A rope is attached from a truck to a 1442 kg car. The rope will break if the tension is greater than 2306 N. Neglecting friction, what is the maximum possible acceleration of the truck if the rope does not break

Answer:

B

C

D

My answers... I hope this helps

Answer:

3500joules of work

Explanation:

Work done = Force×,distance

Given

Focrce= mass ,× acceleration = 140×10 = 1400N

Distance moved = 2.5m

Workdone = 1400×2.5

Work done = 140×25

Workdone = 3500Joules

radiation

when the suns radiation fall on the earth and its objects they receive heat energy and hence get heated. Thus the suns heat reaches the earth by. the process of radiation

Absence of medium is the factor which shows that heat from the sun does reach the earth's surface by convection.

The heat of the sun reaches the earth only through radiation because radiation does not require any medium for the transfer of energy but convection and conduction required a medium to transfer heat energy.

We know that there is no medium present in vacuum so convection and conduction are impossible in a vacuum that's why the sun's heat does not reach the earth by conduction or convection.

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Answer:

yes

Explanation:yes

Answer:

Yes

Explanation:

Earth is accelerated around the sun

Explanation:

K = 5kg\((2 m/s)^{2}\)/2 = 10 J

When force stays the same and the mass increases, the ACCELERATION DECREASES.

Answer:

Explanation: 139 m

The particle moves to the right through a potential difference of Vb-Va = 3.20×10^-19 J / q.

The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 3.20×10^-19 J. To determine the direction and potential difference through which the particle moves, we can use the relationship between electric potential difference (V) and electric force (F) on a charged particle.

The electric potential difference between two points is defined as the work done per unit charge to move a particle from one point to the other. The work done on a charged particle by an electric force is given by the equation

W = Fdcos(theta)

where F is the electric force, d is the distance moved by the particle, and theta is the angle between the direction of the force and the direction of the displacement.

In this case, since the particle is only acted upon by the electric force and moves along the x-axis, the angle between the direction of the force and the direction of the displacement is 0, and the work done by the electric force is given by W = Fdx.

Therefore, the potential difference between point a and point b is given by Vb - Va = W/q, where q is the charge of the particle.

Given that the particle's kinetic energy increases by 3.20×10^-19 J and the work-energy principle states that work done on a particle is equal to the change in kinetic energy, we can say that the work done on the particle is equal to 3.20×10^-19 J.

Now, the direction of the force can be determined by the sign of the potential difference, since the electric force is given by

F = -q(dV/dx).

Given that the potential difference is positive, the electric force is negative, meaning that the force is directed opposite to the direction of motion of the particle, therefore the direction of motion is to the right.

Therefore, the particle moves to the right through a potential difference of Vb-Va = 3.20×10^-19 J / q.

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Answer:

The second fish, X2, is moving faster than the first fish, X1

Explanation:

The given parameters for the equation of motion of the fishes are;

X1 = -6.4 m + (-1.2 m/s)×t

X2 = 1.3 m + (-2.7 m/s)×t

The given equation are straight line equations in the slope and intercept form, where the slope is the speed and in m/s and the intercept is the starting point of swimming of the fishes

For the first fish, the intercept = -6.4 m, the slope = the  speed = -1.2 m/s

For the second fish, the intercept = 1.3 m, the slope = the  speed = -2.7 m/s

Whereby the fishes are swimming in the opposite direction of the measurement of length, we have;

The magnitude of the speed of the second fish \(\left | -2.7 \ m/s \right | = 2.7 \ m/s\), is larger than the magnitude of the speed of the first fish \(\left | -1.2 \ m/s \right | = 1.2 \ m/s\)

Therefore, the second fish, X2, is moving faster than the first fish, X1.

The current through resistor R3 is 0.33 A. A circuit with three resistors connected in series is shown below: Circuit diagram of three resistors connected in series As per the given information, R2 has a resistance of 200 ohms and a voltage drop of 30 volts.

