A stunt bicycle rider goes 39m in 3.0s. How fast is the cyclist riding?
Answers
Answer:
Speed of stunt bike rider = 13 meter/ Second
Explanation:
Given:
Distance cover by stunt bike rider = 39 meter
Time taken by stunt bike rider = 3 seconds
Find:
Speed of stunt bike rider
Computation:
Speed = Distance / Time
Speed of stunt bike rider = Distance cover by stunt bike rider / Time taken by stunt bike rider
Speed of stunt bike rider = 39 / 3
Speed of stunt bike rider = 13 meter/ Second
Related Questions
PLEASE ANSWER!!!
a ship sails a distance of 600 km at a speed of 20km/h.
A) for what amount of time was the ship sailing?
B) is this a scalar quantity or a vector quantity?
Answers
Answer:
A) 30h
B) Scalar quantity
Explanation:
Part A
[Note: v represents speed, d represents distance, and t represents time]
Given:
\(d = 600 km\)
\(v = 20 km/h\)
Required:
\(t = ?\)
Analysis:
\(v = \frac{d}{t} \\t = \frac{d}{v}\)
Solution:
\(t = \frac{d}{v} \\t = \frac{600 km}{20 km/h} \\t = 30 h\)
Statement:
Therefore, the ship was sailing for 30 hours.
--------------------------------------------------------------------------------------------------------------
Part B
This is a scalar quantity because time only has magnitude and can never be given direction so it can never be a vector quantity.
how can an electrical current produce a magnetic field?
Answers
Answer:
by charging the coil
Explanation:
do you know how a magnet grabs another magnetic material and move it closer, an electric current passes through the coil making it act like a magnet by charging the coil called electromagnetism
What advice did the interviewee offer for students interested in his/her career?
Answers
The advice the interviewee offered for students interested in his/her career was to be hardworking and persistent.
What is a Career?This is referred to as the chosen profession or occupation of an individual and is characterized by the individual taking the required courses or training which are needed in the execution of the tasks related to it.
The advise which was offered to the students was to be hardworking and persistent as there are lots of challenges and obstacles which one will face on the journey and will help overcome them and achieve the desired result in practicing the career.
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Give a short introduction to alternative energy
Answers
Answer:
Alternative energy is energy sources other than fossil fuels, including renewable sources and nuclear energy. However, nuclear energy is not classified as a renewable energy source, because it is mined from uranium and thorium elements, which cannot be replenished. Hoped this helped!!!
A rocket moving upward at 2.50 km/s
discards its first stage and continues to
accelerate upward at 40.0 m/s² for
another 120 s. How much altitude does it
gain during this time (km)?
[?] km
Answers
The altitude gained by the rocket is 588km
If an object's velocity changes, it is said to have been accelerated. An object's velocity can alter depending on whether it moves faster or slower or in a different direction.
Since acceleration has both a magnitude and a direction, it is a vector quantity. Additionally, it is the first derivative of velocity with respect to time or the second derivative of position with respect to time.
We know that the second equation of motion is
h = ut + 1/2 at²
Initial speed, u = 2.50km/s
acceleration, a = 40m/s² = 0.04km/s² [1m = 0.001km]
time, t = 120s
Altitude gain during this time, h
h = ut + 1/2 at²
h = 2.50 * 120 + 1/2 * 0.04 * 120²
h = 588km
Hence, the altitude gained by the rocket is 588km
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i will give u brainliest!
Answers
The answer is C. Hope this helps!
heat transfer that occurs through liquids and gases is called
Answers
Heat transfer that occurs through liquids and gases is called Convection.
Heat transfer is the exchange of thermal energy between physical systems. It occurs when there is a temperature difference between two objects or regions of space, causing heat to flow from the hotter system to the cooler one. There are three modes of heat transfer: conduction, convection, and radiation.
Conduction is the transfer of heat through a material by direct contact. In this mode, heat flows from a region of higher temperature to a region of lower temperature. Convection is the transfer of heat through a fluid (liquid or gas) by the movement of the fluid itself. This mode of heat transfer occurs through convection currents, where hot fluids rise and cooler fluids sink.
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Now observe the graph of the vertical velocity against time (vy,vs.t).To do so click y label on the vertical axis and select "vy" velocity y-component from the pop-up menu What do you observe about the vertical velocity of the ball? what does this say about the mathematical relationship between y-velocity and time here
Answers
The vertical velocity of the ball will decrease with time.
