A rectangular block of copper metal weighs 1896 g. The dimensions of the block are 8.4 cm by 5.5 cm by 4.6 cm. From this data, what is the density of copper?

Question 7 options:

7.9 g/cm3


9.0 g/cm3


8.92 g/cm3


0.11 g/cm3

Answer:

The predictions for CO32– are: number of protons is 8, number of electrons is 10; for CrO42– are: number of protons is 16, number of electrons is 18; for I?– are: number of protons is 53, number of electrons is 54; for Na+ are: number of protons is 11, number of electrons is 10; for Cu2+ are: number of protons is 29, number of electrons is 28; for Co2+ are: number of protons is 27, number of electrons is 26; and for Pb2+ are: number of protons is 82, number of electrons is 80.

The ions with negative charges are anions and those with positive charges are cations.

An ion is defined as an atom or a molecule which has a net electrical charge. There are 2 types of ions :1) cation 2) anion . The cation is the positively charged ion and anion is the negatively charged ion . As they are oppositely charged they attract each resulting in the formation of ionic bond.

Ions consisting of single atom are mono-atomic ions while which consists of two or more ions are called as poly-atomic ions . They are created by chemical interactions . They are very reactive in their gaseous state and rapidly react with oppositely charged ions resulting in neutral molecules.

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The specific heat of aluminum is  0.92 J/g°C.

Use the principle of conservation of energy.

Q aluminum = -Qwater-calorimeter

(m aluminum)(c aluminum)(ΔT aluminum) = -(m water + m calorimeter)(c water)(ΔT water)

where Q is the heat transferred, m is the mass, c is the specific heat, and ΔT is the change in temperature.

Calculate the heat lost by the aluminum.

Q aluminum = (m aluminum)(c aluminum)(ΔT aluminum)

where ΔT aluminum is the change in temperature of the aluminum when it was heated in boiling water:

ΔT aluminum = 98.7°C - 100°C

= -1.3°C

Q aluminum = (73.5 g)(c aluminum)(-1.3°C)

Q water-calorimeter = -(m water + m calorimeter)(c water)(ΔT water)

where ΔT water is the change in temperature of the water in the calorimeter:

ΔT_water = 28.2°C - 25.4°C

= 2.8°C

Q water-calorimeter = -(1500 g + m calorimeter)(4.18 J/g°C)(2.8°C)

Q water = -(1500 g)(4.18 J/g°C)(2.8°C)

Substitute the values and solve for c aluminum:

(73.5 g)(c aluminum)(-1.3°C) = -(1500 g)(4.18 J/g°C)(2.8°C)

c aluminum = -(1500 g)(4.18 J/g°C)(2.8°C) / (73.5 g)(-1.3°C)

c aluminum = 0.92 J/g°C

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Answer:

-BaCl₂.

-KBr.

-C₆H₅COOH.

-C₆H₁₂O₆.

Explanation:

As the problem states, conductivity is related to the number of ions in solution, the larger the number of ions, the greater the conductivity.

Meaning the ranking from most conductive to least conductive is:

The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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Answer:

3.31 g/cm³

Explanation:

1000cm³ = 1L

4.87mL = 4.87 × 10^-3 × 1000 = 4.87 cm³

density = mass/volume = 16.12/4.87 = 3.31 g/cm³

Answer:

When metals react they lose electrons.

Explanation:

An ion is defined as a molecule or atom made up of a different number of electrons and protons. This makes the electric charge of the molecule net, not neutral.

In other words, an ion is a molecule or atom that has a positive or negative electric charge, making it an atom whose electric charge is not neutral.

The characteristic property of a metallic atom is to lose one or more of its electrons to form a positive ion. That is, metals lose electrons and acquire a net positive charge, which is why they are electropositive.

The density of nitrogen gas at 67.3 °C and 0.288 atm is approximately 0.0147 g/L.

Nitrogen are commonly used during sample preparation in chemical analysis and It also used to concentrate and reduce the volume of liquid sample.

The density of a gas can be calculated using the Ideal Gas Law:

PV = nRT

We can rearrange the equation to solve for the volume:

V = nRT / P

And then use the density formula:

density = mass / volume = m / V

where m is the mass of the gas and V is the volume.

