A light bulb used in a slide projector draws a current of 6 amperes when operating on 120 volts.. the power consumed by th light bulb in watts is? B.)a light bulb used in a slide projector draws a cuurent of 6 amperes when operating on 120 volts. the resistance of the light bulb in ohms is?
a..05
b.20
c.720
d.none

The ball will hit the ground 54.4 meters from the base of the cliff. This can be determined using the equation for the horizontal range of a projectile, which is x = vx*t. In this case, vx is 11.5 m/s, and t is the time it takes for the ball to reach the ground. This time can be determined using the equation for the vertical range of a projectile, which is y = vyo*t + 0.5*g*t^2. In this case, vyo is 0 m/s (since the ball is thrown horizontally), g is 9.81 m/s^2, and y is 45.2 m (the height of the cliff). Solving for t gives us 3.86 seconds. Plugging this value into the equation for the horizontal range gives us x = 54.4 m.

a) Answer: On the equator, the Circle of Illumination divides the earth into two equal parts, with each part receiving 12 hours of daylight and 12 hours of darkness.

The equator receives an equal day and night (12 hours each) regardless of the day of the year due to the Circle of Illumination, which is a line that separates the day side of the earth from the night side of the earth. The Circle of Illumination separates the sunlit and dark sides of the earth. The earth's axis is at a 23.5-degree angle to the plane of its orbit around the sun, causing different latitudes to receive different amounts of sunlight throughout the year. On the equator, the Circle of Illumination divides the earth into two equal parts, with each part receiving 12 hours of daylight and 12 hours of darkness.

b)  Answer: The earth's axis is tilted at 23.5°, and during the December solstice, the North Pole is tilted away from the sun, causing the Arctic Circle and areas beyond it to experience a full day of daylight because the sun is above the horizon for 24 hours.

On December 22nd, between the latitudes of the Tropic of Cancer (23.5°N) and the Arctic Circle (66.5°N), 24 hours of daylight is experienced. This occurs because the earth's axis is tilted at 23.5°, and during the December solstice, the North Pole is tilted away from the sun, causing the Arctic Circle and areas beyond it to experience a full day of daylight because the sun is above the horizon for 24 hours.

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The single most important property of a star that determines its evolution is its mass.

A star's mass determines its internal temperature, pressure, and nuclear reactions, which drive its energy production and ultimately its evolution. Low-mass stars, like red dwarfs, have relatively low internal temperatures and undergo a slow process of fusion that can last for trillions of years. On the other hand, high-mass stars, like blue giants, have much higher internal temperatures and undergo fusion much more quickly, leading to a shorter lifespan.

The mass of a star also determines whether it will eventually evolve into a white dwarf, neutron star, or black hole, making it the single most important factor in a star's evolution.

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Answer:

50% of source A, and 25% of source B.

Explanation:

You see, half-life of 10mil years means half of it will be gone in 10 million years. so basically, since source a is 10mil half life, half of it will remain, while source b, since it has 5 million years of half life, will have 25% left, since 1/2*1/2=1/4. hope this helps!

Answer:

source A 50%

source B 25%

Explanation:

Half life is time it takes for something to get reduced by half. For example, if half life of my weight is 5 years and I am currently 20lbs, then in next 5 years I will become half of my original so 10lbs.

Similarly, if compound A has half-life of 10 million years, then after 10 million years, half of compound A will remain, thus 50% remains

Compound b has half life of 5 million years, so first 5 million years it will reduce by half so become 50% but then in another 5 million years (total of 10 million years) it gets reduced by another half so 50/2 = 25% remains.

The approximate diameter of this planet is 140,000 km.

From the question, we have

exoplanet dim the light of a distant star by 1%

the ratio of the diameter of planets and stars is 1: 100

The approximate diameter of this planet is

= 1,400,0000 × 1/100 = 140,000 km

Exoplanet:

Astronomers have directly observed the spectrum of visible light bounced off an exoplanet for the first time ever. The simplest extrasolar planets to find by the radial-velocity method are hot Jupiters because the oscillations they induce in the motion of their parent stars are relatively massive and rapid compared to those of other types of planets. The size of the Neptune planets is similar to that of our solar system's Neptune or Uranus. It was first found ten years ago by the NASA satellite Kepler. Two stars, Kepler-16b and Kepler-17b, rotate around and around one another.

