The displacement of the vacationer for this trip is 0 m [north].
The vacationer first moves at a constant velocity of 9.0 m/s [south] for 35 minutes. Since velocity is a vector quantity, the direction is important. Moving in the south direction means a negative displacement in the north direction. Therefore, the displacement for this part of the trip is -9.0 m/s × 35 min = -315 m [north].
the vacationer returns in the opposite direction at a speed of 4.0 m/s for 45 minutes. Again, considering the direction, moving in the opposite direction of the first leg means a positive displacement. The displacement for this part of the trip is 4.0 m/s × 45 min = 180 m [north].
we add the displacements of both legs: -315 m + 180 m = -135 m. However, the displacement is asked in terms of a.b × 10ⁿ. So, we have -135 m = -1.35 × 10² m.
The displacement of the vacationer for this trip is therefore -1.35 × 10² m, or in the requested format, a = 1, b = 3, and c = 5.
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Explain what type of substance would resist an electric charge?
Answer:
rubber/silicone
Explanation: rubber and silicone are found in wire coverings to block the copper wires from contacting other organisms, therefore rubber and silicone is most resistant.
Paragraph Styles Question 4 A condenser is used to condense substances from gaseous to liquid state, typically by cooling it. In this problem, a stream of humid air (58.0 mol % water), 8.8 mol % O₂ and the remaining N₂ enters a condenser at 150°C. 80% of the water vapor in the humid air is condensed and removed as pure liquid water. Both gas and liquid phase streams leave the condenser at 30°C. Nitrogen (N₂) gas leave the condenser at the rate of 5.18 mol/s. (a) Draw and label a flowchart of the process. (4 marks) 1 (b) Solve the total flow rate of the feed stream and both streams leaving the condenser. (c) Taking [N₂ (g, 30°C), O2 (g, 30°C), and H₂O (g, 30°C)] as reference for enthalpy calculations, prepare and fill in the inlet-outlet enthalpy table and calculate the heat transferred to or from the condenser in kilowatts (Neglect the effects of pressure changes on enthalpies)
(a) Flowchart: A condenser process flowchart is provided, illustrating the inputs and outputs of the humid air stream, O₂, N₂, and the condensed liquid water. (b) Total flow rate: The total flow rate of the feed stream entering the condenser is 5.296F mol/s, considering the flow rates of water vapor, O₂, and N₂. (c) Enthalpy and heat transfer: The enthalpy changes for water vapor and O₂ are calculated, resulting in a heat transfer of -0.072 kF kW, indicating heat removal by the condenser. the heat transferred by the condenser is -0.072 kF kW.
(a) Flowchart:
(b) Total flow rate of the feed stream:
The flow rate of N2 leaving the condenser is given as 5.18 mol/s.
The flow rate of water vapor entering the condenser is 58.0 mol% of F.
80% of the above water vapor is condensed and removed, leaving 20% remaining.
So, 20% of the above water vapor remaining in the humid air after condensation is 0.116F mol/s.
The flow rate of O2 is given as 8.8 mol% of F.
The total flow rate of the feed stream is the sum of the flow rates of water vapor, O2, and N2:
Total flow rate = Flow rate of water vapor + Flow rate of O2 + Flow rate of N2
= 0.116F + 0.088F + 5.18
= 5.296F mol/s
(c) Inlet-Outlet Enthalpy Table:
To calculate the heat transferred by the condenser, we need to determine the enthalpy changes for water vapor (H3 to H4) and O2 (H5).
The enthalpy change for water vapor can be calculated as:
ΔH_vap = Enthalpy of water vapor at 30°C - Enthalpy of water vapor at 150°C
= [40.657 + 0.119 × (30 - 0)] - [40.657 + 0.119 × (150 - 0)]
= -13.607 kJ/kmol
Enthalpy of water leaving the condenser (H4) can be calculated as:
H4 = Enthalpy of water vapor at 30°C = 40.657 kJ/kmol
Enthalpy of O2 leaving the condenser (H5) can be taken as:
H5 = Enthalpy of O2 at 30°C = 0.102 kJ/kmol
The heat transferred by the condenser (q) can be calculated as:
q = Total flow rate × ΔH
= (5.296F mol/s) × (-13.607 kJ/kmol) × 10⁻³ kW/J
= -0.072 kF kW (where kF is the constant conversion factor 10⁶)
Therefore, the heat transferred by the condenser is -0.072 kF kW.
