A uniform resistance wire leng th till is stretched its becomes four times. Does its resistance in crease or decrease?​

Because the frequency of light is inversely related to the wavelength of light.

 The equation for speed, wavelength, and frequency are:

                                            c = λf

As we know that  

                             c= 3×10^8m/s           is the speed of light

                             λ      is the wavelength of light

                             f       is the light frequency

So from here we see that frequency and wavelength is inversely related so if one increases than other must decreases.

Like when frequency of light is greater, the wavelength must becomes less than its original value. This does not contradict the postulate that the speed of light remains the same. Because both these parameters adjust with respect to each other to maintain the constant.

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To determine the voltage produced by a voltaic cell consisting of a calcium electrode in contact with a solution of Cu2+ ions, we need to know the standard reduction potentials of the half-reactions involved.

The standard reduction potential of the calcium electrode (Ca2+ + 2e- → Ca) is -2.87 V (reduction potential).

The standard reduction potential of Cu2+ ions (Cu2+ + 2e- → Cu) is +0.34 V (reduction potential).

To calculate the voltage produced by the cell, we subtract the reduction potential of the anode (calcium) from the reduction potential of the cathode (copper):

Voltage = Reduction potential of cathode - Reduction potential of anode

       = (+0.34 V) - (-2.87 V)

       = +3.21 V

Therefore, the voltage produced by the voltaic cell consisting of a calcium electrode in contact with a solution of Cu2+ ions is approximately +3.21 V.

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Answer:

Explanation:

A rise in temperature increases the kinetic energy and speed of particles; it does not weaken the forces between them. The particles in solids vibrate about fixed positions; even at very low temperatures. Individual particles in liquids and gases have no fixed positions and move chaotically.

Given:

Need to find :

Calculation:

Gauss law :- ø = q/Eₒ

1. For small sphere:- ø1 = q/Eₒ

2. For large sphere :- ø2 = q/Eₒ

=> ø1/ø2 = (q/Eₒ)/(q/Eₒ)

=> ø1/ø2 = 1/1

Ratio of flux is 1:1

Increases in ghrelin increase hunger, whereas increases in leptin decrease hunger, this is option A, as ghrelin is a hormone produced in the stomach that stimulates appetite and increases food intake.

The body has a complex system for regulating hunger and appetite, and two of the key hormones involved in this process are ghrelin and leptin, ghrelin is produced in the stomach and is released in response to an empty stomach, while leptin is produced by fat cells and acts as a signal to the brain that the body has enough energy stores.

Hence, Increases in ghrelin increase hunger, whereas increases in leptin decrease hunger; this is option A.

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The question is incomplete, the complete question is below,

a. ghrelin; leptin

b. blood glucose; melanin

c. thyroxin; blood glucose

Answer:

the pressure per square inch is greater from the smaller feet.

Explanation:

different weight distribution

The allowable radii (r) in the Bohr model can be calculated using the equation r = ε_0h^2/(πZe^2n), where n is the principal quantum number and Z is the atomic number of the atom.To solve for the allowable radii (r) in the Bohr model, we need to equate the two different expressions for the allowed electron velocities (v) and eliminate v. Let's start by setting the two expressions equal to each other:

Expression 1: mv/nh = Ze^2/2πε_0r (from part a)
Expression 2: mv = nh/2πr (from part b)

To eliminate v, we can equate the two expressions:

mv/nh = Ze^2/2πε_0r
mv = nh/2πr

Now, let's solve for r:

mv/nh = Ze^2/2πε_0r
mv = nh/2πr

We can cancel out the mass (m) and the Planck constant (h) from both sides of the equations:

v/n = Ze^2/2πε_0r
v = nh/2πr

Next, we can substitute the expression for v in the first equation:

nh/2πr = Ze^2/2πε_0r

We can further simplify by canceling out 2πr from both sides:

nh = Ze^2/ε_0

Finally, we can solve for r:

r = ε_0h^2/(πZe^2n)

In conclusion, the allowable radii (r) in the Bohr model can be calculated using the equation r = ε_0h^2/(πZe^2n), where n is the principal quantum number and Z is the atomic number of the atom.

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To determine the minimum speed that the motorcycle must have at the top of the loop to make it safely around, we need to consider the forces acting on the motorcycle at that point.

