A uniform solid sphere with density p and radius R is spinning with angular velocity wo. What torque is needed to stop it in less than At? wo
Answers
The torque needed to stop a uniform solid sphere with density p and radius R, spinning with angular velocity ω₀ in less than time t, is given by:
τ = (8/15)πpR⁴ω₀/t
Determine how to the torque required to stop a rotating object?The torque required to stop a rotating object is equal to the change in angular momentum divided by the time taken. The angular momentum of a rotating sphere is given by Iω, where I is the moment of inertia and ω is the angular velocity.
For a uniform solid sphere, the moment of inertia is (2/5)MR², where M is the mass of the sphere and R is the radius. The mass of the sphere can be calculated using the formula M = (4/3)πR³p, where p is the density of the sphere.
Substituting the values into the equation, we have:
τ = (2/5)(4/3)πR³pR²ω₀/t
= (8/15)πpR⁴ω₀/t
Therefore, the torque needed to stop the spinning sphere in less than time t is (8/15)πpR⁴ω₀/t.
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Related Questions
An empty container has a mass of 3 g. When it is filled with 5 cm3 of a liquid,
the total mass of container and liquid is 7 g. What is the density of the liquid, in g/cm3?
Answers
Answer:
THE MASS OF THE LIQUID IS 22.5 g
Explanation:
Density = 0.180 g/cm3
Side length = 5 cm
Mass = unknown
To calculate the mass of the liquid, we use the formula:
Mass = density * volume
Volume of a cube or cuboid container = l^3
Volume = 5 ^3 = 125 cm3
So therefore, the mass of the liquid is:
Mass = 0.180 * 125
Mass = 22.5 g
In conclusion, the mass of the liquid in the container is 22.5 g
runs with constant velocity of 3.5m/s 2 seconds later bicyclist accelerates at 2.4m/s squared until he catches runner how long does it take to catch the runner and how far has the runner traveled
Answers
It takes 2.916s for the bicyclist to catch the runner and the runner had ran 17.2m with constant velocity of 3.5m/s
What is velocity?How quickly or slowly an object is moving can be determined by its velocity and speed. The need to determine which of two or more moving objects is moving faster arises frequently in our daily lives.
If both vehicles are traveling down the same road in the same direction, it is simple to determine which is moving more quickly.
To tell who is moving faster, though, is challenging if they are moving in the opposite direction. The idea of velocity is valuable in such circumstances
Lets say runner and bicyclist start at a point vi
The distance bicyclist cover to catch runner is \(S = (v_i)t = \frac{1}{2} at^2\)
As the initial velocity is zero distance \(S = \frac{1}{2} at^2\)
For the runner, distance he could run before bicyclist overpassed him is
S = vt
Now as athletes was 7m ahead so
= (athlete)S = (bicyclist)S
= (athlete)S = (bicyclist)S - 7
Substitute the values
= vt = \(\frac{1}{2} at^2\)
= 3.5t = \(\frac{1}{2} (2.4)t^2\)
= 3.5t = 1.2t²
= 3.5 = 1.2t
= t = 2.916s
Distance of runner = 3.5 × 2.916s
= 10.206 + 7m
= 17.2m
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Umm please help?? Please right it on your own words so I don’t get in trouble.
Answers
kepler's laws hold only for the six planets known in his time.
Answers
Kepler's laws are fundamental principles of celestial mechanics and continue to be valid for all planets in our solar system, including the ones discovered after Kepler's era.
Kepler's laws of planetary motion are fundamental principles that describe the motion of planets around the Sun and were derived based on observational data available to Johannes Kepler during the 16th and 17th centuries. However, these laws are not limited to the six planets known in Kepler's time.
Kepler formulated three laws of planetary motion:
1. Kepler's First Law (Law of Ellipses): Planets orbit the Sun in elliptical paths, with the Sun located at one of the two foci of the ellipse. This law applies to all planets, including those discovered after Kepler's time.
2. Kepler's Second Law (Law of Equal Areas): An imaginary line connecting a planet to the Sun sweeps out equal areas in equal time intervals. This law holds for all planets, regardless of when they were discovered.
