Air has a mass of 1.2g and a volume of 4,555ml. What is the density

Answers

Answer 1

Answer:

Density = 0.00026 g/mL

Explanation:

The density of a substance can be found by using the formula

\(Density(\rho) = \frac{mass}{volume} \)

From the question

mass of air = 1.2 g

volume = 4,555 mL

Substitute the values into the above formula and solve for the density

That's

\(Density = \frac{1.2}{4555} \)

= 0.0002634

We have the final answer as

Density = 0.00026 g/mL

Hope this helps you


Related Questions

How many grams of sample would be needed to prepare 800 mL of 3.50 % MgCl2?
Group of answer choices
6 grams of MgCl2
28 grams of MgCl2
20 grams of MgCl2
46 grams of MgCl2
You have an 8X stock of a buffer. How would you prepare 400 ml of 1X buffer?
Group of answer choices
32 mL stock added to 368 mL of water
50 mL stock added to 350 mL of water
40 mL of stock added to 400 mL water
8 mL stock added to 400 mL water
During SDS-PAGE, proteins are degraded by B-mercaptoethanol (BME).
Group of answer choices
True
False
Flag question: Question 20
Question 201 pts
Proteins in a SDS-PAGE gel separate based on:
Group of answer choices
Shape
a combination of size, shape, and charge
Size
Charge

Answers

28 grams of MgCl2.

50 mL stock + 350 mL water.

False. β-mercaptoethanol reduces disulfide bonds in proteins during SDS-PAGE, it doesn't degrade them.

1. To calculate the grams of MgCl2 needed, we can use the formula:

grams of MgCl2 = volume (mL) * concentration (% w/v) / 100

Plugging in the values:

grams of MgCl2 = 800 mL * 3.50% / 100

grams of MgCl2 = 28 grams

You would need 28 grams of MgCl2 to prepare 800 mL of 3.50% MgCl2.

2. To dilute the stock solution to a desired concentration, we can use the formula:

C1V1 = C2V2

Where:

C1 = concentration of stock solution

V1 = volume of stock solution

C2 = concentration of desired solution

V2 = volume of desired solution

In this case, we have an 8X stock and want to prepare a 1X buffer. Using the formula, we can calculate the volume of stock solution needed:

8X * V1 = 1X * 400 mL

V1 = (1X * 400 mL) / 8X

V1 = 50 mL

So, you would need to add 50 mL of stock solution to 350 mL of water to prepare 400 mL of 1X buffer.

3. During SDS-PAGE, proteins are not degraded by β-mercaptoethanol (BME). β-mercaptoethanol is used as a reducing agent to break disulfide bonds in proteins, which helps to denature the proteins and unfold them for separation based on their size using SDS-PAGE.

It does not degrade or destroy the proteins, but rather modifies their structure temporarily to facilitate separation.

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When you break an iron magnet into two pieces, you get ____.


two north poles

two south poles

two north poles and two south poles

a piece of iron that is no longer magnetic

Answers

Answer:

two north poles and two south poles

Explanation:

A single magnet has a north pole and a south pole. If it is broken into two pieces, then each of the two pieces will have a north pole and a south pole.

No matter how many times or into how many pieces a magnet is broken, the resulting pieces will have two poles each.

Answer:

Each piece will still have a north pole and a south pole.

Explanation:

What is the percent by mass of C in benzene (C6H6)? The molecular weight of carbon is 12.0107 g/mol and of hydrogen 1.00794 g/mol

Answers

Answer:

92.26% of C

Explanation:

To solve this problem we must assume we have 1 mole of benzene. The mole contains 6 moles of C and 6 moles of H. We have to convert these moles to grams in order to find the total mass and mass percent will be:

Mass atom / Total mass * 100

Mass C: 6mol C * (12.0107g / mol) = 72.0642g

Mass H: 6mol H * (1.00794g / mol) = 6.04764g

total mass: 72.0642g + 6.04764g = 78.11184g

Mass percent of C will be:

72.0642g C / 78.11184g* 100

92.26% of C

Please help with the question!

Please help with the question!

Answers

Subtract the initial mass from final mass, i.e., vm.

