A subatomic particle that has a very small mass and has no chargea) beta minus particle b) Photonc) Nucleond) Positrone) Neutronf) Nuclide g) Netritionh) Quark I) Alpha Particle

To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

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Answer:

Explanation:

200.34

Answer:

Between F2 and 2F2

Explanation:

Diagram attached from Teachoo.

Link to website if you need to refer

https://www.teachoo.com/10838/3118/Convex-Lens---Ray-diagram/category/Concepts/

Answer:

5A

Explanation:

The answer is 49 and 131          

Answer:

…..

Explanation:

give brainiest

The answers are (a) |q| = 58.2 cm, M = -1.50, virtual, upright, shrunk; (b) |q| =, M = -, actual, substantially magnified; and (c) |q| = 6.5 cm, M = -1.68, virtual, upright, enlarged.

We can use the magnification formula and the thin lens equation to solve:

Where f is the lens's focal length, d_i is the image distance, and d_o is the object distance, the equation is: 1/f = 1/d_i + 1/d_o.

The formula for magnification is M = -d_i/d_o, where M stands for magnification.

For part (a), the object distance is d_o = -38.8 cm and the focal length is f = -19.4 cm.

1/-19.4 = 1/d_i + 1/-38.8

|d_i| = 58.2 cm

The image is virtual and smaller than the object (since the magnification is less than 1)

For part (b), the object distance is d_o = -19.4 cm, and the focal length is f = -19.4 cm.

1/-19.4 = 1/d_i + 1/-19.4

|d_i| = ∞

The image is at infinity, which means it is a real image and highly magnified (since the object distance is close to the focal length).

For part (c), the object distance is d_o = -9.70 cm, and the focal length is f = -19.4 cm.

1/-19.4 = 1/d_i + 1/-9.70

|d_i| = 6.5 cm

The image is virtual and larger than the object (since the magnification is greater than 1).
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Answer:

45,000 J

General Formulas and Concepts:

Energy

Kinetic Energy Formula: \(\displaystyle KE = \frac{1}{2}mv^2\)

Explanation:

Step 1: Define

Identify variables

[Given] m = 900 kg

[Given] v = 10 m/s

Step 2: Solve for KE

The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

The displacement of an object is the change in the position of the object.

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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Answer:

D. all regions of the spectrum

Explanation:

I did some research ; )

The energy released per kilogram of fuel used is 3.39 * 1014 J/Kg

Energy is released in a reaction because of  the breaking of bonds are well as formation of bonds.

The quantity of energy released in reactions differs according to the reaction type involved.

The energy released in nuclear reactions are far larger than that released in chemical reactions due to the release of nuclear energy from the nucleus.

The energy, E released in nuclear reactions is given by the formula below:

Energy per kilogram of reactants (in joules) = Energy per mole of reactants (in joules) / Total molar mass of reactants (in kg)

Energy per kilogram of reactants (in joules)  = \(1.60218 x 10^-^1^3 joules\) /  5 grams

Energy per kilogram of reactants (in joules)   =  3.39 * 1014 J/Kg

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The energy released per kilogram of fuel used is 5.632 × 10^-14 J/kg.

5 grammes, 0.005 kilogrammes, of reactants are provided.

Since 1 mile of tritium and 1 mile of deuterium are equal to 1 mole of "reactions," the sum of the "reactions" in 0.005 kilogrammes of reactants may be computed as follows:

Total moles of "reactions" in 0.005 kg of reactants = (0.005 kg / 5 g/mol)                            

                                                                                     = 0.001 mole.

The MeV per reaction must now be multiplied by the total number of "reactions" in order to get the total energy released by the "reactions."

Next, the energy must be converted from MeV to Joules.

MeV to Joules conversion factor is 1.6 10-13 J/MeV.

Total energy released = (MeV per reaction) x (number of reactions) x (conversion factor)

Total energy released = (17.6 MeV/reaction) x (0.001 mole) x (1.6 × 10^-13 J/MeV)

Total energy released = 2.816 × 10^-16 J

The total energy released by the "reactions" is 2.816 × 10^-16 J.

To determine the energy released per kilogram of fuel used, we need to divide the total energy by the mass of fuel used.

Total energy released per kilogram of fuel used = (total energy released) / (mass of fuel used)

Total energy released per kilogram of fuel used = (2.816 × 10^-16 J) / (0.005 kg)

Total energy released per kilogram of fuel used = 5.632 × 10^-14 J/kg

Therefore, the energy released per kilogram of fuel used is 5.632 × 10^-14 J/kg.

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Answer:

b. If Wire B carries a northward conventional current and lies to the left (west) of wire A, then it will experience an attractive force to the right (towards Wire A).

d. If Wire B carries a southward conventional current and lies to the left (west) of wire A, then it will experience a repulsive force to the left (away from Wire A).

Explanation:

Two parallel conductors experience attractive force when the current flowing in the conductors are in the same direction.

