A stretched string vibrates with a fundamental frequency of 200 Hz. What is the frequency of the second overtone?

Answer:

B. False

A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point.

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~Brainiliest?~

Answer:

The boiling point of nitrogen on the absolute temperature scale is 77.15 K

Explanation:

Temperature in Kelvin(Absolute temperature) = Temperature in Celcius + 273.15.

Answer:

a pandemic?

Explanation:

i dont know if there is like a A answer and it can kill lot of people

Answer: 6kg

Explanation:

Answer:

Explanation:

W = Fd = 310(210) = 65,100 J

W = KE = ½mv²

v = √(2KE/m) = √(2(65100)/132) = 31.40642... = 31.4 m/s

W = PE = mgh = mgdsinθ

d = W/mgsinθ = 65100/(132(9.81)sin23) = 128.66488... = 129 m

Answer:

a. WD = 65100 J

b. v = 31.4 m/s

c. 129 m

Explanation:

WD = work done (Nm or J)

F = force (N) = 310

d = distance (m) = 210

P = power (W or J/s)

m = mass (kg) = 132

a = acceleration (m/s²)

v = final velocity (m/s)

u = initial velocity (m/s)

s = displacement (m) = 210

\(d_{i}\) = distance up incline (m)

Θ = angle of incline (°) = 23

g = gravity (m/s²) = 9.81

O = opposite

H = hypotenuse

Formulas:

WD = F.d

F (or net F) = ma

v² = u² + 2as

sin(Θ) = O/H

a.

WD = F.d

WD = 310 × 210

WD = 65100 J

b.

Ignoring friction and air resistance:

net F = 310

F = ma:

310 = 132a

a = 2.34848485

v² = u² + 2as:

v² = (0)² + 2(2.348...)(210)

v² = 986.363637

v = 31.4064267 → 31.4 m/s

c.

Coasting means no cycling by cyclist so no F produced up the incline

On incline:

F parallel to incline due to gravity = -132g.sin(23)

F parallel to incline due to gravity = -132(9.81)(0.390731128)

F parallel to incline due to gravity = -505.965552

F = ma:

net F parallel to incline = -505.965552

\(-505.965552 = 132a_{i}\)

\(a_{i} = -3.83307236\)

\((v_{i}) ^{2} = (u_{i})^{2} + 2(a_{i})(d_{i}):\)

\(u_{i} = 31.4064267\)

\(v_{i} = 0\)

\((0)^{2} = (31.4064267)^{2} + 2(-3.83307236)(d_{i}) \\\\ 0 = 986.363638 - 7.66614472(d_{i}) \\\\ 7.66614472(d_{i}) = 986.363638 \\\\ d_{i} = \frac{986.363638}{7.66614472} \\\\ d_{i} = 128.664886\) → 129 m

Answer:

1) B. The use of heat to kill any microorganisms living in a substance

2) B. Burning coal to produce electricity

3) A. Because he misinterpreted the Burgess Shale fossil data

For the space station's rotation to have an effect comparable to gravity on the surface of the planet, it needs to rotate at a speed of around 241.6 m/s.

The station's orbital inclination is 51.6 degrees, moving it from west to east. Depending on the precise height of the ISS, each orbit lasts 90–93 minutes. During that moment, a portion of the Earth is visible in the dark and a portion in the light.

A = v2/r, where an is the centripetal acceleration, v is the linear velocity, and r is the radius of rotation, can be used to compute the centripetal acceleration.

The radius of rotation in this situation is equal to half the diameter, or r = 0.55 km = 550 m.

To solve for v, we obtain:

\(v = √(a*r) = √(9.81 m/s² * 550 m) = 241.6 m/s\)

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Answer:

Explanation:

Volume of bottle filled = 2/3 x π R²h , R = radius = 2.5cm  , h = height = 6 cm

= 2/3 x 3.14 x 2.5² x 6 = 78.5 cm³

volume of one squirt =  π R² x .025 = 3.14 x 2.5² x .025 = .49 cm³

No of squirt required = 78.5 / .49 = 160.2 = 160

b )

mass of extract  = volume x density = 78.5 x 1.135 = 89 gm

c ) mass of one squirt = volume of one squirt x density = .49 x 1.135 = .57 gm

Answer:

Explanation:

according to the graph at B the potential energy of the particle is 2J

therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.

\(E_{k} =1/2mv^{2}\)

2J= 1/2*1/2kg*v^2

8=v^2

v= 2√2 ms-1

Answer:

Both kinetic energies are equal

Explanation:

Kinetic Energy

Is the type of energy of an object due to its state of motion. It's proportional to the mass and the square of the speed.

