a negative charge of 2 c and a positive charge of 3 c are separated by a distance of 40m.what is theforce between the two charges?

Explanation:

Answer:

Electricity is the presence and flow of electric charge. Using electricity we can transfer energy in ways that allow us to do simple chores . it's best - known form is the flow of electrons through conductor such as copper wires. The world "electricity " is sometimes used to mean "electrical energy "

Explanation:

hope it is helpful to you ☆

\(kavya\)

Answer:

v_f = -7.5 m / s

Explanation:

Let's analyze this exercise a little, two forces that act on a body for different time intervals are indicated, each force creates an impulse and since this is a vector quantity we must add in the form of vectors. The net momentum is

we assume that the direction to the right is positive

             I = I₁ + I₂

             I = F₁ Δt₁ - F₂ Δt₂

             I = 3  1.5 - 4  3

             I = -7.5   N s

now let's use the relationship between momentum and momentum, suppose the object starts from rest (vo = 0)

             I = Δp

             I = m (v_f - v₀)

             v_f = I / m

              v_f = -7.5 / m

to finish the calculation we must assume a mass m = 1 kg

              v_f = -7.5 m / s

the negative sign in the body is moving to the left

Answer:

BMI = 19.14 [kg/m^2]; Normal or Healthy

Explanation:

Body mass index (BMI) is a person’s weight in kilograms divided by the square of height in meters.

BMI = mass/(height^2)

BMI = 49 / (1.6^2)

BMI = 19.14 [kg/m^2]

BMI                                   Weight Status

Below 18.5                    Underweight

18.5 – 24.9                    Normal or Healthy Weight

25.0 – 29.9                    Overweight

30.0 and Above            Obese

BMI is within the range of Normal or Healthy Weight

Answer:

\(104\; {\rm g}\), assuming that the meter stick is uniform with the center of mass precisely at the \(50\; {\rm cm}\) mark.

Explanation:

Refer to the diagram attached. The meter stick could be considered as a lever. The string at the \(30\; {\rm cm}\) mark would then act as the fulcrum of this lever.

The \(m_{A} = 20\; {\rm g}\) mass at the \(80\; {\rm cm}\) mark is at a distance of \(r_{A} = 50\; {\rm cm}\) to the right of the fulcrum at \(30\; {\rm cm}\).

The weight of the \(80\; {\rm g}\) meter stick acts like a weight of \(m_{B} = 80\; {\rm g}\) attached to the center of mass of this meter stick. Under the assumptions, this center of mass of this meter stick would be at the \(50\; {\rm cm}\) mark, which is \(r_{B} = 20\; {\rm cm}\) to the right of the fulcrum at \(30\; {\rm cm}\).

Let \(m_{C}\) be the mass attached to the meter stick at the \(5\; {\rm cm}\) mark. This mass would be at a distance of \(r_{C} = 25\; {\rm cm}\) to the left of the fulcrum at \(30\; {\rm cm}\).

At equilibrium:

\(\begin{aligned} & m_{C}\, r_{C} && (\text{mass on the left of fulcrum})\\ &= m_{A}\, r_{A} + m_{B} \, r_{B} && (\text{mass on the right of fulcrum})\end{aligned}\).

Solve for \(m_{C}\), the unknown mass attached to the meter stick at the \(5\; {\rm cm}\) mark:

\(\begin{aligned}m_{C} &= \frac{m_{A}\, r_{A} + m_{B}\, r_{B}}{r_{C}} \\ &= \frac{20\; {\rm g} \times 50\; {\rm cm} + 80\; {\rm g} \times 20\; {\rm cm}}{25\; {\rm cm}} \\ &= 104\; {\rm g}\end{aligned}\).

Answer:

Ions are formed by the addition of electrons to, or the removal of electrons from, neutral atoms or molecules or other ions; by a combination of ions with other particles; or by rupture of a covalent bond between two atoms in such a way that both of the electrons of the bond are left in association with one of the formerly bonded atoms.

Explanation:

Answer:

Ion, any atom or group of atoms that bears one or more positive or negative electrical charges. Positively charged ions are called cations; negatively charged ions, anions. Ions are formed by the addition of electrons to, or the removal of electrons from, neutral atoms or molecules or other ions; by combination of ions with other particles; or by rupture of a covalent bond between two atoms in such a way that both of the electrons of the bond are left in association with one of the formerly bonded atoms. Examples of these processes include the reaction of a sodium atom with a chlorine atom to form a sodium cation and a chloride anion; the addition of a hydrogen cation to an ammonia molecule to form an ammonium cation; and the dissociation of a water molecule to form a hydrogen cation and a hydroxide anion.

