A thin block of soft wood with a mass of 0.072 kg rests on a horizontal frictionless surface. A bullet with a mass of 4.67 g is fired with a speed of 619 m/s at a block of wood and passes completely through it. The speed of the block is 22 m/s immediately after the bullet exits the block.

Required:
Determine the speed of the bullet as it exits the block.

Nuclear power plants have backup generators to ensure that essential equipment, such as cooling systems, can continue to function in the event of a power outage or other emergency.

Nuclear power plants rely on a constant supply of electricity to operate the equipment that controls the nuclear reaction and cools the reactor. If the power supply is interrupted, the reactor can overheat and damage can occur. Backup generators provide power to essential equipment, such as cooling systems, that keep the reactor and spent fuel pools from overheating.  If the backup generators fail, there is a risk of a nuclear accident, as was seen in the disaster in 2011, where the failure of backup generators led to a loss of cooling and a major nuclear incident.

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Answer:

Astronomers use computer models to simulate the process of galactic evolution through mergers and collisions. These models are based on our current understanding of the physical laws that govern the behavior of matter and energy in the universe. By running simulations of galactic mergers and collisions, astronomers can test their understanding of how these physical processes work in practice and how they contribute to the formation and evolution of galaxies.

One way that astronomers might test their understanding of the physical processes of the universe is by comparing the predictions of their models to observations of real galaxies. For example, if a model predicts that a particular type of galaxy should have a certain shape, size, or distribution of stars, astronomers can compare these predictions to observations of actual galaxies to see if they match up. If there is a discrepancy between the model's predictions and the observations, this can indicate that there are some physical processes that are not well understood or included in the model.

Another way that astronomers might test their understanding is by looking for patterns or trends in the properties of galaxies that are consistent with the predictions of their models. For example, if a model predicts that galaxies that have undergone a recent merger should have a particular distribution of gas and dust, astronomers can look for evidence of this pattern in observations of real galaxies. If they find that the predicted pattern is consistently observed in a large sample of galaxies, this can provide support for the model's predictions and the physical processes that it includes.

Overall, computer models of galactic evolution through mergers and collisions provide a powerful tool for astronomers to test their understanding of the physical processes of the universe. By comparing the predictions of their models to observations of real galaxies and looking for consistent patterns and trends, astronomers can refine their understanding of how galaxies form and evolve over time.

The type of dispersion in the Debye model is linear.

When it is at the longer wavelength limit, the density of states is referred to as quadratic.

D(ω) = [3ω²/2π²c³] s rad⁻¹m⁻³

This has a maximum frequency ωD, known as the Debye frequency. In the three dimensions, there are 3 degrees of freedom per atom.

So, the number of phonon modes present here is 3n.

3n = (0→ωD)∫D(ω)dω

Where n is known as the atomic density of the phonon.

We know that, for a frequency that is above the Debye frequency there will be no phonon modes present.

The Debye frequency,

ω³D = 6π²nc³

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Answer:

-1.61 k (N)

Explanation:

L = 1.2 m, I  = 3.5 A, B = 0.50 T, α = 40°

F = I L x B (cross product)

F = I L(sinα i - cosα j) x B (-i)

= -IBLcosα k

= -3.5 * 0.50 * 1.2 * cos40 k

= -1.61 k (N)

Answer:

false

Explanation:

if an object is accelerating the object will not travel the same distance every time interval

Answer:

Hi ??? what is your question

Answer:

1.1299 x 10^-8   second    

Explanation:

Period = 1 / f = 1 / (8.85 * 10^7) = 1.1299 x 01^-8  sec

Answer:

HERE IS YOUR ANSWER

Physical quantity => Unit

1)Length=>metre

2)Time=>second

3)Temperature=>Kelvin

4)mass=>kilogram

5)electric current=>ampere

6)luminous intensity=>candela

7)amount of substance=>mole

8)velocity=>m/s

9)acceleration=>m/s²

10)momentum=>kgm/s

11)density=>kg/m³

12)volume=>m³

13)force=>Newton(N)

14)Energy=>Joule(J)

15)Power=>Watt(W)

16)Pressure=>Pascal(Pa) or N/m²

17)Resistance=>ohm

18)Electrical potential=>volt(V)

19)plane angle=>radian

20)solid angle=>steradian

Explanation:

Physical quantity:-units

Answer:

v = 0.5 m/s.

