A string is wrapped around a wheel of radius 30 cm mounted on a stationary axle. The wheel is initially not rotating. You pull the string with a constant force through a distance of 32 cm. What is the angle in radians and degrees through which the wheel rotates

The  continental volcanic arc and a volcanic island arc different from each other  is An island volcanic arc forms in an ocean basin via ocean-ocean subduction.

The Aleutian Islands off the coast of Alaska and the Lesser Antilles south of Puerto Rico are examples.

A continental volcanic arc forms alongside the margin of a continent where oceanic crust subducts underneath continental crust.

An island arc and a volcanic arc are basically the same type of geological characteristic except for the reality that one is on land and the opposite is surrounded by the usage of water.

Plate tectonics drives the arrival of volcanic arcs. A denser oceanic plate collides with a more buoyant continental plate. The oceanic crusts’ density pulls it downward into the mantle wherein excessive warmness melts it.

The molten rock and volatiles (magma) then art work their way upwards often attaining the ground and erupting. The arc form is the floor trace of the area wherein the down

going plate is melting. it's far an arc because of the truth the earth is a spherical shape.

heaps of the Pacific rim, extensively Japan, Polynesia and the Aleutians are island arcs.

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Hi there!

Recall the conservation of momentum:

m1v1 + m2v2 = m1v1' + m2v2'

Let m1 = 5 kg ball and m2 = 10 kg ball

Since m2 is at rest, we can rewrite:

m1v1 = m1v1' + m2v2'

Plug in the given values:

5(2) = 5(-1) + 10v2'

Solve for v2':

10 = -5 + 10v2'

15 = 10v2'

15/10 = 1.5 m/s

We know that,

m1v1 + m2v2 = m1v1' + m2v2'

5 x 2 + 0 = 5 x -1 + 10 x v2'

10= -5 +10 x v2'

15 = 10 x v2'

v2' = 15/10

v2' = 1.5 m/s

hence , the speed of the larger ball after the collision will 1.5m/s

Answer:

9.0 m

Explanation:

Applying

V = kq/r......................... Equation 1

Where V = Electric potential, q = charge, r = distance, k = Coulomb's constant.

make r the subject of the equation

r = kq/V................... Equation 2

From the question,

Given: q = 1.00×10⁻⁵ C, V = 10000 V

Constant: k = 9.0×10⁹ N⋅m²/C²

Substitute these values into equation 2

r = (9.0×10⁹×1.00×10⁻⁵)/10000

r = 9.0 m

Answer:

9.0

Explanation:

Two light bulbs are parallel-connected in a circuit. If two more light bulbs were put in parallel to the initial ones, Each bulb's brightness would get dimmer as the circuit's overall resistance got lower. Because the circuit's overall resistance would rise, each bulb's brightness would also rise. Even if the circuit's overall resistance would decrease, each bulb's brightness would not change. Even if the circuit's overall resistance would rise, the intensity of each bulb would stay the same.

A resistor is a passive two-terminal electrical component used in circuits to implement electrical resistance. Resistors have a variety of purposes in electronic circuits, including lowering current flow, adjusting signal levels, dividing voltages, biassing active components, and terminating transmission lines.

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Physics is the branch of science that deals with the structure of matter and how the fundamental constituents of the universe interact. It studies objects ranging from the very small using quantum mechanics to the entire universe using general relativity.

Answer:

please ask this question separately

Explanation:

Answer:

Newton's Second Law

Explanation:

The scenario explained above could be best described by Newton's Second Law.

Newton's Second Law state that when a net force is acted on an object, the force will lead to the acceleration of that object, such that force is equal to momentum change per change in time.

Hence, as the runner pushes harder with her leg muscles and speeds up for the last few yards, the speed is directly proportional to the force with which it pushes her leg muscles.

The values constants magnitude are A=-6 MathrmV cdot m-2 A=6 Vm. B = 4 mathrm V cdot m 3, B = 4 mathrm V m 3, C = 2 V m 6, C = -2 V cdot m 6, l = 2 mathrm V m 6, m = 3 mathrm V m 3, and n = 6 mathrm V n = 6.

Magnitude is simply "distance or quantity" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.

The amount that encapsulates the force's strength is known as its magnitude. Consider the following scenario: the force is 10 N in the east. The direction is indicated by "towards east," while the force is indicated by "10." Magnitude can be thought of as simply the "value" or "amount" of any physical quantity.

