Answer:
100m
Explanation:
original distance crossed: 50m
final distance crossed: 50m
50m +50m = 100m
Car A is moving at a speed of 45km/h towards car B which is moving at a speed of 55km/h. if the two car were initially separated at a distance of 150km, determine how long it will take the two cars to meet?
The time taken by the cars to meet is 5.4 x 10³ s.
Speed of car A, v₁ = 45 km/h = 12.5 m/s
Speed of car B, v₂ = 55 km/h = 15.27 m/s
Distance between the cars, d = 150 km = 15 x 10⁴m
The expression for the time taken by the cars to meet can be given as,
Time = Distance/Average speed
t = d/(v₁ + v₂)
Applying the values of d, v₁ and v₂.
t = 15 x 10⁴/(12.5 + 15.27)
t = 15 x 10⁴/27.77
t = 5.4 x 10³ s
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PLEASE HELP ASAPPPPP!!!!!!!!!!!!!!!!
A steel cable lying flat on the floor drags a 20 kg block across a horizontal, frictionless floor. A 100 N force applied to the cable causes the block to reach a speed of 4.2 m/s in a distance of 2.0 m.
What is the mass of the cable?
Answer:
m_cable = 2,676 kg
Explanation:
For this exercise we must look for the acceleration with the kinematic ce relations
v² = v₀² + 2 a x
since the block starts from rest, its initial velocity is vo = 0
a = v² / 2x
a = 4.2² /(2 2.0)
a = 4.41 m / s²
now we can use Newton's second law
Note that the mass that the extreme force has to drag is the mass of the block plus the mass of the cable.
F = (m + m_cable) a
m_cable = F / a -m
m_cable = 100 / 4.41 - 20
m_cable = 2,676 kg
why should a household worker work with dignity and integrity
Answer:
workers must have a legitimate respect for the common good whose advancement they serve.
Explanation:
Answer:
so they don't get fired and they should be over all nice people
Explanation:
Which number represents runoff on the hydrologic cycle diagram?
1
2
3
4
Answer:
number 3
Explanation:
3 represents runoff
Runoff is the water collected after rainfall that drains from the surface area of land. It will be tricky to choose 4 which is likely a smaller waterbody draining to a bigger waterbody
hope it helped
A stone is thrown towards a wall with an initial velocity of v0=19m/s and an angle = 71 with the horizontal, as illustrated in the figure below. The stone reaches point A at the top of the wall, t=3.5s after being thrown. Determine (a) the height h of the wall, (b) the maximum height H of the path of the stone, (c) the horizontal distance between the launching point and point A and (d) the horizontal reach of the stone if the wall did not exist
Answer:
(a) 2.85 m
(b) 16.5 m
(c) 21.7 m
(d) 22.7 m
Explanation:
Given:
v₀ₓ = 19 cos 71° m/s
v₀ᵧ = 19 sin 71° m/s
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
(a) Find Δy when t = 3.5 s.
Δy = v₀ᵧ t + ½ aᵧ t²
Δy = (19 sin 71° m/s) (3.5 s) + ½ (-9.8 m/s²) (3.5 s)²
Δy = 2.85 m
(b) Find Δy when vᵧ = 0 m/s.
vᵧ² = v₀ᵧ² + 2 aᵧ Δy
(0 m/s)² = (19 sin 71° m/s)² + 2 (-9.8 m/s²) Δy
Δy = 16.5 m
(c) Find Δx when t = 3.5 s.
Δx = v₀ₓ t + ½ aₓ t²
Δx = (19 cos 71° m/s) (3.5 s) + ½ (0 m/s²) (3.5 s)²
Δx = 21.7 m
(d) Find Δx when Δy = 0 m.
First, find t when Δy = 0 m.
Δy = v₀ᵧ t + ½ aᵧ t²
(0 m) = (19 sin 71° m/s) t + ½ (-9.8 m/s²) t²
0 = t (18.0 − 4.9 t)
t = 3.67
Next, find Δx when t = 3.67 s.