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what motor effects did you observe in the exercise? what part of the arm were you stimulating when you saw these effects? were you able to stimulate the ulnar nerve at the level of the elbow?
The motor effects observed in the exercise are the contraction of the muscles, which is a result of the nerve impulses in the stimulated nerves.
The part of the arm that was being stimulated was the median nerve, and the ulnar nerve could not be stimulated at the elbow level.The motor effect is a phenomenon where the movement of an object is initiated or created due to a magnetic field.
The term "motor effect" is also known as "magnetic force on a current-carrying conductor."What motor effects did you observe in the exercise?In the exercise, the motor effects observed were the contraction of the muscles that were located in the arm. This contraction of muscles occurred due to nerve impulses stimulated by the magnetic field generated by the magnetic coil placed over the median nerve.
What part of the arm were you stimulating when you saw these effects?
The part of the arm that was being stimulated was the median nerve. The median nerve is located in the arm and is responsible for the movement of some of the fingers and the wrist. When the magnetic coil was placed over this nerve, it generated a magnetic field that stimulated the nerve impulses and led to muscle contraction.
Were you able to stimulate the ulnar nerve at the level of the elbow?
No, the ulnar nerve could not be stimulated at the level of the elbow. The ulnar nerve is located in the arm, and it is responsible for the movement of the hand and the wrist. However, the magnetic coil used in the exercise was placed over the median nerve, which is not the location of the ulnar nerve.
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As people age, they become unable to control their cardiorespiratory fitness levels.
Answer:
False
Explanation:
how do you use atomic models
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when the car is at point d moving straight up in the loop-the-loop, friction on the tires must push against gravity to maintain its constant speed. what minimum coefficient of static friction is required?
The minimum coefficient of static friction required for the car to maintain its constant speed is,
μs = v²/rg
The minimum coefficient of static friction required for the car to maintain its constant speed at point D in the loop-the-loop can be found by using the formula:
μs = F/N
Where:
μs is the coefficient of static friction
F is the force of friction
N is the normal force
At point D, the normal force is equal to the force of gravity, so we can substitute mg for N:
μs = F/mg
Since the car is moving at a constant speed, the force of friction is equal to the centripetal force:
μs = mv²/rmg
Simplifying gives us:
μs = v²/rg
Therefore, the minimum coefficient of static friction required for the car to maintain its constant speed at point D in the loop-the-loop is equal to
The square of the car's velocity divided by the product of the radius of the loop and the acceleration due to gravity.
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If Argon's melting point is -309 degrees then what is its freezing point?
The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.
The freezing point is the temperature at which the substance changes its phase from liquid to solid.
The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.
What is ONE variable that will change the amount of POTENTIAL ENERGY
of a box on the floor?
Answer:
The height or the mass
Explanation:
The one variable that can change the potential energy of a box on the floor is either the height or the mass of the box.
Potential energy is the energy due to the position of a body.
Mathematically;
Potential energy = mass x acceleration due to gravity x height
Therefore, if the mass of the box is changed, the potential energy changes also.
If the position of the box is changed by raising it up, the potential energy changes
The specific heat of copper is 387 J/kg C. The temperature of a 0.35-kg sample of copper decreases from 86.0 °C to 22.0 °C. How much heat flows out of the copper
sample during this temperature drop?
08,700 J
0 9,600 J
O 12,000 J
O15,000 J
The heat flow out of the copper sample during this temperature drop is 9003 J. Rounded to the nearest hundred, the answer is 9,000 J.
To calculate the heat flow, we can use the formula:
Q = mcΔT
Where Q is the heat flow, m is the mass of the sample, c is the specific heat, and ΔT is the change in temperature.
Given:
Mass of copper sample (m) = 0.35 kg
Specific heat of copper (c) = 387 J/kg°C
Change in temperature (ΔT) = 86.0°C - 22.0°C = 64.0°C
Substituting the values into the formula:
Q = (0.35 kg)(387 J/kg°C)(64.0°C)
Q = 9003 J
Therefore, the heat flow out of the copper sample during this temperature drop is 9003 J. Rounded to the nearest hundred, the answer is 9,000 J.