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Answer:

\(a=-3\ m/s^2\)

Explanation:

Given that,

Initial speed of a train, u = 12 m/s

Final speed of a train, v = 9.6 m/s

Time taken, t = 0.8 s

We need to find the average acceleration of the train. We know that the rate of change of velocity is equal to acceleration. So,

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{9.6-12}{0.8}\\\\a=-3\ m/s^2\)

So, the average acceleration of the train is equal to \(-3\ m/s^2\).

Each billiard ball has a velocity of 31.14 m/s immediately after the collision.

In an elastic head-on collision between two identical billiard balls, each with an initial velocity of v, the velocity of each billiard ball is reversed, and the resulting velocity of each billiard ball is also the same as the initial velocity of each billiard ball.

We can use the law of conservation of kinetic energy to solve for the velocities immediately after the collision.

According to the law of conservation of kinetic energy, the sum of the kinetic energies before and after the collision is the same.

The kinetic energy of a particle with a mass m and a velocity v is given by KE = (1/2)mv².

We can use this equation to find the kinetic energy of each billiard ball before the collision.

KE before = (1/2)mv²

KE before = (1/2)(m)(v)²

KE before = (1/2)(0.17 kg)(22 cm/s)²

KE before = 41.14 mJ

The total kinetic energy before the collision is 2(41.14 mJ) = 82.28 mJ.

Since the collision is elastic, the total kinetic energy after the collision is also 82.28 mJ.

We can use this value to solve for the velocities immediately after the collision.

KE after = (1/2)mv²

KE after = (1/2)(m)(v')²

KE after = (1/2)(0.17 kg)(v')²

82.28 mJ = (1/2)(0.17 kg)(v')²

v'² = (2)(82.28 mJ)/(0.17 kg)

v'² = 969.35 m²/s²

v' = sqrt(969.35 m²/s²)

v' = 31.14 m/s

Each billiard ball has a velocity of 31.14 m/s immediately after the collision.

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Answer:

See attached document.

Explanation:

The electron drift velocity ratio for copper to aluminum is 1.70:1.

The electron drift velocity in a wire is given by the expression:

v = I / (n × A × q)

where

I = electric current

n = number density of electrons in the wire

A = cross-sectional area of the wire

q = charge of an electron

The number density of electrons in a material is given by:

n = (density × NA) / (atomic mass × volume)

where

density = density of the material

NA = Avogadro's number

atomic mass = atomic mass of the material

volume = volume of a unit cell of the material

For copper,

the atomic mass = 63.55 g/mol,

density = 8.96 g/cm³, and

volume of a unit cell = 1.09 x 10⁻⁵ cm³.

For aluminum,

the atomic mass = 26.98 g/mol,

density = 2.70 g/cm³, and

volume of a unit cell = 4.05 x 10⁻⁵ cm³.

Since the wires have the same length and diameter, their cross-sectional areas are equal. Therefore, the ratio of the electron drift velocities for copper and aluminum:

v_copper / v_aluminum = (n_copper × density_copper) / (n_aluminum × density_aluminum)

Plugging in the values:

v_copper / v_aluminum = ((density_copper × NA) / (atomic_mass_copper × volume_copper)) / ((density_aluminum × NA) / (atomic_mass_aluminum × volume_aluminum))

v_copper / v_aluminum = ((8.96 g/cm³ × 6.022 x 10²³) / (63.55 g/mol × 1.09 x 10⁻⁵ cm³)) / ((2.70 g/cm³ × 6.022 x 10²³) / (26.98 g/mol × 4.05 x 10⁻⁵ cm³))

v_copper / v_aluminum = 1.70

Therefore, the ratio of the electron drift velocity for copper to aluminum is 1.70:1.