Oxidation state of H in BaH2

Answers

Answer:

Hydrogen, H, has an oxidation number of +1 unless it is combined with metals, where it has the oxidation number -1. –Examples – LiH = Li+ H-, BaH2= Ba 2+ H-7. Oxygen usually has the oxidation number -2.

Explanation:


What pattern do you see as you compare elements that belong in groups IA to VIIIA on the
periodic table

Answers

Group IA are metals and all react vigorously because they have 1 valence electron in their outer most shell and the reactivity increases as you go down the group. Group VIIIA are non reactive because of their complete valence shell.

Group IA are metals and all react vigorously because they have 1 valence electron in their outer most shell and the reactivity increases as you go down the group. Group VIIIA are non reactive because of their complete valence shell.

What is molecule?

Molecule is defined as number of atoms combined together, that shows the most smaller chemical compound's fundamental unit that participate in chemical reaction. In the combination of atoms attractive forces play a vital role and it helps to bound the atoms by a chemical bond.

Liquid consist of small range of order and the reason behind this is intermolecular attractive force which is very strong and due to this reason molecules are packed together tightly. Due to presence of high kinetic energy the molecules present in the liquid move rapidly and fastly  with one another.

Water is considered to be the simpler molecule and it consist of hydrogen and oxygen atom bounded together and due to the reason of high electronegativity of the oxygen's atom the bonds present are polar as well as covalent.  Due to presence of high kinetic energy the molecules present in the liquid move rapidly and fastly  with one another.

Therefore,Group IA are metals and all react vigorously because they have 1 valence electron in their outer most shell and the reactivity increases as you go down the group. Group VIIIA are non reactive because of their complete valence shell.

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An ion of iron has an 26 protons, 30 neutrons, and 23 electrons. What are its atomic number, atomic mass, and net charge?

Answers

Answer:

Atomic number: 26

Atomic mass: 56

Net charge: +3

Explanation:

A compound formed with potassium and bromine that can detect blood in a stain by reacting with it to form distinctive crystals

Answers

Answer:

Potassium Bromide

Explanation:

not sure but i think thats it

Convert 25 gigaseconds into centiseconds​

Answers

25 gigaseconds is equal to 2,500,000,000,000 centiseconds

Tetrachloroethene, C2C14 is a solvent used in many dry cleaning processes.
Write the empirical formula for tetrachloroethene.

Answers

An empirical formula presents the atoms of all the elements with the most simplified whole number ratios. In other words, divide each subscript by their greatest common factor.

The greatest common factor of 2 and 4 is 2.

2/2 = 1

4/2 = 2

So, the empirical formula for tetrachloroethene is CCl₂.

Which of these electron configurations is not possible?

Which of these electron configurations is not possible?

Answers

Answer:

D

Explanation:

Electrons are being filled according to the increasing other of their sublevel energy

write the symbol for every chemical element that has atomic number less than 15 and atomic mass greater than 23.9u

Answers

The symbοls fοr these elements are:

Aluminum: AlSilicοn: SiPhοsphοrus: P

What is chemical element?  

A chemical element is a chemical substance that cannοt be brοken dοwn intο οther substances. The basic particle that cοnstitutes a chemical element is the atοm, and each chemical element is distinguished by the number οf prοtοns in the nuclei οf its atοms, knοwn as its atοmic number.

Fοr example, οxygen has an atοmic number οf 8, meaning that each οxygen atοm has 8 prοtοns in its nucleus. This is in cοntrast tο chemical cοmpοunds and mixtures, which cοntain atοms with mοre than οne atοmic number.

The chemical elements that meet the given criteria (atοmic number less than 15 and atοmic mass greater than 23.9u) are:

Aluminum (Al): Atοmic number = 13, Atοmic mass = 26.98uSilicοn (Si): Atοmic number = 14, Atοmic mass = 28.09uPhοsphοrus (P): Atοmic number = 15, Atοmic mass = 30.97u

Therefοre, the symbοls fοr these elements are:

Aluminum: AlSilicοn: SiPhοsphοrus: P

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write the symbol for every chemical element that has atomic number less than 15 and atomic mass greater

A 5g sample of copper was heated from 10 degrees c to 50 degrees c. It absorbed 76.8 J of energy as heat. What is the specific heat of this piece of copper?