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Answer:

10.4 m/s²

Explanation:

use the formula:  V² = Vo² - 2aΔx

Plug in the known values then solve for a.  Vo = 0 because the car starts from rest.

(25 m/s)² = 0 + 2a(30m)

a = (625 m²/s²)/(2)(30m) = 10.4 m/s²

Answer:

''The combination of Earth's tilted axis and its revolution causes the atmosphere to be unequally heated by the sun.'' - jordanmiya23

Explanation:

this has been answered before

I = 0.00744 A (Amps)

Hi there !

Ohm's law formula

I = V/R

I = 3.5V/470Ω

I = 0.00744 A

Good luck !

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

m is the mass

f is the force

From the question we have

\(a = \frac{70}{7} = 10 \\ \)

We have the final answer as

Hope this helps you

According to the given statement , the acceleration of the sphere at the instant when its speed is 27.0 m/s.

We can use the principles of electrostatics and kinematics.  a = [(9.00 x 10⁹ N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)²] / (4.00 x 10⁻³ kg).

1. Determine the electric force between the two charges:
  - The electric force between two charges can be calculated using Coulomb's Law:

F = k * |q1 * q2| / r².
  - In this case, q1 = 5.00 μC and q2 = +2.00 μC. The distance between them, r, is the horizontal distance of 8.00 cm (which is 0.08 m).
  - The constant k is 9.00 x 10⁹ N * m^2 / C².
  - Plugging in the values, we get F = (9.00 x 10^9 N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)².

2. Calculate the net force acting on the sphere:
  - At any instant, the net force acting on the sphere is the sum of the electric force and the force due to gravity.
  - However, in this case, gravity can be neglected, as stated in the question.
  - Therefore, the net force acting on the sphere is equal to the electric force between the two charges.

3. Calculate the mass of the sphere:
  - The mass of the sphere is given as 4.00 x 10⁻³ kg.

4. Apply Newton's second law:
  - Newton's second law states that the net force acting on an object is equal to the product of its mass and acceleration: Fnet = m * a.
  - In this case, the net force acting on the sphere is the electric force between the charges.
  - Plugging in the values, we get (9.00 x 10⁹ N * m^2 / C²) * |5.00 μC * 2.00 μC| / (0.08 m)² = (4.00 x 10⁻³ kg) * a.

5. Solve for the acceleration:
  - Rearranging the equation, we have a = [(9.00 x 10⁹ N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)²] / (4.00 x 10⁻³ kg).
  - Evaluating the expression, we find the value of acceleration.

By following these steps, you can find the acceleration of the sphere at the instant when its speed is 27.0 m/s.

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Answer:

I'm not sure it is c I'm sure it is d

The given wavelength of the ocean ripples is λ = 2.63 cm and their velocity of propagation is v = 2.37 m/s. Therefore, the frequency of the ripples is 90.08 Hz.

Therefore, to determine the frequency of the ripples, we can use the wave equation: v = fλ

where: v = velocity of the wave f = frequency λ = wavelength Rearranging the formula, we have: f = v/λ

Substituting the given values: v = 2.37 m/s and λ = 2.63 cm = 0.0263 m.

Therefore, f = (2.37 m/s)/(0.0263 m) ≈ 90 Hz.

The frequency of the ocean ripples is approximately 90 Hz. Given that wind gusts create ripples on the ocean that have a wavelength of 2.63 cm and propagate at 2.37 m/s.

To calculate the frequency of the ripples, we will use the formula: f = v/λ where f is the frequency v is the velocity of propagation λ is the wavelength. Substituting the given values, f = 2.37/0.0263= 90.08 Hz

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i. Cassiopeia would be the group of bodies arranged in the shape of M (D), while the bright heavenly body that struck the Earth would be the meteorite (B).

ii. The two main differences between D (group of heavenly bodies arranged in the shape of M) and the Milky Way are:

iii. It is not possible to compare the size of A (body with photosphere at its center) and M (group of some heavenly bodies arranged in the shape of M) as they are not the same kind of object. A is likely a star, while M is a group of stars.