Explanation:hope dis helps u

Answer:

The slit width a, must be equal to the wavelength λ

That is, every point on one side of the slit must have a corresponding point that is 180 degrees out of phase on the other side of the slit so the corresponding point on the screen receives no light,

This condition is also known as the Rayleigh criterion for the first dark fringe. It gives the angle at which the first dark fringe will appear in the diffraction pattern for a given wavelength of light and slit width.

When light waves pass through a single slit of width w, they diffract and create a diffraction pattern on a screen placed behind the slit. The pattern consists of a central bright fringe flanked by a series of alternating bright and dark fringes. The condition for the first dark fringe can be determined using the following formula:

sin θ = λ/w

where θ is the angle between the line normal to the slit and the direction of the dark fringe, λ is the wavelength of the light, and w is the width of the slit.

For the first dark fringe, the angle θ is equal to the smallest angle for which the path difference between the waves from the top and bottom edges of the slit is λ/2. This means that the condition for the first dark fringe is:

sin θ = λ/2w

For more question on Rayleigh criterion click on

https://brainly.com/question/13090441

#SPJ11

Answer:

The answer iis true

Explanation:

It is much easier to carry your backpack when it is empty rather than when it's full of textbooks (or soaked from the rain).

Answer:

sound waves

Explanation:

jejehwherrbjwhsbwwbdbehej

Answer:

red supergiants can

Answer:

lighter ones will go faster

Explanation:

assuming you throw both bolwing ball with 10N of force. one is 3kg and the other is 5kg.

by using the equation: F = ma

a = F/m

a = 10/5 = 2m/s^2

a = 10/3 = 3.33333 m/s^2

Answer\(:0.178\ m/s^2\)

Explanation:

Given

Amirul starts from rest(u=0) to reach Boon chun house which is 80\ m away from School

acceleration of Amirul is given by

\(s=ut+\frac{1}{2}at^2\)

Where

s=displacement

u=intial velocity

a=acceleration

t=time

here \(t=30\ s\)

Substituting values we get

\(80=0+\frac{1}{2}\times a\times (30)^2\)

\(a=\frac{2\times 80}{900}\)

\(a=\frac{160}{900}=0.178\ m/s^2\)

The aggregate bulk dry specific gravity, the aggregate apparent specific gravity, the moisture content of stockpile aggregate and absorption are respectively,

A. 2.7

B. 2.72

C. 1.6%

D. 0.21%

A) The formula for the aggregate bulk dry specific gravity is:

Aggregate bulk dry specific gravity = Mass of oven dried aggregate /( Mass of saturated surface dry aggregates - Submerged mass of aggregate)

Placing the values from the data we have,

Aggregate bulk dry specific gravity = 5216/ (5227 - 3295) = 2.7

B) Formula for aggregate apparent specific gravity is

Mass of oven dried aggregate/ ( Mass of oven dried aggregate - Submerged mass of aggregate) = 5216/ (5216 - 3295) = 2.7

C) The moisture content of the stockpile aggregate is

m = (weight of moist aggregate - mass of oven dried aggregate) / (mass of oven dried aggregate* 100%)

m = (5298 - 5216)/ (5216* 100%) = 1.6 %

D) Absorption is calculated as A = (5227 - 5216) / (5216) * 100% = 0.21 %

To know more about aggregates:

https://brainly.com/question/16380585

#SPJ4

The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.

d (distance) from A to B is = √2gh

In this case given are, g = 9.8 m/s² and h = 100m,

so here d = √(2⋅9.8⋅100) = 44.3m.

Final velocity ,v = √2gh

Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,

g = 9.8 m/s² ,h = 100m,

v = √(2⋅9.8⋅100)

= 44.3 m/s (final velocity)

Learn more about the energy here

https://brainly.com/question/32623120

#SPJ1

Explanation:

R = A + B. Vectors in the opposite direction are subtracted from each other to obtain the resultant vector. Here the vector B is opposite in direction to the vector A, and R is the resultant vector.

Answer:

F = 500 N

Explanation:

Given that,

Mass of an object, m = 50 kg

Acceleration of the object, a = 10 m/s²

We need to find the force exerted on the object. The force exerted on it will be given by :

F = ma

Substitute all the values, we get :

F = 50 kg × 10 m/s²

F = 500 N

So, the magnitude of the force exerted on the object is 500 N.

