Answers
Answer:
1.9×10⁻⁵ °C⁻¹
Explanation:
Coefficient of linear expansion: This can be defined as as increase in length of a material, per unit length per degree rise in temperature, The S.I unit is (K⁻¹).
From the question above,
α = ΔL/L(T₂-T₁)................... Equation 1
Where α = coefficient of linear expansion, ΔL = Change in length, L = original length, T₁ = Initial Temperature, T₂ = Final temperature.
Given: ΔL = 1.4 cm = 0.014 m, L = 24.5 m, T₁ = 4.00°C, T₂ = 34°C
Substitute these values into equation 1
α = 0.014/[24.5(34-4)]
α = 0.014/735
α = 1.9×10⁻⁵ °C⁻¹
Related Questions
what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees
Answers
Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:
You have the initial velocity (v): 35 m/s
You have the launch angle (θ): 45 degrees
We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.
To calculate vx (horizontal component):
vx = v * cosθ
vx = 35 * cos(45) = 24.7 m/s
To calculate vy (vertical component):
vy = v * sinθ
vy = 35 * sin(45) = 24.7 m/s
We can calculate the horizontal distance (d) traveled using:
d = vx * t (where t is time)
Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:
t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)
t = 24.7 / 9.8 = 2.52 seconds
Now we can calculate the full horizontal distance traveled:
d = vx * t
d = 24.7 * 2.52
= 62.3 meters
So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.
Let me know if you have any other questions!
Answer:
To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.
The horizontal component of the motion remains constant throughout the trajectory and is given by:
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.
The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:
Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)
Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.
The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.
Using these calculations, we can find the horizontal distance traveled by the object.
Let's calculate step by step:
Step 1: Calculate the time of flight
Vertical displacement = 0 (at the highest point)
0 = (35 * sin(45))^2 / (2 * 9.8)
0 = (24.75^2) / 19.6
0 = 616.0125 / 19.6
0 = 31.43
Step 2: Calculate the time of flight
Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2
0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2
0 = 24.75 * time - 4.9 * time^2
4.9 * time^2 - 24.75 * time = 0
time * (4.9 * time - 24.75) = 0
time = 0 (initial point) or 24.75 / 4.9
time = 5.05 seconds
Step 3: Calculate the horizontal distance
Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)
Horizontal distance = 35 * 5.05 * cos(45)
Horizontal distance = 35 * 5.05 * (sqrt(2)/2)
Horizontal distance = 88.96 meters
Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.A force F is exerted at a distance D from the axis of rotation of a wrench and is exerted at an angle θ to the wrench (θ is the angle between the direction of the force and the wrench). What force f could be exerted on the wrench at a distance 2D and perpendicular to the wrench so that the torques created by the two forces are EQUAL. Give your answer in terms of F and θ.
Answers
Answer:
Torque = R X F = R * F sin theta
-f * 2R will exert an equal opposite torque
-f * 2 = F sin theta
f = -F sin theta / 2
A falling 0.60 kg object experiences a frictional force due to air resistance of 1.5 N. What is the object's acceleration?
Answers
Answer:
7.5 m/s².
Explanation:
From the question given above, the following data were:
Mass (m) of object = 0.6 Kg
Force of friction (Fբ) = 1.5 N
Acceleration (a) =?
Next, we shall determine the force of gravity on the object. This can be obtained as follow:
Mass (m) of object = 0.6 Kg
Acceleration due to gravity (g) = 10 m/s²
Force of gravity (F₉) =?
F₉ = mg
F₉ = 0.6 × 10
F₉ = 6 N
Next, we shall determine the net force acting on the object. This can be obtained as follow:
Force of friction (Fբ) = 1.5 N
Force of gravity (F₉) = 6 N
Net force (Fₙ) =?
Fₙ = F₉ – Fբ
Fₙ = 6 – 1.5
Fₙ = 4.5 N
Finally, we shall determine the acceleration of the object. This can be obtained as follow:
Mass (m) of object = 0.6 Kg
Net force (Fₙ) = 4.5 N
Acceleration (a) of object =?
Fₙ = ma
4.5 = 0.6 × a
Divide both side by 0.6
a = 4.5 / 0.6
a = 7.5 m/s²
Therefore, the acceleration of the object is 7.5 m/s²
If you are told an image has been made by a single optic that has a positive focal length, which is true?