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The input piston of a hydraulic press is 20 mm in diameter, and the output piston is 10 mm in diameter an input force of 1.0 n will produce an output force of 2.0 N

It is on par with P. O. It will be the same even if there is no note. One exists. We swap out 1.50.  and 0.25 m square and multiplied by 10 with the powers of six and four. find the pressure that has been applied to the input distance. P. I. 200 power six newtons divided by 0.25 m square will equal 6.0 by replacing the figures we obtain. It had been multiplied by 10 and then by 888-349-8884. 20 power six P.A., yes. That was Mhm. The pressure of the input question is 6.0. Ten 20 was multiplied by six B. It's A. Here is the second section. The phrase is written. The expression for the input force is written first. The formula is F.I. Equals P. It's A. I. It's an opportunity to hear AI. Does the input cause the pressure? Equation also contains a single number. By swapping values, we arrive at F = P. I. In between the parentheses was the priority square. We believe it to be a third creation. The power six P. F. or P. I.N. 0.25 M replaces the 0.0. By changing the value for 6.0, we obtain F. The pole square of 0.25 m is a new record. You can eventually multiply by 10 to the power of four newtons. The power for Newton is calculated by dividing the force applied to the input by 10.

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Answer:

There are two answers:

When player 1 collided with player 2, player 1's kinetic energy transferred to player 2.

Player 1 could slow down, stop , change direction, or fall, while player 2 would begin moving away from the collision point and possibly fall.

Explanation:

Answer:

The resultant velocity of the plane relative to the ground is;

150 kh/h north

Explanation:

The flight speed of the plane = 210 km/h

The direction of flight of the plane = North

The speed at which the wind is blowing = 60 km/h

The direction of the wind = South

Therefore, representing the speed of the plane and the wind in vector format, we have;

The velocity vector of the plane = 210.\(\hat j\)

The velocity vector of the wind = -60.\(\hat j\)

Where, North is taken as the positive y or \(\hat j\) direction

The resultant velocity vector is found by summation of the two vectors as follows;

Resultant velocity vector = The velocity vector of the plane + The velocity vector of the wind

Resultant velocity vector = 210.\(\hat j\)  + (-60.\(\hat j\)) =  210.\(\hat j\)  - 60.\(\hat j\) = 150.\(\hat j\)

The resultant velocity vector = 150.\(\hat j\)

Therefore, the resultant velocity of the plane relative to the ground = 150 kh/h north.

40 N is the magnitude of the constant friction force that acts on her as she slides.

According to the scenario, computation of given data are as follows:

Mass (m) = 20 kg

Initially moving (v) = 3

Actual distance (d) = 2.25 m

So, we can calculate friction (f) by using following formula,

f × d =mv^2/2

By putting the value, we get

f × 2.25 =  20 ×9/2

f × 2.25 = 10 × 9

f = 90 ÷ 2.25

= 40 N.

The force that prevents motion when the surfaces of two objects come into contact is known as friction. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output to input ratio.

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The given statement "When light hits the boundary between two different materials, it can undergo both reflection and refraction" is true because Reflection occurs when the light bounces off the object and refraction leads  to bending and change in the direction .

The reflection defined as the bouncing back of the light when it strikes the smooth surface. The refraction defined as  the bending of the light rays when it will travels from the one medium to the another. Generally it occurs on the shinny surfaces that will only allow the rebounding of the light without permitting the penetration through it.

The reflection and the refraction both occurs when light hits the boundary between two different materials.

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A charge of -1e would be present in an antibaryon made up of two antiup quarks and one anti-down quark. Option 2 is correct.

When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.

The complete question is

"An antibaryon composed of two antiup quarks and one anti down quark would have a charge of

(1) +1e

(2) −1e

(3) 0e

(4) −3e"

An antibaryon composed of two antiup quarks and one anti-down quark would have a charge of  −1e.

Hence,option 2 is correct.

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Answer:

C. C

Explanation:

A wave can be defined as a disturbance in a medium that progressively transports energy from a source location to another location without the transportation of matter.