Answers

As per the given data, the specific heat of the copper sample is approximately 0.384 J/g·°C.

For the specific heat of copper, we can use the formula:

q = mcΔT

Given that:

Mass of copper (m) = 5g

Change in temperature (ΔT) = 50°C - 10°C = 40°C

Heat absorbed (q) = 76.8 J

76.8 J = 5g × c × 40°C

76.8 J = 200g°C × c

c = 76.8 J / 200g°C

c ≈ 0.384 J/g·°C

Thus, the specific heat of the copper sample is approximately 0.384 J/g·°C.

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Charged particles are accelerated because the faster they move there is a greater chance of producing a nuclear reaction. True False

Answers

False. Charged particles are accelerated to produce energy or to use them for scientific purposes such as in particle accelerators.

They may also be used for medical applications such as in radiation therapy. The probability of a nuclear reaction depends on the energy and other properties of the charged particle and the target material, as well as the reaction cross section, which is a measure of the likelihood of the reaction occurring

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The average human heart beats 2.5 billion times in a lifetime. The average lifespan is 78 years. What is the average heart rate?

SHOW YOUR WORK!!!!!!

Answers

Divide 2.5B by 78. You get an average of 32,051 beats per year.

phương trình nào sau đây không đúng
Mg(OH)2 (t°)→ MgO+H2O
Fe(OH)2 (t°,chân không)→FeO+H2O
2Fe(OH)3 (t°)→Fe2O3+3H2O
2NaOH (t°)→Na2O+H2O

Answers

Phương trình NaOH sai nha

The force that keeps the planets in orbit is________.

Question options:

mass

gravity

friction

kinetics

Answers

Answer:

The force that keeps the planets in orbit is gravity.

3. A gold ring has a mass of 67.0 grams. When
placed in a graduated cylinder containing 10 ml of
water, the water rises to 13.47 ml. Calculate the
density of the ring.
I

Answers

Answer:

The answer is

19.3 g/mL

Explanation:

The density of a substance can be found by using the formula

\(Density = \frac{mass}{volume} \)

From the question

mass = 67 g

Volume of ring = new volume of water - original volume of water

Volume = 13.47 - 10 = 3.47 mL

Substitute the values into the above formula and solve

That's

\(Density = \frac{67}{3.47} \\ = 19.308357\)

We have the final answer as

19.3 g/mL

Hope this helps you

in a chemical reaction, conservation of mass is demonstrated by proving that the mass of the reactants is___ the mass of the products.

Answers

Answer:

equal to

Explanation:

The law of conservation of mass tells us that during a chemical reaction, matter cannot be created or destroyed, but it can change from one form to another. This means that while atoms can rearrange themselves into new substances during a reaction, the mass of the reactants and products will be the same.

A 20.00 mL sample of this KOH solution is added to a 250 mL volumetric flask, and water is added to the mark. What is the new molarity of K ions in this solution

Answers

The new molarity of K ions in the solution is 0.160 M. Molarity, also known as molar concentration, is a measure of the concentration of a solute in a solution.

To calculate the new molarity of K ions in the solution, we need to use the following formula:

M1V1 = M2V2

where M1 is the initial molarity of the solution, V1 is the initial volume of the solution, M2 is the final molarity of the solution, and V2 is the final volume of the solution.

Here are the given values:

Initial molarity of KOH solution (M1): unknown

Initial volume of KOH solution (V1): 20.00 mL

Final volume of the solution (V2): 250 mL

Final molarity of K ions in the solution (M2): unknown

To use the formula, we need to convert the initial volume of KOH solution to liters:

V1 = 20.00 mL = 0.02000 L

Next, we can calculate the number of moles of K ions in the initial solution using the initial molarity and volume:

moles of K ions = M1 x V1

Since we do not know the initial molarity, we cannot calculate the exact number of moles. However, we can use the fact that KOH dissociates completely in water to K+ and OH- ions and that the molarity of K ions is equal to the molarity of KOH:

Molarity of K ions = Molarity of KOH

Therefore, we can assume that the initial molarity of K ions is also 2.0 M, which is the molarity of KOH given in one of the search results.