Answers
If you are told an image has been made by a single optic that has a positive focal length, The options that are true are:
The image is real. (Option A)
The image is virtual. (Option B)
The image has a positive image distance. (Option C)
The image has a negative image distance. (Option D)
The image is inverted. (Option E)
The image is upright.(Option F)
The image was made with a converging optic. (Option G)
The image was made with a diverging optic. (Option H)
If the optic is a lens, it is convex. (Option I)
If the optic is a mirror, it is convex. (Option K)
What is Focal Lenght?The focal length of an optical system is the inverse of the system's optical power; it measures how strongly the system converges or diverges light.
A system with a positive focus length converges light, whereas a system with a negative focal length diverges light.
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Full Question:
If you are told an image has been made by a single optic that has a positive focal length, which is true?
a. The image is real.
b. The image is virtual.
c. The image has a positive image distance.
d. The image has a negative image distance.
e. The image is inverted.
f. The image is upright.
g. The image was made with a converging optic.
h. The image was made with a diverging optic.
i. If the optic is a lens, it is convex.
j. If the optic is a lens, it is concave.
k. If the optic is a mirror, it is convex.
l. If the optic is a mirror, it is concave.
A surveyor measures the distance across a straight river by the following method: Starting directly across from a tree on the opposite bank, he walks x = 118 m along the riverbank to establish a baseline. Then he sights across to the tree. The angle from his baseline to the tree is = 33.4°. How wide is the river?
Answers
Answer:
68.5 meters
Explanation:
To solve this problem, we can use trigonometry and create a right triangle with the river as the hypotenuse.
Let's call the width of the river "w". We can use the sine function to find the length of the opposite side of the triangle (the distance from the surveyor to the tree).
sin(33.4°) = opposite/hypotenuse
sin(33.4°) = w/x
w = x * sin(33.4°)
w = 118 m * sin(33.4°)
w = 68.5 m
Therefore, the width of the river is approximately 68.5 meters.
An architect has designed two tunnels. Tunnel A is modeled by x2 + y2 + 28x + 52 = 0, and tunnel B is modeled by x2 – 36x + 16y + 68 = 0, where all measurements are in feet. The architect wants to verify whether a truck that is 8 feet wide and 13.5 feet high can pass through the tunnels.Part B: Write the equation for Tunnel B in standard form and determine the conic section. Show your work. (4 points)I only need help with Part B
Answers
Answer:
Tunnel A: Circle
Tunnel B: Parabola
Max height of A: 12 ft
Max height of B: 16 ft
The truck can only pass through tunnel B.
Explanation:
Since we do not know what x and y represent, we assume that is the height of the tunnel and x is the width.
Part A:
Let us convert our equation into the standard form.
The equation for tunnel A is
\(x^2+y^2+28x+52=0\)which we rewrite as
\((x^2+28x+\cdots)+y^2=-52\)Now we complete the square for variable x. What should we add to x^2 + 28x to make it a complete square?
After some thinking, we realise that we do x^2 + 28x + 14^2 then we have (x + 14)^2 .
Therefore, we add 14^2 to both sides of our equation to get:
\((x^2+28x+14^2)+y^2=-52+14^2\)\((x+14)^2+y^2=-52+14^2\)\((x+14)^2+y^2=144\)this equation we recognise as that of a circle! Therefore, the conic section for tunnel A is a circle.
Part B:
Let us now turn to tunnel B and write its equation:
\(x^2-36x+16y+68=0\)The first thing to note is that the above equation is linear in y; therefore, we can rearrange the equation to write it as
\(16y=-(x^2-36x+68)\)Now we have to complete the square on the right-hand side.
subtracting 256 from both sides gives
\(16y-256=-(x^2-36x+68)-256\)\(16y-256=-x^2+36x-324\)\(16y-256=-(x^2-36x+324)\)\(16y-256=-(x-18)^2\)\(\Rightarrow y=-\frac{1}{16}(x-18)^2+\frac{256}{16}\)which is the standard equation for a parabola!
Hence, the conic section for tunnel B is that of a parabola.
(round to 3 significant figures pls) A block of iron at 415 degrees C is put into a 0.625 kg tub of water at 15.0 degrees C. They come to equilibrium at 100 degrees C, and 0.144 kg of the water boils off to steam. What was the mass of the iron block?
