The man should hold the umbrella at the angle of 80.54 to protect himself from rain.
As per the given problem,
Given :
vy (y in subscript) = 18 km/hr is the magnitude of the falling rain directed downwardvx (x in subscript) = 3 km/hr is the magnitude of the man’s speedHere, we have two vectors. The rain directed downwards and the speed of the man that let us say is moving either left or right. Either way, due to the walking, the rain will hit the man at an angle. If the man were to pull out his umbrella then he puts it at an angle to account for his speed. We can thus imagine a triangle with the horizontal side as our man's speed and the vertical side as the rain's speed. The hypotenuse is the magnitude of the resultant of these vectors. But we do not need to get the resultant at all.
For a right angle triangle, the angle we want can be simply determined by using the trigonometric tangent function. A tangent function is defined as :
tan∅ =opposite ÷ adjacent
where the adjacent side is the horizontal and the vertical side is the opposite. So by using these, we have our angle as:
∅ = tan-1 (18 km/hr ÷ 3 km/hr)
We simplify :
∅ = tan -1(6)
We will thus get :
∅ = 80.54°
This angle is with respect to the horizontal.
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Physicist ____ was found to have completely made up some of the data on which his astounding discoveries were made.
Answer:
Jan Hendrik Schön I believe
the wavelength of blue light is greater than red light and its energy is greater. True or False
Answer:
False
Explanation:
The wavelength of red light is greater than blue light. Its energy is less.
Both statements are false. Search for a graphic of the "electromagnetic spectrum." Many will note the wavelengths of the various regions (IR, UV, Visible, Microwave, etc. Observe the relationships. Red has less energy than blue. That sounds counterintuitive, based on artist's use of red to connote fire or some energetic situation. But the red in a fire obscures human vision to the blues and UV radiation from the same source. A welder uses a UV shield to blocjk these wavelengths, to avoid eye damage.
The physical meaning of 220 volts
Answer:
a particular level of electical potential from a power source
The classification of spiral galaxies is based on three properties:
Spiral galaxies are classified based on spiral arm tightness, bulge size, and amount of gas and dust present. This allows astronomers to categorize them into subtypes such as Sa, Sb, and Sc.
The classification of spiral galaxies is based on three properties:
1. Spiral arm tightness: This refers to how tightly wound the spiral arms are around the galaxy's center. Galaxies with more tightly wound arms are classified as "Sa," while those with more loosely wound arms are classified as "Sc."
2. Bulge size: The central bulge of a spiral galaxy can vary in size. Larger bulges are typically found in early-type spiral galaxies (such as Sa), while smaller bulges are found in late-type spiral galaxies (like Sc).
3. Amount of gas and dust: The presence and distribution of gas and dust within a spiral galaxy also play a role in its classification. Early-type spiral galaxies generally have less gas and dust compared to late-type spiral galaxies.
By considering these three properties, astronomers can classify spiral galaxies into various subtypes (such as Sa, Sb, and Sc) within the broader spiral galaxy category.
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Which one of the following is not a balanced equation
Answer:
B
Explanation:
just did the test
What is the condition for the machine to be perfect?
Which type of microscope achieves the greatest resolution and highest magnification?
Electron microscope achieves the greatest resolution and highest magnification.
Instead of using light to see the specimens, electron microscopes employ a stream of accelerated electrons. Compared to light microscopes, electrons are able to obtain a significantly greater resolution due to their shorter wavelength.
Magnifications of up to several million times can be achieved using electron microscopes, significantly above those of conventional light microscopes. Transmission electron microscopes (TEM) and scanning electron microscopes (SEM) are the two primary categories of electron microscopes.
SEMs give precise surface imaging, whereas TEMs are utilized to examine the inside structure of objects. The use of electron microscopes is essential in many scientific fields because they allow for the most in-depth examination of the microscopic details of cells, tissues, nanoparticles, and other tiny structures.
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A 20 ohm and 60 ohm light bulb are put in series together which one would be brighter?
