A line drawn from the leading edge to the trailing edge of an airfoil and equidistant at all points from the upper and lower contours is called the

Answers

Answer 1

A line drawn from the leading edge to the trailing edge of an airfoil and equidistant at all points from the upper and lower contours is called the mean camber line.

The mean camber line is a very important concept in aerodynamics as it defines the overall shape of an airfoil and plays a key role in determining its aerodynamic characteristics, such as lift and drag. It is used to calculate the maximum thickness, maximum camber, and location of the maximum camber of an airfoil.

The mean camber line is typically used as a reference line when designing airfoils, and different shapes can be created by modifying it with specific curves and angles.

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Related Questions

Summary of Possible Weather and Associated Aviation Impacts for Geographic/Topographic Categories Common in the Western United States.
Geographic/Topographic Descriptive Summary of Potential Aviation Impacts
Category of a Possible Weather That Could Impact Based on Weather
of Airport Location Aviation Operations
Along the US West coast,
with steep mountains to the east
(An example of this category is
Santa Barbara Airport, located
on the Southern California Coast,
at an elevation of 10 feet).
Within a valley in elevated terrain
surrounded by high mountains
(An example of this category is
Friedman Memorial Airport, located
in Central Idaho, at an elevation of 5300 feet).
In elevated terrain on the leeside of
high mountains
(An example of this category is Northern Colorado
Regional Airport, located in northern Colorado,
at an elevation of 5000 feet, on the leeside
of the Rocky mountains).

Answers

Answer: answer provided in the explanation section.

Explanation:

Weather phenomenons that would impart Aviation Operations in Santa Barbara -

1. Although winters are cold, wet, and partly cloudy here. It is in general favorable for flying. But sometimes strong winds damage this pleasant weather.

2.  The Sundowner winds cause rapid warming and a decrease in relative humidity. The wind speed is very high surrounding this area for this type of wind.  

3. Cloud is an important factor that affects aviation operations. Starting from April, here the sky is clouded up to November. The sky is overcast (80 to 100 percent cloud cover) or mostly cloudy (60 to 80 percent) 44% on a yearly basis. Thus extra cloud cover can trouble aviation operations.

4. The average hourly wind speed can also be a factor. This also experiences seasonal variations, these variations are studied carefully in the aviation industry. The windier part of the year starts in January and ends in June. In April, the wind speed can reach 9.5 miles per hour.

This and more are some factors to look into when considering wheather conditions that would affect aviation operations.

I hope this was a bit helpful. cheers

organizations must correctly identify their and pursue strategies that best meet their needs.

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In order to achieve their goals and objectives, organizations must identify and pursue strategies that best meet their needs. As a result, it is critical for organizations to properly identify their needs and objectives. After that, they must choose the right strategy to achieve their goals.

Strategic management assists organizations in achieving their objectives and goals by allowing them to determine the best course of action for their company.The following are some of the advantages of pursuing the right strategies that best meet the needs of an organization:Improved understanding: Organizations that pursue the right strategies for their company are more likely to comprehend their operations, customers, and environment more effectively. This aids in the development of strategies that are better suited to the company's needs.Effective decision-making: Strategic planning is an important component of effective decision-making.

An organization that has successfully identified and pursued the right strategies for its needs is better positioned to make sound business decisions.Cost reduction: By pursuing the right strategy, an organization can lower its costs.

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The steel-frame structural support was a main feature in the development of __________. Group of answer choices

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The steel-frame structural support was a main feature in the development of t the floors, roof, walls and  skyscraper.

What structure is aided by a metal frame?

Steel frame is known to be a form of a building method that is used along with a skeleton frame that is made up of steel columns and  I-beams.

Conclusively, This is often used  in the construction of grid to aid the floors, roof and walls of any kind of building. It is also used in the construction of skyscraper.

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An elevation is.... * 10 points a. A detailed description of requirements, composition and materials for a proposed building. b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building. c. The development of the last remaining lots in an existing developed area, the new development within an area already served by existing infrastructure and services, or the reuse of already developed, but vacant properties. d. The practice of creating structures and using processes that are environmentally responsible and resource-efficient throughout a building's life-cycle from siting to design, construction, operation, maintenance, renovation and deconstruction.

Answers

Answer:

b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.

Explanation:

An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.