Therefore, the voltage drop across R1 is V1 = V - V2 - V3V = voltage supplied to the circuit = voltage drop across R1 + voltage drop across R2 + voltage drop across R3R1 = Resistance of resistor R1.R2 = Resistance of resistor R2 = 200 Ω.V3 = Voltage drop across resistor R3.I3 = Current through resistor R3.To calculate the current in resistor R3, let's follow the steps given below.Step 1: Find the voltage drop across R1.Using Ohm's Law, the voltage drop across R2 is V2 = IR2Substitute the values of V2 and R2 to get the value of current I.I = V2/R2I = 30/200I = 0.15 A

Using Kirchhoff's voltage law, the voltage drop across R1 isV1 = V - V2 - V3V = V1 + V2 + V3Substitute the values of V, V2, and V3 to get the value of V1.V1 = V - V2 - V3V1 = 100 - 30 - V1V1 = 70 VStep 2: Find the current through R3.Using Ohm's Law, the voltage drop across R3 is V3 = I3R3.Substitute the values of V3 and R3 to get the value of current I3.I3 = V3/R3I3 = (V - V1 - V2)/R3I3 = (100 - 70 - 30)/R3I3 = 0.33 A

Therefore, the current through resistor R3 is 0.33 A.

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The astronomer on duty going to have a bit of a problem satisfying her request because after a white dwarf cools off it will become too cold and dark to emit seen light.

The enlargement and contraction of pulsating variables can be measured through the use of the Doppler impact. The lines in the spectrum shift in the direction of the blue because the floor of the celebrity moves closer to us and then shifts to the pink because the surface shrinks again.

Astronomers take a look at planets, stars, and different celestial bodies. They use ground-based devices, including optical telescopes, and area-based total gadgets, consisting of the Hubble Space Telescope. some astronomers look at distant galaxies and phenomena which include black holes and neutron stars.

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Answer:

The momentum of an object is equal to the product of its mass and its velocity.

Explanation:

Consider an object of mass \(m\) travelling at a velocity \(\vec{v}\). The momentum \(\vec{p}\) of this object would be:

\(\vec{p} = m \cdot \vec{v}\).

For the law of conservation of momentum, consider two objects: object \(\rm a\) and object \(\rm b\). Assume that these two objects collided with each other.

The sum of the momentum of the two objects would be:

Assume that the system of these two objects is isolated. By the law of conservation of momentum, the sum of the momentum of these two objects should be the same before and after the collision. That is:

\(m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}) = m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})\).

The attractive Coulombic force between the proton and electron is approximately 2.3 x 10^-8 N.

To calculate this force, we can use Coulomb's law: F = (kq1q2)/r^2, where F is the force, k is Coulomb's constant, q1 and q2 are the charges of the two particles, and r is the distance between them. Plugging in the values, we get F = (9x10^9 Nm^2/C^2)(1.6x10^-19 C)*(-1.6x10^-19 C)/(4x10^-18 m^2) = -2.3x10^-8 N. The negative sign indicates that the force is attractive.

In summary, the attractive Coulombic force between the proton and electron is -2.3 x 10^-8 N, which is found using Coulomb's law and the charges and distances given in the problem.

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F = 6.0 x 10⁻⁸ N

Given

mass of 2 dump trucks = 1500 kg

distance = 50 m

Required

Gravitational force

Solution

Newton's Gravity Law:  

\(\rm F=G.\dfrac{m_1.m_2}{r^2}\)

with F = gravitational force,  

G = gravitational constant,  

m1, m2 = mass of object,  

r = distance between two objects.  

Input the value :

F = (6.67.10⁻¹¹N.m² / kg² x 1500²) :  50²

F = 6.0 x 10⁻⁸ N

Answer:

the answer is D metal resting

Explanation:

I just think that because if you treasure can that's physical charge by dropping where you create a physical charge melting and Ice Cube might be 1 but I feel like metal resting is more likely

Answer:

\43 ° n, 72 ° w

42° 0' 30" N, 71° 30' 58" W

The correct order of heat transfer in sealed cans is as follows: conduction, convection, and radiation.

Conduction is the transfer of heat through direct contact between objects or materials. In the case of sealed cans, heat is transferred from the outside to the contents or vice versa through the walls of the can via conduction.

Convection is the transfer of heat through the movement of a fluid, either liquid or gas. Although sealed cans do not allow for direct fluid motion inside, there can be some convective heat transfer occurring within the contents of the can due to natural convection. This is especially relevant when the can's contents are heated, causing the fluid to circulate within the can.

Radiation is the transfer of heat through electromagnetic waves. While radiation can occur in all directions, it is generally less significant in sealed cans compared to conduction and convection. The walls of the can and the contents can emit and absorb thermal radiation, but the effect is typically smaller compared to the other modes of heat transfer.

