A round ball is kicked into the air at an angle of 39 degrees above the horizontal. The
initial velocity of the ball is 32 m/s.
A. How long is the ball in the air?
B. What is the horizontal distance traveled by the ball?
C. What is the maximum height reached by the ball?

The abundance of helium in the universe suggested the existence of the Cosmic Microwave Background Radiation (CMBR) because it supported the Big Bang Theory, which predicted the presence of CMBR.

According to the Big Bang Theory, the universe began as a hot, dense state, and as it expanded and cooled, the first elements formed. Observations showed that around 25% of the observable universe is helium, which supports the idea that the universe had a hot and dense beginning. The Big Bang Theory also predicted the existence of CMBR as a residual radiation that permeates the universe, resulting from the initial expansion and cooling.

The abundance of helium in the universe is an important piece of evidence that supports the Big Bang Theory, which in turn predicts the existence of the Cosmic Microwave Background Radiation.

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To derive the algebraic equation for the vertical force, we must consider the forces acting in the vertical direction and apply Newton's second law of motion.

Newton's second law states that the net force acting on an object is equal to the product of its mass (m) and its acceleration (a). In the vertical direction, the forces that typically act on an object are gravity and any other forces such as the normal force or applied forces.

Assume that the vertical force is denoted as Fv. Forces acting in the vertical direction are typically mass (mg) and the normal force (N) exerted by the surface, if present. Therefore, the equation for the vertical force can be expressed as:

Fv = N - mg,

where:

Fv is the vertical force,

N is the normal force,

m is the mass of the object,

g is the acceleration due to gravity (approximately 9.8 m/s² on Earth).

The normal force N is equal to the weight of the object if the object is at rest on a horizontal surface. In this case, N = mg. However, if the object is on an inclined plane or is subject to other forces, the normal force may differ from the weight.

By substituting the appropriate values ​​for the normal force and mass (mg), you can derive an algebraic equation for the vertical force based on the specific scenario you are considering.

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Answer:

Long-period comets have orbital periods longer than 200 years. ... Since it is the sublimation of these volatiles from the nucleus of the comet as it nears the Sun that gives rise to the coma and highly-visible tails, long-period comets have more material with which to put on a show.

Explanation:

Answer:

C. 18 s

&

B. -7 m

Explanation:

A. 12 m/s, East is a vector. It says "East" so it would be a vector. Therefore this is not our answer since it's a vector and the question is asking for which one is not a vector.

B. It says "7 m". I think that means 7 meters. That's a length. There is no direction. It's not 7 meters up, or to the east, or north. So, with no direction, it's not a vector. Therefore this is not our answer.

C. For this one it says ""18 s". I think that means "18 seconds". Since this one is not mentioned "direction" meaning it's not a vector. Since the question is asking for the ones that are not a vector this would be another answer.

D. Since this one says "miles" it means it has a direction since it has a direction it is probably a vector, since it's a vector it wouldn't be our answer. Therefore this is not our answer.

A bicyclist starts at 3.5 m/s and accelerates along a straight path to a speed of 13.5 m/s in a time of 4.5 seconds. The bicyclist’s acceleration is 2.23 m/sec².

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

Given that is the question a bicyclist starts at 3.5 m/s and accelerates along a straight path to a speed of 13.5 m/s in a time of 4.5 seconds, then

the acceleration of bicyclist is,

acceleration = change in velocity / time taken

                     = (13.5 - 3.5) / 4.5

                     = 2.23 m/sec²

A bicyclist starts at 3.5 m/s and accelerates along a straight path to a speed of 13.5 m/s in a time of 4.5 seconds. The bicyclist’s acceleration is 2.23 m/sec².

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Answer:

v = 4.79 10³ m / s

Explanation:

For this exercise we will use the universal law of gravitation and Newton's second law

          F = G M m / r²

where G is the gravitational constant, m the mass of the satellite, M the mass of the Earth, r the distance from the center of the planet to the satellite

           F = m a

since the satellite has a circular path, the acceleration is centripetal

          a = v² / r

we substitute

          G M m / r² = m v² / r

           G M / r = v²

We calculate

          v² = 6.67 10⁻¹¹ 5.98 10²⁴ / 6.96 10⁶

          v = √ (22.94 10⁶)

          v = 4.79 10³ m / s

Answer:

7570 m/s

Explanation:

take the square root of: 6.67E-11× 5.98E24/6.96E6

Work by gravity plus work by water equals 0 or 2692 = F *1.10 or F = 2447 Newtons

As work-energy, you could:

Since she began and concluded at rest, her initial and final K are both zero. Total work = ΔK.