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The answers to the questions of the object thrown off a cliff with a horizontal speed of 10 m/s and that reach the ground which is 30 m below after 3 seconds, are:

a. We know:

b. We need to find the initial vertical velocity and the total horizontal distance traveled.

c. To calculate the initial vertical velocity and the total horizontal distance traveled by the object, we need to use the following equations:

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)   (1)

\( v_{i_{x}} = \frac{x}{t} \)  (2)

d. The initial vertical velocity and the horizontal distance traveled by the object are 4.72 m/s and 30 m, respectively.

a. From the statement, we know:

b. We need to find the initial vertical velocity and the total horizontal distance traveled.

c. To calculate the initial vertical velocity we can use the following equation:

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)   (1)

Where:

\( y_{f}\): is the final height = 0 m  

\( y_{i}\): is the initial height = 30 m  

\( v_{i_{y}}\): is the initial vertical velocity =?  

g: is the acceleration due to gravity = 9.81 m/s²

t: is the time = 3 s  

And, to find the horizontal distance traveled by the object we need to use the equation:

\( v_{i_{x}} = \frac{x}{t} \)   (2)

Where:

\(v_{i_{x}} \): is the initial horizontal velocity = 10 m/s

x: is the horizontal distance =?

d. The solution to this problem is the following.

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)  

\( 0 = 30 m + v_{i_{y}}*3 s - \frac{1}{2}*9.81 m/s^{2}*(3 s)^{2} \)

Solving for \(v_{i_{y}}\)

\( v_{i_{y}} = \frac{\frac{1}{2}*9.81 m/s^{2}*(3 s)^{2} - 30 m}{3 s} = 4.72 m/s \)

Hence, the initial vertical velocity is 4.72 m/s.  

\( v_{i_{x}} = \frac{x}{t} \)

\( 10 m/s = \frac{x}{3 s} \)

\( x = 10 m/s*3 s = 30 m \)

Therefore, the horizontal distance traveled by the object is 30 m.

Read more here:

I hope it helps you!  

Answer:

c

Explanation:

After one half-life, 8 g of radioactive isotope will remain in the sample.

The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that want to give up some energy in order to move to a more stable form.

The following formula is used to compute the number of half lives elapsed:

\(\rm N=\frac{N_0}{2^n} \\\\ N=\frac{16}{2} \\\\ N= 8 \ gram\)

Hence,8 gram of radioactive isotope remains in the sample after 1 half-life.

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Answer:

Answer is below

Explanation:

8 g

Answer:

Which surface applied the greatest force of friction on the object?

Rougher surfaces have more friction between them. Heavier objects also have more friction because they press together with greater force.

I hope you helped>_<

answer = 33.4 net force.

Answer:

mass is something that takes up space and weight is how much mass something has

Given,The system is at equilibrium and the smooth rod has a mass of 8.00 kg, and a center of mass at point G, which is halfway along the length of the rod.The mass of the rope can be neglected.In order to understand the concept of equilibrium, we must first understand the definition of equilibrium.

When the net force acting on an object is zero, it is in a state of equilibrium.In the given figure, the smooth rod is balanced on the support of two ropes attached to two walls, so the forces are balanced. For an object to be in equilibrium, the sum of all forces acting on it must be zero and the sum of all torques acting on it must also be zero. Since the rod is in equilibrium, the sum of the clockwise torques must be equal to the sum of the anticlockwise torques.

Therefore, the clockwise torque is (8.00 kg x 9.81 m/s² x L) Nm. Similarly, the anticlockwise torque is equal to the tension multiplied by the distance from the pivot point to the point where the rope is attached. Therefore, the anticlockwise torque is (T x L) Nm.Since the system is in equilibrium, the sum of the clockwise torques must be equal to the sum of the anticlockwise torques. Therefore, we can write the equation:mg x L = 2T x LL = (mg/2T)

The tension in each rope is equal to the weight of the rod divided by twice the distance from the center of mass to the pivot point. Therefore, the tension in each rope is:T = (mg/2L)T = (8.00 kg x 9.81 m/s²) / (2 x L)T = 39.24 N / LTherefore, the tension in each rope is directly proportional to the distance from the center of mass to the pivot point. As the distance from the center of mass to the pivot point increases, the tension in each rope decreases.

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Answer: There really aren't many ways to estimate how old the universe is but, astronomers start by looking at the oldest stars in the universe.

Explanation:

Answer:

The big bang 13.7 billion years ago

Explanation:

Everything started 13.7 billion years ago that is when the big bang started.

The pendulum would need to be approximately 18.964 meters long to double its period.

To find the period of a pendulum, we can use the formula:

T = 2π√(L/g)

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

Given that L = 4.74 m and g = 9.8 m/s², let's find the period T:

T = 2π√(4.74/9.8)
T ≈ 2π√(0.4837)
T ≈ 2π(0.6955)
T ≈ 4.372 s

So the period of the pendulum is approximately 4.372 seconds.