3. Kepler's Third Law (Harmonic Law): The square of a planet's orbital period is proportional to the cube of its average distance from the Sun. This law applies to all planets, both the ones known in Kepler's time and the ones discovered later.
Kepler's laws are fundamental principles of celestial mechanics and continue to be valid for all planets in our solar system, including the ones discovered after Kepler's era. They provide important insights into the motion and behavior of celestial bodies.
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Prediction 3-1: If you fix a string on two sides, draw what the longest "standing wave" could look like. What is the wavelength for this wave, compared to the length of the string?
Answers
The longest "standing wave" on a fixed string is known as the fundamental mode or the first harmonic. In this mode, the string forms a single loop with an antinode in the middle and nodes at both ends. The wave pattern appears as a single half-wavelength.
If we denote the length of the string as L, the wavelength (λ) of the longest-standing wave in the fundamental mode is equal to twice the length of the string (2L). In other words, the wavelength of the wave is exactly two times the length of the string. To visualize this, imagine a string fixed at both ends and vibrating in its fundamental mode. The wave pattern will exhibit a single loop (one-half of a wavelength) spanning the entire length of the string. The antinode will be positioned in the middle of the string, while the nodes will be located at the fixed ends. In summary, for the longest "standing wave" on a fixed string (fundamental mode), the wavelength is twice the length of the string.
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A 30-turn circular coil of radius 4.00 cm and resistance 1.00 V is placed in a magnetic field directed perpen- dicular to the plane of the coil. The magnitude of the magnetic field varies in time according to the expres- sion B 5 0.010 0t 1 0.040 0t 2, where B is in teslas and t is in seconds. Calculate the induced emf in the coil at t 5 5.00 s.
Answers
According to the question -61.8 mV is the induced emf in the coil at t 5 5.00 s.
What do the two laws of Faraday say?
The first law states that an EMF is induced in a coil anytime the magnetic flux associated with that coil changes. The second law indicates that the coil's rate of change in magnetic flux and the amount of EMF it induces are directly inversely correlated.
The electric potential created by an electrochemical cell or by modifying the magnetic field is referred to as electromotive force. The abbreviation for electromotive force is EMF. Energy is transformed from one form to another using a generator or a battery.
E=-(dΦ_B)/dt
=-d(NBA)/dt
=-NA dB/dt
=-Nπr²d/dt (0.01t+0.04t² )
=-Nπr² (0.01+0.08t),
E(t=5 s)=-30∙π(0.04 m)² (0.01+0.08∙5 s)
=-0.0618 V
=-61.8 mV.
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The induced emf in the coil at t = 5.00 s is -0.078 V. The negative sign indicates that the direction of the induced emf is opposite to the direction of the current that would be produced by the applied magnetic field.
When a coil is placed in a changing magnetic field, an electric field is induced, which results in an induced emf. The induced emf in a coil is given by Faraday's law of electromagnetic induction, which states that the magnitude of the induced emf is equal to the rate of change of the magnetic flux through the coil.
The magnetic flux through the coil is given by the product of the magnetic field strength and the area of the coil. For a circular coil, the area is given by πr², where r is the radius of the coil. Thus, the magnetic flux through the coil is given by Φ = Bπr², where B is the magnetic field strength.
The rate of change of the magnetic flux through the coil is given by the time derivative of the magnetic flux, which is dΦ/dt = πr²dB/dt. Therefore, the induced emf in the coil is given by:
ε = -N(dΦ/dt),
where N is the number of turns in the coil. The negative sign in the equation indicates that the induced emf is in a direction that opposes the change in magnetic flux.
Substituting the expression for B given in the problem statement, we obtain:
dB/dt = 0.010 + 0.080t
At t = 5.00 s, we have:
dB/dt = 0.010 + 0.080(5.00) = 0.410 T/s
Substituting the values for N, r, and dB/dt, we obtain:
ε = -N(dΦ/dt) = -30(π(0.04)²)(0.410) = -0.078 V
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A circuit consists of a 12 V battery connected across a single resistor. If the current in the circuit is
3 A, calculate the size of the resistor
Answers
Answer:
4 Ohms
Explanation:
Apply the formula:
Voltage = I (current) . Resistance
You can change it the way you want to use for your purpose.
