A solution of glucose sugar (C6H₁206) labeled 2.89 ppm. What is the molarity of the solution?​

Answer:

I think it's A or D im not sure which one..

Answer:

C.) Electrons

Explanation:

Answer:

sin  = (330)

csc = (60)

−4 = cot (−45)

Explanation:

im not sure what you were looking for, make me brainlest please?

Answer:approximately 5.627 × 1019 milliliters

Explanation:

From the given graph, if we change from a moderately acidic environment ( pH near 6) to a basic environment, the peroxidase activity will decrease. Therefore, option (A) is correct.

pH can be described as the negative logarithm of hydrogen ion (H⁺) concentration. Mathematically, pH is generally inversely proportional to the concentration of hydrogen ions (H⁺).

pH = -log ([H⁺])

In chemistry, pH is a scale used to determine the acidity or basicity of an aqueous solution. Acidic solutions are calculated to have lower pH values than basic or alkaline solutions.

The pH scale possesses ranges from 0 to 14 while pH 7.0 is neutral. A low pH (about 1 or 2) is acidic and a high pH (12 or 14) is basic.

When we change the moderately acidic environment to a basic environment. We actually increase the pH value in the graph showing the peroxidase activity decreases when pH increases more than 6.

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Answer:

(a) \(V_B=11.68L\)

(b) \(x_{He}=0.533\)

Explanation:

Hello,

In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:

\(n_A=\frac{0.082\frac{atm*L}{mol*K}*298K}{1.974 atm*6.00L}=2.063mol\)

Thus, since the final pressure is 3.60 bar, we can write:

\(P=x_{Ar}P_A+x_{He}P_B\\\\P=\frac{n_{Ar}}{n_{Ar}+n_{He}} P_A+\frac{n_{He}}{n_{Ar}+n_{He}} P_B\\\\3.60bar=\frac{2.063mol}{2.063mol+n_{He}} *2.00bar+\frac{n_{He}}{2.063mol+n_{He}} *5.00bar\)

The moles of helium could be computed via solver as:

\(n_{He}=2.358mol\)

Or algebraically:

\(3.60bar=\frac{1}{2.063mol+n_{He}} *(4.0126+5.00*n_{He})\\\\7.314+3.60n_{He}=4.013+5.00*n_{He}\\\\7.314-4.013=5.00*n_{He}-3.60n_{He}\\\\n_{He}=\frac{3.3}{1.4}=2.358mol\)

In such a way, the volume of the compartment B is:

\(V_B=\frac{n_{He}RT}{P_B}=\frac{2.358mol*0.082\frac{atm*L}{mol*K}*298.15K}{4.935atm}\\ \\V_B=11.68L\)

Finally, he mole fraction of He is:

\(x_{He}=\frac{2.358}{2.358+2.063}\\ \\x_{He}=0.533\)

Regards.

Answer:

copper metal and steel metak

Answer:

Every element to the left of the staircase on the Periodic Table is a metal, excluding Hydrogen, and everything to the right of that staircase is a non-metal.

Explanation:

The net ionic equation for the reaction between potassium sulfide and magnesium iodide is S2- + Mg2+ -> MgS, as the potassium and iodide ions are spectator ions and do not participate in the reaction.

To determine the net ionic equation for the reaction between potassium sulfide (K2S) and magnesium iodide (MgI2), we first need to identify the ions present in each compound and then determine the products formed when they react.

Potassium sulfide (K2S) dissociates into two potassium ions (K+) and one sulfide ion (S2-):

K2S -> 2K+ + S2-

Magnesium iodide (MgI2) dissociates into one magnesium ion (Mg2+) and two iodide ions (I-):

MgI2 -> Mg2+ + 2I-

Now, we need to determine the possible products when these ions combine. Since potassium (K+) has a +1 charge and iodide (I-) has a -1 charge, they can combine to form potassium iodide (KI):

K+ + I- -> KI

Similarly, magnesium (Mg2+) and sulfide (S2-) can combine to form magnesium sulfide (MgS):

Mg2+ + S2- -> MgS

Now, we can write the complete ionic equation by representing all the ions present before and after the reaction:

2K+ + S2- + Mg2+ + 2I- -> 2KI + MgS

To obtain the net ionic equation, we remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are the potassium ions (K+) and the iodide ions (I-).