Since the moles and the mass of a gas are related by its molecular weight (m = n * MW), we can substitute n * MW for m:

density = (n * MW) / V

Plugging in the values we get:

density = (n * 28.01) / (RT / P)

density = (n * 28.01 g/mol) / ((8.31 J/molK * (67.3 + 273.15 K)) / 0.288 atm)

density = (n * 28.01 g/mol) / (547.57 J/mol / 0.288 atm)

density = (n * 28.01 g/mol) / (1915.69 J/mol / atm)

density = (n * 28.01 g/mol) * (1 atm / 1915.69 J/mol)

density = 0.0147 g/L

Therefore, The density of nitrogen gas at 67.3 °C and 0.288 atm is approximately 0.0147 g/L.

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The density of the Nitrogen gas is 0.29 g/mol.

The Ideal gas law is a scientific equation that describes the behavior of an ideal gas, a theoretical gas made up of a large number of particles that do not interact with each other. The Ideal gas law states that the pressure, volume, and temperature of an ideal gas are directly proportional to each other.

Using the formula;

d = MP/RT

Density = d

Molar mass of the gas = M

Gas constant = R

Temperature = T

d= 28 g/mol * 0.288/0.082 * 340.3

d = 8.06/27.9

d = 0.29 g/mol

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The correct option that represents the constants of the reaction vessel after the N₂ and Cl₂ react as completely as possible is A.

The balanced chemical equation for the reaction is:

N₂(g) + 3Cl₂(g) → 2NCl₃(g)

This means that 1 mole of nitrogen gas and 3 moles of chlorine gas react to produce 2 moles of nitrogen trichloride gas.

The contents of the two vessels are:

Vessel 1: 1 mole of N₂

Vessel 2: 3 moles of Cl₂

When these two vessels are combined, the chlorine gas will react completely with the nitrogen gas to produce nitrogen trichloride gas. The remaining gas in the vessel will be nitrogen trichloride gas.

Which is:

[N₂] = 0 mol

[Cl₂] = 0 mol

[NCl₃] = 2 mol

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Complete question:

11 Question 3 A =N O=CI N2 +3 Cl2 2 NC13 The contents of two vessels are combined, as shown. The balanced chemical equation for the reaction that occurs is also shown. Which of the following represents the contents of the reaction vessel after the N2 and Cl2 react as completely as possible?

Answer:

221.5 g

Explanation:

if you want a step by step problem feel free to ask

B. The movement of basketball players on a court of the following is an example of quantization

The process of translating continuously infinite values to a more manageable collection of discontinuous finite values is known as quantization. It involves estimating real-world values with a digital representation that places restrictions on a value's precision and range in the context of simulation and embedded computing.

As a general guideline, quantize to the note you've played that is the shortest; for example, if the phrase contains both eighth and quarter notes, use eighth note resolution. Keep in mind that many rhythms may really employ triplets; if things aren't working out, you may try utilising a triplet resolution.

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Answer:

The only force on it is its weight, w=9800N

Explanation:

The partial pressure of \(N_2\)is 165.6 kPa and the partial pressure of \(H_2\)is 434.4 kPa.

To calculate the partial pressures of \(H_2\)and \(N_2\)in the 10dmcube container, we need to use the ideal gas law equation, which states that the pressure of a gas is directly proportional to its number of moles and temperature, and inversely proportional to its volume.

First, we need to calculate the number of moles for each gas. Since we are given the volume of each gas and the volume of the container, we can use the formula:

Number of moles = Volume / Molar volume

The molar volume is the volume occupied by one mole of a gas at a given temperature and pressure. At standard temperature and pressure (STP), the molar volume is 22.4 L/mol.

For \(N_2\), the number of moles is 2 dmcube / 22.4 L/mol = 0.089 mol
For \(H_2\), the number of moles is 5 dmcube / 22.4 L/mol = 0.223 mol

Next, we can calculate the partial pressures of each gas using the formula:

Partial pressure = (Number of moles / Total number of moles) * Total pressure

The total pressure is the sum of the pressures of each gas:

Total pressure = Pressure of N2 + Pressure of \(H_2\)

Given that the pressure of N2 is 100 kPa and the pressure of \(H_2\)is 500 kPa, we have:

Total pressure = 100 kPa + 500 kPa = 600 kPa

Now we can calculate the partial pressure of \(N_2\):

Partial pressure of \(N_2\)= (0.089 mol / (0.089 mol + 0.223 mol)) * 600 kPa = 165.6 kPa

Similarly, we can calculate the partial pressure of \(H_2\):

Partial pressure of H2 = (0.223 mol / (0.089 mol + 0.223 mol)) * 600 kPa = 434.4 kPa

Therefore, the partial pressure of \(N_2\)is 165.6 kPa and the partial pressure of \(H_2\)is 434.4 kPa.