The equation for the kinetic energy is:

\(\displaystyle K=\frac{1}{2}mv^2\)

Where:

m = mass of the object

v = speed of the object

The kinetic energy is expressed in Joules (J)

There are two cars:

Car (A) with mass ma=500 kg and speed va= 2 m/s

Car (B) with mass mb=20,000 gr and speed vb= 10 m/s

Calculate the kinetic energy of both cars:

\(\displaystyle K_a=\frac{1}{2}m_av_a^2\)

\(\displaystyle K_a=\frac{1}{2}500*2^2\)

\(\displaystyle K_a=250*4=1,000 J\)

To calculate the Kb, the mass must be expressed in kg:

mb=20,000/1,000 =20 Kg

\(\displaystyle K_b=\frac{1}{2}m_bv_b^2\)

\(\displaystyle K_b=\frac{1}{2}20*10^2\)

\(\displaystyle K_b=10*100=1,000 J\)

Both kinetic energies are equal

The calculated kinetic energy values of the cars are the same. The kinetic energy is 1000 J for each of the cars.

Then, we can conclude that, car (A) with mass 500 kg and velocity of 2 m/s has the same kinetic energy as a car (B) with mass of 20000 g and velocity of 10 m/s.

Kinetic energy can be calculated using the formula

\(K.E = \frac{1}{2} mv^{2}\)

Where K.E is the kinetic energy

m is the mass

and v is the velocity

m = 500 kg

and v = 2 m/s

Then,

\(K.E_{(A)} = \frac{1}{2} \times 500 \times 2^{2}\)

\(K.E_{(A)} = \frac{1}{2} \times 500 \times4\)

\(K.E_{(A)} = 1000 \ J\)

m = 20000 g = 20 kg

v = 10 m/s

Then,

\(K.E_{(B)} = \frac{1}{2} \times 20 \times 10^{2}\)

\(K.E_{(B)} = \frac{1}{2} \times 20 \times 100\)

\(K.E_{(B)} =1000 \ J\)

From above, we can observe that the calculated kinetic energy values of the cars are the same.

Hence, car (A) with mass 500 kg and velocity of 2 m/s has the same kinetic energy as a car (B) with mass of 20000 g and velocity of 10 m/s.

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The speed of the bowling ball after the collision is 4 m/s.

The momentum is defined as the product of the mass and the velocity of the body.

We can use the law of conservation of momentum to solve this problem, which states that the total momentum of a system remains constant in the absence of external forces. The initial momentum of the system (bowling ball + bowling pin) is:

pi= m₁v₁ + m₂ v₂

= 10 kg x 10 m/s + 3 kg x 0 m/s

= 100 kg m/s

where m₁ is the mass of the bowling ball, v₁l is its velocity before the collision, m₂ is the mass of the bowling pin, and v'₂ is its velocity before the collision (which is zero since it's at rest).

After the collision, the momentum of the system is:

pf = m₁v'₁ + m₂  v'₂

Where v'₁  is the velocity of the bowling ball after the collision, and v'₂ is the velocity of the bowling pin after the collision.

Since momentum is conserved, we have:

pi= pf

Substituting the values we know, we get:

100 kg m/s = 10 kg x  v'₁ + 3 kg x 12 m/s

Solving for v'₁, we get:

v'₁ = (100 kg m/s - 3 kg * 12 m/s) / 10 kg

v'₁ = 4 m/s

Therefore, the speed of the bowling ball after the collision is 4 m/s.

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The net electric force on particle q₂ is determined as -9.86 N.

The net force of particle q₂ is determined by applying Coulomb's law of electrostatic force.

The electric force between particle q₁ and q₂ is the repulsive force and the magnitude is calculated as;

F₁₂ = kq₁q₂ / r²

where;

F₁₂ = -(9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶) / (0.25²)

F₁₂ = -14.4 N

The electric force between particle q₃ and q₂ is the attractive force and the magnitude is calculated as;

F₂₃ = kq₃q₂ / r²

F₂₃ = (9 x 10⁹ x 5.9 x 10⁻⁶ x 7.7 x 10⁻⁶) / (0.3²)

F₂₃ = + 4.54 N

The net force on the particle q₂ is calculated as;

F (net) = F₁₂ + F₂₃

F (net) = -14.4 + 4.54

F (net) = -9.86 N

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Answer:

x = 6.05 cm

Explanation:

Given that,

Force acting on the spring, F = 4.3 N

The spring constant of the spring, k = 71 N/m

We need to find the compression distance. The force acting on the spring is given by :

\(F=kx\)

Where

x is the compression distance

So,

\(x=\dfrac{F}{k}\\\\x=\dfrac{4.3}{71}\\\\x=0.0605\ m\)

or

x = 6.05 cm

So, the compression distance is 6.05 cm.

