A falcon flew 70 miles in 3 hours. What was the speed of the falcon? speed = distance over time ; 1 mile = 1609 meters the answer is not 23.3

Answer:

the answer is d(the last one

Step-by-step explanation:

160+25m=40+65m

the sign up fee plus how much each month

The solution to the given integral equation using the fundamental theorem of calculus is \(y(x) = (-(1/2) x^4 + (3/4)) e^(-3/2 x^2) + C e^(-3/2 x^2)\)

Given expression;

\(y(x) = 4 - ∫0^(2x) 3t - ty(t) dt\)

According to fundamental theorem of calculus, we have;

d/dx ∫\(a^x\) f(t) dt = f(x)

Take derivative of both sides of the equation with respect to x;

y'(x) = \(-2x^3 - 3xy(x)\)

y'(x) + 3xy(x) = \(-2x^3\)  (Rearranged)

At this stage, use integrating factor, hence;

u(x) = \(e^(3/2 x^2)\)

Multiply both sides by u(x)

u(x)y'(x) + 3xu(x)y(x) = -\(2x^3u(x)\)

Since the left-hand side is the product rule of (u(x)y(x))', we can write;

(u(x)y(x))' = -\(2x^3u(x)\)

No integrate both sides with respect to x

u(x)y(x) = ∫ -\(2x^3u(x)\) dx + C

where C is a constant of integration.

Evaluate the integral using integration by parts;

∫\(-2x^3u(x) dx\) = (-1/2) ∫ \(u(x) d(x^4) = (-1/2) u(x) x^4 + (1/2)\) ∫ \(x^4\) du(x)

=\((-1/2) e^(3/2 x^2) x^4 + (3/4) e^(3/2 x^2) + K\)

where K is also constant in the integration.

By substituting this back into the equation for u(x)y(x), we have;

y(x) = \((-(1/2) x^4 + (3/4)) e^(-3/2 x^2) + C e^(-3/2 x^2)\)

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Answer:

In the picture, the first five terms are highlighted

This is a geometric sequence

Step-by-step explanation:

This is a geometric sequence because it has a common ratio, unlike arithmetic where it has a common difference.

The isolated value of h is found to be V/πr²

The three-dimensional solid shape of a cylinder is made up of two parallel bases connected by a curved surface. These bases have the shape of a spherical disc. The axis of the cylinder is a line drawn through the centre or connecting the centres of two circular bases. The density of a cylinder is determined by its volume, which represents how much material may be immersed in it or carried inside of it. The formula πr²h, where r is the radius of the circular base and h is the height of the cylinder, determines the volume of a cylinder. Any substance that can fill the cylinder consistently with liquid or another material may be used as the component.

According to given formulae:

V=πr²h

On dividing both side with πr² we get

⇒V/πr²=πr²h/πr²

(Solving R.H.S)

⇒h=V/πr²

Therefore, the value of h in the given question is V/πr²

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The system of linear equations is found to be inconsistent when k = √3 or k = -√3.

The given system of linear equations is:

kx + ky = 1 (1 k)

x+ ky = 3

Using Cramer's rule to solve the system of linear equations:

x = Dx/Dy,

y = Dy/Dx

Where,

Dx = |1 k|

           |3 k|

          = (1 x k) (3 x k) - (k x k)

           = 3 - k²

Dy = |1 k|

          |1 k|

         = (1 x k) - (k x 1)

            = k - 1

Substituting Dx and Dy in the formula,

x = Dx/Dy

= (3 - k²)/(k - 1),

y = Dy/Dx

= (k - 1)/(3 - k²)

The condition(s) on k such that the system is inconsistent is/are:

When k² = 3, then the denominator of x is 0.

Hence, the system of linear equations is inconsistent when k = √3 or k = -√3.

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Answer:

56

Step-by-step explanation:

56 would be the arc. reasoning is because line CG form an arch of 56 and Angle A and C also form a angle of 34

Step-by-step explanation:

If u assume x=y=1, then x+y=2 and x^2+y^2=2

And now, xy=1.

Therefore x=y=1.

Let me know, if anyone come with other answers too.

