A ski jumper starts from rest 45.0 m above the ground on a frictionless track and flies off the track at an angle of 45.0° above the horizontal and at a height of 15.0 m above the ground. Neglect air resistance.
(a) What is her speed when she leaves the track?
m/s

(b) What is the maximum altitude she attains after leaving the track?
m

(c) Where does she land relative to the end of the track?
m

Answers

Answer 1

The speed of the ski jumper when she leaves the track would be 24.2 m/s.

The maximum altitude she attains after leaving the track is 24.8 m.

The ski jumper will land approximately 59.5 m relative to the end of the track.

How to find the speed, maximum altitude and distance ?

To find the ski jumper's speed when she leaves the track, we can use conservation of mechanical energy.

Since mechanical energy is conserved:

PE_initial = KE_final + PE_final

Solving for v:

v = sqrt((2 × (PE_initial - PE_final)) / m)

v = sqrt((2 × (m × g × Δh)) / m)

v = sqrt(2 × g × Δh)

v ≈ sqrt(2 × 9.81 m/s² × 30.0 m)

v ≈ 24.2 m/s

To find the maximum altitude, we can use the vertical component of the velocity (v_y) when she leaves the track.

u_y = 0 (at maximum altitude, vertical velocity is 0)

hf = maximum altitude

h0 = 15.0 m (height when she leaves the track)

0 = (17.1 m/s)^2 - 2 × 9.81 m/s² × (hf - 15.0 m)

hf = (17.1 m/s)^2 / (2 × 9.81 m/s²) + 15.0 m

hf = 24.8 m

To find where she lands relative to the end of the track, we can use the horizontal component of the velocity (v_x) when she leaves the track and the time she spends in the air (t).

To find the time she spends in the air, we can use the following equation:

v_y = u_y + g × t

u_y = 17.1 m/s (initial vertical velocity)

v_y = 0 (at maximum altitude)

0 = 17.1 m/s - 9.81 m/s² × t

t ≈ 1.74 s (time to reach the maximum altitude)

Now we can find the horizontal distance she travels:

Horizontal distance = v_x × total time

Horizontal distance ≈ 17.1 m/s × 3.48 s

Horizontal distance ≈ 59.5 m

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Related Questions

What is the difference between classical mechanics and quantum mechanics?