Answer:

K = C + 273, so 27°C = 27+273 = 300 K

1 dg = 100 mg, so 20 dg = 20×100 = 2,000 mg

Explanation:

Answer:

a. 186.2 J b. 8.63 m/s c. 190 m d. 43.2 s e. 186.2 J

Explanation:

a. From conservation of energy, the potential energy loss of block = kinetic energy gain of the block.

So, U + K = U' + K' where U = initial potential energy of block = mgh, K = initial kinetic energy of block = 0, U' = final potential energy of block at bottom of curve = 0 and K' = final kinetic energy of block at bottom of curve.

So, mgh + 0 = 0 + K'

K' = mgh where m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s², h = initial height above the ground of block = radius of curve = 3.8 m

So, K' = 5 kg × 9.8 m/s² × 3.8 m = 186.2 J

b. Since the kinetic energy of the block K = 1/2mv²  where m = mass of block = 5 kg, v = velocity of block at bottom of curve

So, v = √(2K/m)

= √(2 × 186.2 J/5 kg)

= √(372.4 J/5 kg)

= √(74.48 J/kg)

= 8.63 m/s

c. To find the stopping distance, from work-kinetic energy principles,

work done by friction = kinetic energy change of block.

So ΔK = -fd where ΔK = K" - K' where K" = final kinetic energy = 0 J (since the block stops)and K' = initial kinetic energy = 186.2 J, f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance

ΔK = -fd

K" - K' = - μmgd

d = -(K" - K')/μmg

Substituting the values of the variables, we have

d = -(0 J - 186.2 J)/(0.02 × 5 kg × 9.8 m/s²)

d = -(- 186.2 J)/(0.98 kg m/s²)

d = 190 m

d. Using v² = u² + 2ad where u =initial speed of block = 8.63 m/s, v = final speed of block = 0 m/s (since it stops), a = acceleration of block and d = stopping distance = 190 m

So, a = (v² - u²)/2d

substituting the values of the variables, we have

a = (0² - (8.63 m/s)²)/(2 × 190 m)

a = -74.4769 m²/s²/380 m

a = -0.2 m/s²

Using v = u + at, we find the time t that elapsed while the block is moving on the horizontal track.

t = (v - u)/a

t =(0 m/s - 8.63 m/s)/-0.2 m/s²

t = - 8.63 m/s/-0.2 m/s²

t = 43.2 s

e. The work done by friction W = fd where

= μmgd where f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance = 190 m

W = 0.02 × 5 kg × 9.8 m/s² × 190 m

W = 186.2 J

The potential energy of the loss of the block will be equal to the kinetic energy gain. The kinetic energy of the block is 186.2 J at the bottom of the curved surface.

The potential energy of the loss of the block will be equal to the kinetic energy gain.

So,

\(U = mgh\)

Where,

\(U\) - potential energy

\(m\) - mass of block =  5 kg

\(g\) - gravitational  acceleration = 9.8 m/s²

\(h\) = height = radius of curve = 3.8 m

Put the values in the formula,

\(U = 5 \times 9.8 \times 3.8 \\\\ U = 186.2 \rm \ J\)

Therefore, the kinetic energy of the block is 186.2 J at the bottom of the curved surface.

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Answer:

True!

Explanation:

Change of state due to cooling is due to the removal of thermal energy from a substance. A substance changes states, such as from a gas to a liquid or from a liquid to a solid, when its particles lose kinetic energy as it loses heat and moves more slowly. Eventually, the particles reorganize into a more ordered form with less energy. The term "solidification" or "freezing" refers to this process.

Answer:

21.48 km 2.92° north of east

Explanation:

To find the resultant direction, we need to calculate a sum of vectors.

The first vector has module = 13 and angle = 315° (south = 270° and east = 360°, so southeast = (360+270)/2 = 315°)

The second vector has module 16 and angle = 40°

Now we need to decompose both vectors in their horizontal and vertical component:

horizontal component of first vector: 13 * cos(315) = 9.1924

vertical component of first vector: 13 * sin(315) = -9.1924

horizontal component of second vector: 16 * cos(40) = 12.2567

vertical component of second vector: 16 * sin(40) = 10.2846

Now we need to sum the horizontal components and the vertical components:

horizontal component of resultant vector: 9.1924 + 12.2567 = 21.4491

vertical component of resultant vector: -9.1924 + 10.2846 = 1.0922

Going back to the polar form, we have:

\(module = \sqrt{horizontal^2 + vertical^2}\)

\(module = \sqrt{460.0639 + 1.1929}\)

\(module = 21.4769\)

\(angle = arc\ tangent(vertical/horizontal)\)

\(angle = arc\ tangent(1.0922/21.4491)\)

\(angle = 2.915\°\)

So the resultant direction is 21.48 km 2.92° north of east.

