A LED lamp rated 13 W is on for 28 minutes and a stereo of 52W is on for 9 hours. How much energy has been used in Watt-hours? (response not displayed)

Deflection instruments measure the deviation of a physical quantity (e.g. voltage, current, force) from its zero value, while null output instruments determine the exact value of the physical quantity by nullifying it.

In other words, deflection instruments display the magnitude of a physical quantity, while null output instruments determine its precise value.

Examples of deflection instruments are analog voltmeters and ammeters, which measure the deviation of a voltage or current from zero. Examples of null output instruments are digital multimeters, which determine the precise value of voltage, current, or resistance by nullifying it.

When an engine has been diagnosed with blowby, technician B is only correct who states that the compression rings could be worn.

Engine blowby happens when a mixture of combustion gases or air-fuel leaks between the pistons and cylinder wall into the crankcase of the engine because of the lose pistons's rings. Engine blowby can occur within both gas and diesel engines. Minor levels of engine blowby are normal but excessive levels of engine blowby are an indicator of larger issues. So technician B says correctly.

While technician A is not right to say that a cracked flywheel could be a reason for the blowby engine.

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Answer:

N0

Explanation:

It does not seem reasonable to expect a tensile stress of 200 MPa to produce a reduction in specimen diameter of 0.08 mm

Given data :

Diameter ( d ) = 10 mm

length ( l ) = 150 mm

elasticity ( ∈ ) = 100 GPa

longitudinal strain ( б ) 200 MPa

Poisson ratio ( μ )  ( assumed ) =0.3

Assumption : deformation totally elastic

attached below is the detailed solution to why it is not reasonable .

The Sd value = 0.08 > the calculated Sd value ( 6*10^-3 ) hence it is not reasonable to expect a tensile stress of 200 MPa to produce a reduction in specimen

Answer:

4.75m^2

Explanation:

Given:-

- Temperature of hot fluid at inlet:  \(T_h_i = 300\) °C

- Temperature of cold fluid at outlet: \(T_c_o = 120\) °C

- Temperature of cold fluid at inlet: \(T_c_i = 35\) °C

- The overall heat transfer coefficient: U = 1500 W / m^2 K

- The flow rate of cold fluid: m_c = 10,00 kg/ h

- The flow rate of hot fluid: m_h = 5,000 kg/h

Solution:-

- We will evaluate water properties at median temperatures of each fluid using table A-4.

Cold fluid:   Tci = 35°C , Tco = 35°C

                            Tcm = 77.5 °C ≈ 350 K  --- > \(C_p_c = 4195 \frac{J}{kg.K}\)

 Hot fluid:     Thi = 300°C , Tho = 150°C ( assumed )

                             Thm = 225 °C ≈ 500 K --- > \(C_p_h = 4660 \frac{J}{kg.K}\)

- We will use logarithmic - mean temperature rate equation as follows:

                             \(A_s = \frac{q}{U*dT_l_m}\)

Where,

                 A_s : The surface area of heat exchange

                 ΔT_lm: the logarithmic differential mean temperature

                 q: The rate of heat transfer

- Apply the energy balance on cold fluid as follows:

                   \(q = m_c * C_p_c * ( T_c_o - T_c_i )\\\\q = \frac{10,000}{3600} * 4195 * ( 120 - 35 )\\\\q = 9.905*10^5 W\)

- Similarly, apply the heat balance on hot fluid and evaluate the outlet temperature ( Tho ) :

                   \(T_h_o = T_h_i - \frac{q}{m_h * C_p_h} \\\\T_h_o = 300 - \frac{9.905*10^5}{\frac{5000}{3600} * 4660} \\\\T_h_o = 147 C\)

- We will use the experimental results of counter flow ( unmixed - unmixed ) plotted as figure ( Fig . 11.11 ) of the " The fundamentals to heat transfer" and determine the value of ( P , R , F ).