Answers
Temperature of iron (Ti) = 415 °C Temperature of water (Tw) = 15.0 °CTemperature at equilibrium (Te) = 100 °CMass of water (m) = 0.625 kgMass of steam evaporated (ms) = 0.144 kgHeat lost by iron (Q1) = Heat gained by water (Q2) + Heat required to evaporate steam .
Heat lost by iron = (mass of iron (m) x specific heat capacity of iron (c) x change in temperature of iron (ΔT1))Heat gained by water = (mass of water (m) x specific heat capacity of water (c) x change in temperature of water (ΔT2))Heat required to evaporate steam = (mass of steam (ms) x specific latent heat of vaporization of water (L))Now, using the above formula we can calculate the mass of the iron block as:
Q3m x c x ΔT1 = m x c x ΔT2 + ms x L
Let's calculate the value of Q1 first.
Q1 = m x c x ΔT1m = Q1 / (c x ΔT1)
We know that
c = 450 J/kg °C and ΔT1 = Ti - Te = 415 - 100 = 315°CQ1 = m x c x ΔT1= m x 450 J/kg
°C x 315°C= 141750 m Jm = Q1 / (c x ΔT1)= 141750 / (450 x 315)= 1.002 kg
Now, let's calculate the value of Q3.Q3 = ms x L= 0.144 kg x 2.26 x 10^6 J/kg= 325440 J
Now, let's calculate the value of Q2
.Q2 = m x c x ΔT2m = (Q2 + Q3) / (c x ΔT2)
We know that ΔT2 = Te - Tw = 100 - 15 = 85°CQ2 = m x c x ΔT2= 0.625 kg x 4186 J/kg °C x 85°C= 276981.25 JNow, let's calculate the mass of the iron block.m =
(Q2 + Q3) / (c x ΔT2)= (276981.25 + 325440) / (450 x 85)= 1.003 kg
Hence, the mass of the iron block is 1.003 kg rounded off to 3 significant figures.
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A uniform disk with a mass of 190 kg and a radius of 1.1 m rotates initially with an angular speed of 950 rev/min. A constant tangential force is applied at a radial distance of 0.5 m. How much work must this force do to stop the wheel? Answer in units of kJ.
Answers
Answer:
Explanation:
We can use the work-energy principle to find the work done by the applied force to stop the disk. The work-energy principle states that the work done by all forces acting on an object is equal to the change in its kinetic energy:
W = ΔK
where W is the work done, and ΔK is the change in kinetic energy.
Initially, the disk is rotating with an angular velocity of 950 rev/min. We need to convert this to radians per second, which gives:
ω_initial = (950 rev/min) × (2π rad/rev) × (1 min/60 s) = 99.23 rad/s
The initial kinetic energy of the disk is:
K_initial = (1/2) I ω_initial^2
where I is the moment of inertia of the disk about its axis of rotation. For a uniform disk, the moment of inertia is:
I = (1/2) m R^2
where m is the mass of the disk, and R is the radius. Substituting the given values, we get:
I = (1/2) (190 kg) (1.1 m)^2 = 115.5 kg m^2
Therefore, the initial kinetic energy of the disk is:
K_initial = (1/2) (115.5 kg m^2) (99.23 rad/s)^2 = 565201 J
To stop the disk, the applied force must act opposite to the direction of motion of the disk, and must cause a negative change in the kinetic energy of the disk. The force is applied at a radial distance of 0.5 m, which gives a torque of:
τ = F r
where F is the magnitude of the force. The torque causes a negative change in the angular velocity of the disk, given by:
Δω = τ / I
The work done by the applied force is:
W = ΔK = - (1/2) I Δω^2
Substituting the given values, we get:
W = - (1/2) (115.5 kg m^2) [(F r) / I]^2
The force F can be eliminated using the equation for torque:
F = τ / r = (Δω) I / r
Substituting this into the equation for work, we get:
W = - (1/2) (115.5 kg m^2) [(Δω) I / r I]^2
= - (1/2) (115.5 kg m^2) (Δω / r)^2
Substituting the values for Δω and r, we get:
W = - (1/2) (115.5 kg m^2) [(F r / I) / r]^2
= - (1/2) (115.5 kg m^2) [(2 Δω / R) / (2/5 m R^2)]^2
= - (1/2) (115.5 kg m^2) (25/4) (2 Δω / R)^2
= - 90609 J
where we have used the expression for the moment of inertia of a uniform disk and the given values for the mass and radius. The negative sign indicates that the work done by the applied force is negative, which means that the force does negative work (i.e., it takes energy away from the system). The work done by the force to stop the disk is therefore 90609 J, which is -90.6 kJ (to two decimal places).
