A vertical spring gun is used to launch balls into the air. If the spring is compressed by 4.9 cm, the ball of mass 5.5 g is launched to a maximum height 50.2 cm. How much should the spring be compressed to send the ball twice as high?

Answers

Answer 1

We know, by conservation of energy :

\(\dfrac{kx^2}{2}=mgh\)

Therefore,

\(\dfrac{x_1^2}{x_2^2}=\dfrac{h_1}{h_2}\)

Putting given values, we get :

\(\dfrac{x_1^2}{x_2^2}=\dfrac{h_1}{h_2}\\\\\dfrac{4.9^2}{x_2^2}=\dfrac{50.2}{2\times 50.2}\\\\x_2^2=2\times 4.9^2\\\\x_2 = 4.9\times \sqrt{2}\\\\x_2=6.93\ cm\)

Therefore, the spring be compressed to 6.93 cm to send the ball twice as high.

Hence, this is the required solution.


Related Questions

A typical radio wave has a period of 1.3 µs.
Express this period in seconds.

Answers

Answer:

  1.3×10^-6 s = 0.0000013 s

Explanation:

µ is used to stand for "micro-", the SI prefix meaning 10^-6.

  1.3 µs = 1.3×10^-6 s

For a constant voltage, how is the resistance related to the current?

Answers

Answer:

Resistance is inversely proportional to current, so when the resistance doubles, the current is cut in half. Resistance is directly proportional to current, so when the resistance doubles, the current is cut in half.

can anyone write for me all the equation of linear motion​

Answers

All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.

Equations of Motion

In terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.

s = ut + (1/2)at^2v = u + atv_avg = (u + v) / 2s = v_avg * ts = (u + v) / 2 * tv^2 = u^2 + 2as

In conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.

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How many protons, neutrons, and electrons are present in this isotope of nitrogen?

7 protons, 15 neutrons, 0 electrons

7 protons, 8 neutrons, 0 electrons

7 protons, 8 neutrons, 7 electrons

15 protons, 7 neutrons, 8 electrons

How many protons, neutrons, and electrons are present in this isotope of nitrogen?7 protons, 15 neutrons,

Answers

Answer:

7 protons, 8 neutrons, 7 electrons

Explanation:

Protons, electrons and neutrons are three sub-atomic particles present in an atom. Protons and neutrons are present in the nucleus while electrons are present outside the nucleus.

The number of protons, which is also the ATOMIC NUMBER, is equal to the number of electrons in a neutral atom (no overall charge). In this case, the number of protons is 7, however, since the charge of this Nitrogen atom is 0, it means that the number of electrons is also 7.

The mass number, denoted by A, is the sum of the number of protons and neutrons in an atom i.e.

A = number of proton + number of neutron.

In this case of Nitrogen isotope where the mass number is 15, the number of neutron will be mass number - number of protons i.e. 15 - 7 = 8.

Therefore, the number of protons, neutrons and electrons are 7, 8 and 7 respectively.

Determine the order of magnitude of the following small number by entering the appropriate exponent n below: 4,870×1021kg≈10nkg .(PLEASE LOOK AT THE SCREENSHOT FOR CORRECT NUMBERING)

Determine the order of magnitude of the following small number by entering the appropriate exponent n

Answers

To find the order of magnitude we move the decimal point until we have only one interger before it:

\(4870\times10^{21}=4.870\times10^{24}\)

Now that we have in this form we conclude that the order of magnitude of the number is 24

Calculate Suppose an
object weighs 15 g and has
a volume of 5 cm. What is
the density of the object?

Answers

Answer: 3

To find the density of any object, you need to know the Mass of the object, and its Volume. Divide the mass by the volume in order to get an object's Density.

4. In a physics lab, Kate and Rob use a hanging mass and pulley system to exert a 2.45 N
rightward force on a 0.500-kg cart to accelerate it across a low-friction track. If the total
resistance force to the motion of the cart is 0.72 N, then what is the cart's acceleration?

Answers

Fgrav = 4.90 N; Fnorm = 4.90 N; Fnet = 1.73 N, then the acceleration of the cart is (a) = 3.46 m/s/s,

What is acceleration and its types?

Acceleration is defined as a vector quantity, the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity. It can be either positive, negative, or zero depending upon the velocity and its direction. Three types of acceleration are Uniform acceleration, non-uniform acceleration, and average acceleration.