- So the relations from the figure 11.11 are:

                  \(P = \frac{T_c_o - T_c_i}{T_h_i - T_c_i} \\\\P = \frac{120 - 35}{300 - 35} \\\\P = 0.32\)    

                 \(R = \frac{T_h_i - T_h_o}{T_c_o - T_c_i} \\\\R = \frac{300 - 147}{120 - 35} \\\\R = 1.8\)

Therefore,         P = 0.32 , R = 1.8 ---- > F ≈ 0.97

- The log-mean temperature ( ΔT_lm - cf ) for counter-flow heat exchange can be determined from the relation:

                        \(dT_l_m = \frac{( T_h_i - T_c_o ) - ( T_h_o - T_c_i ) }{Ln ( \frac{( T_h_i - T_c_o )}{( T_h_o - T_c_i )} ) } \\\\dT_l_m = \frac{( 300 - 120 ) - ( 147 - 35 ) }{Ln ( \frac{( 300-120 )}{( 147-35)} ) } \\\\dT_l_m = 143.3 K\)

- The log - mean differential temperature for counter flow is multiplied by the factor of ( F ) to get the standardized value of log - mean differential temperature:

                       \(dT_l = F*dT_l_m = 0.97*143.3 = 139 K\)

- The required heat exchange area ( A_s ) can now be calculated:

                     \(A_s = \frac{9.905*10^5 }{1500*139} \\\\A_s = 4.75 m^2\)

No, the physical address 346E0 cannot be the starting address for a segment. This is because the starting address of a segment must be aligned with the segment's size or boundary, which is determined by the processor's architecture.

Segment boundaries are defined by 16-byte or 4-byte boundaries, depending on the segment's use. Therefore, the starting address of a segment must be a multiple of 16 or 4, respectively, depending on the segment type.

In the given address 346E0, the last digit is 0, which indicates that it is a multiple of 16. However, we do not have enough information about the processor architecture and segment size to determine whether this is an appropriate starting address for a segment.

In general, when defining a segment, it is important to ensure that the starting address is properly aligned with the segment's boundary to avoid any issues with memory access and processing.

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Different lever designs can be engineered and developed to alter the brake pedal effort required of the driver by using different levels of mechanical advantage.

Mechanical advantage can be defined as a ratio of the output force of a lever to the force acting on it (input force or effort), assuming no losses due to wear, flexibility, tear or friction.

This ultimately implies that, different lever designs can be suitably engineered and developed to alter the brake pedal effort (input force) that is required of the driver, especially by using different levels of mechanical advantage.

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Answer:

local. It is a very popular

Answer:

No

Explanation:

In the early Aviation history men have always dominated the world of aviation and women are notoriously under-represented, particularly in technical and leadership roles. Therefore, women was treated unequal.

ANSWER:

Aerospace Engineering. ...

Chemical Engineering. ...

Biomedical Engineering.

EXPLANATION:

This is all i know but ... I hope this helps~

The continental margin is composed of the following three zones: the continental shelf, the continental slope, and the continental rise.

The zone between the ocean floor and the continental slope is known as the continental margin. It is the underwater section of a continent that contains the continental shelf, continental slope, and continental rise.

The Continental Shelf: It is the sloping extension of the continent into the ocean. It starts at the coastline and goes all the way to the continental slope. The continental shelf's breadth is determined by how gently the continent slopes downward into the ocean.

The Continental Slope: The continental slope, as the name implies, is a steep slope that leads down to the ocean floor. The incline is between 3° and 6°. The slope of the continental slope is steeper than that of the continental shelf.

The Continental Rise: It is a gently sloping sediment-covered area that links the continental slope to the deep-ocean floor. The continental rise is a result of the accumulation of sediment that falls off the continental shelf and slope over time.

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To ensure a process's address space is not violated with a paging configuration of 63 pages of 2048 words, the page table should be set up to map the logical addresses to physical addresses correctly.

Also the operating system should enforce access control to prevent unauthorized access to memory.

Paging is a memory management technique that allows a process's logical address space to be divided into fixed-sized pages, which are mapped to physical memory frames by a page table. To ensure that a process's address space is not violated, the page table should be set up correctly to map each logical page to a unique physical memory frame.