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The N/Z ratio for 136Sm is 1.16

N/Z ratio is the ratio of number of neutrons and protons present in the nucleus of an atom.

The ratio of neutrons to protons is very important in determining nuclear stability. If there are more protons in the nucleus, the nucleus will require more neutrons to bind the nucleus together. This is because as the size of the nucleus increases, the electrostatic repulsion between the protons gets weaker.

Given,

The nucleus of Sm has :

Number of protons = 62

Mass number = 136

Number of neutrons = mass number - number of protons

                                  = 136 - 62

                                   =72

         N/Z ratio = \(\frac{number of neutrons}{number of protons}\)

                        = \(\frac{72}{62}\)

                       = 1.16

Therefore, the N/Z ratio for 136Sm is 1.16.

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Answer:

its sodium hydroxide

Explanation:

Marks that might link a bullet to a specific weapon include striations, which are unique patterns and imperfections left on the bullet's surface as it passes through the barrel of a firearm. As for the fingerprints found, it depends on the context of the investigation. Fingerprints can be categorized into three main types: latent, patent, and plastic.

Marks that might link a bullet to a specific weapon include striations, which are unique patterns and imperfections left on the bullet's surface as it passes through the barrel of a firearm. These striations are caused by the unique characteristics of the rifling inside the barrel, such as the number of lands and grooves, their width, depth, and the direction of twist. Comparing the striations on a recovered bullet to test-fired bullets from a suspected weapon can help determine if they match, indicating a potential link.

As for the fingerprints found, it depends on the context of the investigation. Fingerprints can be categorized into three main types: latent, patent, and plastic. Latent fingerprints are invisible and require development techniques such as powder or chemical methods to make them visible. Patent fingerprints are visible prints left on a surface, such as blood or dirt. Plastic fingerprints are three-dimensional impressions left on soft surfaces like clay or wax.

Without specific information on the crime scene or the type of fingerprints found, it is not possible to determine which type the investigator has encountered.

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Answer:

h+(aq)+no−2(aq)⇌hno2(aq)2. hno2(aq)⇌h+(aq)+no−2(aq)3. hno2(aq)⇌h−(aq)+no+2(aq)4. hno2(aq)+h+(aq)⇌h2no+2(aq)5. hno2(aq)+h−(aq)⇌h2no+2(aq)​b.

Explanation:

The acidic equilibrium equation for nitrous acid is shown as HNO₂ ⇄ H⁺ + NO₂⁻ in which acid is in equilibrium with its dissociate ions.

Equilibrium state in any chemical reaction is that state in which concentration of reactant and products will attain constant value.

Acidic equilibrium equation for Nitrous acid (HNO₂) is shown as:

HNO₂ ⇄ H⁺ + NO₂⁻

From the above equation it is clear that in equilibrium state concentration of nitrous acid is in equilibrium with the H⁺ ion and NO₂⁻ ion.

Hence, HNO₂ ⇄ H⁺ + NO₂⁻ is the acidic equilibrium equation.

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Answer:

Nitrobenzene < Bromobenzene < Benzene < Phenol

Explanation:

Aromatic compounds undergo electrophilic aromatic substitution reaction in the presence of relevant electrophiles. Certain substituents tend to increase or decrease the tendency of an aromatic compound towards electrophilic aromatic substitution reaction.

Substituents that increase the electron density around the ring such as in phenol tends to make the ring more reactive towards electrophilic substitution. Halogens such as bromine has a -I inductive effect as well as a +M mesomeric effect.

However the -I(electron withdrawing effect) of the halogens supersedes the +M electron donation due to mesomeric effect.