Answers

Classical mechanics describes the motion of objects on a macroscopic scale, while quantum mechanics deals with the behavior of particles on a microscopic scale. Classical mechanics is deterministic, meaning that it predicts precise outcomes based on initial conditions, while quantum mechanics is probabilistic, providing probabilities of different outcomes. Classical mechanics follows the principle of causality, where every effect has a specific cause, whereas quantum mechanics introduces inherent uncertainty and wave-particle duality. Classical mechanics is well-suited for describing everyday objects, while quantum mechanics is necessary to explain the behavior of particles at the atomic and subatomic levels.

~~~Harsha~~~

the main difference between classical mechanics and quantum mechanics lies in how they describe the behavior of objects.

classical mechanics is the branch of physics that deals with the motion of everyday objects like balls, cars, and planets.

quantum mechanics is a branch of physics that focuses on the behavior of very small particles, such as atoms and subatomic particles like electrons.

Which of the following is a disadvantage of hybridization? 1.offspring are genetic copies of the parent 2.offspring are stronger and larger than the parents 3.offspring have a combination of traits from both parents 4.offspring often have health problems and are sterile​

Answers

Answer:

Explanation:

4 is right

Sam wants to upgrade his toy "golf ball launcher". Right now when he shoots the toy vertically,
the golf ball reaches a height of 1.75 m. A golf ball has a mass of 46 grams and the toy can
hold a spring that can be compressed 24 cm. Using a different spring, Sam believes he can
increase the distance it can be compressed to 32 cm. What spring constant will Sam need the
new spring to be if he wants it to launch the golf ball vertically to a height of 3.0 m?

Answers

To solve this problem, we can use the conservation of energy. At the maximum height, all of the initial kinetic energy of the golf ball is converted into potential energy.

The initial kinetic energy of the golf ball can be found using:
KE = (1/2)mv^2

where
m = 0.046 kg (mass of golf ball)
v = ? (velocity of golf ball)

The potential energy of the golf ball at its maximum height is:
PE = mgh

where
h = 3.0 m (maximum height of golf ball)

Since the launcher is spring-powered, we can relate the initial kinetic energy to the potential energy using the spring constant and the distance the spring is compressed.

The initial kinetic energy can be found using the work-energy theorem:
W = KE

where
W = Fd (work done by the spring)
F = kx (force exerted by the spring)
x = 0.24 m (distance the spring can be compressed with the old spring)
k = ? (spring constant of new spring)

Substituting in the values, we get:
KE = (1/2)mv^2 = Fd = kx^2/2

Solving for k, we get:
k = (mv^2)/(x^2)

Now we can substitute in the values and solve for k:
k = (0.046 kg)(9.81 m/s^2)(1.75 m)/(0.24 m)^2 = 13.6 N/m

Therefore, Sam will need the new spring to have a spring constant of 33.7 N/m to launch the golf ball vertically to a height of 3.0 m.

a science fiction movie was shown to students of class xi in the movie two aliens XIGO and LIGO came on earth from two different planets XIGO weighs 245N while LIGO weighs 39N on earth however on their own planets XIGO weighs 49N and LIGO weighs 196N, From the information what can you conclude about g on their own weigh

Answers

The g on the weight of the two aliens XIGO and LIGO varies as they move from Earth to their planet

How do determine the nature of the acceleration due to gravity, g?

To know th nature of the acceleration due to gravity, g, we shall determine the g of the allies in their respective planets. Details below:

First we shall obtain the mass of each alien.

For alien XIGO on earth:

Acceleration due to gravity (g) = 10 m/s² Weight (W) = 245 NMass of XIGO (m) = ?

Weight (W) = mass (m) × Acceleration due to gravity (g)

245 = m × 10

Divide both sides by 10

Mass = 250 / 10

Mass of XIGO = 25 Kg

For alien LIGO on earth:

Acceleration due to gravity (g) = 10 m/s² Weight (W) = 39 NMass of LIGO (m) = ?

Weight (W) = mass (m) × Acceleration due to gravity (g)

39 = m × 10

Divide both sides by 10

Mass = 39 / 10

Mass of XIGO = 3.9 Kg

Now, we shall determine the g on their planet

For alien XIGO on its planent:

Weight (W) = 49 NMass of XIGO (m) = 25 KgAcceleration due to gravity (g) = ?

Weight (W) = mass (m) × Acceleration due to gravity (g)

49 = 25 × g

Divide both sides by 25

g = 49 / 25

g = 1.96 m/s²

For alien LIGO on its planent:

Weight (W) = 196 NMass of XIGO (m) = 3.9 KgAcceleration due to gravity (g) = ?

Weight (W) = mass (m) × Acceleration due to gravity (g)

196 = 3.9 × g

Divide both sides by 3.9

g = 196 / 3.9

g = 50.25 m/s²

From the above calculation, we can see that the g on the weighs of both aliens varies as they move from Earth to their planet.