Additionally, the operating system should enforce access control by only allowing authorized processes to access specific memory locations, preventing unauthorized access to memory. By properly configuring the page table and enforcing access control, a process's address space can be protected from memory violations.

This question should be provided as:

For the following Paging configuration discuss, what must be done to ensure a processes address space is not violated:

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Answer: Droughts, pumping effects, and rainfall variations affect the groundwater level height.

Explanation: If a well is pumped at a faster rate than the aquifer around it is recharged by precipitation or other underground flow, then water levels in the well can be lowered.

Answer:

b

Explanation:

a) the cubit structure is attached.

b)  The coordination number for each atom in a simple cubic structure is 6.

c) Illustration of the 2d 100 plane and the 110 plate is attached.

d) Density is n = 4/r²

e)  There are more atoms per unit area in the (110) plane, which makes it easier for the atoms to slide past each other.

For a) and c) the shapes or images are attached.

b) The coordination number for each atom in a simple cubic structure is 6. In a complex or coordination compound or crystal, the coordination number is the number of atoms, ions, or molecules that a central atom or ion has as its nearest neighbors.

d) The planar density for the (100) plane is

n = 2/r²

Whille the planar density for the (110) plane is

n = 4/r²

The planar density,which is   defined as the number of atoms per unit area on a plane of interest (Schaffer et al.,),is an essential   characteristic of a crystal structure.

e) The (110) plane is more likely to slip than the (100)plane because it has a   higher planar density. This means that there are more atoms per unit area in the (110) plane,which makes it easier   for the atoms to slide past each other.

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Answer:

778.4°C

Explanation:

I = 700

R = 6x10⁻⁴

we first calculate the rate of heat that is being transferred by the current

q = I²R

q = 700²(6x10⁻⁴)

= 490000x0.0006

= 294 W/M

we calculate the surface temperature

Ts = T∞ + \(\frac{q}{h\pi Di}\)

Ts = \(30+\frac{294}{25*\frac{22}{7}*\frac{5}{1000} }\)

\(Ts=30+\frac{294}{0.3928} \\\)

\(Ts =30+748.4\\Ts = 778.4\)

The surface temperature is therefore 778.4°C if the cable is bare

The mean kinetic energy of the N₂ molecules at 25 °C is 3593.519 joules per mole.

Let suppose that the gas sample behaves ideally. The Graham's law establishes a connection between the ideal gas model and the kinetic theory of gases.

In this question we need to use this law to estimate the average kinetic energy (Kₐ), in joules per mole, of a diatomic gas (N₂), which is defined by the following expression:

\(K_{a} = \frac{3}{2}\cdot R_{u}\cdot T\)   (1)

Where:

If we know that \(R_{u} = 8.314\,\frac{J}{mol\cdot K}\) and \(T = 288.15\,K\), then the average kinetic energy is:

\(K_{a} = \frac{3}{2}\cdot \left(8.314\,\frac{J}{mol\cdot K} \right) \cdot (288.15\,K)\)

\(K_{a} = 3593.519\,\frac{J}{mol}\)

The mean kinetic energy of the N₂ molecules at 25 °C is 3593.519 joules per mole. \(\blacksquare\)

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Answer:

I am pretty confident it is the Employer!

Explanation:

They have the responsibility to provide a safe workplace that is free from serious hazards, according to the General Duty Clause of the OSH Act (OSHA Standards)

I hope this helped you!! :D

Answer:

Employers

Explanation:

OSHA requires employers to: Provide working conditions that are free of known dangers. Keep floors in work areas in a clean and, so far as possible, a dry condition. Select and provide required personal protective equipment at no cost to workers.

Exemplifies a complete answer. Half-duplex connections must be used throughout, and all attached devices must support CSMA/CD.

Data collision prevention is necessary in half-duplex networks. Carrier sense multiple access with collision detection, or CSMA/CD, is the technique employed by Ethernet. In essence, an Ethernet device using half-duplex modes will look to see if any other transmissions are taking place before attempting to broadcast.