A piece of lead of mass 500 g and at air temperature falls from a height of 25 m. (a) What is its initial gravitational potential energy? (b) What is its kinetic energy on reaching the ground (assume g=10 ms-2)? (c) Assuming that all of the energy becomes transferred to internal energy in the lead when it hits the ground, calculate the rise in temperature of the lead. (d) State the energy transfers that have occurred from the moment the lead strikes the ground until it has cooled to air temperature again
Answers
Answer:
(a) The initial gravitational potential energy of the lead can be calculated using the formula:
E = mgh
where E is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height. Substituting the given values, we get:
E = (0.5 kg) × 10 m/s² × 25 m = 125 J
Therefore, the initial gravitational potential energy of the lead is 125 J.
(b) When the lead reaches the ground, all of its potential energy is converted into kinetic energy. The kinetic energy can be calculated using the formula:
E = (1/2)mv²
where E is the kinetic energy, m is the mass, and v is the velocity. At the moment of impact, the lead has a velocity of:
v = √(2gh) = √(2 × 10 m/s² × 25 m) = 10 m/s
Substituting the given values, we get:
E = (1/2) × 0.5 kg × (10 m/s)² = 25 J
Therefore, the kinetic energy of the lead on reaching the ground is 25 J.
(c) The energy gained by the lead due to the impact is converted into internal energy, which raises the temperature of the lead. The amount of energy required to raise the temperature of the lead can be calculated using the specific heat capacity formula:
Q = mcΔT
where Q is the energy gained, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. The specific heat capacity of lead is 128 J/kg°C. Substituting the given values, we get:
125 J - 25 J = (0.5 kg) × 128 J/kg°C × ΔT
ΔT = (100 J) / (64 J/kg°C) = 1.56°C
Therefore, the rise in temperature of the lead is 1.56°C.
(d) The energy transfers that have occurred from the moment the lead strikes the ground until it has cooled to air temperature again are:
Conversion of potential energy to kinetic energy upon impact
Conversion of kinetic energy to internal energy upon impact, raising the temperature of the lead
Transfer of heat energy from the lead to the surrounding air, as the lead cools down to air temperature
water fall,agile,hybrid models
Answers
Agile-Waterfall hybrid method
As defined by Erick Bergmann and Andy Hamilton, the Agile-Waterfall hybrid typically allows teams developing software to work within the Agile methodology, while hardware development teams and product managers stick to the Waterfall approach.
a very long solenoid is constructed as a coil of wire. Current is allowed the flow through the solenoid which creates a magnetic field. How the does the magnetic field change if the radius of the solenoid is doubled but everything else doesnt change
Answers
Answer:
the magnetic field of the solenoid will remain same.
Explanation:
The magnetic field of a solenoid is given by the following formula:
\(B = \frac{\mu_o NI}{l}\)
where,
B = magnetic field
μ₀ = permeability of free space
N = total number of coils
I = current passing through the solenoid
L = length of the solenoid
The formula clearly shows that the radius of the solenoid has no effect on the magnetic field produced by it.
Therefore, the magnetic field of the solenoid will remain same.
A soccer player with a mass of 80.0 kg kicks a ball by applying a 20.0 N force. What force does the ball exert on the player?
A. 160. N
C. 2.50 N
B. 0.400 N
D. 20.0N
Answers
Answer:
F = 160.0 N
Explanation:
Given: Soccer payer with a mass = 80 kg, force = 20 N
To find: force
Formula: \(F=ma\)
Solution: It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.
F = m × a
F = 20 kg - 10 = 2
F = 80 × 2 = 160
F = 160.0 N
Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.
An average person is 175 cm tall. How
many people could you stack one on top of
another to reach the top of the CN Tower
(553 m)?
Answers
The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people
Hor to convert 175 centimeters to metersWe'll begin by converting 175 cm to m. This can be obtained as illustrated below:
100 cm = 1 m
Therefore,
175 cm = (175 cm × 1 m) / 100 cm
175 cm = 1.75 m
Thus, 175 cm is equivalent to 1.75 m
How to determine the number of people neededThe number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:
Height of tower = 553 mHeight of a person = 1.75 mNumber of people needed =?Number of people needed = Height of tower / height of a person
Number of people needed = 553 / 1.75
Number of people needed = 316 people
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You're out for run. Your initial velocity is 1.5 m/s. Suddenly a crazy dog starts chasing you and you accelerate to a velocity of 3 m/s. It takes you 10 seconds to find a safe place to hide from the Chihuahua. What was your displacement?
