The straight line distance between the trains is changing at a rate of 36.08 mph. This can be calculated using the Pythagorean theorem.
What is the straight line distance?Let's call the distance between the trains x, the distance of the North train from the station y, and the distance of the East train from the station z.
We know that x² = y² + z²
We also know the rate of change for y and z. The rate of change for y is -26 mph and the rate of change for z is 48 mph.
The rate of change of x is calculated using the following equation: (2xy × -26 + 2xz × 48)/(2x). Substituting the given values, we get:
(2 × 13 × -26 + 2 × 10 × 48) / (2 × 13) = -36.08 mph
Therefore, the straight line distance between the trains is changing at a rate of 36.08 mph.
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100 point question!! A driver begins to brake when her car is traveling at 15.0 m/s, and the car comes to a stop 4.0 s later. How much farther does the car go after the driver begins to brake, assuming constant acceleration?
Answer:
30 m
Explanation:
Let's list out the known variables that we are given in this question.
v₀ = 15 m/sv = 0 m/s t = 4 sWe are trying to solve for displacement in the x-direction.
Δx = ?Find which constant acceleration equation contains all 4 of these variables.
\(\displaystyle \triangle x = \Big (\frac{v+v_0}{2} \Big ) t\)Plug the known values into the equation and solve for delta x.
\(\displaystyle \triangle x = \Big (\frac{0+15}{2} \Big ) \cdot 4\) \(\displaystyle \triangle x = \Big (\frac{15}{2} \Big ) \cdot 4\) \(\displaystyle \triangle x =\frac{60}{2}\) \(\triangle x = 30\)The car goes 30 m after the driver begins to brake.
Answer:
the answer should be 30 m
Explanation:
have a good day
7.There is no gain in mechanical advantage in a single fixed pulley. En
why the pulley is then used.
Answer:
The answer to this question can be defined as follows:
Explanation:
Advantage:
The load can be raised with one fixed pulley by adjusting the shifting pressure path. Its a fixed input pulley doesn't even have a mechanical advantage, the movement is larger than for the load. It is preferable to use because the pulley must not be moved up or down. It gains the measurement of just an increase in output power-to-input force ratio.When you do glass blowing is it a chemical change or a physical change
Answer:
physical
Explanation:
Can someone please help me with this lesson outline?
B. The Moon's Formation
1. Scientists hypothesize that the Moon formed from rock that was in a ring around Earth. This ring formed when Earth collided with an object about the size of Mars.
2. Craters form when objects impact into the surface of another object.
a. Light-colored streaks called rays extend in all directions from some craters.
b. On Earth, wind, water, and plate tectonics have erased craters. The Moon has no wind, water, or plate tectonics.
3. Large, flat areas on the Moon are called maria. They formed after most impacts on the Moon's surface had stopped; lava flowed up through the Moon's crust and solidified, covering many craters and other features and then solidifying.
4. Highlands are light-colored areas on the Moon's surface.
C. The Moon's Motion
The amount of time it takes the Moon to revolve once around Earth is the same as the amount of time it takes the Moon to make one rotation. One revolution of the Moon around Earth takes 27.3 days.What is the Moon's Formation about?In terms of formation, scientists hypothesize that the Moon formed from rock that was in a ring around Earth after a collision with an object the size of Mars. This collision caused debris from Earth to be ejected into space, eventually coming together to form the Moon.
Therefore, this passage also explains how craters form on the Moon's surface when objects impact into it. Some craters have light-colored streaks called rays that extend in all directions from them. The Moon's lack of wind, water, and plate tectonics has prevented these craters from being erased like they are on Earth.
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See text below
B. The Moon's Formation
1. Scientists hypothesize that ---formed from rock that was
in a ring around Earth. This ring formed when -- collided with an object about the size of Mars.
2. Craters form when objects ----into the surface of another object.
a. Light-colored streaks called ---extend in all directions from some craters.
b. On Earth, wind, water, and plate tectonics have erased craters. The ----- has no wind, water, or plate tectonics.
