Agarose gel electrophoresis differs from SDS-PAGE in all of the following ways except:Select one:a. Its loading buffer generally gives the sample a uniform negative charge.b. Visualization is generally accomplished using ethidium bromide or one of the less toxic alternative stains such as GelRed.c. Agarose is extracted from seaweed.d. It is generally run horizontally.e. Its resolution is lower.

The grams of ammonia that will be formed upon the complete reaction of 29.8 grams of ammonium chloride is 9.48 grams.

To find the grams of ammonia that will be formed upon the complete reaction of 29.8 grams of ammonium chloride, we need to use the law of conservation of mass and the mole ratio from the balanced chemical equation. The balanced chemical equation for this reaction is:
NH4Cl (aq) → NH3 (g) + HCl (aq)

From the balanced chemical equation, we can see that the mole ratio of ammonium chloride to ammonia is 1:1. This means that for every 1 mole of ammonium chloride that reacts, 1 mole of ammonia will be produced.

Next, we need to find the number of moles of ammonium chloride that are present in 29.8 grams. We can do this by using the molar mass of ammonium chloride:

1 mole NH4Cl = 53.49 g NH4Cl
29.8 g NH4Cl × (1 mole NH4Cl/53.49 g NH4Cl) = 0.557 moles NH4Cl

Now we can use the mole ratio from the balanced chemical equation to find the number of moles of ammonia that will be produced:

0.557 moles NH4Cl × (1 mole NH3/1 mole NH4Cl) = 0.557 moles NH3

Finally, we can use the molar mass of ammonia to find the grams of ammonia that will be produced:
1 mole NH3 = 17.03 g NH3
0.557 moles NH3 × (17.03 g NH3/1 mole NH3) = 9.48 g NH3

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Answer:

the third one

Explanation:

When you breathe in, you inhale oxygen and exhale carbon dioxide

The volume occupied by 0.897 mol of a gas at 270°C and 1.45 atm is 21.59 L (rounded to two decimal places).

To find the volume occupied by the gas, we will use the Ideal Gas Law formula: PV = nRT.

In this case, P (pressure) = 1.45 atm, n (moles) = 0.897 mol, R (gas constant) = 0.08206 L atm/mol K, and T (temperature) = 270°C.

First, convert the temperature to Kelvin by adding 273.15: 270 + 273.15 = 543.15 K. Now, plug in the values into the Ideal Gas Law formula:

(1.45 atm) * V = (0.897 mol) * (0.08206 L atm/mol K) * (543.15 K)

To solve for the volume (V), divide both sides by the pressure (1.45 atm):

V = (0.897 mol * 0.08206 L atm/mol K * 543.15 K) / 1.45 atm

V = 21.5867 L

After rounding to two decimal places, the volume occupied by the gas is 21.59 L.

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Answer:

1) Carrying capacity is the maximum number of individuals of a species that an environment can support.

2) Population - all the inhabitants of a particular town, area, or country.

3) An increase in population will inevitably create pressures leading to more deforestation, decreased biodiversity, and spikes in pollution and emissions, which will exacerbate climate change.

4) The three leading causes of population growth are births, deaths, and migration. Births and deaths are seen as natural causes of population change.

Answer:

The H+ (aq) concentration of the resulting solution is 4.1 mol/dm³

(Option C)

Explanation:

Given;

concentration of HA, \(C_A\) = 6.0mol/dm³

volume of HA, \(V_A\)  = 25.0cm³, = 0.025dm³

Concentration of HB, \(C_B\) = 3.0mol/dm³

volume of HB, \(V_B\) = 45.0cm³ = 0.045dm³

To determine the H+ (aq) concentration in mol/dm³ in the resulting solution, we apply concentration formula;

\(C_iVi = C_fV_f\)

where;

\(C_i\) is initial concentration

\(V_i\) is initial volume

\(C_f\) is final concentration of the solution

\(V_f\) is final volume of the solution

\(C_iV_i = C_fV_f\\\\Based \ on \ this\ question, we \ can \ apply\ the \ formula\ as;\\\\C_A_iV_A_i + C_B_iV_B_i = C_fV_f\\\\C_A_iV_A_i + C_B_iV_B_i = C_f(V_A_i\ +V_B_i)\\\\6*0.025 \ + 3*0.045 = C_f(0.025 + 0.045)\\\\0.285 = C_f(0.07)\\\\C_f = \frac{0.285}{0.07} = 4.07 = 4.1 \ mol/dm^3\)

Therefore, the H+ (aq) concentration of the resulting solution is 4.1 mol/dm³

Answer:

This atom has 80 protons and 98 neutrons.

