A fountain sends water to a height of 113 m. What must be the pressurization (above atmospheric) of the underground water system

Answers

Answer 1

The pressurization of the underground water system must be at least 113 meters of water column or 1.13 megapascals (MPa) above atmospheric pressure.

This pressure is required to overcome the gravitational force and push the water up to a height of 113 meters. To send water to a height of 113 meters, the pressurization of the underground water system needs to be at least 113 meters of water column or 1.13 MPa above atmospheric pressure. This pressure is necessary to counteract gravity and propel the water upwards. To understand why the pressurization of the underground water system must be at least 113 meters of water column or 1.13 MPa above atmospheric pressure, we need to consider the basic principles of fluid dynamics and hydrostatic pressure. The height to which water can be raised in a fountain or any vertical column is limited by the hydrostatic pressure, which is directly proportional to the depth or height of the water column. This pressure is caused by the weight of the water above a specific point.

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Related Questions

thirty 6kg boxes lifted on to ashelf 1.5m height what is the total work​

Answers

We must first determine the amount of force needed to lift the boxes against gravity. The weight of the boxes is calculated as follows: 30 boxes x 6 kg/box = 180 kg

Work = Force x Distance Work = 1765.8 N x 1.5 m Work = 2648.7 Joules Force = Weight x Gravitational Acceleration Force = 180 kg x 9.81 m/s2 Force = 1765.8 N

The total work required to raise thirty 6 kilogram boxes onto a 1.5 m high shelf is therefore 2648.7 Joules.

How can the gravitational pull of a planet be strengthened?

Hence, the gravitational pull between two objects grows as their respective masses do as well. The force of gravity between two objects is equal to their respective masses multiplied by two. To put it another way, the gravitational potential energy directly relates to how high an item is above the earth. Consequently, an item needs be elevated higher in order to enhance its gravitational potential energy. The gravitational potential energy increases with height.

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7) Find F1 and F2
HELP PLEASEEE

7) Find F1 and F2HELP PLEASEEE

Answers

The force F1 is equal and opposite to the downward force thus, F1 is equal to 60 N. The force F2 is inclined to 30 ° from leftward force and it is equal to 38.97 N in magnitude.

What is force?

Force is an external agent acting on a body to deform it or to change its state of motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction.

If two forces acting on a body from the same directions, then the net force will be the sum of these two forces. If they are acting from opposite directions, they will cancel each other in magnitude.

The force F1 is equal and opposite to the force acting downward. Thus its magnitude is 60 N. The force F2 is inclined to 30 ° from horizontal direction.

F2 = 45 cos 30 = 38.9 N.

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The Enterprise wants to orbit a4.15 x 10^24kg planet with a period of14100 s. What should the radius oftheir orbit be?

Answers

Given:

Mass of planet, m = 4.15 x 10²⁴ kg.

Period, T = 14100 s

Let's find the radius.

To find the radius, apply the formula from Kepler's Third aw:

\(\begin{gathered} \frac{T^2}{R^3}=\frac{4\pi^2}{GM} \\ \\ \end{gathered}\)

Where R is the radius.

Rewrite the formula for r:

\(R=\sqrt[3]{\frac{GM*T^2}{4\pi^2}}\)

Where:

G is gravitational constant = 6.67 x 10⁻¹¹ m3 kg-1 s-2

M is the mass = 4.15 x 10²⁴ kg

T is the period = 14100 s

π = 3.54

Plug in values and solve for R;

\(\begin{gathered} R=\sqrt[3]{\frac{6.67\times10^{-11}*4.15\times10^{24}*14100^2}{4\pi^2}} \\ \\ R=\sqrt[3]{\frac{5.503\times10^{22}}{39.4784}} \\ \\ \end{gathered}\)

Solving further:

\(\begin{gathered} R=\sqrt[3]{1.394\times10^{21}} \\ \\ R=11170796.49\approx1.12\times10^7\text{ m} \end{gathered}\)

Therefore, the orbital radius will be 1.12 x 10⁷ meters.

ANSWER:

1.12 x 10⁷ m

What is one star that has run out of hydrogen

Answers

One star that has run out of hydrogen is known as a white dwarf

Can anyone answer this science question NO LINKS !!!!

Can anyone answer this science question NO LINKS !!!!