In this case...
R = V/I
R = 12/3
R = 4 Ohms (Ohm is the unit of measurement of eletrical resistance)
The ventilation in a house changes the air every five hours. How much power does it take to warm the cold outside air to inside temperature? Assume a standard 150 m2 house and an outside temperature of 0◦C.Inside room temperature 20
Answers
The power needed to warm the cold outside air to inside temperature in a standard 150 m2 house with an outside temperature of 0°C and an inside room temperature of 20°C is 2076.24 watts.
To calculate the power needed, we first need to calculate the amount of heat needed to warm the air. This is done using the following formula:
Heat = Mass * Specific Heat * Temperature Change
The mass of the air in the house is calculated by multiplying the volume of the house by the density of air. The volume of the house is 150 m2 * 3.28 m/m2 = 486 m3. The density of air at 0°C is 1.225 kg/m3.
The specific heat of air is 1.013 kJ/kg·K. The temperature change is 20°C - 0°C = 20°C.
So, the amount of heat needed to warm the air is 486 m3 * 1.225 kg/m3 * 1.013 kJ/kg·K * 20°C = 9962 kJ.
The power needed to warm the air is then calculated by dividing the amount of heat needed by the time it takes to change the air, which is 5 hours * 3600 seconds/hour = 18000 seconds.
So, the power needed is 9962 kJ / 18000 seconds = 0.554 kJ/second = 2076.24 watts.
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A person walking in high heals can damages the floor by making small dimples in the
floor since all their weight is concentrated on the tip of the high heal. It the person
weighs 81 kg and the high of the tip of the high heal is 3.5 cm2, what is the force over
the floor?
SHOW WORK IF POSSIBLE TANKS A LOT
Answers
Answer:
2 314.28571 kg / m
Explanation:
divide
and you see
Project paper:
It consists of a written report that the groups will prepare. Each
group of students has to produce a collective analysis of a
selected company (Mercedes Benz).
1. Strategy Diamond
2. V
Answers
The VRIO analysis will provide valuable insights into the internal factors that contribute to Mercedes Benz's competitive position in the automotive industry.
VRIO Analysis
In addition to the Strategy Diamond, the group will also conduct a VRIO analysis as part of their collective analysis of Mercedes Benz.
VRIO stands for Value, Rarity, Imitability, and Organization, and it is a framework used to evaluate the resources and capabilities of a company.
The VRIO analysis helps assess the competitive advantage of a company by examining whether its resources and capabilities are valuable, rare, difficult to imitate, and well-organized.
This analysis allows the group to identify the company's key strengths and weaknesses and understand how they contribute to its overall strategy.
By applying the VRIO framework to Mercedes Benz, the group can determine which aspects of the company's operations and resources provide a sustainable competitive advantage.
They will evaluate the value of Mercedes Benz's brand reputation, technological innovation, manufacturing capabilities, and distribution network.
They will also assess the rarity of these resources and capabilities and analyze whether competitors can easily imitate or replicate them. Lastly, the group will examine how well Mercedes Benz's organization and management effectively leverage these resources to create value for the company.
The VRIO analysis will provide valuable insights into the internal factors that contribute to Mercedes Benz's competitive position in the automotive industry.
It will help the group understand the unique aspects of the company's operations and guide their analysis of the broader strategic context outlined in the Strategy Diamond.
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If you are 16 miles from Charleston, how long will it take to get there if your average velocity is 42
miles per hour?
Answers
Answer:
22.9 minutes
Explanation:
Distance = Speed x Time
We want the time to go 16 miles at 42 miles/hour (mph).
