A Ford passes a Toyota on the road (both vehicles are traveling in the same direction). The Ford moves at a constant speed of 33.6 m/s. Just as the Ford passes it, the Toyota is traveling at 23.4 m/s. As soon as the Ford passes the Toyota, the Toyota begins to accelerate forward at a constant rate. Meanwhile the Ford just keeps going at a steady 33.6 m/s to the east. The Toyota catches up to the Ford a distance of 110.2 m ahead of where the Ford first passed it. What was the magnitude of the Toyota s acceleration? 2.6 m/s^2 3.1 m/s^2 1.3 m/s^2 6.2 m2

The change of kinetic energy is -156.7 joules.

\(V1_{i}\) =15

\(V2_{i}\)= -13.5(as towards left)

V= common velocity during collision

On applying momentum conservation during the collision

\(m_{1}V1_{i} + m_{2}V2_{i} = V ( m_{1} + m_{2})\)

\(0.650 \ 15 + 0.950 \ (-13.5) = (0.625 + 0.950) \ V\)

    \(\frac{3.075}{1.6}\) =V

V= -1.92 m/s        

To kind change in kinetic energy we will subtract final and initial kinetic energy

ΔK=\(\frac{1\ (m_{1} + m_{2} ) \ V}{2} ^{2}\) - \(\frac{1\ (m_{1} ) \ V1_{i} }{2} ^{2}\)  -  \(\frac{1\ (m_{2} ) \ V2_{i} }{2} ^{2}\)

ΔK= \(\frac{1\ (0.625 + 0.950 ) \ (-13.5)}{2} ^{2}\) -  \(\frac{1\ (0.625 ) \ 15 }{2} ^{2}\)-  \(\frac{1\ (0.950 ) \ 13.5 }{2} ^{2}\)

ΔK=   = - 156.7 J

Learn more about Kinetic energy

brainly.com/question/26472013

#SPJ4

Answer:

\(20\; {\rm m\cdot s^{-1}}\), assuming that friction is negligible.

Explanation:

If an object of mass \(m\) moves at a velocity of \(v\), the momentum \(p\) of this object would be \(p = m\, v\).

if friction is negligible, the sum of the momentum should be the same before and after the collision.

Before the collision:

In other words, the sum of momentum was \(40\; {\rm kg\cdot m\cdot s^{-1}}\) before the collision.

After the collision:

The sum of the momentum stays unchanged at \(40\; {\rm kg\cdot m\cdot s^{-1}}\). Subtract the momentum of the ice skater from the sum to find the momentum of the snowman:

\(40\; {\rm kg\cdot m\cdot s^{-1}} - 0\; {\rm kg\cdot m\cdot s^{-1}} = 40\; {\rm kg\cdot m\cdot s^{-1}}\).

Divide the momentum of the snowman by its mass to find its velocity:

\(\begin{aligned}\frac{40\; {\rm kg\cdot m\cdot s^{-1}}}{2\; {\rm kg}} = 20\; {\rm m\cdot s^{-1}}\end{aligned}\).

In other words, the collision of the snowman would be \(20\; {\rm m\cdot s^{-1}}\) after the collision.

The yellow red stain that occurs on some rock surfaces is the result of Oxidation Form of weathering

A molecule, atom, or ion undergoes oxidation when it loses electrons as a result of a process.

When a molecule, atom, or ion's oxidation state is raised, oxidation takes place. When there is an increase in electrons or a drop in an atom, molecule, or ion's oxidation state, the process is known as reduction.

According to the given information

When you see crimson stains on rock, you are looking at the results of oxidation, which is when oxygen causes chemical changes. Steel and other iron-containing materials oxidise, which sets off a chemical reaction that causes the material to rust. Similar chemical weathering occurs in rocks.

The yellow red stain that occurs on some rock surfaces is the result of Oxidation Form of weathering

To know more about Oxidation

https://brainly.com/question/9496279

#SPJ4

Answer:

A

Explanation:

The amount of time necessary for half of anything to go through a process, such the amount of time needed for half of a radioactive substance's atoms to decay. Thus, option A is correct.