Putting all these together, the order of increasing reactivity of the compounds towards electrophilic aromatic substitution is;

Nitrobenzene < Bromobenzene < Benzene < Phenol

At STP 32 g of O₂ would occupy by the same volume as  4 g of He

Complete question

At STP 32 g of O₂ would occupy by the same volume as:

Standard Conditions

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So the gas will have the same volume if the number of moles is the same

mol of 32 grams of O₂ :

\(\tt \dfrac{32}{32}=1\)

\(\tt mol=\dfrac{4}{4}=1\)

\(\tt mol=\dfrac{8}{16}=0.5\)

\(\tt mol=\dfrac{64}{2}=32\)

\(\tt mol=\dfrac{32}{64}=0.5\)

So mol of 4 g He = mol of 32 g O₂

STP is the standard temperature and pressure of the gas to compare with the experimental data. At STP 32 gm of oxygen is equivalent to 4 gm of helium.

STP is the standard temperature and pressure of 0 degrees Celsius and 1 atm. At this temperature and pressure, the volume of the gas is 22.4 L/mol.

So, if the moles of the 32 gm oxygen are the same as the other element then the volume will also be the same. Here, the moles of oxygen are 1 mol.

Moles of 4 gm helium is 1, 8 gm methane is 0.5 mol, 64 gm dihydrogen is 32 mol, and 32 gm sulfur dioxide is 0.5 mol.

Therefore, the mole of 4 gm helium is equivalent to the mole of 32 gm oxygen.

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Question:

What occurs to the atoms of reactants in a chemical reaction?

Answer:

In a chemical reaction, the atoms and molecules that interact with each other are called reactants. ... No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Answer: 2.88×\(10^{24}\)atoms \(P_{2}O_{5}\)

Explanation: First, using stoichiometry, we must convert this from grams to moles, then from moles to atoms.

1. For the first step, we should also look at the periodic table to find the molar mass of the compound, then use that as the denominator.

\(0.680g P_{2} O_{5} *\frac{1molP_{2} O_{5} }{141.948gP_{2} O_{5} } =4.79mol P_{2} O_{5}\)

2. Now that it is converted to moles, we must convert it to atoms by multiplying it by Avogadro's number.

\(4.79molP_{2} O_{5} *\frac{6.022X10^{23} }{1mol} =2.88*10^{24}\)

With this information, we know that there are \(2.88X10^{24}\) total atoms in 0.680 grams \(P_{2} O_{5}\).

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The best description of the relationship between population size, carrying capacity, and limiting factors is: "The size of a population usually stays near its carrying capacity due to limiting factors."

Carrying capacity refers to the maximum number of individuals that a particular environment can sustainably support. It represents the limit to which a population can grow given the available resources, such as food, water, and habitat. Limiting factors, on the other hand, are the factors that restrict population growth by reducing birth rates, increasing death rates, or limiting access to resources.As a population approaches its carrying capacity, limiting factors come into play and regulate the population size. These limiting factors can include competition for resources, predation, disease, availability of suitable habitat, and other environmental factors. They act as checks on population growth, preventing it from exceeding the carrying capacity of the ecosystem.

Therefore, the size of a population usually stays near its carrying capacity because the limiting factors ensure that the population does not exceed the available resources and ecological limits of the environment. If the population surpasses the carrying capacity, the limiting factors will intensify, causing a decline in resources and an increase in mortality rates, which ultimately brings the population back towards the carrying capacity.It's important to note that the relationship between population size, carrying capacity, and limiting factors is dynamic and can vary depending on various ecological and environmental factors.

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Answer:

0.322 g

Explanation:

Since our concentration is given in mass per volume percent % (m/v)

% (m/v) = mass of solute in g/volume of solution in mL × 100%

Since % (m/v) = 0.92 and volume of the required solution is 35.0 mL, we find the mass of NaCl from

mass of NaCl = % (m/v)/100 % × volume of solution

= 0.92 % (m/v)/100 %× 35 mL

= 0.0092 × 35

= 0.322 g

The study of a chemical is called chemistry.

The correct answer is 0.322 g

The saline is said that the amount of salt present in the solution. The formula used to solve the question is as follows:-

\(\frac{m}{v} = \frac{mass \ of\ solute}{volume\ of\ solution} * 100\)

The data is given as follows:-

Mass of NaCl is as follows:-

 \(\frac{0.92}{100} * 35 mL\)

\(0.0092 * 35\\= 0.322 g\)

Hence, the correct answer is 0.322g.