The relation between the vertical velocity and time is given as,
\(v_y=u_{}-gt\)Here, u is the initial velocity and g is acceleration due to gravity.
HELP
Which type of wave interaction is shown in the photo?
A. Interference
B. Refraction
C. Reflection
D. Diffraction
Answers
Answer: the answer is c (think bc im on that too)
Explanation:
The interference is a type of wave interaction shown in the photo. Option A is correct.
What is the interference of waves?The result of two or more wave trains flowing in opposite directions on a crossing or coinciding pathways. This phenomenon is known as the interference of waves.
The effect is the sum of the individual wave amplitudes at each site where more than one wave is present.
When two wave pulses are traveling along a string toward each other. They meet and the phenomenon is occur known as interference.
The interference is a type of wave interaction shown in the photo
Hence option A is correct.
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the force f between two charges q^(1) and q^(2) in a vacuum is proportional to the product of the charges and is inversely proportional to the square of the distance d between the two charges solve the formula for k
Answers
From the formula for coulomb's, the formula for k would be k = Fd²/q1q2.
How to determine the formula for K when using Coulomb's Law?Here, we are required to solve for k from the Coulomb's formula, F=kq1q2/d².
Solving the formula for k, we obtain;
k = Fd²/q1q2
To solve the formula for k, we need to make k the subject of the formula;
F = kq1q2/d²
Then, F × d² = kq1q2
Therefore, to make k the subject of the formula; we divide both sides of the equation by q1q2.
Therefore, k = Fd²/q1q2.
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Complete question
Coulomb's Law is given by the formula
F=kq1q2/d2
The force F between two charges q1 and q2 in a vacuum is proportional to the product of the charges, and is inversely proportional to the square of the distance d between the two charges. Solve the formula for k.
Restate Newton’s third law of motion.
Answers
Answer:
The force exerted by one source object on another target object always creates another force at the target object that pushes back on the source object with the same ... or His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.
Fred is conducting a controlled experiment to test whether using a grow light at night will help a tomato plant grow faster. Below are the steps to Fred's experiment: Plant tomato plants in two separate, but identical, flowerpots. Place the flowerpots in the same area outside during the day. At night, bring both flower pots inside and place one in the dark and one under a grow light. Give the plants the same amount of food and water each week. Measure the growth of the plants. Draw conclusions based on the data collected. Which of the following variables must Fred hold constant in this experiment?
Answers
Answer:
the type of tomato plants used.
Explanation:
In the diagram, the liquid is vaporizing at which point?
Answers
Answer:
The liquid is vaprizing at point C
Let a vector field V be given by V = (xe_x) + (ye_y). (a) Use Stokes's Theorem to evaluate the line integral, ∫dr.V where C is the unit circle in the xy-plane centered at (0, 0). (b) Use Stokes's Theorem to determine the same line integral if C is a unit circle centered at (1, 0). (c) Evaluate the two integrals above by actually performing the line integrals themselves.
Answers
A. The line integral ∫dr.V where C is the unit circle in the xy-plane centered at (0, 0) is equal to 0, B) the line integral ∫dr.V where C is a unit circle centered at (1, 0) is equal to 0. and C) the line integral of V over this circle is given by 2
What is vector?Vector is a type of mathematical object that has both magnitude and direction. It is used to represent physical quantities such as force, velocity, or acceleration.
(a) Using Stokes's Theorem, we have:
∫dr.V = ∮C ∇ × V • ds
where C is the unit circle in the xy-plane centered at (0, 0).
Now, ∇ × V = (\(-e_z\)) + (\(e_z\)) = 0
Therefore, ∮C ∇ × V • ds = 0
Therefore, the line integral ∫dr.V where C is the unit circle in the xy-plane centered at (0, 0) is equal to 0.
(b) Now, using Stokes's Theorem, we have:
∫dr.V = ∮C ∇ × V • ds
where C is a unit circle centered at (1, 0).
Now, ∇ × V = (\(-e_z\)) + (\(e_z\)) = 0
Therefore, ∮C ∇ × V • ds = 0
Therefore, the line integral ∫dr.V where C is a unit circle centered at (1, 0) is equal to 0.
(c) To evaluate the two integrals above by actually performing the line integrals themselves, we need to first express the vector field V in its components. We have:
\(V = (xe_x) + (ye_y)\)
Therefore, V = (x, y, 0).