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Step-by-step explanation:

(*) x^2 + y^2 - 2xy = 64

<=> (x - y)^2 = 64

<=> x - y = 8 or x - y = -8

(**) x^2 - y^2 = 40

<=> (x - y)(x + y) = 40

Case 1: x - y = 8

(**) <=> 8(x + y) = 40

<=> x + y = 5

we have: x+y = 5 and x-y = 8

--> x = (5+8)/2 = 6.5

--> y = x - 8 = 6.5 - 8 = -1.5

so (x,y) = (6.5 , -1.5)

Case 2: x - y = -8

(**) <=> -8(x + y) = 40

<=> x + y = -5

we have: x + y = -5 and x - y = -8

--> x = [ (-5) + (-8) ]/2 = -6.5

--> y = -5 - x = -5 + 6.5 = 1.5

so (x,y) = (-6.5 , 1.5)

Answer: (x,y) = (6.5 , -1.5) and (-6.5 , 1.5)

Answer:

The change in temperature is -6.64

The average hourly rate of change is

6 hours or -3.32

Answer:

An equation of the line that passes through the points (0, -6) and (-5, -2) can be found using the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope of the line and b is the y-intercept (the point at which the line crosses the y-axis).

To find the slope of the line, you can use the formula:

m = (y2 - y1) / (x2 - x1)

Plugging in the given points, you get:

m = (-2 - (-6)) / (-5 - 0) = 4 / -5 = -4/5

The y-intercept is the point (0, -6), so the equation of the line in slope-intercept form is:

y = (-4/5)x - 6

This is the equation of the line that passes through the points (0, -6) and (-5, -2).

Answer:

46 degrees

Step-by-step explanation:

Angles 3 and 7 are corresponding angles which also means that they are congruent. Since they are congruent, angle 7 is also 46 degrees.

Answer:

(a) -8°C, -8°C, -4°C, -2°C, 1°C

(b) -13°C, -7°C, -2°C, 4°C, 4°C, 13°C

(c) -7°C, -6°C, -4°C, 0°C, 6°C

Answer:

37

Step-by-step explanation:

Answer:

37

Step-by-step explanation:

You can use absolute value to solve this. l-12l+l25l=12+25=37

Absolute value is the distance from 0.

The required value of x is 125° for the given pentagon.

The external angle of a pentagon is formed by extending one of its sides, and it is supplementary to the adjacent interior angle of the pentagon.

According to the given figure,

We have been given that a pentagon, which has five sides is shown.

As we know that the sum of the external angles of any polygon is always 360 degrees.

So, x° + 40° + 65° + 60° + 70° = 360°

x° + 235° = 360°

x° = 360° - 235°

Apply the subtraction operation, and we get

x = 125°

Therefore, the required value of x is 125°.

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Answer:

.2 Cm

Step-by-step explanation:

Angles in 59 non-similar triangles having degree measures that are integers via arithmetic progression.

Let the summation of the angle values be: Using arithmetic progression & triangle knowledge, letting the sum of the angle values be:

∑degree = 180

For an odd arithmetic progression with a strange number of words, the median term is equivalent to the average of both the sum of all terms:

An arithmetic sequence's nth term,

Let the initial triangle angle =a

Let d be a common difference.

Because the angles' measurements follow an arithmetic progression \(T_{n}\) = a + (n - 1) × d

a + (a + d) + (a + 2d) = 180

3a+3d=180

a+d=60

Because an or d cannot be identical to zero, the minimum and maximum possible values for a and d are 1 and 59, respectively.

As a result, there are 59 distinct triangles.

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The pie chart accurately represents the data from the poll, as it accurately shows the proportion of people who agreed with each candidate's positions.

The pie chart presents a good representation of the data from the poll taken asking people if they agreed with the positions of the 4 candidates for a county office. This is because the pie chart accurately shows the proportion of people who agreed with each candidate's positions. For example, the chart indicates that 26% of the people agreed with Candidate A's positions, 28% agreed with Candidate B's positions, 29% agreed with Candidate C's positions, and 17% agreed with Candidate D's positions. In order to calculate the proportions, the total number of people who responded to the poll was divided by each individual candidate's number of supporters. For example, for Candidate A, the proportion of people who agreed with their positions was calculated by dividing the total number of people responding to the poll (100) by the number of people who agreed with Candidate A's positions (26), resulting in a proportion of 0.26 or 26%. This same approach was used to calculate the proportions of each candidate's supporters. Therefore, the pie chart accurately presents the data from the poll and is a good representation of the data.

