A long, straight metal rod has a radius of 5. 00cm and a charge per unit length of 30. 0nC/m. Find the electric field (c) 100cm from the axis of the rod, where distances are measured perpendicular to the rod's axis

Answer: The pressure decreases as the temperature decreases.

Explanation: As the temperature decreases, the particles of gas start moving more slowly. The particles' velocity decreases and as it collides with the wall of the container, it exerts a less force on the walls of the container. This follows on from the equation Ft = mv - mu. Less force therefore means less pressure as force and pressure are proportional according to equation Pressure = Force / Area.

The amount of heat that  is dropped in the hot reservoir is equal to 100 J. Option A

According to the first law of thermodynamics, we know that energy can neither be created nor destroyed but can be converted from one form another.  

We can see that as the heat is transferred from the we do some work so as to be able to extracts heat from a cold reservoir and dumps heat into a hot reservoir. Since heat can neither be created nor destroyed, the heat that is dumped must be equal to the amount of heat that is extracted.

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The net gravitational force acting on an object situated on this line segment is greatest at a distance of 119.5 thousand miles from the center of the earth.

If an imaginary line segment is drawn between the centers of the earth and the moon, then the net gravitational force F acting on an object situated on this line segment is given by F=(-K)/(x^(2))+(0.012K)/((239-x)^(2)) thousand miles, where K is a constant of proportionality that depends on the masses of the earth and moon, and x is the distance in thousands of miles from the center of the earth to the object.

The gravitational force acting on an object situated on this line segment is determined by the distances of the object from the centers of the earth and moon.

As the object moves away from the earth and closer to the moon, the gravitational force increases, and as it moves closer to the earth and farther from the moon, the gravitational force decreases.

The net gravitational force acting on an object situated on this line segment is the sum of the gravitational forces due to the earth and moon.

Since the gravitational force due to the earth is inversely proportional to the square of the distance from the center of the earth, while the gravitational force due to the moon is inversely proportional to the square of the distance from the center of the moon, the net gravitational force is given by the equation F=(-K)/(x^(2))+(0.012K)/((239-x)^(2)) thousand miles.The maximum value of the net gravitational force occurs at x=119.5 thousand miles.

At this distance, the net gravitational force is F=0.036K thousand miles.

As the object moves away from this distance, the net gravitational force decreases, and as it moves closer to this distance, the net gravitational force increases.

Thus, At a distance of 119.5 thousand miles from the earth's centre, the net gravitational force exerted on an item along this line segment is the strongest.

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Answer:

Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías

Explanation:

Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías

Explanation:

Density=mass/volume

Density=7.5/2.5

density=3g/cm^3

The density of a 2.5-cm3 glass marble that has a mass of 7.5 g is 3g/cm^3.

The density of a material is the measure of how tightly it is packed together. It is expressed as mass per unit volume.

Density Symbol: D or Density Formula: = m/V, where is the density, m is the object's mass, and V is the object's volume.

Density is the amount of "stuff" in a given amount of space. A block of the heavier element lead (Pb), for example, will be denser than a block of the softer, lighter element gold (Au). A Styrofoam block is less dense than a brick. It is expressed in terms of mass per unit volume.

Density = mass / volume

Density = 7.5 / 2.5

density = 3g/cm^3

Thus, The density of a 2.5-cm3 glass marble that has a mass of 7.5 g is 3g/cm^3.

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Answer: I don't have have an explanation but I know its A

Explanation:

Don't have one

We have that the gas will occupy at a pressure of 800 torr if temperature is held constant a Volume of

\(V_2=0.18L\)

From the Question we are told that

Initial Pressure \(P_1=720\)

final Volume  \(V_1=200mL\)

Initial Pressure \(P_2=800\)

final Volume  \(V_2=?\)

Generally the equation for Boyle's law  is mathematically given as

\(P_1V_1= P_2V_2\)

Therefore

\(V_2=\frac{ P_1V_1}{P_2}\\\\V_2=\frac{ 720*200}{800}\\\\V_2=180mL\)

\(V_2=0.18L\)

The gas will occupy at a pressure of 800 torr if temperature is held constant a Volume of

\(V_2=0.18L\)

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In comparison to a galaxy and a planet, a star is heavier. an accurate comparison of the cosmological masses of various objects.

A galaxy has a mass that is between that of a moon and that of a planet. A planet has more mass than a star, which has less mass than a galaxy. The stars need a lot of mass to maintain nuclear fusion, which requires resulted in the production of each.

Planets and stars, solar systems, galaxies, and the cosmos are some key concepts to keep in mind in the following order: smallest to largest. Each phrase is a part of the following.