Now, for the unit circle centered at (0, 0), the equation of this circle is given by \(x_2 + y_2 = 1\). Therefore, the line integral of V over this circle is given by:
∫dr.V = ∫(x, y, 0) • (dx, dy, 0)
= ∫(x dx + y dy, 0, 0)
= ∫(x dx + y dy, 0)
= ∫(x dx + y dy)
= ∫1√1−x² dx + ∫y√1−y² dy
= ∫1√1−x² dx + ∫y dy
= ∫1√1−x² dx + y²
= ∫1√1−x² dx + 1
= ∫1√1−x² dx + x² + 1
= x√1−x² + x² + 1
= 2.
Similarly, for the unit circle centered at (1, 0), the equation of this circle is given by (x-1)² + y² = 1. Therefore, the line integral of V over this circle is given by:
∫dr.V = ∫(x, y, 0) • (dx, dy, 0)
= ∫(x dx + y dy, 0, 0)
= ∫(x dx + y dy, 0)
= ∫(x dx + y dy)
= ∫1√1−(x-1)² dx + ∫y√1−y² dy
= ∫1√1−(x-1)² dx + ∫y dy
= ∫1√1−(x-1)² dx + y²
= ∫1√1−(x-1)² dx + 1
= ∫1√1−(x-1)² dx + (x-1)² + 1
= x√1−(x-1)² + (x-1)² + 1
= 2.
Hence, both the integrals evaluated by actually performing the line integrals themselves have the same value of 2.
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Find the force of attraction between a 60 kg student and:A. Another student of mass 80 kg, 1.4 m away.B. A 130,000 kg blue whale, 10 m away.C. The Great Pyramid in Egypt, with an estimated mass of 5.22 x 109 kg, 1.0 km away.D. A 45 g golf ball, 95 cm away.
Answers
According to Newton's Law of Universal Gravitation, the force between to bodies of masses m and M separated by a distance r is:
\(F=G\frac{Mm}{r^2}\)Where G is the gravitational constant:
\(G=6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2}\)In all cases, use M=60kg, and replace the values of the second mass m and the distance r accordingly.
A) m=80kg, r=1.4m
\(\begin{gathered} F=(6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2})\times\frac{(60\operatorname{kg})(80\operatorname{kg})}{(1.4m)^2} \\ =1.6\times10^{-7}N \end{gathered}\)B) m=130,000kg, r=10m
\(\begin{gathered} F=(6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2})\times\frac{(60\operatorname{kg})(130,000\operatorname{kg})}{(10m)^2} \\ =5.2\times10^{-6}N \end{gathered}\)C) m=5.22*10^9kg, r=1000m
\(\begin{gathered} F=(6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2})\times\frac{(60\operatorname{kg})(5.22\times10^9\operatorname{kg})}{(1000m)^2} \\ =2.1\times10^{-5}N \end{gathered}\)D) m=0.045kg, r=0.95m
\(\begin{gathered} F=(6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2})\times\frac{(60\operatorname{kg})(0.045\operatorname{kg})}{(0.95m)^2} \\ =2.0\times10^{-10}N \end{gathered}\)The center of gravity (CG) is a point, often shown as G, which locates the resultant weight of a system of particles or a solid body. O True O False
Answers
The given statement "The center of gravity (CG) is a point, often shown as G, which locates the resultant weight of a system of particles or a solid body." is True
The center of gravity (CG) is indeed a point that represents the average location of the weight distribution of a system of particles or a solid body. It is commonly denoted as "G" and is used to analyze the stability, equilibrium, and motion of objects. The center of gravity is typically located at the point where the weight of an object can be considered to act.
centre of gravity, in physics, an imaginary point in a body of matter where, for convenience in certain calculations, the total weight of the body may be thought to be concentrated. The concept is sometimes useful in designing static structures (e.g., buildings and bridges) or in predicting the behaviour of a moving body when it is acted on by gravity.
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given the time period in which maria mitchell was born, what obstacles could she have faced in regard to her own education and study of science? how did she overcome those obstacles
Answers
Maria Mitchell was born in 1818, a time when women were not encouraged to pursue education and careers in science. During her childhood, Maria faced many obstacles in regard to her own education and study of science.