Gravity: force * distance

mgΔh = 67 * 9.8 * 4.10 = 2692 Joules.

Force * Dist =- F *1.10

Work by gravity + work by water  =  0

2692 - F *1.10   = 0  

2692  =  F *1.10    

F = 2447 Newtons!

Because gravity continues to affect her even when she is submerged, take note of the total distance she travels: 3.00 + 1.10!

Work now being done by the water: Because of the force pushing up on her as she descends, the equation  is negative. Work is negative when the directions of force and distance are in opposition.

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Answer:

B. mechanical to electrical

Answer:

\(P.E=mgh \\ 109 = m(9.81)(4.2) \\ m = \frac{109}{9.81 \times 4.2} \\ \boxed{m = 2.6455 \: kg}\)

Answer: Downwards

Explanation: Upwards is only at the start of a thunderstorm when air moves towards the poles. During the mature stage, air moves down towards the equator.

Explanation:

1A. The visible light portion of the electromagnetic spectrum shows the rainbow of colors, with violet and blue having shorter wavelengths, and therefore higher energy. At the other end of the spectrum toward red, the wavelengths are longer and have lower energy.

so its option 2

2A. Atom and molecules

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Answer:

a=-5.3m/s2

Explanation:

F=-20N

m=3.75kg

a=?

F=am /:m

a=F/m

a=-20N/3.75kg

a=-5.3m/s2

In summary, the observations about determining ages of rocks and fossils are based on scientific principles such as radioactive decay, superposition, and original horizontality.

A scientific principle is a fundamental concept or law that explains how the natural world works. It is a statement based on empirical evidence and repeated observations that is widely accepted by the scientific community as a fundamental truth. Scientific principles provide a framework for understanding and explaining natural phenomena, and they form the basis for scientific research and discovery.

Examples of scientific principles include:

The law of conservation of energy, which states that energy cannot be created or destroyed, only transformed from one form to another.

The theory of evolution, which explains how species change over time through natural selection and genetic variation.

The law of gravity, which explains the attraction between objects with mass and their impact on space-time.

The principle of relativity, which explains how the laws of physics are the same for all observers in uniform motion relative to each other.

Scientific principles are subject to change and refinement as new evidence and discoveries are made, but they provide a reliable foundation for scientific inquiry and understanding.

Here,

1. Observations about determining ages of rocks and fossils:

Scientists use a variety of methods to determine the ages of rocks and fossils, such as radiometric dating, relative dating, and stratigraphy.

Radiometric dating involves measuring the decay of radioactive isotopes in rocks or fossils, which provides an estimate of the time elapsed since the material was last heated or exposed to sunlight.

Relative dating involves comparing the ages of rocks or fossils based on their position in relation to one another.

Stratigraphy involves studying the layers of rock or sedimentary deposits to determine the relative ages of the materials.

2. Explanation based on scientific principles:

Radiometric dating is based on the principle of radioactive decay, which is the spontaneous breakdown of atomic nuclei into smaller particles over time. The rate of decay is constant, which allows scientists to use the amount of remaining radioactive material to estimate the time elapsed since the material was last heated or exposed to sunlight.

Relative dating is based on the principle of superposition, which states that the oldest rocks or fossils are found at the bottom of a sequence, while the youngest rocks or fossils are found at the top. By comparing the ages of rocks or fossils in different layers, scientists can determine their relative ages.

Stratigraphy is based on the principle of original horizontality, which states that sedimentary layers are deposited in horizontal layers. By studying the layers of rock or sedimentary deposits, scientists can determine the relative ages of the materials based on their position.

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Answer:

The Force between the two charges is an attractive force of 16,000N

Explanation:

Expression for the electric force between the two charges is given by

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

q1 = - 2.0x10^-4C

q2 = + 8.0x10^-4C

r = 0.30 m

Substitute the given values in the above expression -

One charge  is + and the other is a -, therefore the net force is an attractive force (opposites atract)

The attraction force is:

F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2

F= 16,000N

The force between the two charges will be 16,000 N.It is the force exerted by one charge on another charge.