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Answer:

I don't know. Make your question clearer, please.

Step-by-step explanation:

Company A has a higher risk percentage (55%) compared to Company B (3%).

To compute the Coefficient of Variation (CV) for each company, we need to use the formula:

CV = (Standard Deviation / Mean) * 100

Let's calculate the CV for each company:

For Company A:

Risk Percentage = 55%

Return = 14%

For Company B:

Risk Percentage = 3%

Return = 14%

Since we don't have the standard deviation values for each company, we cannot calculate the exact CV. However, we can still compare the riskiness of the two companies based on the provided information.

The Coefficient of Variation measures the risk relative to the return. A higher CV indicates higher risk relative to the return, while a lower CV indicates lower risk relative to the return.

In this case, Company A has a higher risk percentage (55%) compared to Company B (3%), which suggests that Company A is riskier. However, without the standard deviation values, we cannot make a definitive conclusion about the riskiness based solely on the provided information. The CV would provide a more accurate measure for comparison if we had the standard deviation values for both companies.

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Answer:

c≤8

Step-by-step explanation:

Let c be the number of copies that you can make

Each copy is 25 cents or .25

It must be less than or equal to 2 dollars

.25c ≤2.00

Divide each side by .25

.25c/.25 ≤ 2.00/.25

c≤8

P(X ≤ 4) by using the Cumulative Poisson Probabilities table in : P(X ≤ 4) = 0.785.

In this problem, we are given that the number of failures X in a cast-iron pipe of a particular length follows a Poisson distribution with an expected value (mean) of μ = 1.

To find P(X ≤ 4), we need to calculate the cumulative probability up to 4, which includes the probabilities of 0, 1, 2, 3, and 4 failures. We can use the Cumulative Poisson Probabilities table in the Appendix of Tables to find the cumulative probabilities.

From the table, we can look up the values for each number of failures and add them up to find P(X ≤ 4).

The cumulative probabilities for each value of k are:

P(X = 0) = 0.367

P(X = 1) = 0.736

P(X = 2) = 0.919

P(X = 3) = 0.981

P(X = 4) = 0.996

P(X ≤ 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.367 + 0.736 + 0.919 + 0.981 + 0.996 = 0.785

Therefore, P(X ≤ 4) is approximately 0.785 (rounded to three decimal places).

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Complete question

The article "Expectation Analysis of the Probability of Failure for Water Supply Pipes"† proposed using the Poisson distribution to model the number of failures in pipelines of various types. Suppose that for cast-iron pipe of a particular length, the expected number of failures is 1 (very close to one of the cases considered in the article). Then X, the number of failures, has a Poisson distribution with μ = 1. (Round your answers to three decimal places.)

(a) Obtain P(X ≤ 4) by using the Cumulative Poisson Probabilities table in the Appendix of Tables. P(X ≤ 4) =

The answer for the equation:

7x+31 = 8x -1/3(27x+3) is x=-4

Answer: C

Step-by-step explanation:

The width of the larger cell phone: \(W_{2}=\frac{(W_{1} *L_{2})}{L_{1} }\)

Length is a measure of the size of an object in one dimension. It refers to the distance between two points, usually measured in units such as meters, feet, inches, or centimetres.

Width is a measure of the size of an object in one dimension, specifically the distance between its two sides that are parallel to each other. It is usually considered the shorter of the two dimensions, the other being length.

Since the length and width of the two cell phones are proportional, we can express this relationship using a proportion. Let \(L_{1}\) and \(W_{1}\) be the length and width, respectively, of the smaller cell phone, and let \(L_{2}\) and \(W_{2}\) be the length and width, respectively, of the larger cell phone. Then we have:

\(\frac{L_{1} }{W_{1} } =\frac{L_{2} }{W_{2} }\)

We can rearrange this equation to solve for the width of the larger cell phone:

\(W_{2}=\frac{(W_{1} *L_{2})}{L_{1} }\\\)

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Answer:

y = 4x + 2

Step-by-step explanation:

This is the formula:  \(y - y_{1} = m(x - x_{1})\)

y - 2 = 4(x - 0) (distribute the 4)

y - 2 = 4x (add 2 on both sides)

y = 4x + 2

That's all she wrote!

Hope this helps ya!!

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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