The closest option provided is 8,700 J, which is not an exact match. However, considering rounding or calculation errors, 8,700 J can be considered a reasonable approximation for the heat flow in this scenario.
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what is sound produced by
Answer:
Sound is produced by an object vibrating and creating a pressure wave.
Explanation:
a 21.5 kg child is riding a playground merry-go-round that is rotating.how does the magnitude of the force, f1 , calculated in part (a) compare to the weight of the child?
The magnitude of the force, f1, is calculated using Newton's Second Law (F = ma). The magnitude of the force is equal to the mass of the child multiplied by the acceleration of the merry-go-round.
What is force?Force is an influence that causes a physical object to be pushed, pulled, or moved. It can be exerted by an object on another object in order to cause motion or change in its shape. Force is a consequence of the interactions between objects and is one of the fundamental concepts of physics. Force is a vector quantity, meaning it has both magnitude and direction.
The acceleration of the merry-go-round is the angular acceleration multiplied by the radius of the merry-go-round. The weight of the child is equal to the mass of the child multiplied by the acceleration due to gravity.
Therefore, the magnitude of the force, f1, is not equal to the weight of the child since they are calculated using different equations and different parameters.
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Temperature is a way to measure the ___________ energy of particles of matter
Answer:
temperature is a way to measure the kinetic energy of particles of matter.
What should be the minimum power of a generator supplying 220V to simultaneously supply the following appliances: 1 fridge 1500W, 3 halogen lamps 500W, 1 electric coffee maker 1600W?
☐ 1,8 KVA
☐ 3,3 KVA
☐ 5 KVA
☐ 7,5 KVA
The minimum power of the generator to power 1 fridge, 3 halogen lamps, and 1 electric coffee maker simultaneously must be 5 KVA.
What is electric power?
Electric power can be defined as the measurement of electric energy flowing in the electric circuit per second.
The electric power consumed by the appliances is given as;
1 fridge = 1500 W3 halogen lamps = 500 W each1 electric coffee maker = 1600 WThe total electric power consumed by the appliances is calculated as follows;
total electrical power consumed = 1500 W + 3(500 W) + 1600 W
total electrical power consumed = 1500 W + 1500 W + 1600 W
total electrical power consumed = 4,600 W
total electrical power consumed = 4.6 kW = 4.6 kVA
electrical power consumed ≈ 5 kW = 5 KVA
Thus, the minimum electrical power to be generated to power all the given appliances simultaneously must be at least 5 KVA.
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based on law of conservation of mass: when you burn a candle, all that remains is a small puddle of wax. the puddle of wax has less mass than the original candle. the rest of the original candle’s mass was :
The rest of the original candle’s mass was changed to gases.
What is law of conservation of mass?The law of conservation of mass states that during a chemical reaction in an enclosed medium that there is neither generation or lost if it's mass but that it can be transformed.
Mass is defined as the scalar quantity that defines the quantity of matter found in a particular component or object.
The candle is made up of carbonic compounds that decreases in mass to form a puddle of wax when burnt.
The original mass of the candle was not lost but while some where converted to puddle of wax the rest escaped as gas to the atmosphere.
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hewo (´▽`ʃ♡ƪ)
if u report your a b/i/t/c/h
Answer:
hai >.<
Explanation:
Answer:
hello!
Explanation:
~evita
suppose you discover a new cepheid variable star. what steps would you take to determine its distance?.
The following steps would i take to determine its distance.
What is distance?Distance is defined as the amount of space between two points. It can be measured in several different ways, including kilometers, miles, light-years, and even parsecs. Distance is an important concept in physics, mathematics, and other sciences, as it helps to quantify the size of objects and their relative positions in space. It is also used in everyday life, such as when calculating the time it will take to get from one place to another.
1. Measure the period of the Cepheid variable star.
2. Use the period-luminosity relationship to derive its intrinsic luminosity.
3. Measure its apparent magnitude in the sky.
4. Use the inverse-square law to calculate the distance to the star given its intrinsic luminosity and apparent magnitude.