16 miles = (42 mph)*T
T = 16 miles/(42 miles/hr)
Time = 0.381 hours
(60 minutes/hour)*(.381 hours)= 22.9 minutes
Which of the following is a compound that would
be the most soluble in water? (DOK 2)
O A nitrogen triargonide
O B. carbon tetrachloride
O C. lithium fluoride
O D. magnesium disulfide
Answers
Lithium fluoride will be most soluble in water because it is most strongly ionic.
What is solubility?Solubility is the amount of a substance that dissolves in a given volume of solvent at a particular temperature.
Solubility is affected by:
nature of substance: ionic substances are more soluble nature of solvent: polar solvents dissolves polar distance while non-polar solvents dissolve non-polar substances.temperature: solutesdissolve more at higher temperatureWater is a polar molecule.
Lithium fluoride will be most soluble in water because it is most strongly ionic.
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in the hubble extreme deep field (shown), we see galaxies in many different stages of their lives. in general, which galaxies are seen in the earliest (youngest) stages of their lives?
Answers
In the Hubble Extreme Deep Field, the galaxies seen in the earliest (youngest) stages of their lives are typically the small, faint, and irregularly shaped galaxies.
The Hubble Extreme Deep Field is an image captured by the Hubble Space Telescope that shows a small, seemingly empty patch of sky that contains thousands of galaxies. These galaxies vary greatly in size, shape, and color, and they are located at different distances from us.
Some of these galaxies are very young, while others are much older. However, in general, the galaxies that are seen in the earliest (youngest) stages of their lives tend to be small, faint, and irregularly shaped. This is because they are still in the process of forming and have not yet had the chance to merge with other galaxies or grow in size.
In conclusion, the small, faint, and irregularly shaped galaxies are the ones that are typically seen in the earliest (youngest) stages of their lives in the Hubble Extreme Deep Field. As these galaxies evolve and grow, they may become more structured and take on different shapes and sizes.
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Which factor is the main reason the first spaceships were so large?
a. to improve magnetic levitation
b. to increase the thrust to reach escape velocity
c. to carry more astronauts
d. to carry large amounts of fuel
Answers
Answer:
d
Explanation:
Simplicity of conducting the study is to ________ as ability to test large numbers of participants is to ________.
Answers
Simplicity of conducting the study is to archival research as ability to test large numbers of participants is to surveys.
What is Archival research?Archival research is a type of research which involves seeking out and extracting the evidence from archival records. These archival records may be held together either in the collection of institutions, such as libraries and museums, or in the custody of the organization that originally generated or accumulated them, or in that of a successor object.
Archival research can be contrasted with the secondary research, which involves identification and consulting the secondary sources related to the topic of enquiry; and with the other types of primary research and empirical investigation such as fieldwork and experiment.
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explain why thermal energy is always transferred whenever work is done
Answers
Answer:
Heat
Explanation:
All materials have go some sort of heat.
Answer:Since the friction force is non-conservative as potential energy. All the work done by the friction forces results in a transfer of energy into thermal energy of the box floor system.
Explanation:
why is it important to calibrate the thermometer with a set of standards having a range of melting points
Answers
Calibrating a thermometer is important to ensure that the temperature readings are accurate.
By using a set of standards with a range of known melting points, the thermometer can be calibrated against known temperatures to ensure it is providing accurate readings.
This ensures that when the thermometer is used in experiments or other applications, the measurements taken are reliable and can be trusted. Calibration also allows any potential errors in the thermometer readings to be identified and corrected.
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Why don't normal everyday collisions result in fusion?
Answers
a ball is moving at 7.0 m/s and has a momentum of 100kg m/s what is the balls mass
Answers
Answer: 14,286 kg
Explanation:
Mass and velocity, have a positive correlation to momentum.
The formula to determine momentum is:
Momentum = Mass x Velocity
So, if we want to determine the mass of the object, the formula can be rearranged to look like this:
Momentum/Velocity = Mass
And can be solved by imputing the values given in the question:
Mass = (100 kg*m/s) ÷ (7 m/s)
Mass = 14,286 kg
(A) Calculate the focal length of the mirror formed by the convex side of a shiny spoon that has a 1.97 cm radius of curvature.