Explanation:

x-component:

Vx = Vcos(theta)

= (92.5 m)cos(32.0)

= 78.4 m

Answer:

-78.4

Explanation:

For acellus students

The magnetic pressure modifications capacity power into kinetic power. Dylan places magnetic toy trains subsequent to each other on a track.

When magnets have appealing forces among them and they're moved apart, kinetic power is transferred into the magnets whilst they're released and they pass lower back together. converting the space between magnets changes the amount of strength that can be transferred into and out of a magnetic area.

A charged shifting particle is a particle in movement with either a positive or terrible price. Magnetic pressure has a good-sized impact on charged debris. A robust magnetic pressure can alter the route of a transferring charged particle. A big object with a magnetic force encourages particles to revolve around it.

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The magnetic force changes potential energy into kinetic energy.

Moving a magnet around a coil of wire, or moving a coil of wire around a magnet, pushes the electrons in the wire and creates an electrical current. Electricity generators essentially convert kinetic energy into electrical energy.

All magnets have north and south poles. Contrary poles are interested in every different, while the same poles repel every different. While you rub a chunk of iron alongside a magnet, the north-seeking poles of the atoms inside the iron line up inside the same direction. The force generated via the aligned atoms creates a magnetic subject.

When  magnets are brought close collectively they exert a pressure on each different, like poles repel every different.  Unlike poles attract each different. Appeal and repulsion between two magnetic poles are examples of non-touch force.

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The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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During the collision between the bike and the truck, the two objects will experience forces and accelerations. The force of the collision will be the result of the difference between the momentum of the two objects before and after the collision. The momentum of an object is the product of its mass and velocity, represented as p = mv.

Before the collision, the bike has a momentum of 20 kg * 10 m/s = 200 kg m/s to the right and the truck has a momentum of 3,000 kg * -20 m/s = -60,000 kg m/s to the left.

After the collision, since the truck has a much greater mass than the bike, it will experience a much smaller change in momentum than the bike, and the final velocities of the two objects will be close to the initial velocity of the truck.

So, the force of the collision will be the difference between the initial momentum of the bike and truck and the final momentum of the bike and truck. This force will be acting on the bike, causing it to experience an acceleration. The truck will experience a force as well, but it will be much smaller in magnitude because of its much larger mass.

Therefore, the best statement that describes the forces and accelerations involved during the collision is: The bike experiences a large force during the collision, causing it to experience a large acceleration, while the truck experiences a smaller force and acceleration due to its much larger mass.

To help us solve this problem let's plot the points given in the table:

From the graph we notice that this the position can be modeled by a sine function, we also notice that the period of this function is 8. We know that a sine function can be modeled by:

where A is the amplitude, C is the horizontal shift, D is the vertical shift and

is the period.

From the graph we have we notice that we don't have any horizontal or vertical shift, then C=0 and D=0. We also notice that the amplitude is 15, then A=15. Finally, as we said, the period is 8, then:

Plugging these values in the sine function we have:

If we graph this function along the points on the table we get the following graph:

We notice that we don't get an exact fit but we get a close one.

Now, that we have a function that describes the position we can find the velocity by taking the derivative:

Therefore, the velocity is:

Once we have the expression for the velocity we can find values for the times we need, they are shown in the table below:

From the table we have that:

And that:

• The earliest time when the velocity is zero is 2 s.

• The second time when the velocity is zero is 6 s.

• The minimum velocity happens at 4 s.

• The minimum velocity is -11.780972 cm/s

Answer:

congenital insensitivity to pain CIPA

Explanation:

it's a rare disorder but is found on most newborns, genetics mutation that stops the nerve cells transmitting signals of pain.

Congenital insensitivity to pain is a type of rare disorder that includes the inability to feel pain. This generally happens with newborn babies.

A group of issues that significantly complicate, distress, impede or cause pain in a person's daily life can be referred to as a disorder. Obsessive-Compulsive Disorder fits the definition of a disorder, according to the Oxford English Dictionary, which defines it as a condition that interferes with normal bodily or mental function (see the quote above).

In further depth, disorders are physical or mental illnesses that interfere with daily life activities or other regular or typical processes. They can consume a lot of time and hinder a person's ability to conduct themselves normally.