Also two parallel conductors experience repulsive force when the current flowing in the conductors are in opposite direction.

Therefore, b and d are the correct options.

b. If Wire B carries a northward conventional current and lies to the left (west) of wire A, then it will experience an attractive force to the right (towards Wire A).

d. If Wire B carries a southward conventional current and lies to the left (west) of wire A, then it will experience a repulsive force to the left (away from Wire A).

Explanation:

Hey there!!

Here,

Initial velocity (u) = 6m/s.

Acceleration (a) = 1.7m/s^2.

Time (t) = 4.2s.

final velocity (v) = ?

We have,

\(a = \frac{v - u}{t} \)

Putting their values,

\(1.7 = \frac{v - 6}{4.2} \)

7.14 = v - 6

v = 7.14 + 6

Therefore, the final velocity is 13.14 m/s.

Hope it helps....

Answer:

Energy in carriage (Potential energy) = 4,116 J

Explanation:

Given:

Mass of baby = 20 kg

Height = 21 m

Find:

Energy in carriage (Potential energy)

Computation:

The energy accumulated in an object as a result of its location relative to a neutral level is known as potential energy.

In carriage accumulated energy is potential energy.

Energy in carriage (Potential energy) = mgh

Energy in carriage (Potential energy) = (20)(9.8)(21)

Energy in carriage (Potential energy) = 4,116 J

Answer:

the light is reflected, because light is white when the spectrum is combined, and white reflects white. that's why wearing a white shirt outside feels cooler than wearing a black shirt, since it doesn't absorb light.

Answer:

All the light is reflected, so the shirt appears white.

Explanation:

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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South

Explanation:

The magnetic force F on a point charge moving with a velocity v in the presence of a magnetic field B is given by

\(\vec{\textbf{F}} = q\vec{\textbf{v}}\textbf{×}\vec{\textbf{B}}\)

and according to the right-hand rule, an upward magnetic force on a proton moving westward is only possible if the magnetic field is directed southward.

Please find attached photograph for your answer.

The skid mark will be 25.21 m long.

From the question given above, the following data were obtained:

Initial velocity (u) = 22.0 m/s

Final velocity (v) = 0 m/s

Deceleration (a) = –9.6 m/s²

The displacement can be obtained as follow:

0² = 22² + (2 × –9.6 × s)

0 = 484 – 19.2a

0 – 484 = –19.2s

–484 = –19.2s

\(s = \frac{-484}{-19.2} \\\\\)

Therefore, the skid mark is 25.21 m long

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ANSWER

Neutrons and energy

EXPLANATION

Nuclear fission is a reactive process in which the nucleus of an atom splits into two (or more) nuclei causing a release of gamma rays, kinetic energy and free neutrons.

Therefore, the answer is "neutrons and energy".

The concept of an inverse squared relationship explains the behavior of intensity of light and distance of the light source. As the distance of the light source increases, the intensity of light decreases.

The law of inverse square law says that intensity equals the inverse of the square of the distance from the source.

Mathematically, the formula for the inverse square law is given as;

I ∝ 1/r²

where;

The intensity of light can be defined as the measure of the amount of power emitted by a given surface or reflected by the surface.

Thus, the inverse square law is all about the inverse relation between the  intensity of light or power output of a given surface to the distance of the light source.

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The girl can go up the escalator by 2 meters in 2 minutes if a girl runs up the down escalator in the mall and escalator is moving with a velocity of 27 m/min and the girl is running with a velocity of 28 m/min,

When the girl runs up the down escalator, her effective velocity is the difference between her velocity and the velocity of the escalator. In this case, the escalator is moving down with a velocity of 27 m/min, while the girl is running up with a velocity of 28 m/min. So, her effective velocity is:

Effective velocity = Girl's velocity - Escalator's velocity

= 28 - 27

= 1 m/min

Therefore, the girl is moving up the escalator at a speed of 1 m/min.

To calculate how far up the escalator she can go in 2 minutes, we need to use the formula:

Distance = Speed x Time

In this case, the speed is the effective velocity of the girl, which is 1 m/min, and the time is 2 minutes. So, the distance she can go up the escalator is:

Distance = Speed x Time

= 1 x 2

= 2 meters

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Answer:

Equilibrium

Explanation:

Answer:

211.2 kg:m/s

Explanation:

Mark brainily

Answer:

deception

Explanation:

Answer:

Explanation:

Let the spring constant of spring A and B be k₁ and k₂ . Mass of box X and Y be m₁ and m₂ .

Force created in spring which is stretched by d is kd where k is spring constant .