The electric force between the two charges is directly propotional to the product of the charge and inversly propotional to the square of the distance between them.

The given data in the problem is;

q₁ is the megnitude of charge 1= - 2.0x10⁻⁴ C

q₂ is the megnitude of charge 2 = + 8.0x10⁻⁴ C

k is the propotionallity constant = 9 x 10⁹ Nm² / C²

r is the seperated distance = 0.30 m

F is the electric force=?

The electric force is found as;

\(\rm F = \frac{K q_14q_2}{r^2} \\\\ \rm F = \frac{9 \times 10^9 \times 2.0 \times 10^{-4}}{(0.30)^2} \\\\ \rm F = 16,000N\)

Hence the force between the two charges will be 16,000 N.

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Answer:

Explanation:

this is my android auto

The initial velocity and constant acceleration of the green car are 44.4 m = 212 m + v_g * t and 76.4 m = 212 m + v_g * t respectively.

Let's denote the initial velocity of the green car as v_g and its constant acceleration as a_g. We know that the red car has a constant velocity of 20.0 km/h, which is equivalent to 5.56 m/s.

Using the formula for the position with constant velocity:

x = \(x_0\) + v * t

Where x is the position, \(x_0\) is the initial position, v is the velocity, and t is the time, we can calculate the time it takes for the cars to pass each other in both scenarios.

For the first scenario, when the red car passes the green car at x = 44.4 m, the green car's position can be expressed as:

x_g = 212 m + v_g * t

Substituting the values, we have:

44.4 m = 212 m + v_g * t

Similarly, for the second scenario when the red car passes the green car at x = 76.4 m, the green car's position can be expressed as:

76.4 m = 212 m + v_g * t

By solving these two equations simultaneously, we can find the initial velocity and constant acceleration of the green car.

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The complete question is:

In the figure here, a red car and a green car move toward each other in adjacent lanes and parallel to an x axis. At time t=0, the red car is at x , r =0 and the green car is at x, g​=212 m. If the red car has a constant velocity of 20.0 km/h, the cars pass each other at x=44.4 m. On the other hand, if the red car has a constant velocity of 40.0 km/h, they pass each other at x=76.4 m. What are (a) the initial velocity and (b) the (constant) acceleration of the green car? Include the signs.

Given the statement:

The further away the galaxy is, the ____________ the shift found by the Hubble.

Let's complete the statement.

According the Hubble's brilliant observation, the shift of the galaxy is directly proportional to the distance of the galaxy from the Earth.

This means that as the distance of the galaxy increases, the shift also increase.

Therefore, the further away a galaxy is, the greater the shift found by the Hubble telescope.

ANSWER:

D. Greater

Answer:

Explanation:

so her displacement is the distance from the start... she's now at a point (6,5) away from the start..  so what's the length of the side of the right triangle made by one side of 6 and the other of 5

Yes.. use Pythagoras theorem to solve this

C =  √(\(6^{2}\)+\(5^{2}\))

C = √(36 + 25)

C = √61

C = 7.810  miles.. north east of where she started

C = 7.8 miles NE   :P

Answer:

51 miles/hour

Explanation:

Talia is on a road trip with some friends. in the first 2 hours, they travel 100 miles. then they hit traffic and go only 30 miles in the next hour. the last hour of their trip, they drive 75 miles. calculate the average speed of talia’s car during the trip. give your answer to the nearest whole number.

The average speed would be 51 miles/hour.

The average speed of a moving object is defined as the total distance traveled relative to the total time taken fro the journey. Mathematically, it is given as:

  total distance traveled/total time taken.

In this case;

Total distance traveled = 100 + 30 + 75 = 205 miles

Total time taken = 2 + 1 + 1 = 4 hours

Therefore;

Average speed = 205/4 = 51.25 miles/hour

To the nearest whole number = 51 miles/hour

In this case, we would mainly choose a spherical Gaussian surface of radius r which is centered on the charge distribution. The electric flux through this surface would then be proportional to the total charge enclosed within the sphere, that is proportional to the electric field at a distance r:

Φ = 4πr²E

where E is the magnitude of the electric field at a distance r.

According to Gauss's law the electric flux through a closed surface is proportional to the charge enclosed within the surface:

Φ = Q / ε0

where Φ is the electric flux, Q is the charge enclosed within the surface, and ε0 is the vacuum permittivity.