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Answer:

a) v = 11.24 m / s ,    θ = 17.76º   b) Kf / K₀ = 0.4380

Explanation:

a) This is an exercise in collisions, therefore the conservation of the moment must be used

Let's define the system as formed by the two cars, therefore the forces during the crash are internal and the moment is conserved

Recall that moment is a vector quantity so it must be kept on each axis

X axis

initial moment. Before the crash

     p₀ₓ = m₁ v₁

where v₁ = -25.00 me / s

the negative sign is because it is moving west and m₁ = 900 kg

final moment. After the crash

      \(p_{x f}\)= (m₁ + m₂) vx

       p₀ₓ =  p_{x f}

       m₁ v₁ = (m₁ + m₂) vₓ

     vₓ = m1 / (m₁ + m₂) v₁

let's calculate

       vₓ = - 900 / (900 + 1200) 25

       vₓ = - 10.7 m / s

Axis y

initial moment

      \(p_{oy}\)= m₂ v₂

where v₂ = - 6.00 m / s

the sign indicates that it is moving to the South

final moment

     p_{fy}= (m₁ + m₂) \(v_{y}\)

     p_{oy} = p_{fy}

     m₂ v₂ = (m₁ + m₂) v_{y}

     v_{y} = m₂ / (m₁ + m₂) v₂

we calculate

    \(v_{y}\) = 1200 / (900+ 1200) 6

    \(v_{y}\)  = - 3,428 m / s

for the velocity module we use the Pythagorean theorem

      v = √ (vₓ² + v_{y}²)

      v = RA (10.7²2 + 3,428²2)

      v = 11.24 m / s

now let's use trigonometry to encode the angle measured in the west clockwise (negative of the x axis)

      tan θ = \(v_{y}\) / Vₓ

      θ = tan-1 v_{y} / vₓ)

      θ = tan -1 (3,428 / 10.7)

       θ = 17.76º

This angle is from the west to the south, that is, in the third quadrant.

b) To search for loss of the kinetic flow, calculate the kinetic enegy and then look for its relationship

      Kf = 1/2 (m1 + m2) v2

      K₀ = ½ m₁ v₁² + ½ m₂ v₂²

      Kf = ½ (900 + 1200) 11.24 2

      Kf = 1.3265 105 J

      K₀ = ½ 900 25²  + ½ 1200 6²

      K₀ = 2,8125 10⁵ + 2,16 10₅4

        K₀ = 3.0285 105J

the wasted energy is

        Kf / K₀ = 1.3265 105 / 3.0285 105

        Kf / K₀ = 0.4380

this is the fraction of kinetic energy that is conserved, transforming heat and transforming potential energy

The forces acting on the cart are balanced. this  they infer about the cart as it sits on sidewalk. Hence option A is correct.

The most plausible conclusion the students may draw about the cart, which is immobile on the sidewalk, is that the forces pulling on it are balanced based on the facts provided. Accordingly, there is no net force exerted on the cart, and forces operating in opposing directions cancel one another out to bring about equilibrium. The cart's inertia suggests that no unbalanced force is pressing on it, supporting the conclusion that the forces pushing the cart are also balanced. The most logical conclusion the students may draw is option A.

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Answer:

Explanation:

The velocity of sound from the plucked string in the tennis racquet is:

\(v=\sqrt{\frac{FL}{m}}=\sqrt{\frac{274(0.74)}{28}}\approx 2.69 ms^{-1}\)

Then the frequency will be:

\(f=\frac{v}{2L}=\frac{2.69}{2(0.74)}\approx 1.81 Hz\)

Answer:

Thats a personal question

Explanation:

It asks about you

(illusion is something you think is there but is not)

Seeing the dirty look on a friend's face, we assume that he is angry with us, but he may be having a bad day, or may be thinking something that is reflected in his face. We should always ask someone instead of assuming.

Illusory correlation is defined as the phenomenon of assuming a relationship between variables even when no such relationship exists where a false association can be made because rare or novel events are more prominent and therefore attract one's attention.

Illusory correlation occurs when two different variables occur at the same time, with an unproven connection made on the basis of little evidence. An example of this would be when a person has a bad experience with a lawyer and they immediately assume that all lawyers are bad people.

Thus, we should always ask someone instead of assuming.

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Answer:

allows for efficient transport of materials

Explanation:

Living cells relatively have a small size, so small that a microscope is needed to see their structure. However, this small size is for their benefitting as it increases their surface area to volume ratio (SA:V).

A large surface area to volume ratio (SA:V) enables easy movement of molecules to and fro the cell membrane via the process of DIFFUSION. Therefore, having a small size allows for efficient transport of materials needed in the cell.