Overall, the predominant modes of heat transfer in sealed cans are conduction followed by convection, with radiation playing a lesser role.

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Zigzagging mountain roads offer several advantages from the viewpoint of energy conservation and power: Reduced gradient. Improved traction. Reduced stress on the road. Easier construction

What advantages do Zigzagging mountain roads have?

Zigzagging mountain roads also known as switchbacks have several advantages with respect to energy conservation and power: Reduced gradient: Switchbacks allow the road to have a shallower gradient compared to a straight road, which reduces the amount of energy required to climb the mountain. This can save fuel for vehicles and reduce the physical exertion for hikers and cyclists. Improved traction: The zigzagging design provides better traction for vehicles and reduces the risk of skidding or slipping, especially in wet or icy conditions. Reduced stress on the road: A straight road up a steep mountain would experience higher stress and wear and tear, which could lead to damage or even collapse. Zigzagging the road reduces the stress and prolongs the road lifespan. Easier construction: Building a straight road up a steep mountain would require much more excavation and engineering work, making it a more expensive and time-consuming process. Zigzagging the road allows for easier and more efficient construction.

Overall, the switchback design of mountain roads is a more efficient and practical solution that conserves energy, improves safety, reduces stress on the road, and makes construction easier.

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A projectile is fired into a region of no air resistance the horizontal component of velocity remains constant because projectiles

A) is not acted on by any horizontal force

Velocity remain constant until unless any net external force acts on the object . While in a projectile motion , there is a gravitational force which act in downward direction . And there is no horizontal force , hence horizontal velocity remain unchanged . Velocity remains constant because projectiles

A) is not acted on by any horizontal force

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Answer:

B

Explanation:

If you really read and dissect every other question they do not make sense

V was pulled off at a 9.2 km/s clip by us. Three metres per second is equivalent to 9.3 into 10 times.

To avoid wasting too much energy, we need to determine the projectile's highest point. Every project possesses some form of energy, which it will transform into potential energy and use to grow to its highest point

A projectile that oscillates over a horizontal plane in response to external forces is said to be travelling horizontally. The vertical and horizontal motions of the projectile are independent of one another and parallel across short distances.

Motion to the side: In the absence of an impediment, a motion

Let's designate v for vertical velocity and u for horizontal velocity.

Say the horizontal distance (R) is equal to the horizontal velocity (u) times the flying duration (t). In mathematics, R = u T.

But first, we need a flight time (t). Utilizing the equation of motion, which is

v1=v0+at

In this case, v0=20,v1=0,a=g=9.81m/s2, negative because the projectile decelerates as it goes upward. From this point, the projectile's maximum height(t) calculation yields a time of 2.04 seconds.

Given that the flight's time (T) = 2t = 4.08 seconds, the horizontal distance (R) is equal to u T 30 4.08 = 122.4 meters.

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The charge q2 is 1/2 times smaller than q1. This implies that q1 is twice the magnitude of q2.

Given that the electric field 1/3 of the way from a charge q1 to a charge q2 is zero. We can use the concept of Electric field and potential to find the ratio of q2 and q1.

The potential at any point from a point charge is given by the formula;

V = kq/r

where,V = potentialk = Coulomb's constantq = magnitude of the point charger = distance between the point charge and the point in question

The electric field is the negative derivative of the potential.

We can obtain the expression of the electric field by differentiating the expression of the potential using the expression below:

E = -dV/dr

where, E = Electric fieldr = distance between the point charge and the point in questiondV/dr = rate of change of the potential

Thus, the electric field 1/3 of the way from a charge q1 to a charge q2 is zero.

This implies that there is no potential difference between these points.

That is, the potential at the midpoint is equal to the average potential at the endpoints.

Since the electric field is zero, we can deduce that the potential at the midpoint is also zero. This implies that the average potential at the endpoints is also zero.

Therefore, we have;

V(q1) + V(q2) / 2 = 0

Substituting the expression of potential, we obtain;

kq1/r1 + kq2/r2 / 2 = 0

Multiplying by r1r2/2, we obtain;q1r2 + q2r1 = 0

Given that the point of interest is 1/3 of the way from q1 to q2, we can deduce that;r2 = 2r1

Substituting this in the equation above;q1(2r1) + q2r1 = 0q1 + 2q2 = 0q2 = -1/2 q1.