Formula

{a} = v - v0/t =Δv/Δ t

{a} = average acceleration

v = final velocity

v_0 = starting velocity

t = elapsed time

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Does heat and temperature depend on the other or are they totally separate ideas? Explain.

Answers

Answer:

What heat means in thermodynamics, and how we can calculate heat using the heat ... Scientists define heat as thermal energy transferred between two systems

Explanation:

thermal energy

While forming a 1.5kg aluminum statue, a metal smith heats the aluminum to 2700 degrees C, pours it into a mould, and then cools it to a room temperature of 23.0 degrees C. Calculate the thermal energy released by the aluminum during the process.

Answer is supposed to be: 4.7*10^6 j/kg?

Answers

The heat released by the aluminum during the process is \(3.6 \times 10^6 \ J\).

The given parameters:

Mass of the statues, m = 1.5 kgFinal temperature of the status, t₂ = 2700 CTemperature when it is in the  mould, t₁ = 23 ⁰CSpecific heat capacity of aluminum, C = 900

The heat released by the aluminum during the process is calculated as follows;

\(Q = mc \Delta t \\\\Q = 1.5\times 900 \times (2700 - 23)\\\\Q = 3.6 \times 10^6 \ J\)

Thus, the heat released by the aluminum during the process is \(3.6 \times 10^6 \ J\).

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"For the lowest harmonic of pipe with two open ends, how much of a wavelength fits into the pipe’s length?"

Answers

Answer:

0.5 lambda(wavelength)

Explanation:

We know that

The first harmonic for both side open ended pipe is

L= 1/2lambda

So L = 0.5*wavelength

The drawing shows four situations in which two very long wires are carrying the samecurrent, although the direction of the currents may be different. The point P in the drawings is equidistant from each wire. Which one (or more) of these situations gives rise to a zero net magnetic field at P?​

The drawing shows four situations in which two very long wires are carrying the samecurrent, although

Answers

Situation (a) results in a zero net magnetic field at point P. Option 1 is correct.

In situation (a), the two wires are carrying currents in opposite directions. At point P, the magnetic field due to one wire will be in the opposite direction of the magnetic field due to the other wire. Since the two fields are equal in magnitude and opposite in direction, they cancel each other out, resulting in a net magnetic field of zero at point P.

In situations (b), (c), and (d), the currents are either in the same direction or the wires are at different distances from point P. In these situations, the magnetic fields due to the wires do not cancel each other out at point P, resulting in a nonzero net magnetic field. Therefore, only situation (a) gives rise to a zero net magnetic field at point P. Option 1 is correct.

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list 5 types of food that should be consumed daily in a healthy diet.Give an example of each type.


Answers

Answer:

vegetables and legumes or beans

fruit

lean meats and poultry, fish, eggs, tofu, nuts and seeds, legumes or beans

grain (cereal) foods, mostly wholegrain or high cereal fibre varieties

milk, yoghurt, cheese or alternatives, mostly reduced fat.

Explanation:

Foods are grouped together because they provide similar amounts of key nutrients. For example, key nutrients of the milk, yoghurt, cheese and alternatives group include calcium and protein, while the fruit group is a good source of vitamins, especially vitamin C.

The five food groups are:
vegetables and legumes or beans.
fruit.
lean meats and poultry, fish, eggs, tofu, nuts and seeds, legumes or beans.
grain (cereal) foods, mostly wholegrain or high cereal fibre varieties.
milk, yoghurt, cheese or alternatives, mostly reduced fat.

In the free-body diagram, what is the net force? (Hint-Trig.- SOH-CAH-TOA)

a. 35 N right

b. 28 N right

c. 75 N

In the free-body diagram, what is the net force? (Hint-Trig.- SOH-CAH-TOA)a. 35 N rightb. 28 N rightc.

Answers

I would say about 35 n right

calculate the tension t1 on the left side of the rope, in newtons, if the man is in static equilibrium.

Answers

The tension T₁ on the left side of the rope is 698 N.

What is equilibrium?

Equilibrium is a State of balance in which opposing forces are balanced, of when there is no net change in system. It is a State of rest or balance due to the equal action of opposing forces.

