A machine wheel spins at a rate of 500 revolutions per minute. if the wheel had a diameter of 80 centimeters, what is the angular speed of the wheel, in radians per second? round your answer to the nearest hundredth. ______ rad/sec

The algebraic expression for the given condition is 3x - 7 ≥ 20, where x represents the unknown number. This equation represents the difference of 3 times a number and 7 being greater than or equal to 20.

Let's represent the unknown number by x. The phrase "3 times a number" can be expressed as 3x. The word "difference" implies that we need to subtract something from this expression. In this case, we subtract 7. Finally, the phrase "is at least 20" means that the result should be greater than or equal to 20, so we use the inequality symbol "≥" to represent this condition.

Putting it all together, the algebraic expression for the given condition is 3x - 7 ≥ 20. This equation allows us to solve for the value of x that satisfies the condition, where the difference of 3 times the number and 7 is at least 20.

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Answer:

x>3

The answer is B

The side-angle-side (SAS) theorem, which states that two sides and an included angle of one triangle are congruent if they are comparable to two sides and an included angle of another triangle, is the first of these theorems.

If all three corresponding sides and all three corresponding angles are equal in size, two triangles are said to be congruent.

Slide, twist, flip, and turn these triangles to create an identical appearance.

They are in alignment with one another when moved.

The first such theorem is the side-angle-side (SAS) theorem, which states that two sides and an included angle of one triangle are congruent if they are equivalent to two sides and an included angle of another triangle.

Therefore, the side-angle-side (SAS) theorem, which states that two sides and an included angle of one triangle are congruent if they are comparable to two sides and an included angle of another triangle, is the first of these theorems.

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The McNemar's Test can be thought of as the chi-square type equivalent to the paired t-test.

The McNemar's Test is a non-parametric statistical method used to analyze the differences between paired or matched categorical data, such as repeated measurements on a single group. Like the paired t-test, which is used to compare continuous data, the McNemar's Test evaluates the changes in the proportions of success or failure between the paired observations.

This test is particularly useful when dealing with small sample sizes or when the assumptions of normality and homogeneity of variances required for the paired t-test are not met. By using the chi-square distribution, McNemar's Test provides a way to determine the significance of the differences between paired categorical data, while accounting for the dependency between the observations.

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An unnormalized relation refers to a table in a relational database that contains more than one row. This means that there are duplicate rows in the table, which violates the rules of normalization.

Normalization is a process in database design that aims to eliminate data redundancy and ensure data integrity. It involves breaking down a database into multiple tables and defining relationships between them. By doing so, we can efficiently store and retrieve data while minimizing inconsistencies.

In an unnormalized relation, duplicate rows can lead to various problems. For example, it can result in data inconsistencies, as updating one instance of a row may not reflect changes in other duplicate rows. Additionally, it can cause unnecessary storage and maintenance overhead.

To normalize an unnormalized relation, we need to identify the functional dependencies in the table and create separate tables for related data. This helps organize the data and reduces redundancy.

In summary, an unnormalized relation is a table in a relational database that has duplicate rows. It is important to normalize such relations to ensure data integrity and efficiency.

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Answer:

B

Step-by-step explanation:

i searched it up

The price of the watch before the discount is calculated to be £24.44.

As the total price of the watch and a pair of trainers is £53. 55 and the price of the trainer before the discount was £38, we first calculate the price of the trainers after the discount as follows;

discount on a pair of trainers = 15/100 × 38 =  £5.7

cost of trainers after discount =  £38 - 5.7 =  £32.3

Now the price of the watch after the discount can be calculated by subtraction as follows;

price of watch after discount = total price - price of trainers after discount

price of watch after discount =  £53. 55 - £32.3

price of watch after discount = £21.25

Now the price of the watch before the discount can be calculated as follows;

price of watch before discount = £21.25 × 15/100

price of watch before discount = £21.25 + £3.1875

price of watch before discount = £24.44

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Types of quadrilaterals are parallelograms, rectangles, squares, rhombi, trapezoids, kites, and isosceles trapezoid.