Answers

Answer:

it is certainly a as clearly a has the greater mass

i also agree on a, it says the MOST and it’s the biggest

let assume a hypothetical planet was discovered orbiting around the star. its orbital distance was measured to be 300 million kilometers. what is the orbital period

Answers

The hypothetical planet discovered orbiting the star has an orbital period of 4.44 Earth years.

When a hypothetical planet is discovered orbiting a star, its orbital distance is measured to be 300 million kilometers. The orbital period of the planet is determined by its distance from the star and the mass of the star.

The time taken by an object to complete a single orbit around another object is known as the orbital period. It is calculated based on the distance between the two objects and the mass of the central object. The formula for calculating the orbital period of a planet is:

Orbital period = 2π √(r³/GM)

Where r is the distance between the planet and the star, G is the gravitational constant, and M is the mass of the star.π is the mathematical constant pi whose value is 3.14.So, in the case of the hypothetical planet, the orbital period can be calculated as:

Orbital period\(= 2π √(r³/GM) = 2 x 3.14 √[(300,000,000)^3/ (6.67 x 10^-11 x M)]\)

Where the value of the gravitational constant is\(6.67 x 10^-11 Nm^2/kg^2\).

Assuming the mass of the star is one solar mass or \(1.989 x 10^30\)kg,

the orbital period can be calculated as:

Orbital period = \(2 x 3.14 √[(300,000,000)^3/ (6.67 x 10^-11 x 1.989 x 10^30)] = 4.44\) Earth years

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i will give u brainliest!

i will give u brainliest!

Answers

Answer:

I think its false

Explanation:

It doesn't make sense that the doctor found it in her stool

The following force measurements were taken during actual testing of the lever pictured. What is the AMA of this lever?
-O 0.20
-5.5
-0.18
-2.75

The following force measurements were taken during actual testing of the lever pictured. What is the

Answers

Answer:

0.18

Explanation:

The force by effort on the lever is 5.5 N and the load is 1 N. Them actual mechanical advantage of the lever is 0.18.

What is mechanical advantage ?

The lever's mechanical advantage is determined by the output force to input force ratio. This connection demonstrates that, assuming no losses from friction, flexibility, or wear, the mechanical advantage can be calculated from the ratio of the distances from the fulcrum to where the input and output forces are applied to the lever.

The ideal mechanical advantage is calculated as ratio of the distance from the load and the effort from the fulcrum. If we know the actual force acting on both side, we can calculate the actual mechanical advantage (AMA).

The force of effort  = 5.5 N

force by the load on the lever = 1 N

AMA    = load / effort

           = 1 /5.5 = 1.8

Therefore, the mechanical advantage of the lever is 0.18.

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true or false solids possess a greater level of kinetic energy than gases ​

Answers

Answer:

False

Explanation:

Solid particles have the least amount of energy, and gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles. A change in phase may occur when the energy of the particles is changed.

Due in a few minutes plzzzz help! Will mark brainliest

Due in a few minutes plzzzz help! Will mark brainliest

Answers

Answer:

1. 960

2. 16.6666

3. 0.41666666666

4. 10

Explanation:

A*V=W

A*120=50

V=I*R

R being resistance

(I'm not a 100% sure on 2 & 3)

Using Kepler's 3rd law, how long will it take a new planet that is 3.68 x 107 km to travel around the Earth?

Answers

Answer:

Pls mark brainlist...    A graph showing Kepler's 3rd law. ... Kepler's 3rd law is a mathematical formula. It means that if you know the period of a planet's orbit (P = how long it takes the planet to go around the Sun), then you can determine that planet's distance from the Sun (a = the semimajor axis of the planet's orbit).

Explanation:

The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit” That's Kepler's third law. In other words, if you square the 'year' of each planet, and divide it by the cube of its distance to the Sun, you get the same number, for all planets

There are actually three, Kepler's laws that is, of planetary motion: 1) every planet's orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet's orbital period is proportional to the cube of the semi-major axis of its ..

T=2π√r3GME. For an ellipse, recall that the semi-major axis is one-half the sum of the perihelion and the aphelion.

Johannes Kepler proposed some laws based on the revolution of planets and according to his third law, the time taken for a new planet that is 3.68 x 107 km to travel around the Earth will be 0.121 years.

What is Kepler's third law?