__m
(B) What is its power in diopters?
__D
Answers
Answer:(A) For a spherical mirror, the focal length (f) is half of the radius of curvature (R):
f = R / 2
In this case, the radius of curvature is 1.97 cm, so the focal length of the mirror formed by the convex side of the spoon is:
f = 1.97 cm / 2 = 0.985 cm = 9.85 mm
The focal length is 9.85 mm.
(B) The power (P) of a lens or mirror is the reciprocal of its focal length in meters, expressed in diopters (D):
P = 1 / f (in meters)
To convert the focal length from millimeters to meters, we divide by 1000:
f = 9.85 mm / 1000 = 0.00985 m
Substituting this value into the formula for power, we get:
P = 1 / 0.00985 m = 101.53 D
So the power of the mirror formed by the convex side of the spoon is approximately 101.53 D.
Explanation:
(A) The focal length of a mirror is half the radius of curvature. Therefore, the focal length of the mirror formed by the convex side of the shiny spoon with a radius of curvature of 1.97 cm would be:
focal length = radius of curvature / 2
focal length = 1.97 cm / 2
focal length = 0.985 cm
(B) The power of a mirror is the inverse of its focal length, expressed in diopters. The formula for calculating power in diopters is:
power = 1 / focal length
Substituting the focal length we found in part (A), we get:
power = 1 / 0.985 cm
power = 1.015 D
Therefore, the power of the mirror formed by the convex side of the shiny spoon with a radius of curvature of 1.97 cm is 1.015 diopters.
Hi! I'd be happy to help you with your question.
(A) To calculate the focal length (f) of the mirror formed by the convex side of the shiny spoon, we can use the mirror formula:
f = R/2
Where R is the radius of curvature (1.97 cm). Plugging in the value, we get:
f = 1.97 cm / 2
f = 0.985 cm
To convert it to meters, divide by 100:
f = 0.985 cm / 100
f = 0.00985 m
The focal length of the mirror formed by the convex side of the shiny spoon is 0.00985 meters.
(B) To calculate the power (P) in diopters, we can use the formula:
P = 1 / f
Where f is the focal length in meters (0.00985 m). Plugging in the value, we get:
P = 1 / 0.00985 m
P = 101.52 D
The power of the mirror formed by the convex side of the shiny spoon is 101.52 diopters.
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INSTRUCTION:Refer your TWO answers in diagram/picture above with explanation please
>Which combination of elements would likely form a covalent bonds?
a. W and Y
b. Y and Z
c. V and W
d. X and Y
>Which combination of elements would likely form a covalent bonds?
a. V and Z
b. Z and W
c. V and Y
d. Y and X
Answers
#1
W and Y
Y has 6electrons-->2electrons to complete octet.
W has 2electrons-->6electrons to complete octet.
#2
Z and V
V needs 7electrons to complete octet.
Z needs 1 electron to complete octet.
W and Y, Y has 6electrons-->2electrons to complete octet. W has 2 electrons --> 6 electrons to complete the octet. Z and V, V needs 7 electrons to complete the octet. Z needs 1 electron to complete the octet.
How are covalent bonds formed?A covalent bond is formed when two atoms exchange one or more pairs of electrons. The two atomic nuclei are concurrently drawing these electrons to them. The sharing of electron pairs between atoms occurs in covalent bonds.
In contrast to polar covalent bonds, which are formed when electrons are exchanged between atoms with uneven electronegativity, electron pairs shared between atoms with equal or very similar electronegativity form nonpolar covalent bonds, such as H-H or C-H. (e.g., H–O).
Therefore, when the difference between the electronegativities of two atoms is too tiny for an electron transfer to take place to create ions, a covalent bond is formed.
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1.) Calculate whether 14462Sm and 14762Sm may α-decay. The natural abundance of 144Sm is 3.1% and that of 147Sm is 15.0%. How can this be explained ?
2.) Find which of the α and β decays are allowed for 22789Ac.
Answers
1.) 14462Sm and 14762Sm may not α-decay due to their stable nature. The natural abundance of 144Sm is 3.1%, and that of 147Sm is 15.0%.