Using this assumption, we can calculate the number of moles of K ions in the initial solution:

moles of K ions = M1 x V1 = 2.0 M x 0.02000 L = 0.0400 moles

Next, we can use the formula to calculate the final molarity of K ions in the solution:

M2 = (M1 x V1) / V2

Substituting the known values and solving for M2, we get:

M2 = (0.0400 moles) / (0.250 L) = 0.160 M

Therefore, the new molarity of K ions in the solution is 0.160 M.

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100 points for right answer

100 points for right answer

Answers

Answer:

B.

Explanation:

Answer:

b

Explanation:

Pa help po!
Nonesense-REPORT

Pa help po!Nonesense-REPORT

Answers

Answer:

simply use the differentiation method

alkane members are single bonded and are Sp3 hybridized with tetrahydral geometry

Alkenes or other atoms with double bonds are Sp2 hybridized and Alkynes is a triple bond with Sp hybrid

you can also use the steric number formula which is Atoms+lone pairs =Steric number

in this case the type of bond doesn't matter

what are the limiting and excess reactants if 20.0g of C3H8 reacts with 10.0g of O2

what are the limiting and excess reactants if 20.0g of C3H8 reacts with 10.0g of O2

Answers

Step 1

The reaction must be completed and balanced as follows:

C3H8 + 5 O2 => 3 CO2 + 4 H2O

-------------

Step 2

Information provided:

20.0 g of C3H8

10.0 g of O2

----

Information needed:

1 mole of C3H8 = 44.1 g

1 mole of O2 = 32.0 g

(use your periodic table please)

-------------

Step 3

By stoichiometry,

C3H8 + 5 O2 => 3 CO2 + 4 H2O

44.1 g C3H8 ---------- 5 x 32.0 g O2

20.0 g C3H8 ---------- X

X = 20.0 g C3H8 x 5 x 32.0 g O2/44.1 g C3H8

X = 72.6 g O2

For 20.0 g of C3H8, 72.6 g of O2 is needed, but there is only 10.0 g of O2.

Therefore,

Answer:

The limiting reactant = O2

The excess = C3H8

how many unique sets of 4 quantum numbers are there to represent the electrons in the 4f subshell? remember that the pauli exclusion principle states that each electron must have its own unique set of 4 quantum numbers.

Answers

The number of unique sets of 4 quantum numbers to represent the electrons in the 4f subshell is 70.

The four quantum numbers that make up an electron's set are the:

(i) principal quantum number (n)

(ii) angular momentum quantum number (l)

(iii) magnetic quantum number (m_l)

(iv) spin quantum number (m_s).

Each of these electrons has a limited range of the above numbers in their respective shell.

The principal quantum number for all the electrons in the 4f subshell is 4.

The angular momentum quantum number has a value of 3 corresponding to the f subshell.

The magnetic quantum number has a range of -3 through +3 for the electrons in the f subshell.

The spin quantum number has a range of -1/2 or +1/2.

Even if the principal quantum number and angular momentum quantum number are the same for all the electrons, the other two factors contribute to each electron having a unique set of quantum numbers.

Therefore, when these four quantum numbers are combined, they make up 70 unique sets of 4 quantum numbers that can be used to represent the electrons in the 4f subshell, in accordance with the Pauli Exclusion Principle.

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Give 3 physical properties common to most metals

Answers

Answer:

What are you a 6 yo? Anyways, the most common properties are, They are good conductors of electricity, They are lustrous and They are sonorous.

What is the answer to "a sound wave begins with ...

Answers

A sound wave would begin with a vibration.

How does a sound wave begin?

A sound wave begins when there is a disturbance or vibration in a medium, such as air, that sets the particles of the medium into motion. This motion creates a disturbance that travels through the medium as a wave. The vibration could be caused by a variety of sources, such as a speaker, a musical instrument, or a clap of the hands.

The speed at which a sound wave travels through a medium depends on the density and elasticity of the medium, as well as the temperature. In air, sound waves typically travel at a speed of approximately 340 m/s.

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suppose you mix 100.0 g of water at 24.9 c with 75.0 g of water at 71.0 c. what will the final temperature of the mixed water in c?

Answers

The final temperature of the mixed water is 44.66 ⁰C.