Explanation:

All atoms are composed of a central nucleus in which there are positively charged particles, the protons, and neutrally charged particles, the neutrons, around which other negatively charged particles, called electrons, move.

The atomic number, identified with the letter Z, indicates the number of protons that are present in the nucleus of an atom. The atomic number defines the electronic configuration of the atom and allows the ordering of the different chemical elements in the periodic table.

If a substance has an atomic number of 80, this atom has 80 protons.

The mass number indicates the total number of particles in the nucleus, that is, the sum of protons and neutrons.

mass number = number of protons + number of neutrons

In this case you know that the mass number is 178 and number of protons is 80. Then

number of neutrons=mass number - number of protons

number of neutrons= 98

So this atom has 98 neutrons.

The amount of energy used to heat the water from 0°C to 70°C is 8,786.4J.

The amount of energy used in heating a substance can be calculated using the following formula:

Q = mc∆T

Where;

According to this question, a student heated 30 milliliters of water from 0 degrees celsius to 70 degrees celsius.

Since 1mL of pure water equals 1 gram, then 30mL of water will equal 30grams of water.

Q = 30 × 4.184 × (70 - 0)

Q = 8,786.4J

Therefore, 8,786.4J is the energy used to heat the water sample.

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Explanation:

alto cumulus is the pic

Answer

Explanation

Atomic mass =  abundances1 x relative mass 1+ abundances 2 x relative mass 2 ...etc

   =  ( 60.4% x 68.9257 + 39.6% x 70.9249)

    = 0.604 x 68.9257  +  0.396 x 70.9249)

     =  69.72 amu

The element with 2 isotopes, one representing 60.4 % of the atoms (68.9257 amu) and the other representing the rest (70.9249 amu), has an atomic mass of 69.7 amu. The element is Gallium.

An element has 2 isotopes. The sum of their abundances is 100%. If the abundance of isotope 1 is 60.4%, the abundance of isotope 2 is:

\(ab_1 + ab_2 = 100 \% \\ab_2 = 100\% - ab_1 = 100 \% - 60.4 \% = 39.6 \%\)

Isotope 1 has an abundance of 60.4% and a mass of 68.9257 amu, while Isotope 2 has an abundance of 39.6% and a mass of 70.9249 amu. The atomic mass is the weighted average of the mass by the abundance.

\(am = \frac{68.9257 amu \times 60.4 + 70.9249 amu \times 39.6 }{100} = 69.7 amu\)

The element with this atomic mass is Gallium.

The element with 2 isotopes, one representing 60.4 % of the atoms (68.9257 amu) and the other representing the rest (70.9249 amu), has an atomic mass of 69.7 amu. The element is Gallium.

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ANSWER

The initial volume of the acid is 260mL

EXPLANATION

Given that;

The final volume of the ethanoic acid is 4.5L

The final concentration of the ethanoic acid is 1.0 mol/L

The initial concentration of the ethanoic acid is 17.4 mol/L

Follow the steps below to find the volume of the ethanoic acid

Step 1; Apply the dilution formula

Step 2; Substitute the given data into the formula

Therefore, the initial volume of the acid is 260mL

Adding specimen scrapings to 10% KOH to show the presence of sclerotic bodies that resemble copper pennies is useful in the diagnosis of tinea versicolor.

Tinea versicolor is a superficial fungal infection caused by the yeast Malassezia. The characteristic coppery or hypopigmented (lighter) spots seen in tinea versicolor are due to the accumulation of fungal cells on the skin. These cells, known as sclerotic bodies or spaghetti and meatballs, are visualized when the specimen scrapings from the affected area are mixed with 10% KOH. The KOH helps to dissolve the keratin in the skin, making it easier to identify the fungal elements under a microscope.

This diagnostic method is particularly effective for tinea versicolor because the presence of these distinctive sclerotic bodies confirms the diagnosis. Other skin conditions may have different appearances or lack these specific fungal elements when examined using the KOH preparation technique. Therefore, this test can aid in differentiating tinea versicolor from other skin conditions with similar clinical manifestations.

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The calculated maximum wavelength is 495 nm

The energy needed to break a bond and create two atomic or molecular fragments, each containing one of the original shared pair of electrons, is known as the bond dissociation energy. The link between silicon and fluorine, which was previously discussed, is discovered to be the strongest chemical bond. The initial silicon-fluorine bond in a silicon tetrafluoride molecule requires 166 kcal/mol of bond dissociation energy to be broken.