According to third law of Kepler, if the distance a travelled by a planet is expressed in astronomical unit and period of travel p in years then the relation between these two parameters is written as follows:

P²= a³

Kepler proposed that the planets in the solar system is revolving around the sun in an elliptical orbit and this is somewhat contradictory to the circular orbit model of Copernicus.

The distance of travel is given in 3.68 × 10⁷ km. One kilometer is 6.68 × 10⁻⁹ astronomical unit. Thus the given distance is 3.68 × 10⁷ × 6.68 × 10⁻⁹ = 0.2459 Au

Now, the time period P can be calculated as follows:

P² = (0.2459 Au)³

    = 0.0145

p   = 0.1249 years.

Therefore,  according to Kepler's third law the time taken for a new planet that is 3.68 x 107 km to travel around the Earth will be 0.121 years.

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give the instantaneous velocity (including unit vector) of the object at t=1.5s

Answers

Since an object's instantaneous velocity equals the derivative of its displacement at a certain point, we can also state that the instantaneous velocity at time t = 1 is around 2 meters per second.

The derivative of x with respect to t, or the upper limit of the average velocity as the elapsed time approaches 0, is the instantaneous velocity of an object:

v (t) equals d d t x (t). v (t) equals d d t x (t).

Instantaneous velocity is a vector having a dimension of length per time, similar to average velocity. The speed of an object at a specific time is its instantaneous speed. The instantaneous velocity is obtained by adding the direction to the speed.

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a lion is running at constant speed toward a gazelle that is standing still, as shown in the top figure above. after several seconds, the gazelle notices the lion and accelerates directly toward him, hoping to pass the lion and force him to reverse direction. as the gazelle accelerates toward and past the lion, the lion changes direction and accelerates in pursuit of the gazelle. the lion and the gazelle eventually each reach constant but different speeds. which of the following sets of graphs shows a reasonable representation of the velocities of the lion and the gazelle as functions of time?

Answers

The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.

Velocity is the rate of change of displacement over time.

It has SI units as m/s.The total amount of movement of an object per unit time is also called velocity. It depends on both the size and direction of the moving object.Velocity can also be called as speed when distance is taken into consideration instead of displacement.

As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.

So option A is correct.

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a lion is running at constant speed toward a gazelle that is standing still, as shown in the top figure

What happens when two continental plates meet ?
A One will be heavier and subduct
B They will crash into each other and form mountains
C They will begin to move apart
D One plate will be scared and start crying

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Answer:

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Explanation:

Answer:

option B is correct answer of this question

they will crash into each other and form mountains

hope it helps

Mike is pushing a car up a ramp. What could Mike do to reduce the effort force he needs to use to push the car?

Answers

Answer:

He could use a really big pulley system or get in it and drive or call a tow truck.

is a=f/m = 10000/50000 does it equal 0.2 ms to the power of -2

Answers

Yes, a=f/m where a is the acceleration, f is the force, and m is the mass of an object,  a=0.2m/s^2

According to Newton's 2nd law of motion, According to this law, the rate of change of linear momentum of a body is directly proportional to the external force applied on the body, and this change takes place always in the direction of the force applied. In simple terms, it means that a larger force will change the momentum of an object more quickly as compared to a smaller force.

Mathematically, we can write

F∝ dp/dT

where p is the momentum

F∝ (mv-mu)/t₂-t₁

where v is the final velocity and u is the initial velocity

Now, F∝{m(v-u)}/(t₂-t₁)

         F∝ma                       [∵ a=(v-u)/t]

         F=kma

∴  when k=1

  F=ma

Now according to this question,

f=10,000 N    and     m=50,000kg

By applying the formula,

F=ma

10,000=50,000*a

∴ a= 10,000÷50,000

a=0.2  or 2×10⁻¹ m/s²

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What type of motion do star trails result from?

Answers

Answer:

Star trails reflect Earth's rotation, or spin, around its axis. The Earth makes a complete rotation relative to the backdrop stars in a period of about 23 hours and 56 minutes.

In which of these reactions is energy released?
A. Exothermic reactions

B. No reactions

C. All reactions

D. Endothermic reactions

Answers

Answer:

exothermic reaction

Explanation:

Exothermic reactions are reactions or processes that release energy, usually in the form of heat or light. In an exothermic reaction, energy is released because the total energy of the products is less than the total energy of the reactants.