At the top of the loop, the motorcycle is experiencing two forces: the force of gravity pulling it downward and the normal force exerted by the track pushing it upward. The minimum speed required is when the normal force becomes zero, indicating that the motorcycle is just about to lose contact with the track.The net force acting on the motorcycle at the top of the loop is the centripetal force, which is given by:
F_net = m * (v^2 / r)
Where:F_net is the net force.m is the mass of the motorcycle (250 kg).v is the speed of the motorcycle.r is the radius of the circular track (12 m).At the top of the loop, the net force is the difference between the gravitational force and the normal force:
F_net = mg - N
Setting the net force equal to zero (N = 0), we can solve for the minimum speed:
mg = m * (v^2 / r)
Canceling out the mass:
g = v^2 / r
Solving for v:
v = √(g * r)
Plugging in the values:
v = √(9.8 m/s^2 * 12 m)
v ≈ √(117.6 m^2/s^2)
v ≈ 10.85 m/s
Therefore, the minimum speed that the motorcycle must have at the top of the loop to make it safely around is approximately 10.85 m/s.

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The angular dispersion of a hollow 60° prism filled with carbon disulfide, whose refractive index for blue light is 1.652 and for red light is 1.618 is

The angular dispersion of a prism is defined as the angle between the two refracted light rays, of different wavelengths, that emerge from the prism.

The refractive index of carbon disulfide for blue light is = 1.652

and for red light the refractive index of carbon disulfide is = 1.618.

To calculate the angular dispersion of the hollow 60° prism filled with carbon disulfide, we need to use the formula:

Angular Dispersion = (nRed - nBlue) * 60° where nRed and nBlue are the refractive indices of the prism for red and blue light, respectively.

Plugging in the values, we get:

Angular Dispersion =\((1.618 - 1.652) * 60\)

Angular Dispersion = \(-0.034 * 60\)

Angular Dispersion = -2.04°

Therefore, the angular dispersion of the hollow 60° prism filled with carbon disulfide is -2.04°.

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Graphs A, B, C, and D match the numbers 3,4,1, and 2 respectively.

Distance is a numerical representation of the distance between two objects or locations.

The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

Graph C shows a person leaving home and traveling at a constant speed.

Graph D shows a person leaving home, traveling at a constant speed, stopping for a short time and then returning home.

Graph A shows a person leaving home, traveling to their destination, and immediately returning.

Graph B shows a person leaving home, traveling at a constant speed, stopping for some time, and then continuing the journey away from home.

Hence, the numbers 3, 4, 1, and 2 are matched by graphs A, B, C, and D, respectively.

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Rounded to the nearest whole number, the work required to pump the oil out of the spout is approximately 127736473 J.

To calculate the work required to pump the oil out of the spout, we need to determine the weight of the oil and multiply it by the height it is being lifted.

Given:

Density of the oil (ρ) = 900 kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Height of the spout (h) = 4 m

First, we need to determine the volume of oil in the tank. Since the tank is half full, the volume of oil (V) can be calculated as half the volume of the tank.

Volume of the tank (V_tank) = (4/3) * π *\((r^3)\)

where r is the radius of the tank (12 m).

Volume of oil (V) = 0.5 * V_tank

Next, we can calculate the mass of the oil (m) using the density and volume:

m = ρ * V

Now, we can determine the weight of the oil (W) using the formula:

W = m * g

Finally, we can calculate the work required (W_work) to pump the oil out of the spout:

W_work = W * h

Let's perform the calculations:

Volume of the tank (V_tank):

V_tank = (4/3) * π * (12^3)

≈ 7238.23 m³

Volume of oil (V):

V = 0.5 * V_tank

≈ 3619.12 m³

Mass of the oil (m):

m = ρ * V

= 900 kg/m³ * 3619.12 m³

≈ 3257210.59 kg

Weight of the oil (W):

W = m * g

= 3257210.59 kg * 9.8 m/s²

≈ 31934118.42 N

Work required (W_work):

W_work = W * h

= 31934118.42 N * 4 m

≈ 127736473 J.

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An appropriate value for the resistance in parallel with the smoothing capacitor would be 1.59 kΩ.

To ensure good tracking of the AM envelope, the resistance in parallel with the smoothing capacitor should be low enough to discharge the capacitor quickly during the troughs of the modulated signal, but high enough to avoid discharging it too quickly during the peaks of the signal.

The time constant (τ) of the RC circuit formed by the smoothing capacitor and the parallel resistance is given by the formula:

τ = RC

where R is the resistance and C is the capacitance.

To determine an appropriate value for the resistance, we need to calculate the time constant and compare it to the period of the modulated signal.

The period of a 500 kHz signal is T = 1/f = 2 μs. The modulating signal has a bandwidth of 5 kHz, which means its period is 200 μs.

Assuming a small signal approximation, we can use the formula for the time constant to calculate an appropriate value for the resistance:

τ = 20 nF × R = T/2π = 31.8 ns

Solving for R, we get:

R = τ/C = 31.8 ns / 20 nF = 1.59 kΩ

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Complete question is:

The input signal into an envelope detector is an am signal of carrier frequency 500 khz. the envelope detector employs a smoothing capacitor of 20 nf. the modulating signal has a bandwidth of 5 khz. specify an appropriate value for the resistance in parallel with the smoothing capacitor for a good tracking of the am envelope.