The period of time it takes for one-half of a radioactive isotope to decay is known as the half-life. An individual radioactive isotope's half-life is unaffected by environmental factors and is independent of the isotope's starting concentration.

Radiation emission stops after an atom achieves energy stability through radiation. A radionuclide's concentration falls over time, and its radioactivity declines. A (physical) half-life is the length of time required for radioactivity to degrade and diminish to half.

Therefore, The time it takes for half the parent nuclei in a sample to become daughter nuclei.

Learn more about isotope here:

https://brainly.com/question/28039996

#SPJ5

Answer:

Harmful bacteria are called pathogenic

Explanation:

Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.

Here are the observations

Sugar:-

Corn syrup:-

Oil:-

The strength of the magnetic force is inversely proportional to the square of distance between the magnets. Thus, as the distance increases, force between the magnets decreases.

Magnetic force, is the force generated by magnetic flux lines arised from a magnetic field.  A magnet have a south pole and north pole. There will be repulsive force between two like poles and attractive force between two unlike pole.

The force between two objects is always in inverse proportion with the distance and this is well explained by Coulomb's law of forces.

Thus, F ∝ 1/r² where, r is the distance.

Therefore, as the distance between two magnets increases the magnetic force between them decreases.

To find more on magnetic force, refer here:

https://brainly.com/question/3160109

#SPJ1

The area of the shaded region is 4621.5 cm2 - 1083.8 cm2 = 3537.7 cm.

Area is the space or size of a two-dimensional surface or shape. It is a measure of the size of a surface and is typically expressed in square units, such as square feet or square meters. Area is usually calculated by multiplying the length of a shape by its width. For example, the area of a rectangle with a length of 4 feet and a width of 3 feet is 12 square feet. Area can also be calculated for shapes with curved sides such as circles, triangles, and other polygons.

The shaded region is the area between the two circles. To calculate the area of the shaded region, we need to subtract the area of the inner circle from the area of the outer circle.

The area of the outer circle can be calculated using the formula A = πr2, where r is the radius of the circle. Since the two circles have the same center, the radius of the outer circle is twice the radius of the inner circle.

Therefore, the radius of the outer circle is 2 × (117.436/2π) = 38.212 cm.

The area of the outer circle is A = π × 38.212^2 = 4621.5 cm2.

The area of the inner circle can be calculated using the same formula: A = πr2. The radius of the inner circle is (117.436/2π) = 18.606 cm.

The area of the inner circle is A = π × 18.606^2 = 1083.8 cm2.

To learn more about area

https://brainly.com/question/28012687

#SPJ9

Answer:

El coeficiente de roce estático entre las dos superficies es 0.131.

Explanation:

El coeficiente de roce estático entre dos superficies (\(\mu_{s}\)), sin unidad, es igual a la fuerza de resistencia (\(F\)), en newtons, dividida por el peso del cuerpo a mover (\(W\)), en newtons.

\(\mu = \frac{F}{m\cdot g}\) (1)

Donde:

\(m\) - Masa, en kilogramos.

\(g\) - Aceleración gravitacional, en metros por segundo al cuadrado.

Si sabemos que \(F = 45\,N\), \(m = 35\,kg\) y \(g = 9.807\,\frac{m}{s^{2}}\), entonces el coeficiente de roce estático es:

\(\mu = \frac{45\,N}{(35\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}\)

\(\mu = 0.131\)

El coeficiente de roce estático entre las dos superficies es 0.131.

Answer:

Explanation:

Work done in lifting the weight once = mgh

= 20 x 9.8 x (1.9+1.7)

= 705.6 J  

= 705.6 / 4.2 calorie

= 168 cals

Total energy to be spent = 600 x 10³ cals

No of times weight is required to be lifted

= 600 x 10³ / 168

= 3.57  x 10³ times

Total time to be taken = 2 x 3.57 x 10³

= 7.14 x 10³ s

=119 minutes .