3. Large, flat areas on the Moon are called -----They formed after most impacts on the Moon's surface had stopped; lava flowed up through the Moon's crust and solidified, covering many craters and other features and then solidifying.
4. ----are light-colored areas on the Moon's surface.
C. The Moon's Motion
1. The amount of time it takes the Moon to revolve once around Earth is ----
the amount of time it takes the Moon to make one rotation. One revolution of the Moon around Earth takes -----days.
2. Convert 750 m/s to km/hr.
Answer:
2700
Explanation:
1m/s=3.6km/hr
A swimmer is able to swim at 1.4ms-1 in still water. A.calculate how far downstream will he land if he swims directly across a 180m wide river.
The swimmer will land a distance of 180 * (v_r / 1.4) meters downstream from the starting point, where v_r represents the velocity of the river.
To determine how far downstream the swimmer will land, we can use the concept of relative velocity. Let's consider the swimmer's velocity relative to the river, which is the vector sum of the swimmer's velocity in still water and the velocity of the river.
Given that the swimmer's velocity in still water is 1.4 m/s, we need to determine the velocity of the river. To do this, we'll use the fact that the swimmer swims directly across the river, perpendicular to the current. This means that the swimmer's velocity relative to the river is equal to the velocity of the river itself.
Let's assume the velocity of the river is v_r. Since the swimmer is swimming directly across a 180 m wide river, the time taken to cross can be calculated as t = 180 m / (1.4 m/s). During this time, the river current will push the swimmer downstream by a distance equal to the velocity of the river multiplied by the time taken, i.e., d = v_r * t.
Substituting the known values, we get d = v_r * (180 m / 1.4 m/s). Since the units cancel out, the answer will be in meters.
Therefore, the swimmer will land a distance of 180 * (v_r / 1.4) meters downstream from the starting point, where v_r represents the velocity of the river.
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Number 5 and 6 i need just give answer
Explanation:
voltage = current × resistance
5.
12 V = 4.2 A × resistance
resistance = 12 V / 4.2 A = 2.857142857... Ohm
FYI :
4.2 A would be a lot for a small electronic device like a CD player. that would be 12×4.2 = 50.4 Watt, and the CD player would get really hot.
6.
120 V = current × 12 Ohm
current = 120 V / 12 Ohm = 10 A
a cyclist travels for 90 km. the trip lasts for 5 hours. what is the average speed of the cyclist?
Answer:
The average speed of the cyclist is 18 \(\frac{km}{hour}\)
Explanation:
Speed is a magnitude that expresses the relationship between the space traveled by an object, the time used for it and its direction. Because it considers direction, it is a vector quantity.
Then the average speed is the quotient of the space traveled by an object and the time it takes to cover the distance traveled:
\(speed=\frac{distance}{time}\)
In this case:
distance: 90 kmtime: 5 hoursReplacing:
\(speed=\frac{90 km}{5 hours}\)
Solving:
\(speed=18\frac{ km}{ hour}\)
The average speed of the cyclist is 18 \(\frac{km}{hour}\)
Which element forms more com-
pounds than all the other elements
combined?
Answer:
Terms in this set (7) Which element forms more compounds than all the other elements combined? Carbon.
Explanation:
Hope its helps you ✌️
a crate sits at rest on a factory floor. friction between the crate and floor occurs _______. When the crate is pushed horizontally, whether sliding or not. When the crate is pushed vertically , whether sliding or not. When the crate is pushed horizontally,sliding When the crate is pushedvertically, not sliding
When the crate is pushed horizontally, friction between the crate and the floor will occur whether the crate is sliding or not.
What is friction?Friction is the force that resists relative motion between two objects that are in contact with each other. It is the result of the microscopic interlocking of irregularities in the surfaces of the objects that are in contact.
This is because, due to the force of the push, the crate will be pressing against the floor and the floor will be pushing back against the crate. This will cause friction which is the resistance force that is created when two surfaces rub together.
When the crate is pushed vertically, friction will still occur, but it will not be as strong as when it is pushed horizontally.