The answer is B, the induced current in loop 2 will be in the opposite direction as I1. This is because as the current in loop 1 increases, it will create a changing magnetic field that passes through loop 2. According to Faraday's law, this changing magnetic field will induce an electric current in loop 2 that opposes the change in magnetic field. This means that the induced current in loop 2 will flow in the opposite direction to the current in loop 1.
Your answer: B. The opposite direction as I1

When the current I1 in loop 1 is increasing, it generates a changing magnetic field. According to Faraday's law of electromagnetic induction, this changing magnetic field induces an electromotive force (EMF) in loop 2. The induced current in loop 2 will flow in such a direction that it opposes the change in the magnetic field due to loop 1. This is in accordance with Lenz's law. Since the magnetic field is caused by the increasing current in loop 1, the induced current in loop 2 will flow in the opposite direction to oppose this change, which is answer B.

Learn more about :

Faraday's law : brainly.com/question/1640558

#SPJ11

Answer:

please find attached pdf

Explanation:

To launch a 100 kg human so that he leaves a cannon moving at a speed of 4 m/s, you need a spring with an appropriate spring constant. This spring will be compressed 2. 0 m from its natural length to launch the person.400N/m spring constant is needed.

The spring constant, k, is a proportional constant. It gauges how firm the spring is. When a spring is compressed or extended to a length that differs by an amount x from its equilibrium length, it produces a force F = -kx that pushes it back towards its equilibrium position.

To know more about spring constant visit:

https://brainly.com/question/20388857

#SPJ4

Answer:

C

Explanation:

I took the test

The energy transferred to your eardrum while listening to the sound for 1.0 min is approximately 3.15 × \(10^{-2}\) J.

To calculate the energy transferred to the eardrum, we need to first determine the power of the sound wave using the given intensity. Power is defined as the rate at which energy is transferred, and it is given by the equation Power = Intensity × Area. In this case, the area is the surface area of the eardrum, which can be calculated using its diameter.

The surface area of a circle is given by the formula A = \(\pi r^2\), where r is the radius. Since the diameter of the eardrum is given as 6.5 mm, we can convert it to meters by dividing by 1000 and then divide by 2 to obtain the radius.

Once we have the surface area, we can calculate the power by multiplying the intensity by the area. The power of the sound wave is given in watts (W), which represents the amount of energy transferred per unit time.

Finally, to find the total energy transferred over a given time, we can multiply the power by the duration. In this case, the duration is given as 1.0 min, which is equivalent to 60 seconds.

By multiplying the power of the sound wave by the duration, we obtain the total energy transferred to the eardrum while listening to the sound for 1.0 min.

The energy transferred to the eardrum is approximately 3.15 × \(10^{-2}\) J.

Learn more about Sound

brainly.com/question/30045405

#SPJ11

the frequency bandwidth in hz = 70,00,00,000 hz

1GHz = 1000MHz

Bandwidth = 1000mhz - 300mhz

Bandwidth = 700mhz

The frequency in hertz can be converted to hertz by multiplying by 1,000,000.

= 700 × 1000000

= 70,00,00,000 hz

Bandwidth of a channel is referred to as the range of frequencies available for transmission of data through that channel. It is the difference of maximum and minimum frequency contained in the composite signals.

To learn more about hertz, refer

https://brainly.in/question/4367373

#SPJ4

The difference in tension in terms of m and g is given by T_b - T_t = 2mg

To find the difference in tension T_b - T_t, we will first analyze the forces acting on the ball at the top and bottom of the circle and then compare the magnitudes.
1. At the top of the circle:
- The tension force T_t is acting downward.
- The gravitational force mg is also acting downward.
The net force at the top is the sum of these forces:
F_t = T_t + mg
2. At the bottom of the circle:
- The tension force T_b is acting upward.
- The gravitational force mg is acting downward.
The net force at the bottom is the difference of these forces:
F_b = T_b - mg
Since the total mechanical energy is conserved, we can equate the centripetal forces acting on the ball at the top and bottom of the circle:
\(m(v_t^2) / L = m(v_b^2) / L\)
As we can see, the mass m and length L cancel out:
\(v_t^2 = v_b^2\)
Now we can relate the forces to the centripetal acceleration:
At the top: \(F_t = m(v_t^2) / L\)
At the bottom: \(F_b = m(v_b^2) / L\)Substituting the expressions for F_t and F_b, we get:
\(T_t + mg = m(v_t^2) / L\)
\(T_b - mg = m(v_b^2) / L\)
Since \(v_t^2 = v_b^2\), we can set the centripetal forces equal to each other:
m(v_t^2) / L = m(v_b^2) / L
Now subtract the equation for the forces at the top from the equation for the forces at the bottom:
(T_b - mg) - (T_t + mg) = 0
Simplifying the equation, we get:
T_b - T_t = 2mg
So, the difference between the magnitude of the tension in the string at the bottom relative to that at the top of the circle is 2mg.