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Let us assume that the initial direction of the ball, i.e., from the pitching machine to the batter as the negative direction, and the final direction of the ball is the positive direction.

Given,

The mass of the baseball, m=0.148 kg

The initial velocity of the baseball, u=-26 m/s

The final velocity of the baseball, v=39 m/s

The momentum of the ball before the batter hits it is given by,

On substituting the known values,

The momentum of the ball after the batter hits it is given by,

On substituting the known values,

The change in the momentum is given by,

On substituting the known values,

Thus the change in the momentum of baseball is 9.62 kg·m/s

The correct option is 4.

The process by which the isotope 56Fe decays into the isotope 56Co is beta decay.

The correct option is 4.What is beta decay? Beta decay is a type of radioactive decay in which a beta particle, a positron, or an electron is emitted by the nucleus of an atom. Beta decay is a decay process in which the atomic nucleus emits beta particles, which are high-energy, high-speed electrons or positrons.

In beta decay, a neutron in the nucleus transforms into a proton, causing the emission of an electron and a neutrino in the process. The isotope 56Fe decays into the isotope 56Co by the following beta decay process:56Fe26 → 56Co27 + β−where β- is a beta particle, and it is emitted from the nucleus, resulting in an increase in atomic number Z by one, while atomic mass number A remains unchanged. The daughter isotope is 56Co.

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(6) The angular speed of the blade is 293.2 rad/s.

(7) The linear speed of the tips of the blades in miles per hour is 305.4  mph.

(8) The linear speed of the tips of the blades in feet per second is 8.71 ft/s.

(9) The linear speed in miles per hour in which he is traveling is 10.78 mph.

(6) The angular speed of the blade is calculated as follows;

Diameter of the blade = 9 inches, radius = 4.5 inches

angular distance of the blade = 2800 rev/min

ω = 2800 rev/min  x 2π rad/rev  x  1 min / 60s

ω = 293.2 rad/s

(7) The linear speed of the tips of the blades in miles per hour is calculated as;

v = ωr

the angular speed, ω = 5 rev/s  x 2π rad/rev = 31.42 rad/s

r = 14 ft = 0.0027 mile

the linear speed, v = 31.42 rad/s  x 0.0027  mile = 0.085 mi/s

= 0.085 mi/s x 3600 s / hr = 305.4  mph

(8) The linear speed of the tips of the blades in feet per second is calculated as;

r = 25 inch = 2.08 ft

ω = 40 rev/min  x  2π rad/rev  x 1 min / 60s = 4.19 rad/s

the linear speed = v = 4.19 rad/s x 2.08ft = 8.71 ft/s

(9) The linear speed in miles per hour in which he is traveling is calculated as;

Diameter = 28 inches, radius = 14 inches

14 inches = 0.00022 mile

ω = 130 rev/min  x  2π rad/rev   x   60 min/1 hr = 49,008.85 rad/hr

the linear speed, v = 49,008.85 rad/hr x  0.00022 mile = 10.78 mph

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Answer:

A

Explanation:

Amplitude = height of the wave = 1

Wavelength = 3

They are slightly shifted.

The first statement is the correct one.  Don't make me type the whole thing out.

Answer:

Energy is being transferred

Explanation:

If you are pushing an object, you are transferring your energy to the object causing it to move

The force constant of the spring is 2,717 × \(10^{3}\) N/m

To solve this problem, we should understand Hooke's Law. According to this law, the displacement or magnitude of a deformation is directly proportional to the deforming force or load for relatively modest deformations of an item. Mathematically, Hooke's Law could be stated in a form of equation as written below.

\(F = k\) Δ\(x\)

where \(F\) is the force, \(k\) is the spring constant, and Δ\(x\) is the displacement.

In this question, we have already known the value of force (as a result of multiplication between weight of the load and gravity value) and displacement.

\(F = 178 N\)

Δ\(x\)\(= 0.0655 m\)

By using the formula of Hooke's Law, we could calculate the value of spring constant.

\(F = k\) Δ\(x\)

\(k=F/\)Δ\(x\)

\(k = 178 N / 0.0655\)

\(k = 2717 N/m\)

\(k = 2,717\) × \(10^{3} N/m\)

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The impurity molecules have time to return to the solution if they don't fit the environment well. To create a very saturated solution, keep adding solute to the solution up until a point where it manifests as a solid precipitate or crystals.

A decreased temperature and/or a phase shift are typically the results of cooling, which is the removal of heat. Cooling can also refer to any method of reducing temperature. The exchange of thermal energy can take place by convection, heat conduction, or thermal radiation.