At her lab in Orlando, Florida,

k₁ x .0204 m = m₁ g where g is acceleration due to earth's gravity

k₁ = 49 m₁ g

At a research station on the moon

k₁ x .34 x 10⁻² m = m₁ g₁ where g₁ is acceleration due to gravity at moon

k₁  = 294 .11 m₁ g₁

49 m₁ g = 294 .11 m₁ g₁

g = 6.0022  g₁

At a research station on the moon

k₁ x .54 x 10⁻² m = m₂ g₁

k₁ = 185.18 m₂ g₁

294 .11 m₁ g₁ = 185.18 m₂ g₁

1.588 m₁ =  m₂

1 )

At her lab in Orlando, Florida,

k₁ x d  = m₂ g , where d is the new stretch that is to be calculated .

185.18 m₂ g₁ d =m₂ g

185.18 d  g₁ = g

185.18 d  g₁ = 6.0022  g₁

d = .03241 m

= 3.24 cm .

2 )

At a research station on the moon

when Block Y is hanging from Spring B

k₂ x .013   = m₂ g₁

k₂ = 76.92 m₂ g₁

At her lab in Orlando, Florida,

Spring B stretch when Block X is hanging from it

k₂ d₁ = m₁ g

76.92 m₂ g₁ d₁ = m₁ g

76.92 m₂ g₁ d₁ = m₁ 6.0022  g₁

76.92 m₂  d₁ = m₁ 6.0022  

12.815  x  1.588 m₁ x  d₁ = m₁

d₁ = .049 m

= 4.9 cm .

In this exercise we have to use the knowledge of springs to calculate the distance from it, that way:

A)d=3.24 cm

B)d=4.9 cm

So, before starting the calculations, we have to organize the values ​​and put everything in function of a single unknown such as:

\(k_1 * 0.34 * 10^{-2} m = m_1 g_1\\ k_1 = 294 .11 m_1 g_1\\49 m_1 g = 294 .11 m_1 g_1\\g = 6.0022 g_1\\k_1 *0 .54 * 10^{-2} m = m_2 g_1\\k_1 = 185.18 m_2 g_1\\294 .11 m_1 g_1 = 185.18 m_2 g_1\\1.588 m_1 = m_2\)

A) By calculating the distance we find that:

\(k1_1 * d = m_2 g\\185.18 m_2 g_1 d =m_2 g\\185.18 d g_1 = g\\185.18 d g_1 = 6.0022 g_1\\d = 0.03241 m= 3.24 cm\)

B) So now calculating the distance from the lab to the moon, so:

\(k_2* 0.013 = m_2 g_1\\k_2 = 76.92 m_2 g_1\\k_2 d_1 = m_1 g\\76.92 m_2 g_1 d_1 = m_1 g\\76.92 m_2 g_1 d_1 = m_16.0022 g_1\\76.92 m_2 d_1 = m_1 6.0022\\12.815 * 1.588 m_1 * d_1= m_1\\d_1 = 0.049 m = 4.9 cm\)

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The steps of the experiment "Sky is Falling" are listed below:

This refers to the systemic activity that is done in order to make a discovery or to test a hypothesis, usually through the use of the scientific method.

Hence, we can see that the steps to perform the "Sky is Falling" experiment is listed above and they are:

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The expression \(X^{N} + Y^{N}\)is not divisible by X - Y (where Y is not equal to 0).

To determine whether the expression \(X^{N} + Y^{N}\) is divisible by X - Y (where Y is not equal to 0), we can use the factor theorem and the property of binomial expansion.

The factor theorem states that if a polynomial P(x) is divisible by (x - a), then P(a) equals zero. In our case, if \(X^{N} + Y^{N}\) is divisible by (X - Y), then when we substitute X = Y into the expression, the result should be zero.

Let's substitute X = Y into the expression:

\(Y^{N} + Y^{N}\)

Since \(Y^{N}\) is equivalent to \(Y^{N}\) , the expression becomes:

2(\(Y^{N}\))

We can see that the expression 2(\(Y^{N}\)) is not equal to zero unless Y is equal to zero. Therefore, if Y is not equal to zero, \(X^{N} + Y^{N}\) is not divisible by X - Y.

In summary, unless Y is equal to zero, the expression \(X^{N} + Y^{N}\) is not divisible by X - Y according to the factor theorem and the given condition.

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Answer:

organizing

Explanation:

thinking about where things should go, to make it so that everybody has an easy experience when inside of my store.

Answer:

Explanation:

2as=vf^2-Vi^2

vf=30 m/s

vi= 0 m/s

a=g=9.8 m/s^2

s=vf^2-Vi^2/2a

s=(30)²-(0)²/2*9.8

s=900-0/19.6

s=45.9=46 m

Answer:

W = 735.75[J]

Explanation:

Work is defined as the product of force by distance. Therefore we can use the following equation.

\(W=F*d\)

where:

W = work [J] (units of Joules)

F = force [N] (units of Newtons)

d = distance = 3 [m]

But first, we must determine the force that is equal to the product of mass by gravity (weight of the body).

\(F=m*g\\F=25*9.81\\F=245.25[N]\)

\(W=F*d\\W=245.25*3\\W=735.75[J]\)