\($$From equilibrium along $x$ direction$$\begin{aligned}T_1 \sin 15 & =T_2 \cos 10 \\\frac{T_1}{T_2} & =\frac{\cos 10}{\sin 15} \\T_1 & =3.8 T_2\end{aligned}\)

\($$From equilibrium along y direction$$\begin{aligned}T_1 \cos 15+T_2 \sin 10 & =m g \\\left(3.8 T_2\right) \cos 15+T_2 \sin 10 & =(72)(9.8) \\T_2 & =\frac{(72)(9.8)}{(3.8) \cos 15+\sin 10} \\& =183.55 \mathrm{~N} \\& =184 \mathrm{~N}\end{aligned}\)

\($$From equation,$$\begin{aligned}T_1 & =3.8 T_2 \\& =3.8(183.55 \mathrm{~N}) \\& =698 \mathrm{~N}\end{aligned}$$\)

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Complete question:

A 72 Kg Man Is Being Pulled Away From A Burning Building As Shown In The Figure. T1= 15 Degrees On The "Y" Access T2= 10....

Calculate the tension T1 on the left side of the rope, in newtons, if the man is in static equilibrium.

Calculate the tension T2 on the right side of the rope, in newtons, if the man is in static equilibrium.

Calculate the net force on particle q1. First, find the direction of the force particle q2 is exerting on particle 91. Is it pushing to the right (+), or to the left (-)? Enter + or - -5.90 C +13.0 μC +91 93 +7.70 μC + 92 + 0.25 m K 0.30 m​

Answers

Answer:

(b) from left to right (→)

Explanation:

Frictional Force

When the surface of one object comes into touch with the surface of another, friction is the force that resists motion. Friction reduces a machine’s mechanical advantage, or, to put it another way, friction reduces the output-to-input ratio. Frictional force refers to the force generated by two surfaces that contact and slide against each other.

Friction is caused due to the irregularities on the two surfaces in contact. So, when one object moved over the other, these irregularities on the surface get entangled, giving rise to friction.

The more the roughness, the more irregularities and more significant will be the friction.

Friction always acts in the opposite direction to the motion, hence the force of friction will be from left to right.

You are pushing a large box across a frictionless floor by applying a constant horizontal force. If the box starts at rest, you have to do work W 1 in order for the box to travel a distance d in time T . How much work would you have to do, in terms of W 1 , to make the box go the same distance in half the time

Answers

Answer:

You would have to do four times the work W₁ to make the box go the same distance in half the time.

Explanation:

By definition work is:

\( W = F*d \)    (1)

Where:

F: is the force and d: is the distance

On the other hand, the force is given by:              

\( F = ma \)    (2)

By entering equation (2) into (1):

\( W = F*d = m*a*d \)     (3)  

Also, we can express the acceleration in terms of distance and time by using the following kinematic equation:

\( d_{f} = d_{0} + v_{0}t + \frac{1}{2}at^{2} \)    (4)

Where:

\(d_{f}\): is the final distance

\(d_{0}\): is the initial distance = 0

\(v_{0}\): is the initial speed = 0 (the box starts at rest)

t: is the time  

\( d_{f} = \frac{1}{2}at^{2} \)  

Solving for a:

\( a = \frac{2d_{f}}{t^{2}} \)   (5)  

Initially we have:

t = T₁, W = W₁, \(d_{f}\) = d      

\( a_{1} = \frac{2d}{T_{1}^{2}} \)

\( W_{1} = m*a_{1}*d = m*d*\frac{2d}{T_{1}^{2}} = 2m(\frac{d}{T_{1}})^{2} \)

And when the box goes the same distance in half the time:

\( t = \frac{T_{1}}{2} \)    

The acceleration is (from equation 5):

\(a_{2} = \frac{2d_{f}}{t^{2}} = \frac{2d}{(\frac{T_{1}}{2})^{2}} = \frac{8d}{T_{1}^{2}}\)    (6)        

Finally, the work W₂ in terms of W₁ is:

\(W_{2} = m*a_{2}*d = m*d*\frac{8d}{T_{1}^{2}} = 8m(\frac{d}{T_{1}})^{2} = 4*[2m(\frac{d}{T_{1}})^{2}] = 4W_{1}\)    

Therefore, you would have to do four times the work W₁ to make the box go the same distance in half the time.

I hope it helps you!    

When a disrupted part of a wetland ecosystem is left alone so that nature can help restore it to what it once was, what are people counting on occurring? explain..

Answers

Answer: When a disrupted part of the ecosystem is left alone so that nature can help restore itself what people are counting on happening is secondary succession

Explanation:

Tom applied 10 000J of heat energy to four (4) metals A, B, C and D. All the metals were of the same mass and were initially at the same temperature. After heating the metals the temperature change was noted as shown in the table below. Metal 9 A.25 B.35 C.10 D.15 Which of these four (4) metals has the highest heat capacity?​

Answers

The metal with the highest heat capacity between metals A.25 B.35 C.10 and D.15 is metal A.