The two-way radio walkie-talkie, which contains a push-to-talk button, is an illustration of a half-duplex gadget. By pressing this button, the local user can communicate with the distant user by turning on the transmitter while turning off the receiver.

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Answer:

\(I=3A\)

Explanation:

From the question we are told that:

Number of lamps \(N=4\)

Potential difference \(V=60v\)

Total Resistance of the lamp is \(R= 20ohms\)

Generally the equation for Current I is mathematically given by

 \(I=\frac{V}{R}\)

 \(I=\frac{60}{20}\)

 \(I=3A\)

Answer:

The answer is false, I hope this helps. :3

Answer:

False

Explanation:

I took the quiz and it was correct

Answer:

Gently push the micropipette into the tip box and tag tightly to load the tip.

Explanation:

The recommended practice when putting a tip on a micropipette is ;  Gently push the micropipette into the tip box and tag tightly to load the tip.

Given that it is not advisable to remove tip from rack so as not to contaminate it, if we want to put a tip on a micropipette we should gently push the micropipette into the tip box.

Answer:

13.335 CM (1 ft, 1.335 cm)

I am 80% sure this is the answer, but i am not too keen on math so if i am wrong let me know and i will try my best to fix it!

I hope this helped! Have a good day :]

In social network analysis, a k-clique, or quasi-complete sub-graph, is a relaxed clique. A k-clique in a graph is a subgraph where any two vertices are separated by less than k.

A relaxed clique is a k-clique, also known as a quasi-complete sub-graph, in social network research. Any subgraph in a graph where any two vertices are separated by fewer than k is known as a k-clique. A graph with a few vertices can be observed quickly. Because a clique of size k in a graph G has k vertices, each vertex's degree in that clique is k-1. When a portion of a graph's k vertices are linked to one another, the graph is said to have a k-clique. A clique is a subgraph of a graph with connected vertices. The k-clique problem seeks to locate the greatest complete subgraph.

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The key similarity between focusing on what someone is saying to you and jotting down a phone number as you hear it on the radio is the need for active listening and concentration.

In both situations, active listening and concentration are essential for accurate comprehension and retention of information. When someone is speaking to you, actively listening means giving your full attention, processing their words, and understanding their message. It involves being present in the conversation, focusing on the speaker's words, and avoiding distractions.

Similarly, when jotting down a phone number from the radio, active listening requires concentration to capture the numbers accurately. You need to focus on the audio, mentally convert the spoken numbers into written form, and write them down without mistakes. This process demands attentiveness to details, quick mental processing, and hand-eye coordination to ensure you record the correct information.

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Answer:

The electric ceiling fan was invented in 1882 by engineer and inventor, Philip Diehl. He had earlier invented an electric sewing machine and adapted the motor from this invention to create the ceiling fan. He called his invention the “Diehl Electric Fan” and it was such a success that he soon had many other people competing with him.

Explanation:

The unknown capacitor in arm CD must have a value of 330 microfarads, and the unknown resistor must have a value of 100 kilo-ohms.

To solve the problem, use the following formula:
Cseries = C1 x C2 / (C1 + C2)

Where C1 is the value of the capacitor in arm AB (47 microfarads) and C2 is the value of the capacitor in arm BC (330 microfarads).

Therefore, Cseries = 330 microfarads.

Also, the total resistance of arms CD is the sum of the resistance of the resistor (R) and the reciprocal of the capacitive reactance of the capacitor (1/Xc).

Using the following formula:
Rtotal = R + 1/Xc

Where Xc = 1/2πfC,

f is the frequency and C is the capacitance.

For this problem,

Xc = 1/2π(50)(330 x 10-6)

=> 100 kilo-ohm.

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Modern aircraft are designed in a way that, when all seats are occupied and baggage is full, and all fuel tanks are full, the aircraft is overloaded.

Aircraft storage refers to all storage systems in an aircraft for human transportation and also to transport products among countries.

The aircraft storage system is well calculated to work is a maximum capacity in commercial fly lines.

In conclusion, modern aircraft are designed in a way that, when all seats are occupied and baggage is full, and all fuel tanks are full, the aircraft is overloaded.

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