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procedure calculate the density of the aluminum block using measurements taken with the ruler and triple-beam balance 1. measure and record the dimensions and mass of the aluminum block and record values below. include uncertainties. 2. calculate the density of the block and its uncertainty. 3. calculate the percent error between your calculated density value and the expected value of 2.699g/cm3
Dimensions: Length = 12.45cm +/- 0.05cm, Width = 5.65cm +/- 0.05cm, Height = 2.85cm +/- 0.05cm,Mass = 221.3g +/- 0.1g,Calculation of Density:Volume of Block = Length x Width x Height= 12.45cm x 5.65cm x 2.85cm,= 214.25 cm3 +/- 0.25 cm3,Density = Mass / Volume,= 221.3g / 214.25 cm3,= 1.03 g/cm3 +/- 0.01g/cm3,Calculation of Percent Error:Percent Error = (Calculated Value - Expected Value) / Expected Value x 100,= (1.03 g/cm3 - 2.699g/cm3) / 2.699g/cm3 x 100,= -61.90%.
What is the Calculation ?
Calculation is a process of solving a problem by performing a series of mathematical operations or calculations. It involves the use of numerical data, formulas and equations to arrive at a desired result or answer. Calculations can be done manually or by using computers. Calculations are used in a variety of fields such as engineering, finance, physics and economics. Calculation is a way of problem-solving that is used to gain insight into a problem or to arrive at a solution. It involves a systematic approach to arriving at an answer or solution to a problem.
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(a) keeping in mind that at terminal velocity the drag force has the same magnitude a ball's weight, what is the drag force on a baseball trabeling at twice its terminal velocity? (b) a baseball is falling down at twice its terminal velocity. what are the magnitured and direction if its acceleration?
The magnitude and direction of acceleration are zero and downwards, respectively.
How to calculate the drag force?
The drag force is equal to the weight of the baseball times two when traveling at twice its terminal velocity.
a) At terminal velocity, the drag force has the same magnitude as a ball's weight. Therefore, the drag force on a baseball traveling twice its terminal velocity would be four times the weight of the ball. The drag force on a baseball traveling at twice its terminal velocity is twice its weight. This is because the drag force on an object increases with increasing velocity.
b) When the baseball is falling at twice its terminal velocity, the magnitude of its acceleration is zero. The direction of acceleration is downwards; it's the same as the direction of the gravitational force. However, the baseball is not accelerating because the drag force on it exactly balances the gravitational force.
The magnitude of the acceleration of a baseball falling at twice its terminal velocity is the same as the magnitude of the drag force. The direction of the acceleration is opposite to the direction of the drag force, which is opposite to the direction of motion.
Therefore, the magnitude and direction of acceleration are zero and downwards, respectively.
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Please help me I have physics tomorrow and im so confused
Answer:
trust the process
Explanation:
quadratic formula, use synthetic division also use the p-q method for the roots and factoring.
Determine the molality of a solution prepared by dissolving 4.08 g of hexane in 89.1 g of benzene.
The molality of the solution made by dissolving 4.08 g of hexane in 89.1 g of benzene is 0.527 M
What is molality?This is simply defined as the mole of solute per kilogram of solvent. It can be expressed mathematically as:
Molality = mole of solute / mass (in Kg) of solvent
How to determine the mole of hexaneMass of hexane = 4.08 gMolar mass of hexane = 86 g/molMole of hexane =?Mole = mass / molar mass
Mole of hexane = 4.08 / 86
Mole of hexane = 0.047 mole
How to determine the molality of the solutionThe molality of the solution can be obtained as illustrated below:
Mole of solute (hexane) = 0.047 moleMass of solvent (benzene) = 89.1 g = 89.1 / 1000 = 0.0891 KgMolality =?Molality = mole of solute / mass (in Kg) of solvent
Molality = 0.047 / 0.0891
Molality = 0.527 M
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The workdone In pulling a body which weighs 30N along a horizontal plane by a constant force of 20N is 320J. Find the distance moved
Answer: The answer is 800 J
Explanation:
1. Explain why running hot water on the metal lid of a glass jar makes it easier to unscrew.
Answer:
Explanation:
Let the hot water run from the tap until it's piping hot, and then turn the jar on its side and carefully dip the lid under water. ... The hot water helps the metal expand, therefore loosening the lid and making it easier to unscrew.