Exothermic reactions

calculate the volume of a liquid with a density of 5.45g/cm³ or centimeter square and a mass of 65g.​

Answers

Answer:

12 ml

Explanation:

The thing to remember about a substance's density is that it tells you the mass of every unit of volume of said substance.

Planet X has a mass of M and a radius of R. Planet Y has a mass of 3M and a radius of 3R. Identical satellites orbit both planets at a distance R above their surfaces, as shown above. The planets are separated by such a large distance that the gravitational forces between them are negligible.

How does the magnitude of the gravitational force FY exerted by Planet Y on its satellite compare to the gravitational force FX exerted by Planet X on its satellite?

Answers

Answer:

\({FY} = \dfrac{3}{4} \times FX\)

Explanation:

The parameters given for the planets are;

The mass of planet X = M and the radius of planet X = R

The mass of planet Y = 3·M and the radius of planet Y = 3·R

The magnitude of the gravitational force of the planets on their satellites are given by the following equation;

\(F=G \times \dfrac{M_{1} \cdot m_{2}}{R^{2}}\)

Where;

M₁ = The mass of the first object = The mass of the planet

m₂ = The mass of the second object = The mass of the satellite

R = The distance between the centers of the two planets = The distance between the center of the planet and the satellite

G = The universal gravitational constant

The force between planet X and the satellite in its orbit = \(FX=G \times \dfrac{M \times m}{(2 \cdot R)^{2}} = G \times \dfrac{M \times m}{4 \cdot R^{2}}\)

The force between planet Y and the satellite in its orbit = \(FY=G \times \dfrac{3\cdot M \times m}{(4 \cdot R)^{2}} = G \times \dfrac{3\cdot M \times m}{16 \cdot R^{2}} = G \times \dfrac{ 3\cdot M \cdot m}{16 \cdot R^{2}}\)

Therefore;

\(\dfrac{FY}{FX} = \dfrac{G \times \dfrac{ 3\cdot M \cdot m}{16 \cdot R^{2}}}{G \times \dfrac{M \times m}{4 \cdot R^{2}}} = \dfrac{3}{16} \times \dfrac{4}{1} = \dfrac{3}{4}\)

\({FY} = \dfrac{3}{4} \times FX\)

why are astronauts weightless in the space station?

Answers

Answer:

Astronauts float around in space because there is no gravity in space. Everyone knows that the farther you get from Earth, the less the gravitational force is. Well, astronauts are so far from the Earth that gravity is so small. This is why NASA calls it microgravity.

Explanation:

Explain how the perfume atomizer works under Bernoulli's principle

Answers

Answer:

In an atomizer, or perfume sprayer, you squeeze a rubber bulb to squirt air through a tube. Because of the Bernoulli principle, the air rushing through the tube has a lower pressure than the surrounding atmosphere. ... The perfume is pushed out of the tube and sprays into the air as a fine mist.

Explanation:

Why should the driver and passengers in a car wear seatbelts? Choose the options that most accurately complete the statement: When a car moving forward at a constant speed v comes to a sudden stop, passengers without seatbelts continue moving forward at speed v because of their inertia; according to Newton's second law. Newton's first law. Newton's third law:

Answers

When a car moving forward at a constant speed v comes to a sudden stop, passengers without seatbelts continue moving forward at speed v because of their inertia is according to Newton's first law.

This law, also known as the law of inertia, states that an object in motion will stay in motion, and an object at rest will stay at rest unless acted upon by an external force. In the case of a car moving forward at a constant speed v and coming to a sudden stop, the passengers without seatbelts will continue moving forward at speed v because of their inertia. This is why it is important for the driver and passengers in a car to wear seatbelts, as they provide an external force that can help prevent injury in the event of a sudden stop.

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Two carts are free to slide along the frictionless track shown in figure below. Cart A of mass m1 = 8 kg is released from 12m. A cart B of mass m2 = 4 kg, initially at rest. The two carts combine together and move as one object. Calculate the height reached
by the two carts after collision.

Answers

The height reached by the two carts after collision is determined as 5.34 m.

Initial velocity of Cart A

Apply the principle of conservation of mechanical energy.

K.E = P.E

v = √2gh

v = √(2 x 9.8 x 12)

v = 15.34 m/s

Final velocity of the two carts after the collision

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

8(15.34) + 4(0) = v(8 + 4)

122.72 = 12v

v = 10.23 m/s

Height reached by both carts

Apply the principle of conservation of mechanical energy.