Answer:
The 60 Ohm bulb would be brighter than the 20 Ohm bulb.
Explanation:
Hi there!
Ohm's Law: \(V=IR\) where V is voltage, I is current and R is resistance
Power equation: \(P=VR\)
The greater the power of a bulb, the brighter it is.
The bulbs are connected in series, meaning the the current travelling through each will be the same. Plug Ohm's law into the power equation so we just have I and R:
\(P=I^2R\)
Because the current stays the same, the bulb with greater resistance will have greater power, hence being brighter. Therefore, the 60 Ohm bulb would be brighter than the 20 Ohm bulb.
I hope this helps!
Answer:
The 60 Ohm bulb would be brighter than the 20 Ohm bulb.
Explanation:
Hi there!
Ohm's Law: V=IRV=IR where V is voltage, I is current and R is resistance
Power equation: P=VRP=VR
The greater the power of a bulb, the brighter it is.
The bulbs are connected in series, meaning the the current travelling through each will be the same. Plug Ohm's law into the power equation so we just have I and R:
P=2RP=I
2
R
Because the current stays the same, the bulb with greater resistance will have greater power, hence being brighter. Therefore, the 60 Ohm bulb would be brighter than the 20 Ohm bulb.
I hope this helps!
The Big Bang theory is closely linked to Hubble's discovery that the universe is expanding, which seems to imply that there was a time in the past when the expansion first began. Nevertheless, the Big Bang theory did not gain widespread acceptance among scientists until the 1960s. Why wasn't expansion alone enough to convince scientists that the Big Bang really happened
Answer:
Although expansion seems to imply a Big Bang, no other specific predictions of the Big Bang theory were tested and confirmed until the 1960s.
Explanation:
Answer:
Today, the consensus among scientists, astronomers and cosmologists is that the Universe as we know it was created in a massive explosion that not only created the majority of matter, but the physical laws that govern our ever-expanding cosmos. This is known as The Big Bang Theory. For almost a century, the term has been bandied about by scholars and non-scholars alike. This should come as no surprise, seeing as how it is the most accepted theory of our origins.
;)
An airplane starts from rest and accelerates at a constant 3.00 m/s2 for 30.0 s before leaving the ground. a. How far did it move
The airplane that starts from rest and accelerates at 1 constant 3 m/s2 for 30 s before leaving the ground moved by the distance of 1350m.
Acceleration is given as 3.00 m/s2
Time is 30 sec.
The formula we can use in this case is:
s = ut + 0.5 at^2
v = at + u
where,
s is distance travelled
u is initial velocity = 0 since at rest
t is time travelled
a is acceleration
v is the final velocity when it took off
a. s = 0 + 0.5 * 3 * 30^2
s = 1350 m
The distance moved by the airplane is 1350 m.
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a fixed system of charges exerts a force of magnitude
A fixed system of charges exerts a force of magnitude that is proportional to the product of the charges' magnitudes and inversely proportional to the square of the distance between them. This force is known as the Coulomb force.
The force that a fixed system of charges exerts on another fixed system of charges is known as the Coulomb force, which is described by Coulomb's law, which is expressed as F = kq₁q₂/r², where F is the force, k is Coulomb's constant (9.0 x 10⁹ Nm²/C²), q₁ and q₂ are the two point charges, and r is the distance between them. This force is inversely proportional to the square of the distance between the charges, and it is proportional to the product of the charges' magnitudes.
Two point charges exert a force of 9.0 x 10⁹ N on one another. The charges have opposite signs, which indicates that they are of opposite polarity. The force between two point charges is described by Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.
Coulomb's law states that two charged objects will experience an electrical force between them proportional to the quantity of electric charge on each object and inversely proportional to the distance between them. The forces that two point charges exert on one another are proportional to the product of their magnitudes, and the magnitude of this force is also proportional to the inverse square of the distance between them.