The social norms of the time also acted as an obstacle for Maria. Women were expected to focus on domestic duties and marry at a young age. Pursuing a career in science was not considered a respectable profession for women. Maria faced criticism from her family and society for her interest in science. Despite these obstacles, Maria Mitchell was determined to pursue her passion for science. She spent countless hours studying the night sky, observing and recording celestial bodies. She also taught herself advanced mathematical concepts, such as calculus, which was not part of the regular curriculum for girls during her time.
Maria's hard work and dedication paid off when she discovered a comet in 1847. She became the first woman to discover a comet, and her achievement was recognized worldwide. Her discovery led to her being appointed as the first female professor of astronomy at Vassar College.
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You'fe driving on a straight road (in the +x direction) at a constant speed of 29 m/5. In 8 seconds, you speed up to 39 m/5 to pass a truck. (a) Assuming your car speeds up at a constant rate (constant force by the road on the tires), what is your average x component of velocity vavi.x duning this maneuver? V
avey.e
=m/s (b) How far do you go during this maneuver?
Answers
The average x-component of velocity vavi.x during this maneuver is 34 m/5 and the distance covered during this maneuver is 272 m. Given the following data:Initial speed of the car, u = 29 m/5
Final speed of the car, v = 39 m/5
Time, t = 8 s
Using the formula for average acceleration, we can find the average x-component of the velocity of the car during this maneuver.Average acceleration = (Change in velocity) / Time takena
= (v - u) / ta
= (39 - 29) / 8a
= 1.25 m/s²
(a) Now, using the formula for average velocity along x-axis, we can find the average x-component of the velocity of the car during this maneuver.
Average velocity along x-axis = (Change in position along x-axis) / Time takenvavi.x
= (vxi - uxi) / tvavi.x
= [(v + u) / 2]vavi.x
= [(39 + 29) / 2]vavi.x
= 34 m/5
(b) Using the formula for distance covered during uniformly accelerated motion, we can find the distance traveled by the car during this maneuver.
Distance covered = (Initial velocity x Time taken) + [(1 / 2) x Acceleration x Time taken²]s
= ut + (1/2)at²s
= 29 x 8 + (1/2) x 1.25 x (8)²s
= 232 + 40s
= 272 m
Therefore, the average x-component of velocity vavi.x during this maneuver is 34 m/5 and the distance covered during this maneuver is 272 m.
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An engineer wants to design a go-kart that can reach an acceleration of 20 m/s2
If the cart has a mass of 75 kg and can hold one person with a mass of 80 kg,
the engineer must design an engine that can produce a force of
newtons. *
Answers
This question involves the concepts of Newton's Second Law of Motion, Force, and acceleration.
The engineer must design an engine that can produce a force of "3100 N".
According to Newton's Second Law of Motion:
\(F = ma\)
where,
F = Force of engine = ?
m = mass carried by engine = mass of cart + mass of person = 75 kg + 80 kg
m = 155 kg
a = acclereration of the cart = 20 m/s²
Therefore,
\(F = (155\ kg)(20\ m/s^2)\)
F = 3100 N = 3.1 KN
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The attached picture shows Newton's Second Law of Motion.
a marble is rolling around in the back of a small toy wagon as the wagon is pulled along the sidewalk. when the wagon is stopped suddenly by a rock under one of the wheels, the marble rolls toward the front of the wagon. why does the marble keep going when the wagon stops?
Answers
The marble keeps going when the wagon stops because of the Inertia.
What is inertia?Inertia is defined as the property of an object to remain in a state of rest or uniform motion in a straight line unless acted upon by an external force. Newton's first law of motion, often known as the law of inertia, explains this.
Inertia is a fundamental concept in physics, and it applies to everything, from electrons to massive objects like planets and galaxies.
When a small toy wagon with a rolling marble is abruptly stopped by a rock under one of its wheels, the marble moves forward since it has a forward velocity due to its motion when the wagon was rolling, and because of inertia.
As a result, when the wagon comes to a halt, the marble is still moving forward, allowing it to keep going until it eventually reaches the front of the wagon.
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PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
I can help with the last question.
Explanation:
The force from the ball on the left ball will hit the ball next to it, bringing the force all the way to the right ball, and vice versa. Have a great day!
Answer:
gravity is pulls objects to the center of the earth.
friction is slows or stops motion when objects rub together.
magnetism is pushes or pulls objects containing iron or other metals.
Questions
Q1.
A teacher takes a group of students on to a sports field to measure the speed of sound in air.