Δx = v₀ₓ t + ½ aₓ t²
Δx = (19 cos 71° m/s) (3.67 s) + ½ (0 m/s²) (3.67 s)²
Δx = 22.7 m
advantages and disadvantages of magnetic waves in transportation of goods
Answer:
Advantages: has the best magnetic properties, good price, good strength, and are easy to process into special shapes.
Disadvantages: are not resistant to high temperature and corrosion, and are fragile.
Explanation:
a stone dropps 7,11m how long will it take it to fall
The time it takes the stone to fall from a height of 7.11 m is 1.2 seconds.
What is time?Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.
To calculate the time it takes the stone to drop from an height of 7.11 m, we use the formula below.
Formula:
H = ut+gt²/2............ Equation 1Where:
H = Heightu = Initial velocityt = Timeg = Acceleration due to gravityFrom the question,
Given:
u = 0 m/sH = 7.11 mg = 9.8 m/s²Substitute these values into equation 1 and solve for t.
7.11 = (0×t)+9.8×t²/27.11 = 4.9t²t² = 7.11/4.9t² = 1.451t = √1.451t = 1.2 secondsHence, the time it takes the stone to fall is 1.2 seconds.
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Gold forms a solid solution with silver. Since the densities of pure gold and silver are 19.32 g/cm³ and 10.49 g/cm³, respectively, calculate the number of gold atoms per cubic centimeter for a silver-gold alloy containing 10% Au and 90% Ag by weight.
There are 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.
The density of a binary alloy can be calculated using the following equation:
ρ = w1ρ1 + w2ρ2
where,
ρ = density of the alloy
w1 and w2 = weight fractions of the two components (in this case, gold and silver)
ρ1 and ρ2 = densities of the pure components.
We are given that the alloy contains 10% gold and 90% silver by weight, so we can calculate the weight fractions as:
\(w_{Au}\) = 0.10
\(w_{Ag}\) = 0.90
We are also given the densities of pure gold and silver as:
ρ_Au = 19.32 g/\(cm^{3}\)
ρ_Ag = 10.49 g/\(cm^{3}\)
Now we can substitute these values into the density equation to find the density of the alloy:
ρ = \(w_{Au}\)ρ_Au +\(w_{Ag}\)ρ_Ag
ρ = (0.10)(19.32 g/\(cm^{3}\)) + (0.90)(10.49 g/\(cm^{3}\))
ρ = 11.08 g/\(cm^{3}\)
Next, we need to calculate the number of gold atoms per cubic centimeter in the alloy.
To do this, we can use Avogadro's number and the atomic weights of gold and silver:
\(N_A\) = 6.022 × \(10^{23}\) atoms/mol
Aum = 196.97 g/mol
Agm = 107.87 g/mol
The number of gold atoms:
\(n_{Au}\) = (\(w_{Au}\)ρ/ Aum) × \(N_{A}\)
Substituting the values, we get:
\(n_{Au}\) = (0.10 × 11.08 g/\(cm^{3}\)/ 196.97 g/mol) × 6.022 × \(10^{23}\) atoms/mol
\(n_{Au}\) ≈ 3.37 × \(10^{22}\) atoms/\(cm^{3}\)
Therefore, there are approximately 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.
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What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 kilograms?
Answer:
Explanation:
f =ma
F 2500 kg (20m/s-0m/s/15s)
F=2500kg(1.33m/s²)
F =3,325 N
f =ma, F 2500 kg (20m/s-0m/s/15s) and F=2500kg(1.33m/s²), F =3,325 N.
What is Force?A push or pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on each of the objects.
The force is no longer felt by the two objects when the interaction ends. Only when there is interaction do forces actually exist.
Action-at-a-distance forces are those that happen even when the two interacting objects are not physically touching each other but are nevertheless able to push or pull against each other despite their physical separation. Gravitational forces are an example of action-at-a-distance forces.
Therefore, f =ma, F 2500 kg (20m/s-0m/s/15s) and F=2500kg(1.33m/s²), F =3,325 N.