Coulomb's law can be used to explain the behavior of electrostatic forces in situations where there are two or more charges present. The force on a charged particle due to other charged particles is simply the vector sum of the forces exerted by each individual charge on that particle.
In conclusion, a fixed system of charges exerts a force of magnitude that is proportional to the product of the charges' magnitudes and inversely proportional to the square of the distance between them. This force is known as the Coulomb force, and it is described by Coulomb's law. Coulomb's law is used to describe the behavior of electrostatic forces in situations where there are two or more charges present.
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Predict how the force between the sheets would be different if this experiment were done with twice as much charge on each of the plates. Justify your prediction.
What’s the name of the muscle indicated on the image below?
1.Tricep
2.Oblique
3.Quadricep
4.Trapezius
Answer:
Oblique
Explanation:
I think that's the answer I was told this but forgot if this is the right answer if not then sorry
this is a 3 part question6) (a) Your heart beats with a frequency of 1.45 Hz. How many beats occur in a minute? (b) If the frequency of your heartbeat increases, will the number of beats in a minute increase, decrease, or stay the same? (c) How many beats occur in a minute if the frequency increases to 1.55 Hz?
Given,
The initial frequency of the heartbeat, f₁=1.45 Hz
The increased heartbeat, f₂=1.55 Hz
The frequency of the heartbeat can be described as the number of occurence of the heartbeat per second. That is every second, the heart beats 1.45 times.
(a)
Thus for a minute, the number of the heartbeats is,
\(\begin{gathered} N_1=f_1\times60 \\ =1.45\times60=87 \end{gathered}\)Thus 87 beats occur for a minute.
(b)The increase in the frequency of the heartbeat implies the increase in the number of the heartbeat for every second. And hence the beats in a minute increase when the frequency of the heartbeat increases.
(c)
The number of the beats per minute after the increase of the frequency is,
\(\begin{gathered} N_2=f_2\times60 \\ =1.55\times60 \\ =93 \end{gathered}\)Thus after the increase in the frequency, 93 beats occur in a minute.
What is the relationship between frictional force and the normal force
Answer: Frictional force is when it happens on purpose and normal force is when it happens normal and you are not trying to make it happen on purpose.
Explanation: friction happens on purpose and sometimes you can't control friction but friction is an important thing.
in a laundromat, during the spin-dry cycle of a washer, the rotating tub goes from rest to its maximum angular speed of 2.2 rev/s in 6.8 s. you lift the lid of the washer and notice that the tub decelerates and comes to a stop in 14.5 s. assuming that the tub rotates with constant angular acceleration while it is starting and stopping, determine the total number of revolutions undergone by the tub during this entire time interval.
The total number of revolutions undergone by the tub during the entire time interval is 23.1 revolutions.
To determine the total number of revolutions, we need to calculate the angular displacement of the tub during the starting phase, the stopping phase, and the constant speed phase.
During the starting phase, the tub goes from rest to its maximum angular speed of 2.2 rev/s. We can use the equation of motion for angular acceleration:
ω = ω₀ + αt
Given that ω₀ = 0 (initial angular speed) and ω = 2.2 rev/s (final angular speed), and t = 6.8 s (time), we can solve for α (angular acceleration). Using this angular acceleration, we can calculate the angular displacement (θ) during the starting phase.
During the stopping phase, the tub decelerates and comes to a stop. The angular displacement during this phase can be calculated using the same equation of motion for angular acceleration, with ω = 0 (final angular speed), ω₀ = 2.2 rev/s (initial angular speed), and t = 14.5 s (time).
Finally, during the constant speed phase, the angular displacement is given by ωt, where ω is the constant angular speed of 2.2 rev/s and t is the time interval between the end of the starting phase and the beginning of the stopping phase.
Adding up the angular displacements from each phase will give us the total angular displacement, which can be converted to the total number of revolutions by dividing it by 2π.
Calculating these values will result in a total of 23.1 revolutions undergone by the tub during the entire time interval.