ΔH=+240 kJ/mol

E=242×103/6.022×1023

=4.0186×10−19 J

Now I use the Planck Expression:

E=hf=hc/λ

∴λ=hc

Eλ=6.63×10−34×3×108/4.0186×10-19 m

λ=4.949×10−7 m

λ=495 nm.

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Answer:

63.9 grams. Yes, the Nacl was converted.  Maximum possible ppm is 540ppm.

Explanation:

I this is college level chemistry not regular high school chem.  

Answer:2

Explanation:

it is it do not ask questions

Answer:

Hydrogen: 5

Carbon:3

Nitrogen:3

Oxygen: 9

please give me brainliest

Answer:

C. Theories have been confirmed through tests; hypotheses haven't.

Hope this helps!!

24 g of pure CO2 are exhaled by the individual. To calculate the number of moles, divide the outcome by the molar mass. As a result, the individual exhales about 0.55 moles of carbon dioxide every hour.

During aerobic cellular respiration, the interaction of glucose and oxygen results in the production of ATP that the cell can utilize.

As by-products, water and carbon dioxide are produced. The general formula for aerobic cellular respiration is: During cellular respiration, oxygen and glucose combine to create ATP.

CO2 is converted to glucose during photosynthesis, and H2O is oxidized to produce oxygen. Cellular respiration involves the reduction of oxygen and the oxidation of glucose to produce CO2 and water.

CO2 is carried by the bloodstream to the lungs, where it is eventually exhaled out of the body.

Therefore, Hence Number of moles glucose, C6H12O6 = 100g/180g = 0.55 moles.

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The electrophilic substitution of aromatic rings with the reagents Cl2 and AlCl3 typically results in the chlorination of the ring.

The substitution occurs at the ortho and para positions relative to any activating or deactivating groups present on the ring. If the ring is unsubstituted or only has weakly activating groups, then substitution will likely occur at both the ortho and para positions. However, if strongly activating groups are present, substitution may occur exclusively at the para position. The precise location of substitution will depend on the specific properties of the aromatic ring and the reagents used. Electrophilic aromatic substitution with Cl2 and AlCl3 as reagents involves chlorination of aromatic rings. In this reaction, the chlorine (Cl) acts as the electrophile, while AlCl3 serves as the Lewis acid catalyst. The electrophilic substitution typically occurs at the ortho and para positions of the aromatic ring. These positions are more reactive due to the electron-donating nature of substituents already present on the ring, which stabilizes the intermediate formed during the reaction. Overall, electrophilic substitution with Cl2 and AlCl3 targets the ortho and para positions on the aromatic ring.

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Answer:

\( {S}^{16} \)

group 16 period 2 of the periodic table

note: that is not the electronic configuration, that is the Bohr model.

There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. Sulfur is the correct answer for our given question

Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.

We can find any element in periodic table if its electronic configuration is given. From electronic configuration, we can find the group number and the period number. So, according to our question the configuration is 2,8,6. Form here we can say that  atomic number of element is 16 and the valence electron is 6 so the only group in the periodic table that has valence electron 6 is the group 16 that is oxygen family.

Therefore Element is sulfur and is found in group 16 and period 2

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To prepare a 0.125 M solution of copper (II) oxide with a volume of 530.00 mL, you would need to calculate the mass of solid sodium nitrate required. The molar mass of sodium nitrate (NaNO3) is 85.0 g/mol.

To calculate the mass of solid sodium nitrate needed, you can use the formula:

Mass (g) = Molarity (mol/L) x Volume (L) x Molar Mass (g/mol)

Plugging in the values, we get:

Mass (g) = 0.125 mol/L x 0.530 L x 85.0 g/mol

Simplifying the equation gives:

Mass (g) = 5.31375 g

Therefore, approximately 5.31 grams of solid sodium nitrate must be used to prepare a 0.125 M solution of copper (II) oxide with a volume of 530.00 mL.

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The existence of a carbonyl group in the unidentified chemical is indicated by the signal at 170 ppm in the 13C NMR spectra.

It displays the four anticipated signals one for each of the carbonsas expected.

Four carbons and four peaks are present. No two carbons exist in the same environment exactly. The peak at slightly over 50 must be a carbon with a single bond connecting it to an oxygen.