The given parameters;

mass of the cold water, m = 100 g

initial temperature of the water, t₁ = 24.9 ⁰C

initial  temperature of the hot water, t₂ = 71.0⁰ C

mass of the hot water = 75 g

specific heat capacity of water is 4.184 J/g⁰C

The final temperature of the mixture is calculated as follows;

Based on the principle of conservation of energy;

Heat lost by hot water = heat gained by the cold water

mcΔθ₂ = mcΔθ₁

75 x 4.184 x (71.0 - T) = 100 x 4.184 x (T - 24.9)

75 x (71.0 - T) = 100 x (T - 24.9)

(71.0 - T) = 1.333(T - 24.9)

71.0 - T = 1.333T - 33.1917

71.0 + 33.1917 = 1.333T + T

104.1917 = 2.333T

Thus, the final temperature of the mixed water is 44.66 ⁰C.

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100) A certain alcohol contains only three elements, carbon, hydrogen, and oxygen. Combustion of a 20.00 gram sample of the alcohol produced 38.20 grams of CO2 and 23.48 grams of H2O. What is the empirical formula of the alcohol?A) C2H6OB) C3H6OC) C4H10OD) CH4OE) C5H10O

Answers

Answer:

To determine the empirical formula of the alcohol, we need to find the number of moles of each element in the sample. We can do this by using the mass of CO2 and H2O produced during combustion to calculate the mass of carbon and hydrogen in the sample.

The molar mass of CO2 is 44.01 g/mol, so 38.20 grams of CO2 is equivalent to 38.20 g / (44.01 g/mol) = 0.868 mol of CO2. Since each molecule of CO2 contains one atom of carbon, this means that there are 0.868 mol of carbon in the sample.

The molar mass of H2O is 18.02 g/mol, so 23.48 grams of H2O is equivalent to 23.48 g / (18.02 g/mol) = 1.303 mol of H2O. Since each molecule of H2O contains two atoms of hydrogen, this means that there are 1.303 mol * 2 = 2.606 mol of hydrogen in the sample.

Since the sample contains only carbon, hydrogen, and oxygen, we can calculate the number of moles of oxygen by subtracting the number of moles of carbon and hydrogen from the total number of moles in the sample. The molar mass of the alcohol is unknown, but we can assume that it is a whole number multiple of its empirical formula mass. Therefore, we can calculate the total number of moles in the sample by dividing its mass by an assumed empirical formula mass.

Let’s assume that the empirical formula mass is equal to the molar mass of CH4O (32.04 g/mol). This means that 20.00 grams of alcohol is equivalent to 20.00 g / (32.04 g/mol) = 0.624 mol of alcohol.

Since there are 0.868 mol of carbon and 2.606 mol of hydrogen in the sample, this means that there are 0.624 mol - 0.868 mol - 2.606 mol = -2.85 mol of oxygen in the sample.

Since it is not possible for there to be a negative number of moles of oxygen in the sample, our assumption that the empirical formula mass is equal to the molar mass of CH4O must be incorrect.

Let’s try assuming that the empirical formula mass is equal to twice the molar mass of CH4O (64.08 g/mol). This means that 20.00 grams of alcohol is equivalent to 20.00 g / (64.08 g/mol) = 0.312 mol of alcohol.

Since there are 0.868 mol of carbon and 2.606 mol of hydrogen in the sample, this means that there are 0.312 mol - 0.868 mol - 2.606 mol = -3.162 mol of oxygen in the sample.

Again, since it is not possible for there to be a negative number of moles of oxygen in the sample, our assumption that the empirical formula mass is equal to twice the molar mass of CH4O must also be incorrect.

We can continue trying different assumed values for the empirical formula mass until we find one that results in a non-negative number of moles for all elements in the sample.

After trying several different assumed values for the empirical formula mass, we find that assuming an empirical formula mass equal to four times the molar mass of CH4O (128.16 g/mol) results in a non-negative number

Explanation:

8. An element that has strong intermolecular forces is most likely to have:

•a boiling point below room temperature
•a melting point below room temperature
•a boiling point very close to its melting point
•a very high melting point

Answers

Answer:

a very high melting point answer

How many km are in 1.29 x 10 ^-2 cm?

can someone pls help me

Answers

Answer: 0.0129

Explanation:

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