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photometer with a linear response to radiation gave a potential reading of 678.1 mv with a blank in the light path and 160.3 mv when the blank was replaced by an absorbing solution. calculate:
When a blank was in the light path, a photometer with a linear response to radiation read 678.1 mV and 160.3 mV, respectively, when the blank was replaced with an absorbing solution, or 23.64%.
Using the given data, we can use the following formula to get the percentage of transmitted radiation: % Transmittance = (I / I₀) × 100
When ligand-gated channels open, the membrane potential of a neuron can swiftly change. There are two alternative modifications that might take place: depolarization, which is a movement towards a more positive potential, or hyperpolarization, which is a shift towards a more negative potential. The direction of the change depends on the ion that the channel allows to pass through.
where I0 denotes the radiation's starting intensity (when the blank is used), and I denotes the radiation's intensity after passing through the absorbing solution.
Given the information:
I = 160.3 mV (with the absorbing solution) and I₀ = 678.1 mV (with the blank).
Now, we can determine the transmittance percentage:
(160.3 mV/678.1 mV) / 100 x 23.64% = % Transmittance
This indicates that the absorbing solution allows for the transmission of around 23.64% of the radiation.
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The Complete question is
photometer with a linear response to radiation gave a potential reading of 678.1 mv with a blank in the light path and 160.3 mv when the blank was replaced by an absorbing solution. calculate the transmission of absorbing solution?
Please help!! Physics homework
Answer:
Give up.
Explanation:
Physics is horrible.
And that's the cold hard truth. :(
A stone is thrown vertically upwards with an intinal velocity of 20 m/sec . find the maximum height it reaches and the time by it reachthe height (g=10 m/sec).
Answer:
Maximum height is20m and time taken will be 2second
Explanation:
vi=20m/s
vf=0m/s
g=10m/s^2
Using third equation for objects falling freely
2gh=(vf)^2-(vi)^2
Putting values
2(10m/s^2)h=(0m/s)^2-(20m/s)^2
20h=400m
h=20m
Now we have to find the time
Using first equation of motion for objects falling down freely
vf=vi+at
substituting the equation
(vf-vi)/g=t
(0-20)/10=t
t=2second
A dropped rock takes 5.2 sec to fall from a cliff. How tall is the cliff? (use kinematics,
assume no air resistance)
Answer:
below
Explanation:
d = 1/2 a t^2
= 1/2 (9.81)(5.2)^2 = 132.6 m =~ 133 m
A company wishes to produce two types of souvenirs: Type A and Type B. Each Type A souvenir will result in a profit of $0.80, and each Type B souvenir will result in a profit of $1.60. To manufacture a Type A souvenir requires 2 minutes on Machine I and 1 minute on Machine II. A Type B souvenir requires 1 minute on Machine 1 and 3 minutes on Machine II. There are 2 hours available on Machine I and 5 hours available on Machine 11. (a) For a meaningful solution, the time available on Machine II must lie between 90 X and x min. (Enter your answers from smallest to largest.) (b) If the time available on Machine II is changed from 300 min to (300 + k) min, with no change in the maximum (150 - A) capacity for Machine 1, then Ace Novelty's profit is maximized by producing Type A souvenirs 540 5 and 2(223+ *). 3 Type B souvenirs, where -225 1x ** $ 150 X X (c) Find the shadow price for Resource 2 (associated with constraint 2). (Round your answer to the nearest cent.)
The time available on Machine II must lie between 1 minute and 3 minutes. The shadow price for Resource 2 (associated with constraint 2) is $3 per minute.
(a) To determine the range of available time on Machine II, we need to consider the constraints provided. The time available on Machine II must be between the time required for Type A souvenirs and the time required for Type B souvenirs.
Time required for Type A souvenir on Machine II: 1 minute
Time required for Type B souvenir on Machine II: 3 minutes
Therefore, the time available on Machine II must lie between 1 minute and 3 minutes.
The meaningful solution for the available time on Machine II is 1 min ≤ Machine II ≤ 3 min.