The strength of the electric field can be calculated using Coulomb's Law, which states that the magnitude of the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Thus, we have:

Electric field strength = (k * Q) / r^2

where k is the Coulomb's constant, Q is the magnitude of the charge, and r is the distance between the charges.

Substituting the given values, we get:

Electric field strength = (9.0 × 10^9 N·m^2/C^2) * (0.20 C) / (0.8 × 10^-3 m)^2

Electric field strength = 1.13 × 10^12 N/C

Therefore, the electric field strength that the negative charge experiences is 1.13 × 10^12 N/C.

The electric field strength at a point is a measure of the force that a unit positive charge would experience at that point. It is a vector quantity that has both magnitude and direction. The SI unit of electric field strength is newtons per coulomb (N/C).

In this problem, we are given the magnitudes of two charges and the distance between them. We need to find the electric field strength experienced by a third charge at a certain distance from one of the charges. Coulomb's Law provides us with a formula to calculate this electric field strength.

The formula tells us that the electric field strength is proportional to the product of the charges and inversely proportional to the square of the distance between them. This means that if the charges are increased, the electric field strength will also increase. Similarly, if the distance between the charges is increased, the electric field strength will decrease. Substituting the given values into the formula, we can calculate the electric field strength. The answer we obtain is in N/C, which tells us how much force a unit positive charge would experience at the given point. The negative charge in the problem experiences a force in the opposite direction to the electric field, as it has an opposite charge to the positive charge.

learn more about electric field at :

https://brainly.com/question/15800304

#SPJ4

The kinetic energy (KE) of the emitted photoelectrons in the Sodium surface will be: lower compared to the KE of the photoelectrons in the Potassium surface.

The work function of a material is the minimum amount of energy required to remove an electron from its surface. If the work function of Sodium is greater than that of Potassium, it means that Sodium requires more energy to remove electrons compared to Potassium.

When photons of the same wavelength are incident on both surfaces, the energy of the photons is given by E = hf, where h is Planck's constant and f is the frequency of the photons (related to the wavelength).

For the photoelectric effect to occur, the energy of the incident photons must exceed the work function of the material. Since Sodium has a higher work function than Potassium, it will require photons with higher energy to exceed its work function and emit photoelectrons.

Therefore, the photons incident on the Sodium surface, despite having the same wavelength as those incident on the Potassium surface, will have lower energy. As a result, the kinetic energy of the emitted photoelectrons in the Sodium surface will be lower compared to the kinetic energy of the photoelectrons in the Potassium surface.

To know more about kinetic energy (KE), refer here:

https://brainly.com/question/29799215#

#SPJ11

The parts found in an electric generator for the conversion of electric energy into other forms of energy such as mechanical or chemical energy are an armature, a permanent magnet, an electromagnet brushes, and slip rings.

An electric generator is a device that converts motive power into electric power for use in an external circuit.

Parts of electric generators include the following;

These parts of electric generator helps in the generation of electricity or conversion of electric energy into mechanical energy or light energy or chemical energy.

Thus, the parts found in an electric generator for the conversion of electric energy into other forms of energy such as mechanical or chemical energy are an armature, a permanent magnet, an electromagnet brushes, and slip rings.

Learn more about electric generators here: https://brainly.com/question/12475693

Answer:

armature

permanent magnet

electromagnet

brushes

slip rings

Explanation:

edge 2022-2023

Answer:

Hey baby, I love you. Yes i do play metal gear with snake

Explanation:

Answer:

Yes me too. I have played.

Explanation:

Grant sprinted for 16.67 seconds when his average speed was 3.0 m/s.

With an average speed of 3.0 m/s, Grant sprints 50 meters to the right.

So, the distance covered (s)  = 50 m

Average speed (v) = 3.0 m/s

Now,

The formula for evaluating the time(t) is given by,

\(t = \frac{s}{v}\)

Now, Putting all the values in the formula to evaluate time, we get:

\(t = \frac{50}{3} = 16.67\)

Hence, Grant sprinted for 16.67 seconds.