In Science, there are two (2) types of wave and these include;

I. Electromagnetic waves: it doesn't require a medium for its propagation and as such can travel through an empty space or vacuum. An example of an electromagnetic wave is light.

II. Mechanical waves: it requires a medium for its propagation and as such can't travel through an empty space or vacuum. An example of a mechanical wave is sound.

A crest can be defined as the highest (vertically) point on a waveform.

On a related note, a trough is the lowest (vertically) on a waveform.

An amplitude can be defined as a waveform that's measured from the center line (its origin or equilibrium position) to the bottom of a trough or top of a crest. Thus, the vertical axis (y-axis) is the amplitude of a waveform i.e it's measured vertically.

In this scenario, waveform C which is represented by a blue curvy line has the smallest amplitude in comparison with the other waveforms because it has the minimum height when measured from the origin.

In contrast, waveform A represented by a purple line has the highest amplitude because it has the maximum height when measured from the origin.

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

Answer:

The answer is indeed D as the comment above suggests.

Explanation:

Simply put, wave D's highest point is closer to the line than all of the other high points of A, B and C

As early chemists worked to purify ores and discovered more elements, they realized that various elements could be grouped together by their similar chemical behaviors.

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The pressure at the bottom of the column is determined as 94,080 Pa.

The hydrostatic pressure of the water column is pressure exerted due to the vertical column of water and it can be calculated by applying the following formula.

Mathematically, hydrostatic pressure is given as;

P = ρgh

where;

The given parameters include the following;

Substitute the above parameters and solve for the pressure exerted by the water column.

P = 1000 x 9.8 x 9.6

P = 94,080 Pa

Thus, the pressure exerted by the column of the water depends on the depth of the water or water column.

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Answer:

refraction!

Explanation:

it's the bending of light. it makes it possible for us us have lenses, magnifying glasses, rainbows and other stuff

The correct pairs are:

distance to object A: 0.000006127 light-years

distance to object B: 30.06 AU

distance to object C: 0.082 light-years

The correct pairs in alternative units are:

distance to object A: 0.0001458 pc

distance to object B: 5.2 AU

distance to object C: 57.91 million km

distance to object A: 0.000001877 pc = 0.000006127 light-years (using the conversion factor 1 parsec = 3.262 light-years)

distance to object B: 30.06 AU (no conversion needed as the distance is already given in astronomical units)

distance to object C: 778.3 million km = 0.082 light-years (using the conversion factor 1 light-year = 9.5 × 10^12 km)

So, the correct pairs are:

distance to object A: 0.000006127 light-years

distance to object B: 30.06 AU

distance to object C: 0.082 light-years

Alternatively, we can express the distances in other equivalent units:

distance to object A: 0.0001458 pc (using the conversion factor 1 light-year = 9.5 × 10^12 km)

distance to object B: 5.2 AU (using the conversion factor 1 AU = 1.5 × 10^8 km)

distance to object C: 57.91 million km (no conversion needed as the distance is already given in kilometers)

So, the correct pairs in alternative units are:

distance to object A: 0.0001458 pc

distance to object B: 5.2 AU

distance to object C: 57.91 million km

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Yes, melting lead into a liquid to form pellets is a physical change.

This is because the chemical composition of lead remains the same even after it has been melted and then solidified into pellets. In other words, the molecular structure of lead does not change during the melting process, but only the physical state of the material changes from a solid to a liquid and then back to a solid. This type of change is reversible and can be undone by cooling the lead pellets to their solid state. Therefore, melting lead to form pellets is an example of a physical change rather than a chemical change.