Now, to double the period, we have to find the new length L'. We can use the same formula but with the new period T':

T' = 2T
T' ≈ 2(4.372)
T' ≈ 8.744 s

Now, let's solve for L':

8.744 = 2π√(L'/9.8)
(8.744/2π)² = L'/9.8
1.932² = L'/9.8
L' ≈ 1.932² * 9.8
L' ≈ 18.964 m

To double the period, the pendulum would have to be approximately 18.964 meters long.

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Answer:

um Saturday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday?

Explanation:

Answer:

A. 2 m/s

(m x v) (m x v) = (m+m)v

The number of turns in the secondary coil if the input voltage is 120V and the number of turns for the primary coil has 380 turns is 29 turns.

Consider the number of turns in the primary coil to be N₁. The number of turns in the secondary coil is N₂. The input voltage is considered as V₁ and its value is, V₁=120V. The output voltage is considered as V₂ and its value is, V₂= 9V. Now by using the transformer formula, which relates the number of turns, EMF, and current in both the primary and the secondary coils. N₂/N₁ =V₂/V₁ = I₁/I₂. So, N₂/380= 9/120, N₂= (9×380)/120 =28.5 ≈29turns in the secondary coils.

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Answer:

I believe it is crater.

The forces acting on a skateboard include gravity, friction, air resistance, and applied force, and they all affect the motion of the skateboard in different ways.

When a skateboard is in motion, several forces act on it that affect its movement. The main forces acting on a skateboard are:

Gravity: This is a force that pulls the skateboard downwards towards the ground. The weight of the skateboard and the rider are also affected by gravity.

Friction: This is a force that opposes the motion of the skateboard. Friction is caused by the skateboard's wheels rolling on the ground or surface, and it can slow down the skateboard's speed.

Air resistance: This is a force that opposes the motion of the skateboard as it moves through the air. The faster the skateboard moves, the more air resistance it experiences.

Applied force: This is the force applied by the rider to propel the skateboard forward or to perform tricks. The amount of applied force determines how fast or slow the skateboard moves.

The combination of these forces affects the motion of the skateboard. If the applied force is greater than the forces of friction, air resistance, and gravity, the skateboard will accelerate. If the forces of friction, air resistance, and gravity are greater than the applied force, the skateboard will slow down or come to a stop.

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Answer:

0,146 L

Explanation:

Según la ley de Charles; el volumen de una determinada masa de gas es directamente proporcional a su temperatura a presión constante.

A partir de los datos proporcionados;

V1 = 0,2 L

T1 = 100 ° C + 273 = 373 K

V2 =

T2 = 0 ° C + 273 = 273 K

V1 / T1 = V2 / T2

V1T2 = V2T1

V2 = V1T2 / T1

V2 = 0,2 × 273/373

V2 = 0,146 L

(a). The velocity of the center of mass is (4.32 î + 6.43 ĵ) m/s.

(b). The total momentum of the system is:

\(p_{total\) = \(p_1 + p_2\)  = (4.10 î − 6.00 ĵ) kg · m/s + (3.22 î + 17.62 ĵ) kg · m/s = (7.32 î + 11.62 ĵ) kg · m/s

(a) The velocity of the center of mass can be found using the formula:

\(v_cm = (m_1v_1 + m_2v_2) / (m_1 + m_2)\)

where\(m_1\) and \(v_1\) are the mass and velocity of the first particle, and \(m_2\) and \(v_2\) are the mass and velocity of the second particle. Substituting the given values, we get:

\(v_{cm\) = (1.96 kg)(2.09 î − 3.05 ĵ) m/s + (2.98 kg)(1.08 î + 5.91 ĵ) m/s / (1.96 kg + 2.98 kg)

\(v_{cm\) = (4.32 î + 6.43 ĵ) m/s

(b) The total momentum of the system can be found by adding the momentum of each particle. The momentum of a particle is given by:

p = mv

where m is the mass of the particle and v is its velocity. Substituting the given values, we get:

\(p_1\) = (1.96 kg)(2.09 î − 3.05 ĵ) m/s = (4.10 î − 6.00 ĵ) kg · m/s

\(p_2\) = (2.98 kg)(1.08 î + 5.91 ĵ) m/s = (3.22 î + 17.62 ĵ) kg · m/s

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Examples of radiation are from the burner to air that is not touching it. In the surrounding air as air currents develop. The correct options are A and B.