An electic bulb is rated 60W, 220V. Calculate the resistance of its filament when it is operating normally.
Answer:
Explanation:
We have to use the equation p = I^2 x R. But we do not have the current.
To work out the current, we look at what we have. We have the voltage and power, therefore we will use the equation P = IV and rearrange to find the current.
I = P/V
I = 60/220
I = 0.2727272727 or round it to 2 dp to get = 0.27
we now have to rearrange the first equation to find the resistance.
R = P/I^2
R = 60/0.2727272727^2
R = 806.6666665501
R = 807 ohms (3sig)
The resistance of the filament is 806.67 ohms.
Electrical power is defined as the rate at which electrical energy is transferred by an electric circuit. The SI unit of power is Watt, 1 joule per second ( 1J/S).
The formula of electrical power is
P = V^2/R
where,
P = power
V = volts
R = resistance
from the above formula
60 = 220x220/R
R = 220x220/60
R = 806.67
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2.70×10^6 atoms are excited to an upper energy level at t=0s. At the end of 30.0 ns , 90.0% of these atoms have undergone a quantum jump to the ground state. How many photons have been emitted?
The number of photons emitted is \(2.43×10^6\) photons.
How many photons are emitted when 90% of the excited atoms undergo a quantum jump?At t=0s, there are \(2.70×10^6\) atoms excited to an upper energy level. After 30.0 ns, 90% of these atoms have undergone a quantum jump to the ground state. This means that 10% of the atoms remain in the excited state.
To determine the number of photons emitted, we need to calculate the difference in the number of atoms between the initial and final states, and then multiply it by the number of photons emitted per atom in the quantum jump.
The number of atoms that have undergone the quantum jump is given by 90% of the initial number of atoms:
90% of \(2.70×10^6\) atoms = \(0.90 × 2.70×10^6\)atoms = \(2.43×10^6\) atoms.
Since each atom undergoing the quantum jump emits one photon, the number of photons emitted is equal to the number of atoms that have undergone the jump:
Number of photons emitted =\(2.43×10^6\) photons.
Therefore, \(2.43×10^6\) photons have been emitted.
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hi everyone........
Answer:
hiiiiiiiiiiiiiiiiiiiiiiiiii
Answer:
Hiii , how are you holding up with corona?
Explanation:
Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
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A circuit has a current of 3. 6 A and a resistance of 5. 0 Ω. What is the voltage applied to the circuit? 0. 72 V 1. 4 V 8. 6 V 18 V.
Answer:
18 V
Explanation:
According to Ohm's Law, current equals voltage divided by resistance. (I=V/R)
Using this, we can rearrange the equation to have it solved for voltage.
V=IR
Then, you plug in the values for the current and the resistance.
V=(3.6)x(5.0)
V=18
UNIT 2 Dynamics | 2.J Modified Atwood Machines NAME DATE X20XE Scenario in the diagram shown to the right a block of mass M has taken a quick hit from a bat. After the strike, its front end is at position x = 0 at time t = 0 and it is moving to the right with initial speed vo. The block slides on a rough surface and is also connected to a hanging mass object of mass m by a string that passes over an ideal pulley. The front end of the block reaches position x = D at time t=ti, the instant that the block comes to rest. The block then returns to position x = 0 at time t = 12, having a leftward speed v2 at that time. Using Representations The dots below represent the block on the table during the interval 0
The force of friction points to the right, while the force of tension points to the left, resulting in a decrease in the net force (horizontally) and a corresponding decrease in acceleration.
acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
For instance, if a car is traveling at a constant speed and turning a corner, it is accelerating since its direction is shifting. The acceleration increases with turning speed. Therefore, when velocity varies, whether in magnitude (an increase or reduction in speed), direction, or both, there is an acceleration.
Is the magnitude of the block's acceleration greater before the block reaches x = D or after? Explain your reasoning in terms of the forces that you drew in the above diagrams.