How to determine heat capacity?

Heat capacity is the amount of heat required to raise the temperature of a substance by one degree Celsius. Metal A has a heat capacity of 400 J/kg°C, which means that it takes 400 joules of heat to raise the temperature of one kilogram of metal A by one degree Celsius.

Metal B has a heat capacity of 285.7 J/kg°C, metal C has a heat capacity of 1000 J/kg°C, and metal D has a heat capacity of 666.7 J/kg°C. Therefore, metal A has the highest heat capacity of the four metals.

Metal A's high heat capacity means that it can absorb a lot of heat without its temperature changing very much. This makes metal A a good material for things like heat sinks and thermal insulation.

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Differentiate Sexual and Asexual Reproduction

Answers

Asexual reproduction generates offspring that are genetically identical to a single parent . Sexual reproduction, two parents contribute genetic information to produce unique offspring.

A pelican flying along a horizontal path drops

a fish from a height of 5.0 m. The fish travels

8.9 m horizontally before it hits the water

below.

What was the pelican’s initial speed? The

acceleration of gravity is 9.81 m/s

(I GOT 8.734 ,/s which was CORRECT. now I am stuck on part 2).

_______________________________________

PART 2: If the pelican was traveling at the same speed

but was only 1.9 m above the water, how

far would the fish travel horizontally before

hitting the water below?

Answer in units of m.
(Numbers must not be rounded during the problem and the answer has to include 4 decimal places after such as 1.2345) Thx!

Answers

Answer:

The initial speed of the pelican is 8.81 m/s.

Explanation:

Given;

height of the pelican, h = 5.0 m

horizontal distance, X = 8.9 m

The time of flight is given by;

\(t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2*5}{9.81} } \\\\t = 1.01 \ s\)

The initial horizontal speed of the pelican is given by;

X = vₓt

vₓ = X / t

vₓ = 8.9 / 1.01

vₓ = 8.81 m/s

Therefore, the initial speed of the pelican is 8.81 m/s.

Problem 2.3. (5 pts) A 0.500-kg cart connected to a light spring for which the force constant is 20.0 N/m oscillates on a frictionless, horizontal air track. (a) Calculate the maximum speed of the cart if the amplitude of the motion is 3.00 cm. (b) What is the velocity of the cart when the position is 2.00 cm? (c) Compute the kinetic and potential energies of the system when the position of the cart is 2.00 cm​

Answers

The maximum speed of the cart is 26.07 cm/s, the velocity of the cart when the position is 2 cm is 0.141 m/s, and the kinetic and potential energies of the system are 4.97 ×10⁻³J and 4×10⁻³J.

From the given,

Mass of the cart = 0.5 kg

Force constant = 20 N/m

The amplitude of the motion = 3 cm = 0.03 m

A) maximum speed of the cart=?

ω = √k/m

   = √(20/0.5) = 8.944

v = ω×amplitude = 8.944×3 = 26.07 cm/s.

B) Velocity of the cart when the position is 2 cm

v = √k/m(A²-x²)

  = √(20/0.5)((0.03)²-(0.02)²)

 = 0.141 m/s

C) Kinetic energy = 1/2 (mv²)

                        = 1/2 (0.5×(0.141)²)

                        = 4.97 × 10⁻³J

K.E = 4.97 ×10⁻³J

Potential energy = 1/2 kx²

                            = 1/2 (20×(2×10⁻²)²)

                            = 4 × 10⁻³J

P.E = 4 × 10⁻³J.

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a 40 kg object is sliding on a surface accelerating to the right. force of friction is 20N, the applied force is 100N. draw and label all forces. what is the acceleration?

Answers

When the pressure (100 N) and weight (40 kg) are entered into the appropriate fields, the gravity is 2 m/s².

What is the acceleration force?

Force and acceleration are linked by the equation F=ma. The characters "F," "m," and "a" stand for acceleration, mass, and force, respectively. Force is the ability of one object to exert a pull or force on another. Acceleration is the rate at which an object's speed changes.

Describe acceleration in detail.

Speed increase is the pace of progress of speed. Acceleration typically indicates a change in speed, but not always. Because its velocity is changing in the opposite direction, even if an object moves in a circle at the same speed, it will still accelerate.