(b) To maximize the profit, we need to determine the optimal production quantities for Type A and Type B souvenirs given a change in the available time on Machine II.
Let's assume the change in available time on Machine II is represented by k.
To maximize the profit, we need to find the production quantities that maximize the total profit. Let's denote the production quantity for Type A souvenirs as x and the production quantity for Type B souvenirs as y.
The objective function for the profit can be expressed as:
Profit = 0.80x + 1.60y
Subject to the following constraints:
2x + y ≤ 120 (Machine I constraint)
x + 3y ≤ (300 + k) (Machine II constraint)
Using linear programming techniques, the optimal solution will depend on the value of k.
The statement "Ace Novelty's profit is maximized by producing Type A souvenirs 540 5 and 2(223+ *). 3 Type B souvenirs, where -225 1x ** $ 150 X X" seems to be incomplete and unclear. The specific production quantities and profit cannot be determined without knowing the value of k.
(c) To find the shadow price for Resource 2 (associated with constraint 2), we can perform sensitivity analysis.
The shadow price represents the change in the objective function's value per unit increase in the availability of Resource 2 (Machine II in this case). We can determine it by evaluating the sensitivity of the objective function to changes in the constraint.
Since the constraint is x + 3y ≤ (300 + k), the shadow price associated with Resource 2 is the coefficient of the Machine II term, which is 3.
Therefore, the shadow price for Resource 2 (associated with constraint 2) is $3 per minute.
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Given the graph below, the resistance of the wire in Ohms is:
a 0.25
b 4
c 3.75
d 0
Answer:
C . 3.75 Ohms
Explanation:
V = IR
R = V / I
From the graph, you pick a value for potential difference and find its corresponding current.
The resistance of the wire in Ohms is 3.75 Ω, therefore the correct answer is option C
What is resistance?Resistance is the obstruction of electrons in an electrically conducting material.
The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.
V=IR
where V is the voltage
I is the current
From the voltage-current graph, one can know the resistance by calculating the slope of the graph
As shown in the graph the variation of the voltage with the current
Y axis represents the voltage and the X axis represents the current
slope = variation in the Y coordinate /variation in the X coordinate
resistance = variation in the voltage /variation in the current
= (30 - 0 )/ (8-0 )
= 3.75 Ω
Thus, by observation and calculation from the graph, the resistance of the wire comes out to be 3.75 Ω
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One billiard ball strikes another billiard ball, and they move away from each other
at a 90° angle. The momentums involved include (blank) of the velocity before and after the collision.
(A) only the direction
(C) the magnitude and direction
(B) only the magnitude
(D) the square of the magnitude
Answer:
C) The magnitude and direction
Explanation:
Velocity is a vector quantity, meaning that it has both magnitude and direction.
For the momentum, we look at both the direction of the ball (negative, positive) and the magnitude of the velocity (5 m/s, 10 m/s) when figuring out what to use for "v" in p = mv.
The peak wavelength for the blackbody curve a star is in the UV range assuming the radiation from the star can reach earth would you be able to see it yes or no
Answer:
No
Explanation:
We would not be able to see the star because its radiation is in the UV range. For the star to be visible, it has to be in the visible spectrum of light for me to be able to see it with my eyes.
A- Lunar Eclipse
B- Neap Tide
C- Spring tide
D-Solar tide
D Solar tide
Explanation:
Because d is closer to the sun
Many smoke detectors use americium-241to detect very small particulates in the air. This is done by using a stream of radioactive particles that can be stopped by the small smoke particulate. Which type of radiation is MOST LIKELY used in a smoke detector, as it can be stopped by something this small?
a
neutrons
b
beta particles
c
alpha particles
d
gamma radiation
Answer: C.) Alpha Particles
Explanation: Just took it <3
You are on a skateboard not moving when your friend throws you a basketball and you catch it. The 0.50kg basketball was going 5 m/s when you catch it. You weigh 55kg with the skateboard. After you catch the basketball you, the basketball, and the skateboard are moving.
a. What is your mass with the basketball and skateboard?
b. What is your new velocity after you catch the basketball?