Thus, the net ionic equation for the reaction between potassium sulfide and magnesium iodide is:

S2- + Mg2+ -> MgS

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Answer:

the molarity of the solution would be 10.0 M if 80.0 grams of NaOH were added to 200 milliliters of water.

Explanation:

To calculate the molarity of a solution, we can use the formula:

Molarity = moles of solute / volume of solution in liters

First, we need to calculate the moles of sodium hydroxide (NaOH) in the given mass:

moles NaOH = mass of NaOH / molar mass of NaOH

The molar mass of NaOH is 40.00 g/mol (the atomic mass of Na is 22.99 g/mol, the atomic mass of O is 15.99 g/mol, and the atomic mass of H is 1.01 g/mol).

For 52 g NaOH:

moles NaOH = 52 g / 40.00 g/mol = 1.30 mol

Now, we can calculate the molarity of the solution:

Molarity = moles NaOH / volume of solution in liters

We don't know the volume of the solution for the first case, so we cannot calculate the molarity.

For the second case, we have 80.0 g NaOH and 200 mL of water. We need to convert the volume to liters:

200 mL = 0.200 L

Now, we can calculate the moles of NaOH:

moles NaOH = 80.0 g / 40.00 g/mol = 2.00 mol

Finally, we can calculate the molarity of the solution:

Molarity = moles NaOH / volume of solution in liters

Molarity = 2.00 mol / 0.200 L

Molarity = 10.0 M

Therefore, the molarity of the solution would be 10.0 M if 80.0 grams of NaOH were added to 200 milliliters of water.

Answer:

D.

Explanation:

When the resistance changes , the distance between the electrodes will get changed to 62.74 cm

The resistance and length formula clearly states that, for a given material, the resistance is precisely related to its length. The resistance value of a material increases with an increase in length. The material's resistance value will drop as its length does as well.

Here it is given that ,

Resistance of solution of CuSO₄ (R₁) = 0.51 ohms,

Distance between electrodes (d₁)= 4.00cm

When resistance changes,

R₂= 8 ohms

We have to calculate d₂,

d₂=?

It is given that ,

Resistance is directly proportional to distance between electrodes,

R∝ d

R₁/R₂= d₁/d₂

0.51/8=4/d₂

d₂= 8×4/0.51

=62.74 cm

So, the distance between the electrodes will be 62.74 cm , it is directly proportional to the resistance, it increases as the resistance increases.

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Answer:

Pressure goes up

Explanation:

The pressure is inversely proportional to the volume.  So when volume is decreased the pressure rises.

The molecules are getting pushed closer together and more collisions occur which will also increase the temperature.

Chemical bonds can come in 3 main types, single bonds, double bonds and triple bonds, the difference is, as the name already suggests, the number of bonds that two atoms are forming, this will impact the strength of the bond and also the proximity of both atoms.

The order of strength will be:

1. Triple bonds, they have more bonds and the atoms are closer

2. Double bonds, in between single and triple, they have one extra pi bond which makes it stronger than single bonds

3. Single bonds, only one bond, which makes it weaker than the previous bonds.

For our question:

Single

Double

Triple

Answer: \(K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}\)

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. Pure solids are assumed to have a concentration of 1.

The given balanced equilibrium reaction is:

 \(CH_3OH(aq)+Cl^-(aq)\rightleftharpoons CH_3Cl(aq)+OH^-(aq)\)

The expression for equilibrium constant for this reaction will be,

\(K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}\)

Thus the equilibrium constant expression for this reaction is \(K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}\)

Answer: -2 because it gains 2 electrons

Explanation:

An ion is considered to be an atom which is formed by gain or loss of electrons.

The ions are classified into two which are called the cation and anion.

The cation is classified as the positive charge formed by loss of electrons.

The anion is classified as the negative charge ion formed by gain of electrons.

On gaining two electrons, the atom would occupy -2 charge.

The synthesis of Ammonia occurs over a catalyst.

Ammonia (NH3) can be synthesized through the Haber-Bosch process, which is a large-scale industrial process used to produce ammonia from nitrogen gas (N2) and hydrogen gas (H2). The process is typically carried out at high pressure (150-450 atm) and high temperature (450-550°C) using an iron-based catalyst. The reaction can be represented by the following equation:

N2 + 3H2 -> 2NH3

In the Haber-Bosch process, nitrogen gas and hydrogen gas are compressed and mixed, then fed into a reactor where they are heated to the desired temperature and pressure. The reaction mixture is then passed over an iron-based catalyst.