Explanation:

P =F * v

F = m * a = 65 kg * 9.81 ms^-2 * 12 passengers

v = d/t = 150m / 64 s

I think you can calculate and substitute this units should be watts

The power needed to transport the passengers through this height is 17.933 KW or 17933 Watts.

Power can be defined as the rate at which work is done by an object. Power can be calculated by the formula:

P = W × t

where, P = power, w = work done, and t = time taken.

The SI unit for power is the watt (W), where 1 watt power is equal to 1 joule/second (1W = 1J/s). Because, the work done by an object is the energy transfer by the object, and power is also the rate at which energy is expended.

P = F × v

where, P = Power, F = Force, and V = velocity of the object

F = m × a = 65 kg × 9.81 ms⁻² × 12 passengers = 7651.8

v = d/t = 150m / 64 s = 2.343

P = 7651.8 × 2.343

P = 17,933.90

P = 17.933 KW

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Answer:

from a lesser hight

Explanation:

because you need less force

hope its right if it is mark brainlyest ;)

Answers:

a. The relationship between the variables is directly proportional (i.e. the x axis is directly proportional to the y axis).

b. The graph is linear.

c. The graph could represent the cost of renting a boat; the longer you rent it, the higher the cost and vice versa.

a. The relationship between the variables is directly proportional (i.e. the x axis is directly proportional to the y axis).

b. The graph is linear.

c. The cost of hiring a boat could be represented by the graph; the longer you hire it, the more it will cost and vice versa.

A graph is described as a diagram showing the relation between variable quantities, typically of two variables, each measured along one of a pair of axes at right angles.

The purpose of a graph is to present data that are too numerous or complicated to be described adequately in the text and in less space.

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Answer:

3200 is the answer have a good day

Explanation:

hope this helps? :))

Answer:

3,200

Explanation:

3,200

Hi there!

We can begin by calculating the time the ball takes to reach the highest point of its trajectory, which can be found using the following:

\(t_{max} = \frac{vsin\theta}{g}\)

Where:

tmax = (? sec)

vsinθ = vertical comp. of velocity = 10sin(48) = 7.43 m/s)

g = acceleration due to gravity (9.8 m/s²)

We can solve for this time:

\(t_{max} = \frac{7.43}{9.8} = 0.758 s\)

When the ball is at the TOP of its trajectory, its VERTICAL velocity is equivalent to 0 m/s. Thus, we can consider this a free-fall situation.

We must begin by solving for the maximum height reached by the ball using the equation:

\(d = y_0 + v_{0y}t + \frac{1}{2}at^2\)

d = displacement (m)

vi = initial velocity (7.43 m/s)

a = acceleration due to gravity

d = displacement (m)

y0 = initial VERTICAL displacement (28m)

Plug in the values:

\(d = 28 + 7.43(0.758) + \frac{1}{2}(-9.8)(0.758^2) = 30.817 m\)

Now, we can use the rearranged kinematic equation:

\(t = \sqrt{\frac{2h}{g}}\)

\(t = \sqrt{\frac{2(30.817)}{9.8}} = 2.51 s\)

Add the two times together:

\(0.758 + 2.51 = \boxed{3.266 s}\)

Answer:

t = 3.27 s  (2 d.p.)

Explanation:

Use the Constant Acceleration Equations where:

As the projectile is modeled as moving only under the influence of gravity, the only acceleration the projectile will experience will be acceleration due to gravity (g = 9.8 m/s²).  Acceleration due to gravity acts vertically downwards, so will only affect the vertical component of the projectile's velocity.

To find the time it takes for the ball to touch the ground, resolve vertically, taking up as positive:

Given:

\(\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac{1}{2}at^2\\\implies -28 & = (10 \sin 48^{\circ})t+\dfrac{1}{2}(-9.8)t^2\end{aligned}\)

Rearrange the equation to equal zero:

\(\implies 4.9t^2-(10 \sin 48^{\circ})t-28 =0\)

Quadratic Formula

\(x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0\)

Use the quadratic equation to solve for t:

\(\implies t=\dfrac{-(-10 \sin 48^{\circ}) \pm \sqrt{(-10 \sin 48^{\circ})^2-4(4.9)(-28)} }{2(4.9)}\)

\(\implies t=3.266162987, -1.749540894\)

As time is positive,

\(\implies t=3.266162987...\)

\(\implies t=3.27 \: \sf s \: \:(2\:d.p.)\)

Answer:

You may tip the car over or crash.

Explanation:

Going really fast at high speeds and turn a corner might make the car crash into an object or fall over.