Explanation:

Total distance, d = 20 m + 20 m = 40 m

Total time taken, t = 30 s + 50 s = 80 s

The average speed of an object is the total distance divided by time taken. So,

\(v=\dfrac{40}{80}\\\\=0.5\ m/s\)

So, the average speed of the object is 0.5 m/s.

Answer:

a) The diagrams can be seen in the picture attached

(b) By comparing the diagrams we can conclude that the resultant R₁ = R₂ = R₃

Further explanation

Vector is quantity that has magnitude and direction.

One example of a vector is acceleration.

Acceleration is rate of change of velocity.

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

This problem is about Vector and Vector Diagram.

Given:

Vector A = -200 j

Vector B = -250 i

Vector C = (150 sin 30.0°) i + (150 cos 30.0°) j = 75 i + 75√3 j

Unknown:

R₁ = A + B + C = ?

R₂ = B + C + A = ?

R₃ = C + B + A = ?

Solution:

R₁ = A + B + C  = (-200 j) + (-250 i) + (75 i + 75√3 j)

R₁ = -175i + (75√3 - 200)j

R₂ = B + C + A = (-250 i) + (75 i + 75√3 j) + (-200 j)

R₂ = -175i + (75√3 - 200)j

R₃ = C + B + A  = (75 i + 75√3 j) + (-250 i) + (-200 j)

R₃ = -175i + (75√3 - 200)j

From the results above, it can be concluded that the resultants above produce the same results. This can be confirmed from the diagrams in the attachment.

Explanation:

Answer:

It would show a "straight line".

Explanation:

Newton's First Law of Motion states that an object at rest will remain at rest and an object in motion will remain in motion (at a constant velocity) unless acted upon by an unbalanced force. Newton's first law of motion is also called the law of inertia.

The magnitude of the acceleration of  the crate is 1.033 m/s².

The given parameters;

The mass of the crate is calculated as;

W = mg

\(m = \frac{W}{g} \\\\m = \frac{925}{9.8} \\\\m = 94.388 \ kg\)

The normal force on the crate is calculated as;

Fₙ = 925 - 325 x sin(25)

Fₙ = 925 - 137.35

Fₙ = 787.65 N

The frictional force on the object is calculated as follows;

\(F_k = \mu F_n\\\\F_k = 0.25 \times 787.65\\\\F_k = 196.91 \ N\)

The magnitude of the crates acceleration is calculated from the net horizontal force on the crate;

\(\Sigma F_x = 0\\\\Fcos (\theta) - F_k = ma\\\\325\times cos(25) \ - \ 196.91 = ma\\\\97.54 = ma\)

\(a = \frac{97.54}{94.388} \\\\a = 1.033 \ m/s^2\)

Thus, the magnitude of the acceleration of  the crate is 1.033 m/s².

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The angle that the net force makes with respect to the x- axis, is determined as 55.3⁰.

The angle that the net force makes with respect to the +x axis, is determined as follows;

F = qvBsinθ

Fy =  qv(By)sinθ

Fx =  qv(Bx)sinθ

The angle that the net force makes with respect to the +x axis;

tanθ = Fy/Fx

tanθ = qv(By)sinθ / qv(Bx)sinθ

tanθ = By/Bx

tanθ = 0.065/0.045

tanθ = 1.444

θ = tan⁻¹(1.444)

θ = 55.3⁰

Thus, the angle that the net force makes with respect to the x- axis, is determined as 55.3⁰.