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--The complete Question is, Is lead melting into liquid to form pellets a physical change? --

Answer:

The speed of the faster ship is 22.5 m/s

Explanation:

The length of the ships are;

Ship 1 = 200 m

Ship 2 = 100 m

The time it takes for the ships to completely cross each other when travelling in opposite directions = 10 seconds

The time it takes both ships to cross each other when travelling in the same direction = 25 seconds

Let x represent the speed of the first ship, ship 1, and y represent the speed of the second ship, ship, 2, we have;

(x + y) × 10 = 200 + 100 = 300

10·x + 10·y = 300...(1)

(x - y) × 20 = 200 + 100 = 300

20·x - 20·y = 300...(2)

Multiply equation (1) by 2, to get;

(x + y) × 10 × 2 = 300 × 2

20·x + 20·y = 600...(3)

Adding equation (1) to equation (3) gives;

20·x + 20·y + 20·x - 20·y = 600 + 300

40·x = 900

x = 900/40 = 22.5

x = 22.5

The speed of the first ship, ship 1 = x = 22.5 m/s

From equation (1), we have;

10·x + 10·y = 300

y = (300 - 10·x)/10 = (300 - 10×22.5)/10 = 7.5

y = 7.5

The speed of the second ship, ship 2 = y = 7.5 m/s

Therefore, the faster ship is ship 1 with a speed of 22.5 m/s

The average power developed by the cheetah during the acceleration phase of its motion is approximately 1,377 watts (W) or 1.84 horsepower (hp).

Power is defined as the rate at which work is done or energy is transferred. The formula to calculate power is: power = work / time.

Given:

Final velocity (v) = 8.1 m/s

Initial velocity (u) = 0 m/s (starting from rest)

Time (t) = 1.2 s

Mass (m) = 112 kg

To find the work done, we can use the formula: work = (1/2)mv² - (1/2)mu².

Since the initial velocity is 0, the equation simplifies to: work = (1/2)mv².

Substituting the values, we have:

Work = (1/2)(112 kg)(8.1 m/s)²

Work ≈ 3,156.432 joules (J)

Now, we can calculate the average power using the formula:

Power = Work / Time

Power = 3,156.432 J / 1.2 s

Power ≈ 2,630.36 W

Therefore, the average power developed by the cheetah during the acceleration phase is approximately 2,630.36 watts (W).

To convert this to horsepower, we can use the conversion factor: 1 horsepower = 745.7 watts.

So, to calculate the power in horsepower:

Power (in hp) = 2,630.36 W / 745.7

Power ≈ 3.53 hp

The average power developed by the cheetah during the acceleration phase of its motion is approximately 1,377 watts (W) or 1.84 horsepower (hp). This power output reflects the rate at which work is done by the cheetah in accelerating its mass. The calculations involve finding the work done using the formula for kinetic energy and then dividing it by the time taken to calculate the average power. The conversion from watts to horsepower is included as an additional unit of power measurement.

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Explanation: Well, If you arrive in my class 45 seconds after leaving math, which is 90 meters away. you traveled 2m/s ( I hope this helped <3)

In the context of the Ballistic Pendulum and Projectile Motion, the expression for the time (t) it takes the ball to hit the floor when fired from the launcher is given by: t = √(2h/a)

In the context of the Ballistic Pendulum and Projectile Motion, the expression for the time (t) it takes the ball to hit the floor when fired from the launcher can be found using the following steps and formula below:

Step 1:

Write down the formula for the projectile motion, where t represents the time taken, v represents the initial velocity, a represents the acceleration due to gravity, and d represents the vertical distance traveled, such that: d = vt + (1/2)at²

Step 2:

Recognize that in this case, the ball is fired horizontally and thus the initial velocity in the vertical direction is zero. Therefore, v = 0 and the formula can be rewritten as: d = (1/2)at²

Step 3:

Since the ball is fired into the ballistic pendulum, the vertical distance traveled can be measured as the height that the pendulum swings to after being struck. Therefore, substitute d with h, the height of the pendulum's swing, and the formula becomes: h = (1/2)at²

Step 4:

Rearrange the formula to solve for t, the time taken by the ball to hit the floor when fired from the launcher such that:

t = √(2h/a)

Step 5:

Check units. The expression for time (t) has the units of seconds (s) which is appropriate since it represents the duration of time taken for the ball to hit the floor when fired from the launcher. The units of height (h) are in meters (m) and the units of acceleration due to gravity (a) are in meters per second squared (m/s²).

Therefore, the expression for the time (t) it takes the ball to hit the floor when fired from the launcher is given by:

t = √(2h/a)

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