The teacher fires a starting pistol.
It produces a loud bang and a flash of light at the same time.
The students take measurements.
Describe how the measurements are made and used to determine the speed of sound in air.
Answers
Answer:
Below
Explanation:
Measure distance to pistol .....
speed of light is nearly instantaneous in this situation (short distance)
measure time from flash to hearing the sound
speed of sound = distance to pistol / time to hear
calculate the height (in m) of a cliff if it takes 2.32 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.19 m/s. 7.37 correct: your answer is correct. seenkey 7.37 m (b) how long (in s) would it take to reach the ground if it is thrown straight down with the same speed? 0.649 correct: your answer is correct. seenkey 0.649 s
Answers
To calculate the height of the cliff and the time it takes for the rock to reach the ground when thrown straight down, we can use the equations of motion.
(a) Height of the cliff:
When the rock is thrown straight up, it reaches its highest point before falling back down. The time it takes for the rock to reach its highest point is equal to the time it takes for the rock to fall back down to the ground.
Using the equation:
s = ut + (1/2)at^2
Where:
s is the distance traveled (height of the cliff),
u is the initial velocity (8.19 m/s),
t is the time (2.32 s),
a is the acceleration due to gravity (-9.8 m/s^2, taking downward direction as negative).
Rearranging the equation:
s = ut + (1/2)at^2
s = (8.19)(2.32) + (1/2)(-9.8)(2.32)^2
s = 19.004 - 25.798
s = -6.794 m
Since the height of a cliff cannot be negative, we take the absolute value of the result:
Height of the cliff = |s| = 6.794 m
So, the height of the cliff is approximately 6.794 meters.
(b) Time to reach the ground when thrown straight down:
When the rock is thrown straight down with the same speed, the initial velocity (u) is still 8.19 m/s, but the acceleration due to gravity (a) remains -9.8 m/s^2.
Using the equation:
s = ut + (1/2)at^2
Where:
s is the distance traveled (height of the cliff, which is now negative),
u is the initial velocity (8.19 m/s),
t is the time we want to find,
a is the acceleration due to gravity (-9.8 m/s^2, taking downward direction as negative).
Substituting the known values:
-6.794 = (8.19)t + (1/2)(-9.8)t^2
Rearranging the equation:
-6.794 = 8.19t - 4.9t^2
Rearranging further:
4.9t^2 - 8.19t - 6.794 = 0
Solving this quadratic equation, we find two possible values for t: 0.828 seconds and 1.303 seconds. Since we are considering the time it takes to reach the ground, the valid solution is t = 0.828 seconds.
Therefore, when the rock is thrown straight down, it takes approximately 0.828 seconds to reach the ground.
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to unlock the fifth wheel the locking lever should be placed in the _____ position.
Answers
According to the information we can infer that the complete sentence would be: The locking lever should be placed in the "unlocked" position.
How to complete the sentence?To complete the sentence we have to read the available information and look for the term that completes it based in the context. In this case we can infer that the term is "unlocked" because to unlock the fifth wheel, the locking lever needs to be positioned in the "unlocked" position.
The fifth wheel is a coupling mechanism used in heavy-duty trucks and trailers to connect the trailer to the tractor unit. It allows for articulation and provides a pivot point for turning movements.
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two particles each having a mass of 5g and charge of 1.0×10^-7C stay in limiting equilibrium on a horizontal table with a separation of 10cm . The coefficient of friction between them and the table is same . Find the value of this coefficient.
Answers
The value of the coefficient is μ=0.18.
What is meant by Friction?A force that opposes this motion of the hands is activated when they brush against one another. The frictional force is the force resisting motion that is exerted in the direction that is counter to the direction that the hands are moving, and it is what creates heat energy.The force that prevents one solid item from moving across another is known as friction. Static, sliding, rolling, and fluid friction are the four main categories of friction.Many times, the uses of friction can be understood by imagining what would happen in their absence. You wouldn't be able to walk, operate a car, or grip anything if there was no friction. Pencils and pencils wouldn't function. Using brakes on a car or bicycle to halt requires friction as well.Find the value of this coefficient.
The particles are in equilibrium, meaning the net force on them is zero.
Thus, repulsion due to their charge = friction due to the table.
As the equilibrium is limiting, friction reaches its maximum value.