A polygon having four sides and four angles are called a quadrilateral. Quadrilaterals come in a wide variety of forms, each with its own set of qualities and attributes.

Some of the most typical varieties are listed below:

Parallelogram - A quadrilateral has opposing sides that are equally long and parallel.

Rectangle - A parallelogram with all angles at 90 degrees is referred to as a rectangle.

Square - A rectangle with equally long sides.

Rhombus - A parallelogram with equal-length sides is referred to as a rhombus.

Trapezoid - A quadrilateral with just one set of diagonally opposed sides is called a trapezoid.

Kite - A quadrilateral has two sets of adjacent sides that are of equal length or a kite.

Isosceles trapezoid - An isosceles trapezoid is one with equally long non-parallel sides.

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Answer:

3 minutes

Step-by-step explanation:

If Ms. Selwa can run 1/6 of a kilometer in a minute, she can run 3/6 of a kilometer in 3 minutes.

This is because 1/6 times 3 equals 3/6, which is the distance of the school from her home.

So, it will take Ms. Selwa 3 minutes to run to school.

Answer:

x = -7

Step-by-step explanation:

So we are asked to find what x is equal to in the equation:

\(\frac{x}{7}-4=-5\)

In other words, we are asked to solve for x.

\(\frac{x}{7}-4=-5\)

Add 4 to both sides of the equation.

\(\frac{x}{7}=-1\)

Multiply both sides by 7.

x = -7

So we have solve the equation for x and have found that x = -7.

I hope you find my answer and explanation to be helpful. Happy studying.

Answer:

Step one. Equate the two right hand sides to each other.

3x - 4 = 2x + 1

Step-by-step explanation:

Well one of the things you could do is graph the two equations. The intersection point is the solution to the system. We get 5,11 as the answer. I can hear you saying that's cheating, and it likely is, but it does get the answer.

The very first step without the graph is to equate each of the right hand sides to each other. That's because the left side are both ys and they have to be equal.

3x - 4 = 2x + 1                     Add 4 to both sides

3x - 4 + 4 = 2x + 1 + 4

3x = 2x + 5                         Subtract 2x from both sides

3x-2x = 2x-2x + 5              Combine

x = 5

y = 3x - 4

y = 3*5 - 4

y = 15 - 4

y = 11.

ANSWER:

STEP-BY-STEP EXPLANATION:

When x is equal to a constant, the graph will be a straight line parallel to the y axis, the straight line is located at the value of the constant, like this:

Answer:

a < 4

Step-by-step explanation:

7 + a < 11

Subtract 7 from each side

7+a-7 <11-7

a < 4

Answer: a=3

Step-by-step explanation:

Answer:

50 friends = 20:30

100 friends = 40:60

Step-by-step explanation:

Let candy lovers = cl

Let popcon lover = pl

Let total = t

1) Let's write in ratio form.

pl : cl

4  : 6

2) Add the ratios (4 + 6 = 10) and write it in fraction form multiplying the desired amount.

pl: \(\frac{4}{10} * 50\)

cl: \(\frac{6}{10}*50\)

3) Solve them.

pl: 20

cl: 30

3) Take the same steps to get the ratio for 100 friends.

pl: \(\frac{4}{10} * 100\)

cl: \(\frac{6}{10} * 100\)

-------------------------

pl: 40

cl: 60

Therefore the solution of this problem is a)critic value t = 2.8982 b)margin of error=  2.985146

In statistics, the standard deviation measures how widely distributed or how much a set of values might vary. In contrast to a high standard deviation, which indicates that values are widely dispersed, a low standard deviation indicates that values are typically close to the set's mean.

Here ,

where s is the sample's standard deviation

Finding the number of degrees of freedom is the first step in solving this problem. The sample size has been reduced by 1.