Show your work for displacement.
Include units.
Answers
The displacement of your motion during the entire motion is 22.5 m
The given parameters;
your initial velocity, u = 1.5 m/syour final velocity , v = 3 m/stime of motion, t = 10 sThe displacement of your motion during the entire motion is calculated from your average velocity and time of motion.
This magnitude of this displacement is calculated as follows;
\(s = (\frac{u+ v}{2} )t\\\\s = (\frac{1.5 + 3}{2} ) \times 10\\\\s = 22.5 \ m\)
Thus, the displacement of your motion during the entire motion is 22.5 m.
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What is the magnitude of the electric force on charge A
in (Figure 1)?
Answers
According to the question by Coulomb's Law the final value of the equation is 0.00 N .
What is Coulomb's Law?Coulomb's Law is a fundamental law of physics that states the magnitude of the electrostatic force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. In equation form, the law states F = k * (q1 * q2)/r², where F is the magnitude of the force, k is a constant, q1 and q2 are the magnitudes of the two charges, and r is the distance between the two charges.
Note that by Coulomb's Law,
F = kq1q2/r²
where
k = 8.99E9 Nm²/kg²
q1, q2 = the two interacting charges
r = the distance of separation of the two charges
Thus, for force of B on A points to the right, as opposite charges attract.
qA = 1.0E-9 C
qB = -1.0E-9 C
r = 0.01 m
Thus,
F(B on A) = 8.99E-5 N
Now, for force of C on A points to the left, as like charges repel.
Thus, as
qA = 1.0E-9 C
qC = 4.0E-9 C
r = 0.02 m
F(C on A) = -8.99E-5 N [the negative sign because it is to the left]
Thus,
Fnet (A) = F(B on A) + F(C on A)
Fnet (A) = 0.00 N
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You want to use a metal bar as a resistor. Its dimensions are 1 by 3 by 13 units. To get the largest resistance from the bar, you should attach leads to the two opposite sides that have dimensions of 1 by 3 units. All configurations give the same resistance. 3 by 13 units. 1 by 13 units. None of the above.
Answers
Answer:
1 by 3 units
Explanation:
The resistance (R) of a conductor is given by the formula:
R = ρL / A
where L is the length of the conductor, ρ is resistivity and A is the cross sectional area.
Let us assume that the metal bar has a resistivity of ρ.
a) If the leads is attached to the two opposite sides that have dimensions of 1 by 3 units.
The length of the bar would be 13 units and the cross sectional area (A) would be = 1 * 3 = 3 units²
R₁ = ρL / A = ρ(13) / 3 = 13ρ / 3
b) If the leads is attached to the two opposite sides that have dimensions of 3 by 13 units.
The length of the bar would be 1 units and the cross sectional area (A) would be = 3 * 13 = 39 units²
R₂ = ρL / A = ρ(1) / 39 = ρ / 39
c) If the leads is attached to the two opposite sides that have dimensions of 1 by 13 units.
The length of the bar would be 3 units and the cross sectional area (A) would be = 1 * 13 = 13 units²
R₃ = ρL / A = ρ(3) / 13 = 3ρ / 13
Therefore we can see that the largest resistance is gotten If the leads is attached to the two opposite sides that have dimensions of 1 by 3 units
Answer the following Critical Thinking Questions. Each answer is worth 5 points, for a total of 25 points.
A particular star is 20 pc away from the Earth, and its luminosity is 160 times the luminosity of the Sun and has a surface temperature of 4000 K. Its absolute magnitude is -0.66. The temperature of the Sun is 5800 K. Explain/show your work.
What is this star's parallax?
What is this star's spectral class?
What is the wavelength at which this star radiates the most energy?
What is this star's apparent magnitude?
What is this star's radius, in solar radii?
Answers
Using the absolute magnitude (M) and apparent magnitude (m) relation, we can find the star's apparent magnitude:
m - M = -5 + 5 log(d)
where d is the distance to the star in parsecs.
Plugging in the values we have, we get:
m - (-0.66) = -5 + 5 log(20)
m = 3.34
Therefore, this star's apparent magnitude is 3.34.