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The initial velocity of the car as it slow to rest with an acceleration of -5 m/s² is 11.5 m/s.

This can be defined as the ratio of displacement to the time of a body

To calculate the initial velocity of the car, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the initial velocity of the car is 11.5 m/s

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C.1. The two basic premises for the special theory of relativity are: The laws of nature are the same for everyone and The speed of light is the same for everyone.

The special relativity theory is based on two fundamental tenets: that the light speed should be constant in all inertial frames of reference and that the rules of physics ought to be independent of a uniform motion of such a frame.

The separation of two occurrences in space and time, an object's energy momentum, and of course his speed of light are all examples of absolute dimensions of space and time that Einstein also specified.

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Answer:

Cell theory is the scientific theory that states that all living things are composed of cells and that cells are the basic unit of life. The three principles of cell theory are the cell is the smallest unit of life, all cells come from preexisting cells, and cells are the basic unit of function in living things.

Explanation:

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When an electrically neutral pith ball gains 4.0 * 10^23 electrons, its charge becomes negative, with a magnitude of approximately -1.6 * 10^-5 coulombs.

An electrically neutral object has an equal number of protons and electrons, resulting in a net charge of zero. However, when the pith ball gains electrons, the number of electrons exceeds the number of protons, giving the pith ball a negative charge.

Each electron has a charge of approximately -1.6 * 10^-19 coulombs, and gaining 4.0 * 10^23 electrons means the pith ball's charge will be approximately -6.4 * 10^-3 coulombs. Thus, the charge of the pith ball is q = -6.4 * 10^-3 C.

It's important to note that the charge of an object is quantized, meaning it can only exist in discrete multiples of the elementary charge (-1.6 * 10^-19 C). In this case, the pith ball gained a large number of electrons, resulting in a measurable negative charge.

The magnitude of the charge is determined by the number of excess electrons, while the negative sign indicates the presence of an excess of electrons compared to protons.

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The radius of curvature of the mirror is 40 cm.

In this case, the mirror produces an inverted image, which means it is a concave mirror. We are given the object distance (u), image distance (v), and magnification (M). The magnification is -2, as the image is twice as tall and inverted. The mirror formula for concave mirrors is:
1/f = 1/u + 1/v
We can find the focal length (f) using the magnification formula:
M = -v/u
By solving for v, we get:
v = -2u
Now, we can substitute this value back into the mirror formula:
1/f = 1/u - 1/(2u)
Since the image is 60 cm from the mirror:
1/f = 1/60 - 1/(2 * 60)
1/f = 1/60 - 1/120
1/f = 2/120 - 1/120
1/f = 1/120
Thus, the focal length (f) is 60 cm / 2 = 30 cm
The radius of curvature (R) is twice the focal length:
R = 2 * f = 2 * 30 = 40 cm

Summary: The radius of curvature of the mirror is 40 cm.

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The paper should be placed at the focal point of the lens to obtain a sharp image.

The focal point of a lens is the point where parallel rays of light converge or diverge after passing through the lens. Placing the paper at this point ensures that the incoming light rays from the object on the other side of the lens converge precisely onto the paper, resulting in a focused and sharp image.

The distance between the lens and the paper should be equal to the focal length of the lens. The unit of focal length is typically measured in millimeters (mm) or meters (m), depending on the scale of the lens. Therefore, the paper should be positioned at the focal point of the lens to achieve a sharp image, with the distance measured in units of length such as millimeters or meters.

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Answer:

distance between two points having phase difference 5.6 rad is

Φ = 2.33 m

Explanation:

given

frequency, f = 130Hz

speed of sound in air, v = 340m/s

distance between two crust or through with phase difference 2\(\pi\) = λ (wavelength)

phase difference = 5.6 rad

note: distance between two points having a phase difference = \(\frac{ \lambda }{2\pi }\)

∴ distance between two points having phase difference of 5.6 rad is = \(\frac{ \lambda }{2\pi }\) ×5.6

Recall

v = f × λ

speed = frequency × wavelength

wavelength = speed/frequency

λ  = v/f

λ  = 340/130 = 2.615 m

∴ distance between two points having phase difference 5.6 rad is = \(\frac{ 2.615 }{2\pi }\) ×5.6 = 2.33 m