Ice can turn into liquid water if it's heated up enough. A substance's molecules move more quickly when it is heated. A substance's molecules travel more slowly as it is cooled.

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Answer:

the source of sound moves towards an observe

Explanation:

The Doppler effect is related to waves such as sound or light. the effect causes an increase or decrease in the frequency of sound light or other waves when the souces either move towards or away from the observer. For example the siren of the train to a person on the platform, the redshift seen by astronomers.

Therefore, The Doppler shift can be observed when the source of sound moves towards an observer From a place closer to the observer than the last wave's crest, each consecutive wave crest is sent. Each wave therefore, takes a little less time than the preceding wave to reach the observer.

Answer:

45

Explanation:

because you divide volume and mass

Answer:

a=f/p

Explanation:

p=f/a

f=p×a

this all

Explanation:

w = (4.52 ± 0.02) cm, x = ( 2.0 ± 0.2) cm, y = (3.0 ± 0.6) cm. Find z = x + y - w and its uncertainty.

z = x + y - w = 2.0 + 3.0 - 4.5 = 0.5 cm

Dz = Dx + Dy + Dw = 0.2 + 0.6 + 0.02 = 0.82 rounding to 0.8 cm

So z = (0.5 ± 0.8) cm

Solution with standard deviations, Eq. 1b, Dz = 0.633 cm

z = (0.5 ± 0.6) cm

Notice that we round the uncertainty to one significant figure and round the answer to match.

A car with a mass of 1,060.0 kg accelerates from 0 to 88.0 km/h in 10.0 sec .The net force (in n) on the car during its deceleration is F = 7812.5 N.

Given

m= 1000 kg

u= 0 m/s

V = 90 km/h = 25m/s

t = 10 sec

a)by equation of motion :

v = u+at

25 = 0+ ax10

a = 2.5 m/c2

( b )By newton's law;

F= m*a

F=100X 2.5

F =2500N

( C )

u= 25m/s

V = 0

S = 40m

by equation of motion ;

v² = u²+2as

0=25²+80a

a=-7.8125 m/s²

by newton's law

F= m*a

F= 1000X 7.8125

F = 7812. 5N

A higher level motion control operation than velocity control is the control of acceleration and deceleration. Given that torque is the result of inertia and rate of altered speed, the system's forces will be affected by the rate of acceleration or deceleration. Any force calculation of this kind must take into account the actuator's or motor's inertia because it can significantly affect the torque needed. Control performance will also be impacted by the acceleration or deceleration profiles used. A motor needs linear acceleration in order to transition smoothly from one velocity to the next until the desired speed is reached. The rates of change, on the other hand, depend on both position and velocity when acceleration follows a non-linear, curved profile.

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The radius of the cylinder is approximately 2.19 m, and the cylinder is experiencing a deceleration of approximately 1.86 m/s². Since the cylinder is decelerating and the force applied is less than the friction force, it is not slipping.

From the given information:

Mass of the cylinder, m = 5 kg

Moment of inertia of the cylinder, I = 12 kg·m²

Diameter of the cylinder, D = 0.5 m

Force applied, F = 25 N

Coefficient of friction, μ = 0.7

Radius of the cylinder, r = ?

To determine the radius (r) of the cylinder, we can use the relationship between moment of inertia (I) and mass (m) for a solid cylinder:

I = (1/2) * m * r²

Given I = 12 kg·m² and m = 5 kg, we can solve for r:

12 = (1/2) * 5 * r²

r² = 12 / (1/2) * 5

r² = 12 / 2.5

r² = 4.8

r ≈ √4.8

r ≈ 2.19 m

So, the radius of the cylinder is approximately 2.19 m.

Now, let's determine the acceleration of the cylinder. The force applied is given as F = 25 N. The friction force can be calculated using the equation:

Friction force = μ * Normal force

Since the cylinder is being pulled by the string, the normal force is equal to the weight of the cylinder, which is given by:

Weight = mass * acceleration due to gravity

Weight = m * g

Assuming a standard acceleration due to gravity of 9.8 m/s²:

Weight = 5 kg * 9.8 m/s² = 49 N

Friction force = μ * Normal force = μ * Weight = 0.7 * 49 N = 34.3 N

Now, we can calculate the net force acting on the cylinder:

Net force = Force applied - Friction force

Net force = 25 N - 34.3 N

Net force = -9.3 N

Since the net force is negative, indicating that the force applied is less than the friction force, the cylinder will experience a deceleration rather than acceleration. The magnitude of the deceleration can be calculated using Newton's second law:

Net force = mass * acceleration

-9.3 N = 5 kg * acceleration

acceleration = -9.3 N / 5 kg

acceleration = -1.86 m/s²

The negative sign indicates that the deceleration is in the opposite direction to the force applied, which means the cylinder is moving in the direction opposite to the applied force.