The star's luminosity is 160 times that of the Sun.
Using the Stefan-Boltzmann law, we can find the star's radius:
L = 4πR²σT⁴
where L is the luminosity, R is the radius, σ is the Stefan-Boltzmann constant, and T is the surface temperature.
We can write the ratio of the star's luminosity to that of the Sun as:
L/Lsun = (R/Rsun)²(T/Tsun)⁴
Plugging in the values we have, we get:
160 = (R/Rsun)²(4000/5800)⁴
Solving for R, we get:
R = 10.7 R⊙
Therefore, this star's radius is 10.7 times that of the Sun.
Using Wien's law, we can find the wavelength at which the star radiates the most energy:
λmax = 2.898 × 10⁶ / T
Plugging in the values we have, we get:
λmax = 724.5 nm
Therefore, this star radiates most of its energy at a wavelength of 724.5 nm.
The star's surface temperature is 4000 K.
Using the Harvard spectral classification system, we can find the star's spectral class based on its surface temperature:
O B A F G K M
50,000 10,000 7500 6000 5200 3700 2400
The star's surface temperature falls in the range of a K-type star.
Therefore, this star's spectral class is K.
Finally, we can use the definition of parallax to find the star's parallax:
p = 1/d
where p is the parallax in arcseconds and d is the distance to the star in parsecs
How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food
A. The amount of oxygen in the atmosphere increased
B. Mass extinctions occurred
C. The oceans became larger
D. Rainfall increased
Answers
Need help solving this problem
Answers
a) The tension in the rope is 123.9 N.
b) The moment of inertia of the wheel is 0.09 kg m².
c) The angular speed of the wheel 3.50 s after it begins rotating, starting from rest, is 58.5 rad/s.
(a) To determine the tension in the rope, we need to analyze the forces acting on the object. There are two forces: the force of gravity pulling the object down the incline and the tension force pulling the object up the incline.
The force of gravity can be broken down into two components: one parallel to the incline and one perpendicular to the incline.
The parallel component causes the object to accelerate down the incline, while the perpendicular component is balanced by the normal force of the incline.
The tension force is responsible for the object's acceleration down the incline, so we can set up the following equation:
T - mg sin(theta) = ma
where T is the tension force, m is the mass of the object, g is the acceleration due to gravity, theta is the angle of the incline, and a is the acceleration of the object down the incline.
Putting in the given values, we get:
T - (12.5 kg)(9.81 m/s²)(sin(37°)) = (12.5 kg)(2.00 m/s²)
Solving for T, we get:
T = 123.9 N
Therefore, the tension in the rope is 123.9 N.
(b) To determine the moment of inertia of the wheel, we can use the following equation:
I = (1/2)MR²
where I is the moment of inertia, M is the mass of the wheel, and R is the radius of the wheel.
Putting in the given values, we get:
I = (1/2)(12.5 kg)(0.12 m)²
= 0.09 kg m²
Therefore, the moment of inertia of the wheel is 0.09 kg m².
(c) To determine the angular speed of the wheel after 3.50 s, we can use the following equation:
ω = ω₀ + αt
where ω is the final angular speed, ω₀ is the initial angular speed (which is zero in this case), α is the angular acceleration, and t is the time.
We can find the angular acceleration using the following equation:
α = a/R
where a is the acceleration of the object down the incline (which we already know) and R is the radius of the wheel.
Putting in the given values, we get:
α = 2.00 m/s² / 0.12 m
= 16.7 rad/s²
Putting in the values for α and t, we get:
ω = 0 + (16.7 rad/s²)(3.50 s)
= 58.5 rad/s
Therefore, the angular speed of the wheel 3.50 s after it begins rotating, starting from rest, is 58.5 rad/s.
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Forces that cancel each other are called_ forces \
Answers
Answer:
balanced forces
What is the biggest agent of erosion?
a tornadoes
b pollution
c gravity
d water
Answers
Answer:
D - Water
Explanation:
D or A
A cat of mass 5.5 kg was observed going from rest to sprinting at 20 m/s. How much work was required for this acceleration?
Answers
The amount of work required for the cat to accelerate from rest to sprinting at 20 m/s depends on the change in its kinetic energy. The work done is equal to the change in kinetic energy.
The work required for the cat to accelerate is 1100 Joules.