If you tend to be absent-minded, the theory of forgetting that is probably to blame is the Encoding Failure Theory. According to this theory, forgetting occurs when information is not properly encoded or stored in memory. In other words, if you are absent-minded and have trouble remembering things, it is likely because you did not pay enough attention to the information in the first place.

Encoding is the process of transforming sensory input into a form that can be stored in memory. If information is not attended to and processed deeply, it will not be encoded properly, leading to difficulties in retrieval and remembering. Therefore, if you tend to be absent-minded, it is essential to ensure that you are paying adequate attention to the information you want to remember.

Furthermore, it is important to note that factors such as stress, sleep deprivation, and lack of concentration can also contribute to encoding failure and forgetfulness. Thus, practicing good study habits, getting enough rest, and reducing stress can improve memory encoding and help reduce forgetfulness.

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Blocks x and y exerts action-reaction forces on each other with 146.1 N and 53.1 N respectively.

The given parameters:

mass of block x = 10 kg

mass of block y = 5 kg

magnitude of the frictional force of block x = 8 N

magnitude of the frictional force of block y = 4 N

the applied force to the right = 40 N

To find:

The block y pulls block x to the left with the following reaction forces;

Force of block y = force due to its own weight + frictional force

where;

g is the acceleration due to gravity = 9.81 m/s²

Thus, block y reacts on block x with a force of 53.1 N

The block x acts on block y towards the right direction with following forces;

Force of block x on y =  force due to its own weight + frictional force + applied force to the right

Thus, block x acts on block y with a force of 146.1 N

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The sun appears larger than other visible stars because it is closer than they are.

The sun appears larger than other visible stars because it is closer than they are. The Sun is a star that is found at the center of our Solar System. The Sun contains around 99.86% of the total mass of the Solar System. The Sun is also known as Sol, which is the source of life for our planet. The Sun is the brightest object in our Solar System.

The sun appears larger than other visible stars because it is closer than they are. Although the sun is one of the smallest stars in the universe, it appears larger and brighter than any of the other visible stars in the sky because it is closer to the Earth than any of the other stars. This is due to the fact that the Sun is the nearest star to the Earth, and as a result, it appears larger and brighter than any of the other visible stars.

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Answer:

\(r = \frac{v}{i} = v = ri \\ i = \frac{v}{r} \)

Answer:

XZXDHF

Explanation:ZDHF

The index of refraction of the unknown material is 1.5.

The index of refraction (n) of a medium is defined as the ratio of the speed of light in a vacuum (c) to the speed of light in the medium (v):

n = c / v

In this case, the speed of light in the unknown material is given as 2.00 × \(10^8\) m/s. The speed of light in a vacuum is approximately 3.00 × \(10^8\) m/s. Substituting these values into the formula:

n = (3.00 × \(10^8\) m/s) / (2.00 × \(10^8\) m/s)

Simplifying the expression:

n = 1.5

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Answer:

increase in amount or extent.

Explanation:

in other words speed up or go faster in a less time period

Answer:

56

Explanation:

Its 56 just because

Answer:

The correct choice is A. She should just create a long-term goal.

She can record what days she exercises and the type of activity to record her progress. Correct option is D.

Documenting the days she exercises and the type of activity she engages in is a valuable way for Dina to track her progress in developing healthy habits. This approach aligns well with her focus on healthy habits rather than a specific weight-related goal.

Tracking exercise routines allows Dina to:

Monitor Consistency: By recording exercise days, she can see how consistently she's engaging in physical activity. Consistency is key to forming lasting healthy habits.

Variety: Recording the types of activities she participates in helps her ensure that she's incorporating a variety of exercises, which contributes to overall fitness and prevents boredom.

Gradual Improvement: Over time, she can observe if she's able to increase the duration, intensity, or frequency of her workouts, indicating progress in her fitness level.

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If the efficiency of this power plant is 70 % of the maximum possible value, 862,920,000 J of heat must be thrown into the river.

The heat that must be dumped into the river will be calculated using the energy conservation law. The energy that goes into the power plant, minus the work done by the plant and the heat that goes into the river, is equal to the energy that is converted into electricity. Therefore, the energy conservation law is expressed as:

E in = E out or E in - E out = 0

The energy going into the power plant is 800,000 kW, and the work thrown into the river is 300 kW; therefore, the energy leaving the plant is (800,000 - 300) kW or 799,700 kW. The efficiency of the plant is 70 percent; therefore, 70 percent of the maximum energy that can be used is converted into electrical energy.

Since the maximum energy that can be used is equal to the energy going into the plant, the electrical energy produced is:

0.7 x 800,000 kW = 560,000 kW

The energy not converted into electrical energy is:

E in - 560,000 kW = 239,700 kW

To compute the heat to be thrown into the river, this amount must be converted into energy or heat:

239,700 kW x 3,600 s = 862,920,000 J

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