Hence, the radius of the cylinder is approximately 2.19 m, and the cylinder is experiencing a deceleration of approximately 1.86 m/s². Since the cylinder is decelerating and the force applied is less than the friction force, it is not slipping.

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The density of the wood and the oil is 615 kg/m^3 and 690kg/m^3 .

(a) Finding the density of wood (\($\rho_{\text {wood }}$\))

Taking the density of water as \($\rho_{\text {water }}=1000 \mathrm{~kg} / \mathrm{m}^3$\)

Based on the principle of floatation:

- fraction of volume submerged in water = Ratio of density of wood to the density of water

-\($f_w=\frac{\rho_{\text {wood }}}{\rho_{\text {water }}}$\)

-\(0.615=\frac{\rho_{\text {wood }}}{1000 \mathrm{~kg} / \mathrm{m}^3}\)

- \($\rho_{\text {wood }}=615 \mathrm{~kg} / \mathrm{m}^3$\)

(b) Finding the density of oil ( \($\rho_{\text {oil }}$\) )

Similar to (a),

- fraction of volume submerged in oil = Ratio of density of wood to the density of oil

- \($f_o=\frac{\rho_{\text {wood }}}{\rho_{\text {oil }}}$\)

- \($0.892=\frac{615 \mathrm{~kg} / \mathrm{m}^3}{\rho_{\text {oil }}}$\)

- \($\rho_{\text {oil }} \approx 690 \mathrm{~kg} / \mathrm{m}^3$\)

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Answer:

9.6 minutes

Explanation:

We have that it takes Claire \(t=0.16h\) amount of time to get to school

\(t=0.16h\)

From the Question we are told that

Velocity\(v= 25 km/h.\)

Distance \(d=4km\)

Generally the equation for Time  is mathematically given as

\(v=\frac{d}{t}\\\\t=\frac{4}{25}\\\\t=0.16h\)

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The pattern formed by iron filings around magnets shows the magnetic field lines produced by the magnets.

Magnetic field lines are described as imaginary lines, which depict the strength and direction of the magnetic field.

The iron filings align themselves along the magnetic field lines, which helps to provide a visual representation of the field's direction and shape. The filings tend to concentrate near the poles of the magnets, where the magnetic field is stronger.

This pattern is important as it helps visualize the magnetic field and understand its characteristics, such as the shape, direction, and strength of the magnetic field produced by the magnets.

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If a football is kicked from the ground with a speed of 16.71 m/s at an angle of 49.21 degrees, then the vertical component of the initial velocity would be 12.65 m/s

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second.

As given in the problem A football is kicked from the ground with a speed of 16.71 m/s at an angle of 49.21 degrees

The horizontal component of the velocity is given by

Vx = Vcosθ

The vertical component of the velocity is given by

Vy = Vsinθ

As we have to find the vertical component of the velocity given that speed of 16.71 m/s at an angle of 49.21 degrees from the ground

Vy = 16.71 × sin49.21°

Vy = 12.65 m/s

Thus, the vertical component of the velocity would be 12.65 m/s

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The water weighs 900kg / (\(m^{2}\))

Force required to raise this layer is,

\(F_{t}\) = 900g(\(V_{t}\))

= 900(9.8) π(225 -\(y_{1}\) ^ 2) Δy

Each particle in the layer must travel a distance of approximately (15 + 5) -  \(y_{1}\)= 20 - \(y_{1}\)

The work \(w_{1}\) done to raise this layer to the top is approximately the product of the force \(F_{1}\) and the distance 20 - y

\(W_{1}\) ≈ \(F_{1}\)(20 - \(y_{1}\) )

≈ 900(9.8) π (225 - \(y_{1}\)^2)(20 - \(y_{1}\)) Δy

then solve,

and we get,

volume = π(225 - \(y_{1}\)^2)Δy

What is density ?

The substance's mass per unit of volume is known as its density (volumetric mass density or specific mass). Although the Latin letter D may also be used, the sign most frequently used for density is (the lower case Greek letter rho). The density of a pure substance is equal to its mass concentration in numbers. Density varies widely among materials and may be important in relation to packaging, purity, and buoyancy. The densest known elements under conditions of normal temperature and pressure are osmium and iridium. It is occasionally substituted by the dimensionless quantity "relative density" or "specific gravity," which is the ratio of the density of the material to that of a standard material, typically water, to make density comparisons across different systems of units easier.