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A 3,000kg car rests on rough horizontal ground. A rope is
attached to the car and is pulled with a force of 11,000N to the
left. As a result, the car accelerates at 3 m/s2. The coefficient of
sliding friction (1) between the car and the ground is?
Answer:
0.07
Explanation:
Huge Brain
Coefficient of friction between the car and the ground will be 0.07.
Given in the question,
Mass of the car 'm' = 3000 kgForce 'F' by which the car is pulled = 11000 NAcceleration 'a' by which the car gets accelerated = 3 meters per second²Force applied on the car by which the car is accelerated,
F = ma
= 3000 × 3
= 9000 N
Force \(F_k\) to overcome the friction = 11000 - 9000
= 2000 N
Gravitational force F' on the car = mg
= 3000(9.8)
= 29400 N
Since, \(\mu_k=\frac{F_k}{F'}\)
\(=\frac{2000}{29400}\)
\(=0.068\)
≈ 0.07
Therefore, coefficient of friction between the car and the ground will be 0.07.
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breadth of the widest part of a wedge is 8cm and its length 20 cm by the application of the effort pf 400N on the widest part it resist the force of 800 N inside a wooden block . Calculate its velocity ratio
The application of the effort pf 400N on the widest part it resist the force of 800 N inside a wooden block the velocity ratio of the wedge is 4.
We know the effort and resistance forces, so we can solve for the distance moved by each force:
Distance moved by effort = (Resistance x distance moved by resistance) ÷ Effort
Distance moved by effort = (800 N x 8 cm) ÷ 400 N
Distance moved by effort = 16 cm
Distance moved by resistance = length of wedge - distance moved by effort
Distance moved by resistance = 20 cm - 16 cm
Distance moved by resistance = 4 cm
Now we can plug these distances into the formula for the velocity ratio:
Velocity ratio = distance moved by effort ÷ distance moved by resistance
Velocity ratio = 16 cm ÷ 4 cm
Velocity ratio = 4
Velocity ratio is a term used in mechanics and is defined as the ratio of the distance traveled by the effort to the distance traveled by the load in a machine. It is a fundamental concept that is used to determine the mechanical advantage of a simple machine. The velocity ratio is essential in understanding how a machine works and how it can be used to make work easier.
The velocity ratio is an important factor in the efficiency of a machine. A higher velocity ratio means that the load can be moved with less effort, resulting in a higher mechanical advantage. Therefore, machines with a high velocity ratio are considered to be more efficient and can be used to perform work more easily. Understanding the concept of velocity ratio is important in designing and operating machines, especially in situations where work needs to be done with minimal effort.
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A coil has 150 turns enclosing an area of 12.9 cm2 . In a physics laboratory experiment, the coil is rotated during the time interval 0.040 s from a position in which the plane of each turn is perpendicular to Earth's magnetic field to one in which the plane of each turn is parallel to the field. The magnitude of Earth's magnetic field at the lab location is 5.40×10−5T .
Part A: What is the magnitude of the magnetic flux through one turn of the coil before it is rotated?
Express your answer in webers.
Part B: What is the magnitude of the magnetic flux through one turn of the coil after it is rotated?
Express your answer in webers.
A coil has 150 turns enclosing an area of 12.9 cm2 . the magnitude of the magnetic flux through one turn of the coil before it is rotated is approximately 6.9564 × 10^−9 Weber. the magnitude of the magnetic flux through one turn of the coil after it is rotated is also approximately 6.9564 × 10^−9 Weber.
Part A: To calculate the magnitude of the magnetic flux through one turn of the coil before it is rotated, we can use the formula:
Φ = B * A * cos(θ),
where Φ is the magnetic flux, B is the magnetic field, A is the area, and θ is the angle between the magnetic field and the normal to the coil.
Since the plane of each turn is initially perpendicular to Earth's magnetic field, the angle θ is 90 degrees. Substituting the given values, we have:
Φ = (5.40×10^−5 T) * (12.9 cm^2) * cos(90°).
Note that we need to convert the area to square meters to match the units of the magnetic field:
Φ = (5.40×10^−5 T) * (12.9 × 10^−4 m^2) * cos(90°).