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Answer:

2560m or 2.56km (rounded to 3 significant figures)

Explanation:

First, list all known and desired values/variables (initial vertical velocity is 0 as the plane is kept level and vertical acceleration is just gravity):

\(Vertical \ velocity \ (\frac{m}{s} ) = u_{v} = 0 \\\\ Horizontal \ velocity \ (\frac{m}{s} ) = u_{h} = 200\\\\ Vertical \ acceleration \ (\frac{m}{s^{2} } ) = a_{v} = 9.8 \\\\ Horizontal \ acceleration \ (\frac{m}{s^{2} } ) = a_{h} = 0 \\\\ Vertical \ displacement \ (m) = s_{v} = 800 \\\\ Horizontal \ displacement \ (m) = s_{h}\)

The horizontal displacement is going to be the distance travelled, horizontally of course, once the package is released;

First thing to understand is that the vertical and horizontal components are to be dealt with separately because they don't affect each other;

Since there is no horizontal acceleration (ignoring air resistance), we simply require a velocity and time to find the horizontal displacement, using the formula v = d/t (or speed = distance/time);

What we have is the horizontal velocity but we don't have the time taken;

One thing we know is that the time elapsed for the vertical fall of 800m and for the horizontal displacement must be the same;

What we do, therefore, is find the time taken for the vertical displacement using the formula, s = ut + ¹/₂·at², since we know the vertical velocity, height and acceleration:

800 = (0)t + ¹/₂·(9.8)t²

800 = 4.9t²

t² = 163.26...

t = 12.77...

We now have the time taken for the vertical fall and the horizontal displacement, we can use this with the horizontal velocity we know already and get the horizontal displacement:

\(u_{h} = \frac{s_{h} }{t} \\\\ 200 = \frac{s_{h} }{12.77...} \\\\ s_{h} = 200(12.77...) \\\\ s_{h} = 2555.5...\)

a)  the average power of the elevator motor during this period is 0.1696 hp

b) The power during an upward trip with constant speed is 16.13 horsepower.

To calculate the average power of the elevator motor during the period of acceleration, we need to find the work done by the motor and divide it by the time taken.

Given:

Mass of the elevator (m) = 682 kg

Acceleration (a) = (1.80 m/s - 0) / 3.10 s = 0.5806 m/s²

Time taken for acceleration (t) = 3.10 s

(a) First, let's calculate the displacement (d) using the formula for uniformly accelerated motion:

d = 0.5 * a * t^2

= 0.5 * 0.5806 m/s² * (3.10 s)^2

= 1.0153 m

Next, we can calculate the work done (W) by the elevator motor:

W = m * a * d

= 682 kg * 0.5806 m/s² * 1.0153 m

= 391.55 J

Now, to find the average power (P), we divide the work done by the time taken:

P = W / t

= 391.55 J / 3.10 s

= 126.36 W

To convert the power to horsepower, we can use the conversion factor: 1 horsepower (hp) = 745.7 watts.

Therefore, the average power of the elevator motor during this period is:

P = 126.36 W / 745.7

= 0.1696 hp

(b) During an upward trip with constant speed, the elevator does not accelerate, so the power required is only to counteract the force of gravity and friction. The power during an upward trip with constant speed is equal to the power required to overcome the force of gravity and friction.

The force of gravity (Fg) can be calculated using:

Fg = m * g

= 682 kg * 9.8 m/s²

= 6683.6 N

The power (P) required is given by the formula:

P = Fg * v

= 6683.6 N * 1.80 m/s

= 12030.5 W

To convert the power to horsepower:

P = 12030.5 W / 745.7

= 16.13 hp

Therefore, the power during an upward trip with constant speed is 16.13 horsepower.

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Answer:

The box will not move from its position.

Explanation:

First, we will calculate the static frictional force that is stopping the box to move from its position:

\(f = \mu R = \mu W=\mu mg\)

where,

f = static frictional force = ?

μ = coefficient of static friction = 0.3

m = mass of box = 4 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

\(f = (0.3)(4\ kg)(9.81\ m/s^2)\\f=11.77\ N\)

Since the frictional force (11.77 N) is greater than the applied force (10 N).

Therefore, the box will not move from its position.

Answer:

Weight measures the force of gravity pulling on an object

Explanation:

Bot sure if tht answered ur question

According to the information, the rms speed of the gas will remain unchanged.

The rms (root-mean-square) speed of a gas is directly proportional to the square root of its temperature. In this scenario, the temperature is constant, which means that the rms speed of the gas will also remain constant.

The change in volume does not have a direct effect on the rms speed of the gas, as long as the temperature remains unchanged. Therefore, the rms speed of the gas in the vessel will not change.