It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.

what term is used to describe the study of designing machines and work settings to minimize injury and illness?

Answers

The term used to describe the study of designing machines and work settings to minimize injury and illness is ergonomics.

Ergonomics is the science of designing machines and work settings to fit the needs of the worker, taking into account their physical, cognitive, and psychological capabilities.

This includes designing machines and work settings to reduce the risk of injury or illness, and to improve comfort, safety, and efficiency.

Ergonomics also focuses on designing workstations, tools, and processes to be as ergonomically friendly as possible. This includes providing adjustable chairs, adjustable keyboards and mice, and making sure that tasks don't require the worker to be in the same position for extended periods of time.

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According to astm d2487, a piece of stone with a 1.5-inch diameter is considered:______.

Answers

Answer: Your answer friend is Boulder. Good luck man

Explanation:

in the (fill in the blank) process, the sculptor begins with a mass of material, chipping it away as the work proceeds.

Answers

In the Subtractive Process , the sculptor begins with a mass of material, chipping it away as the work proceeds.

What is Subtractive Process?

A solid block of starting material is depleted by subtractive processes. Boring, milling, and machining are all subtractive operations used to make or change shapes.

A broad term for various controlled machining and material removal processes, subtractive manufacturing refers to the shaping of solid blocks, bars, and rods of plastic, metal, or other materials by removing material through cutting, boring, drilling, and grinding.

Turning is a subtractive machining technique that produces a range of shapes for finished components made of stone, wood, metal, or plastic.

Subtractive mixing gets its name from the fact that when paints are mixed, wavelengths are removed from what we see because each paint absorbs some of the wavelengths that the other paint reflects, leaving us with fewer wavelengths afterward.

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A picture of a ______ is the label pictogram on a chemical that warns of a product's acute toxicity.
A) Flame over circleB) Gas cylinderC) Skull and crossbonesD) Bomb

Answers

Answer:

C) Skull and crossbones

Explanation:

Its on the OSHA website under HCS Pictograms and Hazards

1. A saturated soil with a mass of 43.2gr. When dried in the oven its mass was 30gr. The volume of the wet sample is 20 cm3 and the dry sample is 12 cm3. Find the limit of contraction.
2. The unit weight of a saturated soil is 2010 kg/m3, if its Gs = 2.74, determine the dry unit weight(γus), e, n and Moisture content (w (%)).
Please do not do it directly but put formulas also to see the steps.

Answers

A saturated soil with a mass of 43.2g. When dried in the oven its mass was 30g, the limit of contraction is 0.4.

For the limit of contraction, we know that:

Limit of contraction (Lc) = (Vw - Vd) / Vw

Lc = (20 - 12) / 20

Lc = 8 / 20

Lc = 0.4

Therefore, the limit of contraction is 0.4.

Now for the dry weight,

Dry unit weight (γd) = γw / (1 + e)

e = (Gs - 1) / Gs

n = e / (1 + e)

w = (wet weight - dry weight) / dry weight

In this case,

γw = 9.81 kN/\(m^3\)

Gs = 2.74.

So,

γd = 2010 / (1 + ((2.74 - 1) / 2.74))

γd = 2010 / (1 + 0.727)

γd = 2010 / 1.727

γd = 1163.54 kg/m^3

e = (2.74 - 1) / 2.74

e = 1.74 / 2.74

e ≈ 0.635

n = 0.635 / (1 + 0.635)

n = 0.635 / 1.635

n ≈ 0.388

w = (43.2 - 30) / 30

w = 13.2 / 30

w ≈ 0.44

Therefore, the dry unit weight (γd) is approximately 1163.54 kg/m^3, the void ratio (e) is approximately 0.635, the porosity (n) is approximately 0.388, and the moisture content (w) is approximately 0.44.

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The least value of the extraterrestrial solar radiation is in ed 2.00 Select one: on O a. Autumn O b. Spring Oc Constant throughout the year O d. Summer O e. Winter Apyranometer with a shading ring to measure diffuse radiation at location with latitude 0° on Fe a reading of 100 W/m2 What is the adjusted reading of this pyranometer?

Answers

The least value of extraterrestrial solar radiation is constant throughout the year. Therefore, the answer is option (c) Constant throughout the year. The extraterrestrial solar radiation is the amount of solar radiation received from the sun at the top of the Earth's atmosphere, the solar constant (Isc). The adjusted reading of the pyranometer is 82 W/m2.

