)

\(f=\dfrac{1}{4.17}\)

\(f=0.24Hz\)

__________________________________________________________

Rearranging formula for velocity to make wavelength the subject:

\(v=\lambda f\)

\(\dfrac{v}{f} =\dfrac{\lambda f}{f}\)

\(\lambda=\dfrac{v}{f}\)

__________________________________________________________

Finding wavelength:

\(\lambda=\dfrac{v}{f}\)

\(\lambda=\dfrac{362}{0.24}\)

__________________________________________________________

\(\boxed{\lambda=1508.33m}\)

The total angle, in radians, through which a point on the flywheel rotates is 7540 radians

From the question, we are to determine the total angle in radians

Using the formula,

\(\omega = \frac{\theta}{t}\)

Where \(\omega\) is the angular velocity

\(\theta\) is the angle

and t is the time

From the given information,

\(\omega = 30 \ rev/s\)

Convert to rad/s

\(\omega = 30 \times 2\pi \ rad/s\)

\(\omega = 188.496 \ rad/s\)

and t = 40 s

From the formula

\(\omega = \frac{\theta}{t}\)

\(\theta = \omega t\)

∴ \(\theta = 188.496 \times 40\)

θ = 7539.822 rad

θ ≅ 7540 rad

Hence, the total angle, in radians, through which a point on the flywheel rotates is 7540 radians

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a) The motion of the object between 15 s to 30 s is increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is 0.167 m/s.

(c) The position of the object at 5.0 seconds is 0.5 m.

(d) Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

(a) The motion of the object between 15 s to 30 s can be described as increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is calculated as;

average velocity = total displacement / total time

average velocity = (2.5 m - 0 m ) / ( 15 s - 0 s ) = 0.167 m/s

(c) The position of the object at 5.0 seconds is calculated as follows;

at 5.0 seconds, the position of the object is traced from the graph as 0.5 m.

(d) The motion of the object between 30 and 40 seconds is calculated as;

velocity = ( 0 m - 4 m ) / ( 40 s - 30 s ) = - 0.4 m/s

Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

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Answer:

the current flowing in the circuit is 0.1 A.

Explanation:

Given;

potential difference, V = 12 V

resistance of the circuit, R = 120 ohms

The current flowing in the circuit is calculated as;

V = IR

I = V/R

where;

I is the current flowing in the circuit

I = 12 / 120

I = 0.1 A

Therefore, the current flowing in the circuit is 0.1 A.

Answer:

15 m/s

Explanation:

Speed(m/s) = distance(m)/time(s)

distance = 216 km = 216,000 m

time = 4 hours = 14,400 s

speed = 216000/14400 = 15 m/s

Answer:

V=S/T

V=216km/4hr

V=54km/hr

Explanation:

1km/hr = 5/18 m/s

54km/hr= X

X=5/18m/s * 54km/hr

         1km/hr

X=15m/s(approximately)

Explanation:

Particle moving in a circular path with a constant speed.

Explanation:

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. ... The gravitational potential energy is equal to its weight times the height to which it is lifted. PE = kg x 9.8 m/s2 x m = joules. The 9.8 us the gravitational acceleration constant.

so the answer is "the gravitational potential energy is decreasing"

The two-dimensional curl of the vector field F(x, y) = (-2xy, x²) is computed to be 4x - 2. The region R bounded by y = 0 and y = x(2-x) is sketched as a triangular region in the xy-plane. By applying Green's Theorem in the circulation form, the integrals are evaluated and shown to be equal, confirming the consistency of the computations.

(a) To compute the two-dimensional curl of the vector field F(x, y) = (-2xy, x²), we need to find the partial derivatives of the components of the vector field and take their difference. The curl is given by the expression:

\(\[\nabla \times \textbf{F} = \left( \frac{\partial}{\partial x} (x^2) - \frac{\partial}{\partial y} (-2xy) \right) \textbf{i} + \left( \frac{\partial}{\partial y} (-2xy) - \frac{\partial}{\partial x} (x^2) \right) \textbf{j}\]\)

Simplifying this expression yields:

\(\[\nabla \times \textbf{F} = (0 - (-2x)) \textbf{i} + (4x - 0) \textbf{j} = 2x \textbf{i} + 4x \textbf{j} = \boxed{2x \textbf{i} + 4x \textbf{j}}\]\)

(b) The region R is bounded by the y-axis (y = 0) and the curve y = x(2-x). Sketching this region in the xy-plane, we find that it forms a triangular region with vertices at (0, 0), (1, 0), and (2, 0).

(c) Applying Green's Theorem in the circulation form, which states that the line integral of a vector field around a closed curve is equal to the double integral of the curl of the vector field over the region enclosed by the curve, we can evaluate both integrals. Let C be the boundary of the region R.

Using the circulation form of Green's Theorem, the line integral becomes:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (\nabla \times \textbf{F}) \cdot d\textbf{A}\]\)

The first integral is evaluated over the boundary curve C, and the second integral is evaluated over the region R. Substituting the given vector field and the computed curl, we have:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (2x \textbf{i} + 4x \textbf{j}) \cdot d\textbf{A}\]\)

Integrating this expression over the triangular region R will yield a specific result. By evaluating both integrals, it can be verified that they are equal, confirming the consistency of the computations.

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Answer: The battery in circuit 3 would run out more quickly when the switches are closed because the two bulbs are brighter, which means the battery is providing more energy to that circuit.

Explanation: Answer from plato

Answer:

100 ml de una disolucion 05 M de sulfate de vivre

The deflection when a 40 kg child stands at the end of the board is c) 4.6 cm.

The deflection of a springboard depends on the weight or mass applied to it. In this case, we are given that a 69 kg man causes the board to deflect by 8.0 cm. Since the deflection is directly proportional to the weight, we can use this information to find the deflection caused by a 40 kg child.

By setting up a proportion, we can determine the relationship between the weights and deflections:

69 kg / 8.0 cm = 40 kg / x

Cross-multiplying and solving for x, we find:

x = (40 kg * 8.0 cm) / 69 kg ≈ 4.6 cm

Therefore, The correct answer is C. The deflection when a 40 kg child stands at the end of the board is 4.6 cm

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We cannot determine the speed at which a star in the galaxy is moving away from us based on its mass, luminosity, age, or color alone. it is false

The speed at which a star in the galaxy is moving away from us is determined through the measurement of its spectrum using a technique known as redshift.

When a star or galaxy moves away from us, its light is shifted towards longer wavelengths, resulting in a redshift. By analyzing the degree of redshift, astronomers can estimate the speed at which the star is receding.

However, factors such as mass, luminosity, age, and color do not provide direct information about the star's motion away from us.

These characteristics are important for studying other properties of stars, such as their composition, brightness, evolutionary stage, and temperature. To determine the motion of a star in the galaxy, redshift measurements are essential.

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Answer:

It will roll 9 meters in 3 seconds

Explanation:

3 m/s times 3 is 9

Thanks for warning me.

I'll be careful to stay out of its way.

Do you have a question to ask ?

Answer:

3km? im a beginner

The slope of position versus time graph represent the velocity.

position vs. time graph attached below.

In a position-time graph, the velocity of the moving object is represented by the slope of the graph line.

So, the position vs. time graph for a person walking at a  constant speed of 1 m/s for 10 seconds will be a straight line having slope of 1 in the interval of 0 to 10 seconds.

Similarly,  the position vs. time graph for a person walking at a  constant speed of 4 m/s for 10 seconds will be a straight line having slope of 4 in the interval of 0 to 10 seconds.

Graph attached below.

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