P.E = K.E

mgh = ¹/₂mv²

h = v²/(2g)

h = (10.23²) / (2 x 9.8)

h = 5.34 m

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A 0.50-kilogram frog is at rest on a rock next to a pond. The frog leaps pushing off of the rock with an acceleration of 5.0 m/s2. What is the magnitude of the net force exerted on the frog as it leaps? a)2.5 N b)1.5 N c)1.0 N d)2.0 N

Answers

Given that,

Mass of a frog, m = 0.5 kg

The frog leaps pushing off of the rock with an acceleration of 5.0 m/s².

To find,

The magnitude of the net force exerted on the frog as it leaps.

Solution,

Let the net force exerted on the frog is given by the formula as follows :

F = ma

Putting the values of m and a to find F as follows :

F = 0.5 kg × 5 m/s²

F = 2.5 N

So, the magnitude of net force is 2.5 N.

The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.

Hence, Option a) 2.5N is the correct answer.

Given the data in the question;

Mass of frog; \(m = 0.5kg\)Acceleration; \(a = 5.0m/s^2\)

Force Exerted; \(F = ?\)

To determine the magnitude of the net force exerted on the frog as it leaps, we the expression from the Newton's Second law of motion:

\(F = m * a\)

Where m is mass and a is acceleration

We substitute our given values into the equation

\(F = 0.5kg * 5.0m/s^2\\\\F = 2.5kgm/s^2\\\\F= 2.5N\)

The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.

Hence, Option a) 2.5N is the correct answer.  

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How are solar flares different from solar prominences.

Answers

A prominence is a loop of cool incandescent gas that extends above the photosphere. A solar flare is an explosive release of energy that comes from the sun and causes magnetic ditrubances.

Answer:

What is the difference between a prominence and a solar flare? A prominence is a loop of cool incandescent gas that extends above the photosphere. A solar flare is an explosive release of energy that comes from the sun and causes magnetic ditrubances.

Explanation:

How to derive the formula for centripetal acceleration.

Answers

Because r is given, we can use the second expression in the equation ac=v2r;ac=rω2 a c = v 2 r ; a c = r ω 2 to calculate the centripetal acceleration. Solution.

The radius of a pulley is 125 mm and the moment of inertia about its axis is I=0.05 kg-m2.When the mass-pulley system shown below is released from rest,determine: a) The tension in the rope between the 20 kg mass and the pulley b) How far the 20 kg mass falls in the first 0.5 s. 4 kg 20 kg

Answers

The tension in the rope between the 20 kg mass and the pulley is 176.47 N, and the 20 kg mass falls 0.6125 m in the first 0.5 s.

1. Calculate the net torque acting on the pulley: τ = Iα, where α is the angular acceleration.


2. Use the 20 kg mass to find the torque: τ = rF, where r is the radius (0.125 m) and F is the force (20 kg * 9.81 m/s²).


3. Solve for α: α = τ/I = (0.125 * 20 * 9.81)/0.05.


4. Calculate the linear acceleration of the 20 kg mass: a = rα.


5. Find the tension in the rope: T = m(a + g), where m is the 20 kg mass and g is the acceleration due to gravity (9.81 m/s²).


6. Determine the distance the 20 kg mass falls in the first 0.5 s using the equation: d = 0.5 * a * t², where t is the time (0.5 s).

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Describe how you would draw a diagram that shows the electric field between two particles that attract each other.

Please help?? PWEASE PWEASE PWEASEDescribe how you would draw a diagram that shows the electric field

Answers

Answer:

draw the two atomic structures and then focus in on the electrons either gaining or losing and draw them with arrows and dots

Explanation:

How does changing the mass of an object in the system's acceleration when a constant force is applied?

Answers

When a constant force is applied, an increase in the mass of an object decreases its acceleration and vice versa.

What is the relationship between the force, mass, and acceleration of an object?

The mass of an object is the quantity of matter present in the object.

Force is a push or pull agent that causes a change in the motion or state of rest of an object.

Acceleration of an object is the change in velocity with time of the object.

The relationship between the force, mass, and acceleration of an object is given below:

Force  = mass * accelerationMass = Force / accelerationAcceleration = Force / mass

From the above formulas, it can be seen that mass and acceleration have an inverse relationship such that as one increases, the other decreases, and vice versa.

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