So

df = 18 - 1 = 17

99% confidence interval

We must now determine the value of T, which can be done by consulting the t table, which has 17 degrees of freedom (on the y-axis) and a confidence level of).

\(1 - \frac{1-0.99}{2} =0.995\)

So we have T = 2.8982.

The margin of error is:

M = T*s = 2.8982*1.03 = 2.985146

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a. Present value of $400 per year for 14 years at 14%: $2,702.83
b. Present value of $200 per year for 7 years at 7%: $1,155.54
c. Present value of $400 per year for 7 years at 0%: $2,800
d. Present value of $400 per year for 14 years at 14% (annuity due): $2,943.07
  Present value of $200 per year for 7 years at 7% (annuity due): $1,233.24
  Present value of $400 per year for 7 years at 0% (annuity due): $2,800

To find the present values of the ordinary annuities, we can use the formula for the present value of an annuity:

PV = PMT * [(1 - (1 + r)^(-n)) / r]
Where:
PV = Present value
PMT = Payment per period
r = Interest rate per period
n = Number of periods

a. $400 per year for 14 years at 14%:
PV = $400 * [(1 - (1 + 0.14)^(-14)) / 0.14]

≈ $2,702.83

b. $200 per year for 7 years at 7%:
PV = $200 * [(1 - (1 + 0.07)^(-7)) / 0.07]

≈ $1,155.54

c. $400 per year for 7 years at 0%:
Since the interest rate is 0%, the present value is simply the total amount of payments over the 7 years:
PV = $400 * 7

= $2,800

d. Reworking previous parts assuming they are annuities due:
For annuities due, we need to adjust the formula by multiplying it by (1 + r):

a. Present value of $400 per year for 14 years at 14%:
PV = $400 * [(1 - (1 + 0.14)^(-14)) / 0.14] * (1 + 0.14)

≈ $2,943.07

b. Present value of $200 per year for 7 years at 7%:
PV = $200 * [(1 - (1 + 0.07)^(-7)) / 0.07] * (1 + 0.07)

≈ $1,233.24

c. Present value of $400 per year for 7 years at 0%:
Since the interest rate is 0%, the present value remains the same:
PV = $400 * 7

= $2,800

In conclusion:
a. Present value of $400 per year for 14 years at 14%: $2,702.83
b. Present value of $200 per year for 7 years at 7%: $1,155.54
c. Present value of $400 per year for 7 years at 0%: $2,800
d. Present value of $400 per year for 14 years at 14% (annuity due): $2,943.07
  Present value of $200 per year for 7 years at 7% (annuity due): $1,233.24
  Present value of $400 per year for 7 years at 0% (annuity due): $2,800

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There are two points that satisfy the system of equations:

(0.79, 0.37)

(-3.79, -12.37)

The system of equations is:

y = 3x - 3

y = -x^2

To determine which point from a specified set satisfies the system of equations, we need to find the values of x and y that satisfy both equations simultaneously.

Substituting y = 3x - 3 into the second equation, we get:

3x - 3 = -x^2

Rearranging this equation, we get:

x^2 + 3x - 3 = 0

Using the quadratic formula, we can solve for x:

x = (-3 ± sqrt(3^2 - 41(-3))) / (2*1) = (-3 ± sqrt(21)) / 2

Therefore, there are two possible values of x that satisfy the system of equations:

x = (-3 + sqrt(21)) / 2 ≈ 0.79

x = (-3 - sqrt(21)) / 2 ≈ -3.79

To find the corresponding values of y, we can substitute these values of x into either equation. For example, if we use y = 3x - 3, we get:

y ≈ 0.37 (when x ≈ 0.79)

y ≈ -12.37 (when x ≈ -3.79)

Therefore, there are two points that satisfy the system of equations:

(0.79, 0.37)

(-3.79, -12.37)

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Answer:

1) \(16\frac{2}{3}\)% or 20%

Step-by-step explanation:

Given that:

An experiment which is carried out by flipping a coin and rolling six sided die.