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Answer:

A = 65.46 u

Explanation:

Given that,

The composition of zinc is as follows :

Zn-64 = 48.63%

Zn-66 = 27.90%

Zn-67 = 4.10%

Zn-68 = 18.75%

Zn-70 = .62%

We need to find the  average atomic mass of the given element. It can be solved as follows :

\(A=\dfrac{48.63\times 64+27.90\times 66+4.1\times 67+18.75\times 68+0.62\times 70}{100}\\A=65.46\ u\)

So, the average atomic mass of zinc is 65.46 u.

Answer: The answer is 78.0748064. We assume you are converting between grams Calcium Fluoride and mole.

Explanation:  Meeting ID: nine nine two, three eight six seven, zero five eight zero

The correct answer for emperical and molecular formula = C5H14N2 .

3.23 g x (12.011 / 44.0098) = 0.8815 g carbon

1.865 g x (2.016 / 18.0152) = 0.2087 g Hydrogen

1.58 g x (28.014 / 108.009) = 0.4098 g Nitrogen

1.50 g minus (0.8815 + 0.2087 + 0.4098) = 0.

Convert each element's mass to moles.

0.8815 g/12.011 g/mol = 0.0734 mol carbon

0.2087 g 1.008 g/mol = 0.207 mol Hydrogen

0.4098 g 14.007 g/mol = 0.02926 mol Nitrogen

Step three is to calculate the ratio of molar amounts expressed in the smallest, whole numbers.

0.0734 mol 0.02926 mol = 2.51 carbon

7.07 mol hydrogen = 0.207 mol 0.02926 mol

Nitrogen: 0.02926 mol = 1 Nitrogen: 0.02926 mol = 1

Doubling each value yields C = 5, H = 14.14, and N = 2, resulting in the empirical formula C5H14N2. 

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Answer:

A

Explanation: n = m/M = 38,72/ (M{CO2}) = 38,72 / 44

There are 0.88 moles of CO₂ in 38.72 gram sample of the compound.

The mole is a unit for measuring the amount of a substance.

1 mol equals the number of particles in 12.0 g of carbon-12.

mol is the abbreviation used for mole.

It is given in the question 38.72 gram of CO₂ is present in the sample

Moles of CO₂ has to be calculated

1 mole = molar mass of a compound

Molar mass of CO₂ is 44g

44 gram of CO₂ makes 1 mole

So 38.72 gram will make 38.72*1 / 44

= 0.88 moles

Therefore ,There are 0.88 moles of CO₂ in 38.72 gram sample of the compound.

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The capacity of a phosphorus atom to create double bonds with other elements like oxygen, nitrogen, and sulfur is further hampered by its size.

Four phosphorus atoms are joined by covalent bonds to form a closed ring structure in white phosphorus molecules. This shape results in a low bond angle, which causes strain inside the molecule and accounts for its extraordinarily reactive properties.

The periodic table's group V elements include nitrogen and phosphorus. Due to their comparable outermost shell electrons, they have several shared characteristics, particularly when forming compounds. Both feature an electron configuration with a ns2 np3 valence shell. Our bodies contain the fourth greatest amount of nitrogen.

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complexes can be classified based on number of unpaired electron as follows square planar strong field: 2 unpaired electrons, octahedral weak field: 4 unpaired electrons, tetrahedral strong field: 2 unpaired electrons, octahedral strong field: 0 unpaired electrons, tetrahedral weak field: 4 unpaired electrons, square planar weak field: 4 unpaired electrons.

In a coordination complex, the number of unpaired electrons in the metal ion depends on the strength of the ligand field and the orientation of the ligands. Strong field ligands have a higher affinity for the d orbitals and can more effectively stabilize them, leading to a lower number of unpaired electrons in the metal ion.

Weak field ligands have a lower affinity for the d orbitals and do not stabilize them as effectively, leading to a higher number of unpaired electrons in the metal ion. The number of unpaired electrons also depends on the orientation of the ligands, with an octahedron (6 ligands) and a tetrahedron (4 ligands) leading to different numbers of unpaired electrons.