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A 40kg mass is pulled along a surface by a horizontal force of 300N. Friction on the mass is 30N. What is the acceleration of the mass???

Answers

Answer:

6.75 m/s²

Explanation:

The following data were obtained from the question:

Mass (m) of object = 40 Kg

Force applied (Fₐ) = 300 N

Force of friction (Fբ) = 30 N

Acceleration (a) =?

Next, we shall determine the net force acting on the mass. This can be obtained as follow:

Force applied (Fₐ) = 300 N

Force of friction (Fբ) = 30 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fբ

Fₙ = 300 – 30

Fₙ = 270 N

Thus, the net force acting on the mass is 270 N.

Finally, we shall determine acceleration of the mass. This can be obtained as follow:

Mass (m) of object = 40 Kg

Net force (Fₙ) = 270 N

Acceleration (a) =?

Net force = mass × acceleration

Fₙ = m × a

270 = 40 × a

Divide both side by 40

a = 270 / 40

a = 6.75 m/s²

Therefore, the acceleration of the mass is 6.75 m/s²

A 1.70 m tall woman stands 5.00 m in front of a camera with a 50.00 cm focal
length lens. Calculate the size of the image formed on flim​

Answers

Answer:

18.89cm

Explanation:

As we know that the person is standing 5m in front of the camera

\(d_0=5m=500cm\)

The focal length of the lens =50cm

f=50 cm

By Lens formula we have:

\(\dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}\\\dfrac{1}{50} = \dfrac{1}{d_i} + \dfrac{1}{500}\\\dfrac{1}{d_i} =\dfrac{1}{50}-\dfrac{1}{500}\\\dfrac{1}{d_i}=0.018\\d_i=55.56cm\)

By the formula of magnification

\(\dfrac{h_i}{h_o} = \dfrac{55.56}{500}\\\\h_i = \dfrac{55.56}{500} \times h_o\\\\ h_o=1.70m=170cm\\\\Therefore: h_i=\dfrac{55.56}{500} \times$ 170 cm\\\\h_i =18.89 cm\)

The height of the image formed is 18.89cm.

List the 6 questions you may apply to formulating a logical, reasonable perspective to any situation.

Answers

Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust

What are the 6 questions that may be applied to formulate logical, reasonable perspective to any situation?

Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:

What are the issues that should be addressed?

What are the relevant facts and data related to this problem or issue?

What assumptions am I making about the problem or issue?

What are the possible solutions or outcomes, and what are the pros and cons of each?

What are my values and priorities related to this problem or issue?

What additional information do I need to make an informed decision or come to a reasonable conclusion?

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Pls help and explain how to get the answer

Pls help and explain how to get the answer

Answers

(a) The magnitude of the gravitational force on the rock is 64.68 N and on the pebble is 5.488 x 10⁻³ N.

(b) The acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².

What is the gravitational force exerted on each object?

The gravitational force exerted on each object is calculated by applying Newton's law of universal gravitation as follows;

Fg = Gm₁m₂ / R²

where;

G is universal gravitation constantm₁ is the mass of the rockm₂ is the mass of pebble

The acceleration of each object will be constant and equal to acceleration due to gravity, the force on each object is calculated by using Newton's second law of motion.

Force on the rock;

F = mg

where;

g is acceleration due to gravity

F = 6.6 kg x 9.8 m/s²

F = 64.68 N

The force on the pebble;

F = mg

F = 5.6 x 10⁻⁴  x 9.8

F = 5.488 x 10⁻³ N

Thus, the acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².

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3.) A boat is moving south at 15.0, a passenger is walking north along the boat deck at 4.0 and throws a
rock north at 3.0, what is the velocity of the rock when viewed from the boat and the shore? (2)

Answers

When viewed from the boat, the velocity of the rock will be equal to the sum of the velocity of the rock relative to the passenger (3.0 m/s north) and the velocity of the passenger relative to the boat (4.0 m/s south).

Therefore, the velocity of the rock when viewed from the boat will be:

Vrock (boat) = Vrock (passenger) + Vpassenger (boat)

Vrock (boat) = 3.0 m/s north + (-4.0 m/s south)

Vrock (boat) = -1.0 m/s south

So, when viewed from the boat, the velocity of the rock will be 1.0 m/s south.

When viewed from the shore, the velocity of the rock will be equal to the velocity of the boat relative to the shore (15.0 m/s south) plus the velocity of the rock relative to the boat (which we calculated as -1.0 m/s south).

Therefore, the velocity of the rock when viewed from the shore will be:

Vrock (shore) = Vrock (boat) + Vboat (shore)

Vrock (shore) = -1.0 m/s south + (-15.0 m/s south)

Vrock (shore) = -16.0 m/s south

So, when viewed from the shore, the velocity of the rock will be 16.0 m/s south.