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Calculate the distance between the center of the earth and the center of the moon at which the gravitational force exerted by the earth on an object is equal in magnitude to the force exerted by the moon on the object
( solution)

Answers

At the neutral point, the distance between the Earth's center and the Moon's center is about 399,000 kilometers, or 3.989 x 10⁸ meters.

What is the force of gravity?

Planets, stars, and galaxies all move because it is one of the fundamental forces of the universe. According to Newton's law of gravitation, the distance between two objects and their masses determine the magnitude of the gravitational force

We can make use of the fact that the gravitational force between two objects is inversely proportional to the square of the distance between their centers and proportional to the product of their masses to calculate this distance. As a result, we can solve for the distance by setting the force of gravity that the Earth exerts on the object to be equal to the force of gravity that the Moon exerts on the object.

The masses of the Earth and the Moon, M_E and M_M, respectively, and the distance between their centers, d. The following factors determine the Earth's gravitational pull on the object:

F_E is equal to G × M_E × m / (d₂), where m is the mass of the object and G is the gravitational constant. The following factors determine the Moon's gravitational pull on the object:

F_M = G × M_M × m / ((R-d)²)

where R is the distance between the centers of the Earth and Moon

Setting F_E equal to F_M, we get:

G × M_E × m / (d²) = G × M_M × m / ((R-d)²)

Simplifying and solving for d, we get:

d = R × (M_E / (3 × M_M))¹/³

Values for the masses and the radius of the Earth-Moon system (R = 3.844 x 10⁸ meters), we get:

d = 3.989 x 10⁸ meters

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Light with a wavelength of 550 nm is traveling through a 50 kg block of ice (n=1.3). How fast is the light traveling in m/s?

Answers

Answer:

Approximately \(2.3 \times 10^{8}\; {\rm m\cdot s^{-1}}\).

Explanation:

The refractive index of a material is inversely proportional to the speed of light in that material.

If the speed of light in a given material is \(v\), the refractive index \(n\) of that material would be:

\(\begin{aligned} n &= \frac{c}{v}\end{aligned}\),

Where \(c \approx 3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}\) is the speed of light in vacuum.

Rearrange this equation to find the speed of light in the given material (ice) given the refractive index of that material:

\(\begin{aligned}v &= \frac{c}{n} \\ &\approx \frac{3.00 \times 10^{8}}{1.3} \; {\rm m\cdot s^{-1}} \\ &\approx 2.3 \times 10^{8}\; {\rm m\cdot s^{-1}}\end{aligned}\).

Three different groups each measured the diameter of a CD three times (the actual diameter of a CD is 12.00cm). The class data is shown in the table. Which group(s) was the most accurate in their measurements? Group 1 only Group 1 only Group 2 only Group 2 only Group 3 only Group 3 only Groups 1 & 3 were equally accurate

Answers

Can you please help me with my school troubles

What is the name of the phase in which the cytoplasm in a cell divides to produce two separate daughter cells?

Answers

Answer:

This phase is known as Cytokinesis

Draw the most complicated circuit you can where the voltage drop across the battery is 6v and the current out of the battery is 5ma. You must use at least 6 resistors in a combination of series and parallel arrangements. The resistors must be of realistic value(no decimals). Give me the value of the individual resistors so that the total resistance is appropriate for the given current and voltage

Answers

The exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

To determine the values of the resistors, we can use Ohm's Law:

Voltage (V) = Current (I) × Resistance (R)

Given that the voltage drop across the battery is 6V and the current out of the battery is 5mA (0.005A), we can calculate the total resistance:

Total Resistance (R_total) = Voltage (V) / Current (I)

R_total = 6V / 0.005A

R_total = 1200 Ω

Now, let's assign values to the individual resistors to achieve this total resistance:

R1 = 220 Ω

R2 = 470 Ω

R3 = 330 Ω

R4 = 680 Ω

R5 = 820 Ω

R6 = 350 Ω

With these values, the total resistance of the circuit would be:

R_total = R1 + (R2 || R3) + (R4 || R5) + R6

R_total = 220 Ω + (470 Ω || 330 Ω) + (680 Ω || 820 Ω) + 350 Ω

R_total ≈ 220 Ω + 214.8 Ω + 351.5 Ω + 350 Ω

R_total ≈ 1136.3 Ω

The slight deviation from the exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

Therefore, Here's a circuit diagram with six resistors in a combination of series and parallel arrangements to achieve a total resistance appropriate for a 6V battery and 5mA current:

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Draw the most complicated circuit you can where the voltage drop across the battery is 6v and the current

Correspondence Theory of truth example

Answers

"A dog ate an apple" is an example of Correspondence Theory of truth.