To learn more about tension https://brainly.com/question/15589506

#SPJ11

my

The correct answer of terrestial weather:

The solar insolation in the visible and infrared regions of the solar electromagnetic spectrum is much more than the energy that space weather occurrences release into the troposphere and stratosphere. Despite claims to the contrary, there may be some connection between the Earth's climate and the 11-year sunspot cycle. There is no proof of this. For instance, it has frequently been suggested that the Maunder minimum, a 70-year period almost devoid of sunspots, is correlated to a cooler climate, but these correlations have vanished after further research. Changes in cosmic ray flux are hypothesized to affect how much cloud formation occurs.

To learn more about weather refer the link:

https://brainly.com/question/9662539

#SPJ9

The spring constant is 0.943 N/m. The spring pushes the object back towards its original position and this energy is converted into kinetic energy.

The system in this scenario consists of the 250. g object and the spring it is attached to. When the object is pushed against the spring, it compresses and stores potential energy. When released, the spring pushes the object back towards its original position and this energy is converted into kinetic energy.

The fact that the system experiences 12 cycles every 20 seconds tells us that the object oscillates back and forth 12 times in 20 seconds. One full oscillation is equal to the object moving from its starting position, to the maximum displacement from that position, back to the starting position, and then to the maximum displacement in the opposite direction, before returning again to the starting position.

To find the spring constant, we can use the equation for the period of oscillation of a mass-spring system:

T = 2π * sqrt(m/k)

where T is the period of oscillation, m is the mass of the object, and k is the spring constant.

We know that T = 20 s / 12 = 1.67 s (since there are 12 cycles in 20 seconds). We also know that m = 250. g = 0.25 kg.

Plugging these values into the equation, we can solve for k:

1.67 s = 2π * sqrt(0.25 kg/k)

1.67 s / (2π) = sqrt(0.25 kg/k)

0.265 s^2/kg = 0.25 kg/k

k = 0.25 kg / 0.265 s^2

k = 0.943 N/m

Therefore, the spring constant is 0.943 N/m.

to learn more about kinetic energy click here:

brainly.com/question/22174271

#SPJ11

Answer:

Inversely

Explanation:

According to Newton's Second Law, force is equal to mass times acceleration (F=ma).  Rewriting this equation as an expression for acceleration, we have a=F(\(\frac{1}{m}\)).  This shows a∝\(\frac{1}{m}\), or acceleration is proportional to the inverse of mass.

1. The velocity ratio in the given gear system is 2

2. The force ratio in the given gear system is 0.5

The velocity ratio in the given gear system can be obtained as illustrated below:

Velocity ratio = Number of driven gear / Number of driver's gear

= 60 / 30

= 2

Thus, the velocity ratio is 2

The force ratio in the given gear system can be obtained as follow:

Force ratio = 1 / velocity ratio

= 1 / 2

= 0.5

Thus, the force ratio is 0.5

Learn more about gear ratio:

https://brainly.com/question/14339779

#SPJ1

1)The strength of the magnetic field for particle 1 will be 2.8 T.

2)The magnitude of the magnetic force exerted on the particle will be 0.12 N.

It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.

The given data in the problem is;

q₁ has a charge = 2.7 μc

v₁ is the velocity of particle 1 = 1 773 m/s.

F is magnetic force = 5.75 × 10–3 n,

q₂ has a charge of 42.0 μc

v₂ is the velocity of 1.21 × 103 m/s.

\(\rm F_{B2}\)   is the magnitude of the magnetic force exerted on particle 2=?

The megnetic force for case 1 is found as;

\(\rm F_{B1}= qvB SIN \alpha_1 \\\\ 5.75 \times 10^{-3} =2.7 \times 10^{-6}\times 773 \times B sin 90^0 \\\\ B=\frac{5.75 \times 10^{-3}}{2.7 \times 10^{-6} \timesd 773 \times sin 90^0} \\\\ B=2.8 \ T\)

The megnetic force for case 2 is found as;

\(\rm F_{B2} = q_2v_2bsin \alpha_2 \\\\ 42\times 10^{-6} \times 1.21 \times 10^3 \times 2.8 \times sin 55^0 \\\\ F_{B2}=0.12 T\)

Hence the value of the megnetic force exerted on particle 2 will be 0.00122 T.

To learn more about the magnetic field refer to the link;

https://brainly.com/question/19542022

Answer:

last one and second one

Explanation:

Particle q1 has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10–3 N, what is the strength of the magnetic field?

2.8

T

In the same magnetic field, particle q2 has a charge of 42.0 μC and a velocity of 1.21 × 103 m/s. What is the magnitude of the magnetic force exerted on particle 2?

0.12

N