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☯ Distance is a scalar quantity and has only magnitude but no direction.

☯ Displacement is a vector quantity and has both magnitude and direction.

☯ Distance can only have +ve values whereas displacement can be +ve, -ve or even be zero.

Answer:

d=75 m

Explanation:

Before Skidding

\(v^2-v_o^2=2ad\)

\(0^2-49^2=2a(12)\)

After Skidding

\(v^2-v_o^2=2ad\)

\(0^2-122.5^2=2ad\)

\(\frac{49^2}{122.5^2}=\frac{12}{d}\)

\(d=75 m\)

Hope it helps

Answer:

7.5 m/s².

Explanation:

From the question given above, the following data were:

Mass (m) of object = 0.6 Kg

Force of friction (Fբ) = 1.5 N

Acceleration (a) =?

Next, we shall determine the force of gravity on the object. This can be obtained as follow:

Mass (m) of object = 0.6 Kg

Acceleration due to gravity (g) = 10 m/s²

Force of gravity (F₉) =?

F₉ = mg

F₉ = 0.6 × 10

F₉ = 6 N

Next, we shall determine the net force acting on the object. This can be obtained as follow:

Force of friction (Fբ) = 1.5 N

Force of gravity (F₉) = 6 N

Net force (Fₙ) =?

Fₙ = F₉ – Fբ

Fₙ = 6 – 1.5

Fₙ = 4.5 N

Finally, we shall determine the acceleration of the object. This can be obtained as follow:

Mass (m) of object = 0.6 Kg

Net force (Fₙ) = 4.5 N

Acceleration (a) of object =?

Fₙ = ma

4.5 = 0.6 × a

Divide both side by 0.6

a = 4.5 / 0.6

a = 7.5 m/s²

Therefore, the acceleration of the object is 7.5 m/s²

The child's speed at the lowest point is 5.42 m/s.

At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.

Using the conservation of mechanical energy, we can write:

Potential energy at highest point = Kinetic energy at lowest point

mgh = (1/2)mv²

where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.

First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:

h = (1/2)3.00 m = 1.50 m

Next, we can solve for the child's speed at the lowest point:

mgh = (1/2)mv²

40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²

588 J = 20.0 kg * v²

v² = 29.4 m²/s²

v = 5.42 m/s

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Answer: Your answer would be B, a Capacitor.

Hope this helps!

Answer:

The answer is B. a capacitor

It as dangerous to be hit by the gun as by the bullet because of the following;

(A) The butt distributes the recoil force over an area much larger than that of the bullet.

(B) The rifle has a much lower speed than the bullet.

The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.

That is the sum of the initial momentum is equal to the sum of the final momentum.

momentum of the gun = momentum of the bullet

Mu = mU

where;

If the forward momentum of a bullet is the same as the backward momentum of the gun, the speed of the gun will be smaller than the speed of the bullet since the mass of the gun is bigger than mass of the bullet.

We cannot conclude on the kinetic energy, since it depends on both mass and velocity.

Finally, the butt distributes the recoil force over an area much larger than that of the bullet, since the butt has a larger surface area and will hit more surface area than the bullet.

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From the image we notice that the object is located in front of the focal point of the mirror. We know that in this case the image will be located somewhere on the opposite side of the mirror. Regardless of exactly where in front of F the object is located, the image will always be located behind the mirror. In this case, the image will be an upright image. That is to say, if the object is right side up, then the image will also be right side up. In this case, the image is magnified; in other words, the image dimensions are greater than the object dimensions.

Therefore the answer is d.

A

Explanation: sorry sir but its required step up transformer for high voltage not step

Answer:

Breaking an atom refers to a process called nuclear fission, which involves splitting the nucleus of an atom into smaller nuclei. This is typically accomplished by bombarding the atom with a neutron, which causes the nucleus to become unstable and split apart, releasing a large amount of energy in the process. This energy is what is harnessed in nuclear power plants to generate electricity. However, it should be noted that nuclear fission can also have potentially harmful effects, such as the release of radioactive material and the potential for nuclear accidents.

Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.

The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.

These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.

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