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POINTS + BRAINLIEST TO CORRECT ANSWER
In old Polaroid cameras, the image was projected on film that developed inside the camera. The developed image was then ejected from the camera as a printed photograph. The standard film size for one popular camera was 79 mm square. The film was 116 mm behind the lens.
If you wanted a picture of your 1.8-m-tall friend to fill half the frame, how far away from you did she need to stand?
100 points + Brainliest to correct answer
Answer:
5.3 m
Explanation:
Your friend is 1800 mm tall, and you want them to fill half the frame (79 mm / 2 = 39.5 mm).
The film is 116 mm behind the lens. Using similar triangles:
x / 1800 = 116 / 39.5
x = 5286
Rounded to two significant figures, your friend should stand 5.3 meters away.
Given an average cell is ten times the mass of a bacterium. The mass of a bacterium is 10-15 kg. And a person's mass is 65 kg.
Given the mass of the cell is 1 * 10⁻¹⁴ kg, the number of cells in the 65 kg person is 6.5 * 10¹⁵ cells.
What is the number of cells in a person weighing 65 kg?The number of cells in a human is calculated as follows:
The mass of an average cell is ten times the mass of a bacterium.
The mass of a bacterium = 1 * 10⁻¹⁵ kg
mass of an average cell = 10 * 1 * 10⁻¹⁵ kg = 1 * 10⁻¹⁴ kg
Number of cells = mass of person/mass of cell
Number of cells = 65 kg/1 * 10⁻¹⁴ kg
Number of cells = 6.5 * 10¹⁵ cells.
In conclusion, the number of cells is obtained by dividing the mass of the person by the mass of a average cell.
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Note that the complete question is given below:
Assuming the mass of an average cell is ten times the mass of a bacterium (which is 10⁻¹⁵ kg): Calculate the number of cells in a human assuming the mass of the person is 10² kg.
A spherical bowling ball of mass 7 kg and radius 0.18 m rolls down a hill that has a vertical height of 7 m. If the ball started from rest at the top, what is its angular momentum at the bottom of the hill? Use two sig figs.
Answer:
er so ue 0.984 kg study your self brhh
Chemical bonds are broken in which molecules? Question 1 options: C6H12O6 & H2O CO2 & O2 O2 & C6H12O6 CO2 & H2O
Answer:O2 & C6H12O6
Explanation:
C6H12O6 + 6O2-> 6CO2 + 6H2O
O2 and C6H12O6 molecules' chemical connections are disrupted.
What is chemical bond?A chemical bond, which is a powerful attraction between atoms, ions, or molecules, enables the construction of molecules. The connection could be brought on by electrostatic force.Overview of the fundamental types of... Bonds in chemical formula solid chemical ties. Covalent or ionic bonds are two different types of chemical bonding.A chemical bond is an attraction between two atoms or ions. To form bonds, atoms exchange or swap their valence electrons. Atoms need to form chemical bonds in order to attain a complete outer energy level, which is the most stable arrangement of electrons.A chemical bond is the binding force that binds various constituents (atoms, ions, etc.) in diverse chemical species.
C6H12O6 + 6O2-> 6CO2 + 6H2O
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If a component obeys Ohm’s Law, then decreasing the temperature of a material will ___________ the resistance.
A. Keep constant
B. Increase
C. Not enough info
D. Decrease
If a component obeys Ohm’s Law, then decreasing the temperature of a material will decrease the resistance.
According to Ohm's Law, the resistance of a conductor is directly proportional to its temperature, and inversely proportional to its cross-sectional area and the length of the conductor.
However, for most conductors, the change in resistance due to a change in temperature is relatively small, and can be approximated using the temperature coefficient of resistance (TCR) of the material. The TCR is a measure of how much the resistance of a material changes per degree change in temperature.
In general, for metallic conductors, the TCR is positive, which means that the resistance increases as the temperature increases, and decreases as the temperature decreases. Therefore, if the temperature of a material decreases, the resistance of the material will also decrease, assuming that the other factors affecting resistance (such as length and cross-sectional area) remain constant.