\(\frac{kQ^{2} }{r^{2} }\)=μmg
\(k=9*10^{9} Nm^{2} C^{-2}\)The electrostatic constant \(Q=10^{-7} C\) is the charge, and r=0.1m is the distance between the charges.
\(\frac{(9*10^{2})(10^{-7})^{2} }{(0.1)^{2} }\)=μ*\((5*10^{-3})(10)\)
Therefore, The answer is μ=0.18.
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Where can Microsoft users browse forums by topic, search existing questions and answers, or ask their own questions?
Answers
Group of answer choices.
A. Community and Forum Resources.
B. Get Live Help.
C. Tech Specs.
D. Top Support Issues.
Answer:
A. Community and Forum Resources.
Explanation:
Microsoft is a multinational corporation that designs and develops various types of software applications or programs such as Microsoft operating system (OS), Microsoft Word, Microsoft Excel, Microsoft Access, Microsoft PowerPoint, etc., to avail end users the ability to perform different tasks on their computers.
Whenever these users encounter a problem with any of these software applications or programs, they can easily go to the official forums and communities to get help from professionals and other end users who may have experienced such problems in the past. These community and forums are typically interactive in nature and as such serves its purpose often times.
Hence, Microsoft users can browse forums by topic, search existing questions and answers, or ask their own questions on Community and Forum Resources.
The question is attached
Answers
Answer:
The answer is B.
Explanation:
It is clear that the substance will be in liquid state above its melting point and below its boiling point.
A) This is incorrect. The substance is above the melting point but it is also above the boiling point (0 is greater than -183)
B) This is your correct answer. The substance is above the melting point and also below the boiling point.
C) This is incorrect. The substance is below both the melting point and the boiling point.
D) This is incorrect. The substance is drastically below the melting and boiling point.
Therefore , the only correct answer for this question would be B.
Find the resultant of forces P and Q as shown in Figure 3 . Use analytical method of vector addition
Answers
Figure 3 represents the analytical method of vector addition, as illustrated in the question. The resultant of forces P and Q can be obtained by using the Pythagoras Theorem and trigonometry.
Let the angle between P and Q be θ.
Force P makes an angle α with the horizontal and force Q makes an angle β with the horizontal.
The horizontal component of force P is P cosα, and the vertical component is P sinα.
The horizontal component of force Q is Q cosβ, and the vertical component is Q sinβ.
The horizontal component of the resultant R is equal to the sum of the horizontal components of P and Q, Rcosθ = P cosα + Q cosβ.
The vertical component of the resultant R is equal to the sum of the vertical components of P and Q, Rsinθ = P sinα + Q sinβ.
Applying the Pythagoras Theorem,
we have R² = (Rcosθ)² + (Rsinθ)².
Substituting the above equations,
we get R² = (P cosα + Q cosβ)² + (P sinα + Q sinβ)².
Simplifying the expression and using the trigonometric identity cos²θ + sin²θ = 1, we obtain R = sqrt(P² + Q² + 2PQcosθ).
The resultant of forces P and Q is R = sqrt(6² + 8² + 2(6)(8)cos60) = sqrt(36 + 64 + 48) = sqrt(148) ≈ 12.17 units.
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A gas, initially at 2.50 atm and 3.00 L, expands to a volume of 10.00 L. What is the new pressure of the gas? a. 0.75 atm d. 8.33 atm b. 1.33 atm e. 12.0 atm
Answers
The new pressure of the gas after expanding to a volume of 10.00 L is 0.75 atm. The correct answer is (a) 0.75 atm.
To find the new pressure of a gas that initially has a pressure of 2.50 atm and a volume of 3.00 L and expands to a volume of 10.00 L, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature and amount of gas remain constant.
Boyle's Law formula: P1 * V1 = P2 * V2
Plug in the initial pressure (P1) and volume (V1), as well as the final volume (V2).
(2.50 atm) * (3.00 L) = P2 * (10.00 L)
Solve for the new pressure (P2).
P2 = (2.50 atm * 3.00 L) / 10.00 L
Calculate P2.
P2 = 7.50 atm / 10.00 L = 0.75 atm
After growing to a volume of 10,000 litres, the petrol has a new pressure of 0.75 atm. The appropriate response is (a) 0.75 atm.
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which has the higher frequency, red light or blue light?
Answers
The shorter the wavelength, the higher the frequency.
Red light has a longer wavelength compared to blue light, therefore it has a lower frequency than blue light.