When does your body conduct current more readily?

when it is hot
when it is dry
when it is cold
when it is wet

Answers

Wetness increases conductivity

Answer:

When you are wet or you are sweating current passes easily.

Explanation:

wetness increases conductivity. therefore 'when it is wet'.

Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.

Answers

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

How do i determine the quantity of heat energy?

First, we shall list out the given parameters from the question. This is shown below:

Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Which of these changes will decrease the acceleration of an object? Select the two correct answers

increasing the applied net force

decreasing its mass

increasing its mass

decreasing the applied net force​

Answers

Answer:

✔️From Newton's second law of motion we know that

✔️acceleration is inversely proportional to the mass of the body

✔️Here in this question increasing the mass of body will decrease its acceleration.

Explanation:

Hope it will help you :)

Which can be excluded due to the absence of fossil records?(1 point)
Responses



a dinosaur's backbone

b. the shell of a snail

c. the shell of a crab

d.the body of a jellyfish

Answers

The body of a jellyfish can be  excluded due to the absence of fossil records and is denoted as option D.

What is a Fossil?

This is referred to as the remains of plants and animals which have been preserved in the earth crust and it is important as it helps to give more information about life history of different organisms.

Examples of fossils include bones, shells etc as they are the parts of the organism which are preserved and not doesn't decay. The body of a jellyfish will decay and not form a fossilized structure which is therefore the reason why option D was chosen.

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Marisol drives north at 64.3 km/h. How far does Marisol travel after 5.8 h?

Answers

Answer:

372.94 km

d= st

= (64.3 km/h)(5.8h)

=372.94 km

Answer: 372.94

Explanation: it’s correct❤️

What is the answer to this problem

What is the answer to this problem

Answers

Answer:

Material that allow the electrons to move freely in order to produce a current

Please mark as brainliest if answer is right

Have a great day, be safe and healthy  

Thank u  

XD  

material that allow the electrons to move, it is B

PLEASE HELP!
A Cadillac Escalade car and a Mini Cooper car are both making a sharp right turn. The Escalade is four times more massive than the Mini Cooper. If both cars make the turn with the same constant speed, how do the centripetal forces acting on the two cars compare? Hint: use the Fc equation to consider how increasing the mass will affect the force.
The centripetal force cannot be determined without more information.
The centripetal force on the Mini Cooper is four times greater than that of the Cadillac Escalade.
The centripetal force on the Cadillac Escalade is four times greater than that of the Mini Cooper.
The centripetal force is the same for both cars.

Answers

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which statements describe the Gironde ecosystem

Answers

Answer:

Gironde Ecosystem is an important biological and cultural area.

Explanation:

What is the correct answer option for question 14?

What is the correct answer option for question 14?

Answers

Based on the information provided in the second paragraph of "On a Mountain Trail," the correct option would be "The pack surrounding the sleigh is a very real threat to the two men on the trail." The correct option is C.

In the second paragraph, it is mentioned that the wolves had stopped running and were now "moving at a dogtrot, leisurely and methodically encircling the sleigh." This description implies that the wolves are actively surrounding the sleigh, which suggests a potential threat to the two men on the trail. The word "encircling" indicates a deliberate and coordinated action by the wolves, which implies predatory behavior.

Now let's examine why the other options are not true:

A. The surrounding pack should not be concerning to the two men.

This option is not true because the description in the paragraph clearly implies that the pack of wolves surrounding the sleigh is a cause for concern.

B. The wolves will eventually tire and will return to the safety of the underbrush.

This option is not supported by the information provided in the paragraph. There is no mention of the wolves becoming tired or retreating to the safety of the underbrush. The description implies that the wolves are actively encircling the sleigh, indicating an ongoing threat.

D. Once a sleigh is surrounded by a pack of wolves, there is no chance for human survival.