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A 5 MHz signal will penetrate approximately twice as far as a 10 MHz signal when their initial intensity decreases by a factor of 100.

Assuming both signals travel through the same medium and encounter the same obstacles, a 5 MHz signal will penetrate approximately twice as far as a 10 MHz signal when their initial intensity decreases by a factor of 100.

The reason for this is that lower-frequency signals have longer wavelengths, which allow them to diffract more around obstacles and penetrate deeper into materials. However, as the signal's intensity decreases, its ability to penetrate obstacles and travel further decreases as well.

When the initial intensity of each signal decreases by a factor of 100, the received power of the 5 MHz signal will be 20 dB less than the received power of the 10 MHz signal. This means that the 5 MHz signal will have only 1% of the original power, while the 10 MHz signal will have 0.01% of the original power.

Thus, while the 5 MHz signal will penetrate further than the 10 MHz signal, both signals will experience significant attenuation and their range will be limited. The exact amount of penetration will depend on various factors such as the type of medium, the obstacles in the path of the signal, and the specific frequencies being used.

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A. The water will shoot out of the hole at a speed of 7.5 x 10⁻² m/s. B. The water will shoot out of the hole at a speed of 8.3895 m/s when the diameter of the hole is three times as large.

Part A: The volume of water entering the fountain per second is 7.5 x 10-2 m3. The diameter of the hole is 4.55 cm. The area of the hole is given by;

A=πr²

Where; r = d/2

Substituting the values of diameter and π into the equation, we get;

A = π x (4.55/2)²

A = π x 2.275²

A = 16.26 cm²

We convert the area to meters² so as to make the units of volume the same.

V= A x V_1

V= 16.26 cm² x (7.5 x 10⁻² m³/s) x (10⁻⁴ m²/cm²)V = 1.2195 x 10⁻⁴ m³/s

To find how fast the water will shoot out of the hole, we use the continuity equation;

A₁V₁ = A₂V₂

Where; A₁ and V₁ are the area and velocity of the water entering the hole respectively. A₂ and V₂ are the area and velocity of the water exiting the hole respectively.

Since water is incompressible, the volume of water entering is the same as that exiting.

A₁V₁ = A₂V₂

V₂ = A₁V₁/A₂

Where; A₁ = πr₁² = π(4.55/2)² = 16.26 cm²

V₁ = 7.5 x 10⁻² m³/s

A₂ = πr₂² = π(4.55/2)² = 16.26 cm² (assuming the hole is circular)

V₂ = (16.26 cm² x 7.5 x 10⁻² m³/s)/(16.26 cm²)

V₂ = 7.5 x 10⁻² m/s

Therefore, the speed is 7.5 x 10⁻² m/s.

Part B: If the diameter of the hole is three times as large, then the radius of the hole will also be three times as large. That is;

r₂ = 3r₁ = 3(4.55/2) cm = 6.825 cm

The area of the hole is given by;

A₂ = πr₂²

A₂ = π(6.825/100)² m²

A₂ = 1.464 x 10⁻⁴ m²

Substituting the values into the continuity equation;

V₂ = A₁V₁/A₂

V₂ = (16.26 cm² x 7.5 x 10⁻² m³/s)/(1.464 x 10⁻⁴ m²)

V₂ = 8.3895 m/s

Therefore, the speed is 8.3895 m/s when the diameter of the hole is three times as large.

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Answer:

3m/s is the answer.

Explanation:

f = c/λ

f = frequency

c = speed (m/s)

λ = wavelength

f = c/λ

1.5 = c/2

c = 3m/s

Answer:

8173.8 km

Explanation:

Fg=G(M*m/r^2)

r=sqrt(G*M*m/Fg)

G=6.6743*10^-11

M(earth)=5.972*10^24kg

M(object)=352kg

Fg=-2100N

r=sqrt((6.6743*10^-11)*(5.972*10^24kg)*(352)/-2100)

r=8173808m

r=8173.8km

According to Newton's calculations, gravity reduces to a fourth of what it was at the surface of the Earth if the distance from the planet's centre is doubled. At the Earth's surface, a satellite with a mass of 1,000 kg exerts a weight force of 9,800 N.

Satellites are pulled toward Earth by its gravity, even when they are hundreds of kilometres distant. The satellite doesn't fall back to Earth; instead, it travels into orbit above it due to gravity and the velocity it acquired during launch into space.

A satellite that is in a steady circular orbit around the Earth is always falling. It encounters a gravitational pull toward the centre of Earth as it orbits, which forces it to shift course and “fall” towards Earth.

Therefore, Since gravity is the only force acting on a satellite in circular orbit, the centripetal force and gravity must be equal: Fc = Fg.

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