2.) For 22789Ac, both α and β- decays are allowed.
1) The stability of a nucleus depends on the balance between the strong nuclear force and the electrostatic repulsion among protons. For 14462Sm and 14762Sm, their relative natural abundances (3.1% and 15.0%, respectively) suggest that they are stable and do not undergo α-decay.
2) In the case of 22789Ac, both α-decay (losing a helium nucleus) and β- decay (conversion of a neutron to a proton, releasing an electron and an antineutrino) are allowed, as they help the nucleus achieve a more stable state by reducing the ratio of neutrons to protons or by decreasing the overall mass of the nucleus.
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What’s the substance that is formed as the result of a chemical reaction?
A. Chemical reaction
B. Catalyst
C. Activation energy
D. Collision theory
E. Products
F. Reactants
G. Reaction rate
Answers
Answer:
d
Explanation:
Design two separate oscillators of 97 kHz with NE555, crystal
oscillator and 79 MHz.
Answers
To design separate oscillators of 97 kHz and 79 MHz using the NE555 timer and a crystal oscillator.
Follow the steps below:
Designing an oscillator with the NE555 timer for a frequency of 97 kHz:
1. Connect pins 1 (Ground) and 8 (Vcc) of the NE555 to the appropriate power supply.
2. Connect pin 4 (Reset) to Vcc to disable the reset function.
3. Connect pin 5 (Control Voltage) to Ground.
4. Connect a resistor (R1) and a capacitor (C1) in series between pins 6 (Threshold) and 7 (Discharge). Choose values for R1 and C1 to set the desired time constant.
5. Connect pin 2 (Trigger) to the junction of R1 and C1.
6. Connect pin 3 (Output) to an appropriate load or circuit.
7. Provide necessary decoupling capacitors and stabilize the power supply.
8. Adjust the values of R1 and C1 to achieve the desired frequency of 97 kHz.
Designing an oscillator with a crystal oscillator for a frequency of 79 MHz:
1. Choose a crystal oscillator with a resonant frequency of 79 MHz.
2. Connect the crystal oscillator component to the appropriate pins of a suitable oscillator circuit or microcontroller.
3. Provide necessary decoupling capacitors and stabilize the power supply.
4. Configure the oscillator circuit or microcontroller to use the crystal oscillator component as the clock source.
5. Program or adjust the oscillator circuit or microcontroller to generate an output signal with a frequency of 79 MHz.
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Which technique can scientists use to determine the characteristics of Earth's layers?.
Answers
Scientists can use seismic imaging techniques to determine the characteristics of Earth's layers.
Seismic imaging is a powerful technique used by scientists to study the internal structure of the Earth. It involves analyzing the behavior of seismic waves that propagate through the Earth's layers. Seismic waves are generated by earthquakes or artificially induced vibrations, such as those produced by explosives or specialized machinery.
When seismic waves encounter boundaries between different materials within the Earth, they undergo reflection, refraction, and scattering. By carefully measuring the arrival times, amplitudes, and other properties of these waves at various locations on the Earth's surface or within boreholes, scientists can infer valuable information about the composition, density, and thickness of the Earth's layers.
One commonly used method in seismic imaging is called reflection seismology. It involves deploying a network of seismometers that record the vibrations caused by artificially generated seismic waves. The data collected from these seismometers are then processed and analyzed to create detailed images of the subsurface layers, revealing features such as sedimentary basins, faults, and even the boundaries between different types of rocks.
In addition to reflection seismology, other seismic techniques like refraction seismology and tomography are also employed to further investigate the Earth's layers and their characteristics. These techniques rely on the analysis of how seismic waves travel through the Earth and how their paths are bent or refracted due to variations in the materials they encounter.
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Find the weight of the same object on a planet where the gravitational attraction has been reducted to 1/10 of the earths pull show all work
Answers
Answer: 1/10th of its weight on Earth.