This option is an extreme statement and goes beyond the information provided in the paragraph. The paragraph does not provide any conclusive information about the chances of human survival in such a situation. It simply describes the current state of the wolves surrounding the sleigh, but it does not make a definitive statement about the outcome for the two men.

Therefore, The correct option is C.

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If the rock is kicked at initial velocity of 12 m/s from a height of 106 m above the ground what horizontal distance does the rock travel before striking the ground?

If the rock is kicked at initial velocity of 12 m/s from a height of 106 m above the ground what horizontal

Answers

Answer:

74 m.

Explanation:

From the question given above, the following data were obtained:

Height (h) = 186 m

Initial velocity (u) = 12 m/s

Horizontal distance (d) =?

Next, we shall determine the time taken for the rock to get to the ground. This can be obtained as follow:

Height (h) = 186 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

H = ½gt²

186 = ½ × 9.8 × t²

186 = 4.9 × t²

Divide both side by 4.9

t² = 186/4.9

Take the square root of both side

t = √(186/4.9)

t = 6.16 s

Thus, the time taken for the rock to get to the ground is 6.16 s

Finally, we shall determine the horizontal distance travelled by the rock as follow:

Initial velocity (u) = 12 m/s

Time (t) = 6.16 s

Horizontal distance (d) =?

Horizontal distance (d) = Initial velocity (u) × Time (t)

d = u × t

d = 12 × 6.16

d = 73.92 ≈ 74 m

Therefore, the horizontal distance travelled by the rock is 74 m

On a warm summer day, a large mass of air (atmospheric pressure 1.01×105Pa) is heated by the ground to a temperature of 25.0 ∘C and then begins to rise through the cooler surrounding air. Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×104 Pa. Assume that air is an ideal gas, with γ=1.40. (This rate of cooling for dry, rising air, corresponding to roughly 1 ∘C per 100 m of altitude, is called the dry adiabatic lapse rate.)

Answers

The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.

Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:

(1.01×10⁵ Pa)×V = (nR/T1)×T1(8.70×10⁴ Pa)×V = (nR/T2)×T2

Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:

(T2/T1) = [(P2/P1)^(γ-1)/γ] = [(8.70×10⁴ Pa)/(1.01×10⁵ Pa)]^(1.4/1.4) = 0.813

Solving for T2, we get:

T2 = T1×(P2/P1)^(γ-1)/γ = (25+273) K×0.813 ≈ 287.3 K ≈ 14.3°C

Thus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

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1. A força de atração eletrostática é responsável pela união dos íons, onde cargas elétricas de sinais opostos se atraem. Falando a um nível microscópico, tal atração entre os íons acaba produzindo aglomerados com formas geométricas bem definidas, representados pela figura a seguir: Qual a melhor definição para essa estrutura iônica e que composto é formado a partir dela? * 1 ponto cristais de sal / cloreto de potássio. cristal com face plana / cloreto de cálcio. retículo cristalino / cloreto de sódio. retículo de ligações / clorato de sódio.

Answers

Answer:

estrutura cristalina / cloreto de sódio

Explicação:

O cloreto de sódio forma a estrutura cristalina da treliça. Nesta estrutura, um átomo de sódio é cercado por 6 íons de carga oposta. Os íons opostos são negativos porque o sódio perde elétrons, o que o torna ião carregado positivamente chamado cátion, de modo que 6 íons negativos estão presentes ao redor do sódio. A estrutura cristalina também é conhecida como cúbico simples, o que significa que eles são distribuídos em três dimensões com igual distância entre eles e formando um ângulo de 90 graus.

A gun is fired with muzzle velocity 1114 feet per second at a target 4950 feet away. Find the minimum angle of elevation necessary to hit the target. Assume the initial height of the bullet is 0 feet, neglect air resistance, and give your answer in degrees.

Answers

Answer:

The elevation angle is  \(\theta = 3.67^o\)

Explanation:

From the question we are told that

   The velocity is  \(u = 1114\ ft/s\)

    The range of the bullet projection is   \(R = 4950 \ ft\)

     The initial height of bullet is  \(h_1 = 0 \ ft\)

Range of this bullet projection is mathematically represented as

          \(R = \frac{u^2 sin (2 \theta )}{g}\)

=>      \(\theta = \frac{sin ^{-1} [\frac{R * g }{ u^2} ]}{2}\)

Here  \(g = 32 ft/s^2\)

substituting values

         \(\theta = \frac{sin ^{-1} [\frac{4950 * 32 }{ 1114^2} ]}{2}\)

        \(\theta = 3.67^o\)

 

The rod shown below moves to the right on essentially
zero-resistance rails at a speed of v = 3.0 m/s. If
B = 0.75 T everywhere in the region, what is the current
through the 5.0-Ω resistor? Does the current circulate
clockwise or counterclockwise?

Answers

The required, current 0.018 A circulates counterclockwise through the 5.0-Ω resistor. Option B is correct.

The induced emf causes a current to flow through the loop (the rod and the 5.0-Ω resistor). Since the resistance (R) of the resistor is given as 5.0 Ω, we can find the current (I) through the resistor:
I =E/R

Substitute the value of the induced emf:
I = -[Bwv]/R

Substitute the value in the above equation:
I = -[0.75*4/100*3]/5
I = 0.018 A counterclockwise direction

Thus, the required, current 0.018 A circulates counterclockwise through the 5.0-Ω resistor. Option B is correct.

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Curran is testing out a newly waxed hallway floor by sliding in his socks.
He runs from one end of the hallway and starts sliding midway going all
the way to the right. The forces acting on Curran as he is sliding are
represented in the diagram below. Identify the forces and match them
correctly to the numbers.

Curran is testing out a newly waxed hallway floor by sliding in his socks.He runs from one end of the

Answers

Answer:

Curran is testing out a newly waxed hallway floor by sliding in his socks.

He runs from one end of the hallway and starts sliding midway going all

the way to the right. The forces acting on Curran as he is sliding are

represented in the diagram below. Identify the forces and match them

correctly to the n

pls help need it last question on my test

pls help need it last question on my test

Answers

The force that results in the decrease in speed from the midpoint to the end of the track is friction. The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.

The force that would cause the Hot Wheels car to slow down from the midpoint of the track to the end of the track is friction between the car's wheels and the track.

Friction is a force that opposes motion between two surfaces in contact.

In this case, the wheels of the car and the surface of the track are in contact, and the friction force acts in the opposite direction of the car's motion, which slows it down.

As the Hot Wheels car travels down Track #2 during the Speed Lab activity, its initial velocity decreases due to friction.

Friction is a resistance force that opposes motion.

It is caused by the interaction between the surfaces in contact. In this case, the surface of the track and the wheels of the car are in contact.

When the car is moving, there is friction between the two surfaces.

The direction of the friction force is opposite to the direction of motion of the car.

This means that the friction force slows the car down.

In conclusion, the force that results in the decrease in speed from the midpoint to the end of the track is friction.

The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.

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Compare sound and earthquake waves

Answers

When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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Water molecules move the slowest at
which temperature?
A. 0°C
B.
32°C
C. 100°C
D. 212°C

Answers

Answer:

Water molecules move slowest at 0 degrees C, so the answer is A.

Explanation:

The colder the molecules, the less energy they have. Thermal energy is the measurement of how fast the molecules are moving, so the less energy, the less speed. So the answer will be the temperature that is the lowest.

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The following is an example of what type of reaction?

The following is an example of what type of reaction?

Answers

Answer:

Single Displacement Reaction

Explanation:

Here, only one element is getting replaced during the reaction, that is, silver gets replaced by copper, hence, single displacement reaction.

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Suppose you have a Frisbee with a mass of 0.10 kg. You first throw it with a force of 5N and then change the force you throw it at to 20N. As your force increases, what is happening to the acceleration of your Frisbee?

Answers

Answer:

The acceleration increases.

Explanation:

From Newton's 2nd Law, we have \(\Sigma F=ma\). We can see that force is directly proportional to mass and acceleration. Therefore, as force increases, either mass or acceleration must increase as well, and vice versa. Since mass is maintained here, if you increase the force applied to the Frisbee, the acceleration will increase as well.

An arrow in a bow has 357 J of elastic potential energy How much Winette enere
Will the arrow have after it has been shot assuming there is no sir restoran

Answers

Answer:

357 J

Explanation:

The elastic potential energy of arrow in the stretched bow is 357 J.

The kinetic energy of the arrow after it has been shot is given by half of the product of the arrow's mass and velocity of the arrow.

Here there are no other forms of energy at play here. Only potential and kinetic energy.

As we know that in any system the energy is conserved accordingly the elastic potential energy of the arrow will be equal to the kinetic energy of the bow after it is released i.e., 357 J.

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