The least value of extraterrestrial solar radiation is constant throughout the year. A pyranometer is an instrument used for measuring the solar irradiance (total energy flux from the Sun) that falls upon a planar surface. A pyranometer with a shading ring is used to measure diffuse radiation at a location with a latitude of 0°.If a pyranometer with a shading ring is used to measure diffuse radiation at a location with a latitude of 0° and it has a reading of 100 W/m2, the adjusted reading of this pyranometer will be as follows:

Let’s assume the correction factor of a pyranometer with a shading ring is 0.18. Therefore the adjusted reading of pyranometer is calculated as: Adjusted reading = (1 - 0.18) × reading= 0.82 × 100= 82 (W/m2).

Therefore, the adjusted reading of the pyranometer is 82 W/m2.

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Water and air quality are critical issues facing human society.


True

False

Answers

Humans impact the physical environment in many ways: overpopulation, pollution, burning fossil fuels, and deforestation. Changes like these have triggered climate change, soil erosion, poor air quality, and undrinkable water.

1: A baseball is hit 4 feet above the ground leaves the bat with an initial speed of 98 ft/sec at an angle of 0 45 is caught by an outfielder at a height of 3 feet.

Answers

Answer:

299.36 feet

Explanation:

\(To \ find \ the \ distance \ of \ the \ ball \ from \ the \ home \ plate. \\ \\ From \ the \ given \ information:\)

\(Height \ h = 4 \ ft\)

\(Initial \ speed \ V_o = 98 \ ft/s ec\)

\(The \ angle \ \theta = 45^0\)

\(Acceleration \ due \ to \ gravity (g)= 32.2 \ ft/s\)

\(U_x = V_o \ cos 45 = \dfrac{98}{\sqrt{2}}\)

\(U_y = V_o \ sin 45 = \dfrac{98}{\sqrt{2}}\)

So;

\(S_y = u_y t - \dfrac{1}{2}gt^2\)

\(-1 =\dfrac{98}{\sqrt{2}}t - \dfrac{1}{2}*32*1.85t^2\)

By solving:

\(t_1 = 4.32 \ sec\)

Thus;

\(horizontal \ distance = U_x t\)

\(= \dfrac{98}{\sqrt{2}}\times 4.32\)

\(\mathbf{=299.36 \ feet}\)

\(\mathbf{Thus \ , the \ distance \ from \ the \ home \ plate \ = \ 299.36 \ feet}\)

A highway has the following pavement design
daily traffic: 300 single axles at 10,000 lb each, 120
single axles at 18,000 lb each, 100 single axles at
23,000 lb each, 100 tandem axles at 32,000 lb each,
30 single axles at 32,000 lb each, and 100 triple axles
at 40,000 lb each. A flexible pavement is designed to
have 4 inches of sand-mix asphalt wearing surface, 6
inches of soil-cement base, and 7 inches of crushed
stone subbase. The pavement has a 10-year design
life, a reliability of 85%, an overall standard
deviation of 0.30, drainage coefficients of 1.0, an
initial PSI of 4.7, and a TSI of 2.5. What is the
minimum acceptable soil resilient modulus?

Answers

Answer:

pay attention in class how about that

Explanation:

thats the answer

A truss is subjected to three loads. The truss is supported by a roller at A and by a pin joint at B. What is most nearly the reaction force at B

Answers

Answer:

Hello the diagram related to the question is missing attached is the diagram

Answer : 3833.33 KN

Explanation:

The most nearly reaction force at B

= ∑ Mb = 0 = 21Ay

= (2000 * 17.5 ) + ( 3000 * 10.5 ) + ( 4000 * 3.5 )

= 35000 + 31500 + 14000 = 80500

therefore Ay = 80500 / 21 = 3833.33 KN

x = 7/2 = 3.5m

A truss is subjected to three loads. The truss is supported by a roller at A and by a pin joint at B.
A truss is subjected to three loads. The truss is supported by a roller at A and by a pin joint at B.

An aluminum cylinder is 5cm long and has a mass of 42g. If aluminum has a density of 2700*9/m 3, how long is the cylinder?

Answers

The radius of the cylinder is the length that measures from the center to the parameter. The length of the cylinder is 1 cm.

What is Density?