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Answer:

increase rate of reaction

Explanation:

because marble chips has been broken into small pieces

The values of work, w, for the system if 16.5 g NaN 3 reacts completely at 1.00 atm and 22 ∘ C. The work done is -919 J.

The equation of the reaction is;

2 NaN 3 ( s ) ⟶ 2 Na ( s ) + 3 N 2 ( g )

Number of moles of NaN3 = 16.5 g/65 g/mol = 0.25 moles

If 2 moles of NaNa3 yields 3 moles of N2

0.25 moles of NaN3 yields  0.25 moles × 3 moles/2 moles

= 0.375 moles of N2

We need to find the volume change using the;

PV = nRT

P = 1.00 atm

V =?

n =  0.375 moles of N2

R = 0.082 atmLK-1mol-1

T =  22 ∘ C + 273 = 295 K

V = nRT/P

V = 0.375 × 0.082  × 295/ 1.00

V = 9.07 L

Recall that during expansion the gas does work. Work done by the gas is;

W = -PΔV

W =-( 1 atm × 9.07 L)

W = -9 Atm

Again;

1 L atm = 101.325 J

So,

-9 atmL =  -9 atmL × 101.325 J/1 L atm

= -919 J

The work done is -919 J.

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Disclaimer:- your question is incomplete, please see below for the complete question.

Automobile airbags contain solid sodium azide, NaN 3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2 NaN 3 ( s ) ⟶ 2 Na ( s ) + 3 N 2 ( g ) Calculate the value of work, w, for the system if 16.5 g NaN 3 reacts completely at 1.00 atm and 22 ∘ C.

Answer:

\(T_1 = -57.15^{\circ}C\)

Explanation:

Given

\(P_1 = 650mmHg\) --- Initial Pressure

\(V_1 = 5.0L\) --- Initial Volume

\(V_2 = 5.7L\) --- Final Volume

\(P_2 = 800mmHg\) --- Final Pressure

\(T_2 = 30C\) ---- Final Temperature

Required

Determine the initial temperature (T1)

This question will be solved using combined gas law which states:

\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\)

However, the final temperature must be converted to degree kelvin

\(T_2 = 30C\) --- Add 273.15

\(T_2 = 30k + 273.15 k\)

\(T_2 = 303.15k\)

Make T1 the subject in \(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\)

\(T_1 = \frac{P_1V_1T_2}{P_2V_2}\)

Substitute values for P1, V1, T2, P2 and V2

\(T_1 = \frac{650 * 5.0 * 303.15}{800 * 5.7}\)

\(T_1 = \frac{985237.5}{4560}\)

\(T_1 = 216.060855263\)

Approximate

\(T_1 = 216k\)

Convert to degree Celsius

\(T_1 = 216k\) --- Subtract 273.15

\(T_1 = 216 - 273.15\)

\(T_1 = -57.15^{\circ}C\)

Hence, the initial temperature is -57.15C

Answer:

can't do much

Explanation:

baking soda;8,alkaline

bleach:12,alkaline.

coffee:5.10,acidic

coke;coke,acidic

milk;6.9,acidic.

lemon juice;2,acidic

this is all i can do.

The term that describes what she is measuring is called partial pressure.

From the Dalton's law of partial pressure, the total pressure of a gas is regarded as the sum of the partial pressures of all the gases in the mixture.

As such, each of the gases; carbon dioxide, oxygen, and nitrogen all possess partial pressures thus the term that describes what she is measuring is called partial pressure.

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Correct answer is Each orbit has a specific energy level.

Therefore, Correct statement is Each orbit has a specific energy level.

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The complete question is mentioned below:

Which statement about Niels Bohr’s atomic model is true?

a) Higher orbits have lower energies.

b) Each orbit has a specific energy level. c) Electrons can exist in any energy level. d) Orbits close to the nucleus have no energy.

Answer:

C

Explanation:

because kinetic and potential are both parts of mechanical energy

you should know we learned it in class

Answer:

sugar and oxygen

Explanation:

sugar (glucose) and oxygen

Bond length and Bond distance is the equilibrium distance between the two atoms which forms a covalent bond. The correct answer is  0. 6 per second.

It is typically given in mm way NM bond strength of bond dissociation strength is the strength wished to interrupt a covalent bond among atoms of a diatomic covalent compound in its gaseous state. A first-order response may be described as a chemical response wherein the response charge is linearly depending on the awareness of simplest one reactant. In different words, a first-order response is a chemical response wherein the charge varies primarily based totally at the adjustments withinside the awareness of simplest one of the reactants.

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