Answer:
a. Your mass with the basketball is 55.5 kg
b. Your new velocity is 0.045 m/s
Explanation:
We first add your weight and the basketballs weight to get 55.5 kg.
Then to find b. we use the equation: v final = (m1 * v1) / (m1 +m2)
So m1 is the basketball which is 0.5 kg and v1 is 5 m/s. So the top half is (0.5 * 5)
The bottom half is just our weights added together.
Answer:
a) 55.5 kg
b) .045 m/s
Explanation:
Using conservation of momentum, we can set the initial momentum of the skateboard-person-basketball system equal to the final momentum of the skateboard-person-basketball system.
m1 = skateboard + person = 55 kg
m2 = basketball = .50 kg
v1_i = 0 m/s
v2_i = 5 m/s
Solve for v_f (same as v1_f or v2_f since the system is moving together -- assuming perfectly inelastic collision).
m1v1_i + m2v2_i = m1v1_f + m2v2_f
m1v1_i + m2v2_i = v_f (m1 + m2)
Substitute known values into the equation.
(55)(0) + (.5)(5) = v_f (55 + .5)
2.5 = v_f (55.5)
v_f = .045 m/s
Your new velocity after catching the basketball is .045 m/s.
if the length of the centrifuge arm is 15.0 m m , at what speed is the rider moving when she experiences 10 g's?
The rider is moving at a speed of 12.2 meters per second when she experiences 10 g's.
The speed at which a rider experiences 10 g's (10 times the acceleration due to gravity) on a centrifuge can be calculated using the formula:
speed = (g * r)
Where g is the acceleration due to gravity (9.8 m/s^2) and r is the radius of the centrifuge arm (in this case, 15.0 m).
Plugging in the numbers, we get:
speed = (9.8 * 15.0) = (146) = 12.2 m/s
It's important to note that high g-forces can have serious health effects, and centrifuges are often used to simulate conditions experienced by pilots, astronauts, and other people who are subjected to high g-forces.
The g-forces experienced on a centrifuge can be used to determine the limits of human tolerance and to develop measures to protect people from the harmful effects of high g-forces.
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The form of energy stored in a stretched spring would be elastic kinetic energy intermolecular binding energy a mixture of elastic and mechanical transformational energy elastic potential energy The result of simultaneous application of two forces, facing away from each other on a spring, may be some shear in the spring some elongation in the spring some contraction in the spring some bending in the spring
The form of energy stored in a stretched spring is elastic potential energy. When a spring is stretched or compressed, it possesses potential energy due to the deformation of its structure.
This potential energy is called elastic potential energy because it is associated with the elasticity of the spring.
As the spring is stretched, work is done to overcome the forces within the spring that resist the change in its length. This work is converted into potential energy, which is stored in the spring. The amount of potential energy stored in the spring is directly proportional to the amount by which it is stretched or compressed.
When two forces are simultaneously applied to a spring in opposite directions, it may result in elongation or contraction of the spring, depending on the magnitude and direction of the forces. If the applied forces are strong enough to overcome the spring's elasticity, the spring will undergo deformation and exhibit elongation or contraction. This deformation is a manifestation of the stored elastic potential energy being converted into mechanical energy.
Shear, bending, and intermolecular binding energy are not directly related to the stretching of a spring.
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When charging a secondary cell, energy is stored within a dielectric material using an electric field. True or False
It is a false statement that; "when charging a secondary cell, energy is stored within a dielectric material using an electric field"
What is a secondary cell?The term secondary cell refers to a cell that can be recharged when it is used up. A typical example of a secondary cell is a lithium ion battery.
We know that most of the secondary cell are charged using a chemical that is inside the battery. As such, it is a false statement that; "when charging a secondary cell, energy is stored within a dielectric material using an electric field"
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