The density of the given substance can be used as the measure of the mass and the volume of the substance.

Given,

Length of the aluminum cylinder = 5cm

Mass = 42 g

Density of aluminum = 2700 kg/ m³ = 2.7 gm/cm³

From the density the volume is calculated as:

Density = mass ÷ volume

2.7 = 42 ÷ V

V = 42 ÷ 2.7

= 15.56

The radius of the cylinder is calculated as:

(r) = √(V / π × h)

Here, V =  15.56, π = 3.14, h = 5 cm

Substituting values:

r = √(15.56 ÷ 3.14 × 5)

= √ (15.56 ÷ 15.7)

= 0.99

= 1

Therefore, 1 cm is the length.

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unfortunately, there is no way to store and call on functions when using turtle graphics.

Answers

Unfortunately, when using turtle graphics, there is no built-in way to store and call on functions. This means that each time you want to use a particular set of commands, you have to rewrite them in your code.

However, there are some workarounds that you can use to achieve similar functionality. One option is to define a list of commands as a variable, and then iterate through that list using a for loop. Another option is to define a custom function that takes in parameters and then executes a set of turtle commands based on those parameters.

While these solutions may not be as elegant as having built-in function storage and calling, they can still be effective for simplifying your code and reducing repetition. Overall, it's important to be creative and resourceful when working with turtle graphics, and to explore different approaches until you find one that works best for your specific needs.

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What measurement is the usable area of conduit based on?

Answers

the cable outside diameter and the conduit inside diameter.

Which gas is released in the SMAW process causing a
shielding affect on the molten weld pool?

•nitrogen

•carbon dioxide

•argon

•hydrogen

Answers

Argon ( I’m not sure )

Strength of learning is one factor that determines how long-lasting a learned response will be. That is, the stronger the original learning (e.g., of nodes and links between nodes), the more likely relevant information will be retrieved when required. Discuss three of the six factors enhancing the strength of learning.

Answers

Three factors that enhance the strength of learning are repetition, meaningfulness, and emotion.

How  is this so?

Repetition involves repeating information or practicing a skill multiple times, which helps reinforce memory and retrieval.

Meaningfulness refers to connecting new information to existing knowledge or personal experiences, making it more relevant and easier to understand.

Emotion plays a significant role in memory consolidation and retrieval, as emotionally charged experiences tend to be more memorable.

Thus, these factors contribute to stronger learning and improve the likelihood of successful retrieval when needed.

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helppppppp plssss Identifying job responsibilities for staff members is an example of which section of the project charter?


project requirements

project objectives

project team

project description

Answers

The correct answer is project team.

There are withdrawn 100 ft3
of air measured at 30 psia and 90°F from a 50 ft3
tank containing air
initially at 100 psia and 140°F. What is the pressure of the air remaining in the tank if its
temperature is 130 °F?

Answers

Answer:

2+2g

what time is good afternoon my

A venture tube is used to measure the flow rate of a liquid in a pipe (liquid density is 800 kg/m3). The pipe has a diameter of 10 cm and the smallest diameter of the venture has a diameter of 4 cm. A manometer with a manometer fluid of mercury (specific weight of 133 kN/m3) is used to calculate the flow rate which is connected to the venture section such that one leg is far upstream and the second leg is at the minimum diameter of the venture tube. If the flow rate is 0.05 m3/s determine the elevation change in the manometer fluid.
a. 14.6 m
b. 9.28 m
c. 4.64 m
d. 2.32 m

Answers

Answer:

\(\triangle h=4.935m\)

Explanation:

From the question we are told that:

Liquid density \(\rho=800\)

Diameter of pipe \(d=4cm \approx 0.004m\)

Diameter of venture \(d=10cm \approx 0.010m\)

Specific weight of mercury P_mg \(133 kN/m^3\)

Flow rate \(r=0.05 m^3/s\)

Area A:

            \(A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\\)

Generally the Bernoulli's equation is mathematically given by

\(\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\\)

Where

\(V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}\)

Therefore

\(P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

Generally the equation for pressure difference b/w manometer fluid is given as

\(P_1-P_2=(p_mg-pg)\triangle h\)

Therefore

\((p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

\(\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}\)

\(\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}\)

\(\triangle h=4.935m\)

Therefore elevation change is mathematically given by

\(\triangle h=4.935m\)

Technician a says that a steering column may be designed to absorb energy technician b says that vehicle seats may be designed to absorb energy who’s right

Answers

Since Technician A says that a steering column may be designed to absorb energy and Technician B says that vehicle seats may be designed to absorb energy. The both of them ( Tech A and B) are right.