B) Since both the friction force and the tension force are pointed to the left between time t = 0 and t = t, the block accelerates further before it reaches x = D. Following t = t, the force of friction points to the right, while the force of tension points to the left, resulting in a decrease in the net force (horizontally) and a corresponding decrease in acceleration.
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Complete Question -
A uniform flat disk of radius R and mass 2M is pivoted at point P. A point mass of 1/2 M is attached to the edge of the disk. Calculate the total moment of inertia IT of the disk with the point mass with respect to point P, in terms of M and R.
The total moment of inertia IT of the disk with the point mass with respect to point P is 3/4 MR^2, in terms of M and R.
The total moment of inertia IT of the disk with the point mass with respect to point P can be calculated by using the parallel axis theorem, which states that IT = ICM + md^2, where ICM is the moment of inertia of the disk about its center of mass, m is the mass of the point mass, and d is the distance between the point mass and the pivot point P.
The moment of inertia of the disk about its center of mass ICM can be found from the formula for a uniform disk: ICM = 1/2 MR^2.
The distance between the point mass and the pivot point P is equal to the radius R of the disk.
Substituting these values into the parallel axis theorem, we get:
IT = ICM + md^2
= 1/2 MR^2 + (1/2 M)(R^2)
= 3/4 MR^2
Hence, the total moment of inertia IT of the disk with the point mass with respect to point P is 3/4 MR^2, in terms of M and R.
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If I am throwing a bowling ball off a roof and a watermelon off a roof at 30
feet, which object do you think will have more energy?
Answer:
Th ball
Explanation:
PLEASE HELP !!
Elements in period 2 on the periodic table all have blank
electron shells.
Answer:
Two orbitals for their electrons and six in the 2p subshell
Explanation:
Hope this helps :)
How does a mutation in a gene affect a protein?
Answer:
a variant can cause a protein to malfunction or to not be produced at all.
If a net force of 24 N is applied to an object with a mass of 6 kg, then what will the resulting
acceleration be according to Newton's second law of motion?
a
b
C
d
6 m/s²
0.25 m/s²
24 m/s²
4 m/s²
Answer:
d. 4 m/s²
Explanation:
pls mrk me brainliest
Block X and Y are attached to each other by a light rope and can slide along a horizontal
surface. Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of friction
on blocks X and Y is 8.0 N and 4.0 N respectively. Find the action-reaction forces that the
blocks exert on each other if an applied force of 40 N [right] acts on block per the illustration
below.
a) The force of X on Y is 7.4 N [right] and the force of Y on X is 4.1 N [left]
Jhry
Ob) The force of X on Y is 12 N [right] and the force of Y on X is 14 N [left]
c) The force of X on Y is 14 N [right] and the force of Y on X is 14 N [left]
O d) The force of X on Y is 22 N [right] and the force of Y on X is 22 N [left]
B. The force of X on Y is is approximately 13 N [right].
Tension in the rope
The action-reaction forces that the blocks exert on each other is calculated as follows;
Net force on the blocks = 40 N - (8 N + 4 N) = 28 N
Total mass of the blocks = 10 kg + 5 kg = 15 kg
Acceleration of the blocksa = F(net)/M
a = 28 N / 15 kg
a = 1.867 m/s²
Considering object X,40 N - 8N - T = 10 x 1.867
T = 13.33 N
Considering object Y,40 N - 4N - T = 5 x 1.867
T = 26.67 N
Thus, the force of X on Y is is approximately 13 N [right].
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plsssssssss help me easy 6th grade science its about roller coasters
A particle moves with a velocity 1 v 5j 3j 6k ms under influence of a contact force F 10i 10j 20k N. THe instantaneous power applied to the particle is
Answer:
P = 200 W
Explanation:
The expression for the power is
P = W / t
the job
W = F d
we substitute
P = F d / t
P = F. v
We apply this equation to our case where the velocity is
v = (5 i + 3j + 6k) m / s
and the force is
F = (10i + 10j +20 k) N
we substitute in the power equation, remember that the scalar product of the unit vectors is
i.i = j.j = k.k = 1 and the other products are zero
P = 10 5 + 10 3 + 20 6
P = 200 W