Decreasing the temperature of a material that obeys Ohm's law generally decreases the resistance because the charged particles in the material move slower, resulting in less resistance to current.
Explanation:If a component obeys Ohm’s Law, resistance in most common materials generally increases with temperature. Therefore, decreasing the temperature of a material will normally decrease the resistance. This is because the charged particles in the material move more slowly at lower temperatures, leading to less resistance to current flow.
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calculate the power required of a 60- kg person climbs a tree 5 meters high in 10 seconds. Acceleration due to gravity is 10 m/s 2.
The Power is equal to 300 J/s or 300 Watts.
A force that causes a displacement is what the term "quantity work" refers to. The duration of this force's action to produce the displacement has nothing to do with work or power. Sometimes the task is completed quite fast, and other times it is completed fairly slowly. For instance, it takes an unusually long time for a rock climber to raise her body a few meters up the cliff's edge. A trail hiker, on the other hand, could quickly raise her body a few meters if she chooses the simpler route up the mountain. Even though they both perform the same amount of labor, the hiker completes it in a lot less time than the rock climber.
The formula for power is ( P = \(\frac{W}{t}\) ) or ( P = \(\frac{m \times a \times d}{t}\) )
m ( mass ) = 60 kg
a ( acceleration ) = 10 m/s²
d ( distance ) = 5 m
t ( time ) = 10 s
P ( Power ) = ?
P = \(\frac{m \times a \times d}{t}\)
= \(\frac{60\times 10 \times 5}{10}\)
= \(\frac{3000}{10}\)
= 300 J/s
= 300 Watts
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A cube is on the ground. Each side is 50cm. The cube has a mass of 20kg. How much pressure does it exert on the ground?
Answer:
We know that,
Pressure = Force ÷ Area
First let's find the force of the cube.
F = m × g
= 20 kg × 10 ms⁻²
= 200N
Now let us find the Area of the cube.
A = 6 a²
= 6 × \(\frac{50}{100}\) × \(\frac{50}{100}\)
= 1.5 m²
Now let us find the pressure.
Pressure = Force ÷ Area
= 200 N ÷ 1.5 m²
= 133 . 33 N m⁻² / 133 . 33 Pa
Hope this helps you :-)
Explanation:
We know that
F = ma
Here,
a = g = 10 m/s²
So,
F = mg
=> F = 20 × 10
=> F = 200 N
now,
As 1 m = 100 cm
50 cm = 50/100 = 0.5 m
=> SA of cube = 6a²
=> SA = 6(0.5)²
=> SA = 6 × 0.25
=> SA = 1.5 m²
Now,
P = F/A
=> P = 200/1.5
=> P = 2000/15
=> P = 400/3
=> P = 133.3 Pa
What's a good way to start the problem?
Answer: Start by writing down the problem in your own words using as much detail as possible. Be as specific as possible in your description.
Explanation:
An elephant of mass 2800kg has feet of average area of 200 cm2. A vulture of mass 12 kg walks beside the elephant on a muddy area, the average area of the feet of the vulture is 2.0 cm2. Which one is likely to sink? Explain your answer showing any necessary calculations.
Explanation:
The formula we are going to use is
Pressure = F/A
Elephant:
First, we need to convert weight into newtons.
1kg=9.8 newtons, so 2800kg × newtons = 27440newtons
For 4 feet= 200×4= 800cm^2
Convert the area to meter squared using the following:
1 centimeter squared = 0.0001 meters squared
800cm^2×0.0001= 0.08m^2
Pressure=F/A
Pressure= 27440/0.08
The pressure exerted on the ground by the elephant is 343000 Pascals.
Vulture:
12kg×9.8=117.6newtons
for 2 feet= 2.0×2=4cm^2
4×0.0001=0.0004m^2
117.6/0.0004= 294000 Pascals
To compare the pressure, just do a ratio of the elephant's pressure to vulture's pressure.
343000/294000≈ 1.17
So the pressure is about 1 times bigger.
Keep in mind that the elephant has 4 feet, which help to increase the area which in turn decrease the pressure.
Elephant's feet are more likely to sink as elephant's feet apply more pressure on the muddy area.