What does a car's steering column do?

The rod that the steering wheel is mounted to is known as the steering column of a vehicle. On a shaft inside the steering column, the steering wheel is mounted. The steering inputs are delivered to the steering rack or box by the steering column.

A shaft that passes through the steering column is used to link the steering wheel to the shaft.

Therefore, The purpose of bumper reinforcements, which are often made of highly strong materials like UHSS or aluminum, is to spread the crash energy.

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The UHRS platform is optimized for Edge/Internet Explorer only. You can still use your favorite browser, but keep in mind that you may experience technical issues when working on UHRS with a different browser than Edge or Internet Explorer.

UHRS is optimized for...

Answers

It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

What is a UHRS?

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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What energy transformation takes place when you turn on a light

Answers

Answer:

From electrical energy to radiation

Explanation:

A light bulb converts electrical energy to light, which is nothing more than radiation. Don't regard radiation as a bad thing, this light is non-iodizing radiation, which does not have the possibility to alter our DNA, and thus it's safe.

The simplest example can be found in old lights (obsolete now because they are vastly inefficient). This lights were just resistors which turned electrical energy into heat. A very hot material reflects light in the form of radiation, as described above.

Technologies like LEDs are more complicated to explain.

how should a vfr flight plan be closed at the completion of the flight at a controlled airport?

Answers

When completing a VFR flight at a controlled airport, it is important to close the flight plan with the appropriate authorities. The first step is to contact the appropriate air traffic control facility and advise them that you have completed your flight and would like to close your VFR flight plan. This can be done either through radio communication or by phone.

If you are communicating via radio, the controller will ask you for your aircraft identification, and then confirm that your flight plan has been closed. They may also ask for additional information, such as your current position or altitude. Once this information is provided, the controller will confirm that your VFR flight plan has been closed, and you can proceed with landing at the airport.

If you are unable to communicate via radio, you can also close your VFR flight plan by calling the appropriate facility via phone. You will need to provide your aircraft identification, as well as your current location and estimated time of arrival at the airport. The controller will then confirm that your VFR flight plan has been closed.

Overall, it is important to ensure that your VFR flight plan is properly closed at the end of your flight, in order to ensure safety and to avoid any confusion or miscommunication with air traffic control.

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Determine T and magnitude of R

Determine T and magnitude of R

Answers

Answer:

The magnitude of a vector →PQ is the distance between the initial point P and the end point Q . In symbols the magnitude of →PQ is written as | →PQ | . If the coordinates of the initial point and the end point of a vector is given, the Distance Formula can be used to find its magnitude.

Explanation:

what are the advantages of disc brakes compared to drum brakes?

Answers

Disc brakes offer several advantages over drum brakes.

The advantages

A) Better heat dissipation   - Disc brakes have a rotor exposed to air, allowing for efficient heat dissipation and reduced brake fade during heavy braking.

B) Improved stopping power - Disc brakes provide stronger and more consistent braking performance, enabling shorter stopping distances.

C) Easier maintenance  - Disc brakes are easier to inspect, service, and replace, making maintenance tasks more straightforward.

D) Reduced weight - Disc brakes are generally lighter than drum brakes, contributing to overall vehicle weight reduction and improved fuel efficiency.

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6.03 Discussion: Then & Now - Safety
Discussion Topic
I'm Done
In this unit, you have learned about the evolution of the industry’s machines, through both technology and innovation. These improvements have reduced risk and injury to the Operating Engineers.

Choose one innovation or device.
Explain why you think that technology is the most important advancement in Operating Engineers’ safety.

Answers

Answer:

Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.

Large wind turbines with blade span diameters of over 100 m are available for electric power generation. Consider a wind turbine with a blade span diameter of 100 m installed at a site subjected to steady winds at 8 m/s. Taking the overall efficiency of the wind turbine to be 32 percent and the air density to be 1.25 kg/m3 , determine the electric power generated by this wind turbine. Also, assuming steady winds of 8 m/s during a 24-hour period, determine the amount of electric energy and the revenue generated per day for a unit price of $0.09/kWh for electricity

Answers

Answer:

The wind turbine generates \(19297.222\) kilowatt-hours of electricity daily.