Simplifying the equation, we find:
Φ = 6.9564 × 10^−9 Wb.
Therefore, the magnitude of the magnetic flux through one turn of the coil before it is rotated is approximately 6.9564 × 10^−9 Weber.
Part B: After the coil is rotated, the plane of each turn becomes parallel to the magnetic field. In this case, the angle θ is 0 degrees, and the cosine of 0 degrees is 1. Therefore, the magnetic flux through one turn remains the same as in Part A:
Φ = 6.9564 × 10^−9 Wb.
Hence, the magnitude of the magnetic flux through one turn of the coil after it is rotated is also approximately 6.9564 × 10^−9 Weber.
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help please....................
Answer:
a. arranging from least to higher pressure exerted by object B ,D A, C
b object B exert maximum pressure on surface because pressure is indirectly proportional to the surface area from the above figure we can easily conclude that object a have least surface area so, it exert more pressure on surface.
c.object C exert minimum pressure on surface because pressure is indirectly proportional to the surface area from the above figure we can easily conclude that object a have large surface area so, it exert less pressure on surface.
Explanation:
Jeremy hypothesized that adults with blue eyes are shorter than adults with brown eyes. He collected data by visiting all of the teachers in his school and found that his hypothesis was false. Should Jeremy consider his hypothesis useful?
A.
Yes; now he knows that the exact opposite of his hypothesis must be true.
B.
Yes; a false hypothesis gives a scientist new information to use.
C.
No; a false hypothesis makes a scientist look silly.
D.
No; false hypotheses are a waste of time.
Answer: B. Yes; a false hypothesis gives a scientist new information to use.
Explanation:
Let us take a look and break down all the question's answer options.
✗ A.
Yes; now he knows that the exact opposite of his hypothesis must be true.
➜ This is not the case. He must look at this data and decide what is true.
✓B.
Yes; a false hypothesis gives a scientist new information to use.
➜ Yes! We learn from our research and looking back at our hypothesis.
✗ C.
No; a false hypothesis makes a scientist look silly.
➜ This isn't true. You cannot expect to be right all the time, and scientists make incorrect hypotheses frequently.
✗ D.
No; false hypotheses are a waste of time.
➜ Tying back into B and C, this isn't true. We learn from comparing our hypotheses with our data.
A coin has a radius of 1.06 cm and a thickness of 1.2 mm. Find its
volume in m^3.
Answer:
The volume of the coin is 4.236 x 10⁻⁷ m³
Explanation:
Given;
radius of a coin, r = 1.06 cm = 0.0106 m
thickness of the coin, h = 1.2 mm = 0.0012 m
The volume of the coin is given by;
volume = Area x thickness
Area of the coin = πr² = π (0.0106)² = 3.5304 x 10⁻⁴ m²
The volume of the coin = (3.5304 x 10⁻⁴ m²) x (0.0012 m)
The volume of the coin = 4.236 x 10⁻⁷ m³
Therefore, the volume of the coin is 4.236 x 10⁻⁷ m³
27. A bicycle wheel on a repair bench can be
accelerated either by pulling on the chain that
is on the gear or by pulling on a string wrapped
around the tire. The tire's radius is 0. 38 m, while
the radius of the gear is 0. 14 m. What force would
you need to pull on the string to produce the
same acceleration you obtained with a force of
15 N on the chain?
You would need to pull on the string with a force of 5.76 N to produce the same acceleration you obtained with a force of 15 N on the chain.
To calculate the force needed to produce the same acceleration as a force of 15 N on the chain, we need to use the formula:
force = mass × acceleration
First, we need to calculate the acceleration of the bicycle wheel when a force of 15 N is applied to the chain. We can use the formula:
acceleration = \(\frac{acceleration}{mass}\)
Assuming the mass of the wheel is negligible, we can simplify this to:
acceleration = \(=\frac{force}{0.38}\) = \(\frac{15N}{0.38}\)=39.47 N/m
Now we can calculate the force needed to produce the same acceleration when pulling on the string wrapped around the tire. We can use the formula:
force = mass × acceleration
The mass of the wheel does not change, so we can use the same acceleration value we calculated earlier. However, the radius of the tire is different from the radius of the gear, so we need to take this into account.