To read more about average speed, visit https://brainly.com/question/12322912

#SPJ1

Answer:

The thrust that you feel at the time of firing is one of the real-life example of the conseriation nomentum

If the impulse of a particular force is represented by the symbol J, then:
(a) the momentum is equal to J.
(b) the change in momentum is also equal to J.
(c) J is equal to the product of F and Δt.

(d) The force is equal to the change in momentum divided by the time interval over which the force acts.

(a) Momentum: Impulse (J) is equal to the change in momentum (Δp). So, if you know the impulse, you can find the momentum before and after the application of force.

(b) Change in momentum: As mentioned above, the change in momentum (Δp) is equal to the impulse (J).

(c) Force: Impulse (J) is also equal to the product of force (F) and the time interval (Δt) during which the force is applied. To find the force, you can use the equation J = F × Δt, and you'll need to know the time interval.

(d) Change in force: The change in force would require additional information, such as the initial and final force acting on the object, or the relationship between force and time. The impulse is equal to the change in momentum, and the force is equal to the change in momentum divided by the time interval over which the force acts.

For more such questions on Impulse.

https://brainly.com/question/16980676#

#SPJ11

The legal verilog identifiers among the given options are:  a_123 and _a123.

Identifiers are described as the names of variables and other elements in verilog code that can be any letter or digit may be used, also the _underscore and $ characters are used and the  Identifiers must not begin with a digit and it should not be a verilog keyword.

In Verilog, legal identifiers follow certain rules as shown below:

The  options, 123a, a123_, c1 c2, and $and1, are not legal Verilog identifiers because they do not follow the rules mentioned above.

Learn more about legal identifiers  at:

https://brainly.com/question/24760562

#SPJ4

The following Verilog identifiers are legal:

a_123

a123

_c1c2

$and1

Verilog Identifiers are an identifier is a name used to identify an object in a program. The rules for Verilog identifiers are as follows:

An identifier is a string of characters that begins with a letter of the alphabet or an underscore.

It is followed by a string of letters, digits, or underscores.

The maximum length of an identifier is 1024 characters.

The following Verilog identifiers are legal:

a_123

a123

_c1c2

$and1

Therefore, the answer to the question "Which of the following are legal Verilog identifiers?" is:

a_123

a123

_c1c2

$and1

Learn more about verilog

https://brainly.com/question/32096172

#SPJ11

Answer:

125.44 N

Explanation:

From the question given above, the following data were obtained:

Weight on earth = 784 N

Acceleration due to gravity of the moon (gₘ) = 1.6 m/s²

Weight on moon =?

Next, we shall determine the mass of the person. This can be obtained as follow:

Weight on earth (Wₑ) = 784 N

Acceleration due to gravity of earth (gₑ) = 10 m/s²

Mass (m) =?

Wₑ = m × gₑ

784 = mass × 10

Divide both side by 10

Mass = 784 / 10

Mass = 78.4 Kg

Finally, we shall determine the weight of the person on moon. This can be obtained as follow:

Mass (m) = constant = 78.4 Kg

Acceleration due to gravity of the moon (gₘ) = 1.6 m/s²

Weight on moon (Wₘ) =?

Wₘ = m × gₘ

Wₘ = 78.4 × 1.6

Wₘ = 125.44 N

Therefore, the weight of the person on moon is 125.44 N.

The speed acquired by the body is 49m/s and 59m/s respectively.

The speed can be calculated using the formula:

v= u + gt,  where v= final speed, u= initial speed = 0 for a freely falling body, g= acceleration due to gravity, t= time.

The speed acquired by a freely falling object 5 seconds after being dropped from a rest position is 49 m/s. This is because an object dropped from rest will accelerate at a rate of 9.8 m/s², so after 5 seconds it will be moving at a speed of 5 * 9.8 = 49 m/s.