Radiation is the emission or transmission of energy through a material medium or across space in the form of waves or particles. Radiation is the heat transfer method in which the heat is transferred without any direct contact between the two objects.

Given that a pot of water is heated on a gas-flame stove and begins to boil. Which two transfers of thermal energy are involved?

Here the heat is transferred through the radiation in which no direct contact is there between the two objects. The two thermal heat transfer energies are from the burner to air that is not touching it and In the surrounding air as air, currents develop.

Therefore, examples of radiation are from the burner to air that is not touching it. In the surrounding air as air currents develop. The correct options are A and B.

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(a) the angle the sailor should steer his ship is 53°.

(b) The magnitude (speed) of the resultant velocity is approximately 5.26 ms-1.

(a) Since the wind is blowing towards the South of East, the course the sailor should steer the ship in order to travel directly East is given by the bearing of the vector sum of the wind and the boat's velocity vector. We need to find this bearing.

From the diagram below, the resultant vector, R, is the vector sum of the boat's velocity vector, B, and the wind vector, W. The direction of the R is given by the bearing of the line QR.

Since PR = 6 and PQ = 8, the angle between PQ and QR is given by:

tan θ = PR / PQ

= 6 / 8

= 0.75θ

= 37° (to the nearest degree)

Therefore, the bearing of the resultant vector R is 90° - θ = 90° - 37°

= 53° (to the nearest degree).

Hence, the angle the sailor should steer his ship is 53°.

(b) The magnitude of the resultant velocity can be found by finding the magnitude of the resultant vector R.

From the diagram above,

\(cos \theta = PQ / PR\cos  \theta \\= 8 / 6\\\cos \theta = 1.333R^2 \\= PQ^2 + PR^2 - 2PQPR\\\cos  \theta R^2 = 8^2 + 6^2 - 2(8)(6)\\\cos  \theta R^2 = 64 + 36 - 96\\\cos  \theta R^2= 100 - 96(1.333)\\R^2 = 100 - 127.68\\R = \sqrt{(-27.68)}\\R = 5.26\)ms-1 (to 3 significant figures)

Therefore, the magnitude (speed) of the resultant velocity is approximately 5.26 ms-1.

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The magnitude (speed) of the resultant velocity is 10 m/s.

To find the angle (as a bearing) the sailor should steer his ship to and the magnitude (speed) of the resultant velocity, we can use vector addition.

Let's break down the given information:

Boat's speed in still water (no wind): 8 m/s.

Wind's direction: 150° (measured clockwise from the North).

Wind's magnitude: 6 m/s.

a) To determine the angle (bearing) the sailor should steer his ship to, we need to find the resultant direction by adding the vectors representing the boat's velocity and the wind's velocity.

Since the wind's direction is 150°, and the boat wants to travel east (90°), the resultant direction should be the sum of

these two angles.

Resultant direction = 150° + 90° = 240° (measured clockwise from the North).

Therefore, the sailor should steer his ship to a bearing of 240°.

b) To find the magnitude (speed) of the resultant velocity, we need to calculate the magnitude of the resultant vector by using the Pythagorean theorem.

Let the magnitude of the resultant velocity be V.

Using the Pythagorean theorem:

V^2 = (Boat's velocity)^2 + (Wind's velocity)^2

V^2 = (8 m/s)^2 + (6 m/s)^2

V^2 = 64 m²/s² + 36 m²/s²

V^2 = 100 m²/s²

Taking the square root of both sides:

V = √(100 m²/s²)

V = 10 m/s

Therefore, the magnitude (speed) of the resultant velocity is 10 m/s.

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The acids are sour flavour, dissolves some metals and turns litmus paper red.

The bases are bitter flavour, feels slippery and turns litmus paper to blue.

The German word for acid, sauer, describes its sour flavour. Since hydrochloric acid, which is used to digest food, can harm cells, our stomachs require a special lining to shield it from this acid. Acids are something we're all familiar with; they're present in tomatoes, citrus fruits, and vinegar. There are numerous varieties of salts in chemistry, and acids react with most metals, including magnesium, to produce hydrogen gas.

When two substances come into contact, corrosive substances will cause a chemical reaction that will damage or destroy the other substances.

On contact, bases feel slick. This is due to their ability to alter protein structure. Because it begins to harm the proteins in your skin, a strong base can result in severe chemical burns.

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