The outcomes can be:

{H1, H2, H3, H5, H6, T1, T1, T2, T3, T5}

As per question statement:

Number of outcomes having tails and an odd number greater than one is 2 (i.e. T3 and T5)

Total number of outcomes here is 10.

Therefore, to find the percentage, we use the following formula:

\(\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\times 100\)

\(\Rightarrow \dfrac{2}{10}\times 100 = 20\%\)

As per question statement, the answer is 20%.

If we consider all the outcomes, i.e.

{H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}

Total number of outcomes = 12

The percentage will come out be :

\(\Rightarrow \dfrac{2}{12}\times 100 = 16\frac{2}{3}\%\)

Step-by-step explanation:

ans;

6x=34-4

6x=30

x=30/6

:x=5#

Answer:

see below

Step-by-step explanation:

v=πr² (h/3)

h=3v/πr²

original equation measures v using bottom circle area multiply the height.

the equation for the height reverses the multiplication using volume divided by the area, so the result is a linear measurement.

Answer:

- 9 < x < - 3

Step-by-step explanation:

- 53 < 9x + 1 < - 26 ( subtract 1 from each interval )

- 54 < 9x < - 27 ( divide each interval by 9 )

- 6 < x < - 3

The result of executing the given code is (B) an array of 6 values, ranging from 0 through 5, will be created and referenced by the variable x.

The code `int[] x = {0, 1, 2, 3, 4, 5};` is initializing an array of integers named `x`. The values inside the curly braces represent the elements of the array. In this case, the values are 0, 1, 2, 3, 4, and 5.

Option (A) is incorrect because the values in the array are not all initialized to 0. Instead, each value corresponds to its respective position in the array.

Option (C) is also incorrect because the variable `x` does not directly store the values 0 through 5. Instead, `x` is a reference to the array that contains those values.

Option (D) is not applicable as the code provided is syntactically correct and will not result in a compiler error.

Therefore, the correct answer is (B) - an array of 6 values, ranging from 0 through 5, will be created and referenced by the variable `x`.

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Answer:

y = -1/2x + 3

Step-by-step explanation:

Plug it in into the form y = mx + b (m is the slope)

​

Answer:

Two triangles are said to be congruent if they are exactly identical. We know that a triangle has three angles and three sides. So, two triangles have six angles and six sides. If we can prove the any corresponding three of them of both triangles equal under certain rules, the triangles are congruent to each other. These rules are called axioms.

The method you will use depends on the information you are given about the triangles.

--> SSS(Side-Side-Side): If you know that all three sides of a triangle are congruent to the corresponding sides of another triangle, then the two triangles are congruent.

--> SAS(Side-Angle-Side): If you know that two sides and the angle between those sides are equal to the another corresponding two sides and the angle between the two sides of another triangle, then you say that the triangles are congruent by SAS axiom.

--> ASA(Angle-Side-Angle): If you know that the two angles and the side between them are equal to the two corresponding angles and the side between those angles of another triangle are equal, you may say that the triangles are congruent by ASA axiom.
--> AAS(Angle-Angle-Side): This method is similar to the ASA axiom, but they are not same. In AAS axiom also you need to have two corresponding angles and a side of a triangle equal, but they should be in angle-angle-side order.

--> RHS(Right-Hypotenuse-Side) or HL(Hypotenuse-Leg): If hypotenuses and any two sides of two right triangles are equal, the triangles are said to be congruent by RHS axiom. You can only test this rule for the right triangles.

Answer:

So, there are four ways to figure out if two triangles are the same shape and size. One way is called SSS, which means all three sides of one triangle match up with the corresponding sides on the other triangle. Another way is called AAS, where two angles and one side of one triangle match two angles and one side of the other triangle. Then there's SAS, where two sides and the angle between them match up with the same parts on the other triangle. Finally, there's ASA, where two angles and a side in between them match up with the same parts on the other triangle.