The speed 6 seconds after being dropped from a rest position is approximately 59 m/s. This is because an object dropped from rest will accelerate at a rate of 9.8 m/s², so after 6 seconds it will be moving at a speed of 6 * 9.8 = 58.8 m/s.

In summary, the speed of an object dropped from rest 5 seconds after being dropped is 49 m/s, and 6 seconds after it is approximately 59 m/s.

To know more about speed, refer here:

https://brainly.com/question/17661499#

#SPJ11

If you see a displayed diver-down flag while boating, it is necessary to maintain a certain distance from the flag for safety reasons. The specific distance may vary depending on local regulations and circumstances, but it is generally recommended to stay at least 100 feet away from the flag.

A diver-down flag is used to indicate the presence of divers in the water. Its purpose is to alert boaters to the potential hazards and to ensure the safety of the divers. The exact distance you must stay away from the flag may be specified by local laws or regulations, so it is important to familiarize yourself with the rules of the area you are boating in.

In many places, a common guideline is to stay at least 100 feet away from the diver-down flag. This distance allows for a safe buffer zone to prevent any accidental collisions or disturbances to the divers. However, it's crucial to check and adhere to the specific regulations in your boating location, as they may vary and could require a different distance to be maintained. Prioritizing safety and respecting the presence of divers is essential to avoid any accidents or harm to both boaters and divers.

Learn more about distance here: https://brainly.com/question/29769926

#SPJ11

Answer:

323.4N

Explanation:

Given parameters:

Mass of the box = 33kg

Unknown:

Normal force on the body  = ?

Solution:

The normal force of a body is the vertical force the body exerts on another body.

It is expressed as;

        Normal force  = mass x acceleration due to gravity

Acceleration due to gravity  = 9.8m/s²

Normal force  = 33 x 9.8  = 323.4N

A current of 4.75 A is going through a 5.5 mH inductor is switched off. It takes 8.47 ms for the current to stop flowing. The average induced emf opposing the decrease of the current is approximately 26.125 volts.

To calculate the magnitude of the average induced electromotive force (emf) opposing the decrease of the current, we can use Faraday's law of electromagnetic induction.

Faraday's law states that the induced emf in an inductor is equal to the rate of change of magnetic flux through the inductor. Mathematically, it can be expressed as:

emf = -L * (di/dt)

Where:

emf is the induced emf (in volts)

L is the inductance of the inductor (in henries)

di/dt is the rate of change of current (in amperes per second)

Given:

Current (I) = 4.75 A

Inductance (L) = 5.5 mH = 5.5 x \(10^{-3}\) H

Time (t) = 8.47 ms = 8.47 x \(10^{-3}\)) s

To find di/dt, we need to calculate the change in current over time. Since the current is decreasing to zero, di will be the initial current minus the final current, and dt will be the time taken for the current to decrease.

Initial current (Iinitial) = 4.75 A

Final current (Ifinal) = 0 A

di = Iinitial - Ifinal = 4.75 A - 0 A = 4.75 A

dt = 8.47 x \(10^{-3}\) s

Now we can calculate the magnitude of the average induced emf:

emf = -L * (di/dt)

= - (5.5 x \(10^{-3}\) H) * (4.75 A / 8.47 x \(10^{-3}\) s)

Calculating the value:

emf = - (5.5 x \(10^{-3}\) H) * (4.75 A / 8.47 x \(10^{-3}\) s)

= - (5.5 x \(10^{-3}\)) H) * (4.75 A / 8.47 x \(10^{-3}\) s)

= - (5.5 x 4.75) V

= - 26.125 V

Taking the magnitude, the average induced emf opposing the decrease of the current is approximately 26.125 volts.

To know more about average induced emf here

https://brainly.com/question/31979754

#SPJ4

The unit tangent vector T(t) for the curve defined by r(t) = (e², 2t, e) at t = 2 is \(\[T(2) = \left(\frac{e^2}{\sqrt{e^4 + 16 + e^2}}, 4, e\right)\]\). The unit normal vector N(t) for the curve at \(\[N(2) = \left(\frac{-2e^2}{\sqrt{4e^4 + 1}}, 1, 0\right)\]\).