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Ethanol is formed by the combination of carbon, hydrogen and oxygen as shown in the image attached.

We know that ethanol is an organic compound and the compound is part of the alkanol family of the organic compounds. In this case we are trying to find the equation that shows the enthalpy of the formation of the ethanol.

We know that such equation would have to involve the pure substances that can be combined so as to form the ethanol and the equation for this reaction has been shown in the image attached to this answer.

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Although there is some variation amongst tissues, the physiologically typical intracellular pH ranges from 7.0 to 7.4. Skeletal muscle in mammals typically has a pHi of 6.8 to 7.1.

A cell is the basic membrane-bound living thing and can either have one or more cells. All the molecules required for an organism to function are found in cells. An atomic is 10-10m in size. In contrast, a cellular is 10-6 metres in size. Because all cells are composed of atoms, they are therefore bigger than atoms.

Acid excretion, efflux through plasma membranes, and buffering mechanisms all work together to precisely preserve the pH of body fluids. Protons are extruded from the cytosol into the extracellular space through the organic cation transporter (MCT) and the Na+/H+ exchanger (NHE).

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Explanation:

Carbon-14 has a half life of 5730 years, meaning that 5730 years after an organism dies, half of its carbon-14 atoms have decayed to nitrogen atoms. Similarly, 11460 years after an organism dies, only one quarter of its original carbon-14 atoms are still around.

Answer:

Hey there!

That would be the alkaline earth metals.

Hope this helps :)

Answer: alkaline earth metals

Explanation:

a) The balanced chemical equation for the reaction is: 2H₂ + O₂ → 2H₂O

b) the number of moles of O₂ required is approximately 1.004 moles.

c)  approximately 45 liters of H₂ and 22.5 liters of O₂ are needed to obtain 45 liters of H₂O.

a) Balancing the chemical equation:

The balanced chemical equation for the reaction is: 2H₂ + O₂ → 2H₂O

b) Calculating the number of moles of the reactants needed to obtain 45 liters of H₂O:

From the balanced equation, we can see that for every 2 moles of H₂O produced, we need 2 moles of H₂ and 1 mole of O₂. Since the stoichiometry is based on moles, we need to convert the given volume of H2O into moles.

To convert volume to moles, we need to use the ideal gas law, PV = nRT. At standard temperature and pressure (STP), the molar volume of an ideal gas is 22.4 liters.

Given that we have 45 liters of H2O, we can calculate the number of moles as follows:

moles of H₂O = (volume of H₂O) / (molar volume at STP)

            = 45 liters / 22.4 liters/mol

            ≈ 2.008 moles of H₂O

Since the stoichiometry of the reaction is 2 moles of H₂O for every 2 moles of H₂, we need an equal number of moles of H₂. Therefore, the number of moles of H₂ required is also approximately 2.008 moles.

For O₂, since the stoichiometry is 1 mole of O₂ for every 2 moles of H₂O, we need half the number of moles of H₂O. Thus, the number of moles of O₂required is approximately 1.004 moles.

c)  the volume of the reactants:

Since the stoichiometry of the balanced equation is 2 moles of H₂for every 1 mole of O₂ and 2 moles of H₂O, we can deduce the volume of the reactants based on their molar volumes at STP.

For 2.008 moles of H₂, the volume can be calculated as follows:

volume of H₂= (moles of H₂) * (molar volume at STP)

            = 2.008 moles * 22.4 liters/mol

            ≈ 45 liters of H₂

For 1.004 moles of O₂, the volume can be calculated similarly:

volume of O₂= (moles of O₂) * (molar volume at STP)

            = 1.004 moles * 22.4 liters/mol

            ≈ 22.5 liters of O₂

Therefore, approximately 45 liters of H₂and 22.5 liters of O₂ are needed to obtain 45 liters of H₂O

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The molar ratio of (6 moles of NaBr)/(1 mole of Fe₂S₃) is correct based on the balanced chemical equation.

The balanced chemical reaction is given as;

2FeBr₃ + 3Na₂S   →  Fe₂S₃   +  6NaBr

From the balanced chemical reaction above, 6 moles of NaBr will also correspond to 1 mole of  Fe₂S₃.

Thus, the molar ratio of (6 moles of NaBr)/(1 mole of Fe₂S₃) is correct based on the balanced chemical equation.

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