What is pressure?Pressure is defined as the thrust per unit area. Thrust is the perpendicular force applied. Its SI unit is pascals.
So, P = T/A
Here,
Mass of elephant = 2800 kg
Force applied = 2800 × 9.8 ( 1kg = 9.8 N)
= 27440 N
Average feet area of elephant = 200 cm2
Since an elephant has 4 feet,
200 × 4 = 800 cm2 = 0.08 m2
Now, P = F/A
27440/0.08 = 343000 pascals
For the vulture,
Force of the vulture = 12 × 9.8 = 117.6 N
Area = 2.0 × 2 = 4cm2 = 0.0004 m2
Now, P = 117.6 / 0.0004 = 294000 pascals
So, pressure applied by the elephant's feet is more than the pressure applied by the vulture's feet. Therefore, the elephant's feet will sink.
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Pam, wearing a rocket pack, stands on frictionless ice. She has a mass of 40.0 kg. The rocket supplies a constant force for 22 m and Pam acquires a speed of 62 m/s. What is the magnitude of the force?
The force is 3496 N
What is the acceleration?Acceleration is the rate at which an object's velocity changes over time. Mathematically, acceleration is defined as the change in velocity (delta v) divided by the change in time.
The unit of acceleration in the International System of Units (SI) is meters per second squared (m/s²). This means that if an object's velocity changes by 1 meter per second (m/s) every second, its acceleration is 1 m/s².
We know that;
v^2 = u^2 + 2as
Where u = 0
v^2 = 2as
a = v^2/2s
a = (62)^2/ 2 * 22
a = 87.4 m/s^2
Force = ma
= 40 Kg* 87.4 m/s^2
= 3496 N
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Which of the following statements are true?
a. By convention, the direction of a current is taken to be the direction of flow for negative charges.
b. When an electric field is applied to a conductor, the free electrons move only in the direction opposite the applied electric field.
c. Current is the total amount of charge that passes through a conductor's full cross section at any point per unit of time.
d. In order to maintain a steady flow of current in a conductor, a steady force must be maintained on the mobile charges.
e. In a circuit, current is delivered by the positive terminal of a battery, and it is used up by the time it returns to the negative terminal of the battery.
Answer:
A, C, D and E are the true statement about current flowing.
You have a great summer job working in a cancer research laboratory. Your team is trying to construct a gas laser that will give off light of an energy that will pass through the skin but be absorbed by cancer tissue. You know that an atom emits a photon (light) when an electron goes from a higher energy orbit to a lower energy orbit. Only certain orbits are allowed in a particular atom. To begin the process, you calculate the energy of photons emitted by a Helium ion in which the electron changes from an orbit with a radius of 0.30 nanometers to another orbit with a radius of 0.20 nanometers. A nanometer is 10-9m. The helium nucleus consists of two protons and two neutrons. (In reality, the energy levels of electrons in atoms are governed by quantum mechanics, but this classical calculation is a good first estimate.)
Answer:
ΔE = 7.559 eV , λ = 1,645 10⁻⁷ m
Explanation:
For this exercise we can use the Bohr model for ionized atom with only one free electron,
r_n = n² a₀ / Z
E_n = -13,606 Z² / n²
Where a₀ is the Bohr radius of the hydrogen atom (a₀ = 0.0529 nm), Z is the atomic number of the atom under study and 13.606 eV is the energy of the ground state of Hydrogen.