The normal acceleration ar at \(\[ar(2) = \frac{\sqrt{4e^4 + 1}}{\sqrt{e^4 + 16 + e^2}}\]\). The tangential acceleration at t = 2 is aT(2) = 0 since the curve is defined as a straight line and has no curvature.

To find the unit tangent vector T(t), we take the derivative of the position vector r(t) with respect to t and normalize it by dividing by its magnitude. The derivative of \(\[T(t) = \frac{(e^2, 4, e)}{\sqrt{e^4 + 16 + e^2}}\]\).

To find the unit normal vector N(t), we differentiate T(t) with respect to t and normalize the resulting vector. The derivative of T(t) is (0, 0, 0), which means the curve is a straight line. Therefore, N(t) is constant and given by \(\[N(t) = \frac{(-2e^2, 1, 0)}{\sqrt{4e^4 + 1}}\]\).

The normal acceleration ar at t = 2 is the magnitude of the derivative of T(t) with respect to t, which simplifies to \(\[\frac{\sqrt{4e^4 + 1}}{\sqrt{e^4 + 16 + e^2}}\]\).

Since the curve is a straight line, there is no change in the direction of the velocity vector, and therefore, the tangential acceleration aT is zero.

To know more about acceleration, refer here:

https://brainly.com/question/12550364#

#SPJ4

The net force on an object is zero that is pulled with forces of 80 newtons to the right and 80 newtons to the left.

Net force is equal to sum of all the force acting on a body.

The formula for net force if n force are acting on it:

                       \(F_{net}=F_{1}+ F_{2}+F_{3}.....F_{n}\)

In this case the two forces are equal but opposite in direction.

Putting the values in the formula

\(F_{net} = 80+(-80)\) (since forces are equal but opposite)

\(F_{net}= 0\)

So the net force acting on the object is zero because the forces are equal and opposite.

If you need to learn more about net force, click here

https://brainly.com/question/14361879?referrer=searchResults

#spj4

The net force on an object that is pulled with forces of 80 newtons to the right and 80 newtons to the left is: 0 newtons

To solve this problem the formula of net force and the procedure that we have to use is:

Fr = ∑F

Where:

Information about the problem:

Applying the resultant force formula we get:

Fr = ∑F

Fr = F1 + F2

Fr = 80 newtons - 80 newtons

Fr= 0 newtons

We can say that the resultant force is the algebraic sum of all the forces acting on a body.

Learn more about resultant force at: brainly.com/question/25239010

#SPJ4

The ratio of the drag force on the jet to the drag force on the prop-driven transport is approximately 3.43.

The drag force on an airplane is given by the formula,

Fd = (1/2) * rho * v^2 * A * C

where Fd is the drag force, rho is the density of air, v is the velocity of the airplane, A is the effective cross-sectional area, and C is the drag coefficient.

For the jet flying at 1000 km/h at an altitude of 10 km,

Fd_jet = (1/2) * 0.38 kg/m^3 * (1000 km/h)^2 * A * C

For the prop-driven transport flying at half the speed and altitude,

Fd_prop = (1/2) * 0.67 kg/m^3 * (500 km/h)^2 * A * C

Fd_jet/Fd_prop = [(1/2) * 0.38 kg/m^3 * (1000 km/h)^2]/[(1/2) * 0.67 kg/m^3 * (500 km/h)^2]

Simplifying this expression,

Fd_jet/Fd_prop = (0.38/0.67) * (1000/500)^2

Fd_jet/Fd_prop ≈ 3.43

To know more about drag force, here

brainly.com/question/12774964

#SPJ4

Answer:

A. New problem or discovery Engineering solution Development Research Explanation:

A possible  sequence of steps in the research and development cycle are  A. New problem or discovery Engineering solution Development Research​. In the  research and development cycle, the first step is the problem that a scientist observe. After that we have discover a solution for that problem through many research so the above materials are the possible sequence of steps in the research and development cycle.