The wind turbine makes a daily revenue of 1736.75 US dollars.

Explanation:

First, we have to determine the stored energy of wind (\(E_{wind}\)), measured in Joules, by means of definition of Kinetic Energy:

\(E_{wind} = \frac{1}{2}\cdot \dot m_{wind}\cdot \Delta t \cdot v_{wind}^{2}\) (Eq. 1)

Where:

\(\dot m_{wind}\) - Mass flow of wind, measured in kilograms per second.

\(\Delta t\) - Time in which wind acts in a day, measured in seconds.

\(v_{wind}\) - Steady wind speed, measured in meters per second.

By assuming constant mass flow and volume flows and using definitions of mass and volume flows, we expand the expression above:

\(E_{wind} = \frac{1}{2}\cdot \rho_{air}\cdot \dot V_{air} \cdot \Delta t \cdot v_{wind}^{2}\) (Eq. 1b)

Where:

\(\rho_{air}\) - Density of air, measured in kilograms per cubic meter.

\(\dot V_{air}\) - Volume flow of air through wind turbine, measured in cubic meters per second.

\(E_{wind} = \frac{1}{2}\cdot \rho_{air}\cdot A_{c}\cdot \Delta t\cdot v_{wind}^{3}\) (Eq. 2)

Where \(A_{c}\) is the area of the wind flow crossing the turbine, measured in square meters. This area is determined by the following equation:

\(A_{c} = \frac{\pi}{4}\cdot D^{2}\) (Eq. 3)

Where \(D\) is the diameter of the wind turbine blade, measured in meters.

If we know that \(\rho_{air} = 1.25\,\frac{kg}{m^{3}}\), \(D = 100\,m\), \(\Delta t = 86400\,s\) and \(v_{wind} = 8\,\frac{m}{s}\), the stored energy of the wind in a day is:

\(A_{c} = \frac{\pi}{4}\cdot (100\,m)^{2}\)

\(A_{c} \approx 7853.982\,m^{2}\)

\(E_{wind} = \frac{1}{2}\cdot \left(1.25\,\frac{kg}{m^{3}} \right) \cdot (7853.982\,m^{2})\cdot (86400\,s)\cdot \left(8\,\frac{m}{s} \right)^{3}\)

\(E_{wind} = 2.171\times 10^{11}\,J\)

Now, we proceed to determine the quantity of energy from wind being used by the wind turbine in a day (\(E_{turbine}\)), measured in joules, with the help of the definition of efficiency:

\(E_{turbine} = \eta\cdot E_{wind}\) (Eq. 4)

Where \(\eta\) is the overall efficiency of the wind turbine, dimensionless.

If we get that \(E_{wind} = 2.171\times 10^{11}\,J\) and \(\eta = 0.32\), then the energy is:

\(E_{turbine} = 0.32\cdot (2.171\times 10^{11}\,J)\)

\(E_{turbine} = 6.947\times 10^{10}\,J\)

The wind turbine generates \(6.947\times 10^{10}\) joules of electricity daily.

A kilowatt-hours equals 3.6 million joules. We calculate the equivalent amount of energy generated by wind turbine in kilowatt-hours:

\(E_{turbine} = 6.947\times 10^{10}\,J\times\frac{1\,kWh}{3.6\times 10^{6}\,J}\)

\(E_{turbine} = 19297.222\,kWh\)

The wind turbine generates \(19297.222\) kilowatt-hours of electricity daily.

Lastly, the revenue generated per day can be found by employing the following:

\(C_{rev} = c\cdot E_{turbine}\) (Eq. 5)

Where:

\(c\) - Unit price, measured in US dollars per kilowatt-hour.

\(C_{rev}\) - Revenue generated by the wind turbine in a day, measured in US dollars.

If we know that \(c = 0.09\,\frac{USD}{kWh}\) and \(E_{turbine} = 19297.222\,kWh\), then the revenue is:

\(C_{rev} = \left(0.09\,\frac{USD}{kWh} \right)\cdot (19297.222\,kWh)\)

\(C_{rev} = 1736.75\,USD\)

The wind turbine makes a daily revenue of 1736.75 US dollars.

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