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Answer:

. A sample of hydrogen has a volume of 65.0 mL at a pressure of 0.992 atm and a temperature of 16°c. What volume will the hydrogen occupy at 0.984 atm and 25°c? 2. A sample of nitrogen collected in the laboratory occupies a volume of 725 mL at a pressure of 0.971 atm. What volume will the gas occupy at a pressure of 1.40 atm, assuming the ...

Explanation:

We can compute the number of moles of oxygen created in the process using the supplied equation. We know that two moles of water (2H2O) and one mole of oxygen (O2) are created for every two moles of hydrogen peroxide (2H2O2) consumed.

Given that the number of moles of hydrogen peroxide (2H2O2) is 0.2 mol, the number of moles of oxygen created may be calculated as follows: 0.1 mol O2 = 0.2 mol x (1 mol O2/2 mol 2H2O2).

As a result, the amount of oxygen created in the reaction 2H2O2(aq) 2H2O(l) + O2(g) is 0.1 mol. The correct response to the question is 0.1  Mole in total.

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Answer:

Calculate the frequency of light having wavelength of 456 nm.

1.22*10^8nm

Explanation:

In the given question, \(6.58 \times 10^{14}\) Hz is the frequency of the light with a wavelength of 456 nm.

Frequency is a measure of the number of cycles of a periodic wave that occur per unit of time.

The frequency of light can be calculated using the following equation:

frequency = speed of light / wavelength

where the speed of light is a constant equal to \(\rm 3 \times 10^8 \ m/s\).

To use this equation, we need to convert the wavelength from nanometers to meters:

456 nm = \(\rm 456 \times 10^{-9}\ m\)

Now, we can substitute the values into the equation:

frequency =  \(\rm 3 \times 10^8 \ m/s\) / \(\rm 456 \times 10^{-9}\ m\)

=  \(6.58 \times 10^{14}\) Hz

Therefore, the frequency of light with a wavelength of 456 nm is  \(6.58 \times 10^{14}\) Hz.

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Answer:

Genes are segments of deoxyribonucleic acid (DNA) that contain the code for a specific protein that functions in one or more types of cells in the body.

Chromosomes are structures within cells that contain a person's genes. A trait is any gene-determined characteristics and is often determined by more than one gene.

for study island:

A single trait can be controlled by multiple genes.

A single gene can influence multiple traits.

If 128g of a certain gas in a container with a volume of 21.5 L has a pressure of 140 kPa and a temperature of 45°C, the molar mass of the gas is 112 g/mol

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as

                                        PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

Given,

Volume = 21.5L

Pressure = 140 kPa

Temperature = 318 K

Using ideal gas equation, PV = nRT

                            140 × 21.5 = n × 8.314 × 318

                                      n = 1.138 moles

Mass = moles × molar mass

Molar mass = 128 ÷ 1.138

= 112 g/mol

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Answer:

2.25 moles ≈ 2.3 moles

Explanation:

Full Question:

Acetylene C2H2 gas is often used in welding torches because of the very high heat produced when it reacts with oxygen O2 gas, producing carbon dioxide gas and water vapor. Calculate the moles of oxygen needed to produce 1.5mol of water. Be sure your answer has a unit symbol, if necessary, and round it to significant digits.

First off, let's put the equation of the reaction sown;

C2H2 + O2 → H2O + CO2

Upon balancing, we have;

2C2H2 + 3O2 → 2H2O + 4CO2

So from the equation;

3 mole of oxygen is required in order to produce 2 mole of water vapour.

The question asks to calculate moles of oxygen needed to produce 1.5mol of water

This leads us to;

3 moles = 2 moles

x moles = 1.5 moles

x = ( 1.5 * 3 ) / 2

x = 4.5 / 2 = 2.25 moles ≈ 2.3 moles

Answer:

The final temperature of the water when measuring the food sample is: The temperature of the water when the food sample has finished burning completely.

Explanation:

When measuring the food sample in energy and specific heat lab, it is pertinent to note that there is an initial temperature and even while still burning, the temperature gradually increases. But since we are dealing with final, temperature, what we need is basically the final temperature of the water when the food has finished burning. This is so because that's the final temperature of the water as once the food sample has finished burning and you turn off the heat source, the temperature will start to gradually reduce from then on.