In our case the Helium atom has two protons Z = 2
let's calculate the quantum number and the energy of each orbit
r_n = 0.30 nm
n₁ = √ (r_n Z / a₀)
n₁ = √ (0.30 2 / 0.0529)
Note that we do not have to reduce the radius since they are all in nanometers
n₁ = 3.3
since n is an integer we approximate it to
n₁ = 3
r_n = 0.20 nm
n₂ = √ (0.2 2 / 0.0529)
n₂ = 2.7
To approximate this value we must assume that there could be some error in the medicinal radio,
n₂ = 2
having the quantum numbers of the two radius we can calculate their energy
E₃ = - 13,606 2²/3²
E₃ = - 6.047 eV
E₂ = -13.606 2²/2²
E₂ = -13.606 eV
the energy of the emitted photon is
ΔE = E₃ - E₂
ΔE = -6.047 + 13.606
ΔE = 7.559 eV
You do not indicate in the exercise if you want the energy or the wavelength of the photon,
to find the wavelength We use the Planck relation
E = h f
c = λ f
E = h c /λ
λ = h c / E
we must reduce the energy to the SI system
E = 7.559 ev (1.6 10⁻¹⁹ J / 1eV) = 12.09 10⁻¹⁹ J
λ = 6.63 10⁻³⁴ 3 10⁸ / 12.09 10⁻¹⁹
λ = 1,645 10⁻⁷ m
Examine the boxes below. Both boxes are identical to one another. The mass of each box is concentrated in the very center, so the center of mass is in the
middle of the box. (Remember that mass is similar to weight) The arrows represent gravity pulling down on the center of mass of each box. Which of the boxes
represents a stable system? if you were to give that box a small push, what would happen to its state of equilibrium? Describe how a disturbance to this box
would affect it. Use the terms center of mass and equilibrium in your response.
According to the Declaration of Independence, from where does government get its power?
from God
from a written constitution
from elected representatives
from the consent of the governed
The government derive its power according to the Declaration of Independence is the document that declare the freedom of the people. The document was approved by the Continental Congress on July 4, 1776.
Below are the main messages of the declaration of independence.
(1) God made all men equal and gave them the rights of life, liberty, and the pursuit of happiness.
(2) The main business of government is to protect these rights.
(3) If a government tries to withhold these rights, the people are free to revolt and to set up another government.
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A ball of clay is moving at a speed of 12 m/s collides and sticks to a stationary ball of clay. If each ball has a mass of 13 kg, what's the combined velocity of the two balls of clay after the collision
Answer:
p_{f} = 6 m / s
Explanation:
We can solve this exercise using conservation of momentum. For this we define a system formed by the two balls, so that the forces during the collision have been intense and the moment is preserved
Initial instant. Before the crash
p₀ = m v +0
Final moment. Right after the crash
\(p_{f}\) = (m + m) v_{f}
how the moment is preserved
p₀ = p_{f}
m v = 2 m v_{f}
v_{f} = v / 2
we calculate
v_{f} = 12/2
p_{f} = 6 m / s
what happens if you leave a drink on top of the car and drive off
Answer:
it spills or sometimes it doesn't
Explanation:
depends on the road and speed
The planet Skaro has 4 times the gravitational field strength and the same radius as the Earth.
How does the mass of the planet Skaro compare with the mass of Earth?
Answer: mSkaro = 4mEarth
Explanation:
Trust me
Drag each label to the correct location on the image
Identify the particles and characteristics on this model of an atom
(Provide picture to explain more clearly)
A- Positively Charged
B- Electron
C- Proton
E- Neutron
D- Negatively Charged
Answer:
you cant really give any answers because i cant tell u were to drag
To decrease the amount of force required to do work, you can increase the distances applied. True or False
Answer:
True
Explanation:
At the surface of a certain planet, the gravitational acceleration g has a magnitude of 20.0 m/s^2. A 22.0-kg brass ball is transported to this planet.
What is (a) the mass of the brass ball on the Earth and on the planet, and (b) the weight of the brass ball on the Earth and on the planet?
Answer:
a, 22 kg and 22 kg
b, 215.8 N and 440 N
Explanation:
a
The mass of the ball remains constant and unchanged irrespective of where it has been to, need to go or is going. So, basically the mass of the ball on earth is as the same mass of the ball on the said planet, 22 kg
b
The weight of any object factors in the acceleration due to gravity of the said area(or planet).
W = mg, with m being the mass and g being the acceleration due to gravity.
On earth
W = 22 * 9.81 = 215.8 N
On the said planet,
W = 22 * 20 = 440 N
Do therefore, the weight is 215.8 N on earth and 440 N on the planet