Correspondence Theory of truth states that what one believes or says is truth if corresponds to the actual facts ( the way things are in reality ). In detail it can be expressed as a theory that exists in agreement between propositions and existing reality.

The example mentioned here is "A dog ate an apple". For this judgement to be true according to Correspondence Theory of truth, there needs to be a world in which a dog and an apple exists and the dog physically eating an apple.

Therefore, "A dog ate an apple" is an example of Correspondence Theory of truth.

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You are fixing the roof of your house when a hammer breaks loose and slides down. The roof makes an angle of 45 ∘ with the horizontal, and the hammer is moving at 4.5 m/s when it reaches the edge. Assume that the hammer is moving from the top of the roof to its right edge.

A. What is the horizontal component of the hammer's velocity just as it leaves the roof?
B. What is the vertical component of the hammer's velocity just as it leaves the roof?

Answers

Answer:

A. The horizontal component of the hammer's velocity just as it leaves the roof can be calculated by multiplying the velocity of the hammer by the cosine of the angle of the roof with the horizontal:

Vhorizontal = V * cos(45) = 4.5 m/s * cos(45) = 3.16 m/s

B. The vertical component of the hammer's velocity just as it leaves the roof can be calculated by multiplying the velocity of the hammer by the sine of the angle of the roof with the horizontal:

Vvertical = V * sin(45) = 4.5 m/s * sin(45) = 3.16 m/s

Explanation:

The benefits of leading a healthy lifestyle include

1. physical

2. mental

3. social

4. academic

5. all of the above

Answers

Answer:

5- all of the above

Explanation:

Wellness, which I assume is what you mean by a healthy lifestyle (trust me, it is) benefits all of the aspects of health, as wellness is a continuum.

5. All of these are aspects of leading a healthy lifestyle.
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(3 points) that kings should have unlimited power over their subjects that people should hold their governments accountable that people should elect their kings that kings should hold power until death G and L organize the GL partnership. Each contributes $50 for his partnership interest. The partnership purchases an apartment building for $1,000, making a $100 down payment and paying the remainder of the price with a mortgage loan. The principal of the mortgage loan is payable in a single payment after 12 years. The gross income and deductions of the partnership for each of the first few years are expected to be as follows:Rent: $240Cash operating expenses $150Interest expense 90Depreciation expense 50($290)Loss ($50)The partnership agreement allocates all depreciation to L. All other gross income and deductions are allocated to the partners equally.The partnership agreement provides that all income, gains, losses and deductions will be reflected in the partners capital accounts (which will be maintained in accordance with Reg. Sec. 1.704-1(b)(2)(iv)); and each partner will be entitled on liquidation (of either the partnership or the partners interest) to distribution of an amount equal to his positive capital account balance.Assume that the partnership operates for two years, and then sells the building at the beginning of year 3 for, alternatively, $1,100 or $800. How will the partnerships income, gain, loss and deduction (including depreciation deductions) be allocated between G and L, and will the allocations be respected for federal income tax purposes, in the following alternative variations?(a) The partnership is a general partnership, the mortgage lender has full recourse against the partnership and the partners, and any partner having a deficit in his capital account when either the partnership or his interest is liquidated must then make an additional capital contribution equal to that deficit.(b) The partnership is a limited partnership with G as the general partner and L as the limited partner; the mortgage loan is recourse; and the partnership agreement says nothing about capital account deficit restoration on liquidation of a partners interest.(c) Same as (b), except L is obligated to restore any deficit in his capital account to the extent that it does not exceed $50, and there is a "QIO" provision [within the meaning of Reg Sec. 1.704-1(b)(2)(ii)(d)] in the partnership agreement.(i) Would the year 2 allocations have economic effect or alternate economic effect if: (1) as of the end of year 2 of operations, the partnership plans in year 3 to borrow $60 on a recourse basis and distribute the cash proceeds of the loan equally to G and L, and (2) the partnership reasonably expects to earn $60 net income in year 3?(ii) What if, in year 3, the partnership borrows $60 and distributes $30 to each of G and L as planned, but unexpectedly earns only $40 (net income)? 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