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There is no constant speed parameter ß that can satisfy the given conditions. The problem is not solvable as it leads to contradictory equations.

To determine the constant speed parameter ß required for the trip, let's break down the problem step by step.

1. Let's assume the daughter's age is represented by D and the father's age is represented by F.

2. We are given that the father is 22.00 years older than his daughter, so we can write the equation:
  F = D + 22.00

3. The father wants to travel outward from Earth for 3.000 years and then back to Earth for another 3.000 years. This means the total time elapsed for the father's journey is 6.000 years.

4. After the journey, the father wants to be 22.00 years younger than his daughter. So we can write the equation:
  F + 6.000 = D - 22.00

5. Now we have two equations:
  F = D + 22.00
  F + 6.000 = D - 22.00

6. We can solve this system of equations to find the values of F and D. Subtracting the first equation from the second equation gives:
  F + 6.000 - F = D - 22.00 - (D + 22.00)
  6.000 = -44.00

7. This is not a valid equation, which means there is no solution to the problem. The constant speed parameter ß cannot be determined in this case.

In summary, there is no constant speed parameter ß that can satisfy the given conditions. The problem is not solvable as it leads to contradictory equations.

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Answer:

SEx is where two species breed to produce offspring. In biology, asexual does not involve the fusion of gametes. In other terms, asexual means to not reproduce or enjoy partaking in sEx.

Explanation:

Answer: c

Explanation:

The frequency range of electromagnetic waves of X-ray is 3 ×10¹⁶ Hz to  3 ×10¹⁹ Hz. The wavelength range of electromagnetic waves of X-ray is  0.01 nm t0 10 nm.

The electromagnetic spectrum of electromagnetic waves can be described as the range of frequencies of electromagnetic radiation and its wavelengths and photon energies. The electromagnetic spectrum have range from one Hertz to above 10²⁵ Hertz.

The wavelength of electromagnetic radiation lies in between 380 to 760 nm and is detected by the human eye and characterized as visible light.

Electromagnetic waves of each frequency band are known by different names; starting at the low frequency (long wavelength) end of the spectrum these are radio waves, microwaves, infrared (IR), visible light, UV, X-rays, and gamma rays at the high-frequency (short wavelength) end.

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Napagyayaman ang kaalaman sa parabula bilang akdang pampanitikan?

→ Ang parabula ay mahalagang maunawaan at mapahalagahan bilang akdang pampanitikan sapagkat ito ay mga salita ni Hesus na kanyang ginamit upang maiparating sa mga tao ang mensahe ng Ama para sa kaligtasan ng mga makasalanan. Hindi lang ito malaking parte ng akdang pampanitikan ngunit pati na rin sa Katolikong paniniwala at pananampalataya.

Nakabubuo ng sariling konsepto tungkol sa parabula at sa layunin nito sa mambabasa.

→ Ito ay tumutukoy sa isang kwento na Kong saan ay tao ang gumaganap at into at patungkol sa bibliya

The potential difference between the plates is 3,281.25 V, with plate A at the higher potential.

The kinetic energy of an electron is given as 5.25 × \(10^{-16}\) J. This kinetic energy gained by the electron is equal to the work done on the electron by the electric field. Using the formula for the kinetic energy of an electron in an electric field we get, KE = (1/2)mv², where KE is the kinetic energy, m is the mass of the electron and v is the velocity of the electron.

In this case, we are given the value of KE which is 5.25 × \(10^{-16}\) J. We know the mass of the electron is 9.1 × \(10^{-31}\) kg.  Therefore, we can calculate the velocity of the electron using the given kinetic energy.

= 5.25 × \(10^{-16}\) = (1/2) × (9.1 × \(10^{-31}\)) × v²

⇒ v = 1.25 X × \(10^{7}\) m/s

The potential difference between the plates is given by the formula,

V = (KE / e)

where V is the potential difference, KE is the kinetic energy of the electron, and e is the charge on the electron which is equal to 1.6 × \(10^{-19}\) C. Therefore,

V = (5.25 × \(10^{-16}\) / 1.6 × \(10^{-19}\))

= 3,281.25 V

The plate from which the electron moves to the other plate is at a higher potential. Hence, plate A is at a higher potential.

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