To calculate the work done, we need to determine the change in kinetic energy, which is given by the formula:
Change in Kinetic Energy = 1/2 * mass * (final velocity)^2 - 1/2 * mass * (initial velocity)^2
Given data:
Mass of the cat (m) = 5.5 kg
Initial velocity (u) = 0 m/s (rest)
Final velocity (v) = 20 m/s (sprinting)
Calculate the change in kinetic energy using the formula:
Change in Kinetic Energy = 1/2 * mass * (final velocity)^2 - 1/2 * mass * (initial velocity)^2
Plugging in the values:
Change in Kinetic Energy = 1/2 * 5.5 kg * (20 m/s)^2 - 1/2 * 5.5 kg * (0 m/s)^2
= 1/2 * 5.5 kg * (400 m^2/s^2)
= 1/2 * 5.5 kg * 400 J
= 5.5 kg * 200 J
= 1100 J
The work required for the cat to accelerate is equal to the change in kinetic energy, which is 1100 Joules.
Therefore, the work required for the cat to accelerate from rest to sprinting at 20 m/s is 1100 Joules.
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Two cars, one in front of the other, are traveling down the highway at 53.7 m/s. The car behind sounds its horn, which has a frequency of 536 Hz. What is the frequency heard by the driver of the lead car
Answers
Answer:
Explanation:
The source is approaching the observer which is moving away from the source , so applying Doppler's effect
\(n = n_o\frac{V-V_O}{V-V_S}\)
where n is apparent frequency , n₀ is original frequency , V₀ is velocity of observer , V_S is velocity of source , V is velocity of sound
Putting the given values
= \(n = 536\frac{340-53.7}{340-53.7 }\)
= 536
So apparent frequency will be same as original frequency .
ie 536 .
In central Texas there is a large domed hill of pink granite surronund by low hills of more common bedrock of Texas, limestone. Develop and explain your hypothesis for how this mineral dome was formed.
Answers
Answer:
It was probably formed by when the particles were pressed together.
Explanation:
Answer:
Formed by particles pressed against each other
Explanation:
The figure below shows electrons moving along an electric current towards and away from the light bulb.
Electrons traveling along an electric current. Arrow under electrons points right and left both towards and away from the light bulb.
Does this figure show a direct or alternating current? Explain your response.
Answers
Based on the information provided, it is likely that the figure shows an alternating current (AC). The arrows under the electrons pointing right and left, both towards and away from the light bulb, indicate that the direction of the electron flow is changing periodically. This is a characteristic of alternating current, where the flow of electric charge reverses direction periodically, typically in a sinusoidal manner.
In an AC circuit, the voltage also changes direction periodically, which is consistent with the changing direction of the electron flow shown in the figure.
In an alternating current, the flow of electrons periodically reverses direction, causing the current to switch between positive and negative values. This is different from direct current (DC), where electrons flow in a single, constant direction.
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Which statement is true? speed is a scalar quantity and velocity is a vector quantity, speed and velocity are both scalar quantities,
Answers
speed is a scalar quantity and velocity is a vector quantity
In our solar system, which celestial object is known as the dwarf planet?
Answers
Answer:
unfournatletly
Explanation:
i have no clue sorry to waste ur time ill rather not say a answer that will be incorrect.
Answer:
Pluto
Explanation:
Pluto was part of our solar system till 2006In 2006 international scientific committee removed it from planets listIt's known as dwarf planet nowWhat is the value of acceleration due to gravity, g, on Earth?
Answers
Explanation:
It varies with altitude, but at sea level, it's 9.8 m/s².
A truck driver attempting to deliver some furniture travels 5 km east turns around and travels 3 km west and then travels 17 km east to his destination. What distance has a driver traveled answer in km?
What is magnitude of the drivers total displacement? answer in Im
Answers
Answer:
pp
Explanation:
hahahahhahahhahahahahahaahhahaha.. tbh
If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed? (1 point)
O A series of light and dark bands would appear on the screen.
O Two bright bands would appear on the screen in line with the slits.
O The screen would remain dark because no radiation would reach the screen.
O One bright band would appear in the center of the screen.
Answers
If electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.
Bahavior of particles in double-slit experimentIn a double-slit experiment, single particles, such as photons, pass one at a time through a screen containing two slits.
The photons behave like wave and the constructive interfernce of the waves of these photons will generate a high amplitude wave seen as a bright band in the center of the screen.
Thus, if electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.
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