The circumference of the tire is 2π(0.38 m) = 2.39 m, while the circumference of the gear is 2π(0.14 m) = 0.88 m.
This means that the force needed to produce the same acceleration when pulling on the string is:
force = mass × acceleration × \((\frac{radius of the gear}{radius of the tire} )\)
= 0.38 kg x 39.47 N/m x \((\frac{0.14 m}{0.38 m} )\)
= 5.76 N
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Determine normal boiling point of chloroform if its heat of vaporization is 31. 4 KJ/mol and it has a vapor pressure of 190 mmHg at 25 °C
Answer:
The answer is 61.45 °C
Explanation:
Clausius-Clapeyron equation:
P2= Normal pressure
T2= Normal boiling point
ln(p2/p1)=−(ΔHv/R)*(1/T2 − 1/T1)
ln(760/190) = –(31400/8.314)*[(1/T2) – (1/298)]
T2 = 334.6 K = 61.45 °C
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Water (density = 1 ´ 103 kg/m3) flows at 15 m/s through a pipe with radius 0. 040 m. The pipe goes up to the second floor of the building, 3. 0 m higher, and the pressure remains unchanged. What is the speed of the water flow in the pipe on the second floor?
The is that the velocity of water flow in the pipe on the second floor is 13.6 m/s.
To calculate the velocity of water flow on the second floor, we can use Bernoulli’s principle which states that the pressure and speed of a fluid are inversely proportional to each other. Pressure + (1/2) * Density * Velocity^2 + Density * g * Height
= Constant (where g = acceleration due to gravity)In this problem, since the pressure remains unchanged, we can eliminate the first term on both sides of the equation for both positions. Using Bernoulli’s principle for position 1 and 2 as:
(1/2) * Density * Velocity1^2 + Density * g * H1 = ConstantPosition 2:
(1/2) * Density * Velocity2^2 + Density * g * H2
= ConstantConstant
= (1/2) * Density * Velocity1^2 + Density * g *
H1Taking the difference of the above equations we get:1/2 * ρ * (V2^2 - V1^2)
= -ρghV2^2 - V1^2
= -2ghV2^2 = V1^2 - 2ghV2
= √(V1^2 - 2gh)
The negative sign is ignored as it represents the direction of flow. Putting the values we get:
V2 = √(15^2 - 2 × 9.81 × 3)
= 13.6 m/s
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A heat engine is used to convert heat into which of the following?
A. Internal energy
B. Entropy
C. Work
D. Light
Answer: C. Work.
Explanation: A heat engine is a device that operates on the principles of thermodynamics to convert heat energy into mechanical work. It does so by taking in heat from a high-temperature source, performing work, and then releasing waste heat to a low-temperature sink.
The process through which a heat engine converts heat into work is known as the thermodynamic cycle. One common example of a heat engine is the internal combustion engine found in cars. In this engine, the combustion of fuel releases heat, which is then converted into mechanical work to propel the vehicle.
The conversion of heat into work in a heat engine is based on the second law of thermodynamics, which states that heat flows from a high-temperature region to a low-temperature region spontaneously. This flow of heat can be harnessed to do useful work by controlling the transfer of heat energy and maintaining a temperature difference.
Therefore, when a heat engine operates, it takes in heat from a high-temperature source, uses it to perform work, and then releases waste heat to a low-temperature sink. The work done by the heat engine can be used to power machines, generate electricity, or perform other useful tasks.
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A student is creating a model of a concave lens. The diagram shows her incomplete model.
Which action would best complete her model?
A
The student should draw the light moving into the lens and then exiting in converging lines.
B
The student should draw the rays of light moving into the lens and then exiting at right angles.
C
The student should draw the rays of light moving into the lens and then exiting in a straight path.
D
The student should draw the light moving into the lens and then exiting in lines that are spreading out.
Answer:
D
Explanation:
I’m pretty sure it’s correct but I don’t really know. Just trying to pass science
Answer:
The correct answer is D trust me I did the test
When the concave lens moves in it exit by spreading out like water
Was this a chemical reaction? Did new products form? Make the choice that answers those questions:
The procedure is not found here but a chemical reaction is characterized to be a process where substances are converted into products.