Explanation: Let's assume that the weight of the object on Earth is W, and the gravitational acceleration on Earth is g. We know that weight is given by the formula:
W = m * g where m is the mass
If the gravitational attraction on another planet is 1/10th of Earth's pull, then the gravitational acceleration on that planet will be:
g' = g/10
Using the same formula for weight, the weight of the object on the new planet will be:
W' = m * g'
Substituting the value of g' in the equation above, we get:
W' = m * (g/10)
W' = (m/10) * g
Therefore, the weight of the object on the new planet will be 1/10th of its weight on Earth.
W' = (100/10) N = 10 N
So, the weight of the same object on a planet where the gravitational attraction has been reduced to 1/10th of Earth's pull would be 1/10th of its weight on Earth.
5. {Two polarizing disks have planes that are parallel and centered on a common axis. The direction of the transmission axis (dashed line) in each case is styw relative to the common vertical direction. A polarized beam of light beam of light (with its axis of polarization parallel to the vertical reference direction) is incident from the left on the first disk with intensity S. = 600 W/m? Calculate the transmitted intensity if 8, = 23.0° and 9 - 56.0" W/m2
Answers
The transmitted intensity of the light beam through both polarizers is 223.5 W/m².
\(I_2\)= \(I_1\) cos²θ
where θ is the angle between the transmission axis of the first polarizer and the vertical reference direction. In this case, θ = 23.0°, so:
\(I_2\) = 600 W/m² × cos²(23.0°)
= 445.1 W/m²
\(I_3 = I_2\) cos²ϕ
where ϕ is the angle between the transmission axes of the two polarizers. In this case, ϕ = (90.0° - 56.0°) = 34.0°, so:
\(I_3\) = 445.1 W/m² × cos²(34.0°)
= 223.5 W/m²
Intensity refers to the level of strength or power of a particular phenomenon or activity. It can describe physical phenomena such as light or sound waves, as well as human experiences such as emotions or sensations.
In the context of physical phenomena, intensity typically refers to the amount of energy per unit of time or area, such as the brightness of a light source or the loudness of a sound. In the case of human experiences, intensity can refer to the degree or strength of a sensation or emotion, such as the intensity of pleasure or pain. Intensity can be measured using various quantitative scales or units, depending on the specific phenomenon or experience being measured.
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What is the initial velocity and the net force (I don't want to do this again but I need to know the formula)
If you did it, thank you.
Answers
Answer:
F = 64655.86 N
Explanation:
Im not sure about the initial velocity but its somewhere near 0.23 m/s
A ball is dropped from the top of a cliff. Which graph best represents the relationship between the ball's total energy and the elapsed time as the ball falls to the ground?
Answers
Graph A does.
The work you do to carry the ball up to the top of the cliff is the total energy it has.
Before you drop it, all that energy is potential energy.
Once you drop it, the potential energy starts to turn into kinetic energy as it falls.
When it hits the ground, its kinetic energy is exactly the amount of potential energy it had at the top, and it has no more potential energy.
The total (potential + kinetic) energy is the same amount all the way down. Energy isn't created or destroyed.
The graph that shows the ball's total energy and the elapsed time as the ball falls to the ground is graph A.
For a body that is falling from a height, the potential energy of the body is being converted to kinetic energy. We must note that the total mechanical energy of the body is constant.
As such, the graph that shows the ball's total energy and the elapsed time as the ball falls to the ground is graph A.
Learn more about mechanical energy: https://brainly.com/question/1932868
What is the gravitational field a distance d above the center of
a uniformly-dense disk
of radius R?
Please, write the answer neatly.
Answers
The gravitational field at a distance d above the center of a uniformly-dense disk of radius R can be calculated using the following formula:
g = (2 * G * σ * R² * d) / (R² + d²)^(3/2)
Where:
g is the gravitational field strength,
G is the gravitational constant (approximately 6.67430 × 10^(-11) m³ kg^(-1) s^(-2)),
σ is the surface mass density (mass per unit area) of the disk.
Please note that the surface mass density, σ, should be provided for a more specific calculation.
To know more about density please click :-
brainly.com/question/29775886
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