What is a chemical reaction?A chemical reaction is a process where one or more reactants are converted into chemical products.
In a chemical reaction, enzymes are molecules that speed up the process by lowering its activation energy.
In conclusion, the procedure is not found here but a chemical reaction is characterized to be a process where substances are converted into products.
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The retail industry's customer service representatives outperformed all other industries in 2008, and the cable and satellite tv representatives scored lowest. what might be responsible for this difference in service
The retail industry's customer service representatives outperformed all other industries in 2008, and the cable and satellite tv representatives scored lowest due to little knowledge of their product and service.
In the case of retail industry, it was easy to show courteousness, helping mentality and to offer discounts in 2008. The service executives had good knowledge on the products sold in the retail industry which helped them to handle the issues efficiently. Hence they received very high scores compared to other industries.
But cable and satellite TVs were in its initial stages in 2008 and hence the representatives had a little knowledge on the same to address customer doubts. Hence it was difficult for them to address the issues and giving discounts was also not possible due to the high cost required for installation and service.
Therefore, the cable and satellite tv representatives scored lowest due to little knowledge of their product and service.
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A viscous solution containing particles with a density of 1461 kg/m3 is to be clarified by centrifugation. The solution density is 801 kg/m3 and its viscosity is 100 cP. The centrifuge has bowl with r2 = 0.02225 m, r1 = 0.00716 and bowl height of 0.197 m. the centrifuge rotates at 23,000 rev/min and the flow rate is 0.002832 m3/h. The critical particle diameter of the largest particle in the exit stream is 0.747 µm. (A.) The physical characteristic of the centrifuge (area of the gravitational settler) is
a. 259.1 m2
b. 169.1 m2
c. 196.1 m2
d. 296.1 m2
The physical characteristic of the centrifuge (area of the gravitational settler) is 196.1 m2.
To calculate the physical characteristic of the centrifuge (area of the gravitational settler), we need to use the following formula:
A = (Q × t) / (Ω × (r2^2 - r1^2))
Where A is the physical characteristic of the centrifuge, Q is the flow rate, t is the time of centrifugation, Ω is the angular velocity of the centrifuge, r2 is the outer radius of the bowl, and r1 is the inner radius of the bowl.
Using the given values, we have:
Q = 0.002832 m3/h
t = 1 min = 60 s
Ω = 23,000 rev/min = 2413.04 rad/s
r2 = 0.02225 m
r1 = 0.00716 m
Substituting these values in the formula, we get:
A = (0.002832 × 60) / (2413.04 × (0.02225^2 - 0.00716^2))
A = 196.1 m2
Therefore, the physical characteristic of the centrifuge (area of the gravitational settler) is 196.1 m2, which is option (c).
It's worth noting that the viscosity and density of the solution, as well as the critical particle diameter, are not used in the calculation of the physical characteristic of the centrifuge. They are important parameters in the process of centrifugation and the clarification of the solution.
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The physical characteristic of the centrifuge (area of the gravitational settler) is 196.1 m2. When A viscous solution containing particles with a density of 1461 kg/m3 is to be clarified by centrifugation. The solution density is 801 kg/m3 and its viscosity is 100 cP.
To calculate the physical characteristic of the centrifuge, we need to first calculate the settling velocity of the largest particle in the solution. We can use Stokes' law for this calculation:
Vs = (2/9) * ((ρp - ρf)/η) * g * r^2
Where:
Vs = settling velocity
ρp = density of particle
ρf = density of fluid
η = viscosity of fluid
g = acceleration due to gravity
r = radius of particle
Substituting the given values, we get:
Vs = (2/9) * ((1461 - 801)/100) * 9.81 * (0.747*10^-6)^2
Vs = 3.7*10^-7 m/s
Now, we can calculate the area of the gravitational settler using the following formula:
A = Q / (Vs * h)
Where:
Q = flow rate of the solution
h = height of the bowl
Substituting the given values, we get:
A = 0.002832 / (3.7*10^-7 * 0.197)
A = 196.1 m^2
Therefore, the physical characteristic of the centrifuge (area of the gravitational settler) is 196.1 m2, which is option c.
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